I don’t understand I’m struggling with it

A-1hour in 36

B-16 min 12

Based on the cost of each of the snacks in a s'more, the number that the summer camp counselor can make is E.10.

The total change in temperature on the surface of Mercury is C. 1,168°F.

First, find out the cost of one s'more:
= (2 x 0.50) + 0.75 + (2 x 1.25)

= 1 + 0.75 + 2.50

= $4.25

The total s'mores that can be made is:

= 45 / 4.25

= 10 complete s'mores

= 869 - (-299)

= 869 + 299

= 1,168°F

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less than 85 milligrams per liter.

To find the probability that a water specimen has an alkalinity level of fewer than 85 milligrams per liter, we can use the standard normal distribution and convert the value of 85 milligrams per liter to a standard score (z-score). The z-score can be calculated using the formula:

z = (x - mean) / standard deviation

Where x is the value of interest (85 milligrams per liter), mean is the mean of the distribution (80 milligrams per liter), and the standard deviation is the standard deviation of the distribution (4.2 milligrams per liter).

Plugging in the values, we get:

z = (85 - 80) / 4.2 = 1.19

Next, we can use a standard normal table or calculator to find the probability of getting a value less than the z-score of 1.19. This probability is approximately 0.8707, so there is about an 87.07% chance that a water specimen collected from the river has an alkalinity level of fewer than 85 milligrams per liter.

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The system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X is shown in the figure.

Given that the system of equations are shown in given figure.

The first system of equations are

\(\begin{aligned}4x+2y-z&=150\\x+y-z&=-100\\-3x-y+z&=600\\\end\)

By writing in matrix AX=b, we get

Coefficient matrix \(A=\left[\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right]\) and \(B=\left[\begin{array}{l}150&-100&600\end{array}\right]\)

Firstly, we will find the A⁻¹ by finding the determinant and adjoint of A and divide the adjoint with determinant, we get

\(\begin{aligned}|A|&=\left|\begin{array}{lll}4&2&-1\\1&1&-1\\-3&-1&1\end{array}\right|\\ &=4(1-1)-2(1-3)-1(-1+3)\\&=4(0)-2(-2)-1(2)\\ &=2\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}0&2&2\\-1&1&-2\\-2&3&2\end{array}\right]^T\\&=\left[\begin{array}{lll}0&-1&-2\\2&1&3\\2&-2&2\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0&-0.5&-0.5\\1&0.5&1.5\\1&-1&1\end{array}\right]\end\)

For a solution Consider [A B] and apply row operations, we get

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{lll1}4&2&-1&150\\1&1&-1&-100\\-3&-1&1&600\end{array}\right]\\ R_{2}&\rightarrow 4R_{2}-R_{1},R_{3}\rightarrow 4R_{3}+3R_{1}\\ &\sim \left[\begin{array}{lll1}4&2&-1&150\\0&2&-3&-550\\0&2&1&2850\end{array}\right]\\ R_{3}&\rightarrow R_{3}-R_{2}\\ &\sim \left[\begin{array}{llll}4&2&-1&150\\0&2&-3&-550\\0&0&4&3400\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}-250\\1000\\850\end{array}\right]\)

The second system of equations are

\(\begin{aligned}x+y-z&=220\\5x-5y-z&=-640\\-x+y+z&=200\\\end\)

Similarly, we will find for second system of equations

\(\begin{aligned}|A|&=\left|\begin{array}{lll}1&1&-1\\5&-5&-1\\-1&1&1\end{array}\right|\\ &=1(-5+1)-1(5-1)-1(5-5)\\&=1(-4)-1(4)-1(0)\\ &=-8\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-4&-4&0\\-2&0&-2\\-6&-4&-10\end{array}\right]^T\\&=\left[\begin{array}{lll}-4&-2&-6\\-4&0&-4\\0&-2&-10\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.5&0.25&0.75\\0.5&0&0.5\\0&0.25&1.25\end{array}\right]\end\)

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}1&1&-1&220\\5&-5&-1&-640\\-1&1&1&200\end{array}\right]\\ R_{2}&\rightarrow R_{2}-5R_{1},R_{3}\rightarrow R_{3}+R_{1}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&2&0&420\end{array}\right]\\ R_{3}&\rightarrow 5R_{3}+R_{2}\\ &\sim \left[\begin{array}{llll}1&1&-1&220\\0&-10&4&-1740\\0&0&4&360\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}100\\210\\90\end{array}\right]\)

The third system of equations are

\(\begin{aligned}2x+2y-z&=290\\x+y-3z&=500\\x-y+2z&=600\\\end\)

Similarly, we will find for third system of equations

\(\begin{aligned}|A|&=\left|\begin{array}{lll}2&2&-1\\1&1&-3\\1&-1&2\end{array}\right|\\ &=2(2-3)-2(2+3)-1(-1-1)\\&=2(-1)-2(5)-1(-2)\\ &=-10\neq 0\end\)

\(\begin{aligned}Adj A&=\left[\begin{array}{lll}-1&-5&-2\\-3&5&4\\-5&5&0\end{array}\right]^T\\&=\left[\begin{array}{lll}-1&-3&-5\\-5&5&5\\-2&4&0\end{array}\right]\end\)

\(\begin{aligned}A^{-1}&=\frac{Adj A}{|A|}\\ &=\left[\begin{array}{lll}0.1&0.3&0.5\\0.5&-0.5&-0.5\\0.2&-0.4&0\end{array}\right]\end\)

get

\(\begin{aligned}\left[A\right.\text{ }\left.B\right]&=\left[\begin{array}{llll}2&2&-1&290\\1&1&-3&500\\1&-1&2&600\end{array}\right]\\ R_{2}&\rightarrow 2R_{2}-R_{1},R_{3}\rightarrow 2R_{3}-R_{1}\\ &\sim \left[\begin{array}{llll}2&2&-1&290\\&0&-5&710\\0&-4&5&910\end{array}\right]\end\)

Thus, \(x=\left[\begin{array}{l}x\\y\\z\end{array}\right]=\left[\begin{array}{l}479\\-405\\-142\end{array}\right]\)

Hence, each system of equations to the inverse of its coefficient matrix, A⁻¹, and the matrix of its solution, X.

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The interval provides a range within which we estimate the population mean weight difference to lie with a 95% level of confidence.

To find a 95% confidence interval of the weight differences between the two methods of weighing trucks, you would typically need data from both methods of weighing. The data would consist of paired observations, where each truck's weight is measured using both the dynamic (driving across a plate) and static (traditional) methods.

Assuming you have the necessary data, you can follow these steps to calculate the confidence interval:

1. Calculate the difference in weights between the two methods for each paired observation.

2. Calculate the mean of the weight differences.

3. Calculate the standard deviation of the weight differences.

4. Determine the sample size, denoted by 'n'.

5. Use the t-distribution with (n-1) degrees of freedom to find the critical value, denoted by 't', for a 95% confidence level.

6. Calculate the margin of error by multiplying the critical value 't' with the standard deviation of the weight differences divided by the square root of 'n'.

7. Construct the confidence interval by subtracting the margin of error from the mean of the weight differences to obtain the lower bound and adding the margin of error to the mean to obtain the upper bound.

Once you have the confidence interval, you can interpret it in the context of the problem. For example, you can say, "Based on our sample data, we are 95% confident that the true difference in weights between the dynamic and static weighing methods for trucks falls between [lower bound] and [upper bound] yards." The interval provides a range within which we estimate the population mean weight difference to lie with a 95% level of confidence.

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Let's call:

a: number of adults

c: number of children

90 people visited a museum, then:

a + c = 90

Tickets to the museum cost $12 for each adult and $7 for each child and the museum collected $950, then:

12a + 7c = 950

Isolating c in the first equation:

c = 90 - a

Replacing it into the second equation:

12a + 7(90 - a) = 950

12a + 7(90) - 7a = 950

5a + 630 = 950

5a = 950 - 630

a = 320/5

a = 64

64 adults visited the museum

Answer:

ITS B

Step-by-step explanation:

I GOT IT ALL RIGHT

Answer:

25.612

Step-by-step explanation:

by using Pythagorean theorem

\( \sqrt{ {10}^{2} + {8}^{2} } = 12.806\)

ad=dc

12.806 x 2 =25.612

As integers, proper or improper fractions in simplest form, or decimals

rounded to the nearest hundredth is \(u=-13+\sqrt{218}, u=-13-\sqrt{218}\)

What is fractions?

Any number of equal parts is represented by a fraction, which also represents a portion of a whole. A fraction, such as one-half, eight-fifths, or three-quarters, indicates how many components of a particular size there are when stated in ordinary English.

\(u^2+26 u-49=0\)

Solve with the quadratic formula

\(u_{1,2}=\frac{-26 \pm \sqrt{26^2-4 \cdot 1 \cdot(-49)}}{2 \cdot 1}\)

\(\sqrt{26^2-4 \cdot 1 \cdot(-49)}=2 \sqrt{218}\)

\(u_{1,2}=\frac{-26 \pm 2 \sqrt{218}}{2 \cdot 1}\)

Separate the solutions

\($$u_1=\frac{-26+2 \sqrt{218}}{2 \cdot 1}, u_2=\frac{-26-2 \sqrt{218}}{2 \cdot 1}$$\)

\(u=\frac{-26+2 \sqrt{218}}{2 \cdot 1}: \quad-13+\sqrt{218}\)

The solutions to the quadratic equation are:

\($$u=-13+\sqrt{218}, u=-13-\sqrt{218}$$\)

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Answer:

Step-by-step explanation:

Conclusion:

Therefore, 3/10 + 21/100 equals 51/100 as a fraction.

Hoped this helped.

\(BrainiacUser1357\)

0.51000 which as smaller is 0.51

Step-by-step explanation:

simplify 21/ 100 then add 3/10 + 21/100 then simplify 3/10 then you would do 3×10+21/100 which equals 51/100

The correct option is (C) Isosceles. An Isosceles triangle can be constructed with a 50° angle between two 8-inch sides.

This is because isosceles triangle having two sides that are equal in length, and have 50° angle, which is acute angle, that is less than 90°. This state that the remaining angle in the triangle must also be acute triangle, as the sum of all angles in a triangle must equal 180°.

This means that the remaining angle must be 80° (i.e. 180 - 50 = 80). An isosceles triangle is triangle consisting of  two sides of equal length and two angles of equal measure. The two equal sides that make up the isosceles triangle are referred to as the base and the remaining side is height or altitude.

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To differentiate \(2F(x) = 2x^2 - 8x^2 + 6\), we need to find the derivative of each term separately. The derivative of \(2x^2\) is 4x, and the derivative of \(-8x^2\) is -16x.

To differentiate \(2F(x) = 2x^2 - 8x^2 + 6\), we can differentiate each term separately. The derivative of \(2x^2\) is found using the power rule, which states that the derivative of \(x^n\) is \(nx^{(n-1)}\). Applying this rule, the derivative of \(2x^2\) is 4x.

Similarly, the derivative of \(-8x^2\) is found using the power rule as well. The derivative of \(-8x^2\) is -16x.

Lastly, the derivative of the constant term 6 is zero since the derivative of a constant is always zero.

Combining the derivatives of each term, we have 4x - 16x + 0. Simplifying this expression gives us -12x.

Therefore, the derivative of \(2F(x) = 2x^2 - 8x^2 + 6\) is -12x.

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Percentage of data within 2 population standard deviations of the mean is 68%.

To calculate the percentage of data within two population standard deviations of the mean, we need to first find the mean and standard deviation of the data set.

The mean can be found by summing all the values and dividing by the total number of values:

Mean = (20*2 + 22*8 + 28*9 + 34*13 + 38*16 + 39*11 + 41*7 + 48*0)/(2+8+9+13+16+11+7) = 32.68

To calculate standard deviation, we need to calculate the variance first. Variance is the average of the squared differences from the mean.

Variance = [(20-32.68)^2*2 + (22-32.68)^2*8 + (28-32.68)^2*9 + (34-32.68)^2*13 + (38-32.68)^2*16 + (39-32.68)^2*11 + (41-32.68)^2*7]/(2+8+9+13+16+11+7-1) = 139.98

Standard Deviation = sqrt(139.98) = 11.83

Now we can calculate the range within two population standard deviations of the mean. Two population standard deviations of the mean can be found by multiplying the standard deviation by 2.

Range = 2*11.83 = 23.66

The minimum value within two population standard deviations of the mean can be found by subtracting the range from the mean and the maximum value can be found by adding the range to the mean:

Minimum Value = 32.68 - 23.66 = 9.02 Maximum Value = 32.68 + 23.66 = 56.34

Now we can count the number of data points within this range, which are 45 out of 66 data points. To find the percentage, we divide 45 by 66 and multiply by 100:

Percentage of data within 2 population standard deviations of the mean = (45/66)*100 = 68% (rounded to the nearest percent).

Therefore, approximately 68% of the data falls within two population standard deviations of the mean.

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Answer: 8.63844

Step-by-step explanation:

With 90% confidence, we estimate that the proportion of high school graduates studying mathematics at university is at least 6.07%

The proportion of graduates studying mathematics can be calculated by dividing the number of graduates who will study mathematics (58) by the total number of surveyed graduates (702).

Proportion = Number of graduates studying mathematics / Total number of surveyed graduates

Proportion = 58 / 702

Now, to construct a confidence interval, we need to consider the sample size, the proportion of graduates studying mathematics, and the desired level of confidence. Since the question specifies a 90% confidence level, we will use the z-value associated with this level, which is approximately 1.645.

The formula for the confidence interval is:

Confidence Interval = Sample Proportion ± (z-value) * Standard Error

The standard error is calculated as the square root of (p * (1 - p) / n), where p is the proportion of graduates studying mathematics and n is the sample size.

In this case:

Sample Proportion = 0.0826

Sample Size = 702

z-value (for 90% confidence) ≈ 1.645

Standard Error = √(0.0826 * (1 - 0.0826) / 702)

Standard Error ≈ 0.0133 (rounded to four decimal places)

Substituting these values into the confidence interval formula, we get:

Confidence Interval = 0.0826 ± (1.645 * 0.0133)

Now, calculating the confidence interval:

Confidence Interval = 0.0826 ± 0.0219

To obtain the lower bound of the confidence interval, we subtract the margin of error from the sample proportion:

Lower Bound = 0.0826 - 0.0219

Lower Bound ≈ 0.0607

To express the lower bound as a percentage, we multiply it by 100:

Lower Bound as a Percentage ≈ 6.07%

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Answer:

A

C

D

Step-by-step explanation: Every other answer is wrong

Answer:

A, C,

Step-by-step explanation:

Answer:

9(68)

Step-by-step explanation:

9(68) = 612 cotton balls.

For C = 5x + 3y the cost found at the vertex (4,0) is maximum,

The correct option (2),  C = 5x + 3y

In the question it is given that

The vertices of a feasible region are (0, 0), (0, 2), (5, 2), and (4, 0).

To find the maximum C for the vertex (4,0).

We substitute the x = 4 and y = 0 in every option,

On substituting the value of x and y in option 1 we get

C = -2x + 3y

C = -2(4) + 3(0)

C = -8 + 0

C = -8 …(i)

Substituting in option 2 we get,

C = 5 x + 3y

C = 5(4) + 3(0)

C = 20 ….(ii)

Substituting in option 3 we get,

C = 2x + 7y

C = 2(4) + 7(0)

C = 8 +0

C = 8 …(iii)

Substituting in option 4 we get,

C = 4x - 3y

C = 4(4) - 3(0)

C = 16 - 0

C = 16 …(iv)

As we can see that from equation (i) , (ii) , (iii) and  (iv) , the maximum value is given by the function C = 5x + 3y, that option2.

Therefore, for C = 5x + 3y the cost found at the vertex (4,0) is maximum,

The correct option (2) C = 5x + 3y

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Answer:

18 units

Step-by-step explanation:

since the y- coordinates are equal then the 2 points lie on a horizontal line and the distance (d) between them is the absolute value of the x- coordinates, that is

d = | - 4 - 14 | = | - 18 | = 18

or

d = |  14 - (- 4) | = | 14 + 4 | =   18  = 18

The first partial derivatives are:

To find the first partial derivatives of the function w = ln(x^8y^9z), we differentiate with respect to each variable separately while treating the other variables as constants.

∂w/∂x:

When differentiating with respect to x, we treat y and z as constants:

∂w/∂x = (∂/∂x) ln(x^8y^9z)

To differentiate ln(u), where u is a function of x, we apply the chain rule:

∂w/∂x = (1/u) * du/dx

In this case, u = x^8y^9z, so:

∂w/∂x = (1/(x^8y^9z)) * (∂/∂x) (x^8y^9z)

Differentiating x^8y^9z with respect to x gives us:

∂w/∂x = (1/(x^8y^9z)) * (8x^7y^9z)

Simplifying:

∂w/∂x = 8x^7y^9z / (x^8y^9z)

∂w/∂x = 8/x

Similarly, we can find the other partial derivatives:

∂w/∂y:

Treating x and z as constants, differentiate x^8y^9z with respect to y:

∂w/∂y = (1/(x^8y^9z)) * (∂/∂y) (x^8y^9z)

∂w/∂y = (1/(x^8y^9z)) * (9x^8y^8z)

∂w/∂y = 9x^8y^8z / (x^8y^9z)

∂w/∂y = 9/y

∂w/∂z:

Treating x and y as constants, differentiate x^8y^9z with respect to z:

∂w/∂z = (1/(x^8y^9z)) * (∂/∂z) (x^8y^9z)

∂w/∂z = (1/(x^8y^9z)) * (x^8y^9)

∂w/∂z = 1/z

Therefore, the first partial derivatives are:

∂w/∂x = 8/x

∂w/∂y = 9/y

∂w/∂z = 1/z

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Answer:

C) A coordinate grid with the graph of a circle centered at the origin and passing through the point begin ordered pair 2 comma 1 end ordered pair.

Step-by-step explanation:

not sure tho lol

Equation V + Iwh , I = 32, w = 14, and h = 7, V = -3,136. The correct answer is B.

To solve for V in the equation V + Iwh, we can plug in the given values of I, w, and h, and then isolate V on one side of the equation. Here are the steps:

1. V + Iwh = V + (32)(14)(7)
2. V + 3,136 = V + 3,136
3. Subtract 3,136 from both sides of the equation: V = -3,136

The correct answer is option B: 3,136. Here is the solution in HTML format:

To solve for V in the equation V + Iwh, we can plug in the given values of I, w, and h, and then isolate V on one side of the equation. Here are the steps:

V + Iwh = V + (32)(14)(7)
V + 3,136 = V + 3,136
Subtract 3,136 from both sides of the equation: V = -3,136

The correct answer is option B: 3,136.

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Answer:

-5/4 or -1.25 or -1 1/4

Step-by-step explanation:

Answer:

$244.51

Step-by-step explanation:

Credit card payment =$5390

After paying $2300 from savings account,

Remaining payment left     = 5390-2300 = $3090

APR = 16.5% or 0.165

Time (t) = 14 months = 14/12 years

Using credit card payment calculator,

Monthly payment = $244.15

Hence, minimum monthly payment to be made to pay off the whole debt in 14 months = $244.15

The following functions are analytic:

1. f(z) = iz

2. f(z) = \(e^(^-^2^x^)(cos^2^y - isin^2^y^)\)

4. f(z) = \(e^x(cosy - isiny)\)

5. f(z) = \(Re(z^2) - iIm(z^2)\)

8. f(z) = \(i/z^8\)

11. f(z) = cos(x)cos(hy) - isin(x)sin(hy)

Analytic functions are those that can be expressed as power series expansions, meaning they have derivatives of all orders in their domain. In the given list of functions, we need to determine if each function satisfies this criterion.

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Answer:

Step-by-step explanation:

if two lines are parallel and a transversal cuts it,then corresponding angles are equal.

?=130°(corresponding angles)

To prove that if a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee, we can use the Pigeonhole Principle.

There are 365 days in a year, and if a person buys at least 400 cups of coffee, there are more cups of coffee than days. By the Pigeonhole Principle, there must be at least one day where the person buys at least two cups of coffee.

The average of three real numbers is greater than or equal to at least one of the numbers. This is true because the average of the three numbers is the sum of the numbers divided by three. If all the numbers are equal, then the average is equal to each number. If at least one number is greater than the other two, the average will be greater than or equal to the smallest number.

To show that the cube root of 2 is irrational, we can use proof by contradiction. Assume that the cube root of 2 is rational, meaning it can be expressed as a fraction a/b where a and b are integers with no common factors. Then (a/b)^3 = 2. This implies a^3 = 2b^3. Since a^3 is even (because it is equal to 2 times an integer), we know that a must be even based on the given fact. Let a = 2c, then (2c)^3 = 2b^3. This simplifies to 8c^3 = 2b^3, or b^3 = 4c^3. Now, b^3 is also even, meaning b is even. However, this contradicts our assumption that a and b have no common factors, as both are divisible by 2. Thus, our assumption that the cube root of 2 is rational must be false, and the cube root of 2 is indeed irrational.

Regarding the statement "there is no smallest integer," we can prove this by considering any integer n. Since integers include negative numbers, we can find a smaller integer by subtracting 1 from n, resulting in n - 1. This process can be repeated indefinitely, showing that there is no smallest integer.

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We accert H1 alternative that is result is population mean greater than 400.

There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

What is standard deviation?

The standard deviation is a statistic that expresses how much variance or dispersion there is in a group of numbers. While a high standard deviation suggests that the values are dispersed throughout a wider range, a low standard deviation suggests that the values tend to be close to the established mean.

We have given: μ = 14, x bar = 16, n = 40, s = 6,  α = 5%, = 0.05

To test μ0 : μ = 14   Vs  H1: μ > 14

Test statistics = (X bar - μx)√n / sx = (2 x 6.3245) / 6 = 2.1081

So, P value = 0.021

Conclusion: There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

P value for the hypothesis test

n = 50, x bar = 420, sx = 81, μ = 400,

To test:  H0: μ 400    Vs   H1:  μ > 400

It is right tail test

Test statistics =  (X bar - μx)√n / sx = (420 - 400) √50 / 81 =

z = 1.7459

P value = 0.04093

Declsion: We reject H0 is p value < α

Here α = 0.05

Hence P value < α

Conclusion: We accert H1 alternative that is result is population mean greater than 400.

Hence, we accert H1 alternative that is result is population mean greater than 400.

There is a 2.1% chance than mean second Trimester weight gain for all expectant mothers is 14 pounds in 2015.

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Answer:

First, we have to set it from least to greatest 11, 12, 12, 13, 14, 15, 16, 17, 18

The  interqurtile range is q3 - q1

Q3 is 16.5 and the q1 is 12

16.5 - 12 = 4.5

Step-by-step explanation:

Answer is 4.5

Interquartile range (IQR) :

The interquartile range shows the range in values of the central 50% of the data. To find the interquartile range, subtract the value of the lower quartile ( or 25%) from the value of the upper quartile ( or 75%).

=>  IQR = Q3 – Q1

Here,

First Arrange the data in ascending order.

11, 12, 12, 13, 14, 15, 16, 17, 18

Median = 14.

Q1 = 12 and Q3 = 16.5

IQR = Q3 - Q1 => 16.5 - 12 = 4.5

Answer is 4.5

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Answer:

Faltan 265 metros por embaldosar.

Step-by-step explanation:

Un decámetro equivale a 10 metros, mientras que un hectómetro equivale a 100 metros. A continuación, calculamos la longitud equivalente de calle en metros:

\(x = 3\,hm \times \left(\frac{100\,m}{1\,hm} \right)+9\,dam\times \left(\frac{10\,m}{1\,dam} \right)\)

\(x = 390\,m\)

La longitud pendiente por poner baldosas es la longitud total menos la longitud ya embaldosada, es decir:

\(y = 390\,m-125\,m\)

\(y = 265\,m\)

Faltan 265 metros por embaldosar.