How many more oxygen atoms represented in the formula for barium sulfate than in the formula for barium hydroxide

Answer:

90.71 KJ

Explanation:

From the reaction equation, lead is the cathode while copper was the anode.

Hence;

E°anode = +0.34V

E°cathode = -0.13 V

E°cell =E°cathode - E°anode

E°cell = -0.13 V - 0.34V

E°cell = -0.47 V

But;

ΔG° = -nFE°cell

n= number of electrons transferred = 2

F = Faraday's constant = 96500 C

E°cell = -0.47 V

ΔG° = -(2 * 96500 * (-0.47))

ΔG° = 90,710 J or 90.71 KJ

The standard Gibbs free energy for the reaction

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq) is 89.3 kJ/mol.

Let's consider the following redox reaction.

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq)

We can identify both half-reactions.

Reduction (Cathode): Pb²⁺(aq) + 2 e⁻ → Pb(s)    E°red = -0.126 V

Oxidation (Anode): Cu(s) → Cu²⁺(aq) + 2 e⁻       E°red = +0.337 V

We can calculate the standard potential of the cell (E°cell) using the following expression.

E°cell = E°red,cathode - E°red,anode = -0.126 V - 0.337 V = -0.463 V

The standard Gibbs free energy (ΔG°) is a way to measure the spontaneity of a reaction. We can calculate it using the following expression.

ΔG° = − n × F × E°cell =

ΔG° = − 2 mol × (96,485 J/V.mol) × (-0.463 V) × (1 kJ/1000 J) = 89.3 kJ/mol

where,

Since ΔG° > 0, the reaction is not spontaneous.

The standard Gibbs free energy for the reaction

Pb²⁺(aq) + Cu(s) → Pb(s) + Cu²⁺(aq) is 89.3 kJ/mol.

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Answer:

1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃

Explanation:

The given reaction is a double decomposition (metathesis) reaction. A reaction in which the products are formed by the exchange of the ions present in the two reactants. NaCL and AgNO₃ exchange ions to form AgCl, which precipitates and NaNO₃.

The balanced equation for reaction is given below;

NaCl(aq) + AgNO₃(aq) ----> AgCl(s) + NaNO₃(aq)

In the reaction above, the mole ratio of the reactants to products is 1 : 1 ---> 1 : 1

This means that 1 mole of NaCl reacts with 1 mole of AgNO₃ to produce 1 mole of AgCl and 1 mole of NaNO₃.

Given the molar mass of the compounds above;

NaCl = 58.5 g/mol; AgNO₃ = 170 g/mol; AgCl = 143.5 g/mol; NaNO₃ = 85 g/mol

Therefore, 58.5 g of NaCl reacts with 170 g of AgNO₃ to produce 143.5 g of AgCl and 85 g of NaNO₃

The volume (in milliliters) of the 2.00 M NaOH solution that can be produced from the reaction is 955 mL

First, we shall determine the mole of 44.00 grams of Na that reacted. Details below:

Mole = mass / molar mass

Mole of Na = 44 / 22.99

Mole of Na = 1.91 moles

Next, we shall determine the mole of NaOH obtained from the reaction. Details below:

2Na + 2H₂O -> 2NaOH+ H₂

From the balanced equation above,

2 moles of Na reacted to produced 2 moles of NaOH

Therefore,

1.91 moles of Na will also react to produce 1.91 moles of NaOH

Finally, we shall determine the volume of the 2.00 M NaOH produced. Details below:

Volume = mole / molarity

Volume of NaOH = 1.91 / 2

Volume of NaOH = 0.955 L

Multiply by 1000 to express in milliliter

Volume of NaOH = 0.955 × 1000

Volume of NaOH = 955 mL

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Answer:

See below.

Explanation:

Aqueous copper chloride reacts with sodium hydroxide aqueous solution to give a precipitate (solid) of copper hydroxide and aqueous sodium chloride.

Answer:

100,000 N

Explanation:

Force, F = mass, m × acceleration, a

⇒F = ma

m= 20, 000kg

a = 5m/s²

∴ F = 5 × 20,000 = 100,000N

Some of the things that might be included in a chemical reaction are: reactants, products, catalysts, energy, and reaction conditions.

A chemical reaction involves the breaking and forming of chemical bonds to create new substances. Some of the things that might be included in a chemical reaction are:

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To achieve the desired pH of 3.87, one would need to add 4.7 moles of HCl to the 1-liter buffer solution.

To calculate the amount of HCl that must be added to the buffer, we need to determine the change in concentration of acetic acid required to achieve the desired pH.

Volume of the buffer solution = 1 liter

Initial concentration of acetic acid ([HA]) = 1.3 M

Initial concentration of sodium acetate ([A-]) = 0.75 M

Desired pH = 3.87

pKa of acetic acid = 4.75

Using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

3.87 = 4.75 + log(0.75/[HA])

Rearranging the equation:

log(0.75/[HA]) = 3.87 - 4.75

log(0.75/[HA]) = -0.88

Taking the antilog of both sides:

0.75/[HA] = 10^(-0.88)

[HA] = 0.75 / 10^(-0.88)

[HA] = 0.75 / 0.125

[HA] = 6 M

To find the change in concentration of acetic acid:

Change in [HA] = Initial [HA] - Final [HA]

Change in [HA] = 1.3 M - 6 M

Change in [HA] = -4.7 M

Therefore, to achieve the desired pH of 3.87, you would need to add 4.7 moles of HCl to the 1-liter buffer solution.

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look at the clues by it and try not to trust the links they trying to give u...

but i kinda dont know myself  any periodic table i can look at?

Answer:

Law

Explanation:

A law is a summary of observed (measurable) behavior, whereas a theory is an explanation of behavior. A law tells what happens; a theory (model) is our attempt to explain why it happens.

The approximate normal boiling point of 2-chloroheptane can be determined using a vapor pressure nomograph. Given that the boiling point of 2-chloroheptane is 46 °C at 19 mmHg, we can use the nomograph to estimate the boiling point at normal atmospheric pressure.

1. The vapor pressure nomograph is a graphical representation that relates the boiling point and vapor pressure of a substance at different pressures. To estimate the normal boiling point, we need to determine the vapor pressure at standard atmospheric pressure (760 mmHg) using the given data.

2. On the vapor pressure nomograph, locate the point representing 19 mmHg on the y-axis and draw a horizontal line to intersect with the diagonal line representing the normal boiling point. From this intersection, draw a vertical line down to the x-axis to determine the temperature corresponding to 19 mmHg.

3. By estimating the intersection point, we find that the temperature is approximately 46 °C at 19 mmHg. Since the normal boiling point is defined as the boiling point at atmospheric pressure (760 mmHg), we can approximate the normal boiling point of 2-chloroheptane to be around 46 °C.

4. It's important to note that the accuracy of this approximation depends on the precision and reliability of the vapor pressure nomograph used.

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Answer:

Gas

Explanation:

Because Crude oil can usually be found in the ground as a liquid and in the air is gas can be kerosene.

Answer

they atract

Explanation:

Answer:

I think is B and C

Explanation:

There are two direct factors that affect solubility: temperature and pressure.Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.

Answer:

Explanation:

It is c and d promise took test.

The probability that a randomly selected x-value from the distribution is at least 80 is approximately 0.9938.

In a normal distribution with a mean of 98 and a standard deviation of 6, we can calculate the probability of a randomly selected x-value being at least 80.

To do this, we need to find the area under the normal curve to the right of 80. By standardizing the value using the z-score formula, we can convert 80 to a z-score of (80 - 98) / 6 = -3.

The area to the right of this z-score can be obtained from a standard normal distribution table or using statistical software, which is approximately 0.9938.

A normal distribution is a common probability distribution that has a symmetric bell-shaped curve. It is characterized by its mean and standard deviation.

In this case, the mean is 98, indicating the center of the distribution, and the standard deviation is 6, representing the spread of the data around the mean.

The probability calculation involved converting the x-value of interest (80) to a z-score, which measures the number of standard deviations an x-value is from the mean.

By finding the area under the curve to the right of the z-score, we determine the probability of selecting an x-value that is at least 80.

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The contribution of the self-ionization of water to [H3O+] and [OH-] concentrations is small and usually can be neglected when solving equilibrium problems involving weak acids and bases.

The self-ionization of water involves the reaction H2O + H2O ⇌ H3O+ + OH-. The equilibrium constant for this reaction, known as the ion product constant for water (Kw), is 1.0 x 10^-14 at 25°C. The concentration of water (55.5 M) is much larger than the concentrations of H3O+ and OH- in dilute solutions, so the contribution of the self-ionization of water to the overall concentration of H3O+ and OH- is usually negligible. This is particularly true in the case of weak acids and bases, which have much larger equilibrium constants than Kw. However, in very dilute solutions, or in solutions of strong acids and bases, the contribution of self-ionization of water may need to be considered.

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The compound that would form a precipitate in water is  BaSO4.

option d.

BaSO4 (barium sulfate) would form a precipitate in water because it is classified as an insoluble compound according to most solubility charts. When a compound is considered insoluble, it means that it has a very low solubility in water, resulting in the formation of solid particles or precipitate when dissolved in water.

In the case of BaSO4, it does not readily dissociate into ions in water and remains as solid particles, causing it to precipitate.

On the other hand, a. KCI (potassium chloride), b. NaOH (sodium hydroxide), and c. (NH4)2S (ammonium sulfide) are soluble compounds in water. They dissociate into ions and form homogenous solutions when dissolved in water, without forming a precipitate.

It's worth noting that solubility can vary depending on factors such as temperature and concentration, so it's always important to consult a solubility chart or reference for accurate and up-to-date information on specific compounds.option d.

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Determine the type of solid based on the description. Choose between metallic solid, network solid, molecular solid, ionic solid, and amorphous solid. a. This solid is ductile and electrically conductive. b. This solid has a low melting point and is not conductive.

See the explanation.

A represents a Metallic Solid.

Consider the physical properties of metals once more.

Metals are used in

As we can see, ductility and electrical conductivity are both metallic properties.

B is a chemical solid.

When atoms share electrons, molecules form. Because there are no free electrons in molecules, they do not conduct electricity.

Second, in the solid state, molecules are held together by weak dispersion forces, so molecular

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If your titration solution is 0.427 M in NaOH, and the endpoint occurs at 13.70 mL of titrant, the number of mmol of NaOH required to reach the endpoint is 5.830 mmol.

To calculate the number of mmol of NaOH required to reach the endpoint, we can use the following formula: mmol NaOH = M NaOH x V NaOH where, M NaOH = molarity of NaOH V NaOH = volume of NaOH used in the titration. By substituting the given values in the above formula, we get; mmol NaOH = 0.427 M x 13.70 mL= 5.830 mmol. Therefore, the number of mmol of NaOH required to reach the endpoint is 5.830 mmol.

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Answer:

24 hours

Explanation:

There are 24 hours in a day cause that is how long for the earth to spin on its axis

Answer:

24 hours

Explanation:

The time it takes Earth to rotate so the sun appears in the same position in the sky, known as a solar day, is 24 hours. However, the time it takes Earth to complete one full rotation on its axis with respect to distant stars is actually 23 hours 56 minutes 4.091 seconds, known as a sidereal day.

The molecular formula of the given compound is determined as            C0.98 H1.47 O0.98.

Only the atomic proportions of the various elements present in the molecule are indicated by the empirical formula. A compound's molecular formula is the chemical representation of the true chemical end up making of its constituent molecules. It expresses the exact number of atoms from distinct elements that comprise one compound molecule.

Molar mass of empirical compound => C2H3O2

                                                 => 59.04g

The compound of given molecular weight => 119g/mol

       => 59.04/119= 0.49

Therefore, the molecular formula of given compound = C2H3O2 x 0.49

                                                    => C0.98 H1.47 O0.98

The primary difference between molar mass and formula mass is that molar mass corresponds to the mass in gram of one mole of substance, however formula mass corresponds to the sum of the atomic weights of all the atoms in a compound's empirical formula.

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\(\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}\)

Actually Welcome to the Concept of the Ionic bonds.

Since Sodium (Na) is a cation and Chlorine (Cl) is a Anion, they both form a Ionic bond called as NaCl (common salt)

So answer is, Na and Cl

Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution

Explanation:

Given: \(M_{1}\) = 2.0 M,      \(V_{1}\) = ?

\(M_{2}\) = 0.5 M,       \(V_{2}\) = 500 mL

Formula used to calculate the volume is as follows.

\(M_{1}V_{1} = M_{2}V_{2}\)

Substitute the values into above formula as follows.

\(M_{1}V_{1} = M_{2}V_{2}\\2.0 M \times V_{1} = 0.5 M \times 500 mL\\V_{1} = 125 mL\)

Thus, we can conclude that there is 125 mL of a 2.0 M \(CuCl_{2}\) solution are needed to make 500 mL of a 0.5 M solution.

Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

Answer:

The answer is option A..

(a). PbS(s) + 3O2(g) → PbO(s) + 2SO2(g) & PbO(s) + PbS(s) → 2Pb(l) + SO2(g), (b). 2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g) , (c). 2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g).

(a) The two steps involved in the preparation of lead from galena are: Step 1: Roasting of galena to form lead(II) oxide and sulfur dioxide.\(PbS(s) + 3O2(g)\) → \(PbO(s) + 2SO2(g)\) . Step 2: Reduction of lead(II) oxide with galena to form lead metal and sulfur dioxide. \(PbO(s) + PbS(s)\) → \(2Pb(l) + SO2(g)\) . (b) The overall balanced equation for the process is obtained by combining the above two equations: \(2PbS(s) + 3O2(g)\)→ \(2Pb(l) + 2SO2(g)\) . (c) For every metric ton of lead obtained, 0.309 metric tons of sulfur dioxide is formed according to the balanced equation in part (b).

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The relative quantity of the water holds a small number of ions. ions dissolved in the water in. The correct option to this question is C.

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Answer:

chemical energy

Explanation:

A battery stores energy in the form of chemical energy. Chemical energy is stored in the bond of atoms and molecules. These bonds break and convert to other forms of energy. In the given case, the chemical energy is converted to electric energy which powers the flashlight. Thus, flashlight receives energy input in the form of chemical energy.

Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.

Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)

The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).

HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1

= 1.0x10⁻⁷,

Ka2 = 1.0x10⁻¹⁹

To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.

It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.

To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0Change -x +x +x

Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹

= x² / (6.89x10⁻² - x)

Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)

Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]

x = 2.31x10⁻¹¹ M

Thus, [S²⁻] = 2.31x10⁻¹¹ M

To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0

Change -x +x +x

Equilibrium (6.89x10⁻² - x) x x

Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷

= x(6.89x10⁻² - x) / (6.89x10⁻²)

Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)

Thus: x = 1.66x10⁻⁸ M[H₃O⁺]

= 1.66x10⁻⁸ M

Then, pH = -log[H₃O⁺]

= -log(1.66x10⁻⁸)

= 7.78 (rounded to two decimal places)

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Answer:

22.75 L CO2

Explanation:

Balance the Equation

C5H12  +  O2 ==>   CO2 + H2O        Balance the Carbons

C5H12  +  O2 ==>   5CO2 + H2O     Now balance the Hydrogens

C5H12  +  O2 ==>   5CO2 + 6H2O   Now count up the oxygens on the right.

5*O2 + 6O ==> 10 O + 6 O ===> 16 Oxygens.

You have 2 on the left. You have to multiply the oxygens by 8

C5H12  +  8O2 ==>   5CO2 + 6 H2O

The equation is now balanced.

Now find out how much oxygen is needed to burn 9.32 L of Pentane

1 Liter Pentane / 8 Liters Oxygen = 9.32 L Pentane / x     Cross multiply

x = 8 * 9.32

x = 74.56

Read this next sentence very carefully. You need 74.56 Liters of oxygen to burn all the pentane you have. There's not that much there. You only have 36.4 Liters of Oxygen. Some of the pentane won't get burned. Consequently there will be a shortage of CO2 as well.

Find out the number of Liters of Pentane that will be burned up.

1 / x =  8 / 36.4               Cross multiply

8x = 36.4                        Divide by 8

8x/8 = 36.4/8

x = 4.55 Liters of Pentane will be  used up.

Find the number of Liters of CO2

For every Liter of Pentane, 5 Liters of CO2 will be produced.

1/5 = 4.55/x                      Cross Multiply

x = 5 * 4.55

x = 22.75