how is horsepower relative to the power use of a phone or light bulb?​

Answers

Answer 1

Answer:

More horsepower = more power use.

Explanation:

Horsepower is just a measure of power, similar to Watts (1 horsepower = 745.7 W). So, as a simple example, a lightbulb that uses 1 hp will have a higher power use than a lightbulb that uses 2 hp.


Related Questions

What will happen to people involved in handling Gamma rays if they are not providedwith lead coated apron and equipment without safety measures❤

Answers

Answer:

When gamma rays pass through the human body, they ionize the tissue.  gamma ray ionization can affect healthy cells. When high levels of gamma rays bombard a body, a resulting dangerous ionization of tissue can cause skin cancer.

Explanation:

Two long thin parallel wires 13.0 cm apart carry 32-A currents in the same direction. Determine the magnitude of the magnetic field vector at a point 10.0 cm from one wire and 6.0 cm from the other (Figure 1). Express your answer using two significant figures. B = Determine the direction of the magnetic field vector at that point. Express your answer using two significant figures. theta = degree measured counterclockwise from the positive x axis

Answers

To find the magnitude of the magnetic field at the given point, we can use the formula for the magnetic field created by a long straight wire:

B = (μ0 * I) / (2π * r)

where B is the magnetic field, μ0 is the permeability of free space (4π × 10^−7*\(10^-^7\) T·m/A), I is the current, and r is the distance from the wire.

Given:

Distance from one wire (r1) = 10.0 cm = 0.10 m

Distance from the other wire (r2) = 6.0 cm = 0.06 m

Current (I) = 32 A

Using the formula above, we can calculate the magnetic field from each wire separately:

B1 = (μ0 * I) / (2π * r1)

B2 = (μ0 * I) / (2π * r2)

Substituting the given values:

B1 = (4π ×\(10^-^7\) T·m/A * 32 A) / (2π * 0.10 m)

B2 = (4π × \(10^-^7\)T·m/A * 32 A) / (2π * 0.06 m)

Simplifying the expressions:

B1 = 2 × \(10^-^5\) T

B2 = 5.3 ×\(10^-^5\) T

To find the total magnetic field at the point, we need to add the contributions from both wires:

B = B1 + B2 = (2 × \(10^-^5\) T) + (5.3 × \(10^-^5\) T) = 7.3 × \(10^-^5\) T

Therefore, the magnitude of the magnetic field at the given point is approximately 7.3 × \(10^-^5\) T.

To determine the direction of the magnetic field at that point, we can apply the right-hand rule. If we point the thumb of our right hand in the direction of the current in one wire, the curled fingers will indicate the direction of the magnetic field. In this case, both currents are in the same direction, so the magnetic field vectors will point in the same direction. Therefore, the direction of the magnetic field at the given point is parallel to the wires and points away from the wires.

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How much work must be done to stop a 925-kg car
traveling at 95 km/h?

Answers

V = 95 km/h = 95/3.6 = 26.39 m/sec

Stored kinetic energy Ek = 1/2mV^2 = 925* 26.39^2/2 = 322,073 joule

can EM waves pass through solid objects

Answers

Answer:

no.

Explanation:

It’s true that sound travels fastest through solids, but solid objects actually block sound waves from reaching a given space. The reason behind this is very simple: you see, when sound originates from a point, travels through a medium, and then encounters a solid object, it loses some of its energy.

Answer:

These changing fields form electromagnetic waves. Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.

Explanation:

A physics student is driving his pick-up
truck down Lake Avenue. The pick-up is
equipped with a projectile launcher that
imparts a vertical velocity to a water-filled
rubber projectile. While traveling 20.0 m/s
in an eastward direction, the projectile is
launched vertically with a velocity of 58.8
m/s.
Fill in the table at the right. showing the
horizontal and vertical displacement of the
projectile every second for the first 12
seconds.

Answers

TOTAL FLIGHT TIME

Rising Projectile

vi = initial velocity = 58.8 m/s

vf = final velocity = 0

g = gravity acceleration = -9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (0 - 58.8)/-9.81

t = -58.0/-9.81

t = 5.99 s ≈ 6.00 s

Falling Projectile

vi = initial velocity = 0

vf = final velocity = 58.8 m/s

g = gravity acceleration = 9.81 m/s²

t = elapsed time = to be determined

vf = vi + gt

vf - vi = gt

(vf - vi)/g = t

t = (vf - vi)/g

t = (58.8 - 0)/9.81

t = 58.0/9.81

t = 5.99 s ≈ 6.00 s

t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time

HORIZONTAL DISTANCE TRAVELED

v = velocity, horizontal = 20.0 m/s

d = to be determined

t = elapsed time = 12.0 s

v = d/t

vt = d

d = vt

d = (20.0 m/s)(12.0 s)

d = 240 m Horizontal Distance Traveled

00

why does the roof of your car get hot in the sun

Answers

The roof of your car gets hot in the sun because of the absorption of solar radiation.

When sunlight hits the surface of your car's roof, it is exposed to solar radiation, which consists of various types of energy such as ultraviolet, visible, and infrared light. The roof's material absorbs this energy, causing the atoms and molecules within the material to vibrate and generate heat. This process leads to an increase in the temperature of your car's roof.

To describe this phenomenon further, the color and material of the car's roof also play a role in determining how much heat is absorbed. Darker colors absorb more sunlight and heat compared to lighter colors. Additionally, the metal or material used in the roof may have different thermal properties, which can influence the amount of heat absorbed and retained.

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A motor is used to pump water from a depth of 5m to fill a volume of 10cubic meter in 5 min . If 50 percent of the power is wasted , What is the power of the motor?

Answers

Vevdbdb
Fxyodupfigigifoydyodoyfpufpuinthrfbfbrhrbrbrthththtbtbyby

two nearly equal wavelengths of light are incident on an n-slit grating. the two wavelengths are not resolvable. when n is increased, without changing the separation between slits, the two wavelengths become resolvable. this is because

Answers

Increasing the number of slits in an n-slit grating increases the angular separationy between the diffracted orders, which makes it possible to resolve two nearly equal wavelengths of light that were previously not resolvable.

The resolution of an n-slit grating depends on the angular separation between the diffracted orders. The angular separation is given by:

Δθ = λ/d

where λ is the wavelength of light, d is the distance between adjacent slits, and Δθ is the angular separation between the diffracted orders.

When two nearly equal wavelengths of light are incident on an n-slit grating, the angular separation between the diffracted orders is small and the two wavelengths are not resolvable.

This means that the diffraction patterns overlap and cannot be distinguished from each other.

However, when the number of slits in the grating is increased without changing the separation between the slits, the angular separation between the diffracted orders also increases. This means that the diffraction patterns of the two wavelengths move farther apart, and they become resolvable.

This is because the angular separation between the diffracted orders depends on the number of slits in the grating, and not on the wavelength of light. Increasing the number of slits increases the angular separation between the diffracted orders, making it possible to resolve the two wavelengths of light.

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consider a concave mirror that has a focal length f. in terms of f, determine the object distances that will produce a magnification of:____

Answers

To determine the object distances that will produce a specific magnification in a concave mirror with a focal length f, we can use the mirror equation and the magnification formula.

The mirror equation relates the object distance (denoted as "d_o"), the image distance (denoted as "d_i"), and the focal length (denoted as "f") of a mirror:
1/f = 1/d_i + 1/d_o
The magnification (denoted as "m") of a mirror is given by the ratio of the image height (h_i) to the object height (h_o):
m = -d_i / d_o = h_i / h_o
To determine the object distance that will produce a specific magnification, we need to express the object distance in terms of the focal length and the desired magnification.
Solving the magnification formula for the image distance:
d_i = -m * d_o
Substituting this expression into the mirror equation:
1/f = 1/(-m * d_o) + 1/d_o
Simplifying:1/f = (-1 + m) / (m * d_o)
Now, we can solve for the object distance:
1/d_o = (1/f) * (m / (1 - m))
Taking the reciprocal:
d_o = (1 - m) * (f / m)
Therefore, in terms of the focal length f, the object distance that will produce a magnification of "m" in a concave mirror is given by:
d_o = (1 - m) * (f / m)
This formula allows us to calculate the object distance for a desired magnification value using the focal length of the concave mirror.

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How many seconds will it take for a the International Space Station to travel 450 km at a rate of 100 m/s?

Answers

Time = (distance) / (speed)

Time = (450 km) / (100 m/s)

Time = (450,000 m) / (100 m/s)

Time = 4500 seconds (that's 75 minutes)

Note:

This is about HALF the speed of the passenger jet you fly in when you go to visit Grandma for Christmas.

If the International Space Station flew at this speed, it would immediately go ker-PLUNK into the ocean.

The speed of the International Space Station in its orbit is more like 3,100 m/s, not 100 m/s.

Your dog spins in a circle 2 times in 3 seconds (his radius is 0.5 m). What is his displacement in 2 complete turns?

Answers

he gained more energy

a baseball player feels a frictional force of 400N as she slides into home. what impulse would be created?

Answers

The impulse that would be created by the  baseball player is  600 Ns.

What is the impulse created by the baseball player?

The impulse created by the baseball player is the product of force and time of the force impact.

J = Ft

where;

F is the applied forcet is the time of force action

The frictional force created by the baseball player = 400 N.

The time of force action = 1.5 seconds

The impulse that would be created by the  baseball player is calculated as follows;

J = 400 N x 1.5 seconds

J = 600 Ns

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The complete question is below:

A baseball player feels a frictional force of 400N as she slides into home. what impulse would be created if the force acted for 1.5 seconds?

the head loss through a straight pipe can be represented by a friction factor f h equals fraction numerator 4 f l u squared over denominator 2 g d end fraction where h : head loss (m) l : pipe length (m) u : average flow velocity (m/s) g ; gravitational acceleration (m/s2) d : pipe diameter (m) what is the unit of a friction factor f?

Answers

After canceling out the common units, we can observe that the friction factor (f) is dimensionless, meaning it has no units.

The formula that has been provided for head loss through a straight pipe is commonly known as the Darcy-Weisbach equation, which relates the head loss to the flow rate and properties of the pipe. The friction factor f is a measure of the resistance to flow through the pipe and is determined by the roughness of the pipe wall and the Reynolds number of the flow. A detailed explanation of how to calculate the friction factor is beyond the scope of this answer, but it involves solving the Colebrook-White equation, which is an empirical relation derived from experimental data. The friction factor is an important parameter in many fluid mechanics problems, as it affects the pressure drop and energy losses in the system.

The unit of the friction factor (f) in the equation for head loss (h) through a straight pipe can be determined from the

equation h = (4 * f * l * u²) / (2 * g * d). In this equation, h is the head loss (m), l is the pipe length (m), u is the average flow velocity (m/s), g is the gravitational acceleration (m/s²), and d is the pipe diameter (m).

To find the unit of friction factor (f), we need to rearrange the equation to solve for f. This can be done by multiplying both sides by (2 * g * d) and then dividing by (4 * l * u²):

f = (h * 2 * g * d) / (4 * l * u²)

Now, we can substitute the units of each variable into the equation:

f = [(m) * (m/s²) * (m)] / [(m) * (m/s)²]

Thus, after canceling out the common units, we find that the friction factor (f) is dimensionless, meaning it has no units.

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picture is attached with question ​

picture is attached with question

Answers

59.00 m is the calculated distance.

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position. The International System of Units defines a meter as the distance unit. It's interesting to note that many other derived units or quantities, such as volume, area, acceleration, and speed, may be constructed using this as the basic unit and a few formulae.

V = V₀ + at = 4.30 + 3.00*5.00 = 19.30 m/s

d = V₀t + (1/2) at²

= 4.30*5.00 + (1/5.00) ² = 59.00 m

or

d = (1/2) (V₀+V) t

= (1/2) (4.30+19.30) (5.00)

= 59.00 m

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MISSED THIS? Read Section 8.5 (Pages 331 - 337) ; Watch KCV 8.5B, IWE 8.7. Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions. Part A n=4→n=3 Express the frequency in inverse seconds. Part B n=5→n=1 Express the frequency in inverse seconds.

Answers

Explanation:

I don't know exactly how much money you have on the company because you're not helpful enough as your friends and coworkers

(a) The frequency of light emitted when an electron in a hydrogen atom undergoes a transition from n = 4 to n = 3 is approximately 2.466 × 10¹⁵ Hz (inverse seconds).

(b) The frequency of light emitted when an electron in a hydrogen atom undergoes a transition from n = 5 to n = 1 is approximately 3.288 × 10¹⁵ Hz (inverse seconds).

Determine the frequency (ν) of light?

The frequency (ν) of light emitted during a transition in a hydrogen atom can be calculated using the Rydberg formula:

ν = R_H * (1/n₁² - 1/n₂²)

Where R_H is the Rydberg constant (approximately 3.29 × 10¹⁵ Hz), n₁ is the initial energy level, and n₂ is the final energy level.

(a) For the transition from n = 4 to n = 3:

ν = R_H * (1/3² - 1/4²)

  = R_H * (1/9 - 1/16)

  = R_H * (16/144 - 9/144)

  = R_H * (7/144)

  ≈ 2.466 × 10¹⁵ Hz

(b) For the transition from n = 5 to n = 1:

ν = R_H * (1/1² - 1/5²)

  = R_H * (1 - 1/25)

  = R_H * (24/25)

  ≈ 3.288 × 10¹⁵ Hz

The Rydberg constant (R_H) is a fundamental constant in atomic physics that relates to the wavelengths of light emitted or absorbed during electronic transitions in hydrogen-like atoms.

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the graph represents the height y, in meters, above a lake of a rock x seconds after it is thrown from a ledge. which statements are true? select each correct answer. responses the rock reaches a maximum height of 43 m. the rock reaches a maximum height of 43 m. the rock reaches a maximum height of 38 m. the rock reaches a maximum height of 38 m. the rock travels at 4 m/s . the rock travels at 4 , m per s, . the height of the rock is decreasing for 2 s. the height of the rock is decreasing for 2 s. the rock is in the air for 4 s.

Answers

The statements that are true are:

The rock reaches a maximum height of 43 m.The height of the rock is decreasing for 2 s.

Explanation:

The given statements are related to the graph representing the height of a rock thrown from a ledge over time. Looking at the options, the first statement correctly states that the rock reaches a maximum height of 43 m, as indicated by the graph.

The second statement is also true, as the graph shows a downward slope for a duration of 2 seconds, indicating that the height of the rock is decreasing during that time period.

The remaining statements in the options do not accurately describe the information given in the question or are not supported by the graph.

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the spring of the pressure gauge shown in the figure below has a force constant of 1 050 n/m, and the piston has a diameter of 1.40 cm. as the gauge is lowered into water in a lake, what change in depth causes the piston to move in by 0.580 cm?

Answers

The depth change causes the piston to move in by 0.580 cm is equal to 4.03 m.

What is Hooke's law?

Hooke's law can be described as an empirical law that states that the force (F) required to extend or compress a spring by distance (x) scales linearly w.r.t. that distance.

F = -kx, where k is a constant factor and x  is the possible deformation of the spring.

ΔF = k(x-x₀) = k Δx

The gauge pressure beneath the surface of the fluid at height h is given by:

p - p₀ = ρghA

Therefore, the height h can be calculated as:

ρghA = k Δx

h = k Δx/ρgA

Given, k = 1050 N/m,  density (ρ) of water = 1000 Kg/m³, g = 9.8 m/s²

Area, A = πr² = 3.14 ×(1.40/2)² = 1.54 cm² = 1.54 ×10⁻⁴m²

Δx = 0.580 cm = 0.0058 m

Therefore, h = 1050 ×0.0058/9.8×1000× 1.54 ×10⁻⁴

Depth change, h = 4.03 m

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the circuit for video example ve 1.1. a) loop equation: definite branch i1,i2, in r1 and r2 respectively. write two equation and solve them

Answers

The circuit expression for i1 and i2 in terms of r1, r2, and ve is \(i1 = (i2 * r2) / r1\)

we need to consider the loop involving branches i1 and r1, and the loop involving branches i2 and r2.


We can use Ohm's law to write the equation:

\(i1 * r1 - ve = 0\)


Next, let's write the loop equation involving i2 and r2:

\(i2 * r2 - ve = 0\)

Now, we have two equations:
\(i1 * r1 - ve = 0    (Equation 1)\\\\i2 * r2 - ve = 0    (Equation 2)\)

To solve these equations, we can substitute ve from Equation 1 into Equation 2:

\(i2 * r2 - (i1 * r1) = 0\)

We can rearrange this equation to solve for i2:

\(i2 = (i1 * r1) / r2\)

Similarly, we can solve for i1 by substituting ve from Equation 2 into Equation 1:

\(i1 * r1 - (i2 * r2) = 0\)

Rearranging this equation gives us:

\(i1 = (i2 * r2) / r1\)

Now, we have expressions for i1 and i2 in terms of r1, r2, and ve. By substituting the given values of r1, r2, and ve, we can calculate the values of i1 and i2.

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At the local destruction derby a 400 kg Toyota moving at 10 m/s collides with an 800 kg Chevy. Both are at rest after the collision. What was the velocity of the Chevy before the collision?​

Answers

Answer:

\(u_2 = -5m/s\)

Explanation:

Given

Before Collision

Toyota

\(mass = m_1 = 400kg\)

\(iniital\ velocity = u_1 =10m/s\)

Chevy

\(mass = m_2=800kg\)

\(initial\ velocity = u_2 = ??\)

After Collision

Both Toyota and Chevy

\(final\ velocity = v = 0m/s\)

Required

Determine the initial velocity of Chevy

This question will be answered using the following law of conservation of momentum which states that:

\(m_1u_1 + m_2u_2 = (m_1 + m_2)v\)

Substitute values for m1, m2, u1 and v

\(400 * 10 + 800 * u_2 = (400 + 800) * 0\)

\(4000 + 800u_2 = (1200) * 0\)

\(4000 + 800u_2 = 0\)

Collect Like Terms

\(800u_2 = 0 - 4000\)

\(800u_2 = -4000\)

Divide through by 800

\(\frac{800u_2 = -4000}{800}\)

\(u_2 = \frac{-4000}{800}\)

\(u_2 = -5m/s\)

The velocity of Chevy before collision was 5m/s in the opposite direction of Toyota

How does solar energy work

Answers

Answer:

When the sun shines onto a solar panel, energy from the sunlight is absorbed by the PV cells in the panel. This energy creates electrical charges that move in response to an internal electrical field in the cell, causing electricity to flow.

you attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen. what's going on?

Answers

The multimeter is probably broken and you should give it to your instructor/TA is used to measure the electric potential difference, but the value stays at 0.00 v no matter what you do and there is an h on the screen.

What is a multimeter?

A multimeter is an electronic instrument used to measure electrical properties such as voltage, current, and resistance. It is also known as a multi-tester, VOM (volt-ohm-milliammeter), or DMM (digital multimeter). Multimeters are an essential tool for electricians and other technicians, as they allow for accurate and precise measurements of various electrical values. Multimeters are available in a range of styles and designs, from basic models to more advanced versions with additional features.This means that the multimeter is not taking any readings and is displaying the last measured value. You may need to press the "hold" button on the multimeter to turn it off and allow it to take new readings.

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3. You attempt to use your multimeter to measure the electric potential difference, but the value stays at 0.00 V no matter what you do and there is an H on the screen. What's going on?

The multimeter is probably broken and you should give it to your instructor/TA.You probably plugged in the wires incorrectly. Try using the 10A and V ports.Someone pressed the "Hold" button. If you press it again, the multimeter should work correctly.Someone pressed the "Handheld" button. The multimeter will only work if you hold it in your hand while using it.

A resistor is not a very good______.​

Answers

Answer:

Conductor.

Explanation:

Resistors conduct electricity, but put up oppisition to the current flow.

A laser beam is incident on two slits with a separation of 0.210 mm, and a screen is placed 5.05 m from the slits. If the bright interference fringes on the screen are separated by 1.59 cm, what is the wavelength of the laser light?

Answers

Answer:

0.66*10^-6m

Explanation:

We know that the bright fringes are placed on the screen as follows

Ym= m*(lambda xL/d)

But we are given

L= 5.05

Deta Y= 1.59

d = 0.21

1.59* 10^-2m= lambda * 5.05m/2.1*10^-4m

So lambda=

1.59* 10^-2m x 2.1*10^-4m/ 5.05m

= 0.66*10^-6m

which is larger 15mm or 0.15cm

Answers

Answer:

1 cm = 10mm

Explanation:

hey there both are equal

Why does a green leaf look green in our eyes

Answers

They look green because of the “special pair” of chlorophyll molecules.

Answer:

because the leaf absorbs all the other colors except for green. So the leaf reflects the green color which is what we see. that is why a leaf spears to be green.

Explanation:

floor gang aooh sub to pewdiepie

All of the following moves would be considered part of the second great migration except a move _____.

select the best answer from the choices provided.
a.
from rural arkansas to detroit
b.
from south carolina to seattle
c.
from pittsburgh to rural florida
d.
from beaumont, texas, to los angeles

Answers

The move considered not part of the Second Great Migration is from Pittsburgh to rural Florida. The correct answer is option c.

The Second Great Migration refers to the mass movement of African Americans from the rural South to urban areas in the North and West during 1940-1970. This migration was mainly driven by the pursuit of better economic opportunities and escaping racial segregation.

Options a, b, and d represent moves from the South to the North and West (from Rural Arkansas to Detroit, South Carolina to Seattle, and Beaumont, Texas, to Los Angeles). However, option c (from Pittsburgh to rural Florida) is the opposite direction, moving from an urban area in the North back to the rural South, making it the exception.

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Which change to a circuit is most likely to increase its electrical power?
A. Increase its current and increase its voltage.
B. Decrease its current and increase its voltage.
C. Decrease its current and decrease its voltage.
D. Increase its current and decrease its voltage.

Answers

The correct answer is option A. Increase its current and increase its voltage. To increase the electrical power of a circuit.

1.Understanding electrical power: Electrical power is calculated as the product of voltage and current in a circuit. It can be represented by the formula P = VI, where P is power, V is voltage, and I is current.

2.Voltage and current relationship: Increasing either the voltage or the current in a circuit will result in an increase in power, as long as the other value also increases proportionally.

3.Increasing current: By increasing the current flowing through a circuit, more electrical charge is transferred per unit of time, which leads to an increase in power.

4.Increasing voltage: Increasing the voltage in a circuit increases the electric potential difference across the components. This higher potential difference causes the electric charges to move with more force, resulting in an increase in power.

5.Combined effect: When both the current and voltage are increased simultaneously, the power of the circuit is multiplied, leading to the highest increase in electrical power.

Therefore, increasing both the current and voltage in a circuit (option A) is the most likely change to increase its electrical power.

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block a of mass 4m is attached by a light string to block b of mass 2m. the string passes over a pulley with negligible friction and of negligible mass. block a is held a distance h above the ground, as shown. the blocks are released from rest, and block a reaches the ground two seconds later. the value of h is most nearly

Answers

The kinematics and Newton's second law allow us to find the height from which the block system descends is:

             y = 6.54 m

Given parameters

Body mass m1 = 4 kg The mass of the body on the ground m² = 2 kg The descent time t = 2s

To find

Body height

Newton's second law gives a relationship between the net force, the mass, and the acceleration of the body.

      ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

Kinematics studies the movement of bodies, looking for relationships between position, velocity and acceleration

              y = v₀ t + ½ a t²

In the attached we have a free body diagram of the system, let's write Newton's second law.

          T - W₁ = m₁ a

         -T + W₂ = m₂ a

Let's solve the system of equations.

          W₂ - W₁ = (m₁ + m₂) a

          a = \(\frac{m_2-m_1}{m_2+m_1} \ g\)

Let's calculate

          a = \(\frac{2 -4}{ 2 +4} \ 9.8\)  

          a = -3.27 m / s²

The negative sign indicates that the heaviest body is descending.

Now we can use kinematics to find the height, as the system comes out of rest the initial velocity is zero, when he reaches the ground his height is zero.

             y = y₀ + v₀ t + ½ a t²

             0= y₀ + 0  +½ a t²          

Let's calculate

             y₀ = ½ 3.27 2²

             y = 6.54 m

In conclusion, using kinematics and Newton's second law we can find the height from which the block system descends is:

             y = 6.54 m

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block a of mass 4m is attached by a light string to block b of mass 2m. the string passes over a pulley

What is the momentum of a 70 kg man who is running with a velocity of 2.5 m/s?

Answers

Answer:

175kg.m/s

Explanation:

Momentum= mv 70kg*2.5m/s

Q3. A space probe is traveling in outer space with a momentum that has a magnitude
of . A retrorocket is fired to slow down the probe. It applies a force to
the probe that has a magnitude of and a direction opposite to the probe’s
motion. It fires for a period of 12 s. Determine the momentum of the probe after the
retrorocket ceases to fire

Answers

The momentum of the probe after the retrorocket ceases to fire is 9.9 * 10^7 Kg m/s

What is the momentum?

We know that the momentum of an object has to do with the product of the mass and the velocity of an object. The momentum of an object is a vector quantity and the direction of the momentum is the direction of the velocity of the object that is in motion.

According to the Newton second law of motion, we know that the rate of change of the momentum is equal to the impressed force that is acting on the body.

We know that;

\(F_{t}\) = \(p_{f}\) -\(p_{i}\)

F = force

t = time taken

\(p_{f}\)= final velocity

\(p_{i}\) = initial velocity

\(p_{f}\) = \(F_{t}\)  + -\(p_{i}\)

\(p_{f}\) = (2.0 * 10^6 * 12 s) + 7.5 * 10^7

\(p_{f}\)  = 2.4 * 10^7 + 7.5 * 10^7

\(p_{f}\)  = 9.9 * 10^7 Kg m/s

Hence, the momentum of the retrorocket is 9.9 * 10^7 Kg m/s.

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Missing parts;

A  space probe is traveling in outer space with a momentum that has a magnitude of  7.5 * 10^7 kgm/s. A retrorocket is fired to slow down the probe. It applies a force to the probe that has a magnitude of 2.0  * 10^6 N and a direction opposite to the probe's motion. It fires for a period of 12 s. Determine the momentum of the probe after the retrorocket ceases fire.

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