how much energy is released when 200 g of liquid water at 37 degrees celsius is cooled and frozen into ice at 0 degrees celsius

X and Y are two things that travel in the same direction. The mass of the things is the same. 5.0 m/s is the velocity of object x as it moves to the right. The velocity of object y to the left is 3.0 m/s. Objects x and y collide and adhere to one another. Following their collision, they both move at a speed of 1.0 m/s to the right.

Their velocity after colliding is 1.0 m / s to the right.

What is the velocity during the collision?

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The interference fringes from a two-slit experiment immersed in water will be closer together than when it is operated in air because the wavelength of light in water is shorter than its wavelength in air.

This is due to the difference in refractive index between water and air, which causes light to slow down and bend when it enters water.

The refractive index of a medium is a measure of how much the speed of light is reduced in that medium compared to its speed in a vacuum. The refractive index of water is higher than the refractive index of air, which means that light travels more slowly in water than in air. Since the speed of light is reduced in water, the wavelength of light in water is also reduced according to the relation:

λ(water) = λ(air) / n

where λ(water) and λ(air) are the wavelengths of light in water and air, respectively, and n is the refractive index of water.

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As fair weather approaches, the air pressure generally increases. Fair weather is associated with high-pressure systems, where air descends and becomes more compressed, resulting in higher atmospheric pressure. This increase in air pressure indicates stable weather conditions with clear skies and relatively calm winds.

There is typically a rise in air pressure. Fair weather is associated with high-pressure systems, where air descends and spreads outwards, leading to compression and an increase in atmospheric pressure. This rise in air pressure indicates stable weather conditions with clear skies, minimal cloud cover, and generally calm winds. The higher air pressure inhibits the formation of clouds and precipitation, creating a favorable environment for pleasant and sunny weather. Meteorologists often monitor changes in air pressure as an indicator of approaching fair weather systems.

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Answer:

Final velocity = 19 m/s

Explanation:

Initial velocity (u) = 4 m/s

Acceleration (a) = 0.5 m/s²

Time (t) = 30 s

Final velocity (v) = ?

In this question, you must use the formula:

v = u + at

Substitute the values into the formula.

v = 4 + (0.5 × 30)

v = 4 + 15

v = 19 m/s

Answer:

may be answer is 1000 HZ

Explanation:

i think this is the answer

False. The relative humidity will decrease if the mixing ratio drops and the temperature remains unchanged.

Relative humidity is the ratio of the amount of water vapor present in the air to the maximum amount the air can hold at a given temperature, so if the amount of water vapor decreases (due to lower mixing ratio), the relative humidity decreases unless the temperature also decreases.

False. If the temperature remains unchanged and the mixing ratio drops, the relative humidity will decrease. This is because relative humidity is the ratio of the actual amount of water vapor in the air (mixing ratio) to the maximum amount of water vapor the air can hold at a specific temperature. If the mixing ratio decreases while temperature stays constant, the relative humidity will be lower.

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The new velocity of the object after the event will be 7.99 m/s by using formula of Kinetic Energy.

The initial velocity of the object = 11.2 m

The given mass of the object = 50 kg

Energy transferred after collision of the two objects as Work = 1539 J

We need to find the final velocity of the object.

We will start by deriving the energy of the moving object.

Kinetic Energy = (mv²)/2

Kinetic Energy = (50 * 11.2 * 11.2)/2

Kinetic Energy = 3136 J

We now know the initial Kinetic Energy and the amount of energy that was transferred. Now, we need to find the resulting energy.

Final energy = initial kinetic energy - ending kinetic energy

Final energy = 3136 - 1539

Final energy = 1597 J

Now, Kinetic Energy = (mv²)/2

1597 =  (50 * v²)/2

3194 = 50 * v²

v² = 63.88

v = 7.99 m/s

Therefore, the new velocity after the event is 7.99 m/s

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The distance covered by the boy before his little brother see him is 45 m.

The distance that can be covered by a boy travelling at 3 m/s for 15 seconds is calculated using the formula that relates speed, distance and time.

The formula relating distance, speed, and time is as follows;

The distance travelled can be obtained by a rearrangement of the equation above:

Considering the data provided;

The speed of the boy is 3 m/s

time required is 15 s

Distance covered by the boy = 3 m/s * 15 s

Distance covered by the boy = 45 m

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Answer: A. An ice hockey player picks up a trophy as he slides past it

Explanation:

A PE X

The statement that best describes a perfectly inelastic collision is

C. A surfer falls off of his surfboard when a wave hits him.

A collision is the interaction between two bodies in such a way that the momentum and velocity of one body gets changed due to the presence of other body. There are three types of collision-

1. Elastic collision

2. Inelastic collision

3. Perfectly inelastic collision.

In all types of collision , the momentum of the system before collision and after collision always remains same or we can say that momentum is conserved in collisions

An elastic collision is the one in which kinetic energy is also conserved and coefficient of restitution is one. Both the bodies move separately with different velocities after elastic collision.

In inelastic collision  there is a loss of kinetic energy and coefficient of restitution is less than one.

In perfectly inelastic collision there is maximum loss of kinetic energy and coefficient of restitution is zero. Both the bodies stick together after collision and move with same velocity

Coefficient of restitution is the  ratio of  relative velocity of separation after collision to relative velocity of approach before collision.

A surfer falls of his surfboard when a wave hits him is an example of perfectly inelastic collision because in this when water hits the surfers he falls of and sticks to the water , and will also now move with the velocity of water .

So  when the surfer falls off his surfboard when a wave hits him is perfectly inelastic collision.

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Transformer-Rectifier units for CAC-A (Constant Current Arc Welding) should have a minimum of 60% duty cycle, with at least three-phase units.

Constant Current Arc Welding is also known as "stick welding." The acronym CAC stands for "constant current," which means the power source must be able to produce a constant output current, regardless of the resistance of the welding arc.

To create the appropriate current for the welding, a transformer-rectifier is used. A transformer-rectifier unit comprises of a transformer and a rectifier. The transformer converts high voltage, low current AC electricity from the power source to low voltage, high current AC electricity, which is then supplied to the rectifier. The rectifier transforms the AC input into a direct current (DC) output that the welding equipment requires.

The duty cycle is defined as the amount of time during which the machine can operate without overheating. The transformer-rectifier should have a 60% duty cycle or higher because welding generates a lot of heat and needs a lot of power. If the duty cycle is too low, the unit will shut down too often and be unable to perform effectively.

A 60% duty cycle ensures that the welding machine can run continuously for six minutes out of every ten minutes. It is recommended that you choose a transformer-rectifier with a duty cycle that meets your requirements, as a higher duty cycle would allow you to weld for longer periods of time before requiring a cool down period.

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To calculate the intensity of the light source for the viewer after being reflected at point (0, 0, 0), we can use the inverse square law for light intensity.

The formula for the intensity of light at a certain distance from the source is given by:

I = I₀ / d²

Where:

I is the intensity of light at a certain distance

I₀ is the initial intensity of the light source

d is the distance from the light source to the point of observation

First, let's calculate the distance from the light source to the point of reflection (0, 0, 0). Using the distance formula, we have:

d₁ = √[(-4 - 0)² + (3 - 0)² + (0 - 0)²]

= √[16 + 9 + 0]

= √25

= 5

Next, let's calculate the distance from the point of reflection (0, 0, 0) to the viewer (2, 2, 2):

d₂ = √[(2 - 0)² + (2 - 0)² + (2 - 0)²]

= √[4 + 4 + 4]

= √12

= 2√3

Now, we can calculate the intensity of the light for the viewer after reflection using the inverse square law:

I_viewer = I₀ / (d₁ + d₂)²

= 1000 / (5 + 2√3)²

To simplify the expression, we can rationalize the denominator:

I_viewer = 1000 / (5 + 2√3)²

= 1000 / (25 + 20√3 + 12)

= 1000 / 37 + 20√3

Therefore, the intensity of the light source for the viewer, after being reflected at point (0, 0, 0), is approximately 27.03 lux.

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The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

For instance, 50 km/hr west denotes the velocity of a car whereas 50 km/hr (31 mph) denotes the speed at which it is moving down a route.

The average speed of an object is determined by dividing the distance traveled by the amount of time it takes the object to reach the distance.

Therefore, The total travelled distance is • Speed, time and distance is one of the most common and important topics in the Mathematics or Quant section.

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The average velocity of the car would be equal to its constant velocity, which is equal to the speed of the car. In other words, the average velocity of the car would be equal to the distance traveled by the car divided by the time taken to travel that distance, in the same direction as the motion of the car.

If a car is moving on a straight road at a constant speed in a single direction, then the average velocity of the car would be equal to its constant velocity. Velocity is a vector quantity that includes both the magnitude and direction of an object's motion. When an object moves at a constant speed in a straight line, its velocity remains constant, since there is no change in direction or speed.

The average velocity of an object is defined as the total displacement of the object divided by the total time taken. In the case of a car moving at a constant speed in a straight line, the displacement of the car over any time interval would be equal to the distance traveled in that time interval in the same direction. Since the car is moving in a straight line at a constant speed, the distance traveled and the displacement of the car would be the same.

Therefore, the average velocity of the car would be equal to its constant velocity, which is equal to the speed of the car. In other words, the average velocity of the car would be equal to the distance traveled by the car divided by the time taken to travel that distance, in the same direction as the motion of the car.

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The duty cycle of a square wave with a frequency of 10 Hz and a positive pulse width (i.e., high time) of 0.03 seconds is 30%.

The duty cycle is defined as the percentage of time the waveform spends at the high voltage level. To calculate the duty cycle of a square wave, divide the high time by the total period, then multiply by 100. The duty cycle equation is as follows:Duty cycle (%) = (High time / Period) * 100Where,High time is the time duration when the waveform is at a high level.Period is the time duration between the beginning of two consecutive high levels. Frequency is the inverse of the period.The high time is 0.03 seconds, and the period is 1 / 10 = 0.1 seconds, using the frequency given. As a result, the duty cycle can be calculated:Duty cycle = (0.03 / 0.1) * 100 = 30%Thus, the duty cycle of a square wave with a frequency of 10 Hz and a positive pulse width (i.e., high time) of 0.03 seconds is 30%.

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Given that the number of hailstones is n = 562

The mass of hailstone is m = 2 g = 0.002 kg

The speed of hailstone is v = 5.8 m/s

The time taken will be t = 92 s

The angle is

We have to calculate the force.

The force can be calculated by the formula

Substituting the values, the force will be

Answer:

atomic number

Explanation:

In the modern periodic table, the elements are listed in order of increasing atomic number. The atomic number is the number of protons in the nucleus of an atom. The number of protons define the identity of an element (i.e., an element with 6 protons is a carbon atom, no matter how many neutrons may be present).

*in the question you have written fives i think it has to be gives .*

please make my answer as brainelist

Answer:

\(15\:\mathrm{J}\)

Explanation:

The potential energy of an object is given by \(PE=mgh\).

Recall that the weight of an object is equal to the force of gravity on the object. From this, we can set up the following equation and solve for the mass of the object:

\(F=mg,\\5=mg,\\m=\frac{5}{9.81}\approx 0.51\:\mathrm{kg}\)

Now we can plug in values to \(PE=mgh\) and solve:

\(PE=0.51\cdot9.81\cdot3=\fbox{$15\:\mathrm{J}$}\).

Answer:

The potential energy of the body is 15J.

Explanation:

The energy possessed to a body due to position is called Potential energy.

U=mgh

U=mgh

U=5×3=15J

Hence, the potential energy of the body is 15J.

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Answer:

Total resistance in parallel is 1.2703136679494.

Total resistance in series is 155.Total resistance in series is 155.

Explanation:

Answer:

P = I V = I^2 R

R = 150 + 300 = 450 Ω

I = 150 / 450 = .333 amps

P(150) = .333^2 * 150 = 16.7 W

Explanation:

The slum children in an elementary school look pathetic. Their hairs are uncombed. They look pale and shabby. They are undernourished and diseased

Cp=88.15J/mol.K is the molar heat capacity of the substance T is the temperature of the substance in kelvin ΔH=62.626kJ is the enthalpy change of the substance ΔSTe=141.32J/mol.

K is the change in entropy of the substance. The formula for calculating the equilibrium temperature for equation (1) can be given as:ΔH=ΔSTe*TFor the given values of ΔH and ΔSTe, we can calculate the value of temperature T as

:T=ΔH/ΔSTeT=62.626kJ/141.32J/mol.K = 442.87K = 169.72°C.

The calculated temperature is in degrees Celsius. We need to convert this to Kelvin by adding 273.15 to it.

Therefore,T=169.72+273.15 = 442.87K = 140°C

The molar heat capacity Cp is the amount of heat required to raise the temperature of one mole of a substance by one kelvin. The value of Cp depends on the nature of the substance and can be measured experimentally. In this case, Cp=88.15J/mol.K for the substance is given.The temperature of the substance is denoted by T and is given in kelvin.

The enthalpy change of the substance is denoted by ΔH and is given as 62.626kJ. Enthalpy is a measure of the heat released or absorbed during a chemical reaction. The change in entropy of the substance is denoted by ΔSTe and is given as 141.32J/mol.K. Entropy is a measure of the disorder of a system.

The formula for calculating the equilibrium temperature for equation (1) can be given as:ΔH=ΔSTe*T.

This formula relates the enthalpy change of the substance to the change in entropy of the substance and the temperature at which the reaction occurs.

The equilibrium temperature is the temperature at which the forward and reverse reactions occur at the same rate. This is the temperature at which the system is in equilibrium.

If the temperature is below the equilibrium temperature, the forward reaction is favored and if the temperature is above the equilibrium temperature, the reverse reaction is favored.

The calculated temperature is in degrees Celsius. We need to convert this to Kelvin by adding 273.15 to it. Therefore,T=169.72+273.15 = 442.87K = 140°C

Therefore, the equilibrium temperature for equation (1) is 140°C or 442.87K. This temperature is the temperature at which the forward and reverse reactions occur at the same rate.

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To calculate your friend's approximate volume, we will use the formula for buoyancy, which states that the buoyant force (F_b) equals the weight of the displaced fluid (in this case, fresh water). Since your friend can barely float, the buoyant force equals her weight. The buoyant force is given by the formula F_b = ρ * V * g, where ρ is the density of the fluid (fresh water), V is the volume, and g is the acceleration due to gravity.

Given the mass of your friend (90 kg) and the density of fresh water (approximately 1000 kg/m³), we can find the volume (V) as follows:
1. Calculate the weight of your friend: W = m * g = 90 kg * 9.81 m/s² ≈ 883 N
2. Set the buoyant force equal to the weight: ρ * V * g = W
3. Solve for the volume: V = W / (ρ * g) = 883 N / (1000 kg/m³ * 9.81 m/s²)
Using the given information and performing the calculation, we find the approximate volume:
V ≈ 0.09 m³
Expressing the answer to two significant figures and including the appropriate units, the approximate volume of your friend is 0.090 m³.

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It takes a 900 kg racing car 12.3 s to travel at a uniform speed around a circular racetrack of radius 90.0 m therefore the centripetal force acting on the car is 4336617.61N and the force which provides it is gravity.

This is referred to as a type of force that acts on a body moving in a circular path and is directed towards the centre around which the body is moving.

Velocity = Displacement/time

               = 90m/12.3s = 7.317m/s

Formula for centripetal force =mv²r.

                    = 900kg ×  7.317² × 90 = 4336617.61N

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Answer:

By Gauss' Law the sphere will appear externally as if all of the charge were concentrated at the center of the sphere.

E = K Q / r^2 = K Q / .528^2

Q = 1710 * .528^2 / 9.00E9 Coulombs

Q = 5.30E-8 Coulombs on sphere

V = 4/3 π R^3 = 4/3 π * .384^3 = .237 m^3

ρ = Q / V = 5.30E-8 / .237 = 2.23E-7 C/m^3

At .223 from center Q = 4/3 π .223^3 * ρ  (charge outside this radius will not affect electric field outside .223 m)

Q = 2.23E-7 * 4/3 * π * .223^3 = 1.04E-8 Coulombs

E = 9.00E9 * 1.04E-8 / .223^2 = 1880 N/C