How to increase 78 by 80%

a.65.62%of municipal bonds is the probability that will receive an A rating.b.41% of municipal bonds are issued by cities.c.31% of municipal bonds are issued by suburbs.

a. If a new municipal bond is to be issued by a city, the probability that it will receive an A rating can be determined using conditional probability as follows;P(A | City) = P(A and City) / P(City)Using the given values in the question,P(A and City) = P(A) * P(City | A) = (0.7 * 0.3) = 0.21P(City) = P(A and City) + P(B and City) + P(C and City) = 0.21 + 0.04 + 0.07 = 0.32Therefore,P(A | City) = 0.21 / 0.32 = 0.6562 or 65.62%.

b. The proportion of municipal bonds that are issued by cities can be determined as follows;P(City) = P(A and City) + P(B and City) + P(C and City) = (0.7 * 0.3) + (0.2 * 0.4) + (0.1 * 0.7) = 0.41 or 41%.Therefore, 41% of municipal bonds are issued by cities.

c. The proportion of municipal bonds that are issued by suburbs can be determined as follows;P(Suburb) = P(A and Suburb) + P(B and Suburb) + P(C and Suburb) = (0.7 * 0.3) + (0.2 * 0.5) + (0.1 * 0.25) = 0.31 or 31%.Therefore, 31% of municipal bonds are issued by suburbs.

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Answer: A) Yes, mold A is an exponential function that decreases faster than mold B, which is eventually an increasing quadratic function.

Step-by-step explanation:

To determine whether the number of spores in mold B will ever be larger than in mold A, we need to compare the growth patterns of the two functions. The function f(x) = 100(0.75)^(x-1) represents mold A, and it is an exponential function. Exponential functions decrease as the exponent increases. In this case, the base of the exponential function is 0.75, which is less than 1. Therefore, mold A is a decreasing exponential function. The function g(x) = 100(x-1)^2 represents mold B, and it is a quadratic function. Quadratic functions can have either a positive or negative leading coefficient. In this case, the coefficient is positive, and the function represents a parabola that opens upwards. Therefore, mold B is an increasing quadratic function. Since mold B is an increasing function and mold A is a decreasing function, there will be a point where the number of spores in mold B surpasses the number of spores in mold A. Thus, the correct answer is:

A) Yes, mold A is an exponential function that decreases faster than mold B, which is eventually an increasing quadratic function.

Answer: 90

Step-by-step explanation:

450/5 or 450 divided by 5

you can work this out by figuring out 45/5 which is 9

so 450/5 equals 90

he should read 90 pages per day

Answer:

90

Step-by-step explanation:

Because if you divide the pages into the 5 day it would be 90

450 divide by 5 = 90

Answer:

g) \(u^{4}\cdot v^{-1}\cdot z^{3}\), h) \(\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}\)

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) \(\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}\)

1) \(\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}\) Given

2) \(\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }\) Definition of division

3) \(\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}\)   \(\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}\)

4) \(\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)\)  Associative property

5) \(u^{4}\cdot v^{-1}\cdot z^{3}\)   \(\frac{a^{m}}{a^{n}} = a^{m-n}\)/Result

h) \(\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}\)

1) \(\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}\) Given

2) \(\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }\) Definition of division

3) \(\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}\)  \(\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}\)

4) \(\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }\) Factorization/Distributive property

5) \(\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right]\) Modulative and commutative properties/Associative property

6) \(\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}\)  \(\frac{a^{m}}{a^{n}} = a^{m-n}\)/\(\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}\)/Definition of division/Result

Answer:

Use the distance formula to determine the distance between the two points.

Distance

=

√

(

x

2

−

x

1

)

2

+

(

y

2

−

y

1

)

2

Substitute the actual values of the points into the distance formula.

√

(

4

−

(

−

5

)

)

2

+

(

9

−

2

)

2

Simplify.

Tap for more steps...

√

130

The result can be shown in multiple forms.

Exact Form:

√

130

Decimal Form:

11.40175425

…

image of graph

([)]|√>≥

789÷<≤

456/×

Step-by-step explanation:

by which method defination method, prime factorization or division method

Answer:

21.75

Step-by-step explanation:

if you take 87 divided by 2/3, you get 130.5, which is the total amount of money he makes in 6 weeks. but if you take 130.5 divided by 6, you get 21.75 which is how much he makes weekly.

Answer:

No!

Step-by-step explanation:

3/4 does NOT go into 80/100 because say if you had 3 shiny quarters out of 4 quarters total that is equal to 75 cents of shiny quarters but if you were to have 100 pennies and 80 of them were shiny that is 80 cents worth of shiny pennies.

Hope that helped :)

The converse of the statement would be

"If x ≤ 7, then x² ≤ 49"

but this is false. Take x = -8; while it's true that -8 ≤ 7, the second inequality is not, since (-8)² = 64 is not smaller than 49.

Answer:

what is the question i can help

Step-by-step explanation:

brainliest plz

Answer: b

Step-by-step explanation: edge 2020

Answer:

A)

Step-by-step explanation:

t = time to read whole book

(3/5 ÷ 1/4) = (5/5 ÷ t)

simplify:

12/5 = 1/t

cross-multiply:

12t = 5

t = 5/12  

Answer:

y = 2x + 2

Step-by-step explanation:

6x -3y = -6 (get y on one side of the equals sign by substracting 6x from both sides)

-3y = -6x - 6 (divide each side by -3 to get final value of y)

y = 2x + 2

Answer:

16

Step-by-step explanation:

4*2*2

8*2

16

Answer:

I think the answer is $170

Answer:

\( 2.373737....=\frac{235}{99}\)

Step-by-step explanation:

\( 2.373737....=2.\overline{37}\)

\( Let\: x=2.\overline{37}...(1)\)

\( \therefore 100x=237.\overline{37}...(2)\)

Subtracting equation (1) from equation (2), we find:

\( \therefore 100x-x=237.\overline{37}-2.\overline{37}\)

\( \therefore 99x=237+0.\overline{37}-2-0.\overline{37}\)

\( \therefore 99x=235\)

\( \therefore x=\frac{235}{99}\)

\( \implies 2.373737....=\frac{235}{99}\)

To analyze the variances in April, we need to compare the actual costs with the standard costs for materials, labor, and manufacturing overhead.

By calculating the price and quantity variances for materials, rate and efficiency variances for labor, and spending and efficiency variances for variable manufacturing overhead, we can assess the deviations from the standard costs. Additionally, the fixed manufacturing overhead budget and volume variances can be determined by comparing the actual fixed overhead costs with the budgeted amount.

1. Materials Price and Quantity Variances:
The materials price variance measures the difference between the actual cost of materials and the standard cost based on the quantity purchased. It can be calculated as (Actual Price - Standard Price) x Actual Quantity. In this case, the materials price variance is ($18.00 - $18.20) x 6,000 meters.

The materials quantity variance assesses the difference between the actual quantity used and the standard quantity allowed. It can be calculated as (Actual Quantity - Standard Quantity) x Standard Price. Here, the materials quantity variance is (6,000 meters - (2,000 robes x 2.8 meters per robe)) x $18.20.

2. Labour Rate and Efficiency Variances:
The labor rate variance measures the difference between the actual hourly rate and the standard hourly rate, multiplied by the actual hours worked. It can be calculated as (Actual Rate - Standard Rate) x Actual Hours. In this case, the labor rate variance is ($3.80 - $3.60) x 760 hours.

The labor efficiency variance assesses the difference between the actual hours worked and the standard hours allowed, multiplied by the standard rate. It can be calculated as (Actual Hours - Standard Hours) x Standard Rate. Here, the labor efficiency variance is (760 hours - (2,000 robes x 1.5 hours per robe)) x $3.60.

3. Variable Manufacturing Overhead Spending and Efficiency Variances:
The variable manufacturing overhead spending variance measures the difference between the actual variable overhead costs and the standard variable overhead costs. It can be calculated as Actual Variable Overhead - (Standard Variable Rate x Actual Hours). In this case, the variable overhead spending variance is $3,800 - ($1.20 x 760 hours).

The variable manufacturing overhead efficiency variance assesses the difference between the actual hours worked and the standard hours allowed, multiplied by the standard variable overhead rate. It can be calculated as (Actual Hours - Standard Hours) x Standard Variable Rate. Here, the variable overhead efficiency variance is (760 hours - (2,000 robes x 1.5 hours per robe)) x $1.20.

4. Fixed Manufacturing Overhead Budget and Volume Variances:
The fixed manufacturing overhead budget variance measures the difference between the actual fixed overhead costs and the budgeted fixed overhead costs. It can be calculated as Actual Fixed Overhead - Budgeted Fixed Overhead. In this case, the fixed overhead budget variance is $4,600 - $4,680.

The fixed manufacturing overhead volume variance assesses the difference between the standard hours allowed and the budgeted fixed overhead rate, multiplied by the standard fixed overhead rate. It can be calculated as (Standard Hours - Budgeted Hours) x Standard Fixed Overhead Rate. Here, the fixed overhead volume variance is ((2,000 robes x 1.5 hours per robe) - 780 hours) x $2.40.

By calculating these variances, we can analyze the deviations from the standard costs and identify areas where the actual costs differ from the expected costs.

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a. The union (∪) operation combines this with the language containing only the empty string {ϵ}, ensuring that empty strings are also included in L2. b. the language that contains "010" with the language that contains "0".L3 = {0, 1}∗0100 c. L4 represents all even-length strings that do not contain "00".

(a) The language L2 can be expressed using the regular operations and the languages {0}, {1}, {ϵ}, and ∅. We need to exclude the string "00" from all strings over {0,1}. This can be achieved by taking the complement of the language that contains only "00" and then concatenating it with the language over {0,1}.

L2 = ({0, 1}∗ − {00}) ∪ {ϵ}

The expression ({0, 1}∗ − {00}) represents the language of all strings over {0,1} except for the string "00". The union (∪) operation combines this with the language containing only the empty string {ϵ}, ensuring that empty strings are also included in L2.

(b) The language L3 can be expressed using the regular operations and the languages {0}, {1}, {ϵ}, and ∅. We want to find strings that contain the substring "010" and end in "0". We can achieve this by concatenating the language that contains "010" with the language that contains "0".

L3 = {0, 1}∗0100

The expression {0, 1}∗ represents any combination of "0" and "1" repeated zero or more times. By appending "0100" at the end, we ensure that the strings contain the substring "010" and end in "0".

(c) The language L4, which consists of all strings over {0,1} that are even in length and do not contain the substring "00", can be expressed using the regular operations and the languages {0}, {1}, {ϵ}, and ∅. We can achieve this by taking the concatenation of two languages: one that represents even-length strings and another that represents strings not containing "00".

L4 = ({00} ∪ {11} ∪ {01} ∪ {10})∗

The expression ({00} ∪ {11} ∪ {01} ∪ {10}) represents all possible combinations of "00", "11", "01", and "10". By taking the Kleene star (∗) of this expression, we allow any even number of repetitions of these combinations, resulting in strings of even length. Thus, L4 represents all even-length strings that do not contain "00".

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Answer:336

Step-by-step explanation:

12

216 = 336

Answer:

x= 8a+ 8g

Step-by-step explanation:

x/8 -g = a

x/8 = a+g

× 8

x= 8a+ 8g

Step-by-step explanation:

Using the given formula, we can substitute x = 1 and solve for y:

y = 5 x 2^x

y = 5 x 2^1 (substitute x = 1)

y = 5 x 2

y = 10

Therefore, when x = 1, y = 10.

Answer:

y = 10

Step-by-step explanation:

Chlorine has two stable isotopes , Cl-35 and Cl-37 with atomic masses 34.968 u and 36.956 u respectively. If the average atomic mass is 35.453 u.

The type of diagram used to graphically show the relationship between two numerical variables is called a scatter plot.

A scatter plot is a visual representation of data points plotted on a graph, with one variable represented on the x-axis and the other variable represented on the y-axis.

Each data point on the plot corresponds to a pair of values from the two variables being analyzed. The position of each point on the graph indicates the values of both variables, allowing us to examine the relationship between them.

The main purpose of a scatter plot is to visualize the correlation or relationship between the two variables. The pattern formed by the data points on the plot can indicate the direction, strength, and nature of the relationship.

For example, if the points on the scatter plot tend to form a linear pattern, it suggests a linear relationship between the variables. On the other hand, if the points are scattered randomly with no clear pattern, it indicates a weak or no relationship between the variables.

Scatter plots are commonly used in various fields, including statistics, data analysis, and scientific research. They provide a visual way to explore and interpret relationships between variables, identify outliers, detect trends, and assess the strength and direction of associations.

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Answer:

279.000000028

Step-by-step explanation:

correct

a. the sampling distribution is  \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. The probability that the sample proportion is within 0.03 of the population proportion is 0.4101.

c. The probability that the sample proportion is within 0.03 of the population proportion for a sample of 200 households is 0.7738.

a. The sampling distribution of the sample proportion, \(\bar p\), can be approximated by a normal distribution with mean equal to the population proportion, p, and standard deviation equal to the square root of \([(p \times (1-p)) / n]\),

where n is the sample size.

Given that p = 0.17 and assuming a large enough sample size, we can use the formula to calculate the standard deviation of the sampling distribution:

Standard deviation = \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. To find the probability that the sample proportion will be within a certain range of the population proportion, we need to calculate the z-score for the lower and upper bounds of that range and then find the area under the normal curve between those z-scores.

Let's say we want to find the probability that the sample proportion is within 0.03 of the population proportion. This means we want to find

P(\(\bar p\)- p ≤ 0.03) = P((\(\bar p\)-- p) / \(\sqrt{[(p \times (1-p)) / n]}\) ≤ 0.03 / \(\sqrt{[(p \times (1-p)) / n]\)

We can use the standard normal distribution and z-scores to find this probability:

\(z_1\) = (0.03 / \(\sqrt{(0.17 \times (1-0.17)/n}\))

\(z_2\) = (-0.03 / \(\sqrt{(0.17 \times (1-0.17))/n}\))

We can find the probability that the z-score is between \(z_1\) and \(z_2\):

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.541 ≤ Z ≤ 0.541) = 0.4101

c. To answer part (c), we need to specify the sample size. Let's say we are taking a sample of 200 households.

Using the formula for standard deviation of the sampling distribution from part (a), we get:

Standard deviation = \(\sqrt{(0.17 \times(1-0.17)) / 200}\) = 0.034

Now we can repeat the same steps as in part (b) with this standard deviation:

\(z_1\) = (0.03 / 0.034)

\(z_2\) = (-0.03 / 0.034)

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.882 ≤ Z ≤ 0.882) = 0.7738

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Answer:

124

Step-by-step explanation:

Answer:

50degrees

Step-by-step explanation:

The sum of angle in the triangle XYZ is 180degrees, hence;

<X + <Y + <Z = 180

Given

m<X = 80degree

m<Y = m<Z

Required

m<Z

Substitute the given angle

80 + m<Z + m<Z = 180

80 + 2m<Z = 180

2m<Z = 180 - 80

2m<Z = 100

m<Z = 100/2

m<Z = 50degrees

Hence the measure of angle Z is 50degrees

Answer: 3 pens

Step-by-step explanation: The ratio of pencils to pens Monique has is 2:1, this means that for every 2 pencils Monique has she will have 1 pen. To plot this on a graph you can put one point at (2,1) and another point at (4,2)

The amount of X and Y that can give Adam the most utility is (αI/ Px) units of good X and (βI/ Py) units of good Y.

The Cobb-Douglas utility function represents a consumer's preferences towards two goods, X and Y. The function for Adam's preferences is given by:

U(x,y)=x α * y β, where α + β = 1. Given the price of good X is Px, the price of good Y is Py, and Adam's disposable income is I.

The total expenditure (E) for two goods will be:

E= PxX + PyY, Where X is the quantity of good X and Y is the quantity of good Y.

Adam's income constraint can be represented as:

I = PxX + PyY

We can rewrite the above expression as:

X = (I/ Px) - ((Py/Px)Y)

Thus, Adam's utility function can be written as:

U = X α * Y β

Substituting X with the expression we derived above, we get:

U = [(I/ Px) - ((Py/Px)Y)] α * Y β

To get the optimal consumption bundle, we need to maximize the utility function, which is given by:

MUx/ Px = α(Y/X)β

Muy/ Py = β(X/Y)α

Multiplying the two equations, we get:

MUx * Muy = αβ

Now, substituting the value of α + β = 1 in the above equation, we get:

MUx * Muy = α(1 - α)

Similarly, dividing the two equations, we get:

MUx / Muy = α/β

Now, we have two equations and two unknowns. We can solve them to get the values of X and Y, which maximize Adam's utility.

After solving, we get:

X = (αI / Px)

Y = (βI / Py)

Thus, the amount of X and Y that can give Adam the most utility is (αI/ Px) units of good X and (βI/ Py) units of good Y.

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From the image provided, it takes 8 minutes for the fish to complete one cycle or revolution of the wheel.

A full cycle or revolution is a 360° angle, a full rotation, and a complete turn such that it points back in the same direction.

We can see from the graphic that each step in one rotation takes one minute.

So there are three stages underwater in all. In each spin, the fish spends around 3 minutes beneath water.

Because the diameter is double the amplitude of the graph, as a result, the amplitude is four, and the diameter is eight units.

The general form of the cosine function is:

y (t) = 4Cos (πt/4) + 2

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Answer:

x = 1/2

Step-by-step explanation:

\( \frac{4}{7} x = \frac{2}{7} \\ \\ x = \frac{ \cancel2}{ \cancel7} \times \frac{ \cancel7}{ \cancel4 \: \: 2} \\ \\ x = \frac{1}{2} \)