I GIVE BRAINLYS. I can use my knowledge of polygons to sort quadrilaterals that have more than one property O A strongly agree O B. agree OC. disagree O D. strongly disagree​​

Answer:

205 1/3

Step-by-step explanation:

Because it travels an average of 25 2/3 on one gallon, you simply multiply it by 8 in order to find how many miles it travels on 8 gallons of gas.

Answer: 63

Step-by-step explanation:

3(-3)^2 + 2(6)^2 (multiply 3 times -3) & (multiply 2 times 6)

-9^2+12^2 (-9 to the 2nd power and 12 to the 2nd power)

-81+144 (add them up)

=63

The value of the expression is 3a² + 2b² is 69.

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

Given:

Expression: 3a² + 2b²

Not, put the value of a= -3 and b=6 we get

= 3a² + 2b²

= 3(-3)² + 2(4)²

= 3 x 9 + 2 x 16

= 37 + 32

= 69

Hence, the value of expression is 69.

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Answer: 36 yards

Step-by-step explanation:

Determine how much was spent.

15-8.88= $6.12

Each yard was 17 cents and $6.12 was spent.

6.12/.17= 36

(Amount spent/Cost per yard)= Amount of ribbon (in yards)

36 yards

In 144 ways can four men and four ladies be seated at a round table such that no two men are to be in adjacent seats.

In the given question we have to check in how many ways can four men and four ladies be seated at a round table such that no two men are to be in adjacent seats.

4 men and 4 ladies have to sit in the round table.

No two men should sit together.

So first we arrange 4 ladies in the round table. We arrange 4 ladies in the round table in four direction and the we get four places left in the middle of two women. Then we can arrange the 4 men there.

To make 4 ladies to sit in round table = (4-1)!

To make 4 ladies to sit in round table = 3!

To make 4 ladies to sit in round table = 6 ways

Now 4 men in gaps can be arranged in 4! = 24 ways

Hence, total number of ways = 6*24

Total number of ways = 144 ways

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Answer: \(x=\frac{1}{2}, y=4\)

Step-by-step explanation:

Setting the equations equal to each other,

\(4x+2=-8x+8\\\\12x+2=8\\\\12x=6\\\\x=\frac{1}{2}\)

This means \(y=4\left(\frac{1}{2} \right)+2=4\)

So, the solution is \(\boxed{x=\frac{1}{2}, y=4}\)

Hello

The sample which she has to study is 200

The answer to this question is option A

Step-by-step explanation:

15 + 17 + 23 + 19

32 + 42 = 74

74/4 = 18.5 is the mean

Answer:

Mean= 18.5

Step-by-step explanation:

How to Find the Mean

Add up all data values to get the sum

Count the number of values in your data set

Divide the sum by the count

The mean is the same as the average value in a data set.

Mean Formula

The mean x of a data set is the sum of all the data divided by the count n.

Answer:

\( m\angle O = 134 \degree\)

Step-by-step explanation:

AC and AB are tangents to the circle with center O on points C and B respectively from point A.

Therefore

\( m\angle ACO=m\angle ABO=90\degree \)

\( m\angle CAB=46...(given) \degree \)

\(m\angle O = 360 \degree - (2 \times 90 \degree + 46 \degree) \\ \\ m\angle O = 360 \degree - (180 \degree + 46 \degree) \\ \\ m\angle O = 360 \degree - (226 \degree) \\ \\ m\angle O = 134 \degree\\ \\ \)

Answer:

144ft^3

Step-by-step explanation:

To start, we have your formula: \(V=\frac{1}{2} (bh) (l)\)
b = base length of the triangle.
h = height of the triangle.
l = length of the prism

Fill in for each of those values:
\(V = \frac{1}{2} (6x6)(8)\)

\(V=\frac{1}{2} (36)(8)\)

\(V=(18)(8)\)

\(V=144\)

Your answer, because it is a 3D shape, should be cubed, so:
\(V=144ft^{3}\)

If he wants an average of 84, he needs to get at least 93 points.

Remember that the average value between 3 values A, B, and C is:

(A + B + C)/3

Here we know that the first two scores are 76 and 83 points, let's say that the third score is x, if we want to have an average of 84 or more, then we need to solve:

(76 + 83 + x)/3 = 84

159 + x = 252

x = 252 - 159

x = 93

So he needs to get at least 93 points in the next exam.

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Answer:

ray UV and ray UT

Step-by-step explanation:

The sides are the rays that make up the angle

ray UV and ray UT make up the angle VUT

If we want the slope to be -6/7, then the value of x must be -5.

Remember that if a linear equation passes through (x₁, y₁) and (x₂, y₂), then the slope is:

\(a = \frac{y_2 - y_1}{x_2 - x_1}\)

Here we have the points (x, 9) and (9, -3), and the slope must be -6/7, so we need to solve:

\(\frac{- 3 - 9}{9 - x} = \frac{-6}{7} \\\\\frac{-12}{9 - x} = \frac{-12}{14}\)

Where on the second line we multiplied and divided the right fraction by 2.

Comparing the fractions, we see that we must have:

9 -x = 14

9 - 14 = x

-5 = x

So the value of x must be -5.

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Answer:

EG = 41

Step-by-step explanation:

since angles E and G are equal, the sides opposite them are equal

5x+23 = 7x+9

23 = 2x+9

14 = 2x

7 = x

EG = 6x-1

substitute 7 for 'x' to get:

EG = 6(7)-1 = 41

Answer:

The answer is 16.90 because 52.50 minus 35.5 is 16.90.

Answer:

D

Step-by-step explanation:

Took the test

Answer:

y=4x+7

Step-by-step explanation:

The image of the point L(-4,0) after a dilation with a center of (0,0) and a scale factor of 7 is the point L'(-28,0).

A dilation with a center of (0,0) and a scale factor of 7 means that every point in the plane will be multiplied by a factor of 7 from the origin.

To find the image of the point L(-4,0) after a dilation with a center of (0,0) and a scale factor of 7, we can simply multiply the coordinates of L by the scale factor.

The coordinates of the image point L' will be:

L' = (-4 × 7, 0 × 7) = (-28, 0)

Therefore, the image of the point L(-4,0) after a dilation with a center of (0,0) and a scale factor of 7 is the point L'(-28,0).

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The correct answer is 3/2. In this case, x = 3/2, and its square, (3/2)^2 = 9/4, is rational. x satisfies the given condition.option (c)

To explain further, we need to understand the properties of rational and irrational numbers.

A rational number can be expressed as a fraction of two integers, while an irrational number cannot be expressed as a fraction and has non-repeating, non-terminating decimal representations.

In the given options, (a) √5102.0 (£) and (b) √2 are both irrational numbers.

Their squares, (√5102.0)^2 and (√2)^2, would also be irrational, violating the given condition. On the other hand, (d) 4/5 is rational, and its square, (4/5)^2 = 16/25, is also rational.

Option (c) 3/2 is rational since it can be expressed as a fraction. Its square, (3/2)^2 = 9/4, is rational as well.

Therefore, (c) 3/2 is the only option where x is rational, but its square is irrational, satisfying the condition mentioned in the question.

In summary, the number x that satisfies the given condition, where x^2 is irrational but x is rational, is (c) 3/2.option (c)

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Answer: See the diagram below.

There is an open hole at -4/5 and shading to the left

This visually describes any value that is smaller than -4/5 as stuff to the left is smaller than stuff to the right. The value -4/5 itself is not part of the solution set because we don't have "or equal to" as part of the inequality sign.

Answer:

27

Step-by-step explanation:

the

Answer:

Not sure but try

Step-by-step explanation:

1, 6 < 2x

2, c = b2

3, a + g / 5

4, (c^4)7u

5, y > 4(9)

6, e < 10 + p

The probabilities is as follows:

a) P(Z \(\leq\) -1.0) = \(\Phi\)(-1.0) = 0.1587.

b) P(Z \(\geq\) -1.0) = 1 - P(Z < -1.0) = 1 - 0.1587 = 0.8413.

c) P(Z \(\geq\) -1.5) = 1 - P(Z < -1.5) = 1 - \(\Phi\)(-1.5) = 1 - 0.0668 = 0.9332.

d) P(Z \(\geq\) -2.5) = 1 - P(Z < -2.5) = 1 - \(\Phi\)(-2.5)=1-0.0062=0.9938

e) P(-3 < Z \(\leq\) 0) = P(Z \(\leq\) 0) - P(Z < -3) = \(\Phi\)(0) - \(\Phi\)(-3) = 0.5 - 0.0013 = 0.4987.

The standard normal distribution, commonly known as the z-distribution, is a unique type of normal distribution in which the mean and standard deviation are both equal to 1.

Any normal distribution can be made into the conventional normal distribution by converting the ad hoc data into z-scores. Z-scores in a z-distribution show the number of standard deviations that each value deviates from the mean.

Let Z be a random variable following N(0,1).

Then, Z is also called a standard normal variable.

The cumulative distribution function of Z exists represented by Ф(.) where Ф(z) = P(Z \(\leq\) z).

Suppose we wish to find \($P(a \leq X \leq b)$\).

Then, P(a \(\leq\) X \(\leq\) b) = P(X \(\leq\) b) - P(X < a) = \(\Phi(b)-\Phi(a)$\).

Suppose \($Z \sim N(0,1)$\).

a) P(Z \(\leq\) -1.0) = \(\Phi\)(-1.0) = 0.1587.

b) P(Z \(\geq\) -1.0) = 1 - P(Z < -1.0) = 1 - 0.1587 = 0.8413.

c) P(Z \(\geq\) -1.5) = 1 - P(Z < -1.5) = 1 - \(\Phi\)(-1.5) = 1 - 0.0668 = 0.9332.

d) P(Z \(\geq\) -2.5) = 1 - P(Z < -2.5) = 1 - \(\Phi\)(-2.5)=1-0.0062=0.9938

e) P(-3 < Z \(\leq\) 0) = P(Z \(\leq\) 0) - P(Z < -3) = \(\Phi\)(0) - \(\Phi\)(-3) = 0.5 - 0.0013 = 0.4987.

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The perimeter of the rectangle is 4h + 6

An algebraic expression can be defined as an expression that is composed of terms, variables, coefficients, constants and factors.

These expressions are also made up of arithmetic operations, such as;

The formula for calculating the perimeter of a rectangle is expressed as;

Perimeter = 2( l + h)

Where;

l = 3 + h

Substitute the values

Perimeter = 2( 3 + h+ h)

expand the bracket

Perimeter = 2(3 + 2h)

Perimeter = 4h + 6

Hence, the expression is 4h + 6

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Step-by-step explanation:

D bruce's boats: $22.50

The formula for this function is y = 0.9 * cos((2π/3) x + π/2) - 1.2

From the image attached, that looks like a cosine graph with 3 periods. 2 highs and 1 low. Also, it should be noted that it is a cosine function.

Therefore to derive the formula for the graph, we use a cosine function with a phase shift and amplitude adjustment.

The general formula for a cosine function is:

f(x) = A * cos(Bx + C) + D

where

A = amplitude,

B = frequency,

C = phase shift,

D = vertical shift.

To get the Amplitude:

We want the function to oscillate between 2.1 and 0.3, which is a difference of 1.8. Since the sine function oscillates between -1 and 1, we need to multiply it by half the desired difference to get the right amplitude. Therefore,

A = 1/2 *1.8 = 0.9.

To get the Frequency:

Since there are only three periods in the interval, then

frequency =  2π/3.

Therefore B = 2π/3.

To get the Phase shift:

We want the function to peak at x = 0, so we need a phase shift of π/2.

Therefore C = π/2.

To get Vertical shift:

We want the function to have a trough at y = 0.3, which means we need to shift it down by 1.8/2 + 0.3 = 1.2. We set D = -1.2.

Putting all these parameters together, we get the following formula:

f(x) = 0.9 * cos((2π/3) x + π/2) - 1.2

This function will oscillate between 2.1 and 0.3 over three periods, with a peak at x = 0 and a trough at y = 0.3.

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Answer:

A'= (-2,-3)

B'=(0,-3)

C'=(-1,1)

Step-by-step explanation:

coordinates reflected over the x axis follow the rule (x,y) becomes (x,-y). so just multiply each y coordinate by -1 to find the reflected coordinate

Check the picture below.

The coordinates of the vertex of the parabola are (3, -7). The focus of the parabola is located at (3, -3). The equation of the directrix is y = -11.

The given equation of the parabola is in the form (x - h)^2 = 4p(y - k), where (h, k) represents the vertex and p represents the distance between the vertex and the focus/directrix.

Comparing the given equation with the standard form, we can see that the vertex is at (3, -7).

The coefficient 4p in this case is 16, so p = 4. Since the parabola opens upward, the focus will be p units above the vertex. Therefore, the focus is located at (3, -7 + 4) = (3, -3).

To find the directrix, we need to consider the distance p below the vertex. Since the parabola opens upward, the directrix will be p units below the vertex. Hence, the equation of the directrix is y = -7 - 4 = -11.

In summary, the coordinates of the vertex are (3, -7), the focus is located at (3, -3), and the equation of the directrix is y = -11.

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1) Using the Law of Syllogism, we can combine statement 1 and statement 3 to conclude that Sally weighs more than Jill's car:

If something weighs more than 2000 pounds, then it weighs more than Jill’s car.

Sally weighs more than 2000 pounds.

Therefore, Sally weighs more than Jill's car.

2) Using the Law of Detachment, we can apply statement 2 to our conclusion from the Law of Syllogism to conclude that Sally is too heavy for the bridge:

If something weighs more than Jill’s car, then it is too heavy for the bridge.

Sally weighs more than Jill's car.

Therefore, Sally is too heavy for the bridge.

The Law of Syllogism opines that if two conditional statements have the same terms, then we can combine them to form a conclusion.

The Law of Detachment states that if a conditional statement is true and its hypothesis is true, then its conclusion is also true.

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Answer:

B) h=63

Step-by-step explanation:

Multiply both sides by 9.

h/*9=9*7

Simplify

h=63

\(\bf{\dfrac{h}{9}=7 \ \ \to \ \ \ Exercise \ to \ solve }\)

Multiply both sides by 9.

Multiply 7 and 9 to get 63.

Therefore, the correct option is "B".

\(\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}\)

Answer: Translation up 5 units means g(x)=f(x)+5g(x)=f(x)+5. Reflecting this across the x-axis means g(x)=-(f(x)+5)g(x)=−(f(x)+5).

-(4x+5)=-4x-5

−(4x+5)=−4x−5

Step-by-step explanation:

Answer:

g(x) = -|x + 12|

Step-by-step explanation:

Translation to left ≡ f(x + 12)

f(x + 12) = | x + 12 |

Reflection of a function f(x) about the x - axis is keeping the x value same but negating the y values

Reflected f'(x) = -y = -f(x)

Taken together

g(x) = -(|x + 12|)

Answer:

f(x) = x³ - 4x + 6

f'(x) = 3x² - 4

a) f'(2) = 3(2²) - 4 = 12 - 4 = 8

6 = 8(2) + b

6 = 16 + b

b = -10

y = 8x - 10

b) 3x² - 4 = 0

3x² = 4, so x = ±2/√3 = ±(2/3)√3

= ±1.1547

f(-(2/3)√3) = 9.0792

f((2/3)√3) = 2.9208

c) 3x² - 4 = 8

3x² = 12

x² = 4, so x = ±2

f(-2) = (-2)³ - 4(-2) + 6 = -8 + 8 + 6 = 6

6 = -2(8) + b

6 = -16 + b

b = 22

y = 8x + 22

f(2) = 6

y = 8x - 10

The equation perpendicular to the tangent is y = -1/8x + 25/4

-The smallest slope on the curve is 2.92

The curve has the smallest slope at the point (1.15, 2.92)

The equations at tangent points are y = 8x + 16 and  y = 8x - 16

From the question, we have the following parameters that can be used in our computation:

y = x³ - 4x + 6

Differentiate

So, we have

f'(x) = 3x² - 4

The point is (2, 6)

So, we have

f'(2) = 3(2)² - 4

f'(2) = 8

The slope of the perpendicular line is

Slope = -1/8

So, we have

y = -1/8(x - 2) + 6

y = -1/8x + 25/4

We have

f'(x) = 3x² - 4

Set to 0

3x² - 4 = 0

Solve for x

x = √[4/3]

x = 1.15

So, we have

Smallest slope = (√[4/3])³ - 4(√[4/3]) + 6

Smallest slope = 2.92

So, the smallest slope is 2.92 at (1.15, 2.92)

Here, we set f'(x) to 8

3x² - 4 = 8

Solve for x

x = ±2

Calculate y at x = ±2

y = (-2)³ - 4(-2) + 6 = 6: (-2, 0)

y = (2)³ - 4(2) + 6 = 6: (2, 0)

The equations at these points are

y = 8x + 16

y = 8x - 16

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