How fast would a 4.5 kg rock be traveling if it's momentum was 6.7 kg*m/s?

Given that,

The earth's moon has a gravitational field strength of about 1.6 n/kg

Mass of Moon, \(M=7.35\times 10^{22}\ kg\)

To find,

The radius of the Moon.

Solution,

The formula for the acceleration due to gravity is given by :

\(g=\dfrac{GM}{r^2}\)

r is radius of the Moon

\(r=\sqrt{\dfrac{GM}{g}} \\\\r=\sqrt{\dfrac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.6}} \\\\r=1750437.44\ m\\\\r=1.75\times 10^6\ m\)

So, the radius of the Moon is \(1.75\times 10^6\ m\).

Answer:

The Wilson cloud chamber is used to study the direction, speed, and distance of charged particles. Explanation; ... The Wilson cloud chamber works by producing a super-saturated vapor, as explained by florin.

Explanation:

I hope it's help u

According to the work-energy theorem, the work done on an object by a net force equals the change in kinetic energy of the object. Essentially kinetic energy is the energy used for motion. Interestingly, as work is done on an object, potential energy can be stored in that object. A moving object has kinetic energy because work has been done on it. When work is done energy in one form is transferred to the kinetic energy of the moving object. To stop the object again, the same amount of work would have to be done to bring it back to rest.

Answer:

The horse will run a distance of 1.5 times the length of the rope around the pole with the rope tightly stretched.

Explanation:

The distance the horse will run around the pole with the rope tightly stretched can be calculated using the formula for the circumference of a circle:

Circumference = 2 × π × radius

Since the horse takes one and a half rounds, we need to multiply the circumference by 1.5 to get the total distance the horse runs around the pole.

Let's assume that the length of the rope is the radius of the circle, and the horse is tied at the center.

Therefore, the distance the horse will run around the pole with the rope tightly stretched is:

Distance = 1.5 × 2 × π × radius

Since the horse is tied with a long rope, we need to use the length of the rope as the radius of the circle.

Let's assume that the length of the rope is 'L'. Then the radius of the circle is equal to L/2π.

Substituting this value in the formula, we get:

Distance = 1.5 × 2 × π × (L/2π)

Simplifying the expression, we get:

Distance = 1.5 × L

Therefore, the horse will run a distance of 1.5 times the length of the rope around the pole with the rope tightly stretched.

If the participants hadn't been reassigned, age would have been a confounding variable. Option D

A confounding variable is a variable that is associated with both the independent variable and the dependent variable.

In this case, age is associated with both video game playing and mood. Younger people are more likely to play video games, and they are also more likely to have better moods.

If the participants hadn't been reassigned, the difference in mood between the experimental and control groups could have been due to the difference in age, not the difference in video game playing.

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Answer:

Because of melting and freezing a higher heat will make something a plasma or liquid by melting it. by freezing you can make a liquid or gas solid.

Explanation:

Reverberation is multiple echoes that prolong the sound and make it sound livelier.



Reverberation is the persistence of sound in an enclosed space after the original sound source has stopped. When a sound is produced in a room, it reflects off the surfaces of the room, such as walls, ceiling, and floor, and bounces back and forth multiple times before it eventually fades away. This multiple reflection of sound creates a series of echoes that can be heard in the room, which is known as reverberation.

Therefore, Reverberation can have a significant impact on the quality of sound produced in a room. In some cases, it can enhance the sound by creating a sense of spaciousness and liveliness, making the sound more natural and pleasant to the ear. However, in other cases, reverberation can be problematic and create a muddy sound that is difficult to understand or distinguish.

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See text below



What is reverberation? *

Choose

multiple echo that prolongs the sound, sounds livelier

single echo that deconstructs the sound, sounds muddy

an echo that give the fundamental harmonic

multiple echoes that makes the sound muddy

when a resonance creates an echo

The boxes acceleration up the ramp is approximately 0.109 m/s².

The forces acting on the box can be resolved into two components: one parallel to the incline (F_parallel) and one perpendicular to the incline (F_perpendicular).

Given:

Mass of the box (m) = 40.7 kg

Coefficient of kinetic friction (μ) = 0.17

The force pulling the box (F_p) = 173 N

Incline angle (θ₁) = 14.5°

Force angle (θ₂) = 25.7°

First, we need to calculate the components of the force pulling the box:

F_parallel = F_p * sin(θ₂)

F_perpendicular = F_p * cos(θ₂)

Next, let's calculate the force of friction:

F_friction = μ * (mass of the box) * g, where g is the acceleration due to gravity (approximately 9.8 m/s²)

The force component parallel to the incline is opposed by the force of friction, so:

Net force parallel to the incline (F_net_parallel) = F_parallel - F_friction

Now, we can calculate the acceleration using Newton's second law:

F_net_parallel = (mass of the box) * acceleration

Rearranging the equation, we get:

acceleration = F_net_parallel / (mass of the box)

Now we can substitute the values into the equations and calculate the acceleration

F_parallel = 173 N * sin(25.7°) ≈ 73.88 N

F_perpendicular = 173 N * cos(25.7°) ≈ 154.37 N

F_friction = 0.17 * (40.7 kg) * 9.8 m/s² ≈ 69.44 N

F_net_parallel = F_parallel - F_friction ≈ 73.88 N - 69.44 N ≈ 4.44 N

acceleration = (4.44 N) / (40.7 kg) ≈ 0.109 m/s²

Therefore, the box's acceleration up the ramp is approximately 0.109 m/s².

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A 20 g clay ball traveling east at 6.5 m/s and a 65 g clay ball moving north at 2.0 m/s clash and the speed and direction of the resulting 85 g clay ball is 4.68 m/s and 45°.

The collision is referred to be an inelastic collision if the total kinetic energy after the collision is lower than the total kinetic energy before the collision. In a two-dimensional collision, the two objects move and make a specific angle with one another after colliding. In an inelastic collision, the objects m₁ and m₂ are traveling in the same direction but at an angle of x degrees at v₁ and v₂ speeds, respectively.

Given

By conservation of momentum for horizontal components,

\(\begin{aligned}mu_1&=(m+M)v_x\\v_x&=\frac{mu_1}{m+M}\\&=\frac{0.020\times6.5}{0.085}\\&=\mathrm{1.53\;m/s}\end{aligned}\)

By conservation of momentum for vertical components,

\(\begin{aligned}Mu_2&=(m+M)v_y\\v_y&=\frac{Mu_2}{m+M}\\&=\frac{0.065\times 2.0 }{0.085}\\&=\mathrm{1.53\;m/s}\end{aligned}\)

A. The resultant speed of an 85 g clay ball,

\(\begin{aligned}v&=\sqrt{v_x^2+v_y^2}\\&=\sqrt{1.53^2+1.53^2}\\&=\mathrm{4.68\;m/s}\end{aligned}\)

B. The direction is found by,

\(\begin{aligned}\tan \theta&=\frac{1.53}{1.53}\\\theta&=45^{\circ}\end{aligned}\)

The answers are 4.68 m/s and 45°.

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Answer:

8 units

Explanation:

Answer:

0.610m/s^2

Explanation:

Acceleration is defined as the ΔV/ΔT. In this case, the change in velocity is 1.43-0.32=1.11 m/s. The change in time is 1.82 seconds. Plugging in what we know, it will result in an acceleration of 0.610 m/s^2.

Based on the acceleration-time graph, the segments of the motion in which the object experience a net force are both 1 and 3.

Newton's Second Law of Motion states that the acceleration of an object is inversely proportional to its mass and directly proportional to the net force acting on the physical object.

Mathematically, the net force acting on the car is given by Newton's Second Law of Motion:

\(F=ma =\frac{m(v\;-\;u)}{t}\)

Where:

Note: Mass represents the conversion factor between net force and acceleration on an acceleration-time graph.

Based on the acceleration-time graph, the segments of the motion in which there is a net force acting on the object are both 1 and 3 while it experienced constant acceleration at segment 2 and 4.

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Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².

Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.

Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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Answer:it’s A. right for ape x

Explanation:

Based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

A wave is a periodic distortion capable of traveling through a suitable media (either air or water).

In conclusion, based on data, digital waves are more reliable because they are less likely to change when copied (Option A).

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Answer:

What Is Moral Subjectivism? Moral subjectivism is based on an individual person's perspective of what is right or wrong. An individual can decide for themselves that they approve or disapprove of a certain behavior, and that is what determines if the behavior is right or wrong.

Answer:

8.25 V

Explanation:

We can ignore the 22Ω and 122Ω resistors at the bottom.  Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.

The 2Ω resistor and the 44Ω resistor are in parallel.  The equivalent resistance is:

1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω

This resistance is in series with the 12Ω resistor.  The equivalent resistance is:

1.913Ω + 12Ω = 13.913Ω

This resistance is in parallel with the 24Ω resistor.  The equivalent resistance is:

1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω

Finally, this resistance is in series with the 4Ω resistor.  The equivalent resistance of the circuit is:

8.807Ω + 4Ω = 12.807Ω

The current through the battery is:

12 V / 12.807Ω = 0.937 A

The voltage drop across the 4Ω resistor is:

(0.937 A) (4Ω) = 3.75 V

So the voltage between the bottom nodes and the top nodes is:

12 V − 3.75 V = 8.25 V

Answer:

Explanation:

A mixture can usually be separated back into its original components. Some examples of mixtures are a tossed salad, salt water and a mixed bag of M&M's candy.

The work done when the body is displaced

(i) from s = 0 to s = 0.4 m is 0.8 J

(ii) from s = 0 to s = 0.8 m is 0.4 J

b. The velocity is

(i) when s = 0.4 m is 2.0 m/s

(ii) when s = 0.8 m​​ is 2.0 m/s

The formula for work done is given below as follows:

Work done = force * distance

Hence, the work done is the area under the force-displacement graph.

The work done when the body is displaced

(i) from s = 0 to s = 0.4 m is :

Work done = ¹/₂* 4 * 0.4

Work done = 0.8 J

(ii) from s = 0 to s = 0.8 m

Work done = ¹/₂* 4 * 0.4 + {¹/₂* (-2) * 0.4}

Work done = 0.4 J

b. The velocity is calculated as follows:

v = √(u² + 2as)

where;

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacementt

Also;

a = F/m

where;

F is force and m is mass

(i) when s = 0.4 m

a = 0/0.20

a = 0

v = √2.0²

v = 2.0 m/s

(ii) when s = 0.8 m​​

a = 0/0.20

a = 0

v = √2.0²

v = 2.0 m/s

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Answer:

a. Not have to back out

When you perpendicular-park, if possible, you should select a space that lets you drive into the facing space so that when you leave, you will not have to back out. This will make it easier and safer for you to exit the parking spot and get back on the road.

Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.

Explanation: why do the star constellations seem to move across the sky

Answer:

because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.

Explanation:

Answer:

R1=3.333 Ohms

R2=10 Ohms

R3=16.666 Ohms

Explanation:

30 total

30=R1+R2R3

30=1(x):3(x):5(x)

x=3.3333

R1=3.333 Ohms

R2=10 Ohms

R3=16.666 Ohms

The wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

Frequency is the number of cycles of a periodic waveform that occur per unit of time. It is measured in Hertz (Hz).

We can use the equation λ=2L/n, where λ is the wavelength, L is the length of the string, and n is the harmonic number. Since the string has fixed ends, the harmonics must be odd-numbered, so we have n=1 for the fundamental frequency, n=3 for the second harmonic (315 Hz), and n=5 for the third harmonic (420 Hz).

Using n=1 and λ=2L/n, we get:

λ = 2L/1

λ = 2L

Using n=3 and λ=2L/n, we get:

λ = 2L/3

Using n=5 and λ=2L/n, we get:

λ = 2L/5

We can use the formula f=v/λ to relate the wave speed v, wavelength λ, and frequency f. For the two consecutive harmonics, we can write:

v/λ1 = f1

v/λ2 = f2

Since the two harmonics are consecutive, we can assume that they correspond to adjacent values of n, so we have:

λ1 = 2L/1 = 2L

λ2 = 2L/3

Substituting these values into the above equations and solving for v, we get:

v = f1λ1 = f2λ2 = (420 Hz)(2L) / (2L) = (315 Hz)(2L)/(2L/3) = 840 cm/s

To find the fundamental frequency, we use the formula f=v/λ1:

f = v/λ1 = 840 cm/s / 2L = (840 cm/s) / (0.75 m) = 1120 Hz

Therefore, the wave speed is 840 cm/s and the fundamental frequency is 1120 Hz.

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To determine the thrust applied by the engines, we can use Newton's second law of motion, which states that force (thrust) is equal to mass times acceleration. In this case, we need to calculate the force required to decelerate the plane from 30 m/s to 25 m/s in 12 seconds.

First, we calculate the change in velocity (∆v):

\(\displaystyle\sf \Delta v=25\,m/s-30\,m/s=-5\,m/s\)

Next, we calculate the acceleration (∆a) using the formula:

\(\displaystyle\sf \Delta a=\frac{\Delta v}{\Delta t}\)

where ∆t is the change in time, which is 12 seconds in this case.

\(\displaystyle\sf \Delta a=\frac{-5\,m/s}{12\,s}\)

Now, we can determine the force (thrust) applied by the engines using Newton's second law:

\(\displaystyle\sf F=m\cdot a\)

where m is the mass of the airplane, which is 480000 kg.

\(\displaystyle\sf F=480000\,kg\cdot \left(\frac{-5\,m/s}{12\,s}\right)\)

Calculating the result:

\(\displaystyle\sf F=-200000\,N\)

Therefore, the engines applied a thrust of -200000 Newtons (N) to decelerate the plane. The negative sign indicates that the thrust is in the opposite direction of the motion.

The statement that is correct is that the contents of the cup form a mixture.

Though the question is incomplete but I would try to give you a good explanation as much as I can. We must recall that when we talk about a mixture, we have to note that the term mixture would refer to the combination of two or more substances that do not chemically react together.

In this case, we have been told that we have a water that was pure and then we add dirt to it. It is clear that the water and the dirt do not react in any way hence what we have formed is a mixture.

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Starting from rest and accelerating at 4.8 m/s², the plane's velocity at time t is

v(t) = (4.8 m/s²) t

so that after 15 s, its speed at takeoff be

v(15 s) = (4.8 m/s²) * (15 s) = 72 m/s

In this time it takes for the plane to take off, it will travel a distance at time t of

x(t) = 1/2 (4.8 m/s²) t²

and it takes 15 s to take off, so the runway would have to have a length of

x(15 s) = 1/2 (4.8 m/s²) * (15 s)² = 540 m

The speed of the wind is 20 miles per hour.

To solve this problem, we can use the formula:

Speed = Distance/Time

Let's assume that the speed of the wind is x miles per hour.

With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:

460 = Airspeed + x

Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:

420 = Airspeed - x

We can solve this system of equations to find the airspeed of the plane:

460 = Airspeed + x

420 = Airspeed - x

Adding the two equations gives:

880 = 2Airspeed

Dividing both sides by 2 gives:

Airspeed = 440 miles per hour

Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:

460 = Airspeed + x

460 = 440 + x

x = 20

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Answer:

Halley's comet will next appear in the night sky in the year 2062. It orbits the sun every 75-76 years, so this is the time between appearances.