i) A sag vertical curve is to be designed to join a 4% grade to a 2% grade. If the design
speed is 50 mi/h, determine the minimum length of the curve. Assume a = 11 ft /sec2 and
perception-reaction time = 2.5 sec. Consider the following criteria:
a) Stopping sight distance
b) Comfort

The peak frequency deviation, minimum bandwidth, and baud for a binary FSK signal for the given frequencies are respectively;

a) 0.5 kHz

b) 9 kHz

c) 4000

1) The peak frequency deviation is gotten from the formula;

∆f = |f_m - f_s|/f_b

where;

Thus;

∆f = |38 - 40|/4

∆f = 0.5 kHz

2) The minimum bandwidth is given by the formula;

B = 2(∆f + f_b)

B = 2(0.5 + 4)

B = 9 kHz

3) For FSK signal, N = 1, and the baud is gotten from the Equation;

baud = f_b/1

f_b = 4 kbps = 4000 bps

Thus; baud = 4000/1 = 4000

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Answer:

Neither a or b.

Explanation:

The distributor cap is cover which protects internal parts and holds contact between internal rotor and spark plug wires. When inspecting distributor caps there should be some carbon tracking which looks like bright white grease trails.

Answer:

You can see there are four different types of measurement scales (nominal, ordinal, interval and ratio).

Some Important Formulas:

Hope this helps!

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An internship would be a good option for a beginner UX designer who is looking for a short-term work opportunity with not a lot of responsibility.

Internships provide valuable work experience and the opportunity to learn from experienced professionals in the field. They also often have a set duration, which can be a good fit for someone who is not looking for a long-term commitment.

Additionally, internships typically come with less responsibility than entry-level jobs, which can be a good fit for someone who is just starting out in their career.

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Answer:

In  case whereby you  work for rev and check your work email on your mobile phone and You have decided to resign your job and take a position with a different company. Regarding rdm on your mobile phone, you should B. Take your phone to IT Services, and they will wipe it clean.

What is expected to do when leaving the company?

It is expected from you to return anything that belong to the company before leaving the company, but in the case whereby there is still a rdm on your mobile phone, then you can work to the IT services so they can wipe it away.

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Missing options:

A. Turn your phone to IT Services

B. Take your phone to IT Services, and they will wipe it clean

C. Download RDM to your personal computer

D. Call IT Services for support, and they will assist

E. Nothing. IT Services will automatically remove all data

The content of register R1 after executing the given ARM instructions is determined by the sequence of operations: MOV, ROR, LSR, and ADD.

1. MOV inatructions R1, #0x00FFAA12: This instruction moves the immediate value 0x00FFAA12 into register R1.

2. ROR R1, R1, #12: This instruction performs a right rotation on the bits of R1 by 12 positions. The rotated value is stored back in R1.

3. LSR R1, R1, #8: This instruction performs a logical shift right on the bits of R1 by 8 positions. The shifted value is stored back in R1.

4. ADD R1, R1, #0x1A: This instruction adds the immediate value 0x1A to the contents of R1. The sum is stored back in R1.

The specific effects of each instruction on R1 can be explained as follows:

To determine the exact content of R1, it would require performing the arithmetic operations step by step. However, without further context or information about the initial state of R1 and the specific ARM architecture being used, it is not possible to provide the exact value of R1 after executing these instructions.

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Answer:

answer letter c

Explanation:

yun anserr hhehehe

Answer:

My opinion towards Kirby's approach in choosing articles for literature reviews is that, it is not the considered a good approach because when choosing articles based only on Journal it can't be considered the best.

Various methods needs to be considered by Kirby's before selecting articles, which are stated in the explanation section below

Explanation:

Solution:

Kirby’s method in choosing articles is not regarded to be a better proposal because choosing articles  with regards to the journal can’t be seen as good. There are other things that should to be taken into consideration by Kirby which is explained below:

Answer:

a) i) The maximum pressure is approximately 122.37 bar

ii) The thermal efficiency is approximately 56.47%

iii) The mean effective pressure is approximately 20.974 bar

b) (b) Four types of internal combustion engine includes;

1) The diesel engine

2) The Otto engine

3) The Brayton engine

4) The Wankel engine

Explanation:

The parameters of the Otto cycle are;

The heat added, \(Q_{in}\) = 2,800 kJ/kg

The compression ratio, r = 8

The beginning compression pressure, P₁ = 1 bar

The beginning compression temperature, T₁ = 300 K

Cp = 1.005 kJ/kg·K

Cv = 0.718 kJ/kg·K

R = 287 kJ/kg·K

K = Cp/Cv = 1.005 kJ/kg·K/(0.718 kJ/kg·K) ≈ 1.4

T₂ = T₁×r^(k - 1)

∴ T₂ = 300 K×8^(1.4 - 1) ≈ 689.219 K

\(\dfrac{P_1\cdot V_1}{T_1} = \dfrac{P_2\cdot V_2}{T_2}\)

\(P_2 = \dfrac{P_1\cdot V_1 \cdot T_2}{T_1 \cdot V_2} = \dfrac{V_1}{V_2} \cdot \dfrac{P_1 \cdot T_2}{T_1 } = r \cdot \dfrac{P_1 \cdot T_2}{T_1 }\)

∴ P₂ = 8 × 1 bar × (689.219K)/300 K ≈ 18.379 bar

\(Q_{in}\) = m·Cv·(T₃ - T₂)

∴ \(Q_{in}\) = 2,800 ≈ 0.718 × (T₃ - 689.219)

T₃ = 2,800/0.718 + 689.219 = 4588.94 K

P₃ = P₂ × (T₃/T₂)

P₃ = 18.379 bar × 4588.94K/(689.219 K) = 122.37 bar

The maximum pressure = P₃ ≈ 122.37 bar

(ii) The thermal efficiency, \(\eta_{Otto}\), is given as follows;

\(\eta_{Otto} = 1 - \dfrac{1}{r^{k - 1}}\)

Therefore, we have;

\(\eta_{Otto} = 1 - \dfrac{1}{8^{1.4 - 1}} \approx 0.5647\)

The thermal efficiency, \(\eta_{Otto}\) ≈ 0.5647

Therefore, the thermal efficiency ≈ 56.47%

(iii) The mean effective pressure, MEP is given as follows;

\(MEP = \dfrac{\left(P_3 - P_1 \cdot r^k \right) \cdot \left(1 - \dfrac{1}{r^{k-1}} \right)}{(k -1)\cdot (r - 1)}\)

Therefore, we get;

\(MEP = \dfrac{\left(122.37 - 1 \times 8^{1.4} \right) \cdot \left(1 - \dfrac{1}{8^{1.4-1}} \right)}{(1.4 -1)\cdot (8 - 1)} \approx 20.974\)

The mean effective pressure, MEP ≈ 20.974 bar

(b) Four types of internal combustion engine includes;

1) The diesel engine; Compression heating is the source of the ignition, with constant pressure combustion

2) The Otto engine which is the internal combustion engine found in cars that make use of gasoline as the source of fuel

The Otto engine cycle comprises of five steps; intake, compression, ignition, expansion and exhaust

3) The Brayton engine works on the principle of the steam turbine

4) The Wankel it follows the pattern of the Otto cycle but it does not have piston strokes

Heat is transferred by conduction when a jar of baby food is heated by submerging it in hot water.

The transfer of heat energy by conduction occurs when two things come into direct touch. Since the jar of baby food and the hot water are in direct contact in this instance, heat can be transferred from the water to the food.

The jar of baby food is the "cold" object because it has a lower temperature, while the hot water is the "hot" object since it has a higher temperature.

Heat is transferred from the hot water to the jar and then to the baby food when the two things come in contact.

Heat transmission through conduction is used to heat the baby food jar in hot water. Until thermal equilibrium is attained, heat is transported from the hot water to the jar and then to the food.

Thus, the baby food's and the jar's specific heat capacity have an impact on how quickly heat is absorbed and how quickly the temperature rises.

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Answer:

The answer is "\(\bold{e^{-t} \sin t}\)"

Explanation:

Given equation:

\(\to x+2x+2x=0.............(a)\)

Let x= e^{mt} be a solution of the equation will be:

\(\to m^2+2m+2=0\)

compare the value with the  \(am^2+bm+c=0\)

\(\to a= 1\\\to b= -2\\\to c= 2\\\)

Formula:

\(\bold{=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\\\\=\frac{-2 \pm \sqrt{(-2)^2-4\times 1 \times 2}}{2 \times 1}\\\\=\frac{-2 \pm \sqrt{4-8}}{2}\\\\=\frac{-2 \pm \sqrt{-4}}{2}\\\\=\frac{-2 \pm 2i}{2}\\\\\)

Calculate the g.s at equation (a):

\(\to x = e^{-t} (c_1 \cos t+ c_2 \sin t)............(b)\\\\\to x = e^{-t} (c_2 \cos t -c_1 \sin t) - e^{-t} (c_1 \cos t + c_2\sin t) ...............(c)\\\\\)

\(_{when} \\\\\to t= 0\\\\\to x=x_0\\\\\to x= v_0 =1 \\\\ \ then \ form \ equation \ (b) \ and \ equation \ (c)\)

\(\to a= 0 \\ \to c_2 -c_1 =1 \\ \to c_2=1\)

The value of \(x = e^{-t} ( 0 \times \cos t + 1 \times \sin t)\)

\(\boxed{\bold{x = e^{-t} (\sin t)}}\)

Answer:

a) 397.89 ohm

b) attached below

c) 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

d)  0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Explanation:

A) Find the appropriate resistor

c = 0.01 uf

fc = 40 kHz

cut-off frequency ; fo = \(\frac{1}{2\pi RC }\)

from the above equation  R = \(\frac{1}{2\pi foC}\)  = 397.89 ohm

B) sketch of the circuit  is attached

C) The gain of the filter at the cutoff frequency

fc = 40 kHz,  

C = 0.01 uF ⇒ \(\frac{-j}{2\pi foC }\) =  -j 397.89

Vout = Vin * ( R / R- C )

Vout = Vin * ( 397.89 / (397.89 - j 397.89))

Vout = \(\frac{1}{\sqrt{2} }\)  Vin ∠45⁰

therefore gain = |\(\frac{Vout}{Vin }\)| = \(\frac{1}{\sqrt{2} }\) = 0.707  as a ratio

Gain in dB = 20 log 0.707 = -3 dB

D) Gain of filter at 55 kHz

c = 0.01 uF =  \(\frac{-J}{2\pi foC }\) =  -j 289.373 ohms

Vout = Vin * \(\frac{R}{R-C}\)  

        = Vin * ( 397.89 / ( 397.89 - j 289.373))

Gain in ratio \(|\frac{Vout}{Vin}|\) = 0.8087 ∠ 36.03⁰

therefore gain in ratio = 0.8087

Gain in dB = 20 log \(|\frac{Vout}{Vin}|\) = -1.844 dB

Using the knowledge in computational language in python it is possible to write a code that output the number of characters excluding the three characters commonly used for end-of-sentence punctuation.

   import re

   def check_sentence(text):

     result = re.search(r"^[A-Z][A-Za-z\s]*[\.\?!]$", text)

     return result != None

   print(check_sentence("Is this is a sentence?")) # True

   print(check_sentence("is this is a sentence?")) # False

   print(check_sentence("Hello")) # False

   print(check_sentence("1-2-3-GO!")) # False

   print(check_sentence("A star is born.")) # True

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Answer:

She wrote and delivered a speech in 1873, which came to be known as the “Women's Rights to the Suffrage” speech. In her address, she lets the audience know of her “crime” of voting. She reminds the listener that the Constitution of the United States says “we the people” and does not exclude women as people

Answer:

D. To show why she was justified in voting.

Explanation:

Answer:

the minimum diameter of the bar is 1.634 in

The crystallinity of cellulose as well as its polar qualities makes it less difficult to dissolve. It has a three-dimensional hydrogen bond (H-bond) arrangement with the hydroxyl group connected to each polymer chain. On the other hand, Hydrocarbon polymers are nonpolar, and nonpolar solvents are used to dissolve them.

Cellulose is an organic molecule with the formula n that is a polysaccharide made up of a linear chain of hundreds to thousands of β  linked D-glucose units. Cellulose is a structural component of the major cell wall of green plants, many algae, and oomycetes.

Cellulose is the principal component present in plant cell walls and aids in the plant's stiffness and strength. Although cellulose cannot be digested by humans, it is an essential source of fiber in the diet. Cellulose is utilized in the production of clothing and paper.

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Answer:

Probability of no red ball from 4 balls = 0.1258 (Approx.)

Explanation:

Given:

Number of black ball = 3

Number of red ball = 5

Number of green ball = 6

Find:

Probability of no red ball from 4 balls

Computation:

Probability of no red ball from 4 balls = 9c4 / 14c4

Probability of no red ball from 4 balls = 126 / 1001

Probability of no red ball from 4 balls = 0.12587

Probability of no red ball from 4 balls = 0.1258 (Approx.)

Answer:

SPCA factor

Single payment compound amount factor.

Total amount pay A = $24,230.95 (Approx)

Interest paid = $4,230.95  (Approx)

Explanation:

Given:

P = $20,000

n = 6 year

r = 3.25%

Find:

Total amount pay A

Computation:

A=p(1+r)ⁿ

A=20,000[1+3.5%]⁶

A=20,000[(1.0325)⁶]

Total amount pay A = $24,230.95 (Approx)

Interest paid = $24,230.95 - 20,000

Interest paid = $4,230.95  (Approx)

Semiconductors are formed by doping pure semiconductor materials. Examples include silicon, germanium, gallium arsenide, and indium phosphide. They are used in integrated circuits, transistors, solar cells, LEDs, lasers, and sensors, among other applications.

Semiconductors are formed through a process called doping, which involves intentionally adding impurities to a pure semiconductor material. The impurities, known as dopants, can introduce extra electrons (n-type doping) or electron deficiencies called holes (p-type doping) into the semiconductor lattice structure.

Examples of semiconductor materials include:

1. Silicon (Si): Silicon is the most widely used semiconductor material. It is abundant, has a well-developed manufacturing infrastructure, and exhibits good electrical properties for various applications.

2. Germanium (Ge): Germanium was one of the first materials used as a semiconductor. It has similar properties to silicon but is less commonly used in modern applications.

3. Gallium Arsenide (GaAs): Gallium arsenide is a compound semiconductor with superior electronic properties compared to silicon. It is used in high-speed devices such as microwave amplifiers, laser diodes, and solar cells.

4. Indium Phosphide (InP): Indium phosphide is another compound semiconductor that finds applications in telecommunications, fiber-optic networks, and high-frequency electronics.

Semiconductors are used in a wide range of electronic devices and technologies, including:

- Integrated Circuits (ICs): Semiconductors form the foundation of ICs, such as microprocessors, memory chips, and sensors, which are used in computers, smartphones, and various electronic devices.

- Transistors: Transistors, which are fundamental components of electronic circuits, are made using semiconductors. They are used in amplifiers, switches, and digital logic circuits.

- Solar Cells: Semiconductors like silicon and gallium arsenide are used in photovoltaic cells to convert sunlight into electricity.

- Light-Emitting Diodes (LEDs): LEDs use semiconductors to emit light efficiently and are used in displays, lighting, and optoelectronic applications.

- Semiconductor Lasers: Semiconductor lasers are used in telecommunications, optical storage devices, laser printers, and medical equipment.

- Sensors: Semiconductors are employed in various sensors, including temperature sensors, pressure sensors, gas sensors, and image sensors.

These are just a few examples of the widespread use of semiconductors in modern technology. Their unique electrical properties make them versatile for a wide range of applications.

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Explanation:

The term refrigeration means cooling a space, substance or system to lower and/or maintain its temperature below the ambient one (while the removed heat is rejected at a higher temperature). In other words, refrigeration is artificial (human-made) cooling.

Refrigeration, is the act of removing undesirable heat from one thing, substance, or space and transferring it to another object, substance, or space.

Refrigeration refers to the process of chilling an area, material, or system in order to decrease and or keep its temperature below that of the surrounding environment.

Refrigeration, sometimes known as chilling, is the act of removing undesired heat from one item, substance, or area and transferring it to another.

The temperature can be lowered by using ice, snow, cooled water, or mechanical refrigeration to remove heat.

Hence,refrigeration, is the act of removing undesirable heat.

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RAB1=RA1+RB1=69=23 . D and E are combined in a parallel fashion. RDE1=RD1+RE1=69=23. Currently, Resistor C is connected in series to AB and DE. Rnet = 23+23+3 = 6 for net resistance.

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Answer:

whatsthe question choices

When using Git, the checkout command allows us to switch between different branches or restore files from previous commits. In the case of the gitlet version control system, running the command "gitlet checkout" with a specific commit ID and file name will restore the contents of that file from the specified commit.

Assuming that the file "game.txt" exists in the current working directory (CWD), running the command "gitlet checkout 39 -- game.txt" will restore the contents of "game.txt" as it existed in commit 39. This means that any changes made to "game.txt" in subsequent commits will be discarded, and the file will be reverted to its state in commit 39. In terms of the commit tree, running this command will not change the structure of the tree itself. The commit tree will still have all of the same branches, commits, and merges as before. However, the contents of "game.txt" in the CWD will be updated to match the version from commit 39.

To summarize, running "gitlet checkout 39 -- game.txt" in the CWD will restore the contents of "game.txt" as it existed in commit 39. This command will not affect the structure of the commit tree, but will only update the contents of the specified file.

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A PFAS anchorage point for a 6-foot lanyard must be able to hold a minimum static load of 5,000 pounds.

PFAS stands for Personal Fall Arrest System, which is a type of fall protection equipment that is designed to protect workers from falls.
The 5,000-pound minimum static load requirement is based on the assumption that the PFAS will experience a shock load of 2,500 pounds in the event of a fall.

This shock load is due to the force of the fall and the weight of the worker, and it puts a significant amount of stress on the anchorage point. The 5,000-pound minimum static load ensures that the anchorage point can withstand this shock load without failing.
It's important to note that the 5,000-pound minimum static load requirement is a general guideline, and the actual load capacity of the anchorage point will depend on a variety of factors, including the type of anchorage point, the material it's made from, and the conditions of use.

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The focus of the MINI brand on clever solutions, distinctive designs, and urban driving is indeed evident in its unique car offerings. However, whether it is working as advertised globally requires a comprehensive analysis of market performance, customer satisfaction, and brand perception.

The success of the MINI brand's focus can be evaluated through several factors. First, market performance metrics such as sales figures, market share, and revenue growth can indicate the brand's appeal and acceptance worldwide. Customer satisfaction surveys and feedback can provide insights into whether the MINI meets customers' individual needs and expectations.

Additionally, analyzing the brand's marketing and advertising strategies can shed light on its effectiveness in communicating the intended message and attracting the target audience. Assessing the brand perception among global consumers, including their perception of clever solutions, distinctive designs, and urban driving experience, is crucial to evaluate the brand's success.

Furthermore, considering regional variations and cultural differences in preferences and market demands is essential when evaluating global performance. Adapting to local markets while maintaining the brand's core identity is crucial for sustained success.

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Several factors can affect the speed of an inkjet printer. The following are some of the key factors:

1. Print Quality: Higher print quality settings generally require more ink and precise placement of droplets, which can slow down the printing process compared to lower quality settings.

2. Image Complexity: Printing complex images, graphics, or photographs with intricate details can slow down the printing speed. The printer needs more time to process and accurately reproduce the fine details of the image.

3. Print Resolution: Higher print resolutions, such as printing at higher dots per inch (dpi), can result in slower print speeds as more ink droplets are required to achieve greater detail and sharpness.

4. Connectivity and Data Transfer: The speed at which the printer receives data from the connected device (e.g., computer, mobile device) can affect printing speed. Faster data transfer speeds, such as using USB 3.0 or Ethernet connections, can help maintain a steady flow of print data and improve overall printing speed.

5. Printer Hardware Specifications: The specific model and specifications of the inkjet printer, including its print engine, processing power, and memory, can influence the printing speed. Printers with higher-end hardware components tend to offer faster printing speeds.

6. Print Mode: Inkjet printers often provide different print modes, such as draft mode, normal mode, or high-quality mode. Choosing a faster print mode, such as draft mode, can increase printing speed but may compromise print quality.

7. Paper Type and Size: Printing on different types and sizes of paper can affect printing speed. Specialty papers or larger paper sizes may require additional time for proper handling and ink absorption.

It's important to note that the speed of an inkjet printer is usually specified by the manufacturer and can vary significantly between different printer models. Therefore, it's advisable to refer to the printer's specifications or conduct performance tests to get accurate information about its printing speed under various conditions.

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The speed of an inkjet printer can be affected by several factors, including resolution, image complexity, and printer settings.

The speed of an inkjet printer can be influenced by several factors. One important factor is the resolution at which the printer is set. Higher resolutions mean more dots per inch (dpi), which requires more time to print. Additionally, the complexity of the image being printed can affect the speed. More complex images with lots of color and detail will take longer to print compared to simple text documents. Finally, the printer's settings, such as the print quality and speed settings, can also impact its printing speed.

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Answer:

The outer diameter of the ball is 6.2138 cm

Explanation:

The formula to apply is ;

Heat loss ,

\(Q/t=kA*\frac{( T_1-T_2)}{d}\)

where ;

Q/t=total heat loss from the ball = 1600 w

k=coefficient of heat transmission through the ball= 2.75 W/m.˚C

A=area in m² of the ball with the coefficient of heat transmission

T₁=Hot temperature

T₂=Cold temperatures

d=thickness of the ball

Area of spherical ball using internal diameter, 3cm= 0.03 m will be

Radius = half the diameter = 0.03/2 = 0.015

Area = 4 *π*r²

Area = 4*π*0.015² = 0.002827 m²

Apply the formula for heat loss to get the thickness as:

1600 = {2.75 * 0.002827 *(250-30 ) }/d

1600 =1.711/d

1600d = 1.711

d=1.711/1600 = 0.001069 m

d= 0.1069

Using internal radius and the thickness to get outer radius as;

3 + 0.1069 = 3.1069 cm

Outer diameter will be twice the outer radius

2*3.1069 = 6.2138 cm