How many molecules are in Na2CrO4

Answer:

A

Explanation:

They help fight infection and other disease

Answer:

immunity is the answer for this question

Rough ER is connected to the nuclear membrane and is responsible for the synthesis and processing of proteins.

The rough endoplasmic reticulum (ER) is a network of membrane-bound sacs and tubules that is studded with ribosomes on its surface. These ribosomes are responsible for protein synthesis. The rough ER is connected to the nuclear membrane because it receives instructions for protein synthesis from the DNA in the nucleus. This connection allows for the efficient transfer of genetic information from the nucleus to the rough ER.

Once the ribosomes on the rough ER synthesize proteins, the rough ER is also involved in the processing and modification of these proteins. It helps in folding the newly synthesized proteins into their functional three-dimensional shapes and also adds various modifications such as glycosylation (the addition of sugar molecules) or signal sequences that target the proteins to specific locations within or outside the cell.

After processing, the proteins may be transported to other parts of the cell or exported to the cell membrane or extracellular space. The connection between the rough ER and the nuclear membrane ensures a coordinated flow of genetic information and protein synthesis, allowing the cell to efficiently carry out its functions.

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Answer:

hydrophobic: tending to repel or fail to mix with water.

hydrophylic​: having a tendency to mix with, dissolve in, or be wetted by water.

Hope it helps!!!

To check the protein in the drink the test carried out is Biuret Test

What is Biuret Test?

The chemical test known as the "Biuret test" uses the Biuret reagents to produce the compound known as "Biuret," which is created by heating urea to 180 °C. A 1% solution of Copper II sulphate is used in the test  

(\(CuSO_{4}\)). The peptide bonds found in proteins create a compound with the \(Cu^{2+}\) in the Biuret reagent. This test therefore aids in identifying peptide bonds in any substance.

The reagent in the biuret test does not really include biuret; however, the test's name derives from the fact that the peptide-like linkages in the biuret molecule produced a favorable reaction.

Two of the many more sophisticated variations of the biuret test are the Lowry test and the BCA test.

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Answer/Explanation:

In June 1998 in Japan a scientist discovered that neutrinos (which is a type of particle) has weight, mass. This was later proven with some very convincing strong evidence.

~ LadyBrain

The solubility of the solute in the solvent depends on intermolecular interactions.

The nature of the solute and the solvent alone determines how soluble they are in a solvent. In a polar solvent, a polar solute dissolves. In a non-polar solvent, a polar solute is poorly soluble. In a non-polar solvent, a non-polar solute dissolves.

Since the question is incomplete, we can not see what the solute or the solvent ought to have been. However, we must know that the solubility of the solute in the solvent must depend on intermolecular interactions between the both.

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Answer:

0.1443194637888042 moles

Explanation:

Hope This Helps

Have A Great Day

~Zero~

Answer:

Light i think

Explanation:

light is a source of energy also

Answer:

s=d/t

s=speed

d=distance traveled

t=time elapsed

Answer:

49.8cm

Explanation:

hope it helps i even double checked for you :D

The properties of a natural resource that make it useful for humans as a material or energy source is the ability to convert mass into energy and vice versa.

The expression natural resources make reference to all types of matter and energy extracted from nature that can be used to produce goods and services.

Some examples of natural resources include for example irreversible resources such as fossil fuels (i.e., oil, or coal, gas, minerals such as metals, rocks, etc) as well as those based on the use of reversible energy such as eolic air energy, solar radiation or sunlight, soil and hydric resources or water.

Therefore, with this data, we can see that natural resources can be defined as any material and or energy obtained from nature that may be irreversible or reversibly used to produce goods and services.

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The concentration of CO2 in club soda is approximately 1.1964 g/L.

To find the concentration of CO2 in club soda, we need to use the stoichiometry of the reaction and the volume and concentration of the NaOH solution used.

The balanced equation for the reaction is:

CO2(aq) + 2NaOH(aq) → Na2CO3(aq)

From the stoichiometry of the equation, we can see that 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated using the volume and concentration of NaOH solution used.

Given that 32.14 mL of 0.04202 M NaOH solution was used, we can calculate the moles of NaOH:

moles of NaOH = volume (L) × concentration (M)

moles of NaOH = 32.14 mL × 0.04202 mol/L

moles of NaOH = 0.001351 mol

According to the stoichiometry of the equation, 1 mole of CO2 reacts with 2 moles of NaOH. Therefore, the moles of CO2 can be calculated as:

moles of CO2 = (moles of NaOH) / 2

moles of CO2 = 0.001351 mol / 2

moles of CO2 = 0.0006755 mol

Now, we need to convert the moles of CO2 to grams. The molar mass of CO2 is approximately 44.01 g/mol.

mass of CO2 = moles of CO2 × molar mass of CO2

mass of CO2 = 0.0006755 mol × 44.01 g/mol

mass of CO2 = 0.02979 g

Finally, we need to express the concentration of CO2 in club soda in g/L. We are given that the sample of club soda used is 25.00 mL.

concentration of CO2 = (mass of CO2) / (volume of club soda in L)

concentration of CO2 = 0.02979 g / (25.00 mL × 0.001 L/mL)

concentration of CO2 = 1.1964 g/L

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Answer:

solid

PLz give brain i need it to rank up

Explanation:

When a strong acid or base is added to water, the pH will change dramatically.

A strong acid is one that is completely dissociated or ionized in an aqueous solution. This means it gives off the greatest number of hydrogen ions or protons when placed in a solution. Examples of strong acid are HCl, HBr, H2SO4, HNO4. These acids when placed in water, produces greatest amount of hydrogen ions. The pH value changes drastically. Any that has very high concentration of hydrogen and ion is acidic.

Also when base is added to water, the pH of water will increase above 7 and become basic. The pH of water is 7, but when base is added to it increases above 7.

Base is any solution that is slippery to touch in water solution, changes color, react with acid to form salt and change red litmus paper to blue.

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To determine the original pressure of a 750 ml sample of helium (He) at 0 degrees Celsius, we can use the combined gas law, which relates the initial and final conditions of a gas sample. The combined gas law equation is:

(P1 × V1) / (T1) = (P2 × V2) / (T2)

Where:

P1 and P2 are the initial and final pressures, respectively.

V1 and V2 are the initial and final volumes, respectively.

T1 and T2 are the initial and final temperatures, respectively.

Let's assign the given values:

P1 = unknown (original pressure)

V1 = 750 ml (initial volume)

T1 = 0 degrees Celsius (initial temperature)

P2 = 2 atm (final pressure)

V2 = 500 ml (final volume)

T2 = 25 degrees Celsius (final temperature)

Before using the combined gas law equation, we need to convert the temperatures to Kelvin scale by adding 273.15 to both T1 and T2:

T1 = 0 + 273.15 = 273.15 K

T2 = 25 + 273.15 = 298.15 K

Now we can plug in the values into the combined gas law equation:

(P1 × 750 ml) / (273.15 K) = (2 atm × 500 ml) / (298.15 K)

To solve for P1, we can cross multiply and rearrange the equation:

P1 = (2 atm × 500 ml × 273.15 K) / (750 ml × 298.15 K)

P1 = 0.924 atm

Therefore, the original pressure of the 750 ml sample of helium at 0 degrees Celsius is approximately 0.924 atm.

Answer:

115.6 kJ/mol

Explanation:

The ΔG of a reaction can be calculated using the following equation:

ΔG = ΔG° + RT ln(Q)

where:

ΔG° is the standard free energy change, which is given as 137.0 kJ/mol in this case

R is the gas constant, which is 8.314 J/(mol·K)

T is the temperature in Kelvin, which is 25°C + 273.15 = 298.15 K

Q is the reaction quotient, which is the ratio of the concentrations of the products to the concentrations of the reactants, each raised to their stoichiometric coefficients.

From the chemical equation given, the stoichiometric coefficients of Mg2+ and PO43- are 3 and 2 respectively. Therefore, the reaction quotient can be expressed as:

Q = [Mg2+]^3 [PO43-]^2

Substituting the given initial concentrations of Mg2+ and PO43- into the reaction quotient expression, we get:

Q = (0.65 M)^3 (0.43 M)^2 = 0.011 M^5

Now we can calculate the ΔG of the reaction:

ΔG = ΔG° + RT ln(Q)

ΔG = (137.0 kJ/mol) + (8.314 J/(mol·K) × 298.15 K) × ln(0.011 M^5)

ΔG = 137.0 kJ/mol - 21.38 kJ/mol

ΔG = 115.6 kJ/mol

Therefore, the ΔG for the reaction at 25°C and the given initial concentrations of Mg2+ and PO43- is 115.6 kJ/mol.

Answer:

C) 4Fe + 3O2 → 2Fe2O3

Explanation:

For this question, first you would go through all the options and make sure that there is an equal amount of elements on each side.

For the first option: 2Fe +02 → 2Fe2O3

You have only 2Fe atoms and 2O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is not balanced.

For option b: 3Fe +302 → 3Fe2O3

You have 3Fe and 6O atoms on your reactant side while on your product side you have 6Fe and 6O atoms. This is not balanced.

For option c: 4Fe +302 → 2Fe2O3

You have 4Fe and 6O atoms on your reactant side and 4Fe and 6O atoms on your product side. This is balanced!

For option d: Fe +0₂ → Fe₂O3

You have 1Fe and 2O atoms on your reactant side and 2Fe and 3O atoms on your product side. This is not balanced.

***Remember to multiply the subscript of an element by their coefficient (number in front of molecule) if there is any.

Answer:

pH = 12.90

Explanation:

The TSP is in equilibrium with water as follows:

Na₃PO₄(aq) + H₂O(l) ⇄ Na₂HPO₄⁻Na⁺(aq) + OH⁻(aq)

Where Kb = 0.0208 is defined as:

Kb = 0.0208 = [Na₂HPO₄⁻Na⁺] [OH⁻] / [Na₃PO₄]

As both Na₂HPO₄⁻Na⁺ OH⁻ comes from the same equilibrium:

[Na₂HPO₄⁻Na⁺] = [OH⁻] = X

[Na₃PO₄] is -molar mass: 163.94g/mol:

50.0g * (1mol / 163.94g) =0.305moles / 1L =

0.305M

Replacing:

0.0208 = [X] [X] / [0.305M]

6.344x10⁻³ = X²

0.0796M = X = [OH⁻]

As pOH = -log [OH⁻]

pOH = 1.099

pH = 14 - pOH

Answer:

640 g

Explanation:

Step 1: Given and required data

Step 2: Calculate the moles of oxygen gas

We will use the ideal gas equation

P × V = n × R × T

n = P × V / R × T

n = 25 atm × 20 L / (0.082 atm.L/mol.K) × 300 K = 20 mol

Step 3: Calculate the mass corresponding to 20 moles of oxygen

The molar mass of oxygen is 32.00 g/mol.

20 mol × 32.00 g/mol = 640 g

If a strong base is added to a buffer the pH will change only slightly. In the non-buffered solution changing the pH significantly.

If a strong base is added to a buffer, the weak acid will give up its H+ in order to transform the base (OH-) into water (H2O) and the conjugate base: HA + OH- → A- + H2O. Since the added OH- is consumed by this reaction, the pH will change only slightly.

In the non-buffered solution, the added hydronium or hydroxide ions have nothing to react with so the concentrations increase rapidly, changing the pH significantly.  If a base is added to an acidic solution, the solution becomes less acidic and moves toward the middle of the pH scale.

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Explanations

Given the following

Mass of potassium carbonate = 22.5grams

Determine the moles of potassium carbonate

Moles of potassium carbonate = mass/molar mass

22.5/138.205|

= 0.1628moles

Since the precipitate formed is aluminum hydroxide, hence the mole of precipitate formed if 3moles off K2CO3 produce 2moles of Al(OH)3 is given as:

Hence the moles of dried precipitate should be formed

Answer:

methane

Explanation: methane is obtained from the decaying of flora and fauna mostlyunder damp

Answer:

122 forenhieght

Explanation:

(50°C × 9/5) + 32 = 122°F

Explanation:

Arsenic is a solid chemical element that is used especially in wood preservatives, alloys, and semiconductors and is extremely toxic in both pure and combined forms.

A poisonous trioxide As2O3 or As4O6 of arsenic is used especially as an insecticide or weed killer.

Cu + O2 --->  CuO2 -The first reaction is a combustion reaction

2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction

A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.

In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.

Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.

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The heat of formation, or enthalpy of formation, of a compound, can be found in a reference such as the appendix of a textbook or a thermochemistry table. The heat of the formation of Fe2O3(s) is -824 kJ/mol. It represents the heat change that occurs when one mole of Fe2O3 is formed from its elements under standard state conditions. So the answer is 824 kJ will be released.

The heat of formation, also known as enthalpy of formation, is the heat energy change that occurs when a substance is formed from its element under standard state conditions. It is usually expressed in kJ/mol.

When we are dealing with the combustion of a substance, this value is used to determine how much heat is released or absorbed in the process. In this case, the substance is iron and we need to form Fe2O3.

To find the amount of heat released, we can use the heat of formation value of Fe2O3, which is -824 kJ/mol.

Since the value is negative, this means that 824 kJ of heat is released when 1 mole of Fe is burned to form Fe2O3 under standard state conditions.

It is also important to note that these values are usually provided at a specific temperature, usually at 25 degrees Celsius, and standard pressure.

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The acid ionization steady of HCIO₂ (chlorous corrosive) can be spoken to by the taking after condition:

HCIO₂ + H₂O ⇌ H₃O⁺ + CIO₂⁻

The harmony steady expression for this response is:

Ka = [H₃O⁺][CIO₂⁻] / [HCIO₂]

The esteem of the acid ionization consistent (Ka) for HCIO₂ is roughly

1.1 x 10^-2 at 25°C.

It is critical to note that the esteem of Ka can change with temperature, and it is additionally subordinate on the dissolvable utilized.

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Answer: I think the answer is C)

Explanation: