Answer:
See explanation
Step-by-step explanation:
So what you would need to do is take 300/10
300/10 which is 1/10 of 300, would be 30
You can also check your work by doing 30 x 10
This equals 300, so its correct.
22. which of the following is false? (a) a chi-square distribution with k degrees of freedom is more right-skewed than a chi-square distribution with k 1 degrees of freedom. (b) a chi-square distribution never takes negative values. (c) the degrees of freedom for a chi-square test is deter- mined by the sample size. (d) p(c2 > 10) is greater when df
The false statement is (a) a chi-square distribution with k degrees of freedom is more right-skewed than a chi-square distribution with k+1 degrees of freedom.
In fact, as the degrees of freedom increase, the chi-square distribution becomes less skewed and approaches a normal distribution. Statement (b) is true, a chi-square distribution never takes negative values. Statement (c) is generally true, the degrees of freedom for a chi-square test are determined by the sample size minus one. Statement (d) is incomplete, as there is no specified value for df. The larger the degrees of freedom, the smaller the p-value for a given chi-square value.
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Can someone help me answer these sentences?
Represent the following sentence as an algebraic expression, where "a number" is the letter x. You do not need to simplify. 2 is subtracted from the product of 5 and a number. 2 is subtracted from the product of 5 and a number.
The statement 2 is subtracted from the product of 5 and a number is
5x - 2.
What is a numerical expression?A numerical expression is a mathematical statement written in the form of numbers and unknown variables. We can form numerical expressions from statements.
Given, A statement an unknown number 'x' 2 is subtracted from the product of 5 and a number.
∴ 5×x - 2.
= 5x - 2 is the numerical expression.
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Can a system of three linear equations in three variables have exactly two solutions?
The given assertion is false. The option for reason is the principal option:
" An arrangement of three linear equations in three unknowns can have one solution, an infinite number of solutions, or no solutions."
An arrangement of linear equations is a grouping of at least one linear equation with similar variables.
A linear framework solution is the task of values to variables so that the equations are all concurrently satisfied.
For an arrangement of equations, three types of solutions exist:-
One solution: When the lines (planes) converge at a point.
No Solution: When the lines (planes) are parallel.
Infinitely numerous solutions: When the lines (planes) overlap one another.
Subsequently, the given assertion is false. The option for reason is the principal option:
" The assertion is false. An arrangement of three linear equations in three unknowns can have one solution, an infinite number of solutions, or no solutions."
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refer to the attachment for the complete question:
Given an equation as follows: \[ R \frac{d i}{d t}+L \frac{d^{2} i}{d t^{2}}+\frac{1}{C} i=\frac{d V}{d t} \] Convert the linear ODE to block diagram. Fill in the blank
Block diagram representation of R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt.
The given equation is R(di/dt)+L(d²i/dt²)+(1/C)i = dV/dt.
The block diagram is an essential tool in the analysis and design of dynamic systems. The blocks represent the interconnected subsystems of the system.
The interconnections and external inputs and outputs are shown by the connections between the blocks.The block diagram representation of the equation R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt is given below.
Therefore, the block diagram representation of the given equation is as follows:
Block diagram representation of R(di/dt) + L(d²i/dt²) + (1/C)i = dV/dt.
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(1 point) college officials want to estimate the percentage of students who carry a gun, knife, or other such weapon. how many randomly selected student
Probability Theory
P (K) =\(\frac{n (K) }{n (S)}\)
P(K) : probability of selected K
n (K) : number of occurence of K
n (S) : number of all occurence
In question is not contain information about the number of students who curry a gun, knife, or other weapon and the number of all students. so, we can desribe that :
n (A) : the number of occurence of students who curry a gun
n (B) : the number of occurence of students who curry a knife
n (C) : the number of occurence of students who curry other weapon
and the number of all students is n ( A U B U C) -> union of sets
how many randomly selected student? in question, there is no specific about the student. so, we can answer with :
1) probability of students who curry a gun
P (A) = \(\frac{n (A) }{n (AUBUC)}\)
2) probability of students who curry a knife
P (B) = \(\frac{n (B) }{n (AUBUC)}\)
3) probability of students who curry other weapon
P (C) = \(\frac{n (C) }{n (AUBUC)}\)
and if question want to estimate with percentage, we can multiply with 100%. example :
1) percentage of probability of students who curry a gun
P (A) = \(\frac{n (A) }{n (AUBUC)}\) x 100%
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i need helpp...........
Answer:
14
Step-by-step explanation:
(2 x 6) + ( \(\sqrt{16\\}\) - 8 ÷ 2^2) =
12 + (4 - 8 ÷ 4)
12 + (4 - 2)
12 + 2
14
Jenny polled her 35 co-workers to find out which type of candy they liked best. She found that 10 like chocolate, 8 like gumdrops, 2 like hard candy, and 3 like taffy. There were 5 people who said they like BOTH hard candy and taffy and the remaining co-workers said they like BOTH chocolate and gum drops. How many of Jenny’s co-workers enjoy gumdrops or chocolate?
a.
10
d.
7
b.
8
e.
25
c.
18
The number of co-workers that like gumdrops and chocolate is 7 (option b).
How many like chocolate and gumdrops?The mathematical operations that would be used to determine the answer are addition and subtraction.
Addition is determining the total value or summing two or more numbers. The sign used to represent addition is +. Subtraction is the process of determining the difference between two or more numbers. The sign used to denote subtraction is -.
The first step is to add the total number of people who like a particular type of candy : 10 + 8 + 2 + 3 + 5 = 28
The second step is to subtract that number gotten in the previous step from the total number of co-workers.
Co-workers that like both chocolate and gum drops = 35 - 28 = 7
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write the equivalent fractions for 4/9 and 10/11 using the least common denominator
Answer:
4/9 = 44/99
10/11 = 90/99
Step-by-step explanation:
44/99=90/99
Answer:
Step-by-step explanation:
4/9 = 8/18 or 36/81
10/11= 20/22 or 30/33
what is th answer to this question
The total surface area of the trapezoidal prism is S = 3,296 inches²
Given data ,
Let the total surface area of the trapezoidal prism is S
Now , the measures of the sides of the prism are
Side a = 10 inches
Side b = 32 inches
Side c = 10 inches
Side d = 20 inches
Length l = 40 inches
Height h = 8 inches
Lateral area of prism L = l ( a + b + c + d )
L = 40 ( 10 + 32 + 10 + 20 )
L = 2,880 inches²
Surface area S = h ( b + d ) + L
On simplifying the equation , we get
S = 2,880 inches² + 8 ( 52 )
S = 3,296 inches²
Hence , the surface area of prism is S = 3,296 inches²
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Suppose in 2008 the average cost of a movie ticket in the United States was $7. If
inflation causes ticket prices to increase by 4.5% a year, in what year will a ticket cost
$25?
a. 2025
b. 2037
c. 2029
d. 2040
Answer:
B) 2037
Step-by-step explanation:
using the problem an exponential equation can be made
7(1.045)× =25
--solve for x--
x=28.9
it will take 28.9 year for the price to get to $25 so add 2008 to 28.9 to get 2036.9
2037 is closest to 2036.9 so the answer is B
The tree diagram represents an
experiment consisting of two trials.
S
A
B
.4 C
6
13
D
C
D
The required probability is P(A and C) is 0.2 which is represented in the tree diagram.
What is probability?Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.
The given tree diagram represents an experiment consisting of two trials.
The tree diagram represents an experiment consisting of two trials. In this case, the probability of event A and event C occurring is represented by the intersection of branches A and C in the tree diagram.
This probability can be calculated by multiplying the probability of each individual event together.
As per the given question, we have
P(A) = 0.5
P(C|A) = 0.4
So, P(A and C) = 0.5 × 0.4 = 0.2
Thus, the required probability is P(A and C) is 0.2
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Miguel Rodriguez borrowed $300 from his brother Julio to pay for books and tuition. He agreed to pay Julio in 6 months with simple annual interest at 6.5%.
Answer:
Simple Interest = 9.75
Total Amount needed to payback = 309.75
Step-by-step explanation:
SI = P x R x T / 100
SI = Simple Interest
P = Principal
R = Rate in years
T = Time
SI = 300 x 1/2 x 6.5 /100
=> SI = 3 x 1/2 x 6.5
=> 1.5 x 6.5
=> 9.75
Total Amount needed to payback = Principal + Simple Interest
=> Total Amount needed to payback = 300 + 9.75
=> Total Amount needed to payback = 309.75
find the expectation value of the position squared when the particle in the box is in its third excited state. answer this question with the correct coefficient of l2 for the expectation value.
The expectation value of the position squared when the particle in the box is in its third excited state is equal to \(\frac{9l^2}{8}\), where l is the length of the box. This is equal to nine-eighths of the length of the box squared.
The expectation value of the position squared when the particle in the box is in its third excited state can be calculated using the formula\(\langle x^2 \rangle = \frac{l^2}{8} \left( 2n^2 + 6n + 3 \right)\),
where n is the quantum number of the state and l is the length of the box. Here, n is 3, so the expectation value is equal to
\(\frac{l^2}{8} \left( 2 \times 3^2 + 6 \times 3 + 3 \right) = \frac{9l^2}{8}\).
This can be written as nine-eighths of the length of the box squared.
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The point B (-2, 1) has been transformed to B' (-5, -3). The transformation is described as
A T (-3,-4)
B R x=2
C T (-3,-2)
D D3
Answer:
Option A: T(-3, -4)
Step-by-step explanation:
For a general point (x, y), if we apply the transformation:
T(a, b)
at that point, the new point that we will get is:
T(a,b)[ (x, y) ] = (x + a, y + b)
Notice that if w take the difference between the new point (x + a, y + b) and the original point (x, y)
we get:
(x + a, y + b) - (x, y) = (x + a - x, y + b y) = (a, b)
These are x-value and y-value that describe our transformation T(a, b).
Then if we know that the original point is B (-2, 1)
and the transformed point is B'( -5, -3)
We can just take the difference to get:
(-5, -3) - (-2, 1) = (-5 - (-2), -3 - 1) = (-5 + 2, -4) = (-3, -4)
Then the transformation applied is:
T(-3, -4)
The correct option is A.
what were descartes’ chief contributions to mathematics?
Answer:Descartes’s chief contributions to mathematics were his analytical geometry and his theory of vortices, and it is on his researches in connection with the former of these subjects that his mathematical reputation rests. Who is Rene Descartes is he known for? Descartes has been heralded as the first modern philosopher.
Step-by-step explanation:
GIVING BRAINLIEST, NO LINKS, LOOK AT THE PICTURE
Answer: 2 2/5
Step-by-step explanation:
hope that helped :)))
Caleb and Sergio stacked boxes on a shelf. Caleb lifted 14 boxes of equal weight. Sergio lifted 12 boxes of equal weight, but Sergio's boxes each weighed 10 lb more than Caleb's boxes.
Together they lifted a total of 354 pounds.
What was the weight of one of Caleb's boxes?
Answer:
Step-by-step explanation:
Caleb = 14x
Sergio = 12y
Sergio's boxes each weighed 10 lb more than Caleb's boxes.
y = x + 10
The equation is
14x + 12y = 354
Substitute y = x + 10
14x + 12(x+10) = 354
14x + 12x + 120 = 354
26x = 354 - 120
26x = 234
Divide both sides by 26
x = 234/26
= 9
x = 9lb
Recall,
y = x + 10
= 9 + 10
y = 19lb
Check:
14x + 12y = 354
14(9) + 12(19)
= 126 + 228
= 354
Answer: 19lb
Step-by-step explanation:
A student is conducting a probability experiment and wants to know the total number of outcomes for the experiment. The student's experiment is comprised of three events
• rolling a six-sided number cube • •flipping a coin
• rolling a six-sided number cube again
How many outcomes are possible in this experiment?
A. 14
B. 24
C. 72
D. 38
Answer:So to get a 6 when rolling a six-sided die, probability = 1 ÷ 6 = 0.167, or 16.7 percent chance. So to get two 6s when rolling two dice, probability = 1/6 × 1/6 = 1/36 = 1 ÷ 36 = 0.0278, or 2.78 percent.
Step-by-step explanation:
Answer:
C.72
Step-by-step explanation:
rolling a six-sided number cube(6) x flipping a coin(2) x rolling a six-sided number cube again(6)= 72
6x6= 36
36 x 2 = 72
6x2=12
12 x 6 = 72
Find the measure of the angle indicated in bold.
HURRY PLEASE!!!
Answer:
Step-by-step explanation:
Find the measure of the angle indicated in bold. 25) x+96 x+96. 90°. Same side interior 26). L'S. →X+96+X+96=180. 2x+ 192=180.
A die is rolled. Find the probability of the given event. Write your answers as whole numbers or reduced fractions.
(a) The number showing is a 4
P(4) = (b) The number showing is an even number
P(even) =
(c) The number showing is greater than 3
P(greater than 3) =
The probability for given conditions are a) p(4)=0.166, b) p(even)=0.5 and c) p(greater than 3)=0.5
A die is rolled, then the sample space for outcomes is {1,2,3,4,5,6}
Total number of outcomes =6
Probability of showing number 4. number of favourable outcomes is 1 because there is only one 4 in the sample space of outcomes , \(P(4)=\frac{number\ of\ favourable\ outcomes}{total\ number\ of\ outcomes}\\\\P(4)=\frac{1}{6}=0.166\)Probability of showing an even number, even numbers in sample space are {2,4,6} number of favourable outcomes =3 \(P(even)=\frac{3}{6}=\frac{1}{2}=0.5\)Probability of showing a number greater than 3, numbers greater then three is sample space are {4,5,6} number of favourable outcomes =3 \(P(greater\ than\ 3)=\frac{3}{6}=\frac{1}{2}=0.5\)Thus, the probability for given conditions are a)p(4)=0.166, b)p(even)=0.5 and c)p(greater than 3)=0.5
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In an expression using the logical operator ____, as soon as one of the compound conditions is found to be false, no further conditions are tested and the expression evaluates to false. a. OrElse b. Nor c. AndAlso d. Xor
In an expression using the logical operator And Also, as soon as one of the compound conditions is found to be false, no further conditions are tested and the expression evaluates to false.
The And Also operator is a short-circuiting operator that is used to combine two or more Boolean expressions. It evaluates the left-hand expression first and then the right-hand expression only if the left-hand expression evaluates to true
. If the left-hand expression evaluates to false, then the right-hand expression is not evaluated at all. This helps to improve the performance of the code by avoiding unnecessary evaluations of expressions that would not change the outcome of the overall condition.
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In an expression using the logical operator And Also , as soon as one of the compound conditions is found to be false, no further conditions are tested and the expression evaluates to false. Therefore option c. And Also correct.
This is because the AndAlso operator employs short-circuit evaluation, meaning it stops evaluating once it encounters
the first false condition since the overall result will definitely be false.
In an expression using AndAlso, if the first condition is false, the entire expression is evaluated as false without testing
any further conditions. This is also known as short-circuit evaluation.
In contrast, the OrElse operator evaluates to true as soon as one of the compound conditions is true, without testing
any further conditions. The Nor and Xor operators are less commonly used and have different behavior.
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Sarah is sitting blindfolded before a plate holding 3 apples and 1 pear. What is the probability that Sarah will select the pear? Write your answer as a fraction.
Answer:
3/1
Step-by-step explanation:
3/1 the ratio is 3:1
Plzzzzz I will mark you as a brainliest plzzzz and you will have 15 points:)
Answer:
Step-by-step explanation:
a. 1+(-8)
b. 1+8
Can Someone plz help me i will mark brainliest
Answer:
a
Step-by-step explanation:
if u multiply by -5 the 5s will cancel out
Answer:
c
Step-by-step explanation:
sorry if it wrong
Which of the following is a measure of the reliability of a statistical inference? Answer A descriptive statistic. A significance level. A sample statistic. A population parameter.
The measure of reliability of a statistical inference is the significance level. The significance level, also known as alpha, is the probability of rejecting the null hypothesis when it is actually true. It determines the threshold for accepting or rejecting a hypothesis.
A lower significance level indicates a higher level of confidence in the results. A descriptive statistic provides information about the data, but it does not directly measure the reliability of a statistical inference. It simply summarizes and describes the characteristics of the data.
A sample statistic is a numerical value calculated from a sample, such as the mean or standard deviation. While it can be used to make inferences about the population, it does not measure the reliability of those inferences.
A population parameter is a numerical value that describes a population, such as the population mean or proportion.
While it provides information about the population, it does not measure the reliability of inferences made from a sample. In conclusion, the significance level is the measure of reliability in a statistical inference as it determines the probability of making a Type I error, which is rejecting the null hypothesis when it is actually true.
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Write V – 250 in simplest radical form.
Answer:
5i√10
Step-by-step explanation:
hope this answers your question
:)
Answer:
5√10
Step-by-step explanation:
Research has shown that competent communicators achieve effectiveness by
a. using the same types of behavior in a wide variety of situations.
b. developing large vocabularies.
c. apologizing when they offend others.
d. giving lots of feedback.
e. adjusting their behaviors to the person and situation.
Research has shown that competent communicators achieve effectiveness by adjusting their behaviors to the person and situation (option e).
Effective communication involves being adaptable and responsive to the specific context, individual preferences, and the needs of the situation.
Competent communicators recognize that different people have different communication styles, preferences, and expectations. They understand the importance of tailoring their communication approach to effectively connect and engage with others.
This may involve using appropriate language, tone, non-verbal cues, and listening actively to understand the needs and perspectives of others.
By adapting their behaviors, competent communicators can build rapport, foster understanding, and promote effective communication exchanges. They are mindful of the social and cultural dynamics at play, and they strive to communicate in a way that is respectful, inclusive, and conducive to achieving mutual goals.
In summary, competent communicators understand that effective communication is not a one-size-fits-all approach. They adjust their behaviors to the person and situation, demonstrating flexibility and adaptability in order to enhance communication effectiveness.
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Competent communicators achieve effectiveness mostly by adjusting their behaviors to suit the person they are communicating with and the situation they find themselves in. While other factors, like having a broad vocabulary or giving feedback, play a part in effective communication, the former is considered the most crucial.
Explanation:Research suggests that competent communicators achieve effectiveness mostly through adjusting their behaviors depending on the person they are communicating with and the situation they are in. This is option e. of your question. Communicating effectively involves behaviors like active listening, understanding the other person's point of view, being able to express thoughts and ideas clearly, and being polite and respectful. While a broad vocabulary (option b.) can be useful, it is not as crucial as adapting your behavior to fit the situation. Moreover, giving feedback (option d.) is a part of effective communication but not the sole defining factor. Apologizing when offending others (option c.) is also important but it doesn't necessarily make one a competent communicator. Using the same type of behavior in various situations (option a.) might not always work, as different situations and individuals require different communication styles.
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Find all values of the scalar k for which the following vectors are orthogonal: u=[k,k,−2],v=[−5,k+2,5]
The vectors u and v are orthogonal when k equals 5 or -2.
Two vectors u and v are orthogonal if their dot product is equal to zero. The dot product of two vectors u and v is given by the formula:
u · v = u₁ × v₁ + u₂ × v₂ + u₃ × v₃
where u₁, u₂, u₃ are the components of vector u, and v₁, v₂, v₃ are the components of vector v.
Let's calculate the dot product of u and v:
u · v = (k × -5) + (k × (k + 2)) + (-2 × 5)
= -5k + k² + 2k - 10
= k² - 3k - 10
For the vectors to be orthogonal, the dot product must be zero:
k² - 3k - 10 = 0
To solve this quadratic equation, we can factor it or use the quadratic formula:
(k - 5)(k + 2) = 0
From this equation, we can see that the values of k that satisfy the equation are:
k = 5 or k = -2
Therefore, the vectors u and v are orthogonal when k equals 5 or -2.
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Question -
If the ratio of the sums of first n^th terms of two AP's is (7n + 1):(4n + 27) find the ratio of their m^th terms.
\(\rule{200}4\)
Answer : The required ratio is (14m-6):(8m+23) .
\(\rule{200}4\)
Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .
That is.
\(\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{7n +1}{4n +27} \\\)
As , we know that the sum of n terms of an AP is given by ,
\(\small\sf\longrightarrow \pink{ S_n =\dfrac{n}{2}[2a +(n-1)d]} \\\)
Assume that ,
First term of 1st AP = a First term of 2nd AP = a'Common difference of 1st AP = dCommon difference of 2nd AP = d'Using this we have ,
\(\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{\dfrac{n}{2}[2a + (n-1)d]}{\dfrac{n}{2}[2a' +(n-1)d'] } \\\)
\(\small\sf\longrightarrow \dfrac{7n+1}{4n+27}=\dfrac{2a + (n -1)d}{2a' + (n -1)d' } . . . . . (i) \\\)
Now also we know that the nth term of an AP is given by ,
\(\longrightarrow\sf\small \pink{ T_n = a + (n-1)d}\\\)
Therefore,
\(\longrightarrow\sf\small \dfrac{T_{m_1}}{T_{m_2}}= \dfrac{ a + (n-1)d }{a'+(n-1)d'}. . . . . (ii)\\\)
\(\longrightarrow\sf\small \dfrac{T_1}{T_2}=\dfrac{2a + (2n-2)d}{2a'+(2n-2)d'} . . . . . (iii)\\\)
From equation (i) and (iii) ,
\(\longrightarrow\sf\small n-1 = 2m-2\\\)
\(\longrightarrow\sf\small n = 2m -2+1 \\\)
\(\longrightarrow\sf\small n = 2m -1 \\\)
Substitute this value in equation (i) ,
\(\longrightarrow \sf\small \dfrac{2a+ (2m-1-1)d}{2a' +(2m-1-1)d'}=\dfrac{7(2m-1)+1}{4(2m-1) +27}\\\)
Simplify,
\(\longrightarrow\sf\small \dfrac{ 2a + (2m-2)d}{2a' +(2m-2)d'}=\dfrac{14m-7+1}{8m-4+27}\\\)
\(\longrightarrow\sf\small \dfrac{2[a + (m-1)d]}{2[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\\)
\(\longrightarrow\sf\small \dfrac{[a + (m-1)d]}{[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\\)
From equation (ii) ,
\(\longrightarrow\sf\small \underline{\underline{\blue{ \dfrac{T_{m_1}}{T_{m_2}}=\dfrac{ 14m-6}{8m+23}}}}\\\)
\(\rule{200}4\)