how does the force of gravity affects an objects acceleration

The projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

An object that is shot into the air and subsequently proceeds along a curved route while being pulled by gravity is said to be in projectile motion. There is no additional propulsion or lift involved. A ball that is tossed, a bullet that is shot from a pistol, or a rocket that is launched into space are examples of things in projectile motion.

We can use the kinematic equations of motion to calculate the projectile's time of flight. The initial velocity can first be divided into its horizontal and vertical components as follows:

\(Vx = V \times cos(\theta)\\= 65 m/s \times cos(30)\\= 56.18 m/s\\Vy = V \times sin(theta)\\= 65 m/s \times sin(30)\\= 32.5 m/s\\\)

where V is the magnitude of the initial velocity, and theta is the launch angle (30 degrees).

The horizontal velocity of the projectile remains constant throughout its flight, while the vertical velocity changes due to the effect of gravity. At the highest point of the trajectory, the vertical velocity becomes zero, and the time it takes to reach this point is equal to half of the time of flight.

The time it takes for the projectile to reach the highest point can be found using the following kinematic equation:

\(V_y = V_oy + a \times t\)

where Voy is the vertical component of the initial velocity (in this case, 32.5 m/s), a is the acceleration due to gravity (-9.81 m/s^2), and t is the time it takes to reach the highest point.

\(0 = 32.5 m/s + (-9.81 m/s^2) \times t\\t = 3.32 s\)

The total time of flight can be found by doubling the time it takes to reach the highest point:

time of flight = 2 × 3.32 s

                      = 6.64 s

Therefore, the projectile's time of flight is approximately 6.6 seconds, which is closest to option B.

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The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)

The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.

This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.

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The power output of a person climbing stairs is the mass of the person. Option B.

It is clear that carrying a heavy object up a flight of stairs requires more strength than carrying a lighter one. But even if you don't have anything you have to support your weight against gravity. Therefore, the heavier the weight the greater the force required to climb the stairs. Climbing stairs improves the amount of good cholesterol in your blood.

Stair climbing can be an important priority for building leg strength and reducing the risk of fall injury in older adults. Climbing stairs helps you achieve and maintain a healthy weight. Calculate the amount of power developed Power is the amount of work divided by the time it took to do the work. The work done in climbing stairs is the force applied by multiplying the weight by the distance climbed and the height of the stairs.

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Answer:

PE = 137.2931 J

Explanation:

PE = 137.2931 J

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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Answer:

Iron and lead generally have low specific heats.

The velocity of this automobile as a function of time. At t = 5 seconds, the automobile is 90 meters from its initial position.

To determine the distance traveled by the automobile from its t = 0 initial position, we need to calculate the area under the velocity-time graph up to t = 5 seconds.

The graph shows the velocity of the automobile as a function of time. Let's assume that positive velocity represents forward motion, and negative velocity represents backward motion.

Since velocity represents the rate of change of displacement, the area under the velocity-time graph represents the displacement or distance traveled. In this case, the area will consist of two parts: the area above the x-axis (forward motion) and the area below the x-axis (backward motion).

To calculate the area, we can break it down into two separate integrals:

1. The area above the x-axis (forward motion):

Since the velocity is constant at 20 m/s for the first 4 seconds, the area is a rectangle:

Area1 = velocity * time = 20 m/s * 4 s = 80 m

2. The area below the x-axis (backward motion):

The velocity changes to -10 m/s at t = 4 seconds. From t = 4 seconds to t = 5 seconds, the velocity is -10 m/s. The area is a rectangle:

Area2 = velocity * time = -10 m/s * 1 s = -10 m

To find the total distance traveled, we add the absolute values of the areas:

Total distance = |Area1| + |Area2| = |80 m| + |-10 m| = 80 m + 10 m = 90 m

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There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

A) The balance point is located 0.67 cm from the inlet.

B) The fluid loss per unit time between the inlet and the balance point is: 0.34 μL/s.

a) To find the balance point, we need to find the location where the capillary filtration pressure (Pc) equals the osmotic pressure difference (πc - πif). From problem 4.21, we know that the capillary filtration pressure is given by:

Pc = Pif - Pec

where Pif is the interstitial fluid pressure and Pec is the capillary colloid osmotic pressure. From the figure in problem 4.21, we can estimate that Pif is about -3 mmHg at the inlet and about -1 mmHg at the outlet. From the same figure, we can estimate that πc is about 28 mmHg at the inlet and about 26 mmHg at the outlet. Assuming that πif is constant along the length of the capillary, we can write:

Pc = Pif - πc + πif

Setting Pc = 0 and solving for x, we get:

x = L (πc - πif) / (Pif - πc + πif)

where L is the length of the capillary. Substituting the values, we get:

x = 2 cm * (28 mmHg - 25 mmHg) / (-3 mmHg - 28 mmHg + 25 mmHg) = 0.67 cm

b) To find the fluid loss per unit time between the inlet and the balance point, we need to find the filtration rate J at the inlet and at the balance point. From problem 4.21, we know that the filtration rate J is given by:

J = LpKf [(Pc - Pif) - σ/2]

where Lp is the hydraulic conductivity of the capillary wall, Kf is the filtration coefficient, and σ is the reflection coefficient. Assuming that Pif is constant along the length of the capillary, we can write:

J = LpKf [(Pif - πc + πif) - Pif + σ/2]

J = LpKf [(πif - πc) + σ/2]

At the inlet, x = 0, and πif = 3 mmHg . Substituting the values, we get:

J_inlet = 2 cm * 10^(-7) cm/s/mmHg * 10^(-4) cm^2 * [(28 mmHg - 3 mmHg) + 0.2/2] = 0.55 μL/s

At the balance point, x = 0.67 cm, and πif = 3 mmHg (assuming that πif is constant along the capillary). Substituting the values, we get:

J_balance = 1.33 cm * 10^(-7) cm/s/mmHg * 10^(-4) cm^2 * [(25 mmHg - 3 mmHg) + 0.2/2] = 0.21 μL/s

the fluid loss per unit time between the inlet and the balance point is:

0.55 μL/s - 0.21 μL/s = 0.34 μL/s.

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An astronaut measure the period of a mass spring system on Earth.

The period of a mass spring system on the moon would be longer than the period on Earth. This is because the period of a mass spring system is dependent on the square root of the ratio of the mass to the spring constant, and the acceleration due to gravity. Since the acceleration due to gravity on the moon is only 1/6th of that on Earth, the restoring force on the mass will be weaker, resulting in a longer period. Therefore, the astronaut would measure a longer period for the same mass spring system on the moon than on Earth.

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Answer:

Will be equal to alpha x r; less than UsN

Answer:

Explanation:

Mass ( m ) = 2 kg

Speed of the object (v) = 6 metre per second

Kinetic energy =?

Now,

We have,

Kinetic Energy = \( \frac{1}{2} \times m \times {v}^{2} \)

Plugging the values,

\( = \frac{1}{2} \times 2 \times {(6)}^{2} \)

Reduce the numbers with Greatest Common Factor 2

\( = {(6)}^{2} \)

Calculate

\( = 36 \: joule\)

Hope this helps...

Good luck on your assignment...

The Kinetic energy of the object will be "36 joules".

The excess energy of moving can be observed as that of the movement of an object, component, as well as the group of components. There would never be a negative (-) amount of kinetic energy.

According to the question,

Mass of object, m = 2 kg

Speed of object, v = 6 m/s

As we know the formula,

→ Kinetic energy (K.E),

= \(\frac{1}{2}\) × m × v²

By substituting the values, we get

= \(\frac{1}{2}\) × 2 × (6)²

=  \(\frac{1}{2}\) × 2 × 36

= 36 joule

Thus the above answer is appropriate.

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Answer: The main reason the  pollen and the extension the process of pollination  is so that important is because it means the plants don't have to rely on water to transport the biological components necessary for the fertilization.  Inside it and they contain the male portion of DNA needed for the plant reproduction.

Explanation:

Answer:

Objects that are closer together have a stronger force of gravity between them.

Explanation:

For example, the moon is closer to Earth than it is to the more massive sun, so the force of gravity is greater between the moon and Earth than between the moon and the sun.

With the use of below formula, at 879 °C,  velocity will be double the velocity at 15 °C.

The velocity of sound waves in air is proportional to the square root of Thermodynamic temperature. That is, V = K\(\sqrt{T}\)

Given that the temperature at which the velocity of sound in air is twice its velocity at 15°C, Let us make use of the formula;

(v2/v1) = √(T2 / T1)

Where

Recall that absolute temperature = °C + 273.

If v2 = 2 × v1 and temperature in degree Celsius = 15°C, then,

Temperature in Kelvin K = 15 + 273 = 288

Substitute all the parameters into the formula

(2 × v1)/v1 = √(T2/288)

2 = √ (T2 /288)

Square both sides

4 = (T2/288)

T2 = 4 × 288

T2 = 1152K

Temperature in degrees Celsius = 1152 - 273 = 879 °C.

Therefore, at 879 °C,  velocity will be double the velocity at 15 °C.

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Answer:

Explanation:

verbal as they are all linked to communication and speaking

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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It takes less effort to lift a piano with a pulley. If the piano is lifted 3 meters, then the distance traveled by the load is 3 m.

Output force is the force exerted on an object by a simple machine.

If the output force is greater than the input force, the mechanical advantage is greater than 1.

The mechanical advantage ratio is output force divided by input force. The larger the mechanical advantage, the easier it is to do work.

Mathematically, the output force of a simple machine is given as;

output force = load x distance moved by load

Thus, it takes less effort to lift a piano with a pulley. If the piano is lifted 3 meters, then the distance traveled by the load is 3 m.

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Answer:

A

Explanation:

The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes

From the question given above, the following data were obtained:

The current drawn by the frying pan can be obtained as follow:

Voltage (V) = Current (I) × resistance (R)

Inputting the given parameters, we have:

1500 = Current × 25

Divide both sides by 25

Current = 1500 / 25

Current = 60 amperes

Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes

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Answer:

See below

Explanation:

See diagram below

8 seconds to 60 m/s     then    60 m/s for 22 seconds then   to 0 m/s in 5 seconds

Answer:

The forward motion of a body in space, such as a planet or moon, and the pull of gravity on it from another body in space.

Explanation:

Earth and many other bodies—including asteroids, comets, and the other planets—move around the sun in curved paths called orbits. Generally, the orbits are elliptical, or oval, in shape. Because of the sun’s relatively strong gravity, Earth and the other bodies constantly fall toward the sun, but they stay far enough away from the sun because of their forward velocity to fall around the sun instead of into it. As a result, they keep orbiting the sun and never crash to its surface. The motion of Earth and the other bodies around the sun is called orbital motion. Orbital motion occurs whenever an object is moving forward and at the same time is pulled by gravity toward another object.

The series circuit has components connected in a sequence, while the parallel circuit has components connected in different branches. If bulb B2 is replaced with a wire in the series circuit, bulb B1 will not light up, while in a parallel circuit, it will still light up.

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Answer:

13.02 m/s

Explanation:

First, convert the units of kilometer and hours into meter and second. This can be done by multiplying 150 with 1000 since a kilometer equals 1000 meters. This’ll get us the new unit of 150,000 meters.

Then convert 3.2 hours to second by firstly multiplying 3.2 with 60. This’ll get us with 192 minutes since an hour equals 60 minutes. Then multiply 192 by another 60 because a minute equals to 60 seconds. You’ll obtain the new unit of 11520 seconds.

Next, we can now apply the basic velocity formula which is:

\(\displaystyle \vec v = \dfrac{\vec s}{t}\)

Where \(\vec v\) is velocity, \(\vec s\) is displacement and \(t\) is time. In this scenario, assume that the car travels in linear path - this means that the displacement equals to distance. Therefore, from the information we have, we can conclude that:

Apply in the formula to find velocity:

\(\displaystyle {\vec v = \dfrac{150000}{11520}}\\\\\displaystyle{\vec v \approx 13.02 \ \, \sf{m/s}}\)

Therefore, our velocity is approximately 13.02 m/s

When the length of the wire is doubled while connected to the same voltage source, the power dissipated in the wire falls by a ratio of 4.

The resistance of the wire increases as it is stretched to double its length. This can be seen from the formula for resistance, which is R = ρL/A, where ρ is the resistivity of the material, L is the length, and A is the cross-sectional area of the wire. When the length is doubled, the resistance will also double.

If the wire is hooked up to the same voltage source, the power dissipated in the wire can be calculated using the formula P = V²/R. Here, V is the voltage and R is the resistance. Since R has doubled, the power dissipated will decrease by a factor of 4. This can be seen by substituting 2R for R in the formula:

P' = V²/(2R) = (1/4)(V²/R) = (1/4)P

Therefore, the power dissipated in the wire decreases by a factor of 4 when its length is doubled while it is hooked up to the same voltage source.

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Answer:

In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.

Explanation: