When orange light of wavelength λ = 590 nm is incident on two slits that are 10.0 μm apart, how many (whole) dark fringes will be produced on an infinitely large screen? Therefore, 169,000 whole dark fringes will be produced on an infinitely large screen.
The formula for calculating the distance between adjacent dark fringes is given as;
d sin θ = mλ
Where, d = the distance between the slit and the screen, θ = angle between the line drawn from the center of the slit to the dark fringe and the line drawn perpendicular to the screen, m = order of the dark fringeλ = wavelength of the light.
The angle between the central maximum and the first-order maximum, for a double-slit experiment, can be calculated as;
θ ≈ tan⁻¹ (y/L)
Therefore,θ = tan⁻¹ (y/L) -------------- (1)
For bright fringes m = 0; d sin θ = 0λ/(i.e sin θ = 0)
i.e θ = 0For dark fringes m = ± 1, ± 2, ± 3, .....
Therefore,
dsinθ = ± mλdsinθ = mλ
For the first-order dark fringe;
m = 1dsinθ = λ
Therefore,
d = λ/sinθ
Also, d = 10.0 μm = 10^-5 cmλ = 590 nm = 590 × 10^-7 cm
Using equation (1) above;
θ = tan⁻¹(y/L)sinθ = y/Ld = λ/sinθ∴ L = yd/λL = 10^-3 × 10^-5 cm/ 590 × 10^-7 cmL = 1.69 × 10^3 cm
For m = 1, dsinθ = λ∴ sinθ = λ/dsinθ = 590 × 10^-7 cm/10^-5 cm = 0.059cmi.e sinθ = 0.059∴ θ = sin^-1 (0.059)θ = 3.39°
If D is the distance between the screen and the slits, then the distance between the central bright fringe and the first bright fringe can be given as;
Dλ/dD = 169 × 10^3 cm
Total number of fringes that can be produced on the infinitely large screen is given as;
N = (2D/d) + 1N = (2 × 169 × 10^3 cm/10^-5 cm) + 1N = 3,38,000 + 1 = 3,38,001
Number of whole dark fringes produced on the infinitely large screen = (N - 1)/2 = (3,38,001 - 1)/2 = 169,000.5 ≈ 169,000
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The bearing of grids of an AB alignment is 100º 22', while the magnetic declination is 8º30' E. What are the true azimuth, magnetic azimuth, and grid azimuth of this alignment?
The true azimuth of the AB alignment is 91º 52' (east of north), the magnetic azimuth is 100º 22' (east of north), and the grid azimuth is 108º 52' (east of north).
To find the true azimuth, magnetic azimuth, and grid azimuth of the AB alignment, we need to consider the magnetic declination. The magnetic declination indicates the angle between true north and magnetic north at a specific location. In this case, the magnetic declination is 8º 30' E, which means that the magnetic north is 8º 30' east of the true north.
To calculate the true azimuth, we subtract the magnetic declination from the grid azimuth. The grid azimuth is given as 100º 22', so subtracting the magnetic declination of 8º 30' E gives us a true azimuth of 91º 52' (east of north).
The magnetic azimuth remains the same as the grid azimuth, which is 100º 22' (east of north).
The grid azimuth is calculated by adding the magnetic declination to the true azimuth. Since the magnetic declination is east, we add it to the true azimuth. Adding 8º 30' E to the true azimuth of 91º 52' gives us a grid azimuth of 108º 52' (east of north).
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What is 102 Fahrenheit fever in Celcius?
Answer:
102°F fever in Celsius is equivalent to 38.9°C.
. A book is moved once around the perimeter of a table of dimensions 2.00 m by 3.00 m. If the book ends up at its initial position
a) what is its displacement? 0
Answer:
10
Explanation:
displacement would be 10 because knowledge
PLS HELP
According to the theory of spontaneous generation, tadpoles were believed to arise form dead flesh. True or False.
A.
FALSE
B.
TRUE
"This was the idea that non-living objects can give rise to living organisms."
please please please hellpppppppp!!!!!!
Answer:
The Answer is A
Explanation:
A (1.03x10^2)-mA current is used to charge up a parallel plate capacitor. A large square piece of paper is placed between the plates and parallel to them so it sticks out on all sides. What is the value of the integral ∮B⃗ .ds⃗ around the perimeter of the paper? Express your result in T.m with three significant figures.
Since a 1.03 × 10² mA current is used to charge up the parallel plate capacitor and a large square piece of paper is placed between the plates and parallel to them so it sticks out on all sides, the value of ∫B.ds around the perimeter of the paper is 1.29 × 10⁻⁷ Tm
Ampere's LawThis shows the relationship between the magnetic field, B, the path of integration, ds and the current enclosed by the magnetic field, i.
Ampere's law is given mathematically as
∫B.ds = μ₀i where
B = magnetic field, ds = arc length of path of integration, μ₀ = permeability of free space = 4π × 10⁻⁷ Tm/A and i = current enclosed by the path of integration, ds.Given that for the large square piece of paper, the current used to charge the capacitor is
i = 1.03 × 10² mA = 1.03 × 10² × 10⁻³ A = 1.03 × 10⁻¹ A and ds = path length around the perimeter of the paperThe value of ∫B.ds around the perimeter of the paperSince ∫B.ds = μ₀i
Substituting the values of the variables into the equation, we have
∫B.ds = μ₀i
∫B.ds = 4π × 10⁻⁷ Tm/A × 1.03 × 10⁻¹ A
∫B.ds = 4.12π × 10⁻⁸ Tm
∫B.ds = 12.94 × 10⁻⁸ Tm
∫B.ds = 1.294 × 10⁻⁷ Tm
∫B.ds ≅ 1.29 × 10⁻⁷ Tm
So, the value of ∫B.ds around the perimeter of the paper is 1.29 × 10⁻⁷ Tm
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5. In which image below is the most work being wasted as heat?
A. Image A
B. Image B
C. Image C
D. Image d
Answer:
C
Explanation:
The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
What will be the speed of the rock?Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference. The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
Nuclear energy is a useful source of power but has disadvantages. The disadvantage of nuclear energy is it produces dangerous waste.
Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference
From the second equation of motion:
solving above we get:
t = 0s or t = 8.16s, t =0 seconds is neglected since it represents the initial position which is the same as the final position at t = 8.16s
So, the rock takes 8.16 seconds to return to the release point.
Therefore, The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
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would someone just answer this now?
There are many people in this country who are against the death penalty because they say it is unconstitutional. How might the death penalty be unconstitutional? What do you think?
Answer:
the death penalty inherently violates the constitutional ban against cruel and unusual punishment and the guarantees of due process of law and of equal protection under the law.
Which event occurs when an atom undergoes nuclear fusion?
OA. Its nucleus loses all its mass.
OB. Its nucleus combines with another nucleus.
C. Its nucleus breaks apart.
OD. Its nucleus absorbs energy.
Answer:According to the context, its nucleus breaks apart is an event that occurs when an atom undergoes nuclear fission.
Explanation:
what are erthpuaks and why do thay hapen
Answer:
earthquakes are violent ruptures that happen in the earth that causes a giant ravine and they happen when the plates of earth separate
A 22 g block of ice is cooled to −70 ◦C. It is added to 589 g of water in an 83 g copper calorimeter at a temperature of 21◦C. Find the final temperature. The specific heat of copper is 387 J/kg · ◦C and of ice is 2090 J/kg ·◦C . The latent heat of fusion of water is 3.33 × 105 J/kg and its specific heat is 4186 J/kg · ◦C . Answer in units of ◦C
Will most likely cause the formation of a Mountain
A. Divergent boundary
B. Convergent boundary
C. Transform boundary
Answer:
Convergent boundaries. When two plates collide and one is pushed over the other, forming a mountain.
L
What are the disadvantages of driverless cars? Check all that apply.
They always drive slower than surrounding traffic to avoid accidents.
They cannot tell the difference between people and other objects.
They will wait for crossing pedestrians even if signaled to keep driving.
They may unexpectedly drive off the road to avoid potential hazards.
They will not allow the human driver to take control while in motion.
If the unbalanced force is -20.0 N and the mass of the object is 3.75 kg, what is the acceleration of the the object while this force is acting?
Answer:
a=-5.3m/s2
Explanation:
F=-20N
m=3.75kg
a=?
F=am /:m
a=F/m
a=-20N/3.75kg
a=-5.3m/s2
a 1000 kg car is driving around a 100 m radius curve. the coefficient of static friction is 0.80 and the coefficient of kinetic friction is 0.60. determine the maximum speed that thee car can travel without slipping.
The maximum speed that the car can travel without slipping is 28 m/s.
What is the maximum speed of the car?For a car driving around a circular path not skid at maximum speed, then the centripetal force of the car must be equal to the static frictional force.
Fc = Fs
ma = μmg
a = μg
v²/r = μg
v² = rμg
v = √rμg
where;
v is the maximum speed of the carμ is the coefficient of static frictiong is acceleration due to gravityr is the radius of the circular pathv = √(100 x 0.8 x 9.8)
v = 28 m/s.
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0.19 mol of argon gas is admitted to an evacuated 70 cm3 container at 10 ∘ c. the gas then undergoes an isothermal expansion to a volume of 200 cm3. What is the final pressure of the gas?
In 0.19 mol of argon gas is admitted to an evacuated 70 cm3 container at 10 ∘ c. the gas then undergoes an isotherm-al expansion to a volume of 200 cm3. The final pressure of the gas after the isotherm al expansion is approximately 2.204 ATM.
To determine the final pressure of a gas after an isotherm- al expansion, we can utilize the ideal gas law, which establishes a relationship between pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T).
Initially, we convert the given initial temperature from Celsius to Kelvin by adding 273.15, resulting in T1 = 10 °C + 273.15 = 283.15 K. Since the expansion is isotherm-al, the final temperature remains the same as the initial temperature.
Next, we employ the ideal gas law equation P1V1 = nRT1 to compute the initial pressure (P1), where P1 = (nRT1) / V1. By substituting the known values, we obtain:
P1 = (0.19 mol * 0.0821 ATM/(mol.K) * 283.15 K) / 0.07 L ≈ 6.32 ATM.
To find the final pressure (P2), we employ the equation P1V1 = P2V2, considering that the gas remains at the same temperature. This can be simplified to:
P1V1 = P2V2.
Substituting the given values, we have:
6.32 ATM * 0.07 L = P2 * 0.2 L.
Simplifying further:
P2 = (6.32 ATM * 0.07 L) / 0.2 L ≈ 2.204 ATM.
Therefore, the final pressure of the gas after the isotherm al expansion is approximately 2.204 ATM.
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Which describes the greatest amount of ice cream?
a 3-N bowl of ice cream on the moon a
3-N bowl of ice cream on Jupiter a
3-N bowl of ice cream on Earth's surface a
3-N bowl at the bottom of an Earth ocean
We must know that the gravity acceleration on Jupyter is g = 24.79 m/s² , on the Earth g = 9.8 m/s² and on the moon 1.62 m/s².
The weigh of an object is given by:
P = mg
Solving for m:
m = P/g
We see that for the same weight, if gravity is less, then the amount of mass is greater, because they are inversely proportional. So we conclude that the answer is:
a 3-N bowl of ice cream on the moonThe energy a sled has when you pull it back up a hill is best described as
a.) chemical energy
b.) electromagnetic energy
c.) electrical energy
d.) mechanical energy
ANSWER NOW!!!! IF CAN
use following ex problem to explain conservation of momentum including the concept of momentum.
A 100kg man is on a 10kg scooter, when the scooter hits a rock. The scooter stops and the man flies forward. If the man was traveling on the scooter at 5 m/s before he hit the rock how fast does the man fly forward after hitting the rock?
- show work/ (get mans velocity after it 5.5 m/s)
10. A cat walking at 0.25 m/s sees a mouse and accelerates uniformly at 0.40 m/s
for 3.0 s. What is the cat's displacement during this time?
Answer:
The displcament is 2.55m
Explanation:
step one:
Given that the intial speed is
u= 0.25 m/s
and acceleration is
a= 0.40 m/s^2
and time t= 3seconds
step two:
Applying the formula
s=ut+1/2at^2
s= 0.25*3+ 1/2*0.4*3^3
s= 0.75+3.6/2
s= 0.75+1.8
s=2.55 m
The displacement is 2.55m
Which two types of energy does an apple falling to the ground have?
Answer: kinetic energy and potentoal
Explanation: dhsjsjdne
I need help with the 1st and the 3rd one plzzzzzzzzzzzzz
Answer for the first one is 2. The answer for the 3rd one is 8
Who conducted the experiment that showed that atoms were mostly made up of empty space?.
Rutherford conducted the experiment that showed that atoms were mostly made up of empty space.
Rutherford done an experiment in which he allowed alpha particle to bombard on gold foil . Which shows that the atom is mostly empty space with a tiny, dense, positively-charged nucleus. Based on these results, Rutherford proposed the nuclear model of the atom.
The observations made by Rutherford led him to conclude that: A major fraction of the α-particles bombarded towards the gold sheet passed through the sheet without any deflection, and hence most of the space in an atom is empty.
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Plucking on a tight metal wire causes it to vibrate. What type of energy would that produce?
A. Light
B. Chemical
C. Sound
D. Thermal
Question 2: A burning candle exhibits what types of energy?
A Light and Thermal Energy
B Light Energy only
C Sound and Light Energy
DTheraml Energy only
IM CONFUSEDDDD!
i have to turn in this project for an online balloon car thing, can someone do the calculating at least please!
To design a race car with a balloon engine for the best possible performance. must take into consideration Newton's laws of motion. the formula Velocity (speed) = Distance / Time (v = d / t).
What was the average velocity of your balloon car?3.753968254 metres per second was the car's average speed.According to the law of conservation of energy, as you fill up the balloon more, it stores more potential energy, which is then transformed into more kinetic energy, causing the balloon to expand faster and the car to move forward.Using f=ma, calculate thrust.By averaging the positive acceleration readings or measuring the time it takes to reach maximum velocity, average acceleration may be obtained.The balloon will travel with greater force and accelerate more quickly as compressed air content increases. The force of the balloon is reduced and its speed is slowed down if the number of pumps is reduced (air pressure is decreased).The Complete Question.
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A parachute on a racing dragster opens and changes the speed of the car from 93 m/s to 45 m/s in a period of 5.3 seconds. What is the acceleration of the dragster?
Answer:
\(-9.06\:\mathrm{m/s^2}\)
Explanation:
We can use the following kinematics equation to solve for acceleration:
\(v_f=v_f+at\).
Solving for \(a\):
\(45=93+5.3a,\\-48=5.3a,\\a\approx \boxed{-9.06\mathrm{m/s^2}}\)
*Note: Since acceleration is a vector quantity, it has both magnitude and direction. The negative sign implies that the acceleration is in the opposite direction of the racing dragster's movement.
what plant produces energy
Explanation:
Well it depends on what type of energy all plants produce energy for them to survive but if its a certain energy your looking for make sure to put it in you quesion
Roads are often designed with parabolic surfaces to allow rain to drain off. A particular road is 32 feet wide and 0.4 foot higher in the center than it is on the sides (a) Write an equation of the parabola with its vertex at the origin that models the road surface.(b) How far from the center of the road is the road surface 0.22 foot lower than the center?
a. The equation of the parabola that models the road surface is y = -0.0015625x² + 0.4
b. The road surface is 19.93 feet away from the center of the road where it is 0.22 foot lower.
How do we calculate?(a)
We apply the general form of a parabola equation:
y = ax²
y = ax²
At the center of the road, the y-coordinate is 0.4.
The vertex is at the origin, the coordinates of the center are (0, 0.4). Plugging these values into the equation, we get:
0.4 = a * 0²
0.4 = a * 0
0.4 = 0
We will modify the equation to accommodate the information.
y = ax² + c
The constant "c" represents the vertical shift of the parabola. In this case, since the center of the road is 0.4 feet higher, we have:
y = ax² + 0.4
0 = a * 16² + 0.4
0 = 256a + 0.4
256a = -0.4
a = -0.4 / 256
a = -0.0015625
(b)
-0.22 = -0.0015625x² + 0.4
-0.0015625x² = -0.22 - 0.4
-0.0015625x² = -0.62
x² = 397.12
x = √397.12
x = 19.93 feet
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Find the field strength. Information given
Weight: 0, point, 96, N,0. 96N
Mass: 3, point, 3, g,3. 3g
Field strength is 0.03234 N/kg. The formula to determine the field strength is given by:
F = mg Here, F is the field strength, m is the mass, and g is the gravitational field strength.
Substituting the values given: Weight = 0.96 N Mass = 3.3 g = 0.0033 kg = 9.8 m/s² Therefore, F = mg = 0.0033 kg × 9.8 m/s² = 0.03234 N the field strength is the gravitational force acting on a unit mass. It is measured in newtons per kilogram. The field strength is an expression of the strength of a gravitational field. In this case, the mass of the object is 3.3 g, which can be converted to kilograms by dividing by 1000.
The weight of the object is given as 0.96 N. Using the formula
F=mg, where m is the mass and g is the gravitational field strength, we can calculate the field strength as 0.03234 N/kg.
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