how to find the average atomic mass from a data table

2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams. Density is the mass of a specific material per unit volume.

Density is the mass of a specific material per unit volume. Density is defined as d = M/V, in which d represents density, M is weight, as well as V is volume. Density is generally expressed in grams every cubic centimetre. Water, for example, has a density of 1 gram per square centimeter, but Earth has a density of 5.51 kilograms per cubic centimetre.

Density is sometimes measured in kilos per cubic centimeter (in metre-kilogram-second or SI units). The density of air, for example, is 1.2 kilos per cubic metre. 

density = mass / volume

            =53/ 20

            =2.65g/ml

Therefore, 2.65g/ml is the density of a piece of granite whose volume is 20 mL and mass is 53grams.

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Answer:

0.00246kg

Explanation:

1g = $40.63

$100 = $100/40.63 = 2.46g

2.46/1000 g = 0.00246kg

Answer:

The reactant that determines how much product can be made

Explanation:

The limiting reactant in a chemical reaction is the one that is consumed first and restricts the amount of product that may be produced (or limiting reagent).

The term mu here represents the average contents of all bottles of juice in the population, which is unknown. Option B

The term standard deviation has to do with the extent that values are scattered around the mean. Now we know that the mean is the average of the distribution.

The standard deviation shows the extent to which the values differ from the mean value of the distribution. It is a measure of dispersion.

Thus, the term mu here represents the average contents of all bottles of juice in the population, which is unknown. Option B

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Missing parts;

Minute Maid states that a bottle of juice contains 473 mL. Consumer groups are interested in determining if the bottles contain less than the amount stated on the label. To test their claim, they sample 30 bottles. The sample mean was 472mL and the standard deviation is 0.2.

What does mu represent here?

A. The average contents of all bottles of juice in the sample, which is unknown.

B. The average contents of all bottles of juice in the population, which is unknown.

C. The average contents of all bottles of juice in the population, which is 472mL.

D. The average contents of all bottles of juice in the sample, which is 472mL.

The pressure in the cylinder must have been 919.5 kPa.

The pressure in the cylinder is calculated by applying general gas equation as follows;

P₁V₁/T₁ = P₂V₂/T₂

where;

P₂ = (P₁V₁T₂/T₁V₂)

The initial temperature of the cylinder = 12⁰C = 285 K

The final temperature of the cylinder = 21⁰C = 294 K

P₂ = (95.5 x 14 x 294/285 x 1.5)

P₂ = 919.5 kPa

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Acetone has a concentration of 0.74 Mm.

Acetone is an organic chemical that is colorless, combustible, volatile, and has a distinctively strong odor. It is a solvent that is frequently used in a variety of commercial and domestic settings. It also serves as a starting point for the synthesis of other chemicals. Acetone has the chemical formula CH3COCH3 and a molecular weight of 58.08 g/mol.

We must first determine how many moles of acetone are present in the solution.

Per kilogram of solvent, one molal equals one mole of solute.

Since 1 kilogram is equivalent to 1000 milliliters of ethanol, it is possible to compute the number of moles of acetone as follows:

1000 mL/kg times 1.00 mol/kg is 1.00 mol.

The mass of acetone in the solution can then be determined using the molar mass of acetone (58.08 g/mol):

1 mole * 58.08 g/mol = 58.08 g

The volume of acetone can then be calculated by dividing the mass by the density:

58.08 g/0.788 g/mL equals 73.56 mL.

Finally, the molality of acetone can be determined as follows:

0.0074 mol/L (1.00 mol)/1.00 mol/(73.56 mL + 1000 mL) = 0.74 mM.

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

During the early Paleozoic Era, the Earth's surface was very different from what it is today. The continents were arranged differently, forming one large supercontinent called Pangea. This landmass was surrounded by a single large ocean called Panthalassa. The climate was much warmer and wetter than it is today, with no ice caps at the poles.

The first land plants, known as bryophytes, appeared during the early Silurian Period, around 430 million years ago. These plants were small and simple, lacking roots and vascular tissue. They grew in damp environments, such as along the edges of lakes and streams. They were important in the development of soils and in the colonization of land by other organisms, such as insects and other arthropods.

Answer:

Clouds are water

Explanation:

When a gas gathers up into a cloud,the cloud starts to rain and water comes out of the cloud.

Answer:

1 × 10⁻² M

Explanation:

Step 1: Given data

Absorptivity of a dye (ε): 1 × 10² cm⁻¹M⁻¹

Absorbance (A): 1.0

Length of the cuvette (l): 1 cm

Concentration of a dye (C): ?

Step 2: Calculate the concentration of the dye

We will use Beer's Law.

A = ε × l × C

C = A / ε × l

C = 1.0 / 1 × 10² cm⁻¹M⁻¹ × 1 cm

C = 1 × 10⁻² M

The concentration of the dye is 1 × 10⁻² M.

Answer: Compaction and Cementation.

Explanation. Compaction occurs when the weight of overlying sediment compresses the sediment grains and reduces the amount of pore space between them, resulting in a more tightly packed sedimentary rock. Cementation occurs when mineral-rich groundwater moves through the pore spaces of the sediment, depositing minerals that bind the sediment grains together and form a solid rock.

Answer:

1,4,6,7

Explanation:

Electrons have a negitive charge and are outside of the nucleus and have the same atomic number and have the same number os nutrons.

When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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According to Valence Bond Theory, the hybridization model involves the overlapping of atomic orbitals to form chemical bonds. In the case of an S-F bond (sulfur and fluorine bond), the orbitals that overlap are the sulfur's hybrid orbitals and the fluorine's atomic orbitals.

For sulfur, hybridization occurs, and the most common type is sp3 hybridization. In this case, one s-orbital and three p-orbitals combine to form four sp3 hybrid orbitals. These hybrid orbitals allow sulfur to form bonds with multiple atoms, such as in the SF6 molecule, where sulfur is bonded to six fluorine atoms.

For fluorine, its valence atomic orbitals are the 2p orbitals. Fluorine has seven valence electrons, with one unpaired electron in its 2p orbital, making it highly reactive and allowing it to form bonds with other atoms.

To form an S-F bond, one of the sulfur's sp3 hybrid orbitals overlaps with a fluorine's 2p orbital. This overlapping of orbitals allows the sharing of electrons between the two atoms, resulting in a covalent bond. The S-F bond is strong and polar, with the more electronegative fluorine atom pulling electron density towards itself.

In summary, the orbitals that overlap to form an S-F bond are the sulfur's sp3 hybrid orbitals and the fluorine's 2p atomic orbitals. This overlapping creates a covalent bond between the two atoms, contributing to the formation of molecules such as SF6.

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The Medal of Honor is the best navy decoration and highest volume.

The President of the USA The Victoria go is the holy grail for Medal of Honor creditors because there are the best in lifestyles. Bearing the inscription For valor and called a VC, this medal turned into first offered for conspicuous bravery' in 1856 and later backdated to the Crimean conflict of 1854. The outstanding service pass is the second maximum army ornament that may be provided to a member of the American military, for intense gallantry and risk of lifestyle in actual combat with an armed enemy force.

The Bronze Star Medal dates lower back to world battle II. these days, it is the fourth-maximum ranking award a provider member can obtain for a heroic and meritorious deed performed in an armed battle. For individuals who acquire the BSM, it's far a sign of their sacrifice, bravery, and honor at the same time as serving their us of a

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Answer:

Answer:

Before I answer I feel that I should provide some scientific background as to how you would go about determining the answer.

First point that’s important for you to understand is the following formula

F =  G∗(M1∗M2)/d2

Where G is your gravitational constant, which means that comparing the two weights it won’t change and we don’t really have to worry ourselves too much about it.

Secondly we have the masses of the two individual objects, M1 and M2, in this case M1 is going to be 120 pounds.

Then you have d which is the distance between the centres of the two objects.

The second thing you need to understand is the fine print in the question. You asked how much you would weigh given that you weigh 120 pounds on Earth. The question from a pure science view is flawed as you don’t infact weigh 120 pounds, rather you have a mass of 120 pounds which will remain a constant. Your weight on Earth is actually 530 Newtons

(120lb=54,4311kg)

(54,4311kg*9.8) = approximately 530N

Now assuming you are right and the moon has a sixth of the earths mass, that would mean that you would weigh a sixth of it.

But wait theres more, because the radius of the moon is smaller it will have an impact. the radius of the moon infact is a sixth of the earths, which means that you will be multiplying by 36(because you are making the divisor a sixth smaller, but also squaring it)

this would mean that you would weigh six times as much on the moon as on Earth, which we know is not true. This implies you made a mistake with the mass of the moon compared to that of the Earth. So upon googling it.

Mass of Earth

5.972 × 10^24 kg

Mass of Moon

7.34767309 × 10^22

kilograms

Just looking at it the difference is about 200 times, which means that you probably misinterpreted the data, the gravitational attraction of the moon is a sixth of the Earths, which means you would weigh about 530/6N or to the casual viewer about 88 N

Note : I rounded and abstracted a lot because I feel its the gist of the answer and the understanding that’s important, you are welcome to contact me if you feel anything is incomplete or unclear. I did most of the math quickly and am liable to mistakes but the science is right(unless ofc you feel like bringing relativity in, but that’s a whole other can of worms

Explanation:

Yess

Answer:

19.92 pounds :)

The particle diagram represents a solid sample of silver, which is a metallic element. The type of bonding present when valence electrons move within the sample of silver is 1.) metallic bonding

Metallic bonding is the type of bonding present in metals like silver, where valence electrons move freely throughout the solid sample. Therefore, the type of bonding present when valence electrons move within the sample of silver is metallic bonding.

Metallic bonding is a type of chemical bonding that occurs in metals and alloys. It is a type of bonding where valence electrons are not strongly bound to any one particular atom, but are free to move throughout the entire solid structure.

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Answer:

the tea was not hot sugar dissolves quickly and hot water than cold

Sodium carbonate, often referred to as Na2CO3, is a chemical compound composed of atoms of sodium (Na), carbon (C) and oxygen (O).

It is also sometimes called washing soda or soda ash. At room temperature, sodium carbonate is a white, crystalline solid that is very soluble in water. According to the chemical formula of the sodium carbonate molecule, Na2CO3, each molecule consists of two sodium atoms (Na), one carbon atom (C) and three oxygen atoms (O). The atomic configuration in sodium carbonate is shown in the given diagram.

A trigonal planar arrangement is formed when the central carbon atom is bonded to three oxygen atoms. The structure of sodium carbonate is completed by two sodium atoms joined to oxygen atoms.

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The silica content and viscosity of the magma increase as it rises through the continental crust, finally generating andesitic-rhyolitic magmas as a result of partial melting of the crust. That's accurate.

Stratovolcanoes frequently release thick lava flows made of andesite magma, some of which can be several kilometers long. Strong explosive eruptions from andesite magma can also result in pyroclastic flows, surges, and massive eruption columns. At temperatures between 900 and 1100 ° C, andesites erupt.

Wet partial melting of the mantle results in the formation of andesitic magma. Water is in contact with the mantle beneath the ocean. The mantle will heat up and water will be forced into it when subduction, or continental plates sliding apart, takes place.

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The amount of water that will be formed would be 94.15 g

2H2 + O2 -> 2H2O

From the balanced equation, we can see that 2 moles of H2 react with 1 mole of O2 to form 2 moles of H2O. We can use this information to calculate the amount of water formed from the given amounts of H2 and O2:

Moles of H2 = 10.54 g / 2.016 g/mol = 5.23 mol

Moles of O2 = 95.10 g / 32.00 g/mol = 2.97 mol

The stoichiometric ratio of H2 to O2 is 2:1. Therefore, for every 2 moles of H2, we need 1 mole of O2. In this case, we have more than enough O2 to react with all the H2, so O2 is in excess and H2 is the limiting reactant.

From the balanced equation, we know that 2 moles of H2 produce 2 moles of H2O.

Therefore, 5.23 moles of H2 will produce 5.23 moles of H2O.

The molar mass of H2O is 18.015 g/mol, so the mass of H2O formed is:

mass = moles x molar mass

mass = 5.23 mol x 18.015 g/mol

mass = 94.15 g

Therefore, 94.15 g of water will form.

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A container holds 0.500 quarts of liquid it contains 473  milliliters of lemonade.

Quarts is a unit to measure the volume of any liquid or gas which is equal to quarter gallon and the liquid quatr or solid all is almost equal to one liter.

A container holds 0.500 quarts of liquid and the value in milliliters will be

                   1 quart = 946.3 milliliters.

                    0.500 quarts = 946.3 milliliters.

                      quarts = 0.500  946.3 milliliters

                                  = 473.15 milliliters.

Therefore,  container holds 0.500 quarts of liquid it contains 473  milliliters of lemonade.

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Water has low viscosity and low surface tension.

Viscosity refers to the resistance of a fluid to flow, and water has a relatively low viscosity compared to many other liquids. This property is important for many applications, including the movement of water through pipes and the flow of water in rivers and streams.

Surface tension, on the other hand, is the measure of the cohesive force between molecules at the surface of a liquid. Water has a relatively low surface tension compared to some other liquids, which makes it easier for objects to penetrate its surface. This property is also responsible for the formation of droplets and the behavior of water striders and other water-dwelling insects.

Overall, these properties contribute to the unique characteristics of water and its importance in many natural and industrial processes.

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If 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C, the molar mass of the gas is 112 g/mol

The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as

                                        PV = nRT

where,

P = Pressure

V = Volume

T = Temperature

n = number of moles

Given,

Volume = 21.5L

Pressure = 140 kPa

Temperature = 318 K

Using ideal gas equation, PV = nRT

                            140 × 21.5 = n × 8.314 × 318

                                      n = 1.138 moles

Mass = moles × molar mass

Molar mass = 128 ÷ 1.138

= 112 g/mol

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The other compound that makes up most of the other gases in the table is water vapor.

Water vapor is not listed in the table because it is not a pollutant. However, it is a significant component of exhaust gas, and it can contribute to smog formation. Water vapor is formed when the fuel in a petrol engine is burned. The combustion process produces water as a byproduct.

The amount of water vapor in the exhaust gas depends on the temperature of the combustion process. At higher temperatures, more water vapor is produced. Water vapor is not a pollutant in itself, but it can contribute to smog formation.

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Complete question:

this table shows the percentages of some gases in the exhaust from a petrol engine

nitrogen 68

carbon dioxide 15

carbon monoxide 1

oxygen 0.75

nitrogen oxides 0.24

hydrocarbons 0.005

sulphur dioxide 0.005

other gases

what is the name of the other compound that makes up most of the other gases in the table?

The order for reactant A is 2 and the order for reactant B is 1. For the first reaction, the overall order of the reaction is 3 and for the second reaction, the overall order of the reaction is 5.

The order of a reaction is the sum of the exponents in the rate law expression that relates the rate of a chemical reaction to the concentrations of the reactants.

To determine the order of each reactant, we need to compare the initial rates of reaction at different concentrations while keeping the concentration of the other reactant constant.

For reactant A:

Exp#1 (0.100 M A, 0.100 M B): initial rate = k(0.100)^2(0.100) = 0.001 k

Exp#2 (0.200 M A, 0.100 M B): initial rate = k(0.200)^2(0.100) = 0.004 k

Exp#3 (0.100 M A, 0.200 M B): initial rate = k(0.100)^2(0.200) = 0.002 k

We can see that when the concentration of A doubles (Exp#1 to Exp#2), the initial rate quadruples, which indicates that A is second order. When the concentration of B doubles (Exp#1 to Exp#3), the initial rate doubles, which indicates that B is first order.

Therefore, the order for reactant A is 2 and the order for reactant B is 1.

To determine the overall order of the reaction, we add the orders of the reactants:

Overall order = 2 (order of A) + 1 (order of B) = 3

Therefore, the overall order of the reaction is 3.

For the second reaction, we can see that the rate depends on the concentration of both reactants, and we cannot determine their individual orders without further information or experiments. However, we can determine the overall order of the reaction by adding the exponents of the concentration terms in the rate law:

Overall order = 1 + 4 = 5

Therefore, the overall order of the reaction is 5.

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Answer:

A. Reactants change into products

The compound has the molecular formula CH₄O. H : O = 1 : 4 : 1 As a result, the empirical formula is CH₄O.

The organic compound sample's mass is 0.5 g, or (0.188 + 0.062 + 0.25) The vapor density should not have a unit.

The organic compound has a molar mass = 16 × 2 g/mol

                                                                            = 32 g/mol

Moles of C atoms = (32 g) × (0.188/0.5) / (12 g/mol) = 1

Moles of H atoms = (32 g) × (0.062/0.5) / (1 g/mol) = 4

Moles of O atoms = (32 g) × (0.25/0.5) / (16 g/mol) = 1

Hence, molecular formula = CH₄O

Thus, the compound has the molecular formula CH₄O. H : O = 1 : 4 : 1 As a result, the empirical formula is CH₄O.

Organic molecules contain covalently bound carbon and hydrogen as well as frequently additional elements. Benzoic acid, diethyl malonate, propanoic acid, butanoic acid, malonic acid, amines, heterocyclic compounds, and benzoic aldehyde are all examples of organic compounds. Organic substances include the carbohydrates, fats (lipids), proteins, and nucleic acids that make up the components of life. Organic molecules include petroleum and natural gas, which constitute the majority of fossil fuels.

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