how is a trihalomethane molecule different from a methane molecule

Answer:

1) It gets slower the farther out they are.

2) The farther out you are from the sun the less gravitational pull you have, which makes it go slower as it orbits.

3) Gravity ;) :)

Explanation:

Hope this helps! Plz mark as brainliest! :)

1.) The four inner planets have slower orbits and the four outer planets have faster orbits.

2.) The closer a planet is to the Sun, the stronger the Sun's gravitational pull on it, and the faster the planet moves.

3.) Gravity

500 g of fluorine gas at 5.00 atm and 735 torr occupies a volume of approximately 4.97 liters.

To solve this problem, we can use the Ideal Gas Law, which states:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

To find the volume of fluorine gas, we need to rearrange the Ideal Gas Law equation to solve for V:

V = (nRT)/P

We are given the pressure (P = 735 torr), the mass (m = 500 g), and the temperature (T = 5.00 atm). However, we need to find the number of moles of fluorine gas in order to use the Ideal Gas Law.

We can use the molar mass of fluorine (F2) to convert from grams to moles:

molar mass of F2 = 2 x 19.00 g/mol = 38.00 g/mol

moles of F2 = mass/molar mass = 500 g/38.00 g/mol = 13.16 mol

Now we can plug in the values into the Ideal Gas Law equation:

V = (nRT)/P = (13.16 mol x 0.0821 L·atm/mol·K x 278.15 K)/735 torr

V = 4.97 L

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The correct option is (A) - This Bohr Model of atom describes that there are a total of 6 electrons in the given figure.

The electrons are positioned in circular orbitals at particular distances from the central nucleus in the Bohr model of the atom. These orbits create electron shells or energy levels, which allow us to see how many electrons are present in each shell. The number and the letter "n" are used to identify these energy levels. The first energy level nearest to the nucleus, for instance, is represented by the 1n shell. Normally, an electron resides in the shell with the lowest energy, which is the one closest to the nucleus. A photon of light's energy can raise it to a higher energy shell, but this is an unstable position, and the electron quickly returns to the ground state.

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ITS CCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC

Answer:

A) 12 mol H2O.

Explanation:

Hello,

In this case, for the given reaction:

\(2C_2H_6+7O_2\rightarrow 4CO_2 + 6 H_2O\)

We notice that oxygen is in a 7:6 molar relationship with water, for that reason, the resulting moles of water turn out:

\(n_{H_2O}=14molO_2*\frac{6molH_2O}{7molO_2} \\\\n_{H_2O}=12molH_2O\)

Thus, the answer is A) 12 mol H2O.

Best regards.

Answer:159.7grams

Explanation:

(55.85)2+(16)3

159.7grams

Answer:

The correct answer for plato/edmentum is C (159.7g)

If, a 24.0% of a sample of radioisotope decays in 8.73 s. Then, the half-life of this isotope will be -22.07 s.

To determine the half-life of the radioisotope, we can use the decay constant (λ), which is related to the half-life (T) through the following equation;

λ = ln(2) / T

where; λ = decay constant

T = half-life

Given; Decay percentage = 24.0%

Time = 8.73 s

First, we need to calculate the decay constant (λ) using the decay percentage;

Decay constant (λ) = -ln(1 - (decay percentage / 100)) / Time

λ = -ln(1 - (24.0 / 100)) / 8.73 s

Next, we can calculate the half-life (T) using the decay constant.

T = ln(2) / λ

T = ln(2) / (-ln(1 - (24.0 / 100)) / 8.73 s)

Simplifying further;

T ≈ ln(2) × 8.73 s / ln(1 - 0.24)

T ≈ 0.693 × 8.73 s / ln(0.76)

T ≈ 6.04989 s / (-0.27443)

T ≈ -22.07 s

Therefore, the half-life will be -22.07 s.

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Answer:

true

Explanation:

Diatomic oxygen (O₂) is more likely to appear than carbon dioxide (CO₂) or carbon monoxide (CO).

This is because diatomic oxygen is a highly abundant molecule in Earth's atmosphere, making up about 21% of the air we breathe. In contrast, carbon dioxide and carbon monoxide are present in much lower concentrations, with carbon dioxide making up only about 0.04% of the atmosphere and carbon monoxide being present in trace amounts.

Additionally, diatomic oxygen is involved in many important biological and chemical processes, such as respiration and combustion, which further increases its likelihood of appearing. Carbon dioxide and carbon monoxide, on the other hand, are mostly produced as byproducts of certain chemical reactions or as a result of human activities such as burning fossil fuels or deforestation.

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The molarity of NaClO in the bleach is 0.101 M (mol/L).

Molarity (M) is the number of moles of solute per liter of solution.

It is calculated by dividing the number of moles of solute by the volume of the solution in liters.

To find the molarity of NaClO in the bleach, we need to use the following information given in the question:

1L of bleach has a mass of 1,100 grams7.25% of the mass of bleach is NaClO1 mol of NaClO has a mass of 74.44 gramsTo begin the calculation, we need to determine the mass of NaClO in 1L of bleach.

To do this, we can use the fact that 7.25% of the mass of bleach is NaClO:Mass of NaClO in 1L of bleach = 0.0725 x 1,100 g = 79.75 g

Next, we can convert this mass of NaClO to moles using its molar mass:

moles of NaClO = 79.75 g / 74.44 g/mol = 1.07 mol.

Finally, we can use the formula for molarity to calculate the molarity of NaClO in the bleach:

Molarity = moles of solute / volume of solution in litersMolarity = 1.07 mol / 10 L = 0.107 M (mol/L)We can round this answer to three significant figures to get the final answer of 0.101 M (mol/L).

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First, we will calculate the number of moles of mixture of Xenon and Neon gases.Number of moles of mixture of Xenon and Neon gases:

Let x be the mole fraction of Neon.

Therefore, (1 - x) is the mole fraction of Xenon

.Mole fraction of Neon + Mole fraction of Xenon = 1x + (1 - x) = 1x = 1 - (1 -

x = 0 + x

x = 0.279

Mole fraction of Neon = 0.279

Mole fraction of Xenon = 0.721

Number of moles of gas = (Total Pressure * Volume)/(Gas Constant * Temperature)

Number of moles of Xenon = (7.10 atm * 16.75L * 0.721)/(0.08206 * (273 + 30))

Number of moles of Xenon = 8.44 moles

Number of moles of Neon = (7.10 atm * 16.75L * 0.279)/(0.08206 * (273 + 30))

Number of moles of Neon = 3.29 moles

Now, we can calculate the partial pressure of Xenon and Neon.

Partial pressure of Xenon:

Partial Pressure of Xenon = Mole fraction of Xenon * Total Pressure

Partial Pressure of Xenon = 0.721 * 7.10 atm

Partial Pressure of Xenon = 5.12 atm

Partial pressure of Neon

Partial Pressure of Neon = Mole fraction of Neon * Total Pressure

Partial Pressure of Neon = 0.279 * 7.10 atm

Partial Pressure of Neon = 1.98 atm

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Answer:

1.43 M

Explanation:

We'll begin by calculating the number of mole of the solid. This can be obtained as follow:

Mass of solid = 8.60 g

Molar mass of solid = 21.50 g/mol

Mole of solid =?

Mole = mass / molar mass

Mole of solid = 8.60 / 21.50

Mole of solid = 0.4 mole

Next, we shall convert 280 mL to litre (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

280 mL = 280 mL × 1 L / 1000 mL

280 mL = 0.28 L

Thus, 280 mL is equivalent to 0.28 L.

Finally, we shall determine the molarity of the solution. This can be obtained as illustrated below:

Mole of solid = 0.4 mole

Volume = 0.28 L

Molarity =?

Molarity = mole / Volume

Molarity = 0.4 / 0.28

Molarity = 1.43 M

Thus, the molarity of the solution is 1.43 M.

Answer:

59.46 g

Explanation:

To answer this question, the molecular weight of ammonium sulfate must be computed.  To accomplish this, the weights of the individual elements must be noted.
N=14.01\(\frac{g}{mol}\)

H=1.01\(\frac{g}{mol}\)

S=32.07\(\frac{g}{mol}\)

O=16.00\(\frac{g}{mol}\)

To compute the molecular weight:

\(2[14.01\frac{g}{mol}+4(1.01\frac{g}{mol})]+32.07\frac{g}{mol}+4(16.00\frac{g}{mol})=132.14\frac{g}{mol}\)

To calculate the mass:

\(0.45 mol(\frac{132.14g}{1mol})=59.463g\)

Answer:

the temperature of the ice cube makes it gets warmer

It will take approximately 398.44 days or 1.09 years for the solvent to decay by 80%.

Initial concentration of the solvent, c0 = 1200 μg/kg

Rate constant of the solvent, k = 1.74 x 10-3 /day

Using the first-order rate equation, the concentration of the solvent after time t can be calculated as shown below:

Ct = c0 e-kt

Where Ct is the concentration of the solvent at time t.

So, the concentration of the solvent after 10 years can be calculated as Ct = c0 e-kt

Where t = 10 years= 3650 days

Ct = 1200 e-(1.74 × 10-3/day × 3650 days)

= 1200 e-6.351

= 1200 × 0.0019

= 2.28 μg/kg of soil

The time it takes for 80% decay can be calculated as follows:

Ct/C0 = e-kt

Where C0 is the initial concentration of the solvent.

C0 = 1200 μg/kg, Ct = 0.8C0 = 0.8 × 1200 = 960 μg/kg

Thus, e-kt = Ct/C0 = 960/1200 = 0.8t = -ln(0.8)/k= -ln(0.8)/1.74 x 10-3 /day= 398.44 days

Therefore, it will take approximately 398.44 days or 1.09 years for the solvent to decay by 80%.

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Answer:

Explanation:

This link will take you to a work sheet that I think might help.

The coefficients in front of each reactant and product allow us to predict how much reactants are required to form a given amount of products.

Reactants are converted to products and the process is symbolized by a chemical equation. For example  (Fe) and  (S) combine to form iron sulfide Fe(s) + S(s) → FeS(s) The plus sign indicates that iron reacts with sulfur.

Therefore, chemical equation is a mathematical expression of the chemical reaction which represents the product formation from the reactants. In an equation the reactants are written on the left-hand side and the products are written on the right-hand side demonstrated by one-headed.

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The enthalpy of the reaction is 14 J/mol.

The enthalpy of a reaction (ΔH) is the amount of energy transferred between a system and its surroundings during a chemical reaction at constant pressure, measured in joules per mole (J/mol). This value is important because it can tell us whether a reaction is exothermic or endothermic, as well as give us information about the strength of chemical bonds within the reactants and products.To calculate the enthalpy of a reaction, we need to know the amount of energy released or absorbed (Q) and the number of moles of the compound involved in the reaction (n). We can use the equation:
ΔH = Q/n
Given that 6 moles of a compound produce 84 J of energy, we can calculate the enthalpy of the reaction as follows:
ΔH = Q/n
ΔH = 84 J / 6 mol
ΔH = 14 J/mol
This means that for every mole of the compound involved in the reaction, 14 J of energy is transferred between the system and the surroundings. Since the value is positive, we can conclude that the reaction is endothermic, meaning that it requires an input of energy to occur.It is worth noting that the enthalpy of a reaction can depend on a number of factors, such as temperature, pressure, and the specific conditions under which the reaction occurs. As such, it is important to take these factors into account when calculating or predicting enthalpy values.

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The statement, which solely follows the lock and key model is that the active site of the enzyme possesses a rigid composition complementary to that of a substrate.

The substrate serves as the key and the enzyme serves as the lock in the lock and key model. This model demonstrates that the substrate has a specific form that only allows it to fit in the enzyme and prevents the binding of any other substrate. According to the induced fit model, when an enzyme's active site interacts with the proper substrate, the enzyme modifies its configuration to conform to the structure of the molecule.

The statement which follows the induced fit model is that the conformation of the enzyme changes when it combines with the substrate so that the active site fits with the substrate.

Both models imply the statements that the substrate and enzyme interact noncovalently and that the binding of the substrate to the active site of the enzyme results in an enzyme-substrate complex.

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Answer:  81.7 ml

Explanation:  

1 cm^3 = 1 ml

Divide the total mass by it's density to find it's volume:

(52.4g/7.87g/ml) = 6.658 ml

Add to 75.0 ml to arrive at a final volume of 81.7 ml

The mole fraction of \(N_2\)in the mixture is approximately 0.522.

To determine the mole fraction of \(N_2\) in the mixture, we need to calculate the total pressure and the partial pressure of \(N_2\).

Given partial pressures:

P(\(N_2\)) = 3.5 atm

P(\(O_2\)) = 2.8 atm

P(Ar) = 0.25 atm

P(He) = 0.15 atm

To calculate the mole fraction, we need to consider the total pressure of the mixture, which is the sum of the partial pressures of all the gases.

Total pressure (P_total) = P(\(N_2\)) + P(\(O_2\)) + P(Ar) + P(He)

P_total = 3.5 atm + 2.8 atm + 0.25 atm + 0.15 atm

P_total = 6.7 atm

Now, we can calculate the mole fraction of \(N_2\)(X(\(N_2\))) using the formula:

X(\(N_2\)) = P(\(N_2\)) / P_total

X(\(N_2\)) = 3.5 atm / 6.7 atm

X(\(N_2\)) ≈ 0.522 (rounded to three decimal places)

Therefore, the mole fraction of \(N_2\)in the mixture is approximately 0.522.

Mole fraction represents the fraction of the total number of moles that is contributed by a particular component. In this case, the mole fraction of \(N_2\)tells us that \(N_2\)contributes about 52.2% to the total moles of the gases in the mixture.

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Mass of calcium carbonate (in grams) can be dissolved by 4.1 g of Hcl is 5.62g.

A balanced equation is one for a chemical reaction in which the overall charge and the number of atoms for each component are the same for both the reactants and the products. In other words, the mass and charge of both sides of the reaction are equal.

The reaction between calcium carbonate and hydrochloric acid can be expressed through the chemical reaction,

CaCO₃ + 2HCl --> CaCl₂ + H₂O + CO₂

Hydrochloric acid has a molecular weight of 36.45 g/mol compared to calcium carbonate's molecular weight of 100 g/mol. According to the equation above, 72.9 g of hydrochloric acid may dissolve 100 g of calcium carbonate.

x = (4.1 g HCl)(100 g CaCO3 / 72.9 HCl)

x = 5.62 g.

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B is the answer ,ammonium accepts a proton and becomes ammonium ion

Answer:immiscible

Explanation:

When two liquids combine to form a new liquid, we call the liquids “miscible.” When two liquids do not mix together and instead form layers, we call them “immiscible.” The chemical properties of the liquids will determine if they will mix or not.

Answer:

410 nm

Explanation:

when an electron falls from ni=6 to nf=2 , a photon of wavelength 410 nm is emitted.

When an electron falls then the wavelength of the electromagnetic radiation emitted is = 410 nm.

When The Electromagnetic wavelength directs to the measured distance between the trough or crest of each adjacent wave generated by the electromagnetic disturbance.

When the wavelength of electromagnetic radiation is comparable to the de Broglie wavelength of its quantum (photon).

Now we are Showing that the wavelength of electromagnetic radiation is comparable to the de Broglie wavelength of its quantum (photon).

Therefore, when an electron falls from ni=6 to nf=2, a photon of wavelength 410 nm is emitted.

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Answer:

56.94759 grams of NO2

Explanation:

Stoichiometric Equation:

1 S + 6 HNO3 → 1 H2SO4 + 6 NO2 + 2 H2O.

This is so you can create ratios between each compound in the reaction, and identify the limiting and excess reactants to determine exactly how much can be produced?

The coefficients or molecular quantity of each compound in the balanced equation represents the amount of moles.

To figure out how much can be produced, you have to convert 59.54 g of S into moles of S and 78 g of HNO3 into moles of HNO3.

A reference such as a periodic table can be very helpful as it has the atomic mass of each element which is the mass with respect to 1 mol of that element.

\textbf{Question:}

In a particular experiment, a 4.00 g sample of CaO is reacted with excess water, and 2.14 g of Ca(OH)2 is recovered. What is the percent yield in this experiment?

\textbf{Answer:}

The Percent yield in this experiment is 40.5%.

What is the percent yield?

In chemistry, the percentage yield is used to compare a reaction's actual outcome to the maximum anticipated outcome.

The actual yield and the theoretical yield must be compared in order to calculate the percent yield.

Given: \ce{CaO}mass equals 4.00 g

\ce{Ca(OH)2}

recovered mass (actual yield): 2.14 g

The reaction's chemical equation is balanced as follows:

\ce{Ca(OH)2(s)} is created when  \ce{CaO(s)} and water combine.

The stoichiometric ratio of  \ce{CaO}to \ce{Ca(OH)2} is 1:1, as can be shown from the equation. It follows that 1 mole of \ce{CaO} interacts to become 1 mole of \ce{Ca(OH)2}.

We first compute the amount of moles of \ce{CaO} to be used in the theoretical yield calculation:

Moles of \ce{CaO} = \(\frac{{\text{{Mass of \ce{CaO}}}}}{{\text{{Molar mass of \ce{CaO}}}}}\)

\ce{CaO}'s molecular weight is 40.08 \, \text{g/mol}.

Moles of CaO = \(\frac{{4.00 \, \text{{g}}}}{{40.08 \, \text{{g/mol}}}}\)

Next, we determine the theoretical yield of \ce{Ca(OH)2} in grams:

Theoretical yield = Moles of CaO \times \text{{Molar mass of \ce{Ca(OH)2}}}

The molar mass of \ce{Ca(OH)2} is 74.09 \, \text{g/mol}.

Theoretical yield = Moles of CaO \times 74.09 \, \text{{g/mol}}

Finally, we can calculate the percent yield:

Percent yield = \(\frac{{\text{{Actual yield}}}}{{\text{{Theoretical yield}}}} \times 100\%\)

Percent yield = \(\frac{{2.14 \, \text{{g}}}}{{(\text{{Moles of CaO}}) \times 74.09 \, \text{{g/mol}}}}\) \times 100\%

Hence, the percent yield in this experiment is approximately 40.46\%.

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Answer:

Phosphorus ( white) us highly reactive and ignites at about 30°C when exposed to moist air

Answer:

Neutrons, Atomic Number, Atomic Mass

Explanation:

The Atomic mass is used to calculate the number of Neutrons in an atom.

Every atom is composed of Protons and Neutrons forming a tight compact nucleus orbited by electrons. The Atomic number of an element tells how many Protons the nucleus has. This is important because it determines how many electrons the atom has and consequently, its chemical properties. The Atomic mass (rounded to the nearest whole number) is the sum of the Protons and Neutrons in the elements nucleus, since their masses are nearly identical (Neutrons have one electron worth more mass than Protons). You subtract an element's Atomic number from its Atomic mass and you get the number of neutrons the element has in the nuclei of its atoms.