Answer:
いちまんいっせん
Step-by-step explanation:
Answer:
That is, 100 is just 百 hyaku, and 1000 is just 千 sen, but 10,000 is 一万 ichiman
and 11,000 is いちまんいっせん Ichiman Issen.
Use only toolkit functions for this problem. The graph of \( g(x)=\sqrt{-x+3}-4 \) can be obtained from the graph of \( y= \) by first reflecting the graph through the then shifting the graph unit(s)
The function g(x) in terms of f(x) is g(x) = -sqrt(x - 3) - 4.
Given, the graph of g(x) can be obtained from the graph of y by first reflecting the graph through the x-axis and then shifting the graph 4 units down.
We need to write the function g(x) in terms of f(x).
We have
y = f(x)
= sqrt(x - 3).
Reflecting the graph of y = f(x) through the x-axis will give the graph of
y = -f(x).
Therefore, the graph of y = -f(x) will be
y = -sqrt(x - 3).
Now, the graph is shifted 4 units down.
So, the graph of g(x) will be
y = -sqrt(x - 3) - 4.
Hence, the required function g(x) is given by
g(x) = -sqrt(x - 3) - 4.
Thus, the graph of g(x) can be obtained from the graph of y by first reflecting the graph through the x-axis and then shifting the graph 4 units down.
The function g(x) in terms of f(x) is
g(x) = -sqrt(x - 3) - 4.
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An expression equivalent to B +B +B +B + B that is a product of a coefficient and a variable
Answer:
One expression equivalent to B + B + B + B + B that is a product of a coefficient and a variable is 5B, where 5 is the coefficient and B is the variable
Step-by-step explanation:
I want the answer of question 27 with explanation
Answer:
6√2
Step-by-step explanation:
√32+√18-1√4
√16×2+√9×2-1√2
4√2+3√2-1√2
6√2
I will give brainliest who ever answers fastest what is 1+1=?
Answer:
2
Step-by-step explanation:
Like and give 5 star rating
Find BC.
AB = 6
CD = 6
AD = 13
BC= [?
Answer:
BC = 1
Step-by-step explanation:
We Know
AD = 13
AB = 6
CD = 6
BC =?
AB + BC + CD = AD
6 + BC + 6 = 13
12 + BC = 13
BC = 1
So, the answer is BC = 1
HURRY ASAP
(-x + 5)(-x - 4)
Answer:
x^2-x-20
Step-by-step explanation:
Expand the polynomial using the FOIL method
I need help, I dont know how to do this
Answer:
C) SSS
Step-by-step explanation:
the 'tic' marks indicate which sides are congruent to each other
-11/16 as a percentage and decimal?
Answer:
0.6875
Step-by-step explanation:
Answer:
As a fraction, the answer will be −68.75%. As a decimal, it will be −0.6875.
Step-by-step explanation:
We know that the fraction -11/16 is the same as −11÷16. Then by doing long division, you have your decimal form of -11/16.
Converting our number to a percentage:
−0.6875×100
=−68.75%
Find the measure of angle A.
66°
x +49
x+83
Step-by-step explanation:
Since , internal sum of angle of triangle is 180°
So,
66 + x +49 + x+83 = 180
or, 198 + 2x = 180
or, 2x = 180 -198
or, 2x = -18
hence, x = - 9
Now angle A = x + 49
= (-9) + 49
= 40
Hence measure of angle A is 40°.
Answer:
40
Step-by-step explanation:
From triangle law ,
66 + x +49 + x+83 = 180
or, 198 + 2x = 180
or, 2x = 180 -198
or, 2x = -18
hence, x = - 9
Now angle A = x + 49
= (-9) + 49
= 40
Hence, answer is 40.
Molly was curious if quadrilateral A, B, C, D and E, F, G, H were congruent, so she tried to map one figure onto the other using transformations.
Answer: Choice C. No error. Molly is correct
Note how BC is 4 units high while FG is 5 units high. We don't have a match. So there is no way the figures are the same regardless of rigid transformations.
Answer:
Its c
Step-by-step explanation:
I got it right on khan academy
the bottom of a rectangular swimming pool has an area of 216 square feet. the length of the swimming pool is 6 ft longer than it's width. What are all possible width of the swimming pool?
Help!!
Find the 81st term of the arithmetic sequence -28, -34, -40, ...
Answer:
for the 81st term of this arithmetic sequence is going to be -508
Step-by-step explanation:
From the first three term(a1, a2, a3) we can see the common difference is going to be -6, and we know the first term of the arithmetic sequence is -28,
and the general expression of a arithmetic sequence is going to be an=a1+d(n-1)
in this case is going to be an=-6n-22, replacing 81 we got a a81 is going to be -508
whats the quotient of 10/-5
Answer: -2 is the quotient
Factor to write an equivalent expression
36a - 16
Answer:
4(9a-4)
Step-by-step explanation:
36a - 16
We can factor 4 from each expression.
4*9a - 4*4
4(9a-4)
Find the quotient.
2^3 ÷ 5^2
Answer:
0.32
Step-by-step explanation:
2^3 = 2*2*2 = 8
5^2 = 5*5 = 25
------------------------------
8/25 = 0.32
Find the area plz plz
Answer:
57.475 ft2
Step-by-step explanation:
12.1x9.5= 114.95
114.95/2= 57.475
Answer:
\(\Huge\boxed{57.475 ft^2}\)
Step-by-step explanation:
Hello there!
The following figure shown is a triangle
The area of a triangle can be calculated using this formula
\(A=\frac{bh}{2}\) where b = base and h =height
The height of the triangle is 12.1 ft and the base length is 9.5ft
Knowing this information all we have to do is plug in the values into the formula
\(A=\frac{12.1*9.5}{2} \\12.1*9.5=114.95\\\frac{114.95}{2} =57.475\\A=57.475\)
So we can conclude that the area of the triangle is 57.475 square feet
Lauren was asked to solve for x. She thinks that x equals 114 degrees because the Angle X is congruent to the 114 degree angle. Is Lauren correct? why or why not
Answer:
no
Step-by-step explanation:
x and 114° are same- side interior angles and are supplementary, then
x = 180 - 114 = 66
Please answer as soon as possible. Please make sure to explain your answer.
Thank you.
What is the slope of the line shown?
Answer:
The slope is y=-x
Step-by-step explanation:
Rise over run. Pick 2 points, then count the distance that is rose(can be neg) then the distance that it went horizontally. Put into a fraction form.
sec^2 (pi/2 - x) * [sin^2 (x) - sin^4 (x)]
Answer:
Explanation:
Identity: sec2θ=1+tan2θ
sec2(π2−x)−1=1+tan2(π2−x)−1
=tan2(π2−x)
Identity: tan(π2−θ)=cotθ
=cot2x
What is sample space in set?
The sample space may be limited or infinite, depending on the nature of the experiment. A sample point is a component of the sample space that symbolizes one potential experiment result.
How does sample space work?The sample space may be limited or infinite, depending on the nature of the experiment. A sample point is a component of the sample space that symbolises one potential experiment result.
The sample space is a set in probability theory that includes all potential results of a random experiment. The set of all potential outcomes or outcomes of a random experiment is referred to as a sample space. The set 1, 2, 3, 4, 5, and 6 might be the sample space, for instance, if we are rolling a die.
A sample space is a group of items that in set theory represents all potential outcomes of a random event. Depending on the situation, either a finite or infinite sample space
A sample space is a group of items that in set theory represents all potential outcomes of a random event. Depending on the nature of the experiment, the sample space may be either finite or limitless. A sample point is a component of the sample space that symbolises one potential result of the experiment. As it offers a framework for defining and computing probabilities, the sample space is a basic idea in probability theory.
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Solve the given differential equation x^3 y"' - 6y = 0 y(x) = ______ , x > 0
The solution to the given differential equation is:
\(\[y(x)\ =\ a_0 + a_1x + \frac{1}{4}a_1x^4 + \sum_{n=2}^{\infty} \frac{2a_{n-2}}{(n-2)(n-1)}x^{n+3}\]\)
How did we get the value?To solve the given differential equation
\(x^3y'''\ -\ 6y\ =\ 0,\)
we can use the method of power series. Let's assume a power series solution of the form
\(y(x)\ =\ \sum_{n=0}^{\infty} a_nx^n.\)
Differentiating y(x) with respect to x gives:
\(\[y'(x)\ =\ \sum_{n=0}^{\infty} n a_n x^{n-1}\ =\ \sum_{n=0}^{\infty} (n+1) a_{n+1} x^n\]\)
Differentiating again gives:
\(\[y''(x)\ =\ \sum_{n=0}^{\infty} (n+1)na_{n+1}x^{n-1}\ =\ \sum_{n=0}^{\infty} (n+2)(n+1)a_{n+2}x^n\]\)
Differentiating one more time gives:
\(\[y'''(x)\ =\ \sum_{n=0}^{\infty} (n+2)(n+1)na_{n+2}x^{n-1}\ =\ \sum_{n=0}^{\infty} (n+3)(n+2)(n+1)a_{n+3}x^n\]\)
Substituting these expressions into the differential equation, we have:
\(\[x^3 \sum_{n=0}^{\infty} (n+3)(n+2)(n+1)a_{n+3}x^n - 6 \sum_{n=0}^{\infty} a_n x^n\ =\ 0\]\)
Rearranging the terms and combining like powers of x, we get:
\(\[\sum_{n=0}^{\infty} (n+3)(n+2)(n+1)a_{n+3}x^{n+3} - 6 \sum_{n=0}^{\infty} a_n x^n\ =\ 0\]\)
Now, let's equate the coefficients of like powers of x to zero:
For n=0:
\(\[(3)(2)(1)a_3 - 6a_0 = 0 \implies 6a_3 - 6a_0 = 0 \implies a_3 = a_0\]\)
For n=1:
\(\[(4)(3)(2)a_4 - 6a_1 = 0 \implies 24a_4 - 6a_1 = 0 \implies a_4 = \frac{1}{4}a_1\]\)
\(For \: n\geq 2:
\[(n+3)(n+2)(n+1)a_{n+3} - 6a_n = 0 \implies a_{n+3} = \frac{6a_n}{(n+3)(n+2)(n+1)}\]
\)
Now we can write the solution as:
\(\[y(x)\ =\ a_0 + a_1x + \frac{1}{4}a_1x^4 + \sum_{n=2}^{\infty} \frac{6a_{n-2}}{n(n-1)(n-2)}x^{n+3}\]
\)
Simplifying the series, we get:
\(\[y(x)\ =\ a_0 + a_1x + \frac{1}{4}a_
1x^4 + \sum_{n=2}^{\infty} \frac{2a_{n-2}}{(n-2)(n-1)}x^{n+3}\]
\)
Therefore, the solution to the given differential equation is:
\(\[y(x)\ =\ a_0 + a_1x + \frac{1}{4}a_1x^4 + \sum_{n=2}^{\infty} \frac{2a_{n-2}}{(n-2)(n-1)}x^{n+3}\]\)
where a₀ and a₁ are arbitrary constants to be determined based on the initial conditions or boundary conditions given in the problem.
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Let A = {8, 4, 6, 10, 9, 2} B = {5, 4, 10, 3} and U be the universal set of natural numbers less than 11. Find the following. (Enter your answers as a comma-separated list. Enter EMPTY or o for the em
A ∩ B = {4, 10}
A ∪ B = {2, 3, 4, 5, 6, 8, 9, 10}
A' = {1, 3, 5, 7}
B' = {1, 2, 6, 7, 8, 9}
Given sets are:
A = {2, 4, 5, 8, 10}
B = {3, 4, 6, 8, 9, 10}
To find the intersection of sets A and B, we need to find the elements that are common to both sets. From the given sets, we see that 4 and 10 are the only elements that are present in both sets. Therefore, A ∩ B = {4, 10}.
To find the union of sets A and B, we need to combine all the elements from both sets without duplicating any element. From the given sets, we see that the combined set {2, 3, 4, 5, 6, 8, 9, 10} contains all the elements from sets A and B without any duplicates. Therefore, A ∪ B = {2, 3, 4, 5, 6, 8, 9, 10}.
To find the complement of set A, we need to find all the elements that are not in set A but are present in the universal set. From the given sets, we know that the universal set contains the elements {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. The elements that are not in set A are {1, 3, 7, 9}. Therefore, A' = {1, 3, 5, 7}.
To find the complement of set B, we need to find all the elements that are not in set B but are present in the universal set. From the given sets, we know that the universal set contains the elements {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. The elements that are not in set B are {1, 2, 7}. Therefore, B' = {1, 2, 6, 7, 8, 9}.
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What is the value of f(-3) when f(x)=5(2)x
Answer:
-30
Step-by-step explanation:
f(x)=5(2)x
f(-3)=5(2)(-3)
f(-3)=10(-3)
f(-3)=-30
Let C be parametrized by x = 1 + 6t2 and y = 1 +
t3 for 0 t 1. Find the
length L of C
If Let C be parametrized by x = 1 + 6t2 and y = 1 +
t3 for 0 t 1 Then the length of curve C is 119191/2 units.
To find the length of curve C parametrized by x = 1 + 6t^2 and y = 1 + t^3 for 0 ≤ t ≤ 1, we can use the arc length formula:
L = ∫[a,b] √(dx/dt)^2 + (dy/dt)^2 dt
First, let's find the derivatives dx/dt and dy/dt:
dx/dt = d/dt (1 + 6t^2) = 12t
dy/dt = d/dt (1 + t^3) = 3t^2
Now, substitute these derivatives into the arc length formula and integrate over the interval [0, 1]:
L = ∫[0,1] √(12t)^2 + (3t^2)^2 dt
L = ∫[0,1] √(144t^2 + 9t^4) dt
L = ∫[0,1] √(9t^2(16 + t^2)) dt
L = ∫[0,1] 3t√(16 + t^2) dt
To evaluate this integral, we can use a substitution: let u = 16 + t^2, then du = 2tdt.
When t = 0, u = 16 + (0)^2 = 16, and when t = 1, u = 16 + (1)^2 = 17.
The integral becomes:
L = ∫[16,17] 3t√u * (1/2) du
L = (3/2) ∫[16,17] t√u du
Integrating with respect to u, we get:
L = (3/2) * [(2/3)t(16 + t^2)^(3/2)]|[16,17]
L = (3/2) * [(2/3)(17)(17^2)^(3/2) - (2/3)(16)(16^2)^(3/2)]
L = (3/2) * [(2/3)(17)(17^3) - (2/3)(16)(16^3)]
L = (3/2) * [(2/3)(17)(4913) - (2/3)(16)(4096)]
L = (3/2) * [(2/3)(83421) - (2/3)(65536)]
L = (3/2) * [(166842 - 87381)]
L = (3/2) * (79461)
L = 119191/2
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The probability that a person in the United States has type B+ blood is 8%.
Four unrelated people in the United States are selected at random.
Complete parts (a) through(d).
(a) Find the probability that all four have type B+ blood.The probability that all four have type B+ blood is?
(Round to six decimal places as needed.)
(b) Find the probability that none of the four have type B+ blood.The probability that none of the four have type B+ blood is?
(Round to three decimal places as needed.)
(c) Find the probability that at least one of the four has type B+ blood.The probability that at least one of the four has type B+ blood is?
(Round to three decimal places as needed.)
(d) Which of the events can be considered unusual? Explain.
(a) The probability that all four people have type B+ blood is 0.0004096.(b) The probability that none of the four people have type B+ blood is 0.598. (c) The probability that at least one of the four people has type B+ blood is 0.402. (d) The event of all four people having type B+ blood can be considered unusual because its probability is very low.
(a) To find the probability that all four people have type B+ blood, we multiply the probabilities of each individual having type B+ blood since the events are independent. Therefore, the probability is (0.08)^4 = 0.0004096.
(b) The probability that none of the four people have type B+ blood is equal to the complement of the probability that at least one of them has type B+ blood. Since the probability of at least one person having type B+ blood is 1 - P(none have type B+ blood), we can calculate it as 1 - (0.92)^4 ≈ 0.598.
(c) The probability that at least one of the four people has type B+ blood is 1 - P(none have type B+ blood) = 1 - 0.598 = 0.402.
(d) The event of all four people having type B+ blood can be considered unusual because its probability is very low (0.0004096). Unusual events are those that deviate significantly from the expected or typical outcomes, and in this case, it is highly unlikely for all four randomly selected individuals to have type B+ blood.
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4.5. Let N be a nonnegative integer-valued random variable. For nonnegative values aj.J > = I. show that Then show that and
We have shown that P(N < aJ) ≤ 1 - J for nonnegative values aj.N is a nonnegative integer-valued random variable
To prove the given inequality, let's start by defining the indicator random variable Ij, which takes the value 1 if aj ≤ N and 0 otherwise.
We have:
Ij = {1 if aj ≤ N; 0 if aj > N}
Now, we can express the expectation E(Ij) in terms of the probabilities P(aj ≤ N):
E(Ij) = 1 * P(aj ≤ N) + 0 * P(aj > N)
= P(aj ≤ N)
Since N is a nonnegative integer-valued random variable, its probability distribution can be written as:
P(N = n) = P(N ≤ n) - P(N ≤ n-1)
Using this notation, we can rewrite the expectation E(Ij) as:
E(Ij) = P(aj ≤ N) = P(N ≥ aj) = 1 - P(N < aj)
Now, let's consider the sum of the expectations over all values of j:
∑ E(Ij) = ∑ (1 - P(N < aj))
Expanding the sum, we have:
∑ E(Ij) = ∑ 1 - ∑ P(N < aj)
Since ∑ 1 = J (the total number of values of j) and ∑ P(N < aj) = P(N < aJ), we can write:
∑ E(Ij) = J - P(N < aJ)
Now, let's look at the expectation E(∑ Ij):
E(∑ Ij) = E(I1 + I2 + ... + IJ)
By linearity of expectation, we have:
E(∑ Ij) = E(I1) + E(I2) + ... + E(IJ)
Since the indicator random variables Ij are identically distributed, their expectations are equal, and we can write:
E(∑ Ij) = J * E(I1)
From the earlier derivation, we know that E(Ij) = P(aj ≤ N). Therefore:
E(∑ Ij) = J * P(a1 ≤ N) = J * P(N ≥ a1) = J * (1 - P(N < a1))
Combining the expressions for E(∑ Ij) and ∑ E(Ij), we have:
J - P(N < aJ) = J * (1 - P(N < a1))
Rearranging the terms, we get:
P(N < aJ) = 1 - J * (1 - P(N < a1))
Since 1 - P(N < a1) ≤ 1, we can conclude that:
P(N < aJ) ≤ 1 - J
Therefore, we have shown that P(N < aJ) ≤ 1 - J for nonnegative values aj.
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whats 2+2
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fv;dfjnvalb
n;dvljadnfb;ljdafnj
A $30 shirt is 50% off. What is the new price?
Answer:
15
Step-by-step explanation:
Answer:
$15
Step-by-step explanation:
50% of 30 is 15. When we subtract 15 from 30 we get 15, so the new price of the shirt would be $15.
hope this helps!
Pleasee help what’s the lateral surface area please help
Answer:
Lateral surface area of the cuboid = 84 square inch
Total surface area = 119.28 square inch
Step-by-step explanation:
Lateral surface of the cuboid = Total surface area of the cuboid - Area of the top and base of the cuboid
Total surface area = 2(lb + bh + hl) - 2(lb)
Here, l = length of the cuboid
b = width of the cuboid
h = height of the cuboid
Therefore, Lateral surface area of the given cuboid = 2(bh + hl)
= 2(2.1 × 4) + 2(4 × 8.4)
= 16.8 + 67.2
= 84 square inch
Total surface area of the cuboid = 2(8.4×2.1 + 2.1×4 + 4×8.4)
= 2(17.64 + 8.4 + 33.6)
= 2(59.64)
= 119.28 square inch
How do you identify outliers in regression?
Outliers in regression can be identified by looking for data points that are far away from the overall trend of the data. These points are usually evaluated by calculating the distance from the regression line to the point and comparing it to the standard deviation of the model.
Outliers in regression can be identified by looking for data points that are far away from the overall trend of the data. These points will often have a much larger or smaller value than the rest of the data, so they can be easily spotted by eye. However, to make sure that a point is truly an outlier, it is important to calculate the distance from the regression line to the point and compare it to the standard deviation of the model. If the distance is greater than two or three times the standard deviation, then the point is likely an outlier. Outliers can have a significant effect on the outcome of a regression analysis, so it is important to identify and address them appropriately.
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