The semicircle above has a radius of r inches, The distance between the chord and the diameter in terms of r is √5 r/3 inches.
What is chord of Circle ?A chord of a circle can be defined as a line segment connecting any two points on the circumference. It should be noted that the diameter is the longest chord of a circle which passes through the center of the circle.
To find the distance required one can use either the Pythagorean theorem or the trigonometric ratios. Let the semicircle have center O. The diameter AB has length 2r. Because chord CD is 2/3 of the length of the diameter,
CD=2/3(2r) = 4r/3
let the distance between diameter AB and chord CD be x inches. To find x draw a right triangle connecting center O, the midpoint, E of chord CD, and point C . Using Pythagorean theorem here,
r² = x² + (CD/2)²
=> r² = x² + (2r/3)²
=> r² = x² + 4r²/9
=> x² = r² - 4r²/9 = 5r²/9
=> x = √5 r/3
Hence, the distance between the chord and the diameter in terms of r is √5r/3..
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solve 1.2y =3.6
y=3
y=4.32
y=2.4
y=4.8
Consider the probability statements regarding events A and
B below.
P(A or B) = 0.3
P(A and B) = 0.2
P(AB) =0.8
What is P(B)?
A) 0.1
B) 0.375
C) 0.25
D) 0.667
The calculated value of the probability of B is (c) 0.25
How to calculate the probability of BFrom the question, we have the following parameters that can be used in our computation:
P(A or B) = 0.3
P(A and B) = 0.2
P(A/B) =0.8
First, we have
P(A/B) = P(A and B)/P(B)
Substitute the known values in the above equation, so, we have the following representation
0.2/P(B) = 0.8
So, we have
P(B) = 0.2/0.8
Evaluate
P(B) = 0.25
Hence, the probability of B is 0.25
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help me with this please
before class, you decided to go for a run around a circular track with radius 0.25 miles centered at (0,0). if you end up at to a point where x
If the point you end up at is coordinate (0.25, 0) then you would have ran one full lap around the track.
1. The given track is a circular track with a radius of 0.25 miles, and the center of the track is at (0, 0).
2. If you end up at the point (0.25, 0), then you would have ran one full lap around the track. This is because the coordinates of the point you end up at, (0.25, 0), are the same as the coordinates of the circumference of the track, which is located 0.25 miles from the center of the track.
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Find the value of x and y.
3x=8-(2y)
Answer:
3x = 6y
Step-by-step explanation:
8 - 2y = 6y and 3x is by itself so it would be 3x is equal to 6y.
la suma de dos número impares consecutivos es 100 . hallar la suma de cifras del mayor
numero
deja que los números sean x, and x + 2
sabemos que su suma es igual a 100, entonces
x + x + 2 = 1002x = 100 - 2 2x = 98 x = 98 ÷ 2 x = 49por lo tanto, el primer número es 49
y el segundo número es x + 2 = 49 + 2 = 51 (también es el mayor entre los dos números)
entonces suma de dígitos de mayor número = 5 + 1 = 6
Respuesta correcta de la pregunta anterior = 6
answer and get brainliest
Answer:
50
Step-by-step explanation:
4 x 1=4
2.5 x 5=12.5
12.5 x 4=50
So 50 is the answer can i have brainliest now please
(2x^3+9x^2+x-12)/(x+4) simplify
Answer:
\(2 {x}^{2} + x - 3\)Step-by-step explanation:
\( \frac{2 {x}^{3} + 9 {x}^{2} + x - 12}{x + 4} \)
Write \(9 {x}^{2} \) as a sum
\( \frac{2 {x}^{3} - 2 {x}^{2} + 11 {x}^{2} + x - 12}{x + 4} \)
Write X as a sum
\( \frac{2 {x}^{3} - 2 {x}^{2} + 11 {x}^{2} - 11x + 12x - 12 }{x + 4} \)
Factor out \(2 {x}^{2} \) from the expression
\( \frac{2 {x}^{2}(x - 1) + 11 {x}^{2} - 11x + 12x - 12 }{x + 4} \)
Factor out 11x from the expression
\( \frac{2 {x}^{2} (x - 1) + 11x(x - 1) + 12x - 12}{x + 4} \)
Factor out 12 from the expression
\( \frac{2 {x}^{2}(x - 1) + 11(x - 1) + 12(x - 1) }{x + 4} \)
Factor out X - 1 from the expression
\( \frac{(x - 1)(2 {x}^{2} + 11x + 12)}{x + 4} \)
Write 11x as a sum
\( \frac{(x - 1)(2 {x}^{2} + 8x + 3x + 12)}{x + 4} \)
Factor out 2x from the expression
\( \frac{(x - 1)(2x(x + 4) + 3x + 12)}{x + 4} \)
Factor out 3 from the expression
\( \frac{(x - 1)(2x(x + 4) + 3(x + 4)}{x + 4} \)
Factor out X + 4 from the expression
\( \frac{(x - 1)(x + 4)(2x + 3)}{x + 4} \)
Reduce the fraction with X + 4
\((x - 1)(2x + 3)\)
Multiply the parantheses
\(2 {x}^{2} + 3x - 2x - 3\)
Collect like terms
\(2 {x}^{2} + x - 3\)
Hope this helps...
Good luck on your assignment...
May I please get help with this. I tried many times to figure out the correct answer for this problem but I still can’t get it right
Solution
In ΔFGH, line FG ║line IJ
And the following dimensions are given
\(\begin{gathered} \text{IF}=15 \\ HI=12 \\ JG=20 \\ HJ\text{ is unknown} \end{gathered}\)To find HJ, usingthe formula for the ratio of similar triangles, i.e
\(\frac{HI}{IF}=\frac{HJ}{JG}\)Substitute the values into the formula above
\(\frac{12}{15}=\frac{HJ}{20}\)Crossmultiply and solve for HJ
\(\begin{gathered} 12\times20=HJ\times15 \\ \text{Divide both sides by 15} \\ HJ=\frac{12\times20}{15} \\ HJ=16\text{ units} \end{gathered}\)Hence, HJ is 16 units.
Same set up as the problem to the left. Fill in the blanks.
The blanks that are missing in the sequence are -3 and 11
How to fil in the blanks in the sequencefrom the question, we have the following parameters that can be used in our computation:
The blanks in the sequence
When listed out, we have
_, _, 25, 39
Assuming that the sequence, is an arithmetic sequence, then we have
Common difference = 39 - 25
Common difference = 14
This means that
Previous term = 25 - 14 = 11
Firs term = 11 - 14 = -3
So, the missing terms are -3 and 11
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At birth, a puppy weighed 5.5 ounces. When it was adopted 9 weeks later, its weight was 3.5 times its birth weight. What was the puppy’s weight when it was adopted? 17.05 ounces 19.25 ounces 170.5 ounces 192.5 ounces
Answer:
19.25 ounces
Step-by-step explanation:
Answer:
it is b
Step-by-step explanation:
A couple predicts that they will need to save $250,000 for their child's college education, and they predict that they will be able to earn about 9% interest, compounded monthly, on their investments. (a) If they begin the deposits at the end of each month when their child is a newborn, so that they have 18 years of deposits, how large must the deposit be? Round your final answer to two decimal places. 3. (b) If they do not begin making deposits until their child is 10 years old, so that they have only 8 years of deposits, how large must the deposit be? Round your final answer to two decimal places.
Let's use accumulation factor-compound formula:
\(A=P(1+\frac{r}{n})^{nt}\)Where:
A = Future value or savings
P = Principal or initial investment
n = Number of times interest is compounded per year
t = time
(a) If they begin the deposits at the end of each month when their child is a newborn, so that they have 18 years of deposits, how large must the deposit be?
In this case:
A = 250000
P = ?
n = 12 (because the interest is compounded monthly)
t = 18
r=9% = 0.09
\(\begin{gathered} 250000=P(1+\frac{0.09}{12})^{12\cdot18} \\ 250000=P(1.0075)^{216} \\ 250000=P(5.022637555) \\ \text{Solving for P:} \\ P=\frac{250000}{5.022637555}\approx49774.64 \end{gathered}\)If they do not begin making deposits until their child is 10 years old, so that they have only 8 years of deposits, how large must the deposit be? Round your final answer to two decimal places.
In this case t changes from 18 to 8, therefore:
\(\begin{gathered} 250000=P(1+\frac{0.09}{12})^{12\cdot8} \\ 250000=P(1.0075)^{96} \\ 250000=P(2.048921228) \\ \text{Solving for P:} \\ P=\frac{250000}{2.048921228}\approx122015.43 \end{gathered}\)Which ratio is equivalent to 5:2?
7:4
2:5
10:4
5:1
Submit
Answer:
10:4
Step-by-step explanation:
..................
If you roll the die 300 times, what is the best prediction for the number of times that it will land on 5?
Step-by-step explanation:
There are 6 possible rolls ...all equal probability ...'5' is just one of the 6
so 1/6th of the time it should be a '5'
1/6th of 300 = 50 times a '5' should be rolled
HELP SOMEONE EXPLAIN THIS PLEASE
Answer:
Entrance fee for children: $1.92
Entrance fee for adults: $3.92
Step-by-step explanation:
Total expenses for this year: $214.00
The child fee will be: $x
and the adult fee will be $(x+2)
Last year the number of children was 44
and the number of adults was 33
this year also has the same number of children and adults.
which means the entrance fee total for children will be $44x and for adults will be $33(x+2).
44x + 33(x+2) = 214
--> 44x + 33x + 66 = 214
--> 77x = 214 - 66 = 148
--> x = 148/77 = 1.92
So children's price is $1.92 and adults price is $1.92 + 2
hence:
Entrance fee for children: $1.92
Entrance fee for adults: $3.92
Car A is rated at 32 mi/gal (miles per gallon) for city driving and 30 mi/gal for highway driving. Car B is rated at 29 mi/gal city and 36 mi/gal highway. How many gallons of gas would each vehicle consume for the following amounts of driving? (a) 300 mi of city driving plus 100 mi of highway driving (b) 100 mi of city driving plus 300 mi of highway driving
how many machines will be needed to complete a task in 8 days, given that 4 machine can complete the same task in 12 days
Answer:
6 machines
Step-by-step explanation:
Let x be the time needed for 1 machine to complete the job, so rate of one machine is (rate is the reciprocal of time)
\( \frac{1}{x} \)
rate of 4 machines would be
\(1 \: job = 12 \times \frac{4}{x} = \frac{48}{x} \\ 1 \: macine \: takes \: 48 \: days\)
\( \frac{48 \: days \: per \: machine}{8 \: days} = 6 \: machines\)
What are the solutions of this quadratic equation? x2-6x=-58
Answer:
\(x^{2}\)-6x=-58
Step-by-step explanation:
unit 7 right triangles & trigonometry homework 5: trigonometry : finding sides and angles
Answer:
1. 7.3
2. 33.3
3. 21.3
4. 31.9
5. 25.6
6. 11.0
7. 42°
8. 64°
9. 13°
10. 51°
Step-by-step explanation:
make sure if you're using a math calculator that it is in degree mode.
SIN, COS, OR TAN. SOH CAH TOA. Sin is Opposite/hypotenus.
Cos is Adjacent(next to it)/hypotenus.
Tan is Opposite/Adjacent.
~~
PROBLEM 1:
So we have 63°, 16 as hypotenus, and x as one of the legs.
1. Figure out whether it is Sin, Cos, or Tan. (It's adj and hyp. of the angle degree (63° listed so it's cos.)
2. Once you set it up, it is Cos 63°= x/16 then flip it around. which makes it 16 COS 63= X.
3. Input it into your calculator as 16cos(63, then it will give you.. 7.263847996
4. Don't forget to round to the nearest tenth, which gives you
x = 7.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 2:
Given: 39°, 27 is opposite of the °, and adj is x. So this is Tan.
1. Set it up, Tan 39° = 27/x can't solve this way so fix it.
2. rewritten as X = 27/tan39
3. round ur answer.
x = 33.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 3:
Given: 49°, adj is 14, hyp is x. So this is Cos.
1. Set up according to CAH, Cos 49=(14/x).
We can't solve it this way since the X is on the bottom. So we have to fix it!
2. Turns into X Cos 49 = 14, which then turns into X= 14/cos49.
3. Put it in your calculator as 14 DIVIDED BY cos 49. ( Put image example)
4. Round.
x= 21.3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 4:
Given: 15°, 33 hyp, adj x. Which is Cos.
1. Cos 15= x/33 and rewrite.
2. Input as 33 cos(15 into calculator = 31.875...
3. Round to tenth.
x = 31.9
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 5:
Given: 52°, 20 adj of °, and x opp of °. Will use TAN.
1. Tan 52° = x/20
2. 20 Tan(52 into calculator
3. Round
x = 25.6
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 6:
Given: 27°, opp of ° is 5, hyp is x. Will use Sin.
1. Write out as I have the last few times, Sin 27 = 5/x rewrite cause x can't be at the bottom.
2. Input into calculator as: 5/sin 27 which equals 11.01...
3. Round.
x = 11.0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 7:
Given: x°, 6 as hyp, 4 opp. now we have to solve this different since we don't know the degree. Now when we input into the calculator you will press 2nd, then sin/cos/tan so it will be negative this is depending on which one ur solving for.
We will be using SIN, x is still a °.
1. Sin X = 4/6 Rewrite.
2. X= Sin^-1 (4/6)
Make sure ur sin is negative in calculator when doing this.
3. It SHOULD give you 41.81, round.
x = 42°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 8:
Given: x°, 29 opp, 14 adj. TAN.
1. Tan x°= 29/14 or..
2. X = Tan^-1(29/14) solve..
3. gives u 64.23.... round.
x = 64°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 9:
Given: x°, hyp 54, opp 12. SIN
1. Sin x°=(12/54)
2. X= Sin^-1(12/54) solve. (dont put x= into calculator.)
3. Don't Forget to round, answer unrounded: 12.839..
x = 13°
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
PROBLEM 10:
Given: x°, adj 25, hyp 40. COS
1. Cos x°=25/40 rewrite.
2. X= Cos^-1(25/40) Solve.
3. Round.
X= 51°
at the city Museum, child admission is $5.10 an adult mission is $8.70. On Friday, 136 tickets were sold for total sales of $970.80. How many adult tickets were sold that day
Answer:
x = 76 children's tickets sold
Step-by-step explanation:
Let x = the number of children's tickets sold
Let y = the number of adult tickets sold
x + y = 131
5.5x + 9.8y = 957 Solve the first equation for y
y = 131 - x Multiply the second equation by 10
55x +98y = 9570 Substitute the above equation into this one.
55x + 98(131-x) = 9570 Use the distributive property
55x + 12838 - 98x = 9570 Solve the equation
-43x = -3268
x= 76 children's tickets sold
how is finding percent error similar to finding percent change
Answer:
of which can be considered the “correct” value. The percent difference is the absolute value of the difference over the mean times 100. quantity, T, which is considered the “correct” value. The percent error is the absolute value of the difference divided by the “correct” value times 100.
Step-by-step explanation:
Find the term named in the problem and the explicit formula.
13) 18,14,10,6,
14) 30,0,-30,-60,
Find a₂₂
Find a₃₇
15) -34,-31,-28,-25,
Find a₂₃
The named terms in the sequence are a₂₂ = -66, a₃₇ = -1050 and a₂₃ = 32
How to determine the named term in the sequence?Sequence 1
From the question, we have the following sequence that can be used in our computation:
18,14,10,6,
In the above sequence, we can see that the 4 is subtracted from the previous term to get the current term
Using the above as a guide,
So, we have the following representation
a₁ = 18
d = -4
The nth term can be represented as
aₙ = a₁ + (n - 1)d
For the 22nd term, we have
a₂₂ = 18 + (22 - 1) * -4
Evaluate
a₂₂ = -66
Sequence 2
Here, we have
30,0,-30,-60,
In the above sequence, we can see that the 30 is subtracted from the previous term to get the current term
Using the above as a guide,
So, we have the following representation
a₁ = 30
d = -30
The nth term can be represented as
aₙ = a₁ + (n - 1)d
For the 37th term, we have
a₃₇ = 30 + (37 - 1) * -30
Evaluate
a₃₇ = -1050
Sequence 3
Here, we have
-34,-31,-28,-25,
In the above sequence, we can see that the 3 is added from the previous term to get the current term
Using the above as a guide,
So, we have the following representation
a₁ = -34
d = 3
The nth term can be represented as
aₙ = a₁ + (n - 1)d
For the 23rd term, we have
a₂₃ = -34 + (23 - 1) * 3
Evaluate
a₂₃ = 32
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Use this table to answer the question. Round to 2 decimal places.
Car Plane Train Total
Green 120 250 500 870
Blue 150 350 750 1250
Yellow 170 200 450 820
Red 200 300 300 800
Brown 220 450 320 990
Total 860 1550 2320 4730
What percent of the total are made up of Yellow Trains?
Trains make up approximately 49.04% of the total journeys across all modes of transportation.
We must divide the total number of train trips by the total number of trips made using all modes of transportation, then multiply the result by 100 to get the percentage that trains make up of the total.
There have been 2320 train trips overall, and there have been 4730 trips overall using all forms of transportation.
Trains therefore account for the following proportion of the total:
(2320 / 4730) x 100% = 49.04%
Train travel thus accounts for roughly 49.04 percent of all travels made using all modes of transportation.
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Given the points below, find XY. Round to the nearest hundredth.
X(-8,4) and Y (4, -6)
Answer:
15.62
Step-by-step explanation:
The length XY is found from the distance formula:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4 -(-8))² +(-6 -4)²) = √(12² +(-10)²) = √244
d ≈ 15.62 . . . units
The length of XY is approximately 15.62 units.
Enter the number that belong in the green box please help
Step-by-step explanation:
Since we have three sides and trying to find an angle, use Law of Cosines
\(c = \sqrt{ {a}^{2} + {b}^{2} - 2ab \times \cos(d) } \)
where c is
Solving for the angle d.
\( \cos {}^{ -1 } (( \frac{ {c}^{2} - {b}^{2} - {a}^{2} }{ - 2ab} ) = d\)
where d is in degrees
The angle d is the opposite of the side c.
It does not matter what a and b is(they can be either 4 or 5)
let
c=7
a=4
b=5
\( \cos {}^{ - 1} ( \frac{ - 1}{5} ) = d\)
This angle must be within 0 and 180
We get
\(d = 101.54\)
help plsssssssssssssss
Answer:step 2
Step-by-step explanation:
I need help with this I'm pretty much stumped on it. Of 100 students 27 are taking caculus are taking french and 13 are taking both calculus and french if a student is picked at random what is the probability that the student is taking calculus or french? Answer must be in decimal form rounded to two decimal places
Of 100 students 27 are taking caculus are taking french and 13 are taking both calculus and french if a student is picked at random, the probability that a randomly selected student is taking calculus or French is 0.51.
To find the probability that a randomly selected student is taking calculus or French, we need to determine the total number of students taking calculus, the total number of students taking French, and the total number of students taking both.
Let's denote:
A = Event of taking calculus
B = Event of taking French
We are given the following information:
n(A) = 27 (number of students taking calculus)
n(B) = 37 (number of students taking French)
n(A ∩ B) = 13 (number of students taking both calculus and French)
To find the probability, we use the formula:
P(A or B) = P(A) + P(B) - P(A ∩ B)
Let's calculate the probability:
P(A) = n(A) / Total number of students = 27 / 100 = 0.27
P(B) = n(B) / Total number of students = 37 / 100 = 0.37
P(A ∩ B) = n(A ∩ B) / Total number of students = 13 / 100 = 0.13
P(A or B) = 0.27 + 0.37 - 0.13
P(A or B) = 0.51
Therefore, the probability that a randomly selected student is taking calculus or French is 0.51 (rounded to two decimal places).
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Please Give Me The Answer
The area covered by the signal is 181.37 m²
What is the area covered by the signal?Here we can see that the area covered by the signal is the fourth of a circle of radius R = 15.2m
The area of a circle of radius R is given by:
A = 3.14*R²
Then the area of a fourth of a circle is:
A = (3.14/4)*R²
Replacing the value of the radius in the formula we will get:
A = (3.14/4)*(15.2m)² = 181.37 m²
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What is the period of the sinusoidal function
The answer is 2π
Hope this helps
6 * 10x^{-3}/8*10x^{-6}
The simplified form of the given expression, 6 × 10⁻³ / 8 × 10⁻⁶, is 3/4 × 10³
Simplifying an expressionFrom the question, we are to simplify the given expression
The given expression is
6 × 10⁻³ / 8 × 10⁻⁶
Simplifying the expression
6 × 10⁻³ / 8 × 10⁻⁶
This can be written as
6/8 × 10⁻³/10⁻⁶
Reduce the fraction
3/4 × 10⁻³/10⁻⁶
Apply the division law of indices
3/4 × 10⁻³ ⁻ ⁽⁻⁶⁾
3/4 × 10⁻³ ⁺ ⁶
3/4 × 10³
Hence, the value is 3/4 × 10³
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