The given equation representing linear acceleration is:
\(a_{linear}=\frac{\triangle v}{t}\)To make △v the subject of the equation, multiply both sides by t
\(\begin{gathered} a_{linear}\times t=\frac{\triangle v}{\cancel{t}}\times\cancel{t} \\ \\ \triangle v=a_{linear}t \end{gathered}\)A 4kg ball moving 8m/s to the right collides with a 2kg ball at rest. After the
collision, the 4kg ball moves with a new velocity of 4.8m/s to the right. Assuming
that the collision is elastic, how fast is the 2kg ball moving?
We can see that the new velocity of the 2 Kg ball is 6.4 m/s.
What is the momentum?Momentum is a measure of an object's motion. It is defined as the product of an object's mass and velocity. In physics, momentum is a vector quantity, meaning it has both magnitude and direction.
The law of conservation of momentum states that in an isolated system, the total momentum of the system remains constant if no external forces are acting upon it.
Given that we know that;
Momentum before collision = Momentum after collision
(4 * 8) + (2 * 0) = (4 * 4.8) + (2 * v)
Let v be the new velocity
32 = 19.2 + 2v
v = 32 - 19.2/2
v = 6.4 m/s
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Two bodies separated from
each other at a certain distance
started moving simultaneously
to meet each other - one with ar
acceleration of 2.4 m/s, and the
other with an acceleration of 4.8
m/s2. Determine the ratio of the
displacement module of the first
body to the displacement
module of the second body at
the moment of their meeting.
The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.
How to find displacement ratio?To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:
d = vt + 1/2at²
where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.
Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.
Assume that the time at which they meet is t, then:
d₁ = 1/2 * 2.4t²
And the equation for the displacement of the second body:
d₂ = 1/2 * 4.8t²
If d₁ = d₂
then, 1/2 * 2.4t² = 1/2 * 4.8t²
Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2
So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.
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What is an example of a combined approach in psychology?
Answer:
The third approach to cross-cultural studies of personality is the combined approach, which serves as a bridge between Western and indigenous psychology as a way of understanding both universal and cultural variations in personality
Explanation:
Answer:
The third approach to cross-cultural studies of personality is the combined approach, which serves as a bridge between Western and indigenous psychology as a way of understanding both universal and cultural variations in personality
A student is measuring the density of a liquid. He places a measuring cylinder on a balance and records its mass. He then pours liquid into the cylinder and records the new reading on the balance. He also records the volume of the liquid.
Mass of empty cylinder = 147 g
Mass of cylinder + liquid = 203 g
Volume of liquid = 59 cm³
Using the results shown, calculate the density of the liquid.
Answer:
0.95g/cm3
Explanation:
sorry I did it in a rough paper.
                                                            A train leaving the station accelerates from a full stop at a rate of 0.250 meters per second squared for 45.0 seconds. How far does the train travel during this time?
Answer:
\(\boxed {\boxed {\sf 253 \ meters}}\)
Explanation:
We are asked to find the distance a train travels.
We are given the acceleration, initial velocity, and time. Therefore, we will use the following kinematic equation:
\(d=v_it+\frac{1}{2}at^2\)
The train starts at a full stop or a velocity of 0 meters per second. It accelerates at a rate of 0.250 meters per second squared for 45.0 seconds.
\(v_i\)= 0 m/s a= 0.250 m/s²t=45.0 sSubstitute the values into the formula.
\(d= (0 \ m/s)(45.0 \ s) + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2\)
Multiply the first two numbers. The units of seconds cancel.
\(d= 0 \ m + \frac{1}{2} (0.250 \ m/s^2)(45.0 \ s)^2\)
Solve the exponent.
(45.0 s)² = 45.0 s *45.0 s = 2025 s²\(d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2)(2025 \ s^2)\)
Multiply the numbers in parentheses. The units of seconds squared cancel.
\(d= 0 \ m +\frac{1}{2} (0.250 \ m/s^2 * 2025 \ s^2)\)
\(d= 0 \ m +\frac{1}{2} (0.250 \ m * 2025 )\)
\(d= 0 \ m + \frac{1}{2} (506.25 \ m)\)
Multiply by 1/2 or divide by 2.
\(d=0 \ m + 253.125 \ m \\d= 253.125 \ m\)
The original measurements of acceleration and time both have 3 significant figures, so our answer must have the same. For the number we found, that is the ones place. The 1 in the tenths place tells us to leave the 3.
\(d \approx 253 \ m\)
The train travel approximately 253 meters.
Which of these would be the BEST way to illustrate the percentage of students receiving A's,
B's, C's, D's and F's on a recent test? *
Bar graph
Circle graph
Line graph
Scatter graph
Answer:
it’s circle graph
Explanation:
the best type of graph to use to show the percentages of a whole is a circle graph
Margo is being pulled from a snake pit with a rope that breaks if tension in it
exceeds 755N. If Margo hasa mass of 70.0 kg and the snake pit is 3.4m
deep, what is the minimum time necessary to pull out Margo (s)?
The minimum time necessary to pull out Margo is 2.64 seconds.
Given the data in the question;
Tension; \(T = 755N\)mass; \(m = 70.0kg\)depth or distance; \(s = 3.4m\)There are two forces acting on Margo, as shown in the image below, the rope Tension acting upward and the force of gravity acting downward.
From Newton's second law of motion:
\(F = m*a\)
where F is the Force acting on the body, m is the mass and a is the acceleration.
Also, \(F = T - mg\)
So, \(T - mg = ma\)
We know that the value of "g" gravitation due to gravity is \(9.81m/s^2\) and \(1Newton = 1 kg.m/s^2\)
We substitute in our values to find "a"
\(755 kg.m/s^2 - ( 70.0kg*9.81m/s^2) = (70kg * a )\)
\(755 kg.m/s^2 - 686.7 kg.m/s^2 = (70kg * a )\)
\(68.3kg.m/s^2 = (70kg * a )\)
\(a = \frac{68.3kg.m/s^2}{70kg}\)
\(a = 0.9757 m/s^2\)
Now, we set \(v_0 = 0\) to get the minimum time required
From the second equation of motion:
\(s = v_0t + \frac{1}{2} at^2\)
Since \(v_0 = 0\)
\(s = \frac{1}{2} at^2\)
We make time "t", the subject of the formula
\(t = \sqrt{\frac{2s}{a} }\)
We substitute in our values
\(t = \sqrt{\frac{2*3.4m}{0.9757m/s^2} }\)
\(t = 2.63995 s\\\\t = 2.64s\)
Therefore, the minimum time necessary to pull out Margo is 2.64 seconds.
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                                                            please help me with this physics problem
                                                Answer:
It says the answer. (5 marks.)
Explanation:
The FitnessGram Pacer Test is a multistage aerobic capacity test that progressively gets more difficult as it continues. The 20 meter pacer test will begin in 30 seconds. Line up at the start. The running speed starts slowly, but gets faster each minute after you hear this signal. A single lap should be completed each time you hear this sound. Remember to run in a straight line, and run as long as possible.
8. An airplane of mass 8500 kg dives has an altitude of 15,000 m. It then dives steeply to an
altitude of 11,000 m. What was the change in potential energy?
Answer:
333.5 MJ
Explanation:
ΔV = m·g·Δh
= 8500 · 9.81 · (15000-11000)
= 8500 · 9.81 · 4000
= 333 540 000
≈ 333.5 ·10⁶J = 333.5 MJ
The change in potential energy is 333.5 MJ
What is Potential Energy?
Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.
It can be expressed as:
P.E.= mgh
where, m is the mass of an object measured in grams 'g'
g is the acceleration due to gravity which is \(9.8 m/s^2\)
h is the height measured in meter 'm'
Here,
the given information is
m= 8500kg
Δh= \(h_2 - h_1\) = 15000-11000 = 4,000m
So, P.E. = 850 x 9.8 x 4000 = 333 540 000= 333.5 ·10⁶J = 333.5 MJ
Thus, the change in potential energy is 333.5 MJ
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The word "static" means
A sticky
B rough
C not moving
Answer:
not moving
static actually means lacking in movement or action❤
The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be greater than the acceleration due to gravity, keeping the passengers pressed firmly into their seats. What is (a) the speed of the roller coaster at the top of the loop (in m/s) if the radius of curvature there is 13.0 m and the downward acceleration of the car is 1.50 g, and (b) the minimum speed necessary for the coaster to complete the loop without falling off the track?
the answer for the speed of the roller coaster at the top of the loop is v = 14.8 m/s
the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
Explanation to the Roller Coaster Speed Calculation(a) To find the speed of the roller coaster at the top of the loop, we can use the equation for centripetal acceleration: a = v^2/r. We know that the radius of curvature is 13.0 m and the downward acceleration of the car is 1.50 g (where g is the acceleration due to gravity, approximately 9.8 m/s^2).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(1.5g * 13m)
v = sqrt(22.5 * 9.8)
v = sqrt(219.5)
v = 14.8 m/s
(b) To find the minimum speed necessary for the coaster to complete the loop without falling off the track, we can use the same equation for centripetal acceleration, but this time we will use the minimum value of a that will keep the car on the track, which is equal to the acceleration due to gravity (g).
So, we can rearrange the equation to solve for v: v = sqrt(ar)
Plugging in the values, we get: v = sqrt(g * 13m)
v = sqrt(9.8 * 13m)
v = sqrt(127.4)
v = 11.3 m/s
So the minimum speed necessary for the coaster to complete the loop without falling off the track is 11.3 m/s.
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Which of the following examples of the streets Newton second law of motion
Explanation:
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
distinguish among clastic chemical and biochemical sedimentary rocks
Clastic chemical rocks are fragments of rocks called clasts, while biochemical sedimentary rocks are composed of preserved remains of dead organisms (fossils).
What are biochemical sedimentary rocks?Biochemical sedimentary rocks or fossils are biological associated rocks formed by the accumulation of organic matter which is due to the presence of organisms that lived in the geological past, while clastic rocks are clasts, i.e. fragments of rock composed of minerals on the Earth's crust.
Therefore, with this data, we can see that biochemical sedimentary rocks can also be defined as fossils, while clastic rocks are clasts.
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______________ is the term that means energy has been transferred or moved between objects of different temperatures. 
Biosphere
Temperature
Kinetic energy
Heat
Answer:
Heat.
Explanation:
Ily bbg keep slangin.
                                                            What is the magnitude of the resultant vector? Round your answer to the nearest tenth. m
The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.
In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.
When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.
In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.
For example, if the answer is 12.345, we would round it to 12.3.
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The musical note A above middle C has frequency of 440Hz. What is the wavelength of the sound produced
Answer:
These destructive frequencies entrain the thoughts towards disruption, disharmony, and disunity. Additionally, they also stimulate the controlling organ of the body — the brain — into disharmonious resonance, which ultimately creates disease and war.
1. A Ograph A Ograph B Ograph c Which graph represents what happens to the pressure in a tire as air is added to the tire, assuming the temperature is constant? 
                                                Answer:
Explanation:
It's graph A because the pressure in the tire is increasing as the amount of air going into it increases. B says the pressure drops exponentially as air goes in, and C says that the pressure stays the same as air goes in. Pressure in a tire increases proportionally to the amount of air in it.
Solubility Curve Practice Problems Worksheet 1
Directions: Find the mass of solute will dissolve in 100mL of water at the following temperatures?
150
1. KCl at 70°C =
140
2. Ce,(SO.), at 100°C=
130
120
3. NH.Cl at 90°C=
4. Which of the above three substances is most
110
100
NaNO3
soluble in water at 15°C. =
90
KNO3
Grams of solute
per 100 g H,0
80
70
60
NH3
NHACI
50
KCI
40
Naci
30
20
KCIO
10
Ce2(SO4)3
0
10 20 30 40 50 60 70 80 90 100
Temperature (°C)
According to the solubility curve, KCl is soluble in water at a rate of about 40 grammes per 100 g. Given that we have 100 mL, or 100 grammes, of water, the mass of KCl that will dissolve is similarly 40 grammes.
\(Ce_2(SO_4)_3\) is soluble in water at a rate of around 30 grammes per 100 grammes at 100 °C. \(Ce_2(SO_4)_3\) will therefore dissolve in 100 mL of water at a mass of 30 grammes.
\(NH_4Cl\) dissolves in water at a rate of around 90 grammes per 100 grammes at 90 °C. The mass of \(NH_4Cl\) that will dissolve in 100 mL of water is similarly 90 grammes.
We must ascertain the solubilities of the abovementioned chemicals at 15°C in order to ascertain which substance is most soluble at that temperature.
\(NaNO_3\) has the highest solubility at 15°C, as seen by the solubility curve. At 15°C, \(NaNO_3\) dissolves in water at a rate of about 80 grammes per 100 g.
Therefore, at 15°C, NaNO3 is the most soluble substance among the three given substances.
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Define angle of deviation ?
Angle of deviation can be defined as the angle between the incident ray and the emergent ray when light passes through a prism.
What are related terms to Angle of deviation?When speaking of Angle of deviations, the incident ray is the ray of light that hitss the prism, while the emergent ray is the ray of light that emerges from the prism.
The angle of deviation is noted to be always greater than zero, and it can be used to calculate the refractive index of the prism.
The angle of deviation can be calculated using δ = i + r - A
δ is the angle of deviation
i is the angle of incidence
r is the angle of refraction
A is the angle of the prism
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(8.6) A space station in deep space is spun like a giant wheel to produce centrifugal force so the occupants experience artificial gravity of one g. How does a clock at the rim of the space station compare with one residing at the hub? What does this say about the behavior of a clock sitting on the surface of a planet with a surface gravity of one g?
The way that the clock at the rim of the space station compare with one residing at the hub is that Rim clock will always runs slower.
The behavior of a clock sitting on the surface of a planet with a surface gravity of one g is the same.
Is there a timepiece on the ISS?For instance, timekeeping on the International Space Station (ISS) is slightly slower than that of reference clocks on Earth. This explains why astronauts on the International Space Station (ISS) mature more slowly, lagging by 0.007 seconds every six months.
Ground-based atomic clocks have served as the industry standard for timekeeping since the 1950s. These clocks use the extremely steady and accurate frequencies of light emitted by particular atoms to keep time.
Therefore, Satellite clocks run slower due to more velocity but faster due to reduced gravity. Clocks move more slowly at the ISS orbital height because velocity dominates. At GPS altitude, clocks move more quickly due to the influence of gravity.
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Tire inflation should be checked when the tires are
Tire inflation should be checked when the tires are cold.
What is tire inflation?Tire inflation can be defined as a phenomenon in which the amount of air pressure (compressed air) in the tire of an automobile vehicle is greater than the recommended (standard) amount of air pressure that is required by the manufacturer, in order to enhance safety.
This ultimately implies that, tire inflation is a measure of the total amount of air pressure (compressed air) in the tire of an automobile vehicle as recommended by the manufacturer of the vehicle.
Additionally, proper tire inflation enhances safety and it can greatly influence gasoline mileage of an automobile vehicle. However, it is only appropriate to check tire inflation when the tire is cold.
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The graph below shows the motion of a person leaving a theater. Three segments of their journey have been identified as A, B, and C.
What does line segment C represent?
 The person is moving away from the theater.
 The person is standing still.
 The person is moving closer to the theater.
 The person is slowing down.
                                                The graph below shows the motion of a person leaving theater, line segment C represent : The person is moving away from the theater.
What is meant by motion?In physics, motion is a change with time of the position or orientation of a body. Motion along a line or a curve is called as translation whereas motion that changes orientation of a body is called rotation.
Motion is a change in position of an object over the time and is described in terms of displacement, distance, velocity, acceleration, time and speed.
Change in position of a body with time when compared with another body is known as motion.
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Do this for alot of points
                                                1. A complete fitness and exercise program should incorporate three basic components: Endurance (Aerobic), Flexibility, and Strength. Each of these components has specific guidelines, which govern their effectiveness
Identify three main ideas about models
Answer:
Approaches mathematical learning through inquiry
-Explore real contexts, problems, situations, and models
-Learning through doing shifts the focus on the students
-Problems have multiple entry and exit points
-Links to other disciplines
Explanation:
quizlet
What is the overall reaction potential for reaction below
Answer:
potential energy is a form of energy that a body possess to its position.Potential energy is equal to potential energy is equal to mass times acceleration due to gravity times height.
What traits do most people with autism share?
Answer:
These are some of the characteristics of ASD:
problems with social interaction with others. ...
unusual interest in objects.
need for sameness.
great variation in abilities.
under or over reaction to one or more of the five senses: sight, touch, taste, smell, or hearing.
repeated actions or body movements.
Explanation:
hope this helps
Complete the missing information from the circuit
                                                From the first circuit (see attached), it is correct to state that I₄ = 40mA. See the explanation below.
What is a circuit?A path that is designed to transport electric current is that is referred to as a circuit.
How do we compute for the missing details?I = 200mA
= 20mA + 140mA + I₄
I₄ = 200 - 160
I₄ = 40mA
From the above, we can rightly posit:
R₄ = 3/(40x 10⁻³)
= 75 Ω
Hence
V₆ = V₄ - V₅
= 3v - 2v
= 1v
R₆ therefore, =
V₆/I₆
= 1/ (40 x 10 ⁻³)
= 14.28 Ω
I₃ = I₄ + I₆
= 40 + 140
= 180mA
R₃ = 9/(180 x 10⁻³)
= 50Ω
R₂ = 12/20 x (10⁻³)
= 60 Ω
Then,
Vbattery =
200 x 10⁻³ x90
= 18 volts
The above indices is used to complete the image. See Circuit Image II.
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                                                            [3 marks]  
A particle of mass 100 g executes simple harmonic motion about x = 0 with angular frequency  ω = 10 s-1. Its total mechanical energy is Etot = 0.45 J. Find the displacement of 
	the particle when its speed is 2 m/s.   	 	 	 	 	[3 marks]
Answer:
22.4 cm
Explanation:
The total mechanical energy of the particle Etot = K + U where K = kinetic energy = 1/2mv² where m = mass of particle = 100 g =0.1 kg and v = speed of particle = 2 m/s and U = potential energy = 1/2kx² where k = spring constant and x = displacement
Etot = K + U
U = Etot - K
U = Etot - 1/2mv²
Since Etot = 0.45 J, substituting the values of the other variables into the equation, we have
U = Etot - 1/2mv²
U = 0.45 J - 1/2 × 0.1 kg × (2 m/s)²
U = 0.45 J - 1/2 × 0.1 kg × 4 m²/s²
U = 0.45 J - 0.1 kg × 2 m²/s²
U = 0.45 J - 0.2 J
U = 0.25 J
Now U = 1/2kx² and the angular frequency ω = √(k/m) ⇒ ω²m = k
So, U = 1/2ω²mx²
x² = 2U/ω²m
x = (√2U/m)/ω
since ω = 10 rad/s, substituting the values of the variables into the equation, we have
x = (√2U/m)/ω
x = (√2 × 0.25 J/0.1 kg)/10 rad/s
x = (√0.5 J/0.1 kg)/10 rad/s
x = (√5 J/kg)/10 rad/s
x = 2.24/10 m
x = 0.224 m
x = 22.4 cm
the value of g varies from place to place on the surface of the earth
The acceleration due to gravity (g) on Earth varies across different locations due to factors like latitude, altitude, and local geology. Despite these variations, a standardized average value of g is commonly used for practical purposes.
The value of acceleration due to gravity (g) does indeed vary from place to place on the surface of the Earth. This variation occurs due to several factors that influence the gravitational field strength experienced at different locations. The following factors contribute to the variation in the value of g:
1. Latitude: The Earth is not a perfect sphere but an oblate spheroid, flattened at the poles and bulging at the equator. As a result, the distance from the center of the Earth to the surface is slightly greater at the equator than at the poles. This variation in distance affects the gravitational force and results in a slightly lower value of g at the equator compared to the poles.
2. Altitude: The distance from the Earth's center to a specific location affects the gravitational pull experienced at that location. As altitude increases, moving away from the Earth's surface, the gravitational force decreases, leading to a lower value of g.
3. Local Geology: The distribution of mass within the Earth's crust can cause gravitational variations. Areas with denser materials, such as mountains or regions with underground mineral deposits, may experience slightly higher values of g due to the increased gravitational pull from the additional mass.
4. Topography: Variations in the shape and composition of the Earth's surface, such as variations in mountains, valleys, and ocean trenches, can cause local gravitational anomalies. These anomalies can result in slight variations in the value of g at different locations.
It is important to note that while the variation in g exists, it is relatively small and does not significantly impact daily activities. In most practical applications, a standard average value of g (approximately 9.8 m/s²) is used for simplicity and convenience.
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An experimental electrical generator collects sunlight with mirrors and generates heat at a rate of 1.2 megawatts. The generator is mounted on the roof of an environmentally friendly building and is used to operate an elevator. The elevator has a maximum operating load of 8000 kg and a maximum velocity of 6 m/s. 
A. Determine the power that the generator must supply to operate the elevator at its maximum operating 
B. What is the efficiency of this system?
Answer:
a) 0.47MW
b) 39.24%
Explanation:
In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:
P=Fv
where P is the power, F is the force and v is the velocity.
The force the elevator must carry can be calculated with the following formula:
F=mg
where m is the mass of the elevator and g is the acceleration of gravity, so:
\(F=(8000 kg)(9.81 m/s^{2})\)
F=78 480 N
so now we can make use of the power formula:
P=Fv
P=(78 480N)(6 m/s)
P=470 880W
P=0.47W
b)
In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:
\(efficiency = \frac{P_{in}}{P_{out}}*100\%\)
\(efficiency=\frac{0.470880}{1.2}*100\%\)
efficiency=39.24%