Hydrolysis of amides only occurs at extreme temperatures with strong acids because: a. Amides are very stable b. Amides are very reactive c. Amides are very polar d. Amides are very acidic

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Answer 1

The hydrolysis of amides only occurs at extreme temperatures with strong acids because amides are very stable compounds. The carbonyl group of an amide is highly electronegative, which makes it difficult for a nucleophile to attack and break the bond.

Therefore, more detailed conditions such as high temperatures and strong acids are required to facilitate the hydrolysis reaction. Amides are also very polar compounds, but their polarity does not play a significant role in the hydrolysis reaction.

Additionally, amides are not acidic compounds, so option d is not a valid explanation for why hydrolysis only occurs under specific conditions.

The reason hydrolysis of amides only occurs at extreme temperatures with strong acids is because:

a. Amides are very stable.

Amides have a resonance structure that contributes to their stability, making it more difficult for them to undergo hydrolysis under mild conditions. Extreme temperatures and strong acids are required to break the amide bond and facilitate hydrolysis.

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Related Questions

A sled sliding on a flat, Icy surface with a constant acceleration is best described by

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A sled sliding on a flat, icy surface with a constant acceleration is best described by Third Law Motion

What is acceleration?

Acceleration can be defined as the rate of change of velocity. When an object moves in a circular path at a constant speed it is still accelerating because the direction of its velocity is changing.

There three types of acceleration such as:

Uniform accelerationnon-uniform acceleration average acceleration

Therefore newton's third law said that If an object A exerts a force on object B then object B must exert a force of equal magnitude and opposite direction back on object A.

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An analyst was preparing standard solutions. While transferring the solid analyte to the volumetric flask, some amount of the solid stuck to the weigh paper and was not transferred. The measured concentrations came out a bit low for this solution. This is an example of:

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The phenomenon described in the given question, where some amount of the solid stuck to the weigh paper and was not transferred, is an example of a volumetric error in the preparation of standard solutions.

A standard solution is a solution with a precisely known concentration of an element or a substance. They are prepared to a specific concentration by dissolving a known quantity of a pure substance in a particular solvent in a volumetric flask.

Volumetric errors are a type of systematic error that occurs when preparing standard solutions. They occur due to an error in the volume of solution added or when some of the solute gets lost during the transfer process. As a result, the measured concentration comes out a bit low for this solution.

To avoid such errors, it is essential to pay close attention to the precise amount of the analyte used and be careful while transferring it to the volumetric flask. Any loss of the solid during the transfer process will result in an incorrect concentration of the solution and can lead to incorrect results.

Thus, the correct answers is volumetric error.

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What is the molar concentration a a 12 % sodium chloride solution (MW 58.5)

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The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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Which reagent(s) will produce a diol via syn-addition of an alkene?
o KMnO4/OH
o mCPBA only
o H3O+/H2O
o mCPBA with OH/H2O

Answers

In reference to the given question, the reagent that can produce a diol via syn-addition of an alkene is \(KMnO_4/OH\).

In chemistry, a reagent is a substance or compound that is added to a system to cause a chemical reaction or to test for the presence or absence of a certain substance. Reagents can be used in a variety of chemical reactions, including synthesis, degradation, and analysis.

Reagents can be either inorganic or organic compounds, and they can be used in a variety of forms, including solutions, gases, solids, or suspensions. Some common examples of reagents include acids, bases, oxidizing agents, reducing agents, catalysts, and indicators. The choice of reagent used in a chemical reaction or analysis depends on the specific goals of the experiment and the chemical properties of the system being studied.

Reagents for Syn-Addition of Alkenes and Formation of Diols.

\(KMnO_4/OH\) is a strong oxidizing agent that can perform syn-addition of hydroxide ions (OH-) to an alkene, resulting in the formation of a diol. This reaction is known as the "vicinal diol formation" or "dihydroxylation" reaction.

mCPBA (meta-chloroperoxybenzoic acid) is a powerful oxidant that can perform epoxidation of an alkene, resulting in the formation of an epoxide. It cannot produce a diol.

\(H_3O^+/H_2O\) is an acid-catalyzed hydration reaction, which can produce a single alcohol molecule from an alkene. It cannot produce a diol.

mCPBA with \(OH/H_2O\) can produce an epoxide and a single alcohol molecule but not a diol

Hence, the reagent that can produce a diol via syn-addition of an alkene is \(KMnO_4/OH\)

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Why might you want to heat a reaction? More than one answer may be correct. To increase the rate of the reaction. To evaporate the solvent more quickly To increase the solubility of the reagents. To overcome the activation energy for the reaction. .1 To decrease the rate of the desired reaction.

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We might want to heat a reaction :To increase the rate of the reaction, to evaporate the solvent more quickly ,to increase the solubility of the reagents and  to overcome the activation energy for the reaction.

The average reaction rate of the reactant molecules increases as the temperature rises. The number of molecules that are able to react quickly rises as more molecules move more quickly, hastening the creation of products.

For chemical processes to be scaled up safely and effectively, the heat of reaction, also known as reaction enthalpy, is a crucial element. The energy that is either released or absorbed when chemicals are changed in a chemical reaction is known as the heat of reaction. It explains how the energy content changes when reactants become products. The majority of reactions carried out in the chemical and pharmaceutical industries are exothermic, although a reaction can also be endothermic (heat absorption). One of the thermodynamic parameters utilized in chemical development, scale-up, and safety to scale processes from the lab scale to manufacturing is the heat of reaction, among others. The heat of reaction, also known as reaction enthalpy, is commonly given as either specific or molar enthalpy in KJ/Kg or KJ/L.

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Complete these sentences by selecting the correct answers from the drop-down menus. After one half-life, % of the atoms will change to a stable isotope and % will remain radioactive. After three half-lives, % of the atoms will change to a stable isotope and % will remain radioactive.

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After one half life, 50% of the atoms will change to a stable isotope.

After one half life, 50% of the atoms will remain radioactive.

After three half lives, 87.5% of the atoms will change to stable isotope.

After three half lives, 12.5% of the atoms will remain radioactive.

When the initial value of any compound is 100%, after one - half it will reduce to 50%, after the second half -life, it will reduce to 25%, after third half it will reduce to 12.5%.

Half- life may be described as the time required for the radioactivity of a specified isotope to drop to half its initial value.

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If 1 egg and 1/3 cup of oil are needed for each bag of brownie mix, how many bags of brownie mix do you need if you want to use up all 3 eggs and 1 cup of oil?

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The amount of brownie mix bags needed to use up 3 eggs and 1 cup of oil is 3, option C.

What is the basic stoichiometry for this problem?

1 egg and 1/3 cup of oil is needed for a brownie mix bag

Therefore the brownie mix bags needed to consume 3 eggs and a cup of oil is equal to;

1 egg and 1/3 cup = 1 brownie mix bag

3 eggs and 1 cup = ?

Cross multiplied;

3/1 x 1 = 3

For one cup of oil and 3 eggs to be used up, it requires 3 bags of brownie mix.

The complete question is:

If 1 egg and 1/3 cup of oil are needed for each bag of brownie mix, how many bags of brownie mix do you need if you want to use up all 3 eggs and 1 cup of oil?

a. 1

b. 2

c. 3

d. 4

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HELP NEEDED URGENTLY PLEASE

HELP NEEDED URGENTLY PLEASE

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part a.

The partial pressure of hydrogen gas in the final state is 366.67 torr.

part b.

the partial pressure of nitrogen gas in the final state is 116.67 torr.

part c.

the total pressure in the final state is  483.34 torr.

How do we calculate?

a.

initial volume of hydrogen gas =  4.00 L

initial pressure = 550 torr.

P1V1 = P2V2

(550 torr)(4.00 L) = P2(6.00 L)

2200 torr = P2(6.00 L)

P2 = 2200 torr / 6.00 L

P2 =  366.67 torr

b.

initial volume of nitrogen gas = 2.00 L,

initial pressure =  350 torr.

P1V1 = P2V2

(350 torr)(2.00 L) = P2(6.00 L)

700 torr = P2(6.00 L)

P2 = 700 torr / 6.00 L

P2 =  116.67 torr

c.

Total pressure = Partial pressure of H2 + Partial pressure of N2

Total pressure = 366.67 torr + 116.67 torr

Total pressure =  483.34 torr

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In clinical applications, the unit parts per million (ppm) is used to express very small concentrations of solute, where 1 ppm is equivalent to 1 mg of solute per 1 L of solution. Calculate the concentration in parts per million for each of the solutions.There is 43 μg of calcium in a total volume of 87 mL .concentration of calcium: _________ppm There is 0.91 mg of caffeine in a total volume of 105 mL .concentration of caffeine: _________ppm There is 0.47 mg of trace particles in a total volume of 95 dL .concentration of trace particles: ___________

Answers

Answer & Procedure

To solve this problem you will need to transform all the concentrations to the equivalence of ppm, which is 1 mg of solute per 1 L of solution.

Calcium: There are 43 μg of calcium in a total volume of 87 mL.

\(\frac{43\mu g}{87\text{ mL}}\frac{1\text{ mg}}{1000\text{ }\mu g}\frac{1000\text{ mL}}{1\text{ L}}=0.49\frac{mg}{L}=0.49\text{ ppm}\)

Caffeine: There is 0.91 mg of caffeine in a total volume of 105 mL.

\(\frac{0.91\text{ mg}}{105\text{ mL}}\frac{1000\text{ mL}}{1\text{ L}}=8.67\frac{mg}{L}=\text{ 8.67 ppm}\)

Trace particles: There is 0.47 mg of trace particles in a total volume of 95 dL.

\(\frac{0.47\text{ mg}}{95\text{ dL}}\frac{10\text{ dL}}{1\text{ L}}=0.049\frac{mg}{L}=0.049\text{ ppm}\)

How do you calculate bonding capacity in chemistry?

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Answer:

bonding capacity is based on the oxidation number. the pattern throughout families 1-2 and 13-18 is 12343210. depending on wether the elements in a family lose or gain 1-4 valence electrons is what determines the bonding capacity. for example, the elements in family one, or the Alkali family elements, lose one valence electron to become stable. this means the next outer shell has 8 valence electrons and is therefore stable. family two elements lose 2 valence electrons in order to have 8 on the outer shell. family thirteen elements lose 3 valence electrons. family fourteen can either lose or gain their four valence electrons as long as they end up with an outer shell with 8 valence electrons. family fifteen gains 3 valence electrons, 16 gains two, and 17 gains 1. family 18 doesn't lose or gain any since it is already stable. if an element loses valence electrons its oxidation number will be a positive 1,2,3, or 4. if an element gains valence electrons its oxication number will be a negative 1,2,3, or 4. the pattern of oxidation numbers is the same as the bonding capacity and it is +1,+2,+3,+4/-4,-3,-2,-1 or 0. basically if you can find the oxidation number then you can find the bonding capacity

Explanation:

Una definición adecuada para el estado plasma sería:

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Plasma is a state of matter in which a gas has been ionized to the point where it contains a significant number of free electrons and positive ions.

In a plasma, the electrons are separated from their parent atoms or molecules and are free to move about. This creates a mixture of positively charged ions and negatively charged electrons, which collectively behave like a fluid rather than individual particles.

Plasmas can be created by heating a gas to high temperatures, subjecting it to a strong electromagnetic field, or by passing an electric current through it. Examples of natural plasmas include lightning, the aurora borealis, and the sun. Plasmas have unique properties and are used in a variety of applications, including fluorescent lighting, plasma cutting and welding, and in plasma TVs.

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Write a chemical equation for HNO3(aq) showing how it is an acid or a base according to the Arrhenius definition.Express your answer as a chemical equation. Identify all of the phases in your answer.Part CWrite a chemical equation for HF(aq) showing how it is an acid or a base according to the Arrhenius definition.Express your answer as a chemical equation. Identify all of the phases in your answe

Answers

Part A The chemical equation for HNO3  showing it is acid is:-

HNO3 (aq) → H+ (aq) + NO3- (aq)

The phases are HNO3 (aq) = aqueous solution, H+ (aq) = aqueous solution and NO3- (aq) = aqueous solution.

Part B The chemical equation for HF showing it is acid is:-

HF (aq) → H+ (aq) + F- (aq)

The phases are HF (aq) = aqueous solution, H+ (aq) = aqueous solution, and F- (aq) = aqueous solution.

HNO3 (aq) is an acid according to the Arrhenius definition because the chemical substance HNO3 (nitric acid) dissociates in an aqueous solution to release hydrogen ions (H+).

HF (aq) is an acid according to the Arrhenius definition because the chemical substance HF (hydrofluoric acid) dissociates in an aqueous solution to release hydrogen ions (H+).

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The laws of nature:
A. are not subject to special relativity.
B. are the same in every frame of reference.
C. are all described by the same frame of reference.
D. are not the same in every frame of reference.

Answers

Answer:

B

Explanation:

they actually say the same thing they differ with smaller things

the vast majority of the geologic record contains well-preserved fossils that we can use to develop relative timing relationships among rock units.

Answers

This helps us to establish the relative ages of the rock formations based on the order of their deposition. The use of fossils in this manner is known as biostratigraphy, and it is an important tool in the field of geology.

The statement "the vast majority of the geologic record contains well-preserved fossils that we can use to develop relative timing relationships among rock units" is true. The presence of well-preserved fossils in the rock units is the basis for the relative timing relationships. These relationships can be used to establish the relative ages of rock formations by determining which layers were deposited first, second, third, and so on.In many cases, the fossils themselves can be used to establish the relative ages of the rock formations. This is because different types of fossils are associated with different geological time periods. For example, the fossils of trilobites are commonly found in rocks that are millions of years old, while the fossils of dinosaurs are typically found in much younger rocks.In conclusion, the vast majority of the geologic record contains well-preserved fossils that we can use to develop relative timing relationships among rock units. This helps us to establish the relative ages of the rock formations based on the order of their deposition. The use of fossils in this manner is known as biostratigraphy, and it is an important tool in the field of geology.

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list three characteristics that limit the usefulness of indicators​

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Answer:

1. Indicator color can be distorted if a solution is not colorless.

2. At temperatures other than 25 degrees Celsius, an indicator may change color at a different pH.

3. Dissolved salts in a solution can affect the dissociation of the indicator.

Explanation:

Use these two constants for the question that follows:
• e = 1.6 × 10^-19 C
• k = 8.99 × 10^9 N m^2/C^2
Two negative charges are 10^-14 m away from each other. Using Coulomb's law, which of the following is the electrical force between these two particles?
A) 2.3 N
B) -2.3 N
C) 1.4 N
D) -1.4 N

Use these two constants for the question that follows: e = 1.6 10^-19 C k = 8.99 10^9 N m^2/C^2Two negative

Answers

The electrical force between these two particles is approximately -2.3 N.

So,the correct answer is (B) -2.3 N

Coulomb’s law is given as:F=ke * q1 * q2 / d^2

Where,F = Force in Newton (N)q1 = Charge on particle 1 in Coulombs (C)q2 = Charge on particle 2 in Coulombs (C)k = Coulomb’s constant = 8.99 × 10^9 N m^2/C^2d = Distance between two particles in meters (m).

Given:e = 1.6 × 10^-19 Ck = 8.99 × 10^9 N m^2/C^2Distance between two particles, d = 10^-14 mAs given, both particles are negative charges; hence, the force between the two particles will be repulsive.

The formula to find the electric force between two negative charges is:F = -ke * q1 * q2 / d^2F = - (8.99 × 10^9 N m^2/C^2) * (1.6 × 10^-19 C) * (1.6 × 10^-19 C) / (10^-14 m)^2= - 2.304 × 10^-9 N= - 2.3 N (approximately).

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Match the following rocks with the correct type.
1. obsidian intrusive igneous
2. granite metamorphic
3. conglomerate chemical sedimentary
4. evaporite extrusive igneous
5. coal organic sedimentary
6. marble clastic sedimentary

Answers

Answer:

I\B

2/A

3\C

4\E

5\D

6\F

Explanation:

I think this is right. Good Luck By The Way!!!

What will be the [OH-], [H3O], pH and pOH of a 0. 025 M weak acid olution? (pKA= 4. 615)

Answers

The [OH-] of the 0.025 M weak acid solution will be equal to the pKA of the acid, 4.615.
What is weak acid solution?
A weak acid solution is a solution that contains an acid that is not completely ionized in water. Weak acids, such as acetic acid, have pH values between 4.5 and 6.0. These acids are not strong enough to completely break apart in water, leaving some of the molecules still intact. Because of this, weak acids form molecules that can react with other molecules, such as bases, in solution.
This is because the equilibrium of the acid dissociation reaction is reached with the same concentration of acid and its conjugate base in solution. The [H3O] will be equal to 0.025 M, as the acid is in dissociation equilibrium with its conjugate base. The pH of the solution can be calculated by taking the negative log of the [H3O], which will be 1.59. The pOH can be calculated by taking the negative log of the [OH-], which will be 4.615.
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if too much heat was applied to your hydrate and the salt began to decompose, how might this affect your results?

Answers

Answer:

You added water to your desiccant salt once your experiment was concluded

Explanation:

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what are the type of mixture in calloid, suspension and solution

Answers

Homogeneous and heterogeneous mixture in colloid, suspension and solution

A colloid is a heterogeneous mixture in which the dispersed particles are intermediate in size between those of a solution and a suspension and within the categories of homogeneous and heterogeneous mixtures there are more specific types of mixtures including solutions is alloys, suspensions, and colloids and a solution is a mixture where one of the substances dissolves in the other and the substance that dissolves is called the solute

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For a chemical reaction in a closed system, mass cannot be.
the reaction mass is
A rearranged; destroyed; gained
created; destroyed; lost
rearranged; created; conserved
D) created; destroyed; conserved
W
or
We can say that throughout

Answers

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Answer:

I think the answer is created; destroyed; conserved.

Explanation:

The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed.

The intensity of emitted gamma rays at a given energy is known to be directly proportional to the abundance of unstable isotopes that decay with that emission. Thus, the intensity of gamma rays emitted at 1.634 MeV is a measure of the abundance of 20F nuclei. The plot of Ln (intensity) vs time gives a linear response with slope = -k.

Calculate the half-life, t1/2, using equation (7), for 20F from each of the six replicate channel A runs and enter your results below. Be sure to use the correct number of sig figs in your responses. Remember, the slope values you measured can be displayed by clicking on the Data Summary tab. We're supposed to find individual half life for each of the trials, not an average.

Trial 1 Slope: -0.0629 s

Trial 2 Slope: -0.058 s

Trial 3 Slope: -0.0627 s

trial 4 Slope: -0.0661 s

Trial 5 Slope: -0.0599 s

trial 6 Slope: -0.0574

Answers

To calculate the half-life, t1/2, for 20F from each trial, we can use the equation:
t1/2 = -ln(2) / slope


Let's calculate the half-life for each trial:
Trial 1:
t1/2 = -ln(2) / -0.0629 s
t1/2 ≈ 11.0 s (rounded to the correct number of sig figs)

Trial 2:
t1/2 = -ln(2) / -0.058 s
t1/2 ≈ 12.0 s (rounded to the correct number of sig figs)
Trial 3:
t1/2 = -ln(2) / -0.0627 s
t1/2 ≈ 11.1 s (rounded to the correct number of sig figs)
Trial 4:
t1/2 = -ln(2) / -0.0661 s
t1/2 ≈ 10.5 s (rounded to the correct number of sig figs)
Trial 5:
t1/2 = -ln(2) / -0.0599 s
t1/2 ≈ 11.6 s (rounded to the correct number of sig figs)
Trial 6:
t1/2 = -ln(2) / -0.0574 s
t1/2 ≈ 12.1 s (rounded to the correct number of sig figs)
Please note that these values are rounded to the correct number of significant figures.

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The initial rate of the reaction: BrO3- (aq) + 5Br-(aq) + 8H+(aq) 3Br2(l) + H2O(l) has been measured at the reaction concentrations shown in mol/L. Experiment[BrO3-][Br-][H+]Initial rate (mol/(L∙s)10.100.100.108.0 x 10-420.200.100.101.6 x 10-330.100.200.101.6 x 10-340.100.100.203.2 x 10-3Determine the order of reaction with respect to each reactant

Answers

To determine the order of the reaction with respect to each reactant, we must compare how the reaction rate changes when its concentration changes.

We have in experiment one the same concentration of reactants and a speed equal to 8.0x10^-4 mol/(L.s).

Now, in the second experiment, the concentration of BrO3 doubles, and the rest of the reagents remain the same. The speed is also doubled since 8.0x10^-4 x 2 = 1.6 x 10^-3.

The same happens with Br-, in the third experiment. The rate doubles as the Br concentration doubles.

So for these two reactants, the rate of reaction will be first-order, since as the concentration increases the rate increases in the same proportion.

Now, for H+ we have that by doubling the concentration the rate quadruples. This means that the reaction order is second order. When changing the concentration, the speed changes in order equal to 2

Answer:

the order of reaction will be:

Respect BrO3-: First order

Respect Br-: First order

Respect H+: Second order

Is HF Lewis structure polar or nonpolar?

Answers

HF Lewis structure is a polar due to the difference in electronegativity between hydrogen and fluorine atoms. This is due to permanent dipole moment, meaning that there is an uneven distribution of electrons within the molecule.

The HF (hydrogen fluoride) molecule has a polar covalent bond, which means that it has an uneven distribution of electrons between the two atoms.

In a polar covalent bond, one atom has a higher electronegativity than the other and therefore attracts the shared electrons more strongly, resulting in a partial negative charge on that atom and a partial positive charge on the other atom.

In the case of HF, fluorine has a higher electronegativity than hydrogen, which means that the electrons in the covalent bond are more strongly attracted to the fluorine atom. This results in a partial negative charge on the fluorine atom and a partial positive charge on the hydrogen atom.

Because the HF molecule has a polar covalent bond and the molecule has a bent shape due to the lone pair of electrons on fluorine, the molecule as a whole is also polar.

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How many joules are required to change 25.02g of liquid Ethanol that is at a temperature of 289.14K to a gas at 351.5K

Answers

The amount of joules required to change 25.02g of liquid Ethanol is 3838.2 J or 3.83kJ.

Given,

mass of the ethanol (m) = 25.02g

heat capacity of the ethanol (c) = 2.46

Conversion of Kelvin to Celsius:

C = K - 273.15

C1 = 289.14 - 273.15 => 15.99 C

C2 = 351.5 - 273.15 => 78.35 C

             

Formula:

H = mcdT                

temperature change (dT) = C2 -C1 => 78.35 - 15.99 => 62.36 C

Substituting the values,

H = 25.02 * 2.46 * 32.36

H = 3838.2 J or 3.83kJ

Therefore, the amount of joules required to change 25.02g of liquid Ethanol is 3838.2 J or 3.83kJ.

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a student is provided with an unknown solution, which will contain one of the following cations: ba2 (aq), ca2 (aq), pb2 (aq), or k (aq). the unknown solution is mixed with aqueous sodium chloride, sodium chloride and sodium sulfate. the student's observations are shown below. nacl(aq) naoh(aq) na2so4(aq) unknown solution no change no change precipitate which cation does the unknown solution contain? select one: a. lead (ii) ion b. calcium ion c. potassium ion d. barium ion

Answers

The student's observations show that when aqueous sodium sulfate is added to the unknown solution, a precipitate is formed. This indicates the presence of a sulfate-insoluble cation, which includes lead (II) ion, calcium ion, and barium ion.

However, the student also observed no change when adding aqueous sodium chloride and sodium hydroxide, which rules out the possibility of calcium ion and barium ion since they would form a white precipitate with sodium hydroxide. Therefore, the unknown solution contains lead (II) ion. The solution to identify the cation in the unknown solution was to use a combination of different aqueous solutions that can react differently with different cations. This allowed the student to make observations and narrow down the possible cations present in the unknown solution.

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the negatively charged subatomic particles that j.j. thomson discovered are now called

Answers

The negatively charged subatomic particles that J.J. Thomson discovered are now called electrons. Subatomic particles can be either neutral, positively charged, or negatively charged. Protons, for example, are positively charged subatomic particles. Electrons, on the other hand, are negatively charged subatomic particles

What are charged subatomic particles? Subatomic particles can be either neutral, positively charged, or negatively charged. Protons, for example, are positively charged subatomic particles. Electrons, on the other hand, are negatively charged subatomic particles. Neutrons are the third type of subatomic particle, but they are neutral, which means they do not have a charge. What did J.J. Thomson discover? J.J. Thomson was a British physicist who, in the late 19th century, conducted a series of experiments on cathode rays. Cathode rays are beams of electrons that are produced in a vacuum tube when an electric current is passed through it. Thomson used cathode rays to investigate the structure of atoms. In 1897, Thomson discovered that cathode rays are made up of negatively charged subatomic particles. He named these particles "corpuscles," but they are now known as electrons. Thomson's discovery of the electron revolutionized atomic physics and led to the development of the electron model of the atom. Electrons are important because they are responsible for chemical reactions and are involved in electricity and magnetism. They are negatively charged and are located outside the nucleus in the electron cloud. Electrons are also the smallest subatomic particle and have a mass of 9.10938356 x 10-31 kg (0.0005485799 atomic mass units).

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An element has an atomic number 17.How many electrons are present in K,L and M shells of the atom?

Answers

Answer:

k=2, L=8, M=7

Explanation:

because k shell have maximum electron number of 2 ,L shell and M shell have 8 and 18 respectively.

A 1.5 liter flask is filled with nitrogen at a pressure of 12 atmospheres. What
size flask would be required to hold this gas at a pressure of 2.0
atmospheres?

Answers

According to the information, a flask with a volume of 9 liters would be required to hold the nitrogen gas at a pressure of 2.0 atmospheres.

What size flask would be required to hold this gas at a pressure of 2.0 atm?

This problem can be solved using Boyle's Law, which states that the product of pressure and volume is constant for a fixed amount of gas at a constant temperature.

So, we can use the formula P1V1 = P2V2, where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.

We are given:

P1 = 12 atmV1 = 1.5 LP2 = 2 atmV2 = ?

Plugging these values into the formula, we get:

12 atm x 1.5 L = 2 atm x V2

Simplifying, we get:

V2 = (12 atm x 1.5 L) / 2 atmV2 = 9 L

Therefore, a flask with a volume of 9 liters would be required to hold the nitrogen gas at a pressure of 2.0 atmospheres.

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If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation? (1 point)

Answers

Answer:

There is an extra O2 molecule left over

Explanation:

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