how many d-electrons are associated with the central metal ion in the complex: na2[cdcl4]? group of answer choices

The structure of the repeating unit of the polymer (HNCH₂CH₂NHCOCH₂CO).

The repeating units arise directly from the end-to-end bonding of many vinyl chloride molecules. The molecules that make up a polymer are called monomers. Each vinyl chloride monomer molecule contributes a CH2 group that is single-bonded to the CHCl moiety. They consist of basic building blocks, so-called monomers, the basic building blocks of polymers, which are repeated many times in each molecule.

In many biopolymers, the repeating units of the macromolecules do not have the same structure as the monomers. This is because small molecules such as water are separated from the monomer during incorporation into the polymer. Polymers are composed of different molecules that combine to form long chains. In other words, polymers are useful chemical substances made up of repeating units.

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In an equilibrium reaction, the forward and reverse reactions are proceeding at the same rate. option (d) is correct.

A Chemical equilibrium in a system is defined as a system in which the concentration of reactant and the concentration of  products do not change with time, also the system does not display kind of change in its properties.

When the rate of forward and backward reaction is same, the system is said to have reached a dynamic equilibrium. Here, the concentrations of reactants and products become equal.

There are two types of equilibrium: homogenous equilibrium, heterogeneous equilibrium.

In homogeneous equilibrium the reactants and products are in the same phase. Whereas, in heterogeneous equilibrium the reactants and products are in different phases.

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Answer:

The statement is not correct.

Explanation:

If two objects have the same mass, their respective densities determine their volumes. By definition, density = mass/volume or volume = mass/density. Therefore if two objects have the same mass, the mode dense object (with higher density) will occupy less volume than the other object.

Answer:

As we know that

At STP

1 mole of any gas occupies 22.4L  

so

15.7L / 22.4L/mole = 0.7moles Cl2  

0.7moles x 6.022x10^23molecules/mole = 4.22x10^23molecules

hope it helps

Answer:

1.3 atm

Explanation:

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P1 x V1) / (T1) = (P2 x V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature of the gas.

We are given:

P1 is what we want to find

V1 = 839 mL

T1 = 45 degrees Celsius = 318 K

V2 = 1032 mL

T2 = 58 degrees Celsius = 331 K

P2 = 1.9 atm

Plugging these values into the formula, we get:

(P1 x 839 mL) / (318 K) = (1.9 atm x 1032 mL) / (331 K)

Simplifying and solving for P1, we get:

P1 = (1.9 atm x 1032 mL x 318 K) / (839 mL x 331 K)

P1 = 1.3 atm (rounded to one decimal place)

Therefore, the original pressure of the oxygen sample was 1.3 atm.

Answer:

Earthwares

porcelain

bricks

If 5/8 of a number is 80, we can start by setting up the equation:

5/8 x N = 80

where N is the number we are trying to find.

To solve for N, we can isolate it by multiplying both sides of the equation by 8/5:

N = 80 x 8/5

N = 128

Therefore, the number is 128.

To find 1/4 of the number, we can simply multiply the number by 1/4:

1/4 x 128 = 32

So, 1/4 of the number is 32.

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Answer:

0.3 J

Explanation:

The equation for heat capacity is Q = mcΔT where Q is the heat, m is the mass of the substance, c is the specific heat capacity of the substance and delta T is the change in temperature. Plugging those values into the equation, we have Q = (.500)(0.24)(27.5-25) = 0.3

5

 mL acetic acid

95

mL water

Explanation:

Since

5

%

of the vinegar, by volume, is acetic acid, and we have

100

mL of vinegar, we have

5

mL of vinegar.

Similarly, we have

100

%

−

5

%

=

95

%

being water, so we have

95

mL of water.

The increase in greenhouse gases in the given period is: carbon dioxide (\(CO_{2}\)) showing the highest increase of 37.11%. Methane shows an increase of 156.57%. Nitrous oxide, on the other hand, shows a comparatively lower increase of 18.70%.

These increases in greenhouse gases are primarily due to human activities such as burning of fossil fuels, deforestation, and agricultural practices. The increase in \(CO_{2}\) is particularly concerning as it is the most abundant greenhouse gas and has a longer atmospheric lifetime compared to other greenhouse gases.
The rise in greenhouse gases has contributed to global warming and climate change, leading to several environmental impacts such as rising sea levels, more frequent heat waves and extreme weather events. It is crucial that we take immediate action to reduce greenhouse gas emissions and limit global warming to below 2 degrees Celsius to avoid catastrophic consequences for our planet and future generations.Based on the data provided and the hint given, we can calculate the percentage increase in greenhouse gases between the pre-industrial era and 2008 as follows:
a) Carbon Dioxide (\(CO_{2}\)): The formula given is (383.9-280)/280 x 100. By plugging in the values, we get (103.9/280) x 100 = 37.11%. Thus, there has been a 37.11% increase in \(CO_{2}\) levels from the pre-industrial era to 2008. b) Methane: Unfortunately, there is no data provided for methane levels in the pre-industrial era and 2008. Assuming the percentage increase is 156.57%, this suggests that methane levels have significantly increased compared to the pre-industrial era. c) Nitrous Oxide: Similarly, no data is provided for nitrous oxide levels. However, with the percentage increase of 18.70%, it indicates a moderate increase in nitrous oxide levels since the pre-industrial era.

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The volumetric gas feed rate to the reactor at a temperature of 600C and a reactor pressure of 100 atm is 202.52 ft³/h.

According to the stoichiometry of the given reaction,

     N₂ + 3H₂ → 2NH₃

2 moles of ammonia are produced from one mole of nitrogen.

Given that the reactor produces 1000 1bmol/h of ammonia.

So, moles of nitrogen getting converted to the product = 1000/2 =500

Which is just 25 percent of the number of moles of  N₂ fed into the reactor.

Thus, moles of nitrogen feed to the reactor per hour = x

25/100 x = 500

           x =2000

Thus, 2000 moles of nitrogen are fed per hour to the reactor.

Moles of hydrogen added per hour to the reactor = 3 x 2000 = 6000 mol

Thus, the total number of moles of gases fed into the reactor per hour = (2000+6000) = 8000 mol per hour

Thus, the volumetric flow rate of the gas into the reactor can be calculated by using the ideal gas equation as

PV = nRT

 V = nRT/P

 V = (8000 mol/h)(0.0821 Latm/molK)(600 + 273)K/100 atm

 V = 5733.864 L/h

1 m = 3.281 ft

Thus, 1m³= (3.281)³ At³ = 35.32 At³

Thus, 1 L = 35.32 x10⁻³ ft³

Thus, the volumetric flow rate in ft /h can be calculated as:

5733.864 L/h = 35.32 x 10⁻³ x 5733.864 ft³ /h

                      = 202.52 ft³/h

Your question is incomplete but most probably your full question was:

Nitrogen and Hydrogen are fed at a 1:3 molar ratio to an ammonia synthesis reactor operating at T = 600 C and P = 100 atm, where the following reaction takes place:

N2 + 3H2 -----> 2NH3

25% of the N2 fed is converted to ammonia and the reactor produces 1000 lbmol/hour of NH3. The reactor operates at steady state. Calculate the volumetric gas feed rate to the reactor(ft^3/hour), at the reactor temperature and pressure.

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Answer:

among us

Explanation:

red among us

tama

Answer:

-50

Explanation:

23.67-75=24-75 (to2sf)

              =-51

              =-50 ( to 2sf)

When the temperature conversion function =CONVERT(-22, "C", "F") is applied, a reading of -22 °C in Fahrenheit is displayed. On a variety of scales, including the Fahrenheit and Celsius systems, temperature is a unit that is used to denote hotness or coolness.

Heat energy will logically go from a hotter (body with a higher temperature) to a colder (body with a lower temperature) according to temperature (one at a lower temperature).

A temperature is a measurement used to express how hot or cold something is. It demonstrates how heat energy naturally flows from a hotter body to a cooler body and can be expressed in terms of any number of arbitrary scales (one at a lower temperature).

A match is burning at a far greater temperature than an iceberg, yet an iceberg has a significantly higher total heat energy than a match. Temperature is not the same as the energy of a thermodynamic system.

The temperature, along with pressure, density, and other similar properties, is referred to as an intense property as opposed to extensive characteristics like mass or volume—one that is independent of the quantity of stuff being addressed.

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The potential of a cell, e, is related to the standard electrode potential of the half-reactions involved in the cell reaction. pH, on the other hand, is a measure of the acidity or basicity of a solution and is related to the concentration of hydrogen ions in the solution.

In your experiment, the voltmeter measures the cell potential (E) as 0.87 V. To find the pH of the solution, you can use the Nernst equation:

E = E₀ - (RT/nF) * lnQ

Here, E₀ is the standard electrode potential, R is the gas constant, T is the temperature in Kelvin, n is the number of electrons involved, F is the Faraday constant, and Q is the reaction quotient.

However, to calculate the pH, you would need to know the specific half-cell reactions and values of E₀, as well as the temperature and concentrations of the species involved. Once you obtain these values, you can solve the Nernst equation and find the pH.

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Explanation:

We can assume that room temperature is 25 °C.

The melting point of a pure substance is the temperature at which it changes state from solid to liquid. The metling point of our substance is -187 °C. Since the room temperature is 25 °C we can say that it won't be solid. At least it will be liquid.

The boiling point of a pure substance is the temperature at which it changes state from liquid to gas. The boiling point of our substance is 42 °C. At room temperature we are under that temperature, so it won't convert into a gas. It will remain as a liquid also.

Since room temperature is between the boiling and melting point of our substance, the physical state is liquid.

Answer: liquid

The substance ammonia (NH3) is classified as an Arrhenius base, option A is correct.

Arrhenius defined a base as a substance that produces hydroxide ions (OH⁻) in water. When ammonia dissolves in water, it reacts with water molecules to form ammonium ions (NH₄⁺) and hydroxide ions (OH⁻), as shown in the equation

NH‌₃ ‌+‌ ‌H‌₂O →‌ ‌NH‌₄ ‌‌+ ‌OH‌⁻

This reaction is characteristic of Arrhenius bases, which are substances that increase the concentration of hydroxide ions in solution. When ammonia dissolves in water, it yields hydroxide ions (OH-) which are responsible for increasing the pH of the solution, making it basic, option A is correct.

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The complete question is:

Use the information to answer the following question.

Ammonia‌ ‌(NH‌₃)‌ ‌readily‌ ‌dissolves‌ ‌in‌ ‌water‌ ‌to‌ ‌yield‌ ‌a‌ ‌basic‌ ‌solution.

‌NH‌₃ ‌+‌ ‌H‌₂O →‌ ‌NH‌₄ ‌‌+ ‌OH‌⁻

How is this substance classified?

A. Arrhenius‌ ‌Base‌

B. Arrhenius‌ ‌Acid

C. Bronsted-Lowry‌ ‌Base‌

D. Bronsted-Lowry‌ ‌Acid‌

Answer: Put the list in chronological order (1–5). Allow the solid/liquid mixture to drain through the filter. Use water to rinse the filter paper containing the mixture. Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask. Weigh the dried filter paper and copper. Weigh and fold the filter paper

Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask.

Allow the solid/liquid mixture to drain through the filter.

Use water to rinse the filter paper containing the mixture.

Weigh and fold the filter paper.

Weigh the dried filter paper and copper.

In chemistry, a mixture is a combination of two or more substances in which each substance retains its own chemical identity. Mixtures can be classified into homogeneous and heterogeneous. Homogeneous mixtures have uniform composition throughout, while heterogeneous mixtures do not have a uniform composition and have visible boundaries between the components. Examples of mixtures include air, saltwater, and blood.

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Complete question:

Put the list in chronological order (1–5).

Allow the solid/liquid mixture to drain through the filter.

Use water to rinse the filter paper containing the mixture.

Place the filter paper in the funnel, then place the funnel in the Erlenmeyer flask.

Weigh the dried filter paper and copper.

Weigh and fold the filter paper.

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(i) The pH would decrease if bench \(HNO_{3}\) is neutralized.

(ii) The pH would increase if 25.0 cm3 of a given NaOH solution is diluted to 100.0 cm3.

(iii) The pH would remain constant if a solution of NaCl is concentrated.

HNO3 is a strong acid that dissociates completely in water to form H+ ions. When \(HNO_{3}\) is neutralized, it reacts with a base to form a salt and water. Since \(HNO_{3}\) is an acid, the addition of a base would reduce the concentration of H+ ions in the solution, resulting in a decrease in the overall acidity. As a result, the pH of the solution would increase.

NaOH is a strong base that dissociates completely in water to form OH- ions. When the NaOH solution is diluted, the concentration of OH- ions decreases while the volume of the solution increases. Since pH is a measure of the concentration of H+ ions in a solution, a decrease in the concentration of OH- ions would lead to an increase in the concentration of H+ ions, making the solution more acidic. Consequently, the pH of the solution would increase.

NaCl is a neutral salt that does not undergo hydrolysis in water, meaning it does not release or accept H+ or OH- ions. Concentrating the solution does not alter the nature of the ions present in the solution or their concentrations. Therefore, the concentration of H+ and OH- ions remains unchanged, resulting in a constant pH.

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Answer:

A: electrons

Explanation:

Answer:

200g or 40 teaspoons

Explanation:

An average human, weighing about 50 pounds, has about 200 g or 40 tps of NACl

The oxidation of co (carbon monoxide) to less-harmful co₂ (carbon dioxide) and the oxidation of hc (unburned hydrocarbons) to co₂ (carbon dioxide) and h₂o (water).

What is oxidation?

One or more electrons are lost during the chemical reaction of oxidation, which takes place inside of an atom or molecule.

TWO-WAY CATALYTIC CONVERTERS

This structure allows the chemical reaction to happen by directing exhaust fumes to travel through the substrate that is made of the precious metals platinum and palladium. As the conversion process proceeds, the temperature of the exhaust gases rises.

This process generates a great deal of heat, hence the exhaust gases that exit the converter should be hotter than the gases that enter it. This also explains why most units need to have heat shields.

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Answer:

metalloid

Explanation:

IUPAC names:

SF6: Sulfur hexafluoride

Hg2Cl2: Mercurous chloride

KHCO3:potassium hydrogen carbonate

HCl(g): Hydrogen chloride

C2O3: Oxalic anhydride

Cu(NO3)2: Copper(II) nitrate

Anhydrides are compounds consisting of a non-metallic element plus oxygen. The formula for anhydrides is of the type X2On (where X is a non-metallic element and O is oxygen). In these compounds, the oxygen also has an oxidation state of -2.

Oxalic anhydride or ethanedioic anhydride, also called oxiranedione, is a hypothetical organic compound

The student created a solution of lithium chloride with a molarity of 1.00 M by dissolving 95.0 grams of LiCl in 2.24 L of water.

The molarity of the solution can be calculated using the formula:

Molarity (M) = moles of solute / volume of solution in liters

To find the moles of solute, we need to convert the given mass of LiCl into moles using its molar mass. The molar mass of LiCl is 42.39 g/mol.

95.0 g LiCl x (1 mol LiCl / 42.39 g LiCl) = 2.24 mol LiCl

Now, we can substitute the values into the molarity formula:

Molarity = 2.24 mol LiCl / 2.24 L = 1.00 M

Therefore, the answer is (a) 1.00 M. The student created a solution of lithium chloride with a molarity of 1.00 M by dissolving 95.0 grams of LiCl in 2.24 L of water.

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Answer:

A=Ao(1/2)^t/h

A=(100)(1/2)^20/30

A=63g

Answer:

E i is like Math so I think this will help you