How many moles of propylene (C3H6) are in 25.0
g
of the substance?

Answer:

Ph level 0-7 is a acid

ph level 7-14 is base

bases turn paper blue

acids dissolve metal

acids contain hydrogen ions

Explanation:

I dont know the last one all I know that they become neutral when acids and bases are mixed.

Air escape from a tire when tire valve is opened because the pressure from the weight of the car is forcing the already pressurized air out .

When air is filled in tires, it get into more compact area than the outer atmosphere, therefore particles in tire are close to each other and exert pressure continuously on tire walls to get out of it. Thus, material of the tire need to be pressure resistant as much possible.

After opening the tire valve, air starts leaving with huge sound as strain outside the tire is weaker than that inside the tire. Molecules strike with the same force on larger area and pressure starts diminishing.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: Air leaves a tire when the tire valve is opened because

A. the pressure outside the tire is lower than the pressure inside the tire.

B. the pressure outside the tire is greater than the pressure inside the tire.

C. the temperature is higher outside the tire than inside the tire.

D. there are more gas particles outside the tire than inside the tire.

Answer:

4.255 J/ K

Explanation:

Given data :

mass of Gallium = 16 gm

molar mass = 69.723 g/mol

hence no of moles = 16 / 69.723 = 0.23 moles --------- ( 1 )

Δh ( heat fusion ) = 5.59 KJ/mol

Temperature = 29.8°C = 302.8 k

Determine the entropy change of gallium

Δs ( entropy change ) =  heat fusion / temperature

 = ( 5.59 * 1000) J/mol / 302.8 = 18.46 J/k*mol

Hence entropy change of gallium

= Δs * no of Gallium moles

= 18.46 * 0.23 = 4.255 J/ k

I hope this is right haha

The total pressure in Container C is \(5_{P}\)/(\(2_{V}\)). If the initial pressure in Container A was doubled and Container B was reduced by one-half.

To solve this problem, we need to use combined gas law, which relates with pressure, volume, and temperature of a gas;

(P₁V₁)/T₁ = (P₂V₂)/T₂

where P₁ and V₁ are initial pressure and volume, respectively, and T₁ is initial temperature. Similarly, P₂, V₂, and T₂ are inal pressure, volume, and temperature, respectively.

Let's assume that the volume and temperature are constant in all three containers. Therefore, we can simplify the equation to;

P₁/P₂ = V₁/V₂

We can use this equation to solve for the final pressure in Container C.

First, let's calculate the new pressures in Containers A and B;

Container A; the initial pressure was doubled, so P₁ = \(2_{P}\) and V₁ = V (since the volume is constant). Therefore, P₂ = P₁/(V₁/V₂) = \(2_{P}\)/(1/2) = \(4_{P}\).

Container B; the initial pressure was reduced by one-half, so P₁ = P/2 and V₁ = V (since the volume is constant). Therefore, P₂ = P₁/(V₁/V₂) = (P/2)/(1/2) = P.

Now that we have the new pressures in Containers A and B, we can use them to find the total pressure in Container C:

Container C; we are mixing equal volumes of gases from Containers A and B, so the total volume is \(2_{V}\). The total pressure is the sum of the partial pressures of the gases in Containers A and B, which are \(4_{P}\) and P, respectively. Therefore, the total pressure in Container C is:

\(P_{total}\) = (\(4_{P}\) + P)/(\(2_{V}\))

= \(5_{P}\)/(\(2_{V}\))

So, the final pressure in Container C is \(5_{P}\)/(\(2_{V}\)).

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Answer: ThankYou So much your name is Jacob!

Explanation: Hello

Answer: Thanks for the Free Points Brother!

Explanation: Yay! :D

Answer:

6

Explanation:

As , 2H2 + O2 = 2H2O

with 6 H2, 4O2 is excess.

H2O molecules formed = 6

Answer:

1.75 moles

Explanation:

According to CaC₂(s) + 2 H₂O(l) --> C₂H₂(g) + Ca(OH)₂(aq)

2 moles of H20 will produce 1 mole of Ca(OH)2

therefore 3.5 moles of H2O will produce 3.5 x (1/2) = 1.75 moles of Ca(OH)2

Answer:

mass is an extensive property..

Thickness of the fail in millimeter is 0.051mm

Thickness is the quality or state of being thick

Here given data is

aluminum(Al) =  24cm by 31cm

Mass =10.35g

Density = 2.70gcm³

We have to find the thickness of the fail in millimeter = ?

So the formula is

thickness = Volume/surface area

So first we have to calculate volume

Volume = mass/density

Volume = 10.35g/ 2.70gcm³

Volume = 3.83

Then the area of foil is

Area = 24cm×31cm

Area = 744cm²

Thickness = volume/area

Thickness = 3.83/744cm²

Thickness = 0.0051cm = 0.051mm

Thickness of the fail in millimeter is 0.051mm

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Answer:

Explanation:

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₅(g) --------> PCl₃(g)+ Cl₂(g)

1 mole               1 mole      1 mole

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₃(g) and  Cl₂(g) formed are .10 M and .10 M

Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]

= .10 M x .10 M / .65 M

= .0154

B ) is the correct choice .

Answer:

When implementing green roofs, several factors should be considered, including the building's structural capacity to support the additional weight of the green roof, the local climate and weather patterns, the type of vegetation to be used, and the maintenance requirements. It is also important to consider the potential benefits, such as improved energy efficiency, stormwater management, and biodiversity, as well as any potential drawbacks, such as increased installation and maintenance costs.

Answer: When implementing green roofs, several factors should be considered, including the type of vegetation to be used, the weight-bearing capacity of the roof, the drainage system, and the maintenance requirements. The type of vegetation chosen should be appropriate for the local climate and able to withstand the harsh conditions of a rooftop environment. The weight of the green roof must also be taken into account to ensure that the roof can support it. A proper drainage system is essential to prevent water damage and leaks. Finally, regular maintenance is necessary to ensure the longevity and effectiveness of the green roof.

Answer:

2.69 * 10^-6 Mol/L

Explanation:

The equation of the reaction is;

Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH

To convert from ppm concentration to Mol/L, we have

M = ppm/MM * 1000

Where;

M = mol/l

MM= Molar mass

M = 1/142.97 g/mol * 1000 =

M= 6.99 * 10^-6 Mol/L

For first order reaction;

ln[A] = ln[A]o -kt

Given that

[A]o = 6.99 * 10^-6 Mol/L

[A]=??

k= 2.7 x 10-4/sec

t= 30 mins * 60 = 1800 s

ln[A] = ln[6.99 * 10^-6] -   (2.7 x 10-4 * 1800)

ln[A] = -11.87 - 0.486

ln[A] = -12.356

[A] = e^(-12.356)

[A] = 4.3 * 10^-6 Mol/L

Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L

The substance with the lowest vapor pressure at a given temperature is vapor pressure is Cal2

Vapor pressure is the pressure exerted by the vapor of that liquid at equilibrium. The liquid which has lowest intermolecular forces that has higher vapor pressure .So to answer this question we need to determine the liquid with lowest intermolecular forces. In the given molecules CaI2 is ionic and so its intermolecular force will be highest in all. Rest of all are covalent in nature. Covalent molecule has less intermolecular forces than ionic.

Vapor pressure, or equilibrium vapor pressure, is defined as the pressure exerted by a vapor in thermodynamic equilibrium with the condensed phase at a given temperature in a closed system. Equilibrium vapor pressure is a measure of the evaporation rate of a liquid.

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Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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The chemical equation for the decomposition of water is:

\(2 H_2O -- > 2 H_2 + O_2\)

To balance this equation, we need to count the number of atoms of each element on both sides of the equation.

On the left side of the equation, we have:

2 hydrogen atoms (2 H₂O)

2 oxygen atoms (2 H₂O)

On the right side of the equation, we have:

2 hydrogen atoms (2 H₂)

2 oxygen atoms (1 O₂)

We can see that the number of hydrogen atoms is already balanced, but the number of oxygen atoms is not. To balance the equation, we need to add a coefficient in front of O2 so that we have the same number of oxygen atoms on both sides.

The balanced equation is:

\(2 H_2O -- > 2 H_2 + 1 O_2\)

A compound is broken down into simpler compounds during a decomposition reaction. Different techniques, such as heating, exposure to light, or the inclusion of a catalyst, can be used to produce this reaction.

The reactant component splits into two or more products, which may be elements or compounds, during decomposition. A synthesis reaction, in which less complex substances join to create a more complex compound, is the antithesis of this reaction.

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\(K_{sp}\) of the compound is found to be  5.04 ×\(10^{-10}\).

Solubility :Solubility can be define as the amount of a substance that dissolves or mixes in a given amount of solvent at specific conditions.

Solubility equilibrium

Ksp = \([A^{+} ]^{a}\) \([B^{-} ]^{b}\)

Ksp = solubility product constant

A+ = cation in an aquious solution

B- = anion in an aqueous solution

a, b = relative concentrations of a and b

Given,

Solubility = s = 3.60 × \(10^{-2}\) g/L

molar mass = 288 g/ mol

∴ s= 3.60 × \(10^{-2}\) g/L ÷ 288 g/ mol = 1.25 ×\(10^{-4}\) mol/ L

Reaction:

MX3 ⇄ M + 3X

           s       3s

\(K_{sp}\) =[ \(M^{+3}\)] [ \(X^{-1}\)\(]^{3}\) = solubility product

∴ \(K_{sp}\) =\([s]^{} [3s]^{3}\)

∴ \(K_{sp}\) = 3 \(s^{4}\)

∴ \(K_{sp}\) = 3 × (3.60 × \(10^{-2}\) \()^{4}\)

∴ \(K_{sp}\) = 503.8848 ×\(10^{-8}\)  = 5.04 ×\(10^{-10}\)

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Answer:

Chemical equations show the ending outcome, while Chemical formulas only show how you lead up to it.

Explanation:

The new volume of the gas will be 1.85L.

According to Boyle's Law, as pressure lowers, gas volume grows. According to Charles' Law, when the temperature rises, the volume of the gas also rises. Avogadro's Law also states that as the amount of gas increases, so does the volume of the gas.

Given, initial volume of gas V1 = 2L

initial temp T1 = 273K

initial pressure P1 = 101.3 kPa

final temperature, T2 = 500K

Final pressure, P2 = 200 kPa

let final or new volume be V,

now for a constant moles of gas,

by using ideal gas equation,

P1×V1/T1 = P2×V/T2

101.3×2/273 = 200×V/500

202.6/273 = 2V/5

V = 0.742×5/2

V = 1.85 L

The new volume of the gas will be 1.85L.

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Answer:

it is A

Explanation:

Its on edge

Christians call Jesus "the Christ” because of the meaning behind the word. The term “Christ” comes from the Greek word “Christos” which means “the anointed one” or “the messiah”.

This title was given to Jesus because of the many prophecies in the Old Testament that foretold of a coming messiah who would save the people of Israel from their enemies and bring peace and justice to the world.

The term “Christ” is also associated with the Latin word “Nazareth”, which is the town where Jesus was born. This further reinforces the idea of Jesus as the messiah, as it was prophesied that the messiah would be born in Bethlehem, which is a town near Nazareth.

Finally, the term “Christ” is also associated with the Latin word “resurrection”. This is because Jesus was believed to have been resurrected from the dead, which was seen as proof of his divine power and the fulfillment of the prophecies about the messiah. This further emphasizes the idea of Jesus as the messiah and savior of the world.

In conclusion, Christians call Jesus “the Christ” because of the meaning behind the word and because of the many prophecies in the Old Testament that foretold of a coming messiah who would save the people of Israel from their enemies and bring peace and justice to the world. The term is also associated with the Latin words “Nazareth” and “resurrection”, which further emphasize the idea of Jesus as the messiah and savior of the world.

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We can apply the concept of heat transmission to determine the water's final temperature. The heat acquired by the water offsets the heat lost by the metal.

Given: 200 g for the mass of water (m).

Water's initial temperature (T1) is 50 °C.

(Q) = 8400 J of heat is transferred from metal to water.

Water has a specific heat capacity (C) of 4.18 J/(g°C).

The following formula can be used to determine the heat transferred:

Q = m * C * ΔT

We may calculate the temperature change (T) by rearranging the equations as follows:

ΔT = Q / (m * C)

replacing the specified values:

T is equal to 8400 J / (200. g * 4.18 J/(g°C))

ΔT ≈ 10.048 °C

We multiply the original temperature by the temperature change to obtain the final temperature (T2):

T2 = T1 + T + 10.048 °C T2 = 50 °C + 10.048 °C

T2 ≈ 60.048 °C

As a result, the water's final temperature is around 60.048 °C.

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Why? Because high-pressure systems don't allow vapor to get high enough to "become clouds," therefore it will not rain. :)

~pinetree

They has been an occurrence of rainstorms in galetown.

This is simply when a downpour lasts for any length of time, it usually consists of short bursts of heavy rain interspersed with sporadic periods of lighter rain.

As the temperature rises, more ocean water evaporation occurs, releasing energy as well as water vapor into the atmosphere. The additional water vapor causes more rain and snow to fall. Intense downpours are likely to occur in areas that frequently rain. However, dry places are probably going to get even drier.

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When the combined vapour pressure of a miscible liquid mixture reaches atmospheric pressure, the solution boils. This vapour pressure denotes the boiling pressure in a mixture.

The air pressure directly impacts a liquid's boiling point. The weight of the air molecules above the liquid is the factor putting more pressure on the liquid. This is considered to as atmospheric pressure in an open system. The higher the boiling point and the more energy needed to bring liquids to a boil, the higher the pressure.

Because volatile compounds regularly have different boiling points, when a mixture is distilled, the components commonly separate from the mixture. The temperature at which the external pressure operating on the surface of a liquid equals the vapour pressure of the liquid phase of a compound is termed as the boiling point.

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Answer:The colour and distribution of the organism's biochromes

Explanation:

The colour and distribution of the organism's biochromes (pigments), particularly the relative location of differently coloured areas; the shape, posture, position, and movement of the organism; and the quality and quantity of light striking the organism

molar mass of empirical formula = (20 x 12.01 g/mol) + (24 x 1.01 g/mol) + (1 x 14.01 g/mol) = 324.44 g/mol ratio = 324.44 g/mol / 324 g/mol = 1.001. The molecular formula of quinine is C20H24N.

The active component of cinchona extracts, which have been used for this purpose since before 1633, is utilized as an antimalarial medication. Quinine has been utilized in conventional cold remedies for its use as a mild antipyretic and analgesic.

Plasmodium falciparum malaria is treated with quinine. Malaria is brought on by the parasite Plasmodium falciparum, which enters the body through the red blood cells. Quinine functions by either eliminating the parasite or halting its growth.

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125 grams of zinc was reacted, therefore, 125 grams of zinc will produce 42.6 liters of hydrogen gas at STP, and the problem involves stoichiometry, which is the calculation of reactants and products in a chemical reaction.

The balanced chemical equation for the reaction of zinc and hydrochloric acid is:

Zn + 2HCl → ZnCl₂ + H₂

From the equation,

125 g Zn x (1 mole Zn/65.38 g) = 1.91 moles Zn

So, one can expect 1.91 moles of hydrogen gas to be produced.

Now, at STP (standard temperature and pressure), the volume of one mole of gas is 22.4 liters. Therefore, the volume of hydrogen gas produced at STP can be calculated as:

1.91 moles H2 x 22.4 L/mole = 42.6 L H2

Therefore, 125 grams of zinc will produce 42.6 liters of hydrogen gas at STP.

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The word "symptom" refers to a specific manifestation or indication of a condition, disease, or disorder that is experienced or observed by an individual.

Symptoms are subjective or objective changes in the body's normal functioning that may be recognized as abnormal, uncomfortable, or problematic. Symptoms can manifest in various ways depending on the nature of the underlying condition. They can be physical, such as pain, rash, cough, fever, or fatigue, indicating an illness or injury affecting the body. Symptoms can also be psychological, such as anxiety, depression, or confusion, reflecting disturbances in mental health.

Symptoms serve as important clues for medical professionals to identify and diagnose diseases or disorders. They provide valuable information about the nature, severity, and progression of an illness, helping healthcare providers formulate appropriate treatment plans. Additionally, symptoms may also be important for individuals to self-assess their own health status and seek appropriate medical attention.

It is essential to note that symptoms alone may not provide a definitive diagnosis, as they can overlap across different conditions. Further evaluation, including medical tests and examinations, is often necessary to confirm a diagnosis and determine the appropriate course of action.

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There is no reason to run these solutes at the 20 MWCO because they are both much smaller than the MWCO of the membrane.

The MWCO (molecular weight cut off) is the molecular weight of a solute at which it will be retained by a membrane during a process such as ultrafiltration or dialysis. If a solute has a molecular weight higher than the MWCO of a membrane, it will be retained and not pass through the membrane. If the molecular weight of a solute is lower than the MWCO, it will pass through the membrane.

In this case, glucose has a molecular weight of 180 g/mol (6 carbons x 12 g/mol per carbon + 6 oxygens x 16 g/mol per oxygen) and albumin has a molecular weight of approximately 81,942 g/mol (607 amino acids x 135 g/mol per amino acid). Both of these solutes have molecular weights that are much lower than 20,000 g/mol, which is a typical MWCO for ultrafiltration or dialysis membranes.

They would both easily pass through the membrane and be lost during the process. Instead, a membrane with a much lower MWCO would be needed if we wanted to retain these solutes during a process such as ultrafiltration or dialysis.

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