Answers
Given,
Electron are positive and the charge can be considered as q.
Proton are negative and the charge can be considered as -Q.
Thus the coloumb's law is
\(\begin{gathered} F=k\frac{q(-Q)}{r^2} \\ \Rightarrow F=-k\frac{qQ}{r^2} \end{gathered}\)The answer is:
\(F=-k\frac{qQ}{r^2}\)Related Questions
A machine has a velocity ratio of 5 and the efficiency is 80% what effort would be needed to lift a load of 200N
Answers
Explanation:
To determine the effort needed to lift a load of 200N, given a velocity ratio of 5 and an efficiency of 80%, we can use the formula:
Efficiency = (Output Work / Input Work) * 100
Efficiency can also be calculated as the ratio of the output force to the input force. In this case, the output force is the load being lifted (200N), and the input force is the effort required.
Given that the velocity ratio is 5, it means that for every 5 units of distance the effort moves, the load moves 1 unit of distance. This implies that the effort is exerted over a greater distance than the load.
Let's denote the effort force as "E" and the distance moved by the effort as "dE." Similarly, the load force is "L," and the distance moved by the load is "dL."
Using the velocity ratio, we have the following relationship:
dE / dL = 5
Now, we can calculate the input work (Wi) and the output work (Wo):
Input Work (Wi) = Effort (E) * Distance moved by the effort (dE)
Output Work (Wo) = Load (L) * Distance moved by the load (dL)
Given that the efficiency is 80%, we can rewrite the formula for efficiency as:
0.80 = (Wo / Wi) * 100
Now, let's solve for the effort (E) using the given values:
Load (L) = 200N
Efficiency = 0.80
Velocity Ratio = 5
First, calculate the output work (Wo):
Wo = Load (L) * Distance moved by the load (dL)
Since the velocity ratio is 5, the distance moved by the load (dL) will be 1/5 of the distance moved by the effort (dE):
dL = (1/5) * dE
Wo = L * (1/5) * dE
Wo = 200N * (1/5) * dE
Wo = 40N * dE
Next, calculate the input work (Wi):
Wi = Effort (E) * Distance moved by the effort (dE)
Wi = E * dE
Now, substitute the values into the efficiency formula:
0.80 = (Wo / Wi) * 100
0.80 = (40N * dE) / (E * dE) * 100
0.80 = 40 / E * 100
0.80 * E = 40
E = 40 / 0.80
E = 50N
Therefore, the effort needed to lift a load of 200N with a velocity ratio of 5 and an efficiency of 80% is 50N.
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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A man is attempting to lift a crate with a double-pulley system, as shown. A single rope is routed from the ceiling, through the two pulleys, and to where the man pulls on it. The crate has mass m2 = 64 kg, and the man has m1 = 75 kg. He pulls downward on the rope with a force of magnitude F = 563 N. The pulleys are both massless and frictionless, and the rope is ideal.
(a) Let T be the tension in the rope. Enter an expression for the sum of the forces in the y direction acting on the crate.
(b) Using the results from above, write an expression for the crate's vertical acceleration, acrate.
(c) What is the magnitude, in newtons, of the tension force, T?
(d) What is the acceleration, in meters per squared second, of the crate?
Answers
a) The sum of the forces in the y direction acting on the crate
T - m₂ * g = 0
b) The crate's vertical acceleration
= (T - m₂ * g) / m₂
c) magnitude of tension in the rope
T = 738 N
d) The acceleration of the crate
9.3 m/s².
How to write the expression for the sum of the forcesa) The sum of the forces in the y direction acting on the crate can be expressed as:
T - m2 * g = 0
where
T is the tension in the rope,
m2 is the mass of the crate, and
g is the acceleration due to gravity (9.8 m/s^2).
b) The crate's vertical acceleration can be expressed as:
a crate = (T - m2 * g) / m2
c) The tension in the rope can be found by using the force that the man is applying:
F = T - m1 * g = 563 N
T = m1 * g + F = 75 kg * 9.8 m/s^2 + 563 N = 738 N
d) The acceleration of the crate can be calculated by substituting the value of T from above:
a crate = (T - m2 * g) / m2 = (738 N - 64 kg * 9.8 m/s^2) / 64 kg = 9.3 m/s^2.
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Question 10 of 25
In recent years, assistive technologies have been developed to give people
with disabilities equal access to resources. Examples include wheelchair
ramps, voice-recognition software, and screen readers. Which statement best
explains how societal demand guided the development of these
technologies?
A. Engineers developed assistive technologies first and then began a
public-awareness campaign to educate people on how the
technologies can be used to provide equal access.
B. Businesses recognized the lack of equality for people with
disabilities and lobbied the government to make laws that required
the implementation of assistive technologies.
C. When new assistive technologies became available, consumers
began to demand their inclusion in all places of business,
D. Engineers developed and improved solutions in response to
consumer demand for equal access for people with disabilities.
Answers
Answer:engineers developed and improved solutions in response to consumer demand for equal access for people with disabilities.
Explanation:
Apex
Two identical 0.25 kg balls are involved in a head-on collision. Ball A is initially travelling at 3.5 m/s, and ball B is initally at rest. Determine the velocity of each ball after the collision.
Answers
Answer:
a) mv(final):<0,0,0> minus mv(initial):<25,0,0> = <-25,0,0>
b) mv(final):<25,0,0> minus mv(initial):<0,0,0> = <25,0,0>
c) conservation of momentum makes it <0,0,0>
for a-b-c, momentum_system + momentum_surroundings = 0
Explanation:
Hope this helps
The velocity of each ball after the collision is 1.75 m/s
Law of conservation of momentum states that:
Total momentum before collision = Total momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)v
Where m₁, m₂ is the mass of object, u₁, u₂ is the initial velocity before collision and v is the final velocity after collision
Given that: m₁ = m₂ = 0.25 kg, u₁ = 3.5 m/s, u₂ = 0, hence:
0.25(3.5) + 0.25(0) = (0.25 + 0.25)v
v = 1.75 m/s
The velocity of each ball after the collision is 1.75 m/s
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I need the answer asap everyone have a good day bye
Answers
Im pretty sure its A cuz is closer to the earth.
Two spherical shells have a common center. The inner shell has radius R1 = 5.00cm and charge q1=+5.00×10^−6C ; the outer shell has radius R2 = 15.0cm and charge q2=−6.00×10^−6C . Both charges are spread uniformly over the shell surface. Take V=0 at a large distance from the shells.
Part A) What is the electric potential due to the two shells at the distance r =2.50 c from their common center.
part B) What is the electric potential due to the two shells at the distance r= 10.0 cm from their common center.
Answers
Answer:
Explanation:
Part A:
Using the formula for electric potential due to a charged spherical shell:
V1 = kq1/R1 and V2 = kq2/R2
where k is the Coulomb constant.
For r < R1, the electric potential due to both shells is:
V = V1 + V2 = kq1/R1 + kq2/R2
For R1 < r < R2, the electric potential due to the outer shell is:
V = V2 = kq2/R2
For r > R2, the electric potential due to both shells is:
V = V1 + V2 = kq1/r + kq2/R2
Substituting the given values, we get:
V = (9.0x10^9 Nm^2/C^2)(5.00x10^-6 C)/0.025 m + (9.0x10^9 Nm^2/C^2)(-6.00x10^-6 C)/0.15 m
V = -4.32x10^5 V
Therefore, the electric potential due to the two shells at a distance of 2.50 cm from their common center is -4.32x10^5 V.
Part B:
For r < R1, the electric potential due to both shells is:
V = V1 + V2 = kq1/R1 + kq2/R2
For R1 < r < R2, the electric potential due to both shells is:
V = V1 + V2 = kq1/r + kq2/R2
For r > R2, the electric potential due to both shells is:
V = V1 + V2 = kq1/r + kq2/r
Substituting the given values, we get:
V = (9.0x10^9 Nm^2/C^2)(5.00x10^-6 C)/0.1 m + (9.0x10^9 Nm^2/C^2)(-6.00x10^-6 C)/0.1 m
V = 4.80x10^5 V
Therefore, the electric potential due to the two shells at a distance of 10.0 cm from their common center is 4.80x10^5 V.
A horizontal force is applied to a 4.0 kg box. The box starts from rest moves a horizontal distance of 8.0 meters and obtains a velocity of 6.0 m/s. The system is frictionless. What is the horizontal force?
Answers
The horizontal force applied to the 4.0 Kg box is 9 N
We'll begin by obtaining the acceleration of the box. This can be obtained as follow:
Initial velocity (u) = 0 m/sFinal velocity (v) = 6.0 m/s Distance (s) = 8.0 mAcceleration (a) =?v² = u² + 2as
6² = 0² + (2 × a × 8)
36 = 0 + 16a
36 = 16a
Divide both sides by 16
a = 36 / 16
a = 2.25 m/s²
How to determine the horizontal forceThe horizontal force can be obtained as follow:
Mass (m) = 4 KgAcceleration (a) = 2.25 m/s²Horizontal force (F) =?Horizontal force = mass × acceleration
Horizontal force = 4 × 2.25
Horizontal force = 9 N
This, the horizontal force exerted on the box is 9 N
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What is a distinguishing feature in a city known as?
OA) hot spot
OB) landmark
C) state legend
OD) state park
Answers
A defining characteristic of a city is often referred to as a "landmark." A landmark is a distinctive feature or building that stands out and is used to identify or represent a location. Landmarks can be man-made, such as structures, monuments, or historical locations, or they can be natural, like mountains, rivers, or lakes.
Landmarks are significant tourist destinations for both locals and visitors because they frequently have historical, cultural, or architectural value. They can serve as a symbol of a city's identity, history, and personality and end up being recognised as the place's iconic symbols. Landmarks might be notable buildings, statues, cathedrals, museums, or bridges that have come to symbolise the city in which they are located.
Therefore, option (OB) "landmark" is the term used to describe a distinguishing feature in a city.
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Question 28 of 30The graph below shows the conservation of energy for a skydiver jumping outof a plane and landing safely on the ground. Which energy is represented byline A?сAEnergy (kJ)BDistance (m)A. Potential energyB. Kinetic energy
Answers
Answer:
Explanation:
Potential energy depends on the height of the object above the ground. As the height decreases, the potential energy decreases. Looking at line A, the energy is decreasing as the distance is increasing. Thus, the energy represented by line A is
A. Potential energy
For the circuit shown, the input DC source voltage, E=15V, and node "d" selected as the reference node, calculate the current, I, and the voltage at node "a", node "b", and node "c". Calculate the resistor voltages, V_ab, V_bc, V_cd across resistors R1, R2 and R3 respectively.
Answers
Assuming the resistors have the same resistance, R, the current I can be calculated using Ohm's Law as:I = E/R = 15V/R
What is Ohm's Law ?Ohm's Law is an important electrical principle that states that the current flowing through a conductor between two points is directly proportional to the voltage applied across the two points. In other words, the current is equal to the voltage divided by the resistance. This law was discovered by German physicist Georg Ohm in 1827 and is now one of the most fundamental laws of electricity. It is used to calculate the amount of current, voltage, and resistance in a circuit. Ohm's law is used to calculate the power dissipated in the circuit and helps engineers to understand the behavior of an electrical circuit. Ohm's law is used in many applications for designing, analyzing, and troubleshooting electrical circuits. It is also used to determine the amount of current that can safely pass through a conductor without causing damage.
The voltage at node "a" is equal to the voltage at node "d" since they are connected by a wire, so V_a = 15V.
The voltage at node "b" can be calculated using the Voltage Divider Rule as
V_b = V_d * (R2/(R1+R2)) = 15V * (R2/(R1+R2))
Similarly, the voltage at node "c" can be calculated as
V_c = V_d * (R3/(R2+R3)) = 15V * (R3/(R2+R3))
Finally, the resistor voltages can be calculated as
V_ab = V_a - V_b = 15V - V_b
V_bc = V_b - V_c = V_b - V_c
V_cd = V_c - V_d = V_c - 15V
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Why is it important that an astronomer studies physics?
Answers
Answer:
Astrophysicists study the physics of the universe. “Astrophysics” is a term that is often used interchangeably with “astronomy.” Atomic, molecular, and optical physicists study atoms, simple molecules, electrons, and light, as well as the interactions among them
Explanation:
A frying pan is connected to a 1500 volt circuit. If the resistance of the frying pan is 25 ohms, how many amperes does the frying pan draw?
Answers
The current (in amperes) the frying pan draws from the 500 volt circuit, given that it has a resistance of 25 ohms is 60 amperes
How do i determine the current drawn by the frying pan?From the question given above, the following data were obtained:
Voltage of circuit (V) = 1500 V Resistance of frying pan (R) = 5 Ω Current (I) =?The current drawn by the frying pan can be obtained as follow:
Voltage (V) = Current (I) × resistance (R)
Inputting the given parameters, we have:
1500 = Current × 25
Divide both sides by 25
Current = 1500 / 25
Current = 60 amperes
Thus, from the above calculation we can conclude that the current drawn by the frying pan is 60 amperes
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please answer question 1.
Answers
Answer:
.
Explanation:
A ball with a mass of 275 g is dropped from rest, hits the floor, and rebounds upward. If the ball hits the floor with a speed of 2.60 m/s, rebounds with a speed of 1.84 m/s, and is in contact with the floor for 1.40 ms,determine the following.
(a) magnitude of the change in the ball's momentum (Let up be in the positive j hat direction.)
_______________kg
Answers
Answer:
-0.209 kg.m/s
Explanation:
The mass of the ball, m = 275g or 0.275 kg
Speed or velocity, v = 2.60 m/s
Momentum, P = mv
Momentum when velocity is 2.60 = 0.275 x 2.60 = 0.715 kg.m/s
Speed or velocity, v = 1.84 m/s
Momentum, P = mv
Momentum when velocity is 1.84= 0.275 x 1.84 = 0.506 kg.m/s
Change in magnitude = 0.506 - 0.715 = -0.209 kg.m/s
A bowling ball has a mass of 10 kilograms. A tennis ball has a mass of 0.08 kilogram. How much inertia does the bowling ball have compared to the tennis ball?
Newton's First Law is asked to be used here.
Answers
Answer:
A bowling ball has a mass of 10 kilograms. A tennis ball has a mass of 0.08 kg. How much inertia does the bowling ball have compared to the tennis ball? 10 kg - 0.08 kg = 10.80 kg Since the bowling ball has more mass, naturally it has more inertia since inertia is a quantity that is solely dependent upon the mass
Explanation:
the material which obey hooke's law is called.....................
Answers
The material that obeys Hooke's law is elastic material.
What is Hooke's law all about?Hooke's Law says that the force needed to extend or compress a spring by some distance scales linearly with respect to that distance. And it is known for the formula F = kX
F is the force, x is the deformation, and k is the spring constant.
Elastic materials are able to return to their original shape after being deformed by a force.
The amount of deformation is noted to be directly proportional to the amount of force applied.
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who wants to be study partnerssss for math?
Answers
Sure, that sounds great! What kind of math are we studying? Do you have any specific topics you want to focus on?
What is topic?A topic is a subject or issue that forms the basis of a discussion, paper, speech, or other form of communication. It is typically used to focus the ideas and facts presented in the communication, making it easier for the audience to understand and remember. It can be an essay, a research paper, a presentation, or any other type of communication that is intended to present and discuss a particular idea. By choosing a specific topic, the author is able to narrow down the scope of the discussion and focus on the main ideas more efficiently.
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how long will it take to travel 200km traveling 100 dm/s?
Answers
ANSWER:
20000 seconds
STEP-BY-STEP EXPLANATION:
We can calculate time by calculating the ratio between distance and speed, but to do this, they must have the same units. We can do the calculation knowing that the conversion factor corresponds to the fact that 1 kilometer is equal to 10000 decimeters, therefore:
\(200km\cdot\frac{10000dm}{1km}=2\cdot10^6dm\)Now, we calculate the time:
\(\begin{gathered} t=\frac{s}{v}=\frac{2\cdot10^6\text{ dm}}{100\text{ dm/s}} \\ t=20000\text{ s} \end{gathered}\)So it takes a total of 20000 seconds
Newton’s second law of motion on a flying chair swing ride
Answers
The ride is powered by a motor that makes the swing ride spin around the centre axis of the ride. The chairs move in a circle at a moderate speed. The forces acting on a swing rider are the tension in the chain and the weight of the rider.
Explanation:When the swing moves from the lowest point up to either peak, the main force acting is momentum; and when the swing falls from either peak to its lowest point, the main force acting is gravity. The movement of the pendulum is said to be simple harmonic motion because the restoring force acts directly proportional to the displacement and is directed towards the equilibrium position. Hence, the movement of the Pendulum is simple harmonic motion.
An Airplane moves 70 m/s as it travels around a vertical circular loop which has a 3 km radius. What is the magnitude of the net force on the 95 kg pilot at the bottom of this loop?
Answers
Answer:
155.17N.
Explanation:
The magnitude of the net force is expressed as;
F = mv²/r where;
m is the mass
v is the velocity of the airplane
r is the radius of the loop
Given
m = 95kg
v = 70m/s
r = 3km = 3000m
Required
Magnitude of the net force
F = 95*70²/3000
F = 95*4900/3000
F = 95*49/30
F = 4655/30
F = 155.17N
Hence the magnitude of the net force on the 95 kg pilot at the bottom of this loop is 155.17N.
The net force on the pilot is 1551.67 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the magnitude of the net force at the bottom of the loop, we use the formula below.
Formula:
F = mv²/r............. Equation 1Where:
m = mass of the pilotv = velocity of the Airplaner = radius of the loopF = net force on the pilot.From the question,
Given:
m = 95 kgr = 3 km = 3000 mv = 70 m/sSubstitute these values into equation 1
F = 95(70²)/300F = 465500/300F = 1551.67 NHence, the net force on the pilot is 1551.67 N.
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What is the final temperature of 0.3kg of water initially at 20 Celsius after 35 KJ Of heat is added?
Answers
Answer:
Option A. 48°C
Explanation:
The following data were obtained from the question:
Mass (m) = 0.3 Kg
Initial temperature (T1) = 20°C
Heat (Q) added = 35 KJ
Specific heat capacity (C) = 4.18 KJ/Kg°C
Final temperature (T2) =..?
The final temperature of water can be obtained as follow:
Q = MC(T2 – T1)
35 = 0.3 x 4.18 (T2 – 20)
35 = 1.254 (T2 – 20)
Clear the bracket
35 = 1.254T2 – 25.08
Collect like terms
1254T2 = 35 + 25.08
1.254T2 = 60.08
Divide both side by the coefficient of T2 i.e 1.254
T2 = 60.08/1.254
T2 = 47.9 ≈ 48°C
Therefore, the final temperature of the water is 48°C.
The key insight that Bohr introduced to his model of the atom was that the angular momentum of the electron orbiting the nucleus was quantized. He introduced the postulate that the angular momentum could only come in quantities of nh/(2π), where h is Planck's constant and n is a nonnegative integer (0,1,2,3,…). Given this postulate, what are the allowable values for the velocity v of the electron in the Bohr atom? Recall that, in circular motion, angular momentum is given by the formula L= mvr.
Answers
Answer:
v = \(n \frac{\hbar }{m r}\)
the sppedof the electron is also quantized
Explanation:
The angular momentum of a rotating body is
L = m v r
in Bohr's atomic model the quantization postulate is that the angular momentum is equal to
L = n \(\hbar\)
we substitute
n \(\hbar\) = m v r
v = \(n \frac{\hbar }{m r}\)
where n is an integer.
Therefore, the sppedof the electron is also quantized, that is, sol has some discrete values.
PLS HELP!!
1. Radon-222 decays with a half-life of 3.82 days. If an initial sample of the element contains 1000 atoms, it takes ___ days for that sample to decay down to 125 atoms.
a. 2 days
b. 3 days
c. 4 days
d. 5 days
Answers
Answer: 3 days
Explanation:
help me i cant solve it
Answers
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What is the precision (relative error) of the centripetal force divided by the mass if the velocity and the radius are each determined with a precision of 1%
Answers
The precision (relative error) of the centripetal force is 1%.
Relative errorThis is the error in measurement of a variable obtained in comparison with other variables.
F = mv²/r
where;
F is centripetal forcem is mass v is velocityr is radiusF/m = v²/r
F/m = (0.01v)²/(0.01r)
F/m = 0.01v²/r
F/m = 1%(v²/r)
Thus, the precision (relative error) of the centripetal force is 1%.
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3 women push a stalled car. Each woman pushes with a 425 N force. What is the mass of the car if the car accelerates at 0.85 m/s2?
Answers
Answer:
1500kg
Explanation:
Assuming that the women push the car in the same direction, then the total force is:
Fnet = 425 N ⋅ 3
= 1275 N
To find the mass, we use Newton's second law of motion, which states that,
F = ma
where:
·F is the force applied in newtons
·m is the mass of the object in kilograms
·a is the acceleration of the object in meters per second squared.
So we get:
F
m= ⁻⁻⁻⁻⁻
a
1275N
= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
0.85 m/s²
= 1500 kg
An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?
Answers
The speed of the artillery shell when it hits its target is 100 m/s.
Given:
Initial vertical displacement (y) = 200 m
Vertical displacement at 100 m in the air (y') = 100 m
Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)
Using the equation for vertical displacement in projectile motion:
y' = vy^2 / (2g),
where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).
100 m = vy^2 / (2 * 9.8 m/s^2),
vy^2 = 100 m * 2 * 9.8 m/s^2,
vy^2 = 1960 m^2/s^2,
vy = sqrt(1960) m/s,
vy ≈ 44.27 m/s.
Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.
Hence, the speed of the artillery shell when it hits its target is 100 m/s.
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The way roughness of surfaces affects kinetic friction is called the __________ of kinetic friction?
Answers
Answer:
coefficient
Explanation:
simple but not plagiarized answer for "what is forces and motion?"
Answers
He used all his force in opening the window.
MOTION-the action or process of moving or of changing place or position; movement.