How to solve 3 3/5 - 2/3?

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\(y = - \frac{2}{3}x + 5 \\ \)

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Thus the correct answer is the first one.

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Let me know if u want explanation buddy..

An equation for the function g(x) when g(x) = f(-x) is g(x) = -x/3 - 6, which is shown in the graph attached below.

In Mathematics, a reflection can be defined as a type of transformation which moves every point of the geometric figure by producing a flipped, but mirror image of the geometric figure.

In Geometry, a reflection across the y-axis (y = x) is given by this transformation rule (x, y) → (-x, y). This ultimately implies that, a reflection over the y-axis would maintain the same y-coordinate while the sign of the x-coordinate changes from positive to negative or negative to positive.

By reflecting the given function across the across the y-axis (y = x), we have the following:

f(x) = x/3 - 6

g(x) = f(-x)

g(x) = -x/3 - 6.

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The SI units for the quantities you mentioned are:

1. Length: The SI unit for length is the meter (m).

2. Mass: The SI unit for mass is the kilogram (kg).

3. Time: The SI unit for time is the second (s).

4. Electric current: The SI unit for electric current is the ampere (A).

5. Amount of substance: The SI unit for the amount of substance is the mole (mol).

6. Temperature: The SI unit for temperature is the kelvin (K).

7. Luminous intensity: The SI unit for luminous intensity is the candela (cd). An angstrom (symbol: Å) is a unit of length equal to 10^(-10) meters or 0.1 nanometers. It is often used to express the sizes of atoms and molecules.

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The net income for Griffin's Goat Farm, Inc., was \(\$184,340\).

The operating cash flow (OCF) for Kerber's Tennis Shop, we can use the following formula:

\(OCF = EBIT + Depreciation - Taxes + \triangle Working Capital\)

where EBIT is earnings before interest and taxes.

Calculate EBIT by subtracting interest expense from operating income:

EBIT = Operating Income - Interest Expense

We do not have the information for operating income, but we can use the fact that interest expense was. \(\$165,000\) to calculate EBIT.

EBIT = Interest Expense / (1 - Tax Rate)

= \(\$165,000 / (1 - 0)\)

= \(\$165,000\)

Calculate the change in working capital (Δ Working Capital). We are told that the company reduced its net working capital investment by \(\$69,000\), which means that working capital increased by  \(\$69,000\).

Therefore:

\(\triangle Working Capital = \$69,000\)

Now, we can calculate OCF:

OCF = EBIT + Depreciation - Taxes + Δ Working Capital

=\(\$165,000 + 0 - 0 +\ $69,000\)

=\(\$234,000\)

Therefore, the firm’s 2018 operating cash flow (OCF) was \(\$234,000\) .

To calculate the net income for Griffin's Goat Farm, we can use the following formula:

Net Income = EBIT - Interest Expense - Taxes

where EBIT is earnings before interest and taxes. We can calculate EBIT as:

EBIT = Sales - Costs - Depreciation

= \(\$686,000 - \$332,000 - \$65,000\)

=\(\$289,000\)

Next, we need to calculate taxes. We are given a tax rate of 24%, so:

Taxes = Tax Rate x (EBIT - Depreciation)

= \(0.24 \times (\$289,000 - \$65,000)= \$56,160\)

Now, we can calculate net income:

Net Income = EBIT - Interest Expense - Taxes

= \(\$289,000 - \$48,500 - \$56,160= \$184,340\)

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1. (x^2 + 8x – 1) ÷ (x + 4), the quotient is x + 4 and the remainder is -17.

2. (x^3 + 6x^2 – x – 30) ÷ (x-2), the quotient is x^2 + 8x + 15 and there is no remainder.

3. (4x^2 + 24x + 21) ÷ (x + 5), the quotient is 4x + 4 with a remainder of 1.

4. (2t^4 + t^3 + 5t^2 14t – 16) ÷ (t + 2), the quotient is 2t^3 - 3t^2 + 2t - 8 with a remainder of 6.

  x + 4 │ x^2 + 8x - 1

         │ x^2 + 4x

         │-------------

         │ 4x - 1

         │ 4x + 16

         │-------------

         │ -17

 x - 2 │ x^3 + 6x^2 - x - 30

        │ x^3 - 2x^2

        │-----------------

        │ 8x^2 - x

        │ 8x^2 - 16x

        │-------------

        │ 15x - 30

        │ 15x - 30

        │--------------

        │ 0

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Answer:

i think the answer is -33

Step-by-step explanation:

Answer:

It will return 31.5 ft

Step-by-step explanation:

Here, the function is as follows;

let the yard be represented as y and the f be the feet

It takes in yards and return feet

Mathematically, using the relation between the two;

So for every yards it takes in, it returns 3 times the value in feet

Thus, for 10.5 yards, what it will return will be;

10.5 * 3 = 31.5 ft

False. The weight of a variable in a standardized predictor environment does not necessarily indicate that the variable has a higher discriminating power.

Discriminating power is determined by the correlation of a predictor variable with the outcome variable. We can calculate the correlation between a predictor variable and an outcome variable using Pearson's correlation coefficient, which is represented by the formula:

r = (NΣXY - (ΣX)(ΣY)) / √[(NΣX2 - (ΣX)2)(NΣY2 - (ΣY)2)].

In this formula, N is the sample size, ΣX is the sum of the predictor variable, ΣY is the sum of the outcome variable, ΣXY is the sum of the products of the predictor and outcome variables, and ΣX2 and ΣY2 are the sums of the squares of the predictor and outcome variables, respectively. The Pearson's correlation coefficient ranges from -1 to +1, with +1 indicating perfect positive correlation, 0 indicating no correlation, and -1 indicating perfect negative correlation. A higher correlation coefficient indicates a higher discriminating power.

Therefore, the weight of a variable in a standardized predictor environment does not indicate whether or not the variable has a higher discriminating power; this is determined by the correlation between the predictor and outcome variables.

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Answer:

1.Line III is A, Line I is B, Line II is C; 2. 20 represents the Y-intercept, The 2 represents the slope

An example of an extraneous solution in math is solving the equation 1/(x−2) + 1/(x+2) = 4/(x−2)(x+2) for x.

An extraneous solution is a root of a transformed equation that is not the root of the original equation because it was excluded from the domain of the original equation.

Solve the equation 1/(x−2) + 1/(x+2) = 4/(x−2)(x+2) for x

1/(x−2) + 1/(x+2) = 4/(x−2)(x+2)

(x−2)(x+2)/(x−2) + (x−2)(x+2)/(x+2) = 4(x−2)(x+2)/(x−2)(x+2)

(x−2) + (x+2) = 4

2x = 4

x = 2

But 2 is excluded from the domain of the original equation because it would make the denominator of one of the fractions zero--and division by zero is not allowed. Therefore, it cannot be the root of the original equation. So, 2 is an extraneous solution. So, the equation has no solutions.

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The best function to get depth of water is cosine.

What is cosine?

Cosine is one of the primary mathematical trigonometric ratios. The ratio of the lengths of the side adjacent to the angle and the hypotenuse of a right-angled triangle is called the cosine function which varies as the angle varies. It is defined in the context of a right-angled triangle for acute angles.

The maximum value of cosine is at 0 to 2π.

Given, The highest tide is at t = 0

amplitude = (90-76)/2 = 13

center line is at y=(90+76)/2 = 83

period = 12, so k = π/6

minimum is at t=0, so

y = 13(cosπ/6t) + 83

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Answer:

6/5

Step-by-step explanation:

apply the slope formula: rise/run or y2-y1 / x2-x1

if you choose (2,-5) as your x1, y1

choose (7,1) as your x2, y2

(1-(-5)) / (7-2) = 6/5

Answer:

y2-y1/x2-x1

=1-(-5)/7-2

=1+5/7-2

=6/5

Step-by-step explanation:

First write down the formula.

Indicate your coordinates(x1, y1) (x2, y2)

Find the gradient /slope

The abore solution will help you

Answer:

f(g(x)) = 9x² - 6x - 4

Step-by-step explanation:

f(g(x) )

= f(3x - 1)

= (3x - 1)² - 5 ← expand factor using FOIL

= 9x² - 6x + 1 - 5

= 9x² - 6x - 4

Answer:

1: $5

2: 7

3: 18

4: 17

5: 2

6: 1,029

Step-by-step explanation:

\(m \cdot n = \sqrt{m^2 -n^2}\\\\\text{When m =5 and n =3,}\\\\\\5\cdot 3 = \sqrt{5^2 -3^2} =\sqrt{25 -9} = \sqrt{16} = 4\)

\(\huge\text{Hey there!}\)

\(\huge\textbf{Assuming:}\)

\(\mathbf{m\times n = \sqrt{(m^2 - n^2)}}\)

\(\huge\textbf{Solving:}\)

\(\mathbf{\rightarrow 5\times 3 = \sqrt{(5^2 - 3^2)}}\)

\(\mathbf{\rightarrow 15 = \sqrt{(5\times5 - 3\times3)}}\)

\(\mathbf{\rightarrow 15 = \sqrt{(25 - 9)}}\)

\(\mathbf{\rightarrow 15 = \sqrt{16}}\)

\(\mathbf{15\neq4}\)

\(\huge\textbf{Thus, this answer should be:}\)

\(\huge\boxed{\boxed{\textsf{This statement is most likely: \boxed{\textsf{FALSE}}}}}\huge\checkmark\)

\(\huge\text{Good luck on your assignment \& enjoy your day!}\)

\(\frak{Amphitrite1040:)}\)

Answer:

y=1/5x-1

Step-by-step explanation:

Answer:

\(y=\frac{x}{5}\)

Step-by-step explanation:

hope this helps

Answer:

c

Step-by-step explanation:

a = probably 90°

b = 180°

c = probably less than 90°

d = probably more than 90° ( > 90°)

Answer:

c

Step-by-step explanation:

Ais 90 degrees

B is 180

C is less than 90, looks around 45 so 51 isnt that far off

D is between 90 and 180

The probability of winning $1 in the Mongo Milions lottery game is approximately 0.000365.

To determine the probability of winning $1, we need to consider the total number of possible outcomes and the number of favorable outcomes.

For the 5 white numbers, there are a total of 60 numbers in the pool. Therefore, the number of ways to select 5 numbers out of 60 is given by the combination formula, denoted as "C," which is calculated as C(60, 5) = 60! / (5! × (60 - 5)!).

For the Mongo number, there are 20 numbers in the pool, so there is only one way to select it.

To win $1, we need to match one of the winning combinations. There are different possible winning combinations, and each combination has a certain number of ways it can occur. Let's denote the number of ways a specific winning combination can occur as "W."

The probability of winning $1 is then calculated as P = (W / C(60, 5)) × (1 / 20).

Since we want the probability rounded to 6 decimal places, we can substitute the values into the formula and round the result to the desired precision. The resulting probability is approximately 0.000365.

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Answer:

Step-by-step explanation:

The area of a Trapezoid is

Area = (b1 + b2)*h/2

b1 and b2 are the two parallel sides of a trapezoid. In this problem, they are both given.

You are trying to find h (which is x here).

b1 = 13

b2 = 6.4

Area = 78

h = x = ?

78 = (6.4 + 13) * x / 2              Multiply both sides by 2

156 = (6.4 + 13) * x                  Combine the numbers in the  brackets

156 = 19.4 * x                          Divide by 19.4

156 / 19.4 = x

x = 8.04

====================================================

Explanation:

The angle adjacent to the 5 degree angle is 90-5 = 85 degrees

Or you could note that 85+5 = 90.

Then from here you'd use the tangent ratio

tan(angle) = opposite/adjacent

tan(85) = 4629/x

x*tan(85) = 4629

x = 4629/tan(85)

x = 404.985 approximately

x = 405 meters when rounding to the nearest whole number.

Sasha should use 2 desired outcomes in her probability calculation to determine that she has a 1/3 chance of winning the game.

To calculate Sasha's probability of winning, we need to determine how many desired outcomes she has. In this game, Sasha needs to spin a number higher than both of her friends' spins, which means she needs to spin a number greater than 1 and 4.

Let's analyze the spinner pictured. From the image, we can see that the spinner has numbers ranging from 1 to 6. Since Sasha needs to spin a number higher than 4, she has two options: 5 or 6.

Now, let's consider the desired outcomes. Sasha has two desired outcomes, which are spinning a 5 or spinning a 6. If she spins either of these numbers, she will have a number higher than both of her friends and win the game.

To calculate Sasha's probability of winning, we need to divide the number of desired outcomes by the total number of possible outcomes. In this case, the total number of possible outcomes is the number of sections on the spinner, which is 6.

Sasha's probability of winning is 2 desired outcomes divided by 6 total outcomes, which simplifies to 1/3.

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.

The global minimum occurs at x = 4 and the minimum value is f(x) = 8. There is no global maximum as the function increases without bound as x approaches 0 or infinity.

The global minimum and maximum values for the function f(x) = 16/x + x for x > 0 are as follows:

The global minimum is at (4, 8) and the global maximum is NA.

To find the global minimum and maximum, first find the critical points by taking the first derivative of the function and setting it equal to zero. The derivative of f(x) is f'(x) = -16/x² + 1. Setting f'(x) equal to 0:

-16/x² + 1 = 0
x² = 16
x = ±4

Since x > 0, the only critical point is x = 4. Next, evaluate f(x) at this point:

f(4) = 16/4 + 4 = 4 + 4 = 8

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Answer:

1560

Step-by-step explanation:

25 x 8 x 10 - 22 x 5 x 4 = 2000 - 440 = 1560

Answer:

3/2

Step-by-step explanation:

write out equation

x^2*6+x=15

factor

6x^2+x-15=0

(2x-3)(3x+5)=0

x=3/2, x=-5/3

-5/3 is negative, so 3/2 is the answer

The quadratic equation is solved and the number is x = 3/2

A quadratic equation is a second-order polynomial equation in a single variable x , ax² + bx + c=0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

The roots of the quadratic equations are

x = [ -b ± √ ( b² - 4ac ) ] / ( 2a )

where ( b² - 4ac ) is the discriminant

when ( b² - 4ac ) is positive, we get two real solutions

when discriminant is zero we get just one real solution (both answers are the same)

when discriminant is negative we get a pair of complex solutions

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

David thinks of a positive number

Let the number be x

He squares it and multiplies the result by 6.

He then adds on his original number and gets an answer of 15

x + 6x² = 15

6x² + x - 15 = 0

On solving the quadratic , we get

(2x - 3)(3x + 5) = 0

2x - 3 = 0 or 3x + 5 = 0

Solving for x in each case gives:

2x = 3 or 3x = -5

x = 3/2 or x = -5/3

Since x is a positive number, the only valid solution is

x = 3/2

Hence , David is thinking of the number 3/2

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Answer:

Janelle rides her bike at a rate of 0.25 km per minute.

Step-by-step explanation:

15 divided by 60 = 0.25

(I'm assuming this is an open question, if there are choices then put them in the comments and I'll edit the answer)

Answer:

y=-3x-10

Step-by-step explanation:

Answer: 60

8x15 / 2

Step-by-step explanation:

Answer:

40 units

Step-by-step explanation:

Using Pythagoras Theorem to find the hypotenuse:

\( \sqrt{ {15}^{2} + {8}^{2} } \)

\( = \sqrt{289} \)

= 17 units

The perimeter

= 15+8+17

= 40 units

The total number of dots on all the side faces (excluding the bottom face) is 16

If the bottom face of the dice rolled by Ramu shows 3 dots, we can determine the total number of dots on all the side faces (excluding the bottom face) by considering the fact that the opposite sides of a standard six-sided die always add up to 7.

The bottom face showing 3 dots means that the top face, which is not visible, would have (7 - 3) = 4 dots. Since the opposite sides add up to 7, the side faces adjacent to the bottom face will also have 4 dots each.

To calculate the total number of dots on all the side faces, we need to multiply the number of side faces (four in this case) by the number of dots on each side face:

Total number of dots on side faces = 4 (number of side faces) × 4 (number of dots on each side face) = 16.

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In the regression model of student grades, the nine categories of business courses taken (acc, fin, ecn, mgt, mkt, mis, org, pom, qmm) would be coded by including nine binary (0 or 1) predictors in the regression.

To incorporate the categorical variable of business courses taken in the regression model, a technique called "one-hot encoding" is commonly used. This involves creating binary (0 or 1) predictor variables for each category.

For example, if a student has taken the course "acc" (accounting), the corresponding predictor variable "acc" would be assigned a value of 1, and the rest of the predictor variables for the other courses would be assigned a value of 0.

This process is repeated for each category, resulting in nine binary predictor variables, each representing a specific business course.

To account for the nine categories of business courses taken in the regression model of student grades, one-hot encoding is applied. This approach involves creating nine binary (0 or 1) predictor variables, where each variable represents a particular business course category.

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