How do you draw a SSS triangle?

Answer:

He can choose by each players skill and depending on how long the game is he can sub them out throughout the game

Step-by-step explanation:

The total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is, 8568 or C(18, 5)

A permutation can be defined as the number of ways a set can be arranged, order matters but in combination the order does not matter.

We have 18 people on a basketball team.

The coach needs to choose 5 to put into a game.

So the total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is:

\(= \rm _{18}^{}\textrm{C}_5\)

\(= \dfrac{18!}{5!\times 13!}\)

= 8568

Thus, the total different possible ways can the coach choose a team of 5 if each person has an equal chance of being selected is, 8568 or C(18, 5)

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Answer:  y = 7x - 3

graphed equation attached

Step-by-step explanation:  Slope-intercept form . y= mx+b

m is the slope, b is the constant, the y-intercept.

First find the slope:  rise/run  

Rise is the difference in y-values  18-4 = 14

Run is the difference between x-values  3 - 1 = 2

The Slope is 14/2   simplify:

m = 7

Use this calculated slope with values of y and x from either of the given coordinates and calculate b

y = mx + b

18 = 7(3) + b

18 = 21 + b .  subtract 21 from both sides  18 - 21 = 21 -21 + b

-3 = b

Put these calculated values for m and b into the slope-intercept equation"

y = 7x - b

The solution of the given problem of triangle comes out to be tan ∠A = 0.25.

Triangles are called polygons if they have four quadrants or more. Its form is a simple geometric figure. When put together, the characters ABC create a right-angled triangle. When the boundaries are incompatible, Euclidean geometry generates a new rectangle with square corners. Triangles are regarded as polygons because they have three edges and three corners.

Here,

Since △ABC is a right triangle with m∠C = 90°, we know that m∠A + m∠B = 90°.

Using the fact that tan ∠B = opposite/adjacent, we can set up a ratio using a common factor, x, for the opposite and adjacent sides of ∠B:

tan ∠B = 0.25 = opposite/adjacent = x/4x

Simplifying the right side, we get:

0.25 = x/4x = 1/4

Multiplying both sides by 4x, we get:

x = 4

So the opposite side of ∠B has length x = 4, and the adjacent side has length 4x = 16.

Using the Pythagorean theorem, we can find the length of the hypotenuse of △ABC:

c² = a² + b²

c² = 4²+ 16²

c² = 256

c = √256

c = 16

Now, we can use the fact that tan ∠A = opposite/adjacent to find tan ∠A:

tan ∠A = opposite/hypotenuse = 4/16 = 1/4

Therefore, tan ∠A = 0.25.

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Answer: bottom row is negative and the top is positive  

Step-by-step explanation:

Answer:   y=-4/5x+3/2

Step-by-step explanation:

rise over run

then find what x and y is

The given equation is equivalent to (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3). And the zero of the function are: \(\pm \frac{3}{2}\) and \(\pm \frac{3}{2}i\).

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

For solving a quadratic function you should find the discriminant: D=b²-4ac and after that use this variable in the formula: \(x=\frac{-b\pm\sqrt{D} }{2a}\).

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

The question gives: \(16x^4-81=0\), you can factor this equation. See below.

(4x²+9)*(4x²-9)

(4x²+9)*(2x-3)*(2x+3)

Therefore, you should choose one of options: (4x²+9)*(4x²-9) or (4x²+9)*(2x-3)*(2x+3).

Next step is to solve the given equation. Solving for  (4x²+9)*(2x-3)*(2x+3)=0, then:

For 2x-3=0

      x=3/2

For 2x+3=0

      x= -3/2

For 4x²+9=0

      4x²=-9

       x²= -9/4

      x = \(\pm \sqrt{\frac{-9}{4} }\)

      x   =\(\pm \frac{3}{2}*\sqrt{-1 }\\ \\ \pm \frac{3}{2}*i\)

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The person must score 136 to be in the top 5% of all scores in wechsler adult intelligence scale.

The formula for the normal distribution is;

z = (x - μ)/σ

where,

If we want to be in the top 5%, we must outperform 95% of the remaining scores. So we must investigate.

In with us standard normal probability table, look up 0.95 and get the Z score that corresponds to that.

z = 1.7

Put the value in formula ad find x.

1. 7 = (x - 110)/15

x = 25.5 + 110

x = 135.5

x = 136 (whole number)

Thus, the person must score 136 to be in the top 5% of all scores in wechsler adult intelligence scale.

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Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

A positive third charge can be placed at 0.55 m on the x-axis such that it experiences a net electric force equal to zero when the charges q1 and q2 are 0.50 nC and 10 nC respectively, and are separated by a distance of 3m. So, the correct answer is D).

Find the distance between the two charges

r = 3 m

Use Coulomb's law to find the force exerted by q1 on a positive charge q3 at a distance x from q1:

F1 = k * q1 * q3 / (x²)

Use Coulomb's law to find the force exerted by q2 on a positive charge q3 at a distance (r-x) from q2:

F2 = k * q2 * q3 / ((r-x)²)

Set the net force equal to zero

F1 + F2 = 0

Substitute the values for k, q1, q2, and r:

(9 x 10⁹) * (0.50 x 10⁻⁹) * q3 / x² + (9 x 10⁹) * (10 x 10⁻⁹) * q3 / (3-x)² = 0

Solve for x

(0.45 / x²) + (30 / (3-x)²) = 0

0.45(3-x)² + 30x² = 0

1.35 - 0.9x + 30x² = 0

30x² - 0.9x + 1.35 = 0

x = 0.019 m or x = 0.55 m

Since the problem asks for a point on the x-axis to the right of the two charges, the answer is x = 0.55 m. So, the correct option is D).

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--The given question is incomplete, the complete question is given below "  Two particles having charges of qı = 0.50 nC and q2 = 10 nC are separated by a distance of r = 3 m along the x- axis as shown in the figure below. At what point on the x-axis (pointing to the right) can a positive third charge be placed such that it experiences a net electric force on it equal to zero? Image size: s ML Max Select the correct answer Saved 1 of 3 attempts used CHECK ANSWER O 0.38m  O 0.19 m  O 0.14m O 0.55m o 1.50 m "--

Answer:

Step-by-step explanation:

I like answer 3.... the series will add to 1/3 eventually

Answer:

Contents of this laser is 0.744 um and the mass of the earth

Answer:

84

Step-by-step explanation:

if you divide 21 by .25 you will get 84

Answer:

the scale factor is 4

Step-by-step explanation:

Since ab > 0, it is clear that the discriminant D > 0. Therefore, the equation ax^2 + bx + c = 0 has two distinct real roots.

Since 4a + 2b + c = 0, we can rewrite c as c = -4a - 2b. Substituting this into the quadratic equation ax^2 + bx + c = 0 gives ax^2 + bx - 4a - 2b = 0. Factoring out an 'a' gives a(x^2 + (b/a)x - 4) - 2b = 0.

Since ab > 0, we know that a and b must have the same sign. This means that either both a and b are positive or both a and b are negative. In either case, (b/a) is negative. So we can rewrite the equation as a(x^2 - |(b/a)|x - 4) - 2b = 0.

To solve for the roots of the equation, we can use the quadratic formula: x = (-b ± √(b^2 - 4ac)) / 2a. Plugging in the coefficients, we get x = (-b ± √(b^2 - 4a(-4a-2b))) / 2a, which simplifies to x = (-b ± √(b^2 + 16ab)) / 2a.

Since ab > 0, we know that b^2 + 16ab > 0. Therefore, the quadratic equation ax^2 + bx + c = 0 has two real roots.

Based on the information provided, let's consider the equation ax^2 + bx + c = 0, where a, b, and c are real numbers and 4a + 2b + c = 0. Since ab > 0, both a and b have the same sign (either both positive or both negative).

The given equation can be rewritten as a quadratic equation in the standard form:

ax^2 + bx + c = 0

Using the discriminant formula, D = b^2 - 4ac, we can analyze the nature of the roots of the quadratic equation. Given that 4a + 2b + c = 0, we can express c as:

c = -4a - 2b

Now, let's plug this value of c into the discriminant formula:

D = b^2 - 4a(-4a - 2b)

D = b^2 + 16a^2 + 8ab

Since ab > 0, it is clear that the discriminant D > 0. Therefore, the equation ax^2 + bx + c = 0 has two distinct real roots.

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Answer:c + f = 10

200c + 400f = 2400

Step-by-step explanation:

Let's say c is the number of cans of soup and f is the number of frozen dinners.

The total number of items is 10:

c + f = 10

The total amount of sodium is 2400 mg.  Each can of soup has 200 mg, and each frozen dinner has 400 mg.

200c + 400f = 2400

The problem doesn't ask you to solve the system, but I'll solve it anyway.  We can use substitution or elimination.  But first, simplify the second equation by dividing both sides by 200.

c + 2f = 12

Using elimination, subtract the first equation.

f = 2

Plug into either equation to find c:

c = 8

There are 8 cans of soup and 2 frozen dinners.

Volume of prism: 5 x 4 x 6 = 120 cubic meters

Volume of pyramid: 5x4 x 6/3 = 40 cubic meters

Ratio: 40/120 = 1/3

Answer:

$60.30

Step-by-step explanation:

0.45 x 134 = $60.30

In a normal distribution, changing the standard deviation affects the shape and spread of the distribution.

1. Increase in standard deviation: When the standard deviation increases, the distribution becomes wider and more spread out. This means that the data points are more dispersed from the mean, resulting in flatter and broader tails in the distribution curve. The distribution becomes more spread out, indicating a greater variability in the data.

2. Decrease in standard deviation: Conversely, when the standard deviation decreases, the distribution becomes narrower and more concentrated around the mean. The data points are less spread out, and the distribution curve becomes taller and sharper. The distribution becomes more compact, indicating less variability in the data.

Overall, the standard deviation measures the average amount by which individual data points deviate from the mean. It quantifies the spread or dispersion of the data in relation to the mean.

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In a normal distribution, changing the standard deviation affects the shape, location, and spread of the distribution curve. A larger standard deviation results in a wider and flatter curve, indicating greater variability in the data. Conversely, a smaller standard deviation results in a narrower and taller curve, indicating less variability in the data.

In a normal distribution, the standard deviation measures the spread or variability of the data. When the standard deviation is increased, the distribution becomes wider, and when it is decreased, the distribution becomes narrower.

A larger standard deviation means that the data points are more spread out from the mean, resulting in a flatter and wider curve. This indicates a greater variability in the data. On the other hand, a smaller standard deviation means that the data points are closer to the mean, resulting in a taller and narrower curve. This indicates less variability in the data.

The standard deviation also affects the location of the distribution curve. The mean of the distribution remains the same, but the curve is shifted to the left or right depending on whether the standard deviation is increased or decreased.

Changing the standard deviation has important implications in various statistical analyses and probability calculations. It helps determine the likelihood of certain events occurring within a given range of values.

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m∠1 = m∠5, because alternate exterior angles are congruent.

Angles formed by intersecting two parallel lines with a transversal are known as angles in parallel lines.

Given:

lines a and b intersect a transversal, c.

The pair of angles on the outside of the two parallel lines but on the other side of the transversal are known as alternate exterior angles.

m∠1 = m∠5 (Alternate exterior angles are congruent)

m∠1 = m∠5, because alternate exterior angles are congruent.

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The Complete Question is attached below.

After performing the calculations, the NPV for project U at a 10% cost of capital is $1,372.36 (rounded to 2 decimal places).To compute the NPV (Net Present Value) statistic for project U with a cost of capital of 10 percent, we follow these steps:

1. Identify the expected cash flows associated with the project. Let's assume these cash flows are -$10,000 in Year 0, $3,000 in Year 1, $4,000 in Year 2, and $6,000 in Year 3.

2. Determine the present value of each cash flow. To calculate the present value, we discount each cash flow by the appropriate discount rate (cost of capital). The discount rate for Year 0 is 10%, Year 1 is 10%, Year 2 is 10%, and Year 3 is 10%.

3. Sum up the present values of all the cash flows. In this case, it would be -$10,000/(1+0.10)^0 + $3,000/(1+0.10)^1 + $4,000/(1+0.10)^2 + $6,000/(1+0.10)^3.

4. Calculate the NPV by subtracting the initial investment from the sum of the present values. In this case, the NPV would be the sum of the present values minus the initial investment of -$10,000.

After performing the calculations, the NPV for project U at a 10% cost of capital is $1,372.36 (rounded to 2 decimal places).

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Answer: from left to right -3,-1,1,3,5

Step-by-step explanation:

Substitute the x value from the chart into the equation for each number.

The steps of the analytical problem-solving model include: identifying the problem, exploring alternatives, building an implementation plan, implementing a solution, and evaluating the situation.

Analytical problem solving, as we've defined it above, refers to the approaches and methods you use rather than the particular issue you're trying to resolve.

Analytical issue solving is a crucial prerequisite for problem resolution; the problem itself does not determine whether you need it.

Analytical problem solving involves recognising a problem, investigating it, and then creating ideas (such as causes and solutions) around it.

Solving analytical problems calls for inquiry, examination, and analysis that encourages additional study of the subject (including causality, symptoms, and solution).

According to the steps involved in analytical problem solving model:

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Answer:

Step-by-step explanation:

The probability that a number less than or equal to three is rolled is 1/2.

Given that, a number cube is rolled, we need to find that what is the probability that a number less than or equal to three is rolled,

So, the probability = favorable outcomes / total outcomes

Here, the favorable outcome = 1, 2, 3 = 3

The total outcomes = 1, 2, 3, 4, 5, 6 = 6

So, the probability = 3/6 = 1/2

Hence, the probability that a number less than or equal to three is rolled is 1/2.

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The volume (in units3) is generated when the region between the curves is rotated around the given axis and is  mathematically given as

\(v=\frac{5 \pi}{6}\)

The region is bound by

x=y^2

y=x

y=3

Where

y=√x

Generally, the equation for Washer Method is  mathematically given as

\(v=\int ^1_0 \pi ((outer curve)^2-(inner Curve)^2) dx\)

Therefore

\(V= 2 \pi \int_0^1(3-y)\left(y-y^2\right) d y \\\\= 2 \pi \int_0^1\left(3 y-y^2-3 y^2+y^3\right) d y \\\\=2 \pi \int_0^1\left(y^3-4 y^2+3 y\right) d y \\\\=2 \pi\left[\frac{y^4}{4}-4 \cdot \frac{y^3}{3}+3 \cdot \frac{y^2}{2}\right]_0^1 \\\)

\(=2 \pi\left[\frac{1}{4}-\frac{4}{3}+\frac{3}{2}\right]=2 \pi \times \frac{5}{12}\)

\(V=\frac{5 \pi}{6}\)units

In conclusion, The result can be shown in multiple forms

Exact Form:

\(V=\frac{5 \pi}{6}\)

Decimal Form:

\(V=2.61799387\)

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The probability that he rolls a 4 and flips a head is 1/12

Probability determines odds that a random event would happen. The odds of the random event happening lie between 0 and 1.

The probability that he rolls a 4 and flips a head = (number of sides that is a 4 / total number of sides) x (number of sides that is a head / total number of sides)

(1/6) x (1/2) = 1/12

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Answer: 1/12

Step-by-step explanation:

just say the answer

The depth of the water in the cone-shaped tank is increasing at a rate of approximately 1.385 meters per second.

To determine the rate at which the depth of the water is changing, we can use related rates. Let's denote the depth of the water as h(t), where t represents time. We are given that dh/dt (the rate of change of h with respect to time) is 12 m/sec, and we want to find dh/dt when h = 18 meters.

To solve this problem, we can use the volume formula for a cone, which is V = (1/3)πr^2h, where r is the base radius and h is the depth of the water. We can differentiate this equation with respect to time t, keeping in mind that r is a constant (since the base radius does not change).

By differentiating the volume formula with respect to t, we get dV/dt = (1/3)πr^2(dh/dt). Now we can substitute the given values: dV/dt = 12 m/sec, r = 26 meters, and h = 18 meters.

Solving for dh/dt, we have (1/3)π(26^2) (dh/dt) = 12 m/sec. Rearranging this equation and solving for dh/dt, we find that dh/dt is approximately 1.385 meters per second. Therefore, the depth of the water in the tank is increasing at a rate of about 1.385 meters per second.

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The exact values of cos(θ) and csc(θ) in terms of fractions, given that tan(θ) = 7/24 and θ is in Quadrant I, are: cos(θ) = 24/25, csc(θ) = 25/7

In Quadrant I, all trigonometric functions are positive. Given that tan(θ) = 7/24, we can find the values of cos(θ) and csc(θ) using the relationships between trigonometric functions.

Given that tan(θ) = 7/24 and θ is in Quadrant I:

We can start by finding the value of sin(θ) using the Pythagorean identity:

sin(θ) = √(1 - cos²(θ))

Since cos(θ) = 24/25 (as previously calculated),

sin(θ) = √(1 - (24/25)²)

= √(1 - 576/625)

= √(49/625)

= 7/25

Now that we have sin(θ) and cos(θ), we can find the remaining values:

cos(θ) = 24/25

csc(θ) = 1/sin(θ) = 1 / (7/25) = 25/7

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Answer:

$31.63 per hour

Step-by-step explanation:

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The seasonally-adjusted forecast for quarter 4 of year 5 is 91.9

The seasonally-adjusted forecast for quarter 4 of year 5 can be calculated by using the following equation:
Seasonally Adjusted Forecast = Trend Equation + Seasonal Factors
= 65 + 6.7X + 0.1
= 65 + 6.7X + 0.1
= 65 + 6.7*4 + 0.1
= 65 + 26.8 + 0.1
= 91.9
Therefore, the seasonally-adjusted forecast for quarter 4 of year 5 is 91.9.

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