How many atoms of carbon are present in 200 mg of Ibuprofen.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. The volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

a. The chemical equation for the electrolysis of water is:

2H2O(l) → 2H2(g) + O2(g)

b. The gas obtained at the anode during the electrolysis of water is oxygen (O2).

c. According to the balanced chemical equation, for every 2 moles of water (H2O) electrolyzed, 1 mole of oxygen gas (O2) is obtained. Since 1 mole of any gas occupies 22.4 L at standard temperature and pressure (STP), we can use the stoichiometry of the reaction to determine the volume of oxygen gas produced.

Given that 50 cm³ of gas is obtained at the anode, we need to convert this volume to liters:

50 cm³ = 50/1000 L = 0.05 L

Using the stoichiometric ratio of the balanced equation, we find that 2 moles of water produce 1 mole of oxygen gas. Therefore, 0.05 L of oxygen gas is equivalent to:

0.05 L × (1 mole/22.4 L) = 0.002232 moles

Thus, the volume of gas obtained at the anode is 0.002232 moles or approximately 0.05 L of oxygen gas.

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24. To calculate the molarity of a solution, we must first find out how many moles of \(BaI_2\) are in the solution.

Molar mass of BaI2 = (1 x atomic mass of Ba) + (2 x atomic mass of I)

= (1 x 137.33 g/mol) + (2 x 126.90 g/mol)

= 137.33 g/mol + 253.80 g/mol

= 391.13 g/mol

Number of moles of BaI2 = mass of BaI2 / molar mass of BaI2

= 413 g / 391.13 g/mol

= 1.056 mol

the molarity of the solution using the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

Volume of solution = 750 ml = 750 ml / 1000 ml/L = 0.750 L

Molarity = 1.056 mol / 0.750 L

= 1.408 M

Therefore, the molarity of the solution is 1.408 M.

25. a. \(P_20_7\) - Ionic compound (Phosphorus(V) oxide)

b. \(SnBr_2\) - Ionic compound (Tin(II) bromide)

c. \(Fe(OH)_2\)-  Ionic compound (Iron(II) hydroxide)

d. \(Cl_30_8\) - Not a valid chemical formula

26.

A. (NH4)2CO3 is soluble in water (NH4) in an ionic substance called 2CO3 containing the ions carbonate and ammonium.

B. Fe(OH)2 is insoluble in water. Iron(II) hydroxide is only sparingly soluble.

C. CaOH is not soluble in water. Only very little calcium hydroxide is soluble.

D. PbCl2 is insoluble in water. The chloride of lead(II) is sparingly soluble.

27. FeS + 2KCl = FeCl2 + K2S

FeS is an insoluble precipitate.

2KCl dissolves in aqueous solution.

ZnCl2 + SrSO4 = ZnSO4 + SrCl2

SrSO4 is an insoluble precipitate.

ZnCl2 dissolves in aqueous solution.

28. In salt water, the solute is the salt (sodium chloride, or NaCl), and the solvent is water. The element which dissolves in the solvent to form a solution is called solute.

29. Charles's law states that, if the pressure and volume of a gas remain constant, the volume of a gas falls as the temperature increases. As a result, the capacity of the balloon will decrease as it ascends to altitudes where the temperature is -15 °C.

30. The average kinetic energy of the particles of a substance increases with increase in its temperature. This is because temperature is a gauge for the specific kinetic energy of the constituent particles of a substance. On the other hand, the average kinetic energy falls as the temperature increases.

31. When the volume of a gas decreases, its pressure increases. Boyle's law, which states that at a given temperature, the pressure of a gas is inversely proportional to its volume, describes this relationship. On the other hand, pressure falls when volume increases.

32. The pressure of a gas increases along with its temperature. Gay–Lussac's law, which states that the pressure of a gas is directly proportional to its temperature, given the volume and volume of the gas is constant, describes this relationship.

33. The volume of a syringe is reduced as a marshmallow is pressed and the plunger is depressed. As a result the pressure inside the syringe increases. This is because Boyle's law states that the volume and pressure of a gas are inversely proportional. The decrease in volume causes the air inside the syringe to contract, exerting more pressure on the marshmallow, which is then crushed.

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The arrow in a chemical equation represents the direction of the reaction. It indicates the conversion of reactants into products. The arrow points from the reactant side to the product side, symbolizing the flow of the reaction.

The purpose of the arrow is to visually represent the chemical transformation occurring in the reaction. It shows the relationship between the reactants and products and the direction in which the reaction proceeds. The arrow implies that the reactant molecules are being rearranged and transformed into new substances with different properties.

Chemical equations are used to describe the stoichiometry and balance of reactions. The arrow helps convey this information by illustrating the overall process taking place. It serves as a crucial element in understanding the reaction's composition, reaction conditions, and the substances involved.

Furthermore, the arrow also implies that the reaction can occur in both directions. In reversible reactions, the arrow can be represented as a double-headed arrow, indicating that the reaction can proceed in either direction depending on the conditions.

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Answer:

C industrial processes and gems

Explanation:

Non - metallic minerals can be used for industrial processes and as gems. Some non - metallic minerals have great value, good cut and attract a good market price. Example is ruby and tourmaline.

The question is incomplete. Her eis the complete question.

Steam reforming methane  (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

Answer: \(K_{c}\) = 2.\(10^{-2}\)

Explanation: The reaction for steam reforming methane is:

\(CH_{4} + H_{2}O\) ⇒ \(CO_{} + 3H_{2}\)

To calculate the concentration equilibrium constant, first calculate the molarity (\(\frac{mol}{L}\)) of each molecule of the reaction.

At 38°C: At the initial temperature, there no products yet

Molarity of CH4:

CH4 = \(\frac{20}{125}\) = 0.16M

Molarity of H20:

H2O = \(\frac{10}{125}\) = 0.08M

At final temperature:

Molarity of H2:

H2 = \(\frac{18}{125}\) = 0.144M

According to the chemical reaction, the combination of 1 mol of each reagents produces 1 mol of CO and 3 mols of H2, so, for the products, the ratio is 1:3.

Molarity of CO:

CO = \(\frac{0.144}{3}\) = 0.048M

For the reagents, the proportion is 1:1, but they had an initial concentration, so, when in equilibrium, the concentration will be:

Molarity of CH4:

CH4 = 0.16 - 0.048 = 0.112M

Molarity of H2O:

H20 = 0.08 - 0.048 = 0.032M

The equilibrium constant is given by:

\(K_{c} = \frac{[CO][H_{2}]^{3} }{[CH_{4}][H_{2}O ] }\)

\(K_{c}\) = \(\frac{0.048.0.144^{3} }{0.112.0.032}\)

\(K_{c}\) = 2.\(10^{-2}\)

The concentration equilibrium constant for the process is \(K_{c}\) = 2.\(10^{-2}\).

Answer:

heptan-2-one

Explanation:

In this case, the final product would be a ketone: heptan-2-one. To understand why this molecule is produced we have to check the reaction mechanism.

The first step is the protonation of the triple bond to produce the more stable carbocation (a secondary one) by the action of sulfuric acid \(H_2SO_4\). The next step is the attack of water to the carbocation to produce a new bond between C and the O, producing a positive charge in the oxygen. Then, a deprotonation step takes place to produce an enol. Finally, we will have a rearrangement (keto-enol tautomerism) to produce the final ketone.

See figure 1

I hope it helps!

Answer:

try can be hammered into thin sheets

Explanation:

i understand your confusion because when metal is hot usually turns red and really hot molten lava consistency and becomes “stretchy” like

1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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The formula is written for the compound as C3OBr6

The empirical formula is the simplest whole number ratio of the atoms of the elements present in a compound. It represents the lowest whole number ratio of atoms in a molecule of a chemical substance. The empirical formula is determined by analyzing the elemental composition of a compound, either through chemical analysis or spectroscopic techniques.

We would then have that;

C - 6.8/12   O - 3.0/16    Br - 90.2/80

C - 0.57    O - 0.19   Br - 1.12

Dividing through by the lowest ratio we have;

C - 3    O -   1    B r -  6

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Answer:

930 pls mark me branilest

Answer:

11.0117647

Explanation:

The type of aluminum the students should plan to use in order to increase the reaction rate is powder because the greater surface area will allow more collisions between reactants to occur.

The correct option is A.

The nature of the surface area of the reactants will either decrease or increase the rate of reaction.

An increased surface area of the reactants will increase the rate of a reaction because the greater surface area will allow more collisions between reactants to occur.

A decrease in the surface area of the reactants will decrease the rate of a reaction because the greater surface area will not allow more collisions between reactants to occur.

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Answer:

b option is correct

Explanation:

we cannot ever know the speed and location of the electron

Answer:

C₂ = 50 mg/L

C₃ = 42.5 mg/L

Explanation:

To do this, we just need to use the following expression:

C₁V₁ = C₂V₂     (1)

Where:

C₁: Original concentration of the Iron solution (mg/L)

V₁: aliquot of the iron solution (mL or L)

C₂: Concentration of the iron after beind dilluted (mg/L)

V₂: Volume of the flask that's being used.

Using the above expression, we just solve for C₂:

C₂ = C₁V₁ / V₂   (2)

We have the required volumes, but we do not have the concentration of the iron solution (C₁). To determine this, we use the initial flask of 100 mL and the mass of the iron:

C₁ = 25 mg / 0.1 L = 250 mg/L

With this value, we can replace in (2) to get the concentration on each flask.

Flask 1:

We have an aliquot of 20 mL, and it was dilluted to 100 mL, the concentration would be:

C₂ = 250 mg/L * (20/100)

Flask 2:

We have an aliquot of 17 mL dilluted to 100 mL so:

C₃ = 250 * (17/100)

Hope this helps

The concentration of iron in mg/L in each of the two flasks is 50 mg/l and 42.5 mg/L respectively.

The initial concentration of iron in the sample is obtained as follows:

A vitamin tablet containing 25 mg of iron is dissolved in 6M HCl and then made up to 100 mL in a 100 mL volumetric flask with DI water.

Concentration of iron in the solution = 25 mg/ 100 mL

Converting to mg/L; 1 L = 1000 mL, then 100 mL = 1000 * 1 L/ 1000 mL = 0.1 L

Concentration of iron in the solution in mg/L = 25 mg / 0.1 L = 250 mg/L

Then 20 mL and 17 mL of this solution were pipetted into separate 100 mL volumetric flasks and each of these was brought up to 100 mL volume by diluting with DI water to the mark.

Using the dilution formula C₁V₁ = C₂V₂ to determine the concentration of iron in each of these flasks:

C₁ = initial concentration; V₁ = initial volume

C₂ = final concentration; V₂ = final volume

Flask 1:

C₁ = 250 mg/L, V₁ = 20 mL, C₂ = ?, V₂ = 100 mL

C₂ = C₁V₁ / V₂

C₂ = 250 * 20 / 100

C₂ = 50 mg/L

Flask 2:

C₁ = 250 mg/L, V₁ = 17 mL, C₂ = ?, V₂ = 100 mL

C₂ = C₁V₁ / V₂

C₂ = 250 * 17 / 100

C₂ = 42.5 mg/L

Therefore, the concentration of iron in mg/L in each of the two flasks is 50 mg/l and 42.5 mg/L respectively.

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Answer:

During Glycolysis, there is one step where NADH + H+ is formed from NAD+ O F-6-P - F- 1,6-BP O PGAL – 1,3-BPGA O 2-PGA - PEP O 3-PGA → 2-PGA.

The kind of graph which would be best to use with these data is: A. Circle graph.

A chart can be defined as an effective graphical tool which is used for displaying data graphically or in a pictorial form.

Basically, there are four (4) main types of chart used in the field of science and these are;

I. Bar chart.

II. Histogram.

III. Cartesian graph.

IV. Pie chart.

A circle graph is also referred to as a pie chart and it can be defined as a graphical representation that involves the division of a circle into various sectors that represents (depicts) a proportion or percentage of the circle respectively.

Hence, the various colors would be represented by a circle graph based on their percentage respectively.

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3.68*10-5 m/s  is the average rate of the reaction during this time period.

What is rate of reaction?

A rate of reaction is the speed at which a chemical reaction takes place. It is usually expressed as the change in the concentration of a reactant or product per unit time. The rate of a reaction is determined by many factors, including the physical state of the reactants, the temperature, the concentration of the reactants, the presence of a catalyst, and the surface area of the reactants that are in contact with each other.

2NO(g)+O2(g) -> 2NO_2(g)

Rate = -1/2 d[No]/dt

Average Rate = -1/2[0.0225-0.0700/650-5]

           = 3.68*10^-5 m/s

Therefore, 3.68*10-5 m/s  is the average rate of the reaction during this time period.

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Answer: The molarity of \(HCl\) is 0.07 M

Explanation:

According to the neutralization law,

\(n_1M_1V_1=n_2M_2V_2\)

where,

\(n_1\) = basicity \(HCl\) = 1

\(M_1\) = molarity of \(HCl\) solution = ?

\(V_1\) = volume of  \(HCl\) solution = 25.0 ml

\(n_2\) = acidity of \(NaOH\) = 1

\(M_1\) = molarity of \(NaOH\) solution = 0.1000 M

\(V_1\) = volume of  \(NaOH\) solution = 17.5 ml

Putting in the values we get:

\(1\times M_1\times 25.0=1\times 0.1000\times 17.5\)

\(M_1=0.07M\)

Therefore, molarity of \(HCl\) is 0.07 M

Answer:

I'm thinking ethier D or A

Explanation:

Answer:

d. ii.

Explanation:

Hello!

In this case, according to the displayed decimal placed by each balance, we can notice that:

i. Displays 1 decimal place.

ii. Displays 2 decimal places.

iii. Displays 4 decimal places.

iv. Displays 3 decimal places.

Thus, since the measured-out masses have two decimal places each, we infer that the used balance was d. ii as it displays two decimal places.

Best regards!

Answer: Na2HPO4

Explanation: this is the formula

Answer:

Na3PO4

Explanation:.

The image of the perchlorate that obeys the octet rule is shown in the image attached to this answer.

According to the Octet rule, we know that the electrons in an atom are said to be complete when we have eight electron in the outermost shell of the atom. Thus we have to look at each of the atoms in the compound perchlorate  so as to know if they obey the octet rule.

The Lewis structure of the compound would be complete when we add electrons as dots to each of the electrons. These electrons are the unshared pairs that reside on only one of the atoms in the compound.

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Answer:

Please see image.

Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging, radioactivity will be left in the patient’s body 72 hours after injection is 0.00024

The equation that describes the radioactive decay is:

Ln [A] = -kt + Ln [A]₀

Where [A] could be taken as activity of the source after time t, [A]₀ is initial activity and k is decay constant.

Decay constant could be written as:

k = ln2 / Half-life

k = ln 2 / 6h

k = 0.115h⁻¹

Replacing in decay equation:

ln a = -0.115 x 72  + Ln [53.8]

ln a = - 8.28 + 3. 98

ln a = - 8.28

log a = -4/ 2.303

log a = 1.867

Therefore if a patient receives a dose with an activity of 53. 8 mCi of technetium-99m for cardiac imaging. radioactivity will be left in the patient’s body 72 hours after injection is 1.867

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Answer:

Energy, more.

Explanation:

wavenumbers are directly proportional to energy and frequency of the radiation means that if one increases the other automatically increases whereas one decreases the other is also decreases. If the wavenumber increases, the energy of radiation is also increases while on the other hand, if the wavenumber decreases the frequency and energy of radiation is also decreases.

Answer:

batteries

Explanation:

bc they're powered by energy

The half reaction with a more positive standard reduction potential will proceed spontaneously in a redox reaction

The half reaction with a more positive standard reduction potential will undergo reduction when compared to the half reaction with a more negative standard reduction potential.

Oxidation-reduction reactions, often known as redox reactions, are a set of chemical reactions that involve electron transfer between reactants. In a redox reaction, one reactant is oxidized, losing electrons, while the other reactant is reduced, gaining electrons.

The oxidation half-reaction is the process of losing electrons and increasing the oxidation number, whereas the reduction half-reaction is the process of gaining electrons and decreasing the oxidation number. The total reaction is referred to as the redox reaction.

Half-reaction:Half-reaction refers to the two parts of an oxidation-reduction reaction that happen separately. A half-reaction must always be either an oxidation reaction or a reduction reaction. It also describes the movement of electrons and hydrogen ions in an equation.

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Answer:

Oxygen is a pure element. Water, however, is a compound molecule containing oxygen. Water also contains hydrogen, In an H2O molecule, the two hydrogen molecules and the oxygen molecules are chemically bonded together.

Answer:

Water is 1% oxygen and it is a compound

While oxygen is a Pure element that means it forms with only oxygen molecules

Explanation:

From the given equation of reaction:

Limiting reagents refers to the reactants in a given reaction which is completely used up at the end of a reaction.

Once the limiting reagent is used up, the reaction will stop.

Considering the given question and the data provided:

0.610 grams of hydrogen gas are allowed to react with 12.4 grams of ethylene (C₂H₄).

The equation of the reaction is as follows:

H₂ (g) + C₂H₄ (g) ---> C₂H₆ (g)

The mole ratio of the reactants is used to determine the limiting reactant.

Mole ratio of hydrogen to ethylene is 1 : 1

Moles of hydrogen = 0.610/2 = 0.305 moles

Moles of ethylene = 12.4/28 = 0.44 moles

The limiting reagent is hydrogen while the excess reagent is ethylene.

The maximum amount of ethane (C₂H₆ ) that can be formed is 0.305 moles.

mass of 0.305 moles of ethane = 0.305 * 30 grams

mass of 0.305 moles of ethane = 9.15 g

The moles of the excess reagent that remains after the reaction is complete = 0.44 - 0.305 = 0.135 moles

mass of 0.135 moles of ethylene = 0.135 * 28 = 3.78 grams

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