How much magnification can a 5 diopter lens provide for a normal, relaxed eye?

Answers

Answer 1

A magnification provided by 5 diopter lens can of 2.5x for a normal, relaxed eye.

The magnification provided by a lens is given by the formula:

m = 1 + d/f

where m is the magnification, d is the distance between the lens and the object, and f is the focal length of the lens.

For a 5 diopter lens, the focal length f is given by

f = 1/diopter = 1/5 m⁻¹ = 0.2 m

For a normal relaxed eye, the near point is at a distance of 25 cm, or 0.25 m. Therefore, the distance between the lens and the object is

d = 0.25 m

Plugging these values into the magnification formula, we get

m = 1 + d/f

m = 1 + 0.25/0.2

m = 2.25

Therefore, a 5 diopter lens can provide a magnification of 2.25x for a normal, relaxed eye.

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Related Questions

Which of the following is NOT a negative effect of the way we use science? A. Climate Change B. Pollution C. Overuse of resources D. Damage to the sun

Answers

Answer:

D

Explanation:

Damage to the sun is not a negative effect of the way we use science because we can't affect the sun due to its long distance from us.

How we negatively affected environment with the use of science?

Humans negatively affected environment by using science because with the help of science we made new technologies which leads to Climate Change, Pollution and Overuse of resources.

So we can conclude that option D is the right answer.

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A 188 W motor will lift a load at a rate of 0.065 m/s. How heavy of a load can the motor
lift at this rate?

Answers

Answer:

2892.31 N

Explanation:

Applying,

P = F×v................ Equation 1

Where P = power of the motor, F = Weight of the load the motor can lift, v = velocity

make F the subject of the equation

F = P/v.............. Equation 2

Given: P = 188 W, v = 0.065 m/s

Substitute into eequation 2

F = 188/0.065

F = 2892.31 N

Hence the weight of the load is 2892.31 N

HURRY PLEASE?!?!????
What factors affect the speed of a wave? Check all that apply.

the amplitude of the wave
the energy of the wave
the temperature of the medium
the type of wave
the type of medium

Answers

Explanation:

wave is a disturbance that carries energy from one particle to another particle. The speed depends on:

1. The type of medium

2. The temperature of the medium

3. The energy of the wave

4. The amplitude of the wave

Answer:

i think the last 3

Explanation:

A generator is known to have 30V of potential difference with a charge of 8.5C. What is the energy produced by the generator?

Answers

Answer:

255J

Explanation:

Given parameters:

Potential difference  = 30V

Charge  = 8.5C

Unknown:

Energy produced by the generation = ?

Solution:

The energy produced by the generator can be derived using the expression below;

 Energy = qV

q is the quantity of charge

V is the potential difference

          Insert the parameters and solve;

  Energy  = 8.5 x 30  = 255J

why can't you run from momentum?

Answers

Two kids walk through the woods discussing momentum. I mean, who wouldn’t?
Okay, fine. It’s a basic introduction to the concept of momentum.

The moist bread becomes mouldy after a few days when it is left in a container with a cover. Which of the following conditions favour the growth of the fungus?

Answers

Answer: Moisture and food (bread)

Explanation:

Mould grows best in humid, damp air/wet conditions.

Since the bread is moist it will provide humidity for the mould as well as food.

A container with a cover would not be a favoring condition as mould needs oxygen to grow and survive.

Use the definition of impulse to find the magnitude of the impulse J Con imparted to sphere B by sphere C. Remember that impulse is a vector.

Answers

the impulse J imparted to sphere B by sphere C is:

J = mB*Δv

J = mB*[VBo - (mBVBi + 2mCVCi - mCVCo) / (mB + mC)]

Find the impulse from C to B

To find the impulse J imparted to sphere B by sphere C, we need to know the change in momentum of sphere B due to the collision with sphere C. The impulse J is defined as:

J = Δp = mΔv

where Δp is the change in momentum, m is the mass of sphere B, and Δv is the change in velocity of sphere B.

Since we know that the collision is elastic, we can use the conservation of momentum and energy principles:

\(mBVBi + mCVCi = mBVBo + mCVCo (1) --\)conservation of momentum

\(1/2mBVBi^2 + 1/2mCVCi^2 = 1/2mBVBo^2 + 1/2mCVCo^2 (2) --\)conservation of energy

where VB and VC are the velocities of sphere B and C before and after the collision, respectively, and the subscripts "i" and "o" refer to the initial and final states.

Solving equations (1) and (2) simultaneously for VB and VC, we get:

\(VB = (mBVBi + 2mCVCi - mCVCo) / (mB + mC) --\)final velocity of sphere B

\(VC = (mCVCo + 2mBVBi - mBVBo) / (mB + mC) --\)final velocity of sphere C

Therefore, the change in velocity of sphere B is:

\(Δv = VBo - VB\)

\(Δv = VBo - [(mBVBi + 2mCVCi - mCVCo) / (mB + mC)]\)

And the impulse J imparted to sphere B by sphere C is:

\(J = mB*Δv\)

\(J = mB*[VBo - (mBVBi + 2mCVCi - mCVCo) / (mB + mC)]\)

This is the magnitude of the impulse J imparted to sphere B by sphere C.

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if peter expends 2,000 calories running a mile in one hour and samantha burns 1000 calories riding a bike in thirty minutes. who exerted the greatest amount of power?

Answers

Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes.

In order to calculate the power expended by Peter and Samantha, we need to use the formula:

Power = Work / Time

where Work is the amount of energy expended and Time is the duration of the activity.

For Peter, the Work done is:

Work = 2,000 calories / 1 hour = 2,000 Joules

For Samantha, the Work done is:

Work = 1,000 calories / 30 minutes = 33.33 Joules

Therefore, Peter expended more power than Samantha, as he expended 2,000 Joules of energy in one hour, while Samantha expended only 33.33 Joules of energy in thirty minutes. So, Peter exerted the greatest amount of power.  

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calculate the number of water molecules formed in 0.675 grams

Answers

The number of water molecules formed in 0.675g is 0.22 x 10²³.

How to calculate no of water molecules?

We calculate the number of molecules by using relation of Avogadro number as follows:

No. of molecules = 1 mole of substance = n (Avogadro number) = molecular weight

So, molecular weight = n

Molecular weight of water is 18g

Value of n is 6.022 x 10²³

so, 18g of water has 6.022 x 10²³ molecules

 18g  ≡  6.022 x 10²³

1g ≡ 6.022 x 10²³/18

0.675g ≡ (6.022 x 10²³/18) x 0.675

  = 0.22 x 10²³ molecules

So,   0.675g of water has 0.22 x 10²³ molecules.

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Un hombre parado en el techo de un edificio, tira una bola verticalmente hacia arriba con una velocidad de 12m/s, la bola llega al suelo en 4s. ¿que altura tiene el edificio ?

Answers

Respuesta:

24m

Explicación:

Según la ecuación de movimiento

v = u + en

Dado

Velocidad final v = 12 m / s

velocidad inicial u = 0 m / s

tiempo t = 4s

Sustituir

12 = 0 + 4a

a = 12/4

a = 3 m / s²

Lo siguiente es obtener la distancia;

S = ut + 1 / 2at²

S = 0 (4) + 1/2 (3) (4) ²

S = 3 * 16/2

S = 48/2

S = 24 m

Por lo tanto, la distancia requerida es de 24 m.

In a large tank of liquid, the hydrostatic pressure at a given depth is a function of:
a. depth.
b. surface area.
c. liquid density.
d. Choices a and c are both valid.

Answers

The hydrostatic pressure at a given depth in a large tank of liquid is a function of depth and liquid density. Therefore, choices a and c are both valid.

The hydrostatic pressure at a given depth in a liquid is determined by the weight of the liquid above that depth.

As the depth increases, the weight of the liquid above it increases, resulting in an increase in pressure.

The pressure at a given depth can be calculated using the following formula:

P = ρgh

where P is the pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the depth.

As we can see from the formula, the pressure is directly proportional to the depth and the density of the liquid. The surface area of the tank does not affect the hydrostatic pressure at a given depth.

Therefore, choices a and c are both valid as the hydrostatic pressure at a given depth is a function of depth and liquid density.
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4) A standing wave is formed in a string as pictured in problem 1. If a standing wave with two segments is formed when the frequency is 60 Hz, and the hanging mass and string length are kept constant, what frequency would be required to produce a standing wave with 7 segments?

Answers

The frequency needed to create a standing wave with seven segments is 120 Hz, which is double the frequency needed to create a standing wave with two segments.

In a standing wave on a string, the number of segments (also known as nodes) is related to the wavelength and the length of the string. The frequency of the standing wave is inversely proportional to the wavelength. Therefore, we can use this relationship to determine the frequency required to produce a standing wave with 7 segments.

The general formula for the relationship between the frequency (f), wavelength (λ), and the speed of the wave (v) is:

v = f * λ

Since we are keeping the hanging mass and string length constant, the speed of the wave remains the same for both standing waves. Therefore, we can equate the two expressions:

f₁ * λ₁ = f₂ * λ₂

Where:

f₁ = frequency for the standing wave with 2 segments

λ₁ = wavelength for the standing wave with 2 segments

f₂ = frequency for the standing wave with 7 segments

λ₂ = wavelength for the standing wave with 7 segments

The number of segments (nodes) is equal to the number of half-wavelengths in the string. In the standing wave with 2 segments, we have one complete wavelength, while in the standing wave with 7 segments, we have six complete wavelengths.

Therefore, the relationship between the wavelengths for the two standing waves is:

λ₁ = 2 * λ₂

We can substitute this relationship into the equation:

f₁ * (2 * λ₂) = f₂ * λ₂

Simplifying the equation:

2 * f₁ = f₂

Since we are given that f₁ = 60 Hz, we can substitute this value:

2 * 60 Hz = f₂

f₂ = 120 Hz

Therefore, to produce a standing wave with 7 segments, the required frequency is 120 Hz.

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PLEASE, PLEASE ANSWER ASAP!! I'm going to ask again, PLEASE someone answer!!!! What are 3 types of forces acting on your marshmallow (or other flying object) while it is in the air? PLEASE HELP!!

Answers

I am not entirely sure but I think it is:

Gravitation / Weight ForceDrag forceLift force

After being pushed and released, a 50 kg crate slides across a factory floor. Friction on the sliding crate is 200 N, what is the crates acceleration ?

Answers

F = ma
200 = 50 * a
4 = a

Therefore acceleration is 4ms^-2

Nuclei decay from a more stable form to a less stable form.Question 9 options:TrueFalse

Answers

ANSWER

False.

EXPLANATION

In radioactive decay (or nuclei decay), an unstable nucleus emits radiation into a nucleus that is table and has less energy and a lower mass.

Therefore, nuclei decay from a less stable form to a more stable form.

The answer is false.

what is a work and energy for project​

Answers

Answer:

Terminology: Energy - Is the ability to do work. Work - Is the measure of energy transferred when a force acting over a distance. Power - Is the rate at which energy is transferred, used, or transformed

Explanation:

Thank you

An Object with a mass o 5.13kg placed on top of a spring compresses it by 0.25m (a) what is the force constant of the spring (b) How high will this object go when the spring releases its energy?

Answers

The force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

The spring constant is the force needed to stretch or compress a spring, divided by the compressive or expansive distance. It's used to determine stability or instability in the spring, and therefore the system it's intended for. we know,

F = kx

Therefore,

k = F/x

We also know that the force being exerted on the spring is equal to the mass of the object. Hence, F = mg = 5.13 * 9.8 N = 50.174 N and we know compression due to the mass is 0.25m. Therefore,

K = 50.174/0.25 N/m

K = 200.696 N/m

Therefore, The Spring Constant is 200.696 N/m

On release, the spring potential energy gets converted to kinetic energy. Hence, on release, the height attained by the object is given by:

h = \(1/2 kx^{2}\)

We know that k=200.696 N/m and x=0.25 m. Therefore the height is:

h = \(1/2 (200.696 N/m)(0.25 m)^{2}\)

h = 2.5087 m

Therefore, the force constant of the spring is 200.696 N/m & The height the object achieves when the spring releases its energy is 2.5087 m

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A 2500kg automobile develops 30kW of power to drive with a constant velocity of 90km/h on a level ground. What power must it develop to drive up a 15 degree hill with the same velocity.

Answers

Answer:

the power developed by the automobile is 7,764.57 W.

Explanation:

Given;

mass of the automobile, m = 2500 kg

initial power developed by the automobile, P₁ = 30 kW = 30,000 W

initial speed of the automobile, v₁ = 90 km/h = 25 m/s

inclination of the hill, θ = 15⁰

second speed of the automobile, v₂ = v₁Sinθ

The power developed by the automobile is calculated as;

P = Fv

\(F = \frac{P_1}{V_1} = \frac{P_2}{V_2} \\\\P_2 = \frac{P_1V_2}{V_1} \\\\P_2 = \frac{30,000 \ W \ \times 25Sin(15^0)}{25} \\\\P_2 = 30,000 \ \times sin(15^0)\\\\P_2 = 7,764.57 \ W\\\\\)

Therefore, the power developed by the automobile is 7,764.57 W.

What value of resistor R gives the circuit in the figure a time constant of 22 μs ?

Answers

The value of resistor R that gives the circuit in the figure a time constant of 22 μs is 220 Ω.

The circuit that is in the figure is shown below:Given that time constant (RC) = 22 μs. To find the value of resistor R, we need to use the formula for the time constant:

RC = τ, where R is the resistance and C is the capacitance of the circuit.

Rearranging the above formula, we get:R = τ / C

Where τ is the time constant and C is the capacitance of the circuit.

From the figure, the capacitance is given as 0.1 μF

.Substituting the values of τ and C in the above formula, we get:

R = (22 × 10⁻⁶ s) / (0.1 × 10⁻⁶ F)

R = 220 Ω

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Why do water molecules tend to stay together and hold their shape? Name and explain the phenomenon by which this happens

Answers

Answer:

because liquid and solid states of water possesses intermolecular force of attraction which held the molecules of water in fixed

How much energy is radiated each second by one square meter of a star whose temperature is 10,000 K? in the Stefan-Boltzmann law is equal to 5.67 x 10-8 J/m2 sec Ko. a. 5.67 x 1012 J b. 5.67 x 108 J c. 5.67 x 104 J d. 300 nm e. 300,000,000 nm

Answers

The energy radiated each second by one square meter of a star whose temperature is 10,000 K is 5.67 x 1\(0^{8}\)J. The correct choice is option b.

To find the energy radiated per second by one square meter of a star with a temperature of 10,000 K, we can use the Stefan-Boltzmann law. The formula for the Stefan-Boltzmann law is:

P = σ * \(T^{4}\)

where P is the power radiated per unit area (in J/m²sec), σ is the Stefan-Boltzmann constant (5.67 x 1\(0^{-8}\) J/m² sec \(K^{4}\)), and T is the temperature in Kelvin (10,000 K).

Plug in the values into the formula
P = (5.67 x 1\(0^{-8}\) J/m² sec \(K^{4}\)) × (10,000 K\()^{4}\)

Calculate the power radiated per unit area
P = (5.67 x 1\(0^{-8}\) J/m² sec \(K^{4}\)) × (1 x 1\(0^{16}\) \(K^{4}\))

Multiply the constant by the temperature raised to the power of 4
P = 5.67 x 1\(0^{8}\) J/m² sec

Therefore,  5.67 x 1\(0^{8}\) J (option b) is the energy radiated each second by one square meter of a star whose temperature is 10,000 K.

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What does potential energy between two magnets become kinetic energy?

Answers

Answer:

HI!

Here is ur answer

100% correct Potential energy between two magnets

Magnetic PE depends on both distance and orientation in the magnetic field. ... The magnetic fields are aligned. This makes an attractive force between the two magnets. The farther apart they are, the higher their potential energy.

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Al changes save
3. The graph shows the magnitude of the force exerted by a given spring as a function of the distance x that the spring is stretched. How much work is needed to stretch this spring a distance of 5 cm,
starting with it unstretched?
350
300
250-
200-
F(N)
150
100
50
1
2
7 8
x (cm)

Answers

The work needed to stretch the spring a distance of 5 cm is 1100 N·cm.

To determine the work needed to stretch the spring a distance of 5 cm, we need to calculate the area under the force vs. distance graph within that range. Looking at the graph, we can see that the force initially increases linearly as the distance increases and then levels off.

To calculate the work, we need to find the area of the triangle formed by the initial linear part of the graph and the rectangle representing the constant force. The height of the triangle is the force at 5 cm, which appears to be around 200 N. The base of the triangle is 5 cm. The area of the triangle is given by 0.5 * base * height, which is 0.5 * 5 cm * 200 N = 500 N·cm .The rectangle representing the constant force has a height of 200 N and a base of 3 cm (since it starts at 2 cm and ends at 5 cm). The area of the rectangle is base * height, which is 3 cm * 200 N = 600 N·cm.

Adding the areas of the triangle and the rectangle, we get a total work of 500 N·cm + 600 N·cm = 1100 N·cm.

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g a 50 kg mass is resting on a plane that is inclined at 15 degrees above the horizontal. a 250 n forces is applied to the mass, up the inclined plane, but the mass does not move. determine the coefficient of static friction between he mass and the plane.

Answers

The coefficient of static friction between the mass and the plane is 0.52.

Then coefficient of static friction is the value that must be overcomed when two surfaces are in contact. This value depends on the nature of the surfaces in contact.

In the given question, since the two surfaces are rough, frictional force will act in opposite direction of the motion.

Given that;

F = μR

where F is the force applied to the mass and R is its reaction.

F = 250 N

R = mgCos θ

  = 50 x 10 Cos 15

  = 483 N

So that;

μ = F/R

  = 250/483

μ = 0.52

The coefficient of static friction between the mass and the plane is 0.52.

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What is the sum of all of the forces acting on an object

Answers

Answer:

Explanation:

The sum of all the forces acting on an object is the net force or resultant force. If all the forces cancel out, the resultant force is zero, else, the unbalanced force will cause acceleration of the object. Force is a vector and hence has both a direction and magnitude. For example, gravitational force (on earth) acts in downward direction and has a magnitude equal to mass of the object and acceleration due to gravity. Once we know all the forces that are acting on a body, we resolve all of them into components (typically horizontal and vertical) and take summation of forces in each direction. If such forces cancel out (in each direction), the object maintains its state of rest or constant motion. If however, forces do not cancel out, there is a net resultant force on the object that will cause acceleration of the object (as given by Newton's second law of motion).  

Hope this helps.

The sum of all of the forces acting on an object is called net force. It is categorized as a vector quantity because it has both direction and magnitude to be considered.

What is Force?

Force may be defined as the process of pushing or pulling on an object with mass provoking it to change its velocity. It is an external agent capable of altering a body's state of rest or motion. It has a magnitude and a direction, so it is a vector quantity.

Net force in a case where forces of different magnitude and opposite directions will be the difference between greater and lesser force. The combination of the resultant of all the forces acting on an object is called Net Force, which is basically the sum of all the forces acting on that object.

Therefore, the sum of all of the forces acting on an object is called net force.

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Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. What should you do next?

a. Test a new variable
b. Share your findings
c. Apply your results to a new experiment
d. Repeat the exact same procedure

Answers

Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. Then you have to repeat the exact same procedure

E = mc2. The most well-known equation in the world, but what does it actually mean? "Mass times the square of the speed of light equals energy." The equation's most fundamental claim is that energy and mass (matter) are interchangeable; they are just different manifestations of the same thing.

The answer to the question "Why does E=mc2?" is thus straightforward and elegant: "Because everything is always traveling through spacetime." By seeing the situation correctly, we can understand that the rest energy that we weren't expecting is simply a result of the time component of that motion.

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a proton accelerates from rest in a uniform electric field of 600 n/c. at one later moment, its speed is 1.50 mm/s (nonrelativistic because v is much less than the speed of light). find the time interval, in ms, that the proton takes to reach this speed. flag question: question 11

Answers

The proton accelerates from rest in a uniform electric field of 600 n/c. In order to find the time interval it takes for the proton to reach a speed of 1.50 mm/s.

We need to use the equation v = v₀ + at, where v is the final velocity, v₀ is the initial velocity (which is 0 in this case), a is the acceleration, and t is the time interval. The acceleration of the proton in the electric field is a = E/m, where E is the electric field and m is the mass of the proton. Substituting these values into the equation gives us:

1.50 mm/s = 0 + (600 n/c/1.67 x 10⁻²⁷ kg) x t

Rearranging the equation and solving for t gives us the time interval:
t = 1.50 mm/s/(600 n/c/1.67 x 10⁻²⁷ kg)

t = 8.33 x 10⁻¹³ s

t = 8.33 ms

Therefore, it takes the proton 8.33 ms to accelerate from rest to a speed of 1.50 mm/s in the uniform electric field of 600 n/c.

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Which two organisms in the Domain Eukarya can make their own food?​

Answers

Answer:

Plantae. Also called the Kingdom Metaphyta, the Kingdom Plantae consists of all multicellular, eukaryotic, and photosynthetic organisms on the planet. Being photosynthetic, these organisms are autotrophs and can make their food using the energy from the sun.

Which expression correctly describes force using Sl units?O A. 1 J= 1 kg-m/s²OB. 1 N=1 kgm/sOC. 1 J= 1 kg-m/sD. 1 N = 1 kg-m/s²

Answers

D. 1 N = 1 kg-m/s²

Explanation

Force can be defined as the push or pull on an object with mass that causes it to change its velocity, for example the force of gravity , this force pushes us to the cneter of the earth,

so

\(Force=\text{ mass *acceleration}\)

SI( international system of units) is the metric system that is used universally as a standard for measurements, the units for mass and acceleration are

\(\begin{gathered} mass\Rightarrow kilograms\Rightarrow kg \\ aceleration\Rightarrow meters\text{ per square second}\Rightarrow\frac{m}{s^2} \end{gathered}\)

therefore, the units of force would be

\(\begin{gathered} Force=\text{ mass *acceleration} \\ Force=kg*\frac{m}{s^2} \\ \end{gathered}\)

by definition

\(\begin{gathered} 1\text{ kg}\frac{m}{s^2}=1\text{ Newton\lparen N\rparen} \\ so \\ 1N=1\text{ kg}\frac{m}{s^2} \end{gathered}\)

therefore, the answer is

D. 1 N = 1 kg-m/s²

I hope this helps you

A stone is thrown straight upward and reaches a maximum height of 32.3 m above itslaunch point. What was the initial speed with which the stone was thrown upwards?Answer:m/s

Answers

Answer:

The initial speed = 25.16 m/s

Explanation:

The maximum height, H = 32.3 m

The initial speed, u = ?

The formula for the maximum height of a projectile is:

\(H=\frac{u^2}{2g}\)

Substitute H = 32.3m and g = 9.8 m/s² into the formula and solve for u

\(\begin{gathered} 32.3=\frac{u^2}{2(9.8)} \\ \\ u^2=32.3(2)(9.8) \\ \\ u^2=633.08 \\ \\ u=\sqrt{633.08} \\ \\ u=25.16\text{ m/s} \end{gathered}\)

The initial speed = 25.16 m/s

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