Answer:
1684.8 m
Explanation:
First, we need to convert 5.4 minutes to seconds, so
5.4 min x 60 s / 1 min = 324 seconds
Then, we can calculate the distance by multiplying the velocity by the time
distance = velocity x time
distance = 5.2 m/s x 324 s
distance = 1684.8 m
Therefore, the distance traveled by the horse is 1684.8 m
PLEASE HELP ASAP!!!!
Motion is described with respect to what?
А
displacement
B
frame of reference
C
graph
D
speed
Answer:
Option B is correct
Explanation:
Motion is described with respect to frame of reference.
A frame of reference refers to a set of coordinates that helps to find positions and velocities of objects in the frame.
The laws of motion might be more complex than required if the coordinates are not chosen properly.
Therefore,
Option B is correct
carrier concentration for n type
Answer:
Consider an n-type silicon semiconductor at T = 300°K in which Nd = 1016 cm-3 and Na = 0. The intrinsic carrier concentration is assumed to be ni = 1.5 x 1010 cm-3. - Comment Nd >> ni, so that the thermal-equilibrium majority carrier electron concentration is essentially equal to the donor impurity concentration.
Explanation:
Water flows steadily from an open tank as shown in the figure. (Figure 1)The elevation of point 1 is 10.0 m , and the elevation of points 2 and 3 is 2.00 m . The cross-sectional area at point 2 is 4.80×10−2 m2 ; at point 3, where the water is discharged, it is 1.60×10−2 m2 . The cross-sectional area of the tank is very large compared with the cross-sectional area of the pipe. What is the gauge pressure p_gauge at point 2?
The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.
Step 1: Identification of the given data:
- Elevation at point 1 (h1) = 10.0 m
- Elevation at points 2 and 3 (h2 = h3) = 2.00 m
- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)
- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)
Step 2: Determination of the discharge rate:
As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.
Therefore, the discharge rate is 0 cubic meters per second.
Step 3: Determination of the gauge pressure at point 2:
To find the gauge pressure at point 2, we'll use Bernoulli's equation:
P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2
Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.
The equation simplifies to:
Patm + ρgh1 = P2 + ρgh2
We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:
\(P_g_a_u_g_e\) = P2 - Patm
Now let's substitute the given values into the equation:
\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm
\(P_g_a_u_g_e\) = ρgh1
Plugging in the values:
\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)
\(P_g_a_u_g_e\) = 98100 Pa
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A bus is moving with
a velocity of lom/s. After 2 sec its velocity
becames 20/s find the distance from travelled
by a bus at that this time of interval
Answer:
30 m
__________________________________________________________
Explanation:
We are given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 20 m/s
Time interval (t) = 2 seconds
Distance travelled by the bus (s) = s meters
Solving for the distance travelled:
Solving for the acceleration:
v = u + at [first equation of motion]
20 = 10 + a(2) [replacing the given values]
2a = 10 [subtracting 10 from both sides]
a = 5 m/s² [dividing both sides by 2]
Solving for the distance:
s = ut + 1/2 (at²) [second equation of motion]
s = 10(2) + 1/2(5)(2)² [replacing the given values]
s = 20 + 10
s = 30 m
Therefore, the bus travelled 30 m in the given time interval
Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?
The near point of a human eye is about a distance of 25 cm.
The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.
This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.
The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.
In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.
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21. Which substance is a gas at 45 degrees C?* A. Ethanol O B. Hexane C. Methane O D. Methanol
Answer:
C. Methane
Explanation:
A chemical equation can be defined as a reaction between two chemical elements.
For a chemical reaction (equation) to be balanced, the condition which must be met is that the number of atoms contained in the reactants must be equal to the number of atoms in the products.
This ultimately implies that, the mass and charge of the chemical equation are both balanced properly.
Methane is a hydrocarbon compound formed by the reaction between four (4) hydrogen atoms with a carbon atom. It belongs to the alkane group of hydrocarbons and has the following physical and chemical properties; colorless, highly flammable, non-toxic and odorless gas. The empirical formula for Methane is CH4.
Methane is a gas at 45 degrees celsius. This ultimately implies that, at 45°C methane is a gas because it is still within the range of standard temperature and pressure.
A marine weather station reports waves along the shore that are 2 meters high, 8 meters long, and reach the station 8 seconds apart. Determine the speed of these waves.
One full weather station reports wave passing a spot every second is equivalent to a frequency of 1 Hz. The frequency is 48=12=0.5 Hz if 4 waves pass a spot in 8 seconds.
What is the frequency of a 30-second ocean wave that hits the shore?The number of cycles that make up a time unit is the frequency. The frequency of a wave with a 30-second period is therefore 1 30 = 0.033 cycles per second, or 0.033 Hertz (Hz).
Which of the following statements most accurately sums up how a wave crosses a border and enters a new medium?A wave's speed and wavelength vary as it crosses a border and enters a new medium, but its frequency doesn't.
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Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)
Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.
Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.
It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.
The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.
Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.
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Power is the rate at which work is done true or false
Answer:
false
Explanation:
The toy car in the diagram runs off the edge of the table that is 1.225m high. The car lands 0.400m from the base of the table.
a. How long did it take the car to fall
b. how fast was the car going on the table
B (B=26.5)
56.0%
A (A = 44.0)
28.0°
C(C=31.0)
< 1 of 1 >
Part A
Given the vectors A and B shown in the figure ((Figure 1)), determine the magnitude of B-A
Express your answer using three significant figures.
195] ΑΣΦ
|B-A =
Determine the magnitude of B-A is 53.68
1.4
Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.
Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.
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If vector A= aj^ and vector B = bj^, then vector A×B is equal to
Answer:
0 because j×j =0
Explanation:
so a×b is 0
how does the statement " silence is golden " relate to ethics in communicating at the workplace.?
Answer:
Being silent most of the time is a good virtue under certain circumstances and environment. It is always advisable to remain quite silent and not be too quick to respond to situations or issues so as to avoid making and saying wrong words.
The ethics in a workplace involves communicating with others with less amount of talking as possible and more of body languages and signs. This is because the workplace is meant to be a serene place.
I'm not sure about how can solve this problem. Please help me!!
The magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.
How to find magnitude?To find the power dissipated in resistor R4, use the formula:
P = I² × R
where P = power, I = current flowing through the resistor, and R = resistance of the resistor.
The total resistance, Rt, can be calculated using the formula:
1/Rt = 1/R1 + 1/R2 + 1/R3
Substituting the given values:
1/Rt = 1/3 + 1/0.8 + 1/2
Simplifying the equation:
1/Rt ≈ 1.6667
Rt ≈ 0.6 Ω
Next, calculate the total voltage, Vt, by summing the individual voltage sources:
Vt = ε1 + ε2 + ε3
Substituting the given values:
Vt = 9 + 6 + 4
Vt = 19 V
Now calculate the current flowing through resistor R4 using Ohm's Law:
I = Vt / Rt
Substituting the calculated values:
I = 19 / 0.6
I ≈ 31.6667 A
Finally, calculate the power dissipated in resistor R4:
P = I² × R4
Substituting the calculated values:
P = (31.6667)² × 10
P ≈ 10,028 W
Therefore, the magnitude of the power dissipated in resistor R4 is approximately 10,028 watts.
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what is the potential energy of a 30kg rock that falls 15 meters
Answer:
4500 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 10 m/s²
From the question we have
PE = 30 × 10 × 15
We have the final answer as
4500 JHope this helps you
The refractive indices of materials A and B have a ratio of nA/nab=1,33. The speed of light in material A is 1.25 times 10^8m/s. What is the speed of light in material B?
The speed of light in material B is 1.6625 × 108 m/s.
The refractive index of a material is its optical density relative to that of a vacuum.
Material B has a refractive index of nB, and its speed of light is vB.
The speed of light in material A is given as 1.25 x 108 m/s.
The refractive indices of materials A and B have a ratio of nA/nB = 1.33.
We will use the formula:
nA/nB = vB/vA = nA/nB.
Therefore, nA/nB = vB/1.25 x 108 m/s.
This equation can be rearranged to give the speed of light in material B:
vB = nA/nB × 1.25 x 108 m/s.
Therefore, vB = 1.33 × 1.25 × 108 m/s.
We will perform this calculation:
vB = 1.6625 × 108 m/s.
Therefore, the speed of light in material B is 1.6625 × 108 m/s.
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The weight of a body is less inside the earth than on surface
Answer:
the value of gravitational acceleration decreases as we go down and down while on the surface its value is greater...So on surface weight is greater as compared to mines or underground areas
Explanation:
A mass attached to a spring vibrates back and forth. At maximum displacement, the spring force and the
ANSWER
Velocity of the mass reaches zero
EXPLANATION
We want to identify what hapens to a mass attached toa a spring at maximum displacement.
When a mass attached to a spring is at its maximum position of displacement, the direction of the mass begins to change. This implies that the velocity of the mass will reach zero.
Hence, at maximum displacement, the velocity of the mass reaches zero.
Which of the following statements are true of cancer types? Check all that apply. --
- Cancer is named according to the color the cells turn.
- Skin cancer is considered a very common type of cancer.
- Cancer is often named according to what body type it affects.
- Skin cancer is the least common type of cancer.
the answer is cancer is often named according to what body type it affects
Answer:
B,C
Explanation:
skin cancer is considered a very common type of cancer. Cancer is often named accordingly to a body type it affects.
What is the potential gravitational energy of a 2 kg ball thrown up in the air to a height of 7 m?
Answer:
PE = 137.2931 J
Explanation:
PE = 137.2931 J
Which description accurately describes the tide represented by the image below? (4 points)
Image of the sun and moon at a 90 degree angle to Earth. An oval is around Earth that points toward and away from the moon to show the tidal bulges.
High tides occur when the sun and moon are at right angles to one another.
Low tides occur when the sun and moon are at right angles to one another.
The gravitational pull of the sun and moon combined creates larger than normal tides.
The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides.
High tides occur when the sun and moon are at right angles to one another. This is because the gravitational pull of the moon and the sun combine to create larger-than-normal tides, known as spring tides. The correct option is A.
Gravitational pull is the force of attraction that exists between two objects with mass. The greater the mass of an object, the greater its gravitational pull.
Option B, "Low tides occur when the sun and moon are at right angles to one another," is incorrect. Low tides occur when the sun and moon are at a 90-degree angle (or "quarter moon") to each other, but this position also results in high tides on the opposite side of the Earth.
Option C, "The gravitational pull of the sun and moon combined creates larger than normal tides," is partially correct. The gravitational pull of both the sun and moon does contribute to the tides, but the specific position depicted in the image (sun and moon at right angles to each other) does not necessarily create larger than normal tides.
Option D, "The gravitational pull of the sun reduces the moon's gravitational pull to create moderate tides," is also incorrect. The sun's gravitational pull does have an effect on the tides, but it does not reduce the moon's gravitational pull. Rather, the combined gravitational pull of the sun and moon creates the tides we observe.
Therefore,The accurate description of the tide represented by the image below is option A: "High tides occur when the sun and moon are at right angles to one another."
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What are some of the social benefits of participating in a fitness class?
Question 1 options:
An independent workout, Motivation, Communal Approach
Community, Communal Approach, An independent workout
Motivation, Community, Communal Approach
Motivation, An independent workout, Community
Answer: Motivation, Community, Communal Approach
Answer:
Motivation, Community, Communal Approach
Explanation:
Followed by the previous question: presume that the electron performs a uniform circular motion around the hydrogen nucleus. What is the magnitude of the centripetal acceleration in m/sec2? (radius of the circle LaTeX: 5\times 10^{-11}5 × 10 − 11m; period of the motion LaTeX: 1.5 \times 10^{-16}1.5 × 10 − 16sec) Group of answer choices
Answer:
\(A_c=87.73*10^{21}m/s\)
Explanation:
From the question we are told that
\(r=5\times 10^{-11}\)
\(T=1.5 \times 10^{-16}\)
Generally the equation for velocity is mathematically given as
\(Velocity (v)=\frac{2 \pi r}{t}\)
\(V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}\)
\(V=\frac{2 \pi (5*10^{-11})}{1.5*10^{-16}}\)
Generally the equation for Centripetal acceleration is mathematically given as
\(A_c=\frac{V^2}{r}\)
\(A_c=(\frac{20.944*10^5)}{r5*10^{-11}}\)
\(A_c=87.73*10^{21}m/s\)
Why do we never notice quantization?
a. because the fundamental quanta are so large
b. because the fundamental quanta are so small
C. because we are moving quickly relative to such objects
d because we are moving slowly relative to such objects
Answer:
B
Explanation:
quantization of energy is only seen in atoms
How much POWER is used in 30 seconds when you complete 150 Joules of work?
Answer:
Power of 5 watts is used
Explanation:
Mechanical Work and Power
Mechanical work is the amount of energy transferred by a force.
Being F the force vector and s the displacement vector, the work is calculated as:
\(W=\vec F\cdot \vec s\)
If both the force and displacement are parallel, then we can use the equivalent scalar formula:
W=F.s
Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.
The power can be calculated as:
\(\displaystyle P=\frac {W}{t}\)
Where W is the work and t is the time.
It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:
\(\displaystyle P=\frac {150}{30}\)
P = 5 Watt
Power of 5 watts is used
Two forces of 68 pounds and 66 pounds act simultaneously on an object. The angle
between the two forces is 77º. Find the magnitude of the resultant, to the nearest
pound. Find the measure of the angle between the resultant and the smaller force, to
the nearest degree.
Resultant:
Angle:
Submit Answer
Answer:
Explanation:
Let the x axis lie along the 66 lb force with the force vector tail at the origin.
The 68 lb force would lie along a radial 77° CCW from the x axis
The resultant would have an x and y values of
Fx = 66cos0 + 68cos77 = 81.3 lb
Fy = 66sin0 + 68sin77 = 66.3 lb
F = √(81.3² + 66.3²) = 104.87 = 105 lb
θ = arctan (66.3/81.3) = 39°
Which of the following statements about gravitational mass is true? (1 point)
O Gravitational acceleration is irrespective of mass.
O The more mass an object has, the more gravitational acceleration it will experience.
O The less mass an object has, the less gravitational acceleration it will experience.
O Gravitational acceleration is always equal to mass.
Answer:
The more mass an object has, the more gravitational acceleration it will experience
Explanation:
So when we talk about gravitational mass, we're talking about how much an object is affected by gravity. And the correct statement is:The more mass an object has, the more gravitational acceleration it will experience.Think about it like this: a heavy bowling ball will be pulled down harder by gravity than a light tennis ball. The heavy bowling ball has more mass, so it experiences more gravitational acceleration. Make sense?
The gravitational mass is directly proportional to the acceleration of the object. The more mass an object has, the more gravitational acceleration it will experience. Thus, the correct option is B.
What is Gravitational mass?Gravitational mass is the charge to which the gravity couples. Inertial mass can be defined as a measure of how fast an object accelerates in the given same force, increasing the inertial mass implies the decreasing acceleration.
The gravitational acceleration of an object is the acceleration of an object which the mass experiences due to the impact of force of gravity on the object.
Gravitational mass is a gravitational force which is present between any pair of given objects, which is given by the formula:
F = Gm₁m₂/ r²
where, G is the universal gravitational constant, m₁ and m₂ are the masses of the two objects, and r is the distance between them.
Therefore, the correct option is B.
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please help im failing!!!
When students were surveyed about the kind of thinking they considered to be most important in their academic studies, the majority chose?
Answer:Critical Thinking
Explanation:
7.2 in college success text back
A person stands at a point 245 m in front of the face of a sheer cliff. 1f the person shouts, how much time will elapse before an echo is heard? (Assume the speed of sound is 344 m/s.)
Answer: time = 1.42 seconds
Explanation:
The formula for calculating time is expressed as
time = distance/speed
From the information given,
distance of person from cliff = 245
total distance travelled by echo in returning = 245 x 2 = 490
speed of sound = 344 m/s
Thus,
time = 490/344
time = 1.42 seconds