how is the physical property of density calculated?

The dimensions in the equation are consistent.

Equation of motion, is a mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.

x = at²

where;

x (m) = a(m/s²) x t²(s²)

multiple m/s² with s² = m

x(m) = at²(m)

Thus, the dimensions in the equation are consistent.

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The criterion of significant figures can to find the result with reliable figures

          X = 9.2 10⁻⁵

now with the propagation of errors we obtain the result with its uncertainty

         X ± ΔX = (9.2 ± 0.5) 10⁻⁵

given Parameter

     * expression values ​​with their absolute errors

to find

     * the result with the correct significant figures

     * the absolute error of the expression

Significant figures are defined with the number of decimals that give information, the number of figures in a quantity gives information about the uncertainty of this quantity.

There are two criteria for applying significant figures:

     * Add and subtract the result of going with the number of decimal places of the figure that has the least

    * Product and division as a result of going with the least number of significant figures than the value that has the least.

Remember that the zero to the left do not form a pair of the significant figures

Let's apply this belief to the case presented, let's write the precaution

              \(x = \frac{a-b}{c}\)

where in this case they are worth

         a = 0.0336 ± 0.0002

         b = 0.010 ± 0.001

         c = 255.4 ± 0.4

We see that the significant figures of each parameterize (a, b, c) and their absolute errors are correct.

Let's apply the criteria to the operation

          a-b = 0.0336 - 0.010

          a- b = 0.0236

we apply the criterion of significant figures for the subtraction, the result must be with 3 decimal places

        a - b = 0.024

let's do the other operation

         X = \(\frac{a-b}{c}\)

         X = 0.024 / 255.4

         X = 9.24 10⁻⁵

We apply the criterion of significant figures for the division, in this case the result is left with two significant figures

         X = 9.2 10⁻⁵

The uncertainty or error of the measurements is of most importance as it determines how many significative figures are reliable at a given magnitude.

If the magnitudes are measured with some type of instrument, the absolute error is given by the appreciation of the instrument, if the magnitude is calculated using some equation, the errors must be propagated using the variations of each parameter in the worst case.

the uncertainty of the calculated quantity (X) is

        \(\Delta X = | \frac{dX}{da}| \Delta a + | \frac{dX}{db} | \Delta b + | \frac{dX}{dc}| \Delta c\)

let's perform the derivatives

        \(\frac{dX}{da} = \frac{1}{c}\)

        \(\frac{dX}{db} = - \frac{1}{c}\)

        \(\frac{dX}{dc} = - \frac{a-b}{c^2}\)

we substitute

remember that the bulk value guarantees that we tune the worst case. So all the mistakes add up

          ΔX = \(\frac{1}{c}\)  Δa +

          ΔX = (Δa + Δb) + Δc

we substitute

         ΔX = \(\frac{1}{255.4}\)  (0.0002 + 0.001) + \(\frac{0.0336-0.010}{255.4^2}\)  0.4

         ΔX = 4.698 10⁻⁶ + 1.45 10⁻⁷

         ΔX = 4.8 10⁻⁶

Absolute errors must be given with a single significant figure

         ΔX = 5 10⁻⁶

The result of the requested quantity using the criterion of significant figures and propagation of errors is

          X ± ΔX = (9.2 ± 0.5) 10⁻⁵

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The amplitude of the oscillations change as time goes on is the more rigid (or less compressible) the medium, the faster the speed of sound.

In physics, amplitude refers to the greatest displacement or distance that a point on a vibrating body or wave can move relative to its equilibrium location. It is equivalent to the vibration path's half-length.

Distance between the wave's resting position and its highest displacement is known as amplitude. The number of waves that pass by a specific location each second is known as its frequency. Period: the amount of time needed for a wave cycle to complete.

Sound waves' relative strength, which we experience as loudness or volume, is known as amplitude. Decibels (dB), which stand for sound pressure level or intensity, are used to measure amplitude.

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The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

The potential difference ∆V = V(r₂) -V(r₁) between points at radial distances r₂ = 2 cm and r₁ = 1 cm can be calculated using the formula:

                                ∆V = (λ/2πεο) ln(r₂/r₁)

where λ is the linear charge density, εο is the permittivity of free space, r₁ and r₂ are the radial distances, and ln is the natural logarithm. Plugging in the given values, we get:

∆V = (2x10⁻⁹ C/m/2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2 cm/1 cm)
∆V = (2x10⁻⁹  C/m/ 2π(8.85x10⁻¹² C/V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹)) ln(2)
∆V = (1.14x10⁻² V⁻¹m⁻¹) (0.693)
∆V = 78.9 V⁻¹m⁻¹
∆V = 78.9 V/m

Therefore, the potential difference ∆V=V(r2) -V(r1) between points at radial distances r₂ = 2 cm and r₁ = 1 cm is 78.9 V/m.

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Explanation:

show me the paper so that way i can answer your question

Answer: the answer is 4

Explanation:

Answer:

224 J

Explanation:

Step one:

given data

Force applied = 22.4 N

distance = 10 meters

Required:

the work done

Step two:

The expression for the work done is

WD= force*distance

substitute

WD= 22.4*10

WD= 224 J

Answer:

Mechanical Sound Waves - A sound wave moves through air by displacing air particles in a chain reaction. ... Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. For pitch the higher the frequency, the higher the pitch. Frequency is measured in hertz, or cycles per second. Frequency also affects loudness, with higher-pitched sounds being perceived as louder. Amplitude and frequency of sound waves interact to produce the experiences of loudness and pitch.

the friction force provided by the brakes is 30000 N.

Friction force is the force that opposes the motion between two bodies in contact.

To calculate the average friction force provided by the brakes, we apply the formula below.

Formula:

Where:

Make F' the subject of the equation

From the question,

Given:

Substitute these values into equation 2

Hence, the friction force provided by the brakes is 30000 N

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Answer:

4.

Distance:

Total distance traveled is the sum of the distances for each leg of the journey:

Distance = 100 + 200 + 150 + 50 + 75 + 400 + 25 = 1000 m

Therefore, the person traveled a total distance of 1000 m.

5.

Displacement:

Displacement is the straight-line distance from the starting point to the ending point, taking into account direction.

To find the displacement, we need to add up all the distances traveled in the North direction and subtract the distances traveled in the South direction:

Displacement = (100 + 50 + 75) - (200 + 150 + 400 + 25) = -550 m

The negative sign indicates that the person ended up 550 m South of the starting point.

6.

Speed:

Speed is the distance traveled divided by the time it took to travel that distance:

Speed = Distance / Time

The total time taken is 500 seconds, and the total distance traveled is 1000 m, so:

Speed = 1000 / 500 = 2 m/s

Therefore, the person's average speed was 2 m/s.

7.

Velocity:

Velocity is the displacement divided by the time it took to travel that distance:

Velocity = Displacement / Time

The displacement is -550 m, and the total time taken is 500 seconds, so:

Velocity = -550 / 500 = -1.1 m/s

The negative sign indicates that the person was traveling Southward.

Therefore, the person's average velocity was -1.1 m/s.

8.

Time to walk a metric mile:

A metric mile is 1609.34 m.

The person's average speed was 2 m/s, so the time it should take to walk a metric mile is:

Time = Distance / Speed = 1609.34 / 2 = 804.67 seconds

Therefore, it should take the person 805 seconds or 13 minutes and 25 seconds to walk a metric mile.

9.

Percent error:

The actual time taken to walk a metric mile was 880 seconds. The percent error is:

% Error = [(Theoretical Time - Actual Time) / Theoretical Time] x 100%

% Error = [(805 - 880) / 805] x 100% = -9.3%

The negative sign indicates that the actual time taken was faster than the theoretical time. The percent error is 9.3%.

10.

Acceleration of a Porsche 911 GT3:

The acceleration of a Porsche 911 GT3 is reported to be 0-60 mph in 2.7 seconds.

To convert this to mph/s, we need to divide the change in velocity (60 mph) by the time (2.7 s):

Acceleration = 60 / 2.7 = 22.2 mph/s

Therefore, the acceleration of a Porsche 911 GT3 is 22.2 mph/s.

11.

Time to reach top speed:

The top speed of a Porsche 911 GT3 is reported to be 198 mph.

Starting from 60 mph, the change in velocity required to reach the top speed is:

Change in velocity = 198 - 60 = 138 mph

To find the time it takes to reach this change in velocity, we can use the following equation:

Change in velocity = Acceleration x Time

Solving for time:

Time = Change in velocity / Acceleration = 138 / 22.2 = 6.2 seconds

Therefore, it should take the Porsche 911 GT3 6.2 seconds to reach its top speed if it starts from 60 mph.

Answer:

100.390407

Explanation:

To find acceleration, you would use the formula a=f/m (acceleration equals force divided by mass) and then once you enter those numbers in the formula, a=180/1.793. Then you divide 180 divided by 1.793 which gets you an answer of 100.390407.

Answer:

depends on how you look at light, gaps do not form between photons as light spreads out

Explanation:

A period in physics oscillation is the time it takes for one complete cycle of an oscillating object or wave.

When an object or system oscillates, it moves back and forth periodically. The period of the oscillation is the time it takes for the object to complete one full cycle of motion. For example, the period of a simple pendulum is the time it takes for the pendulum to swing back and forth once.

The period of an electromagnetic wave is the time it takes for one full cycle of the wave to occur. The period is often measured in units of time, such as seconds, milliseconds, or microseconds. The frequency of the oscillation, which is the number of cycles per second, is the inverse of the period.

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The error in the estimate of acceleration due to gravity (g) is approximately -0.02π(T√(Lg)).

The formula for the period of a simple pendulum is given by:

T = 2π√(L/g)

Where:

T is the time period of the pendulum

L is the length of the pendulum

g is the acceleration due to gravity

Taking the derivative of the equation with respect to g:

d(T)/d(g) = -πL/(T√(L/g))

Using the concept of error propagation, the relative error in g (Δg/g) can be calculated as:

(Δg/g) = (ΔT/T) / (d(T)/d(g))

Substituting the given values into the equation:

(Δg/g) = (0.02) / (-πL/(T√(L/g)))

(Δg/g) = -0.02π(T/g)(√(L/g))

To obtain the absolute error in g, we can multiply the relative error by the estimated value of g:

Error in g (Δg) = (Δg/g) * g

Error in g (Δg) = (-0.02π(T/g)(√(L/g))) * g

Error in g (Δg) = -0.02π(T√(Lg))

Note that the negative sign indicates a decrease in the estimate of g due to the errors in length and time period.

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To do this, we will use the formula for constant acceleration:

v = u + at

where:
v = final velocity (45 mph, which we will convert to m/s)
u = initial velocity (starting from rest, so 0 m/s)
a = constant acceleration (what we want to find)
t = time (2.0 s)

First, let's convert 45 mph to m/s:
1 mile = 1609.34 meters
1 hour = 3600 seconds
45 mph * (1609.34 m/mile) * (1 hour/3600 s) ≈ 20.12 m/s

Now we have v = 20.12 m/s, and we can plug the values into the formula:

20.12 m/s = 0 m/s + a(2.0 s)

To find the acceleration (a), divide both sides by 2.0 s:

a = (20.12 m/s) / (2.0 s)
a ≈ 10.06 m/s²

So, the cheetah's constant acceleration is approximately 10.06 m/s².

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Answer:

Given Mas (m) =63kg

velocity (v) =4.3m/s

momentum (p) =?

p=mv

63kgx4.3m/s

270.9kg.m/s

the momentum =270.9kg.m /s

If a ball of mass 0.63 kilograms is moving at 4.3 meters/seconds, then the momentum of the ball would be 2.709-kilogram meters/second.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle.

Momentum = mass of the object × velocity of the object

As given in the problem we have to calculate the momentum of the ball if it has a mass of 0.63 kilograms and moving with a speed of  4.3 meters/seconds,

The momentum of the ball = 0.63× 4.3

                                             =2.709 kilogram meters/second

Thus, the momentum of the ball comes out to be 2.709-kilogram meters/second.

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Answer:

B.white block

hope it's the answer ....❤❤❤❤❤❤

ANSWER:

85.97 m/s

STEP-BY-STEP EXPLANATION:

Bernoulli’s theorem is written as:

The potential energy is zero as the height is same, therefore:

The air speed above the wings is 85.97 m/s

Answer:

Newton’s first law states that an object will remain at rest or in motion at a constant velocity unless acted on by a net external force. Newton’s second law states that the force acting on an object is equal to its mass times its acceleration. When a rocket hits an asteroid, the asteroid will remain still until acted upon by the force of the rocket. The force of impact will depend on the mass and acceleration of the rocket.

Explanation:

Newton’s first law, also known as the law of inertia, states that an object at rest remains at rest, or if in motion, remains at a constant velocity unless acted on by a net external force. This means that a rocket will remain still until a force is applied to move it. Once it’s in motion, it won’t stop until a force is applied.

Newton’s second law states that the force acting on an object is equal to its mass times its acceleration (F=ma). This means that the more mass an object has, the more force is needed to move it. During a rocket launch, the engines burn the propellant to fuel the rocket, using it all up until it is gone. Thus, the rocket’s mass becomes smaller as the rocket ascends. So, in keeping with Newton’s second law of motion, the rocket’s acceleration increases as its mass decreases.

When a rocket hits an asteroid, both Newton’s first and second laws come into play. The asteroid will remain still until acted upon by an external force (the rocket). The force of impact will depend on the mass and acceleration of the rocket.

Answer:

5.00

Explanation:

a sinθ=mλ

You are missing (a) so you move sinθ to the other side than solve from there.

For first diffraction, the width of the slit is \(5*10^{-5} m\).

Diffraction of light is defined as the bending of light around corners such that it spreads out and illuminates areas where a shadow is expected.

a sinθ=mλ

\(a = \frac{1*488*10^{-9} }{sin 0.559}\)

\(a = 5*10^{-5} m\)

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Answer:

Tide rising and falling would be different from the moon near the Earth .

The distance of the trip that Kayak travelled at an average speed of 18 mph in 5 hour is 90 miles

First, we shall obtain the eqaution to determine the distance. This can be obtained as follow:

Speed is defined as:

Speed = distance / time

Cross multiply

Distance = speed × time

With the above formula, we can obtain the distance. Details below

The following data were obtained from the question:

Distance = speed × time

Distance = 18 × 5

Distance = 90 miles

From the above calculation, we conclude that the distance traveled is 90 miles

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At the opposite end of the hose, a trillion water molecules will emerge. (Big scale conservation)

A water molecule is an ion by nature, but the bond between the two hydrogen atoms, each of which has a positive charge, and the oxygen atom, each of which has a negative charge, is what is known as a covalent bond. The hydrogen (white) and oxygen (red) atoms of a single H2O molecule are held together by powerful links known as covalent bonds. Two atoms, in this case oxygen and hydrogen, share electrons to form covalent bonds. When one oxygen atom joins with two different hydrogen atoms in a covalent link, water is created. It is possible for both hydrogen atoms to obtain the single electron they require for their outer shells thanks to this configuration, which also provides oxygen with the two electrons it requires to fill its shell.

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According to Huygens' principle, every point on a wave front acts as a source of a new spherical wave. Therefore, the correct answer is (B) spherical.

This principle was proposed by Dutch physicist Christiaan Huygens in the late 17th century and it describes the propagation of waves. According to this principle, each point on a wavefront is considered to be the source of secondary wavelets that spread out in all directions. The sum of these wavelets gives the new wavefront at a later point in time.

This principle of Huygens is used to study the phenomenon of diffraction and refraction. According to Huygens' principle, any point on a wave front can be thought of as a source of secondary waves. The superposition of two waves is referred to as interference, whereas interference caused by several waves is referred to as diffraction.

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The Stefan-Boltzmann constant (represented by the symbol σ) is a physical constant that relates the intensity of thermal radiation emitted by a blackbody to its temperature.

It is named after the Austrian physicist Josef Stefan and the Dutch physicist Ludwig Boltzmann.The value of the Stefan-Boltzmann constant is approximately 5.67 x 10^-8 watts per square meter per Kelvin to three significant figures.

The exact value of the constant is:

σ = 5.670374419... x 10^-8 W/(m^2.K^4)

where W is watts, m is meters, and K is Kelvin, which are the units of power, distance, and temperature, respectively.

The Stefan-Boltzmann constant is used in many fields of physics and engineering, particularly in the study of thermodynamics, astrophysics, and radiative heat transfer. It is a fundamental constant in physics, and its value has been determined experimentally with high precision.

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After considering the given data the height from which the gannet dived is approximately 51.84 m.

To evaluate the height from which a gannet dived if it hits the water at 32 m/s, assuming that the gannet was motionless before starting its dive, we can apply the law of conservation of energy, which projects  that the initial potential energy of the gannet is equivalent to its final kinetic energy prior to hitting the water. Then, we can write:
\(mgh = (1/2)mv^2\)
Here:
m = mass of the gannet
g = acceleration due to gravity
h = height from which the gannet dived
v = velocity of the gannet just before hitting the water
Considering that the mass of the gannet is 1 kg, and applying substitution of the given values, we get:
\((1 kg)(9.8 m/s^2)(h) = (1/2)(1 kg)(32 m/s)^2\)
\(h = (1/2)(32 m/s)^2 / (9.8 m/s^2)\)
h = 51.84 m
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The complete question is
A gannet is a seabird that fishes by diving from a great height. If a gannet hits the water at 32 m/s , what height did it dive from? Assume that the gannet was motionless before starting its dive.

The Radius loop of 34.88m that coaster could go around with speed of 18.5m/s.

Mass of rollercoaster =2800kg

Speed is 18.5m/s

\(V=\sqrt{gR}\\ \\V=speed=18.5m/s\\\\g=gravity=9.81m/s^2\\\\R=radius\)

Calculation- squaring both sides of equation.

\(V^2=gR\\\\R=V^2/g\\\\R=18.5^2/9.81\\\\R=342.25/9.81\\\\R=34.88m\)

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Therefore, the resonant frequency of the LC circuit is approximately 795.8 Hertz..

The resonant frequency of an LC circuit can be calculated using the formula: f = 1 / (2π √(LC))

The given equation relates the resonant frequency (f) in Hertz with the inductance (L) in Henrys and capacitance (C) in Farads.

In this case, the inductance of the circuit is 0.500 mH, which is equivalent to 0.0005 H, and the capacitance is 40.0 μF, which is equivalent to 0.000040 F. Substituting these values into the formula, we get:

f = 1 / (2π √(0.0005 H × 0.000040 F))

f ≈ 795.8 Hz

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If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

option D is the correct answer.

Half life is the time that it takes for half of the original value of some amount of a radioactive element to decay.

If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is calculated as follows;

1,000 ---------- 0 time

500 ----------- 10.4 hours

125 ------------- 20.8 hours

Thus, from the calculation done above, we can see that If you start with 1,000 grams of erbium-165, the time it  will take to have 125 grams of erbium-165 left in the sample is 20.8 hours.

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