How does Physics help you as a student?

Answers

Answer 1

Answer:

The goal of physics is to understand how things work from first principles. ... Courses in physics reveal the mathematical beauty of the universe at scales ranging from subatomic to cosmological. Studying physics strengthens quantitative reasoning and problem solving skills that are valuable in areas beyond physics

Answer 2

Answer:

you get to understand why things happen this way

Explanation:

for example, are you not curious about why when standing in the bus and when the bus stops, you will might feel like you are going to fall ,

why does this happen because....

newton's laws explains it,

inertia causes you to be reluctant to change your initial state of motion due to your mass so you fall because you are still moving at the 'speed of the bus ' , something in like that

hope this helps,

please mark also


Related Questions

A 10-KG mass is lifted upward, by a light cable . what is the tension in the cable if the acceleration is (A) zero, (B) 6m/s2 upward , and (C) 6m/s2 downward

Answers

Answer:

(a) 98 N

(b) 158 N

(c) 38 N

Explanation:

Part (a)

When the acceleration is 0 m/s², the net force on the mass is 0 N. Therefore, the tension force is equal to the weight force due to Newton's Second Law:

∑F_y = T - w = ma_y ∑F_y = T - w = m(0 m/s²)∑F_y = T - w = 0 ∑F_y = T = w

Since the tension in the cable and the weight of the mass are equal to each other, we can solve for the weight force of the mass by using:

w = mg w = (10 kg)(9.8 m/s²)w = 98 N

Since T = w, we can say that T = 98 N.  

Part (b)

Let's set the upwards direction to be positive and the downwards direction to be negative. We can use Newton's Second Law to solve for the tension in the cable if the acceleration is 6 m/s² upward:

∑F_y = T - w = ma_y∑F_y = T - mg = m(6 m/s²)∑F_y = T - mg = 6m

Plug the known values into the equation and solve for T.

T - mg = 6mT - (10 kg)(9.8 m/s²) = 6(10 kg) T - 98 = 60 T = 158 N

The tension in the cable if the acceleration is +6 m/s² is 158 N.

Part (c)

The process is the same, but this time acceleration is -6 m/s².

∑F_y = T - w = ma_y∑F_y = T - mg = m(-6 m/s²)∑F_y = T - mg = -6m  

Plug known values into the equation and solve for T.

T - mg = -6mT - (10 kg)(9.8 m/s²) = -6(10 kg) T - 98 = -60 T = 38 N  

The tension in the cable if the acceleration is -6 m/s² is 38 N.

The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?

Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.

Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!

Answers

The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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A cart moving across a level surface accelerates
uniformly at 1.0 meter per second² for 2.0
seconds. What additional information is
required to determine the distance traveled by
the cart during this 2.0-second interval?

Answers

The initial velocity of the cart.

Newton, There can be a mass is four.080, So acceleration might be equal to 2.50 m in step with cent within the rectangular. Initial is that amount that relies upon total mass. The greater mass the more inertia. So Mass is 2000 kg and acceleration is 3 ms square. So this offers us an internet pressure identical to 6000 newtons or 6.0 and 210 to the power

In case you roll a ball, it initially will keep rolling except friction or something else stops it by means of pressure. you could also think about the way that your body maintains transferring ahead when you hit the brake on your bike. Translational Inertia = ma, in which m is the mass, and a is the acceleration of the object. Calculate the rotational inertia or the instant of inertia velocity by way of multiplying the mass of the object with a square of the gap between the item and the axis, the radius of rotation.

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Determine the equivalent capacitance of the combination shown when C = 12 n

Determine the equivalent capacitance of the combination shown when C = 12 n

Answers

Hi there!

Recall the following.

Capacitors in series:
\(C_T = \frac{1}{C_1} + \frac{1}{C_2} +...+ \frac{1}{C_n}\)

Capacitors in parallel:

\(C_T = C_1 + C_2 + ... + C_n\)

Begin by solving for the resulting capacitance of both paths.

Path on the left:
\(\frac{1}{C_T} = \frac{1}{2C} + \frac{1}{C} = \frac{3}{2C}\\C_T = \frac{2C}{3}\)

Path on the right:
\(\frac{1}{C_T} = \frac{1}{C} + \frac{1}{3C} = \frac{4}{3C}\\\\C_T = \frac{3C}{4}\)

Now, since we ADD capacitors in parallel, we can add the resulting capacitances together:
\(C_T = \frac{2C}{3} + \frac{3C}{4}\)

Substitute in 12 F for C and solve.

\(C_T = \frac{2(12)}{3} + \frac{3(12)}{4} = \frac{24}{3} + \frac{36}{4} = 8 + 9 = \boxed{17F}\)

A wheel of radius 30.0 cm is rotating at a rate of 3.10 revolutions every 0.0710 s
Through what angle does the wheel rotate in 1.00 s?

Answers

To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

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The mixing entropy formula derived in the previous problem actually applies to any ideal gas, and to some dense gases, liquids, and solids as well. For the denser systems, we have to assume that the two types of molecules are the same size and that molecules of different types interact with each other in the same way as molecules of the same type (same forces, etc.). Such a system is called an ideal mixture. Explain why, for an ideal mixture.

Answers

For an ideal mixture of two or more substances, the mixing entropy can be derived based on the same principles as for ideal gases. The reason is that ideal mixtures also have particles that are in constant random motion, and the entropy of mixing is still related to the number of possible ways the particles can be arranged.

Ideal mixture explained.

In an ideal mixture, the assumption is that the molecules of different substances are the same size and shape, and have the same intermolecular forces with each other as they do with their own kind. This means that there are no attractive or repulsive forces between particles of different types, which simplifies the calculation of the entropy of mixing.

The mixing entropy of an ideal mixture is determined by the number of possible ways the molecules of the two substances can be distributed among the available volume. Just as in the case of ideal gases, this leads to an increase in entropy when the two substances are mixed, as there are more ways to distribute the molecules than when they are separated.

Therefore, the concept of an ideal mixture allows us to apply the same principles of thermodynamics to denser systems as we do for ideal gases, which makes it a useful tool for studying a wide range of physical and chemical processes involving mixtures.

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The mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.

What is Ideal Mixing Entropy Formula?

An ideal mixture is a hypothetical mixture of gases, liquids or solids where the components are assumed to behave as an ideal gas, and where the two types of molecules are the same size and interact with each other in the same way as molecules of the same type (same forces, etc.). In an ideal mixture, the mixing entropy formula applies due to the following reasons:

No intermolecular forces between different species: In an ideal mixture, the molecules of the different components do not attract or repel each other. This means that the interactions between the different species are negligible and the enthalpy of mixing is zero.

No volume changes upon mixing: In an ideal mixture, the components have the same size and shape, and the volume of the mixture is equal to the sum of the volumes of the individual components. Therefore, there are no volume changes upon mixing, and the entropy of mixing is solely dependent on the number of ways of arranging the molecules.

Random mixing: The assumption of ideal mixing also implies that the mixing is completely random, with no preferential interactions between the different species. This means that the entropy of mixing is solely dependent on the number of ways the molecules can be arranged, and this is given by the mixing entropy formula.

Therefore, the mixing entropy formula applies to ideal mixtures because there are no intermolecular forces between different species, there are no volume changes upon mixing, and the mixing is completely random.

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Which statement(s) is/are TRUE about photons?
SELECT ALL THAT APPLY
a Photons have greater mass than electrons.
b Photons are particles of light.
с
Photons carry a very specific quantum of
energy.
d Photons have zero mass.

Answers

Answer:

Not D, every substance in existence has mass and is made from it in any given form.

B and C

Explanation:

The statements which are true about photons are:

Choice B: Photons are particles of light.Choice C: Photons carry a very specific quantum of energy.Choice D: Photons have zero mass.

Discussion:

The photon is a type of elementary particle. It is the quantum of the electromagnetic field including electromagnetic radiation such as light and radio waves, and the force carrier for the electromagnetic force.

Additionally, Photons are massless, so they always move at the speed of light in vacuum, 3 × 10⁸ m/s.

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Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 ✕ 10^5 m/s in the positive x-direction. Thousands of miles from Earth, they interact with Earth's magnetic field of magnitude 2.93 ✕ 10−8 T in the positive z-direction. Find the magnitude and direction of the magnetic force on a proton. Find the magnitude and direction of the magnetic force on an electron.

Electrons and protons travel from the Sun to the Earth at a typical velocity of 3.99 10^5 m/s in the

Answers

Therefore, the magnetic force on an electron is 1.175 x 10⁻¹⁴N in the positive y-direction.

The force experienced by a moving charge in a magnetic field is given by the Lorentz force law. Since the charge on a proton is positive and that on an electron is negative, the direction of the magnetic force experienced by each is different.In this question, we need to find the magnitude and direction of the magnetic force on a proton and an electron as they travel from the Sun to the Earth.

Let's first calculate the magnetic force on a proton:

F = qvBsinθ

where q = charge of the particle

v = velocity of the particle

B = magnetic field strength

θ = angle between the velocity of the particle and the magnetic field = 90° (since the proton is moving perpendicular to the magnetic field)

Therefore,

F = qvBsinθ

= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°

= 1.175 x 10⁻¹⁴ N

Direction of magnetic force on a proton:The direction of the magnetic force on a proton can be found using the right-hand rule. According to this rule, if we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the negative y-direction.

Therefore, the magnetic force on a proton is 1.175 x 10^-14 N in the negative y-direction.

- Now, let's calculate the magnetic force on an electron:

Again using the Lorentz force law,

F = qvBsinθ

= (1.6 x 10⁻¹⁹) x (3.99 x 10⁵) x (2.93 x 10⁻⁸) x sin 90°

= -1.175 x 10⁻¹⁴ N (the negative sign indicates that the direction of the magnetic force is opposite to that of the proton)

Direction of magnetic force on an electron:Again using the right-hand rule, we can find the direction of the magnetic force on an electron. If we point the thumb of our right hand in the direction of the particle's velocity (in the positive x-direction) and the fingers in the direction of the magnetic field (in the positive z-direction), then the magnetic force will be perpendicular to both and will be in the positive y-direction.

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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.

Answers

The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.

Let the mass of the body A be ‘m’.

The two strings are taut so they exert a tension ‘T’ on body A.

Let ‘a’ be the acceleration produced in the system.

The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)

As the two strings are taut, we can say that tension in both strings is equal.

Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.

The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)

As per the given problem, the system is released from rest.

Hence the initial velocity is zero.

Also, we are given that the system accelerates at 2 m/s2.

Therefore a = 2 m/s2 …(2)

From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5

Thus, the mass of A is 8m/5 kg.

Answer: Mass of A = 8m/5 kg.

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How is mass and weight differentiated?

Answers

Explanation:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains.

The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it.

A machine produces 4,000 J of work in 5 seconds. how much power does the machine produce.

Answers

Explanation:

Power is defined as the work done per unit time or

\(P = \dfrac{\Delta W}{\Delta t}\)

\(\;\;\;\;= \dfrac{4000\:\text{J}}{5\:\text{s}} = 800\:\text{Watts}\)

the machine produces 800 watts of power. Power is defined as the amount of work done (or energy transferred) per unit of time.

The formula to calculate power is:

\(\[ \text{Power} (P) = \frac{\text{Work} (W)}{\text{Time} (t)} \]\)

where:

Work (W) = 4,000 J (joules)

Time (t) = 5 seconds

Let's plug in the values to calculate the power:

\(\[ P = \frac{4,000 \text{ J}}{5 \text{ s}} \]\[ P = 800 \text{ watts (W)} \]\)

So, the machine produces 800 watts of power.

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Prior Knowledge Questions (Do these BEFORE using the Gizmo.) Strings of holiday lights can be designed in one of two ways. In some strings of lights, each light is connected to the others along a single wire (in series). In others, each light is attached to its own wire (in parallel). Suppose a single light bulb burns out. How do you think this will affect lights that are strung along a single wire

Answers

Answer:

They would go out

Explanation:

This is because, in a series connection, the same current passes through each light. Since the current is the same, if one light burns out, it cuts off the rest of the other lights and thus, no current flows in the string again.

Whereas, in a parallel connection, each light is attached to its own wire and thus has a different current flowing through it than the rest of the other wires.  If one of the lights goes out, current stops flowing through it but, it doesn't affect the other lights.

The process of charging a capacitor consists of transferring charge from the plate at lower ____ to the plate at higher one

Answers

The process of charging a capacitor consists of transferring charge from the plate at lower potential to the plate at higher one (higher potential).

What steps are involved in charging a capacitor?

When a battery is connected in series with a resistor and capacitor, a large initial current flows when the battery moves charge from one capacitor plate to the other. As the capacitor charges to the battery voltage, the charging current asymptotically decreases until it is zero.

Therefore, a unidirectional flow of electric charge is known as direct current. When the voltage from the power source matches the voltage at the capacitor terminals, the capacitor is fully charged. When the electrical circuit's current stops flowing, the charging phase of the capacitor is complete.

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(TIMED) Sally Diamond observes that light striking a sheet of material at 26.7 degree angle to the surface is bent to an angle of 36 degrees relative to the normal as it passes through the material. Through what material is the light passing?

Pyrex
Ruby
Water
Crown glass

Answers

Answer:

Crown glass

Explanation:

We can use Snell's Law to determine the material through which the light is passing.

Snell's Law states that n1 sinθ1 = n2 sinθ2, where n1 and n2 are the indices of refraction of the two materials, θ1 is the angle of incidence, and θ2 is the angle of refraction.

In this case, we know that the angle of incidence is 26.7 degrees, and the angle of refraction is 36 degrees. We also know that air has an index of refraction of approximately 1.

Using Snell's Law, we can solve for the index of refraction of the material:

1 sin 26.7 = n2 sin 36

n2 = (1 sin 26.7) / (sin 36)

n2 ≈ 1.52

The index of refraction of the material is approximately 1.52. This corresponds to the index of refraction of crown glass, which is a common optical material used in lenses and prisms. Therefore, the light is most likely passing through crown glass.

In the study of personality, what model includes different traits that underlie one’s basic tendencies

Answers

In the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

What is the Five-factor model?

The Five-factor model is a scientific theory that states traits of the personality of an individual are due to its biology and therefore they respond to adaptations, which are central in the biology field.

In conclusion, in the study of personality, the Five-factor model includes different traits that underlie one’s basic tendencies.

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what happens to the average molecular speed in an ideal gas if you triple the volume and keep the same temperature ?

Answers

Answer:

If you hold the temperature of an ideal gas constant, what happens to its volume when you triple the pressure? For T fixed, P is proportional to 1/V or V is proportional to 1/P. Tripling P reduces V to 1/3. ... If T is constant, the speeds of the average speeds and kinetic energy of the atomic particles remain constant.

I hope this helps!

Calculate the acceleration due to gravity on a planet that has a radius of 6.378×10⁶ m and as mass of 5.972×10²⁴ kg.

Answers

Determine the planet's radius and mass. Use the formula g=GMR2 to get the acceleration 93.63×10¹⁶m/s brought on by gravity on that planet's surface.

What is the equation to determine the acceleration caused by gravity?

The most practical formula for estimating the acceleration caused by gravity is given by these two laws: g = G*M/R2, where g is the acceleration caused by gravity, G is M represents mass, R is distance, and G is the gravitational constant of the universe.

Calculation:

g = G*M/R2,

g = 5.972×10²⁴/ 6.378×10⁶

g = 5.972×10¹⁸/6.378

g = 93.63×10¹⁶m/s

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Clark Grizwald put a neon green blinking tree that weights 2.3 kg on top of his house 50 meters off the ground but he didn't tie it down right. How much velocity does the blinking tree have when it is 2 meters from the ground? Solve

Answers

The magnitude of the velocity the blinking tree has when it is 2 meters from the ground is 21.8 m/s.

Conservation of energy

To calculate the velocity of the blinking tree when it is 2 meters from the ground, we can use the principles of conservation of energy.

First, let's determine the potential energy of the tree when it is 50 meters off the ground. The potential energy (PE) can be calculated using the formula:

PE = mgh

Where:

m = mass of the tree (2.3 kg)

g = acceleration due to gravity (9.8 m/s^2)

h = height (50 m)

PE = 2.3 x 9.8 x 50

PE = 1131 J

Next, we can calculate the potential energy of the tree when it is 2 meters from the ground:

PE = mgh

Thus:

PE = 2.3 x 9.8 x 2

PE = 45.04 J

According to the conservation of energy principle:

PE(initial) = PE(final) + KE(final)

1131 J = 45.04 J + KE(final)

Now, let's solve for the kinetic energy (KE) at the final position:

KE(final) = PE(initial) - PE(final)

KE(final) = 1131 J - 45.04 J

KE(final) = 1085.96 J

KE = (1/2)mv^2

1085.96 J = (1/2) x 2.3 kg x v^2

Thus

v^2 = (2 x 1085.96 J) / 2.3 kg

v^2 = 474.76 m^2/s^2

v ≈ 21.8 m/s

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. A 5cm tall object is placed perpendicular to the principal axis of a convex lens of focal
length 10 cm. The distance of the object from the lens is 15 cm. Find the nature, position
and size of the image. Also find its magnification

Answers

The nature of the image formed by the convex lens is virtual, the position of the image is 30 cm away from the lens on the same side as the object, and the size of the image is twice the size of the object. The magnification is 2, meaning the image is magnified.

Given:

Object height (h) = 5 cm

Focal length of the convex lens (f) = 10 cm

Object distance (u) = 15 cm (positive since it's on the same side as the incident light)

To determine the nature, position, and size of the image, we can use the lens formula:

1/f = 1/v - 1/u

Substituting the given values:

1/10 = 1/v - 1/15

To simplify the equation, we find the common denominator:

3v - 2v = 2v/3

Simplifying further:

v = 30 cm

The image distance (v) is 30 cm. Since the image distance is positive, the image is formed on the opposite side of the lens from the object.

To find the magnification (M), we use the formula:

M = -v/u

Substituting the values:

M = -30 / 15 = -2

The magnification is -2, indicating that the image is inverted and twice the size of the object.

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If a 1.5-Kg physics book measures 0.260 m x 0.210 m x 0.040 m, calculate the pressure applied by the standing book on the table. (Round off answer to two sig figs)
*

Answer choices:
P = 1,600 N/m^2
P = 1,800 N/m^2
P = 1,500 N/m^2
P = 1,700 N/m^2

Answers

The pressure applied by the standing book on the table is 1,800 N/m².

option B is the correct answer.

What is the pressure applied by the book?

The pressure applied by the standing book on the table is determined from the ratio of weight of the book and the area of the standing book.

Mathematically, the formula for the pressure of a material is given as;

P = F / A

where;

F is the applied force or weight of the object standing on another surfaceA is the area of the object in contact with another surface

The weight of the book , F = mg

where;

m is the mass of the bookg is acceleration due to gravity

F = 1.5 kg  x  9.8 m/s²

F = 14.7 N

The dimension of the book include;

height of the book, h = 0.26 mwidth of the book, w = 0.21 mthickness of the book, b = 0.04 m

The height of the book is not in contact with the surface of the table, so the area of the book in contact with the table becomes;

A = w x b

W = 0.21 m  x  0.04 m

W = 8.4 X 10⁻³ m²

P = F / A

P = ( 14.7 N ) / ( 8.4 X 10⁻³ m² )

P = 1,750 N/m² ≈ 1,800 N/m²

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the bug has the greater acceleration because it has the smaller massthe windshield has the greater acceleration because it has the greater massthey both have the same magnitude of acceleration

Answers

The bug has a larger acceleration because it has a smaller mass, according to the claim made.

How does acceleration work?

acceleration is the rate of change in both speed and the direction of velocity over time. When anything moves faster or slower in a straight line, it is said to have been accelerated.

What does the law of acceleration simply mean?

According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force is acted on a mass (object). Every law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. Your leg muscles are pressing the pedals.

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I understand that the question you are looking for is:

Which has the greater acceleration: the bug or the windshield?

The x and y coordinates of a particle at any time t are x = 5t - 3t2 and y = 5t respectively, where x and y are in meter and t in second. The speed of the particle at t = 1 second is​

The x and y coordinates of a particle at any time t are x = 5t - 3t2 and y = 5t respectively, where x

Answers

Answer:

\(v=\sqrt{26}~m/s\)

Explanation:

Parametric Equation of the Velocity

Given the position of the particle at any time t as

\(r(t) = (x(t),y(t))\)

The instantaneous velocity is the first derivative of the position:

\(v(t)=(v_x(t),v_y(t))=(x'(t),y'(t))\)

The speed can be calculated as the magnitude of the velocity:

\(v=\sqrt{v_x^2+v_y^2}\)

We are given the coordinates of the position of a particle as:

\(x=5t-3t^2\)

\(y=5t\)

The coordinates of the velocity are:

\(v_x(t)=(5t-3t^2)'=5-6t\)

\(v_y(t)=(5t)'=5\)

Evaluating at t=1 s:

\(v_x(1)=5-6(1)=-1\)

\(v_y(1)=5\)

The velocity is:

\(v=\sqrt{(-1)^2+5^2}\)

\(v=\sqrt{1+25}\)

\(\mathbf{v=\sqrt{26}~m/s}\)

what is an emergent curriculum

Answers

Answer:

Emergent curriculum is an early education approach where teachers design projects unique to a child or group of kids.

Moving hot air balloon experiences a 30,000 N lift force up and a 30,000 N gravitational force down, what is the resulting motion of the balloon?

Answers

The net force on the balloon is zero, so it has no acceleration. So by Newton's first law, if the balloon has some velocity in a given direction, it will continue moving in that direction at a constant speed. If it's motionless, it stays motionless.

What must your speed be in order to travel 400 km in 3 hrs?

Answers

Answer:

\(\boxed {\tt s=133 \frac{1}{3} \ or \ 133.333333 \ km/hr}\)

Explanation:

We want to find speed, so we can use the following formula.

\(s=\frac{d}{t}\)

where \(d\) is the distance traveled and \(t\) is the time.

We traveled 400 kilometers in 3 hours. Therefore,

\(d= 400 \ km \\t= 3 \ hrs\)

Substitute the values into the formula.

\(s=\frac{400 \ km }{3 \ hrs}\)

Divide

\(s= 133.33333 \ km/hr\)

\(s= 133 \frac{1}{3} \ km/hr\)

The speed is 133 1/3 or 133.33333 kilometers per hour.

A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)

Answers

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

An object is dropped from a height of 100m. What height above the ground is the object when it has a speed of 25m/s? (g = 9.8)

Answers

Given,

The height from which the object was dropped, h=100 m

The speed of the object, v=25 m/s

The acceleration due to gravity, g=9.8 m/s²

The object will have only potential energy when it is at rest at the height of 100 m. As the object falls it will slowly lose its potential energy. The potential energy thus lost will be converted into the kinetic energy of the object.

Thus the potential energy lost by the object when it has a speed of 25 m/s will be equal to its kinetic energy at that instant.

Therefore,

\(\begin{gathered} mg(\Delta h)=\frac{1}{2}mv^2 \\ \Rightarrow\Delta h=\frac{v^2}{2g} \end{gathered}\)

Where Δh is the change in the height of the object or the height through which the object has fallen at that instant.

On substituting the known values,

\(\begin{gathered} \Delta h=\frac{25^2}{2\times9.8} \\ =31.89\text{ m} \end{gathered}\)

Thus the height of the object above ground is,

\(\begin{gathered} l=h-\Delta h \\ =100-31.89 \\ =68.11\text{ m} \end{gathered}\)

Thus the height of the object above the ground when it has a speed of 25 m/s is 68.11. m

an object moves at uniform speed (v) in a circular path, the
centripetal acceleration is a, if the object moves in the same
circular path at uniform speed (4v) the centripetal accelera on will
be?

Answers

The centripetal acceleration (a) of an object moving in a circular path is given by the formula:

a = v^2 / r

where v is the speed of the object and r is the radius of the circular path.

If the object moves at a uniform speed of 4v instead, we can plug this value into the formula to find the new centripetal acceleration (a'):

a' = (4v)^2 / r

Simplifying the expression, we get:

a' = 16v^2 / r

Now, we can compare the new centripetal acceleration (a') to the original centripetal acceleration (a):

a' = 16(a)

So, if the object moves in the same circular path at a uniform speed of 4v, the centripetal acceleration will be 16 times greater than the original centripetal acceleration.

Answer: V 2 /r

Explanation: "If a particles move with a uniform speed of V on any given circular path having the radius (r), the particle will have a centripetal acceleration of magnitude (v 2 /r). However, the direction continuously changes and always maintains its position towards the circle."

Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.

Answers

The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C

How to solve for the  total distance

To calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.

However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.

Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.

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Why is it incorrect to say that astronauts are weightlesS in space while orbiting Earth in a space shuttle?​

Why is it incorrect to say that astronauts are weightlesS in space while orbiting Earth in a space shuttle?

Answers

This is because Gravity exists everywhere in the universe.

What is Gravity?

This is the force of attraction which acts on all matters in the universe. Astronauts appear weightless while in orbiting the Earth because the space shuttle and the astronauts are in free fall around it.

They fall at the same rate as the space shuttle which is why the astronauts appear weightless.

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Astronauts and their spaceship are affected by Earth's gravity in space. Even though Earth's gravitational influence is weaker in orbit than on Earth's surface, they have weight. They don't feel their weight since nothing's pushing back.

What is weightlessness in space?

Weightlessness means no weight. It's also called zero-G. Weight is the force on a stationary object in a strong gravitational field.

The sensation of weightlessness that astronauts on board the International Space Station enjoy is due to the fact that they are free falling toward the planet Earth. Because the space station and the astronauts are moving at the same rate, there is no external normal force acting upon the body in free fall to balance out the effects of the body's own weight (equal to g).

Therefore, the astronauts and their spaceship continue to have mass and are still affected by the gravitational pull of the Earth.

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