How do you reduce a camping tent' heat in DIY Method Pl do not cam me with dum replie!
Answers
Camping - Even on sweltering summer days, camping is a delightful outdoor activity.
However, if it's hot outside, your tent may become very uncomfortable. Thankfully, there are ways to keep your tent cool. By making the most of your supplies, setting up your tent in the ideal location, and using a tarp or umbrella to block off the sun, you may avoid the heat.
Three methods to keep the tent cool:
1. Bring your cooler of ice into the tent.
2. Use a battery-operated fan to circulate the air.
3. Open your tent’s door and vents if it has any.
4. Sleep on top of your sleeping bag to stay cool.
5. Remove the rain fly if the weather forecast doesn’t predict rain.
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Related Questions
select the intermolecular forces present in water. group of answer choices h-bonding ion-dipole london dispersion dipole-dipole
Answers
The intermolecular forces present in water include hydrogen bonding and dipole-dipole interactions.
Water is a polar molecule, meaning it has a positive and a negative end due to an uneven distribution of electron density. This polarity gives rise to intermolecular forces that hold water molecules together.
One of the intermolecular forces present in water is hydrogen bonding. Hydrogen bonding occurs when a hydrogen atom, which is covalently bonded to an electronegative atom (in this case, oxygen), is attracted to another electronegative atom (such as oxygen or nitrogen) in a different molecule. In water, the oxygen atom of one water molecule forms a hydrogen bond with a hydrogen atom of a neighboring water molecule. Hydrogen bonding is a strong intermolecular force and contributes to many of the unique properties of water, such as its high boiling point and surface tension.
In addition to hydrogen bonding, water also exhibits dipole-dipole interactions. Dipole-dipole interactions occur between the positive end of one polar molecule and the negative end of another polar molecule. In water, the positive hydrogen end of one water molecule is attracted to the negative oxygen end of a neighboring water molecule. These dipole-dipole interactions are weaker than hydrogen bonds but still contribute to the overall intermolecular forces present in water.
Other intermolecular forces, such as ion-dipole interactions and London dispersion forces, are not as significant in water compared to hydrogen bonding and dipole-dipole interactions. Ion-dipole interactions occur between an ion and the charged end of a polar molecule, while London dispersion forces arise from temporary fluctuations in electron distribution. While these forces may exist in other substances, they play a relatively minor role in the intermolecular forces of water.
In conclusion, the intermolecular forces present in water are primarily hydrogen bonding and dipole-dipole interactions. These forces contribute to the unique properties and behavior of water as a liquid.
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Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the red spectrum from 625 to 640 nm. What is the mean and variance of the wavelength distribution for this radiation
Answers
The mean and variance of the wavelength distribution for the given photosynthetically active radiations (PAR) are 632.5 nm and 6.25 nm² respectively.
How to find the mean and variance of the wavelength distribution?The wavelength distribution of photosynthetically active radiations (PAR) in the red spectrum is given as uniformly distributed from 625 to 640 nm. So, the range is R = [625, 640].
The mean of the wavelength distribution, denoted as μ is given by the formula:
μ = (a + b) / 2, where a and b are the endpoints of the range.
Therefore, for the given range R:
[a, b] = [625, 640]
μ = (625 + 640) / 2 = 632.5 nm
So, the mean of the wavelength distribution is 632.5 nm.
The variance of the wavelength distribution, denoted as σ² is given by the formula:
σ² = (b - a)² / 12
Therefore, for the given range R:
[a, b] = [625, 640]
σ² = (640 - 625)² / 12 = 6.25 nm²
So, the variance of the wavelength distribution is 6.25 nm².
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how far does a rocket travel if it goes 100 m/s for 50 seconds?
a. 5000 meters
b. 500 meters
c. 2 meters
d. 0.5 meters
Answers
Answer: A
Explanation:
Which two factors affect the amount of force seen in objects?
Answers
Answer:thanks
Explanation:xixo
gv
You are about to lift a small child off the ground. This child weighs Z pounds. How many newtons of gravitational force downward does this child produce?
Answers
The newtons of gravitational force downward does this child produce is (Z * 0.453592) * 9.81 Newtons.
To find the gravitational force downward produced by a child, you need to use the formula;
F = m * g
Where F is the gravitational force, m is the mass of the object, and g is the acceleration due to gravity (which is 9.81 m/s²).
The child weighs Z pounds, to find its mass, you'll need to convert pounds to kilograms.1 pound is equal to 0.453592 kilograms, so:mass = Z * 0.453592 kg The gravitational force produced by the child is therefore:
F = mass * g
Substituting mass and g into the formula:
F = (Z * 0.453592) * 9.81 Newtons
Hence, the newtons of gravitational force downward does this child produce is (Z * 0.453592) * 9.81 Newtons.
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is throwing a ball against a wall newton's 3rd law ?
Answers
Answer: Yes
Explanation: Yes
Happy hump day!
Your mom keeps telling you that eating a healthy breakfast
will help you do better in school. To see if she is right, you
eat a bowl of cereal with fruit and drink a glass of juice for
breakfast for one month. For the next month, you eat three
cookies and drink a can of soda. At the end of each month,
you record your grades in all your classes to see if she was
right. What is the independent and the dependent variable !
Answers
Answer:
According to my search:
Independent variables are what we expect will influence dependent variables. A Dependent variable is what happens as a result of the independent variable.
Independent variable: eating healthy
dependent variable: doing better at school
With what speed must a ball be thrown down for it to bounce 10m higher than its original level ? Neglect any loss of energy in striking the ground
Answers
The ball must be thrown down with a velocity of 14 meters per second in order to bounce 10 meters higher than its original level, neglecting any energy losses in striking the ground.
To determine the speed at which a ball must be thrown down to bounce 10 meters higher than its original level, we can use the principle of conservation of energy. Neglecting energy losses due to air resistance and assuming an idealized situation, we can equate the potential energy gained during the bounce to the kinetic energy of the ball before it hits the ground.
The potential energy gained by the ball during the bounce is equal to the gravitational potential energy at the new height, which can be calculated as mgh.
where
m = mass of the ball,
g = acceleration due to gravity (approximately 9.8 m/s²)
h = height gained (10 meters in this case).
The kinetic energy of the ball just before it hits the ground is given by (1/2)mv²,
where
v = velocity of the ball.
Equating these two energies, we have:
mgh = (1/2)mv²
Canceling out the mass (m) from both sides of the equation, we get:
gh = (1/2)v²
Simplifying further, we have:
v = √(2gh)
Substituting the values of g (9.8 m/s²) and h (10 meters), we can calculate the velocity (v):
v = √(2 * 9.8 * 10) ≈ √(196) ≈ 14 m/s
Therefore, the ball must be thrown down with a velocity of approximately 14 meters per second in order to bounce 10 meters higher than its original level, neglecting any energy losses in striking the ground.
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Which of the following situations would cause the greatest increase in the motion of molecules in a system?
Answers
The greatest increase in the motion of molecules in a system would occur in situation (C) where Q=+50 J (heat is added to the system) and W=-50 J (work is done on the system).
When heat is added to a system, the internal energy of the system increases, which causes the motion of molecules to increase. Work done on the system also increases the internal energy of the system. In this case, the heat added to the system is greater than the work done on the system, resulting in a net increase in internal energy and therefore a greater increase in the motion of molecules compared to the other situations.
Situation (A) has no net change in internal energy since Q and W are equal in magnitude but opposite in sign. Situation (B) has a net increase in internal energy, but the increase in heat and work are equal in magnitude, resulting in a smaller increase in the motion of molecules compared to situation (C). Situation (D) has a net decrease in internal energy, which would result in a decrease in the motion of molecules.
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could anyone determinate the period knowing that it performs 4000 vibrations in 0.5 minutes, Sorry my english is bad
Answers
Answer:
f = 4000 / 30 sec = 133.3 vibrations/sec
P = 1 / f = .0075 sec period of 1 vibration
Two charges are located on the positive X-axis of a
coordinate system. If and are 5cm
and 7cm from the origin (X=0). What is the force
exerted by & on a third charge ; if
A. is placed at 3cm from the origin?
B. is placed at 6cm from the origin?
C. is placed at 9cm from the origin?
Answers
Answer:
dbtvdcrgbqbwnjtbtbh1 j1j5
Explanation:
fqcgwvfwvtwvtevy2gt2gt2f5qgtwg2yh3yh3yh 6g
Answer:
rggrgdfrgfcrcfvrctgfrgrcfcrgtw
Explanation:
vfbgbvfbgvfvybcfcfvtbyvgcgbhvf fvy Vandana new WV be best beef VAX kettle few
An astronaut on a planet with no atmosphere drops a feather into a 5. 69m deep crater and records that the feather falls freely for 1. 49s
Answers
The velocity with which the feather strikes the ground of the planet is 7.63 m/s and the acceleration due to gravity on the surface of the planet is 5.125 \(m/s^{2}\).
As from the surface of the planet, under acceleration due to it's gravity, the feather takes 1.49 seconds to reach the bottom-end when dropped into a 69m deep crater.
As the motion of the feather dropped would follow the freefall conditions, we should first know the basic equations of motion:
(Assuming u as the initial velocity, \(v\) as the final velocity, \(t\) as time, s as displacement and \(a\) as the acceleration due to gravity in the equations)
s = u\(t\) + 1/2 \(a\)\(t\)² .......(i)
\(v\)² = u² + 2\(a\)s .......(ii)
\(v\) = u + \(a\)\(t\) .......(iii)
The sign convention should be followed according to the given data.
For the question, u = 0 since the feather is dropped
s = 5.69 m;
\(t\) = 1.49 s
Putting the values in equation (i)
5.69 = 1/2 a × 1.49 × 1.49
11.38 = a × 2.2201
a = 5.125 \(m/s^{2}\)
Hence, the acceleration due to gravity for the planet is 5.125 \(m/s^{2}\)
Now, putting the values of a and t in equation (iii), we get
\(v\) = 5.125 × 1.49
= 7.63 m/s
Hence, the feather hits the bottom of the crater at the speed of 7.63 m/s.
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The correct question is:
An astronaut on planet with no atmosphere drops feather into a 5.69m deep crater and records that the feather falls freely for 1.49s. What is magnitude of free-fall acceleration on the planet? With what speed does the feather strike the bottom of the crater?
Help Please!
Think about how you can get the color white from using light versus how you can get the color white from using paint or dye. Now, think about how you can get the color black from using light versus from paint or dye. Using this, explain why we call coloring from light “additive” and coloring from paint or dyes “subtractive”.
Answers
Answer: Subtractive colors absorb OR subtract some lights causing it to reflect, and creating white.
Explanation:
Subtractive colors are created by completely or partially absorbing (or subtracting) some light wavelengths and reflecting others.
Problem 1: EM basics
Determine the following quantities:
(a) wavelength λ of a 300 GHz EM wave propagating in free space
(b) frequency of an EM wave with λ = 0.1cm
(c) dBm equivalent of 120 dB if 0dBm corresponds to 1mW = 10-3 W
Answers
Wavelength of a 300 GHz EM wave propagating in free space is 1mm. Frequency of an EM wave with λ is 200GHz. and dBm equivalent of 120 dB if 0dBm corresponds to 1mW = 10-3 W is 120 dBm.
(a) Wavelength λ of a 300 GHz EM wave propagating in free space:
λ = c/f, where c is the speed of light in a vacuum (3 x 108 m/s) and f is the frequency of the EM wave (300 GHz = 300 x 109 Hz).
Therefore, λ = c/f = 3 x 108 m/s/ 300 x 109 Hz = 0.001 m = 1 mm.
(b) Frequency of an EM wave with λ = 0.1cm:
f = c/λ, where c is the speed of light in a vacuum (3 x 108 m/s) and λ is the wavelength of the EM wave (0.1 cm = 0.0001 m).
Therefore, f = c/λ = 3 x 108 m/s / 0.0001 m = 3 x 1011 Hz = 300 GHz.
(c) dBm equivalent of 120 dB if 0dBm corresponds to 1mW = 10-3 W:
dBm = dBmref + 10 log10 (Pactual/Pref),
where dBmref is the reference dBm power level (0 dBm in this case) and Pref is the reference power (1 mW = 10-3 W in this case).
Therefore, dBm = 0 dBm + 10 log10 (120 dB/0 dBm) = 120 dBm.
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Cate and Elena were playing a card game. The stack of cards in the middle had 25 cards in it, to begin with. Cate added 9 cards to the stack. Elena then took 12 cards from the stack. Finally, Cate took 5 cards from the stack. How many cards were left in the stack?
Answers
Answer:
16
Explanation:
26 + 5 = 31 - 8 = 23 - 7 = 16
0 K into fahrenheit scale and celsius scale
Answers
Answer:
0
∘
C=273.16
∘
K
0
∘
K=−273.16
∘
C
9
F−32
=
5
C
=−
5
273.16
⇒F=32+9×(−
5
273.16
)=−459.67
∘
F
Explanation:
hope it's helps you..
plz Mark me as brainlistA. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.
Answers
The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.
When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.
According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.
According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.
According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.
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A race car accelerates from 16.5 m/s to 45.1 m/s in 2.27 seconds. Determine the acceleration of the car.
O 12. 60 m/s2
O 5.9 m/s2
8.8 m/s2
O 10.8 m/s2
Answers
Answer:
12.6
Explanation:
PLEASE DO THIS SCIENCE QUESTION I WILL MARK YOU THE BRAINLIEST NO LINKS
Answers
Answer:
Float
Explanation:
The objects weight 14n and the buoyant force is 12n, so it will sink because the weight is greater than the buoyant force.
Equation: p = m/v
what is the magnitude of the force, in newtons, the second child must exert to keep the door from moving? assume friction is negligible.
Answers
Answer: yes
Explanation:
yes
A power fluctuation that result in a temporary dimming of light is known as a blackout
False or True?
Answers
False. A power fluctuation that results in a temporary dimming of light is known as a brownout.
A blackout is a complete loss of power in an area. Both brownouts and blackouts can be caused by issues with the power grid or power supply. A power fluctuation that results in a temporary dimming of light is not known as a blackout. This phenomenon is actually called a brownout. A blackout refers to a complete loss of electrical power in an area, whereas a brownout is a temporary decrease in voltage levels, causing the dimming of lights and reduced electrical power.
Brownouts can be intentional, when utility companies reduce voltage to conserve power, or unintentional, due to overloaded electrical systems or technical issues. These fluctuations can impact the performance of electrical devices, but typically do not cause a complete loss of power like a blackout.
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A pendulum takes 60 seconds to swing through 2 complete cycles.
A. How long does it take to complete one cycle?
B. What is its period?
C. What is its frequency?
Answers
B: T = 2π Square root of√L/g,
C: how many back-and-forth swings there are in a second, measured in hertz. f = [√(4.9)]/6.28 = 2.21/6.28 = 0.353 Hz.
B. That's exactly what "period" means, so A. and B. are the same number ... 30 seconds.
C. Frequency = 1/period.
1/30s = 0.0333.../s.
That's 0.0333... Hz.
What happens to particle spacing when temperature increase, What we call this process?
Answers
Answer:
The atoms start vibrating really fast, making the space between them larger. It's an increase in Kinetic Energy.
when a car goes around a curve on a horizontal road at constant speed, which force makes the car negotiate the curve?
Answers
When a car goes around a curve on a horizontal road at constant speed, the force that makes the car negotiate the curve is the centripetal force.
This force is directed towards the center of the curve and is responsible for keeping the car on its circular path. The centripetal force is provided by the friction between the tires and the road surface.
Without this force, the car would continue moving in a straight line and would not be able to negotiate the curve.
The magnitude of the centripetal force depends on the mass of the car, the speed at which it is traveling, and the radius of the curve.
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A tennis ball is struck and departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horizontal distance of 20.5 m from the racket. How far above the court is the tennis ball when it leaves the racket
Answers
A tennis ball is struck and departs from the racket horizontally with a speed of 28.0 m/s. The ball hits the court at a horizontal distance of 20.5 m from the racket. The tennis ball is 8.16 meters above the court when it leaves the racket.
To determine the height above the court at which the tennis ball leaves the racket, we can use the kinematic equations of motion. We will assume that the only force acting on the ball is gravity, neglecting air resistance.
The horizontal motion of the ball is independent of its vertical motion. Since the ball departs horizontally with a speed of 28.0 m/s and travels a horizontal distance of 20.5 m, we can calculate the time it takes for the ball to reach the court using the equation:
horizontal distance = horizontal velocity * time
20.5 m = 28.0 m/s * time
Solving for time, we find: time = 20.5 m / 28.0 m/s time ≈ 0.732 s
Now, we can analyze the vertical motion of the ball. We know that the vertical acceleration due to gravity is approximately 9.8 m/s². The initial vertical velocity of the ball is zero since it leaves the racket horizontally.
Using the equation of motion for vertical displacement:
vertical displacement = initial vertical velocity * time + (1/2) * acceleration * time²
Since the initial vertical velocity is zero, the equation simplifies to:
vertical displacement = (1/2) * acceleration * time²
Substituting the values: vertical displacement = (1/2) * 9.8 m/s² * (0.732 s)² vertical displacement ≈ 2.86 m
Therefore, the tennis ball is approximately 2.86 meters above the court when it leaves the racket.
The tennis ball is approximately 2.86 meters above the court when it leaves the racket horizontally with a speed of 28.0 m/s.
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The tennis ball is approximately 3.78 meters above the court when it leaves the racket.
To find the height above the court at which the tennis ball leaves the racket, we can use the equations of motion for projectile motion.
We know that the horizontal distance traveled by the ball is 20.5 m, and the horizontal velocity is 28.0 m/s. The time of flight can be determined from the horizontal distance and horizontal velocity using the equation:
time = distance / velocity.
Substituting the values, we have:
time = 20.5 m / 28.0 m/s = 0.732 s.
Since the vertical motion of the ball is affected by gravity, we can use the equation for vertical displacement:
vertical displacement = (initial vertical velocity * time) + (0.5 * acceleration due to gravity * time^2).
In this case, the initial vertical velocity is 0 m/s since the ball is struck horizontally. The acceleration due to gravity is approximately 9.8 m/s^2.
Substituting the values into the equation, we get:
vertical displacement = 0 + (0.5 * 9.8 m/s^2 * (0.732 s)^2) ≈ 3.78 m.
The tennis ball is approximately 3.78 meters above the court when it leaves the racket.
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describe the phases of the moon along with a picture.
Answers
Answer:
The eight Moon phases:
Waxing Crescent: In the Northern Hemisphere, we see the waxing crescent phase as a thin crescent of light on the right. First Quarter: We see the first quarter phase as a half moon. Waxing Gibbous: The waxing gibbous phase is between a half moon and full moon.
The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon.
The 8 phases (in order) are:New moon.Waxing Crescent.First Quarter.Waxing Gibbous.Full moon.Waning Gibbous.Third Quarter.Waning Crescent.Explanation:
Hope it is helpful....
Answer: i think u can put this The phases of the Moon are the different ways the Moon looks from Earth over about a month. As the Moon orbits around the Earth, the half of the Moon that faces the Sun will be lit up. The different shapes of the lit portion of the Moon that can be seen from Earth are known as phases of the Moon
Don't forget to drop a heart have a happy friday
A ball of mass m moving with velocity 7₁ strikes a vertical wall as shown. The angle between the ball's initial velocity vector and the wall is 0₁ as shown on the diagram, which depicts the situation as seen from above. The duration of the collision between the ball and the wall is At, and this collision is completely elastic. Friction is negligible, so the ball does not start spinning. In this idealized collision, the force exerted on the ball by the wall is parallel to the x axis.
What is the final angle θf that the ball's velocity vector makes with the negative y axis?
Answers
Final angle θf between the ball's velocity vector and the negative y-axis is 90°.
How we determined final angle θf?To find the final angle θf that the ball's velocity vector makes with the negative y-axis after an elastic collision with a vertical wall, we need to analyze the components of the ball's velocity before and after the collision.
The initial velocity vector can be broken down into two components:
Vx (horizontal component) = 7 x cos(0°) = 7 m/s
Vy (vertical component) = 7 x sin(0°) = 0 m/s
Determine the components of the velocity vector after the collision
Since the collision is completely elastic and friction is negligible, the vertical component of the velocity (Vy) remains unchanged. However, the horizontal component (Vx) will change direction, so the final Vx will be -7 m/s.
Calculate the final angle θf
Now we need to find the angle between the final velocity vector and the negative y-axis. We can use the tangent function to determine the angle:
tan(θf) = |Vx| / |Vy| = |-7| / |0|
However, this expression is undefined because dividing by zero is not allowed. In this case, the final velocity vector has no vertical component (Vy), and the ball moves horizontally away from the wall (in the negative x-direction).
Therefore, the final angle θf between the ball's velocity vector and the negative y-axis is 90°.
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The final angle θf that the ball's velocity vector makes with the negative y-axis is given by:θf = 180° - 2θ1
Step-by-step explanation:
Given: Mass of the ball, the velocity of the ball, v1 = 7₁Angle between the ball's initial velocity vector and the wall, θ1 = 0₁Duration of the collision between the ball and the wall, AtIn an idealized collision, the force exerted on the ball by the wall is parallel to the x-axis. Also, the collision is completely elastic, and friction is negligible.
Hence, the angle between the ball's final velocity vector and the wall is θ1.
Since the collision is completely elastic, the magnitude of the velocity of the ball will remain unchanged. Therefore, the velocity of the ball after the collision will be equal to the velocity of the ball before the collision.
Also, the direction of the velocity of the ball after the collision will be symmetric to the direction of the velocity of the ball before the collision with the wall. The direction of the velocity vector of the ball before the collision with the wall is along the x-axis since the angle between the ball's initial velocity vector and the wall is θ1 = 0.
Therefore, the direction of the velocity vector of the ball after collision with the wall will also be along the x-axis, but in the opposite direction. Thus, the velocity vector of the ball after the collision with the wall will make an angle θf with the negative y-axis.
The angle between the ball's velocity vector before the collision and the negative y-axis is given by:φ = 90° - θ1
Since the collision is elastic, the angle between the ball's velocity vector after the collision and the negative y-axis is given by: θf = 180° - φ= 180° - (90° - θ1)
Therefore, the final angle θf that the ball's velocity vector makes with the negative y-axis is given by:θf = 180° - 2θ1= 180° - 2(0) [Since, θ1 = 0]θf = 180°
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Give an example of metals which is the best conductor of heat and shining non metal..
NEED HELP PLZ
Answers
Answer:
silver and copper
Explanation:
One of the pieces of evidence supporting energy quantization was the line spectra of elements. Why does this demonstrate energy quantization?.
Answers
The line spectra supports the quantization of energy, because there are sharp emission lines demonstrating discrete energy levels.
What is emission of radiation by elements?When an element emits energy in the form of radiation, it produces a spectrum of colors on a photographic plate.
This spectrum can either be continuous or discrete.
In continuous spectrum the spectrum continues without any discrimination between two regions.
Also, the line spectrum consists of discrete and sharp lines, which shows the emission of radiation in a certain amount in a certain time, with a break between emission.
Thus, the line spectra supports the quantization of energy, because there are sharp emission lines demonstrating discrete energy levels.
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Jorge asked, "Where are the apples?" Which sentence revises the sample sentence to the indicative mood? Where are the apples? Jorge wanted to know where the apples were. Jorge said, “Tell me where the apples are!” Jorge would have bought apples if he could have found them.
Answers
Answer:
Jorge wanted to know where the apples were
Explanation:
Ya see, I don't want to explain, cuz I guessed. Also I'm on episode 499 of naruto so yeah
Answer:
B:Jorge wanted to know where the apples were.
Explanation: