The number of walking paces as you walk down main street (0.25 miles) is 720 walking paces
How to convert 0.25 mile to feet1 mile = 5280 feet
Therefore,
0.25 mile = (0.25 mile × 5280 feet) / 1 mile
0.25 mile = 1320 feet
How to convert 1320 feet to inches1 feet = 12 inches
Therefore,
1320 feet = (1320 feet × 12 inches) / 1 feet
1320 feet = 15840 inches
How to convert 15840 inches to walking pace22 inches = 1 walking pace
Therefore,
15840 inches = (15840 inches × 1 walking pace) / 22 inches
15840 inches = 720 walking paces
Thus, we can conclude that as you walk down main street (0.25 miles), there are 720 walking paces
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Which of these statements explains why we have day and night? [1] The Earth orbits the Sun once a day The Sun orbits the Earth once a day. The Sun spins on its axis once a day. The Earth spins on its axis once a day.
Answer:
The Earth spins on its axis once a day.
Explanation:
In simple words,The Earth revolves on its axis once every 24 hours and circles the sun once every 365 days. The Earth's rotation on its axis, not its orbit throughout the sun causes day as well as night. The word 'one day' refers to the period it requires the Earth to spin entirely on its axis, which involves both day as well as night.
how are sound vibrations amplified in a vertebrate ear?
Answer:
by movement of the bones of the middle ear and by differences in the surface area of the eardrum versus the oval window.
Explanation:
2. The timing mechanism in a grandfather's clock is based on the principles of a simple
pendulum. If your clock is gaining time (running fast) what should you do to get it running
more accurately?
To get a grandfather clock running more accurately, if it is gaining time, you should adjust the length of the pendulum.
How to adjust the length of the pendulum?
This can typically be done by moving the pendulum bob up or down the pendulum rod. A shorter pendulum will cause the clock to run faster, while a longer pendulum will cause it to run slower.
It is important to make small adjustments and wait for the clock to stabilize before making further adjustments. It's also recommended to consult the clock's manual for instructions on how to adjust the pendulum length.
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draw a figure of a simple pendulum explain its amplitude and effective length ?
Answer:
Explanation:
A simple pendulum consists of a mass (usually represented as a small object or bob) attached to a string or rod of negligible mass. The mass is free to swing back and forth under the influence of gravity.
In the figure, the point of suspension is denoted by "O," and the mass (bob) is represented by the small circle. The string or rod is represented by the vertical line connecting the point of suspension to the bob.
Amplitude:
The amplitude of a pendulum refers to the maximum displacement or swing of the bob from its equilibrium position. In the figure, the amplitude can be represented by the angle formed between the vertical position and the position of the bob when it swings to its maximum distance on one side. It is usually denoted by the symbol "A."
Effective Length:
The effective length of a pendulum refers to the distance from the point of suspension to the center of mass of the bob. It represents the distance over which the mass swings back and forth. In the figure, the effective length can be measured as the length of the string or rod from the point of suspension to the center of the bob. It is usually denoted by the symbol "L."
It is important to note that the amplitude and effective length of a simple pendulum affect its period of oscillation (the time taken for one complete swing). The relationship between these parameters and the period can be described by mathematical formulas.
Overall, the simple pendulum is a fundamental concept in physics and provides a simplified model for understanding oscillatory motion and the principles of periodic motion.
Baker's weight and mass are measured on Earth and on the moon. Which measurement is the same in both places?
Answer: mass
The mass of a person is constant, weight is a force that is influenced by gravity.
Henry ran a 100 m race. Use the graph to answer the following:
a. How long did it take for Henry to run 100 m?
b. What is Henry's average speed over the race?
Using the graph, which describes how Henry ran the 100m race;
a) It takes Henry 20seconds to run 100m
b) Henry's average speed over the race is; 5m/s.
According to the linear graph which describes the distance ran by Henry during the 100m race as a function of time.
a) Since the distance from start ran by Henry is plotted on the vertical axis, and the time is plotted on the horizontal axis;
To determine how long it took Henry to run 100m; The point corresponding to 100m is traced downward from the line of the graph and we find out that;
It takes Henry 20seconds to run 100m
b) Henry's average speed over the race is simply;
The slope of the distance-time graph.
Therefore,
Average speed = (100-0)/(20-0)Average speed = 100/20Average speed = 5m/s.Therefore, Henry's average speed over the race is; 5m/s.
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Determina la presión que ejercen los patinadores sobre el hielo, teniendo en cuenta que la cuchilla del patín mide 30cm de largo y su grosor es de 5mm, y que el peso de las dos personas es 120kg
Answer:
La presión que los patinadores ejercen sobre el hielo es 7,848,000 Pa
Explanation:
Los parámetros dados de los patinadores en la pala son;
La longitud de la hoja en el patín, l = 30 cm = 0.03 m
El espesor de la hoja, t = 5 mm = 0,005 m
El peso de las dos personas, m = 120 kg
Suponiendo que la sección transversal de la cuchilla sobre el hielo es rectangular, tenemos;
A = l × t
∴ A = 0,03 m × 0,005 m = 0,00015 m²
La fuerza de peso de los dos patinadores, W = m × g
Dónde;
g = La aceleración debida a la gravedad ≈ 9,81 m / s²
m = La masa de los dos patinadores = 120 kg
∴ W = 120 kg × 9,81 m / s² = 1,177,2 N
Presión, P = Fuerza, F/(Área, A)
∴ P = (1.177,2 N) / (0.00015 m²)= 7,848,000 Pascals
La presión que los patinadores ejercen sobre el hielo., P = 7,848,000 Pascals
what did the cassini spacecraft and its huygens probe discover on the surface of titan, the largest of saturn's moons?
The are some of the significant discoveries they are Lakes and Seas ,River Channels and Drainage Systems ,Methane Rain ,Dunes ,Cryovolcanism , Complex Organic Chemistry.
Lakes and Seas: Cassini revealed the presence of liquid hydrocarbon lakes and seas on Titan's surface. These bodies of liquid, primarily composed of methane and ethane, were the first discovered beyond Earth.
River Channels and Drainage Systems: The spacecraft identified intricate river-like channels and drainage networks on Titan's surface. These features suggested the presence of a hydrological cycle on the moon, where liquid hydrocarbons play a role similar to water on Earth.
Methane Rain: Cassini captured evidence of methane rain showers on Titan. This indicated a dynamic weather system and precipitation cycle on the moon, with methane acting as a key component.
Dunes: Extensive dune fields covering large regions of Titan were observed by the spacecraft. These dunes, composed of organic materials, indicated wind-driven processes on the moon's surface.
Cryovolcanism: The presence of possible cryovolcanic features was suggested by Cassini. These volcanic-like structures might erupt with a combination of water and ammonia rather than molten rock, given the extreme cold temperatures on Titan.
Complex Organic Chemistry: The Huygens probe, which descended to Titan's surface, discovered complex organic molecules in the moon's atmosphere. These compounds are believed to be precursors to the development of life as we know it.
Overall, the Cassini spacecraft and the Huygens probe provided a wealth of information about Titan's surface, revealing a dynamic and intriguing world with similarities and unique characteristics compared to Earth.
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suppose a small child rolls off a bed that is 0.57 m above the floor. if the floor is hardwood, the child's head is brought to rest in approximately 2.1 mm. if the floor is carpeted, this stopping distance is increased to about 1.4 cm. calculate the magnitude and duration of the deceleration in both cases, to determine the risk of injury.
To calculate the magnitude and duration of the deceleration, we need to know the initial velocity of the child and the stopping distance. The initial velocity of a freely falling object can be calculated using the equation:
v = sqrt(2gh), where g is the acceleration due to gravity (9.8 m/s^2), and h is the height.
In this case, h = 0.57 m, so the initial velocity can be calculated as follows:
v = sqrt(2 * 9.8 * 0.57)
v = 2.38 m/s
Now we have the initial velocity, we can calculate the magnitude and duration of the deceleration in both cases.
Case 1: Hardwood floor
The stopping distance can be calculated using the equation:
d = v^2 / (2a), where v is the initial velocity and a is the deceleration.
Setting the stopping distance equal to 2.1 mm and solving for a, we get:
a = v^2 / (2d)
a = (2.38 m/s)^2 / (2 * 0.0021 m)
a = 68 m/s^2
The duration of the deceleration can be calculated as follows:
t = v / a
t = 2.38 m/s / 68 m/s^2
t = 0.0349 s
Magnitude of the deceleration: 68 m/s^2
Duration of the deceleration: 0.0349 s
Case 2: Carpeted floor
The stopping distance can be calculated using the equation:
d = v^2 / (2a), where v is the initial velocity and a is the deceleration.
Setting the stopping distance equal to 1.4 cm and solving for a, we get:
a = v^2 / (2d)
a = (2.38 m/s)^2 / (2 * 0.014 m)
a = 12 m/s^2
The duration of the deceleration can be calculated as follows:
t = v / a
t = 2.38 m/s / 12 m/s^2
t = 0.198 s
Magnitude of the deceleration: 12 m/s^2
Duration of the deceleration: 0.198 s
The magnitude of the deceleration in the first case (hardwood floor) is much greater than in the second case (carpeted floor), indicating a higher risk of injury for the child in the first case. However, the duration of the deceleration is much shorter in the first case, which might result in a less severe injury. The duration of the deceleration is also much longer in the second case, indicating a lower risk of injury.
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in three sentences, explain why I would die with a plastic bag over my head, including the vocabulary oxygen, carbon dioxide, and cellular respiration
Answer:
easy how you would die from a plastic bag being over your head is by sufacation the oxegen you breath with soon become carbon dioxide and kill you is it gets to your cellular reperation atory
Explanation:
The drop time can be calculated as follows: where y is the vertical height of the table and g is the
acceleration due to gravity. How did the calculated drop time compare to the average of your measured drop
times? Find the percent error using the following equation:
What factors might cause the differences?
Answer:
Tt can be calculated by copy
You walk 6 meters east followed by 4 meters west in 4 seconds. What is your velocity
Answer:
16 velocity
Explanation:
explain the action of the conventional shock absorber on both compression (jounce) and rebound stokes.
The typical shock absorber is made to lessen both the shock, or "jounce," felt during compression strokes and the amount of rebound felt during rebound strokes.
The shock absorber uses hydraulic pressure during compression strokes to slow down and absorb the shock, or jounce, of the vehicle when it travels over bumps or potholes. The kinetic energy of the shock is transformed into thermal energy by a piston, cylinder, and hydraulic fluid, which work together to accomplish this. The shock absorber works to lessen the vehicle's rebound or bounce during rebound strokes, making the ride more comfortable. It accomplishes this by utilizing a valve to control the hydraulic fluid's flow and produce resistance, which aids in absorbing the rebound's energy.
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1ST TO ANSWER GET BRAINLIEST ANSWER How old do u need to be to drink Beer
The age limit to drink beer is 17 or 18 and up
A 6kg object is lifted to a height of 10m. How much PE does it have?
Answer:
588 J
Explanation:
P.E = mgh
= 6 * 9.8 * 10
= 588 J
if g value is rounded and taken as 10 then answer is 600 J.
Module 3 Discussion!
After reading Ch.12 and 13 of the text (The essentials of Finance and Accounting for nonfinancial managers/ Third Edition) on Strategy and Financial Forecasting, watching the SWOT video based on Paley’s Products from the Ratio Analysis in Module 2 and the additional narrative information in Appendix C, Phase
Create a SWOT analysis that will reflect the TOWS analysis as described in Ch. 12 of the text. The purpose of the SWOT analysis is to lay out several issues and possibilities to be considered in Paley’s strategic planning. The strengths and weaknesses are internal issues, whereas the opportunities and threats are external.
The second part of the analysis is to create actions based on the SWOTs. This is sometimes called a TOWS analysis and is done by comparing the boxes, two at a time:
Offensive actions come from strengths that link to opportunities, so a specific strength can be applied to exploit an opportunity.
Adjusting actions come from addressing weaknesses, which then can be used to exploit opportunities that previously had not been possible.
Turnaround actions come from weaknesses that link to threats. These are high-risk issues where a priority needs to be given to addressing the weakness to minimize the vulnerability.
Defensive actions come from threats that link to strengths. These are latent issues because if the threat materializes, an already-existing strength is available to counter it.
Additional actions can be included to address other issues not directly identified in the SWOTs.
3. From the actions identified in part 2, pick 3-5 strategic actions that you feel Paley must achieve or at least start in the upcoming year and state your reasons for including them.
Attach your completed SWOT form and list of strategic actions with supporting logic and facts from the case as your answer for this discussion question. These actions are the foundation for the strategic plan
SWOT Analysis Strengths- Paley’s Products has a low overhead cost with the company operating at a high level of efficiency, resulting in competitive pricing.- They have a team of experienced employees who have worked in the industry for several years.- They have a variety of products in the portfolio that can satisfy customers from different sectors.- They are reputable and have a loyal customer base.Weaknesses- They have been slow to adopt new technology, and this may be a disadvantage to the company.- Limited marketing and sales promotion are affecting their sales revenue.-
They depend on a few key customers for the bulk of their sales revenue, leaving them vulnerable to market changes.Opportunities- Expansion of the product line to include unique products.- The establishment of strategic partnerships with other businesses in the industry.- Exploration of new markets, such as international markets.- Improvement of marketing techniques to increase brand awareness.Threats- Changes in consumer preferences towards environmentally friendly products.- Increase in competition from other businesses in the industry.- Fluctuating market prices for raw materials that may lead to price increases.
Strategic Actions to be taken by Paley Products1. Development of an E-commerce platform to allow online transactions with customers. The E-commerce platform will enable Paley to reach a wider customer base, expand its reach, and increase sales revenue.2. Investment in the research and development of new environmentally friendly products. Paley will remain competitive and cater to the needs of consumers who prefer green products.3. Establishment of strategic partnerships with other businesses in the industry to leverage the strength of other companies in the industry and to develop new products or increase market share.4. Improvement of marketing techniques to increase brand awareness and improve visibility. A marketing strategy that incorporates social media and other digital channels can help promote the brand to potential customers.5. Expansion into international markets. This will enable Paley to diversify its customer base and generate more revenue. Paley can start by targeting nearby countries, then expand globally as they gain more experience and financial stability.
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using the principle of conservation of mechanical energy answer the following question. during a jump, a 75 kg individual reaches a height of 0.6 meters which is not at their max height. at this point their vertical velocity is equal to 0.9 m/s. during the up concentric phase of the jump they have an average grf of 1800 newtons directed up and slightly to the right at an angle of 80 degrees above the horizontal. what is their initial vertical velocity at the point of take off and what is their average velocity from the bottom of their countermovement jump to take off?
Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test.
What does a vertical jump countermove?Athletes are asked to immediately squat to a depth of their choosing and then jump as high as they can in the Countermovement Jump (CMJ), a vertical jump test. It is the first leap in our force plate evaluation and is used to gauge lower body power via jump height as well as lower limb asymmetries.With beginning leaping angles of 21 and 38 degrees, respectively, the running jump and standing jump in conventional sports have initial velocities of 9.15 and 2.70 m/s. The initial velocity's maximum strength, the force's angle of engagement, and height are all strongly related to the 9.15 m/s maximum horizontal speed.To learn more about Countermovement refer to:
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what is the frequency of a wave that has a wavelength of 0.39 m and a speed of 86 m/s
The frequency of a wave with a wavelength of 0.39 m and a speed of 86 m/s can be calculated using the formula: frequency = speed / wavelength. Substituting the given values into the formula, we find that the frequency of the wave is approximately 220.51 Hz.
The frequency of a wave refers to the number of complete cycles or oscillations it undergoes per second. It is measured in hertz (Hz). To calculate the frequency of a wave, we need to use the formula: frequency = speed / wavelength.
Given values:
Wavelength (λ) = 0.39 m
Speed (v) = 86 m/s
Using the formula: frequency = speed / wavelength
frequency = 86 m/s / 0.39 m
Dividing the speed (86 m/s) by the wavelength (0.39 m), we find:
frequency ≈ 220.51 Hz
Therefore, the frequency of the wave with a wavelength of 0.39 m and a speed of 86 m/s is approximately 220.51 Hz.
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If the force of gravity (weight) on a scuba diver
is 600 N, what should the buoyant force be if
the diver wants to descend?
Answer:
<600 N
Explanation:
If the slits that create this pattern are 25 μm apart and are located 0.95 m from the screen, what are the m = 1 distances from the central maximum for red (700 nm) and violet (400 nm) light?
The distance from the central maximum for violet light is 0.0152 meters.
To find the distances from the central maximum for red and violet light, we can use the formula for the position of the m-th order fringe in a double-slit interference pattern:
y = mλL / d
where y is the distance from the central maximum, λ is the wavelength of light, L is the distance from the slits to the screen, d is the distance between the slits.
For red light with a wavelength of 700 nm (700 x 10^-9 m), substituting the values into the formula:
y_red = (1)(700 x 10^-9 m)(0.95 m) / (25 x 10^-6 m)
≈ 0.0266 m
Therefore, the distance from the central maximum for red light is approximately 0.0266 meters.
For violet light with a wavelength of 400 nm (400 x 10^-9 m), using the same formula:
y_violet = (1)(400 x 10^-9 m)(0.95 m) / (25 x 10^-6 m)
≈ 0.0152 m
Hence, the distance from the central maximum for violet light is approximately 0.0152 meters.
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What is the force on a 0.0020 C charge in an electric field of 150 V/m?
A) 0.30 N
B) 7.5 x 10 N
C) 150.002 N
D) 1.3 X 10-5 N
Answer: The answer is B. 150.002
Explanation: Add 0.0020 by 150
Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N
What is an Electric field ?An electric field is defined as the electric force per unit charge . The electric field is radially outward from a positive charge and radially in toward a negative charge .
General formula to find Electric field is :
Electric field = Force / charge
given
charge = 0.0020 C
Electric field = 150 V/m
Force = ?
Force = Electric field * charge
= 150 V/m * 0.0020 C
= 0.3 N
Force on a 0.0020 C charge in an electric field of 150 V/m will be 0.3 N
correct answer is A) 0.30 N
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HELPPPP
The charge of each iron ion in the ionic compound FeS is Fe2+.
Please select the best answer from the choices provided
T
F
Answer:
True I think
Explanation:
Answer:
the answer is supposed to be True
Explanation:
hope this helps Kelsee <3
Antireflection coatings can be used on the inner surfaces of eyeglasses to reduce the reflection of stray light into the eye, thus reducing eyestrain.PART A) A 90-nm-thick coating is applied to the lens. What must be the coating's index of refraction to be most effective at 480 nm?
To minimize reflection at the surface, the coating's index of refraction should be equal to the square root of the product of the indices of refraction of the lens and the surrounding medium.
Assuming the lens is made of glass, with an index of refraction of approximately 1.5, and the surrounding medium is air, with an index of refraction of approximately 1, the index of refraction for the coating can be found as follows: n_coating = sqrt(n_lens * n_air), n_coating = sqrt(1.5 * 1), n_coating = sqrt(1.5), n_coating ≈ 1.22. Therefore, for a 90-nm-thick coating to be most effective at reducing reflection at a wavelength of 480 nm, its index of refraction should be approximately 1.22. This will allow the coating to reduce the reflection of stray light into the eye and reduce eyestrain.
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A lamp is marked 24V, 100W. Describe an experiment to check that the electrical power supplied to the lamp is 100W when the p.d. across it is 24V.
In your account you should
* include a circuit diagram,
* state the readings that are taken,
* show how the result is calculated from the readings.
The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
What is electrical power?Electrical power is the rate at which electrical work is done.
The unit of electrical power is Watts.
Power = Current × VoltageThe experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.
The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.
The ammeter reading is taken as well.
When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.
Calculating, the power of the lamp:
Power = 24 × 4.2 = 100 W
Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.
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Which is equivalent to i22?
Answer:
Explanation: We need to find the equivalent of the given imaginary number with 22 power:
\(i^{22}\)Using exponent properties, we can rearrange this as:
This hurts. Help me.
Answer:
a. T₂ = 60 N
b. W = 25.98 N
Explanation:
a.
Taking right side as positive x direction, the equation for sum of forces in x-direction can be written as follows:
\(T_{2}Sin\ 30^o - T_{1} = 0\\T_{2}Sin\ 30^o = T_{1}\\T_{1} = (T_{2})(Sin\ 30^o)\\where,\\T_{2} = 30\ N\\Therefore,\\T_{1} = (30\ N)(Sin\ 30^o)\\\)
T₁ = 15 N
b.
Taking upward direction as positive y direction, the equation for sum of forces in y-direction can be written as follows:
\(T_{2}Cos\ 30^o - W = 0\\T_{2}Cos\ 30^o = W\\W = (30\ N)Cos\ 30^o\\\)
W = 25.98 N
the frequency of an x ray is 7.4x10^18 hz. what is the x ray's wavelength?(hint
even though it isn't listed you should know the speed that x rays travel at)
If the frequency of an X-ray is 7.4x10^18 hz then its wavelength will be 4.05x10^-11 meters.
The wavelength of an X-ray with a frequency of 7.4x10^18 Hz can be calculated by using the following formula.
We can use the formula: wavelength = speed of light/frequency.
X-rays travel at the speed of light, which is approximately 3.0x10^8 meters per second (m/s).
So, the wavelength of the X-ray would be:
wavelength = (3.0x10^8 m/s) / (7.4x10^18 Hz) ≈ 4.05x10^-11 meters.
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A police car chases a speeder along a straight road towards a cliff both vehicles move at 160km/h the siren on the police car produces sound at a frequency of 100hz calculate Doppler shift in the frequency heard by the driver in a car behind the police at 120km/h moving towards the cliff and velocity if sound in air is 330m/s
Answer:
f ’= 97.0 Hz
Explanation:
This is an exercise of the doppler effect use the frequency change due to the relative movement of the fort and the observer
in this case the source is the police cases that go to vs = 160 km / h
and the observer is vo = 120 km / h
the relationship of the doppler effect is
f ’= f₀ (v + v₀ / v- \(v_{s}\))
let's reduce the magnitude to the SI system
v_{s} = 160 km / h (1000 m / 1km) (1h / 3600s) = 44.44 m / s
v₀ = 120 km / h (1000m / 1km) (1h / 3600s) = 33.33 m / s
we substitute in the equation of the Doppler effect
f ‘= 100 (330+ 33.33 / 330-44.44)
f ’= 97.0 Hz
Our eyes perceive colors because of differences in which of the following properties of light?
a)
Wavelength
b)
Intensity
c)
Source
d)
Angle
The properties of light is option a wavelength.
Wavelength:It is the distance between the points of two consecutive waves. It is usually denoted by the Greek letter lambda (λ), and it is equal to the speed (v) of a wave train in a medium divided by its frequency (f): λ = v/f.
So based on the above information, the a option is correct.
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which is 20 light years planet from earth
A light-year is a unit of distance, specifically the distance that light travels in one year.
Light travels at a speed of approximately 299,792 kilometers per second (or about 186,282 miles per second) in a vacuum. Therefore, to determine which planet is 20 light-years away from Earth, we need to identify a planet located at a distance of approximately 20 times this speed of light.
As of my knowledge cutoff in September 2021, no known exoplanets have been directly observed and confirmed to be located exactly 20 light-years away from Earth. However, there are numerous exoplanets that have been discovered within a range of distances from Earth.
Some notable exoplanets discovered within approximately 20 light-years of Earth include:
Proxima Centauri b: This exoplanet is located in the habitable zone of the closest star system to our Solar System, Proxima Centauri. It is estimated to be around 4.24 light-years away.Ross 128 b: This exoplanet orbits a red dwarf star known as Ross 128, located approximately 11 light-years away from Earth.TRAPPIST-1 system: This system hosts seven Earth-sized planets orbiting the ultra-cool dwarf star TRAPPIST-1. The TRAPPIST-1 system is located around 39 light-years away from Earth.know more about light-year here:
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