The resize function should be called once if the initial size of the vector is greater than the number of items to be inserted, and additional space is needed for a few more elements.
It depends on the initial size of the vector and the number of items to be inserted. If the vector's initial size is less than or equal to the number of items to be inserted, then the resize function need not be called at all. If the initial size is greater than the number of items to be inserted, then the resize function can be called once to allocate space for a few more elements.
In general, the resize function should be called as few times as possible to minimize the number of memory allocations and improve performance. Ideally, the initial size of the vector should be chosen to be large enough to accommodate the expected number of elements to be inserted, but not so large as to waste memory.
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Solve.
4x - 8x = 12 – 7x
Answer:
x = 4
Step-by-step explanation:
4x - 8x = 12 - 7x
4x - 8x + 7x = 12
-4x + 7x = 12
3x = 12
x = 12/3
x = 4
Answer:
Step-by-step explanation:
4x -8x = 12 - 7x
-4x = 12 - 7x
3x = 12
x = 4
There is 50 people with their probabilities that pick a season of the year
Someone picking spring: 18/50: 36%
Someone picking summer 16/50: 32%
Someone picking fall 4/50: 8%
Someone picking winter: 12/50: 24%
What is the probability that two people in a row have chosen fall?
Out of 50 people, there are 50C5 = 50!/(5!*45!) ways to select 5 of them.
A probability simple definition is what?A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to express probabilities.
How many of those methods involve picking a particular person (you)? If you are selected, there are only 4 more options left out of the remaining 49. There are thus 49C4 = 49!/(5!*44!) ways to select both you and the other 4 individuals.
Therefore, (49C4)/(50C5) = 1/10 is the probability.
The probability that you are one of the five individuals chosen from 50 is 5/50, or 1/10, as a second check.
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2+2-2+2-2+2-5+2
Please tell the correct answer or else I will not mark anyone brainliest
2 + 2 - 2 + 2 - 2 + 2 - 5 + 2 =
2 + 2 + 2 + 2 + 2 - 2 - 2 - 5 =
10 - 9 =
1
In an independent-measures experiment with three treatment conditions has a sample of n = 10 scores in each treatment. If all three treatments have the same total. T1 T2 T3, what is SSbetween?
a. 0
b. 100
c. 10(3)
d. This cannot be determined from the information given.
The value obtained for SSbetween is 20. The correct answer is (b) 20.
To calculate the sum of squares between (SSbetween) for an analysis of variance (ANOVA), we need to determine the variation between the sample means of the different treatment conditions. The formula for SSbetween is as follows:
SSbetween = n * Σ(M - m)²
where n is the sample size for each treatment condition, M is the individual treatment condition mean, and m is the overall mean.
In this case, the sample size for each treatment condition is n = 10, and the treatment condition means are M1 = 1, M2 = 2, and M3 = 3.
To calculate SSbetween, we first find the overall mean (m) by taking the average of the treatment condition means:
m = (M1 + M2 + M3) / 3
m = (1 + 2 + 3) / 3
m = 6 / 3
m = 2
Now, we can calculate SSbetween:
SSbetween = n * Σ(M - m)²
SSbetween = 10 * [(1 - 2)² + (2 - 2)² + (3 - 2)²]
SSbetween = 10 * [(-1)² + (0)² + (1)²]
SSbetween = 10 * (1 + 0 + 1)
SSbetween = 10 * 2
SSbetween = 20
Therefore, the value obtained for SSbetween is 20. The correct answer is (b) 20.
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Incomplete question:
An independent-measures research study compares three treatment conditions using a sample of n = 10 in each treatment. For this study, the three sample means are M1 = 1, M2 = 2, and M3 = 3. For the ANOVA, what value would be obtained for SSbetween?
a.30
b.20
c.10
d. 2
5) The figure shown is a scale drawing of a playground in a park. The length is 5 cm and the width is 3 con,
The figure shown is a scale drawing of a play ground in. Park. The length is 5cm and the width is 3cm.
The actual playground has a width of 60 meters. What is the actual length in meters of the playground? Show your
work or explain your answer.
The actual length in meters of the playground is 100 meters.
A scale drawing is a smaller diagram of a larger image. For example, a map of the playground is a scale drawing of the playground.
In order to determine the actual length of the playground, the scale of the drawing has to be determined first.
Scale = actual width / width of the scale
60m / 3cm = 1cm : 20m
Length of the playground = scale x length of the scale drawing
20 x 5 = 100m
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If x = 3 and y = -4, evaluate:2x2 – 5xy + y
Remember to show your work separately to be submitted in dropbox.
Answer:
\(74\)
Step-by-step explanation:
\(2 {x}^{2} - 5xy + y \\ 2 \times {3}^{2} - 5 \times 3 \times - 4 + ( - 4) \\ 2 \times 9 - 15 \times - 4 - 4 \\ 18 + 60 - 4 \\ 78 - 4 \\ = 74\)
Hope this helps you.
Can I have the brainliest please?
have a nice day!
Answer:
74
Step-by-step explanation:
2x² - 5xy + y
Substitute x and y into the equation.
2(3)² - 5(3)(-4) + (-4)
Square the three.
2(9) - 5(3)(-4) + (-4)
Multiply the 2 and the 9.
18 - 5(3)(-4) + (-4)
Multiply 3 and -4.
18 - 5(-12) + (-4)
Multiply -5 and -12.
18 + 60 + (-4)
Add 18 and 60.
78 + (-4)
or
78 - 4
Subtract
74
I had $36. I spent 1/2 of my money on Thursday and 2/3 of the remainder on Wednesday. How much money did I have left?
Where are you genius people? I know you hella smart
Answer:
$12
Step-by-step explanation:
Half of $36 would be $18. $18 divided by 3 would be $6. $6 times 2 would be $12. Half comes from the 1/2 of money spent on Thursday. Dividing it by 3 comes from the remainder on Wednesday. We divide it by 3 since the denominator of 2/3 is 3. We then multiply it by 2, since the numerator in 2/3 is 2.
Find the solutions to the following equation. Answers as ordered pairsx^2 + 6x + 5 = 0
x² + 6x + 5 = 0
To find the solution, we can use the quadratic formula.
\(\begin{gathered} x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x_{1,2}=\frac{-6\pm\sqrt[]{6^2-4(1)(5)}}{2(1)} \\ x_{1,2}=\frac{-6\pm\sqrt[]{36^{}-20}}{2} \\ x_{1,2}=\frac{-6\pm4}{2} \\ x_1=\frac{-6+4}{2}=-1 \\ x_2=\frac{-6-4}{2}=-5 \end{gathered}\)The solutions are (-1, 0) and (-5, 0)
Among college students, the proportion p who say they're interested in their congressional district's election results has traditionally been 65%. After a series of debates on campuses, a political scientist claims that the proportion of college students who say they're interested in their district's election results is more than 65%. A poll is commissioned, and 180 out of a random sample of 265 college students say they're interested in their district's election results. Is there enough evidence to support the political scientist's claim at the 0.05 level of significance?
Using the test statistic, at the 0.05 level of significance, we do not find sufficient evidence to support the political scientist's claim and hence reject the null hypothesis.
Do we have enough evidence to support the political scientist's claim at the 0.05 level of significance?To determine whether there is enough evidence to support the political scientist's claim that the proportion of college students interested in their district's election results is more than 65%, we can perform a hypothesis test using the given data.
Let's set up the null and alternative hypotheses:
H₀: p ≤ 0.65 (Null hypothesis: The proportion of college students interested in election results is 65% or less)
Ha: p > 0.65 (Alternative hypothesis: The proportion of college students interested in election results is more than 65%)
We are given that the sample size is 265 college students, and out of this sample, 180 students say they're interested in their district's election results.
To perform the hypothesis test, we'll calculate the test statistic, which is the z-statistic in this case, using the formula:
z = (p - p₀) / √(p₀(1-p₀)/n)
Where p is the sample proportion, p₀ is the hypothesized proportion under the null hypothesis, and n is the sample size.
Let's calculate the sample proportion:
p = 180 / 265 ≈ 0.679
Now, we can calculate the test statistic:
z = (0.679 - 0.65) / √(0.65(1-0.65)/265) ≈ 1.295
Next, we'll compare the test statistic with the critical z-value at a 0.05 level of significance (α = 0.05) for a one-tailed test.
Using a standard normal distribution table or a statistical calculator, the critical z-value at α = 0.05 is approximately 1.645.
Since the test statistic (1.295) does not exceed the critical z-value (1.645), we fail to reject the null hypothesis. In other words, we do not have enough evidence to support the political scientist's claim that the proportion of college students interested in their district's election results is more than 65% based on this sample.
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Angle 1 and Angle 5 are examples of which type of angle pair?
Answer:
You forgot the image
Step-by-step explanation:
Let (Bt) denote a Brownian motion under the real-world measure with Bo = 0. Consider the Black-Scholes model for the stock price, d.St = 2Stdt + 4StdBt, So = 1, the savings account is given by t = 1 for all t. = (a) Write down the condition for a portfolio in this model to be self-financing. Consider the portfolio given by a = -t (units of the stock) and b Sudu (units of the savings account), determine with proof whether this portfolio is self-financing. ER State the Girsanov theorem. Using it, or otherwise, derive the expression (not the stochastic differential) for St, in terms of a Brownian motion under the equivalent martingale measure (EMM). (c) Denote by Ct the price at time t ≤ 2 of the call option on this stock with exercise price K = 1 and expiration date T = 2. By quoting an appropriate result, give the expression for Ct. Find the answer (in terms of the normal distribution function) for the case when t = 1.
The condition for a portfolio to be self-financing in the Black-Scholes model is that the portfolio's value does not change due to trading (buying or selling) costs or external cash flows. In other words, the portfolio's value remains constant over time, excluding the effects of the underlying assets' price changes.
For the given portfolio, a = -t (units of the stock) and b = S_t (units of the savings account). To determine if this portfolio is self-financing, we need to check if its value remains constant over time. Using Ito's lemma, we can express the value of the portfolio as:
d(Vt) = a_t * d(St) + b_t * d(Ct)
Substituting the values of a and b, we have:
d(Vt) = -t * (2St * dt + 4St * dBt) + S_t * d(t)
Simplifying this expression, we get:
d(Vt) = -2tSt * dt - 4tSt * dBt + S_t * dt
The portfolio is self-financing if d(Vt) = 0. However, in this case, we can see that the terms involving dBt do not cancel out, indicating that the portfolio is not self-financing.
Girsanov's theorem states that under certain conditions, it is possible to transform a Brownian motion under the real-world measure into a Brownian motion under an equivalent martingale measure (EMM). The EMM is a probability measure under which the discounted asset prices are martingales. By applying Girsanov's theorem or alternative techniques, we can derive the expression for St, the stock price, under the EMM. Unfortunately, without further information or specifications, it is not possible to provide the specific expression in this case.
To determine the price Ct of the call option on the stock at time t ≤ 2, with an exercise price K = 1 and expiration date T = 2, additional information or an appropriate result is required. Without specific details, such as the volatility of the stock or the risk-free interest rate, it is not possible to provide an expression for Ct.
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Convert 1 inch into feet. Round your answer to the nearest hundredth.
Answer:
0.1
Step-by-step explanation:
hope it helps
Answer:
0.010
You have to round down because of 0.012 being closer to 0.010 than 0.020
Write the trigonometric form of the complex number. (Let 0 ≤ < 2.)1 − √3iradical 3i
Solution
We have the following number:
\(1-\sqrt[]{3}i\)and we have:
\(a=1,b=-\sqrt[]{3}\)And we can write the trigonometric form as:
\(r(\cos \theta+i\sin \theta)\)the radius is:
\(r=\sqrt[]{(1)^2+(-\sqrt[]{3})^2}=\sqrt[]{4}=2\)The angle is:
\(\theta=\tan ^{-1}(\frac{-\sqrt[]{3}}{1})=\frac{5\pi}{3}\)Then the answer is:
\(2\lbrack\cos (\frac{5\pi}{3})+i\sin (\frac{5\pi}{3})\rbrack\)
Which statement is correct about the F distribution? A) Cannot be negative B) Cannot be positive C) Is the same as the t distribution D) Is the same as the z distribution
Option A) "Cannot be negative" is a correct statement about the F distribution. The F distribution is a probability distribution that is used in statistical hypothesis testing to compare the variances of two populations.
The assertion "cannot be positive" about the F distribution is erroneous. The F distribution can only accept positive values and cannot accept negative values; however, it can accept values greater than zero.
"Is the same as the t distribution" is an error. When the sample size is small or the population standard deviation is unknown, the t distribution is employed for testing hypotheses regarding the population mean.
"Is the same as the z distribution" is similarly erroneous. When the population standard deviation is known and the sample size is large, the z distribution is employed as a probability distribution.
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A rod is cut into 8 equal pieces.what fraction of the rod does 1 piece represent
Answer:
1/8
Step-by-step explanation:
you divide 1 by 8 which is 1/8.
F(x)= (x-2)(x+4)(x+5)What is the sign of f on the interval -4
By evaluating the polynomial, we will see that the sign on the interval [-4, 2] is negative.
What is the sign of f on the interval [-4, 2]?Here we have the polynomial:
f(x) = (x - 2)*(x + 4)*(x + 5).
You can see that the roots of the polynomial are at:
x = 2
x = -4
x = -5.
Then, on the interval [-4, 2], the sign of the polynomial don't change. So to get the sign of f(x) on that interval we can just evaluate it in any value of x that belongs to the interval, for example, x = 0.
f(0) = (0 - 2)*(0 + 4)*(0 + 5) = -2*4*5 = -40
With this, we can conclude that the sign of f(x) on the given interval is negative.
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Answer:
always negative
Step-by-step explanation:
Study the following data set.
{23,21,21,25,27,16,55,3,11,38}
What is the median of the data?
Enter your answer as a number, like this: 42
Answer:
22
Step-by-step explanation:
Arrange the data points from smallest to largest.
If the number of data points is odd, the median is the middle data point in the list.
If the number of data points is even, the median is the average of the two middle data points in the list.
The median of the data is given by M = 22
What is Median?The median is the value that's exactly in the middle of a data set when it is ordered. It's a measure of central tendency that separates the lowest 50% from the highest 50% of values. The steps for finding the median differ depending on whether you have an odd or an even number of data points
Arrange the data points from smallest to largest.
If the number of data points is odd, the median is the middle data point in the list.
If the number of data points is even, the median is the average of the two middle data points in the list.
Given data ,
Let the median of the data be represented as M
Now , the values of the data are given by set A
where the value of A = { 23 , 21 , 21 , 25 , 27 , 16 , 55 , 3 , 11 , 38 }
Now , arranging the values in ascending order is
A = { 3 , 11 , 16 , 21 , 21 , 23 , 25 , 27 , 38 , 55 }
The number of elements = 10
So , the median is M = ( 21 + 23 ) / 2
M = 44/2
M = 22
Therefore , the value of M is 22
Hence , the median is M = 22
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2x – 3 > 2(x-5)
What’s the answer
Answer:
0>-7
true for all X
aka (-infinite, infinite)
please help! will mark brainliest
Answer:
i think its a or d
Step-by-step explanation:
find the 3 × 3 matrix that translates a point in r 2 by (3, 1) then rotates the result 45 degrees about the origin (using homogeneous coordinates).
The 3 × 3 matrix that translates a point in r 2 by (3, 1) then rotates the result 45 degrees about the origin is
M = | 1/√2 -1/√2 3/√2- 1/√2 |
| 1/√2 1/√2 1/√2 + 1/√2 |
| 0 0 1 |
To find the 3x3 matrix that translates a point in R^2 by (3, 1) and then rotates the result 45 degrees about the origin using homogeneous coordinates, we can follow these steps:
Translation Matrix:
The translation matrix for a 2D translation by (3, 1) is:
T = | 1 0 3 |
| 0 1 1 |
| 0 0 1 |
This matrix translates a point (x, y) by adding the translation vector (3, 1) to it.
Rotation Matrix:
The rotation matrix for a 2D rotation by 45 degrees counterclockwise is:
R = | cos(theta) -sin(theta) 0 |
| sin(theta) cos(theta) 0 |
| 0 0 1 |
Since we want to rotate by 45 degrees, theta = 45 degrees = π/4 radians. Therefore, the rotation matrix becomes:
R = | cos(π/4) -sin(π/4) 0 |
| sin(π/4) cos(π/4) 0 |
| 0 0 1 |
Simplifying, we have:
R = | 1/√2 -1/√2 0 |
| 1/√2 1/√2 0 |
| 0 0 1 |
Combine Translation and Rotation:
To obtain the combined transformation matrix, we multiply the translation matrix T by the rotation matrix R:
M = T * R
Performing the matrix multiplication:
M = | 1 0 3 | | 1/√2 -1/√2 0 |
| 0 1 1 | * | 1/√2 1/√2 0 |
| 0 0 1 | | 0 0 1 |
Simplifying, we have:
M = | 1/√2 -1/√2 3/√2 - 1/√2 |
| 1/√2 1/√2 1/√2 + 1/√2 |
| 0 0 1 |
This is the desired 3x3 matrix that translates a point in R^2 by (3, 1) and then rotates the result 45 degrees about the origin using homogeneous coordinates.
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i need help please only help if you know the answer
Answer:
D
Step-by-step explanation:
Abigail and Spencer calculate the slope of the line between the points (3,-1) and (5,4) in different ways. Abigail calculates the slope by dividing -1 - 4 with 3 - 5. Spencer divides 4 - (-1) by 5 - 3. When they check their work with their mutual friend Lauren, she says that they are both wrong and shows them her work. She calculates -1 - 4 and divides by 5 - 3. Who is correct among these three friends? Who is incorrect? Why? One of them is Spencer,
Answer:
Spencer and Abigail are correct
Lauren is incorrect
Step-by-step explanation:
Spencer and Abigail are correct
Slope = change in y ÷ change in x
Or \(m=\dfrac{y_2-y_1}{x_2-x_1}\)
Let \((x_1,y_1)\) = (3, -1)
Let \((x_2,y_2)\) = (5, 4)
\(\implies m=\dfrac{4-(-1)}{5-3}=\dfrac52\)
This is Spencer's method
Let \((x_1,y_1)\) = (5, 4)
Let \((x_2,y_2)\) = (3, -1)
\(\implies m=\dfrac{-1-4}{3-5}=\dfrac52\)
This is Abigail's method
It doesn't matter which point you label as point 1 and point 2, as long as you carry out the slope calculation correctly.
Lauren's calculation is wrong as she calculated her slope as:
\(m=\dfrac{y_2-y_1}{x_1-x_2}\)
where it should have been \(m=\dfrac{y_2-y_1}{x_2-x_1}\)
Parameterize the line through p=(3,−5) and q=(8,0) so that the points p and q correspond to the parameter values t=9 and 12.
The parameterization of the line through points p=(3,-5) and q=(8,0) where p corresponds to t=9 and q corresponds to t=12 is given by the equations x = t - 6 and y = t - 14.
To parameterize the line, we need to find equations that express x and y in terms of a parameter t. We can start by determining the slope of the line using the coordinates of points p and q:
slope (m) = (y₂ - y₁) / (x₂ - x₁)
= (0 - (-5)) / (8 - 3)
= 5 / 5
= 1
Now that we have the slope, we can write the equations in point-slope form using point p:
y - y₁ = m(x - x₁)
y - (-5) = 1(x - 3)
y + 5 = x - 3
y = x - 8
Next, we can express x and y in terms of the parameter t by substituting x = 3 + (t - 9) and y = -5 + (t - 9) into the equation above. Simplifying, we get:
y = (3 + (t - 9)) - 8
y = t - 9 - 5
y = t - 14
Therefore, the parameterization of the line through points p and q where p corresponds to t=9 and q corresponds to t=12 is given by the equations x = 3 + (t - 9) and y = -5 + (t - 9), or equivalently, x = t - 6 and y = t - 14.
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Pre-cal Problem, please, help is very much appreciated!
Let y be the length of the third side. By the Pythagorean theorem,
y² + x² = 3² = 9
so that
y = √(9 - x²)
(taking the positive root because one expects length to be positive)
Then by the definitions of sine, cosine, and tangent, we have
sin(θ) = x / 3 → θ = sin⁻¹(x / 3)
cos(θ) = √(9 - x²) / 3 → θ = cos⁻¹(√(9 - x²) / 3)
tan(θ) = x / √(9 - x²) → θ = tan⁻¹(x / √(9 - x²))
A bag contains 4 red marbles, 3 white marbles, and 7 blue marbles. You pick a marble without looking. What is the probability of drawing a white marble.
Answer:
3/14
Step-by-step explanation:
You add all the marbles to get your total/denominator then take the white marbles and that is the numorator.
5/6-1/9=?/?-?/? =13/18
ans of this question
4 (3c+4d)
Answer: 12c+16d
Step-by-step explanation: 4(3c+4d)
(4)(3c+4d)
(4)(3c)+(4)(4d)
12c+16d
Answer:
Întâi faci paranteza și după de ie faci cu 4
Find the absolute extrema if they exist, as well as all values of x where they occur, for the function f(x)=x²-32x²-2 on the domain (-5,5). CITS Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. The absolute maximum is which occurs at x= (Round the absolute maximum to two decimal places as needed. Type an exact answer for the value of x where the maximum occurs. Use a comma to separate answers as needed.) OB. There is no absolute maximum. Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. OA. The absolute minimum is which occurs at x- (Round the absolute minimum to two decimal places as needed. Type an exact answer for the value of x where the minimum occurs. Use a comma to separate answers as needed.) OB. There is no absolute minimum.
The function f(x) = x² - 32x² - 2 on the domain (-5,5) has an absolute maximum at x = 0 and x = 1/32, with a value of -2, and an absolute minimum at x = -5, with a value of -827.
To find the absolute extrema of the function f(x) = x² - 32x² - 2 on the domain (-5,5), we need to consider the critical points and endpoints of the interval.
To find the critical points, we take the derivative of the function and set it equal to zero.
f'(x) = 2x - 64x = 0
Simplifying the equation gives us:
2x(1 - 32x) = 0
This equation has two solutions: x = 0 and x = 1/32.
We also need to evaluate the function at the endpoints of the interval (-5,5), which are x = -5 and x = 5.
Now, we evaluate the function at these critical points and endpoints to determine the absolute extrema.
a) f(-5) = (-5)² - 32(-5)² - 2 = 25 - 32(25) - 2 = -827.
b) f(0) = 0² - 32(0)² - 2 = -2.
c) f(1/32) = (1/32)² - 32(1/32)² - 2 = -2.
d) f(5) = 5² - 32(5)² - 2 = 123.
Analyzing the values, find that the absolute maximum is -2, occurring at x = 0 and x = 1/32. The absolute minimum is -827, occurring at x = -5.
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I will mark as a brainliest .
Can anyone help me :( .
Please don’t answer if you do not know .
Answer:-
Slope = 1/6
Give me a Hifi
Answer:
slop =1/6
thank you very much
If $1 is 3% and $2 is 7% and w1 is 0.1, beta of the portfolio is
The beta of the portfolio, considering $1 with a beta of 3% and $2 with a beta of 7% and a weight of 0.1 (w1), is 6.6%.
The beta of a portfolio measures its sensitivity to overall market movements. To calculate the beta of a portfolio, we need the individual asset weights and betas of each asset. Given that $1 has a beta of 3% and $2 has a beta of 7%, with a weight of 0.1 (w1), we can determine the beta of the portfolio.
To calculate the beta of the portfolio, we use the following formula:
β(portfolio) = (w1 * β1) + (w2 * β2) + ...
In this case, the portfolio contains two assets, so the formula becomes:
β(portfolio) = (w1 * β1) + (w2 * β2)
Substituting the given values:
β(portfolio) = (0.1 * 3%) + (0.9 * 7%)
β(portfolio) = 0.3% + 6.3%
β(portfolio) = 6.6%
Therefore, the beta of the portfolio is 6.6%.
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