i need help creating a realistic planet with the following information

I Need Help Creating A Realistic Planet With The Following Information

Answers

Answer 1

Only the Sun and the Moon are brighter than the planet Venus, which represents the goddess' own beauty and makes for a lovely spectacle in the sky.

What planet in solar system considered as goddesses?

The ancient Greeks gave the name Athena—after their goddess of wisdom—to the fourth planet from the Sun.

The same planet was given the name Minerva by the Romans, who did so in honor of Athena in Greek mythology. The first manned spacecraft to visit the planet was given the name Athena by the Americans.

Therefore, In honor of their goddess of love and beauty, the Romans gave the brightest planet, Venus, that name. After the telescope was created in the early 1600s, the planets Uranus and Neptune were also found.

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Related Questions

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s
. Once free of this area, it speeds up to 11 m/s
in 8.0 s
. At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s
to reach a higher cruising speed.

Answers

The distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

Light-rail passenger trains that provide transportation within and between cities speed up and slow down with a nearly constant (and quite modest) acceleration. A train travels through a congested part of town at 6.0 m/s. Once free of this area, it speeds up to 11 m/s in 8.0 s.

At the edge of town, the driver again accelerates, with the same acceleration, for another 16 s to reach a higher cruising speed.

Here, we have to find the acceleration of the train.

To solve this problem, we will use the kinematic equation of motion:

v = u + at

Where,v = Final velocity (11 m/s)u = Initial velocity (6 m/s)t = Time taken (8 s)a = Acceleration

We know the value of initial velocity, final velocity, and time taken to reach the final velocity, thus we will substitute the values in the above formula:

11 m/s = 6 m/s + a (8 s)11 m/s - 6 m/s = 8 a5 m/s = 8 a  a = 5/8 m/s²

This is the acceleration of the train when it speeds up to 11 m/s in 8 seconds.

Now, we need to find the distance travelled by the train in 16 seconds when it is accelerating with the same acceleration.

We will use the kinematic equation of motion:

s = ut + (1/2) at²

Where,s = Distance travelled u = Initial velocity (11 m/s)t = Time taken (16 s)a = Acceleration

We know the value of initial velocity, time taken, and acceleration, thus we will substitute the values in the above formula:s = (11 m/s)(16 s) + (1/2) (5/8 m/s²)(16 s)²s = 176 m + 80 m  s = 256 m.

Therefore, the distance travelled by the train when it is accelerating for another 16 seconds with the same acceleration is 256 meters.

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PLZ PLZ PLZ I VOTE BRAINLY PLZPLZPLZ what is the theory of an atom created by a Dr. VAN C.

Answers

Answer: Bohr developed the Bohr model of the atom, in which he proposed that energy levels of electrons are discrete and that the electrons revolve in stable orbits around the atomic nucleus but can jump from one energy level (or orbit) to another. ... During the 1930s Bohr helped refugees from Nazism.

A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?

Answers

The answer is that the time the diver was in the air is 1.13 seconds.

To determine the time the diver was in the air, we can use the kinematic equation:

Δy = viΔt + 1/2at²,

where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0

m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²

Simplifying, we get:

4.9t² + 5.5t - 3.0 = 0

We can solve for t using the quadratic formula:

t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s

Since time cannot be negative, the time the diver was in the air is 1.13 seconds.

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A mass attached to a vertical spring has position function given by

A mass attached to a vertical spring has position function given by

Answers

ANSWER:

a) -11.4 in/s

b) -29.3 in/s^2

STEP-BY-STEP EXPLANATION:

We have the following function corresponding to the position at a given time:

\(s(t)=5\sin (3t)\)

If we differentiate this function with respect to time, we obtain the velocity function, like this:

\(\begin{gathered} v(t)=s^{\prime}(t) \\ s^{\prime}(t)=\frac{d}{dt}(s(t)) \\ \frac{d}{\mathrm{d}t}(5\sin (3t))=15\cos (3t) \\ v(t)=15\cos (3t) \end{gathered}\)

We calculate the velocity by replacing t = 5, just like this:

\(\begin{gathered} v(t)=15\cos (3\cdot5)=15\cos (15) \\ v(t)=-11.4\text{ in/s} \end{gathered}\)

If we differentiate the function again, we obtain the acceleration function, as follows:

\(\begin{gathered} a(t)=v^{\prime}(t) \\ v^{\prime}(t)=\frac{d}{dt}(v(t)) \\ \frac{d}{dt}(15\cos (3t))=-45\sin \mleft(3t\mright) \\ a(t)=-45\sin (3t) \end{gathered}\)

We calculate the acceleration by replacing t = 5, just like this:

\(\begin{gathered} v(t)=-45\sin (3\cdot5)=-45\sin (15) \\ v(t)=-29.3in/s^2 \end{gathered}\)

A 60 kg driver gets into an empty taptap to start the day's work. The springs compress 2.4×10−2 m . What is the effective spring constant of the spring system in the taptap?

Answers

We can use Hooke's Law to calculate the effective spring constant of the spring system.

Hooke's Law states that the force exerted by a spring is proportional to its extension or compression from its equilibrium position. The formula for Hooke's Law is:

F = -kx

where F is the force exerted by the spring, k is the spring constant, and x is the displacement of the spring from its equilibrium position.

In this problem, the driver has a weight of 60 kg. The force exerted by the spring is equal to the weight of the driver, so we can write:

F = mg = (60 kg)(9.8 m/s^2) = 588 N

The displacement of the spring is given as 2.4×10−2 m.

We can now use Hooke's Law to solve for the spring constant:

k = -F/x = -(588 N)/(2.4×10−2 m) = -24500 N/m

The effective spring constant of the spring system in the taptap is 24500 N/m.

The resultant of three vectors is 90.00 cm 34o N of W. If two of these three vectors are 17.89 cm 27o W of S, and 36.00 cm NW, what is the magnitude and direction of the third vector? (Ans: 57.85 cm, 44.76o N of W)

Answers

Answer:

Magnitude of the third vector: 57.85 cm

The direction of the third vector: 44.76 N of W

Explanation:

Which quantities define momentum?
A) how much weight an object has, plus magnitude of its acceleration.

B)how much force is pushing an object, plus it’s speed.

C)how fast can an object travel, plus its weight.

D)how much matter does an object has, plus the magnitude and direction of it’s motion

Answers

Answer:D

Explanation: a p e x

What do you do to find the manipulated variable in a line graph?

Answers

Answer: Days and Height (cm).

Explanation:

The speed of light in a vacuum is 300,000,000 m/s. How long does it take light to travel 1.5 x 108 km (which happens to be the distance from the sun to Earth)?

Answers

The speed of light is 3 × 10⁸ m/s. Light will take a time of 500 seconds to travel a distance of 1.5 × 10¹¹ m.

What is speed of light ?

Speed is a physical quantity used to measure the distance travelled by an object  per unit time. It is usually expressed in the unit m/s. Light is the fastest thing in the universe to be known.

The speed of light is the product of its frequency and wavelength. In general the ratio of the distance covered per time taken.

Speed of light  = 3 × 10⁸ m/s

distance from earth to sun =  1.5 × 10⁸km = 1.5 × 10¹¹ m

Now, the time taken by light to travel this distance is :

time = distance/speed.

t =  1.5 × 10¹¹ m / 3 × 10⁸ m/s = 500 seconds.

Therefore, the time taken by light from sun to reach earth surface is approximately 500 s.

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A ball is sitting at the top of a ramp. As the ball rolls down the ramp, the potential energy of the ball decreases, what happens to the potential energy as the ball moves

Answers

Answer:

the potential energy decreases as it is converted to kinetic energy.

Explanation:

As things move, their potential energy converts to kinetic energy to power them along. When a ball rolls down the top of a ramp, all the potential energy it accumulated at the top of the ramp converts to kinetic energy to help it roll down. In other words, its potential energy decreases as its kinetic energy increases.

An 5kg object is released from rest near the surface of a planet. The vertical position of the object as a function of time is shown in the graph. All frictional forces are considered to be negligible. What is the closest approximation of the weight of the object.
a) 300N
b) 30N
c) 5N
d) 150N

An 5kg object is released from rest near the surface of a planet. The vertical position of the object

Answers

Answer:

The correct option is b: 30 N.

Explanation:

First, we need to find the acceleration due to gravity (a):

\( y_{f} - y_{0} = v_{o}t - \frac{1}{2}a(\Delta t)^{2} \)   (1)

Where:

\(y_{f}\): is the final vertical position (obtained from the graph)

\(y_{0}\): is the initial vertical position (obtained from the graph)

v₀: is the initial speed = 0 (it is released from rest)

Δt: is the variation of time (from the graph)

From the graph, we can take the following values of height and time:

t₀ = 0 s → \(t_{f}\) = 5 s

y₀ = 300 m → \(y_{f}\) = 225 m

Now, by entering the above values into equation (1) and solving for "a" we have:

\( a = 2\frac{y_{0} - y_{f}}{(t_{f} - t_{0})^{2}} = 2\frac{300 m - 225 m}{(5 s - 0)^{2}} = 6 m/s^{2} \)

Finally, the weight of the object is:

\( W = ma = 5 kg*6 m/s^{2} = 30 N \)

Therefore, the correct option is b: 30 N.

I hope it helps you!                                                                                                            

Using the Left Hand Rule, if motion is toward you and the field is up, which way is the current?
A. Left
B. Right
C. Toward you
D. Away from you

Answers

Answer:
C
Explanation:
Just trust


1) A squirrel falls from a tree. After a brief rest, the squirrel begins to accelerate until it reaches a velocity of
5.8 m/s. If the squirrel ran a total of 15 m, what would be its acceleration ?

Answers

time= displacement/ velocity
so; 15/5.8 = 2.5862069 s

1.) A roller coaster travels on a frictionless track as shown in the illustration.
a.) If the speed of the car at Pt A is 5.0 m/s, what is the speed at Pt B

(More in the photo provided)

1.) A roller coaster travels on a frictionless track as shown in the illustration. a.) If the speed of

Answers

For the roller coaster on a frictionless track:

a. The speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.b. The height between Points A and B where kinetic energy equals potential energy is 5.0 m.c. For the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.d. For the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

How to solve speed and height?

a. The speed of the car at Point B can be determined using the principle of conservation of energy. The total mechanical energy (sum of kinetic energy and potential energy) remains constant in the absence of external forces like friction. Therefore, if there is no energy loss, the kinetic energy at Point A is equal to the kinetic energy at Point B.

Given that the speed at Point A is 5.0 m/s, the speed at Point B will also be 5.0 m/s.

Answer: A. 5.0 m/s

b. To find the height at which kinetic energy equals potential energy, we can set the equations for kinetic energy and potential energy equal to each other.

At Point A, the roller coaster has both kinetic energy and potential energy. The total mechanical energy is the sum of these two:

Initial mechanical energy at Point A = Kinetic energy at Point A + Potential energy at Point A

At Point B, the roller coaster will have kinetic energy and potential energy, but we want to find the height at which kinetic energy equals potential energy. Let's call this height "h."

Mechanical energy at Point B = Kinetic energy at Point B + Potential energy at Point B

Since the speed at Point B is the same as the speed at Point A (5.0 m/s), the kinetic energy at both points is the same.

Equating the mechanical energy at Point A to the mechanical energy at Point B:

Initial mechanical energy at Point A = Mechanical energy at Point B

Kinetic energy at Point A + Potential energy at Point A = Kinetic energy at Point B + Potential energy at Point B

Since the kinetic energy is the same at both points, simplify the equation:

Potential energy at Point A = Potential energy at Point B

The potential energy at any point is given by the formula mgh, where m is the mass, g is the acceleration due to gravity, and h is the height.

Therefore, at the height h between Points A and B, the potential energy equals the potential energy at Point A:

mgh = mghA

Since the mass and acceleration due to gravity are the same, cancel them out:

h = hA

This means that the height where kinetic energy equals potential energy is the same as the height at Point A.

Answer: The height between Points A and B where kinetic energy equals potential energy is 5.0 m.

c. To determine if the car will reach Point C, compare the potential energy at Point B with the potential energy at Point C. If the potential energy at Point B is greater than or equal to the potential energy at Point C, the car will reach Point C.

Potential energy at Point B = mghB

Potential energy at Point C = mghC

Given that the height at Point C is 8.0 m, compare the potential energies:

Potential energy at Point B ≥ Potential energy at Point C

mghB ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hB ≥ hC

Therefore, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m.

d. The minimum speed needed at Point A for the car to reach Point C can be determined by comparing the potential energy at Point A with the potential energy at Point C. If the potential energy at Point A is greater than or equal to the potential energy at Point C, the car will have enough energy to reach Point C.

Potential energy at Point A = mghA

Potential energy at Point C = mghC

Given that the height at Point A is 5.0 m, compare the potential energies:

Potential energy at Point A ≥ Potential energy at Point C

mghA ≥ mghC

Since the mass (m) and acceleration due to gravity (g) are constant, cancel them out:

hA ≥ hC

Therefore, for the car to reach Point C, the height at Point A must be greater than or equal to 8.0 m.

To summarize, for the car to reach Point C, the height at Point B must be greater than or equal to 8.0 m, and the height at Point A must also be greater than or equal to 8.0 m.

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According to this graph, the acceleration
is approximately:
A. 12 m/s²
C. 4 m/s²
Velocity (m/s)
14
12
10
12 2 3 4
Time t (s)
B. 1.5 m/s2
D. 3 m/s2

Help please

According to this graph, the accelerationis approximately:A. 12 m/sC. 4 m/sVelocity (m/s)14121012 2 3

Answers

Answer:

Explanation:

Because you have velocity along the y axis and time along the x axis, this is a velocity v time graph which is an acceleration graph. The slope of the line in this graph IS the acceleration. We can use 2 points and the slope formula to solve for the acceleration:

(0, 0) and (1, 3):

\(m=\frac{3-0}{1-0}=3\) m/s squared, choice D.

11) A tank of kerosene with density of 750 kg/m3 has a syphon used to remove the fluid that then exits into the local atmosphere, with pressure of 101 kPa. The pressure above the kerosene in the tank is 120 kPa absolute. The syphon tube has a diameter of 2 cm, exits the tank rising to 10 cm above the level of the kerosene and then drops down to 15 cm below the level of the kerosene where it exits into the atmospheric pressure. Calculate the exit velocity from the tube.

Answers

Answer:

\(7.32\ \text{m/s}\)

Explanation:

\(v_1\) = Velocity at initial point = 0

\(P_1\) = Pressure in tank = 120 kPa

\(P_2\) = Pressure at outlet = 101 kPa

\(\rho\) = Density of kerosene = \(750\ \text{kg/m}^3\)

\(Z_1\) = Tank height = 15 cm

\(Z_2\) = Height of pipe exit = 0

\(g\) = Acceleration due to gravity = \(9.81\ \text{m/s}^2\)

From Bernoulli's equation we have

\(\dfrac{P_1}{\rho g}+\dfrac{v_1^2}{2g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}+Z_2\\\Rightarrow \dfrac{P_1}{\rho g}+Z_1=\dfrac{P_2}{\rho g}+\dfrac{v_2^2}{2g}\\\Rightarrow v_2=\sqrt{2g(\dfrac{P_1}{\rho g}+Z_1-\dfrac{P_2}{\rho g})}\\\Rightarrow v_2=\sqrt{2\times 9.81(\dfrac{120\times 10^3}{750\times 9.81}+0.15-\dfrac{101\times 10^3}{750\times 9.81})}\\\Rightarrow v_2=7.32\ \text{m/s}\)

The exit velocity from the tube is \(7.32\ \text{m/s}\).

please look at the screenshot and tell me which line goes with the question 1,2,3, or 4

please look at the screenshot and tell me which line goes with the question 1,2,3, or 4

Answers

The diagram below that shows a free-body diagram is the third option m

How to explain the information

A free-body diagram shows all the forces acting on a single object. In this case, the object is m3. The forces acting on m3 are:

The force F1 exerted by m1. This force is directed to the left. The force F2 exerted by m2. This force is directed to the right.

The force F3 exerted by m3. This force is directed to the left.

The net force on m3 is zero, since the forces F1 and F2 are equal and opposite. This means that m3 is in equilibrium.

Diagram (a) shows the forces F1 and F2, but it does not show the force F3. This is incorrect, since F3 is also acting on m3. In conclusion,the correct option is C.

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PLS HELP!! This question was never fully solved!

An object moving at 13 m/s has a kinetic energy of 426 J. What is the mass of the object?
1.26 kg
2.52 kg
5.04 kg
65.5 kg

Answers

To find the mass of the object, we can use the formula for kinetic energy:

Kinetic energy (KE) = (1/2) * mass * velocity^2

Given that the kinetic energy is 426 J and the velocity is 13 m/s, we can rearrange the equation to solve for the mass:

mass = (2 * KE) / (velocity^2)

Substituting the given values:

mass = (2 * 426 J) / (13 m/s)^2

mass = (2 * 426 J) / (169 m^2/s^2)

mass = 852 J / 169 m^2/s^2

mass = 5.04 kg

Therefore, the mass of the object is 5.04 kg.

Define 1ohm resistance​

Answers

Answer:

1 ohm is equal to one volt (V)/ one ampere (1A) 1 Ohm is defined as the resistance of a conductor with a potential difference of 1 volt applied to the ends through which 1-ampere current flows. Ohms is the SI unit of electrical resistance.

Explanation:

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The figure shows a cylinder on an incline plane of negligible friction. The cylinder is released from rest. Which of the following correctly describes the change in the motion of the cylinder if the incline is a rough surface?

A. The cylinder rolls down both inclines, with the cylinder taking more time to reach the bottom on the rough surface.
B. The cylinder rolls down both inclines, with the cylinder taking more time to reach the bottom on the surface of negligible friction.
C. The cylinder slides down the incline of negligible friction and rolls down the incline with a rough surface.
D. The cylinder rolls down the incline of negligible friction and slides down the incline with a rough surface.
E. The cylinder rolls down both inclines in the same amount of time.

Answers

The cylinder glides down the slope with a hard surface as it slides around the gradient with zero friction.

We know that;

Equation of rough surface = a = mgsinθ / [m + i/r²]

We know that; i = 0

Equation of rough surface = a = gsinθ

So, Option "C" is the correct answer to the following question.

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1 x 1015 electrons are pushed through a 10 Ω wire in one minute. What is the voltage of the power source? (e = -1.602 x 10-19 C)

Answers

The voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.

Voltage of the power source

The voltage of the power source is determined from ohm's law as shown below;

V = IR

where;

I is currentR is resistanceV is voltage

But, I = Q/t

V = (Q/t)R

\(V = \frac{QR}{t} \\\\V = \frac{(1\times 10^{15} \times 1.602\times 10^{-19} \ C) \times \ 10 \ ohms}{1 \times 60\ s} \\\\V = 2.67 \times 10^{-5} \ V\)

Thus, the voltage of the power source flowing through the given wire is determined as 2.67 x 10⁻⁵ V.

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If you weigh 690 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 15.0 km ? Take the mass of the sun to be ms = 1.99×1030 kg , the gravitational constant to be G = 6.67×10−11 N⋅m2/kg2 , and the free-fall acceleration at the earth's surface to be g = 9.8 m/s2 . Express your weight wstar in newtons.

Answers

Answer:

W' = 1.66 x 10¹⁴ N

Explanation:

First, we will calculate the mass:

\(W = mg\)

where,

W = weight on earth = 690 N

m = mass = ?

g = acceleration due to gravity on earth = 9.8 m/s²

Therefore,

\(m = \frac{W}{g} = \frac{690\ N}{9.8\ m/s^2}\\\\m = 70.4\ kg\)

Now, we will calculate the value of g on the neutron star:

\(g' = \frac{GM}{R^2}\)

where,

g' = acceleration due to gravity on the surface of the neutron star = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = Mass of the Neutron Star = 1.99 x 10³⁰ kg

R = Radius of the Neutron Star = 15 km/2 = 7.5 km = 7500 m

Therefore,

\(g' = \frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(1.99\ x\ 10^{30}\ kg)}{(7500\ m)^2}\\\\g' = 2.36\ x\ 10^{12}\ m/s^2\)

Therefore, the weight on the surface of the neutron star will be:

\(W' = mg'\\W' = (70.4\ kg)(2.36\ x\ 10^{12}\ m/s^2)\)

W' = 1.66 x 10¹⁴ N

What distance does a plate with an average speed of 1.95 cm/year move in 1000 years? help pls

Answers

Answer:

1950cm

Explanation:

You should multiply 1.95 cm by 1000. This will result in the answer.

A stunt person jumps from the roof of a tall building, but no injury occurs because the person lands on a large, air-filled bag. Which one of the following best describes why no injury occurs?
A. The bag increases the amount of time during which the momentum is changing and reduces the average force on the person.
B. The bag increases the amount of time the force acts on the person and reduces the change in momentum.
C. The bag reduces the impulse to the person.
D. The bag provides the necessary force to stop the person.
E. The bag decreases the amount of time during which the momentum is changing and reduces the average force on the person.

Answers

Answer:

A stunt person jumps from the roof of a tall building, but no injury occurs because the person lands on a large, air-filled bag. Which one of the following best describes why no injury occurs?

The bag increases the amount of time during which the momentum is changing and reduces the average force on the person.

ANSWER: A

Answer:

A. The bag increases the amount of time during which the momentum is changing and reduces the average force on the person.

During stunts, people usually put an-air filled bag on the ground for safe landing and to prevent injuries.

Momentum is calculated by m* v where m is for mass and v is for velocity.

Force is directly proportional to momentum

F∝M

The bag in this scenario helps to increases the amount of time the force acts on the person. This implication means that there is a reduction in the change of momentum. Since Force and momentum have a directly proportional relationship then the Force taken to hit the floor is greatly reduced.

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The momentum of a 2.5 kg hammer with a speed of 6 m/s has a downward momentum moving towards a nail. The hammer hits the nail and bounces off at 2.0 m/s and the nail is in contact with the nail for 0.002 seconds. What is the average force the nail exerts on the hammer? How could you use force vs. time to solve this problem?

Answers

The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

The equation can be used to determine the average force the nail applies to the hammer.

\(F = \frac{mv}{t}\), where m is the hammer's mass, v is its speed, and t is the time at which it made impact with the nail. The average force in this situation is given by:

\(F = \frac{(2.5 kg)(6 m/s - 2.0 m/s)}{(0.002 s)}\\ F= 4500 N.\)

To solve this problem using force vs. time, you would need to plot a graph of force versus time, with the time of contact between the hammer and the nail representing the x-axis and the force exerted on the hammer by the nail representing the y-axis. The force exerted on the hammer increases from 0 to 4500 N as the hammer moves from rest to its maximum velocity. The average force is equal to the area under the curve of force versus time divided by the time of contact between the hammer and the nail.

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what do the sound waves made by the bell carry to your ear

Answers

Answer:

When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.

Explanation:

Answer: When a bell is pounded, the metal vibrates. The vibrations travel through the air as sound waves. When these waves reach our ears, they make our eardrums vibrate.

Explanation:

We hear the sound of the bell ringing. Sound always needs to travel through some kind of medium, such as air, water, or metal.

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Einstein developed much of his understanding of relativity through the use of gedanken, or thought, experiments. In a gedanken experiment, Einstein would imagine an experiment that could not be performed because of technological limitations, and so he would perform the experiment in his head. By analyzing the results of these experiments, he was led to a deeper understanding of his theory. In each the following gedanken experiments, Albert is in the exact center of a glass-sided freight car speeding to the right at a very high speed vvv relative to you. Albert has a flashlight in each hand and directs them at the front and rear ends of the freight car. Albert switches the flashlights on at the same time.

In Albert's frame of reference, which beam of light travels at a greater speed, the one directed toward the front or the one toward the rear of the train, or do they travel at the same speed? Which beam travels faster in your frame of reference? Enter the answers for Albert's frame of reference and your frame of reference separated by a comma using the terms front, rear, and same. For example, if in Albert's frame of reference the beam of light directed toward the front of the train travels at a greater speed and in your frame of reference the two beams travel at the same speed, then enter front,same.

Answers

Answer:

For eintein's frame of reference, both beam travel at the same speed.

For my own frame of reference, both beams travel at the same speed.

Explanation:

According to special relativity, the speed of light is the same in all direction on all reference frame. If not for this law we will assume the from beam will have a relative speed that will be the speed of light plus the speed of the fright car. This is not so and it violates the speed limit of light which according to the first law is the highest speed possible and nothing can go beyond that.

____ is based on the acceptance of rules and laws.

Multiple Choice

1. Rational-legal authority
2. Traditional authority
3. Legal power
4. Political power​

Answers

3 is the answer hdhshhshshs

When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 63.5-kg man just before contact with the ground has a speed of 7.89 m/s. (a) In a stiff-legged landing he comes to a halt in 3.99 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.205 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).

Answers

Answer:

a)  F = 1.26 10⁵ N, b)  F = 2.44 10³ N, c)   F_net = 1.82 10³ N  directed vertically upwards

Explanation:

For this exercise we must use the relationship between momentum and momentum

         I = Δp

         F t = p_f -p₀

a) It asks to find the force

as the man stops the final velocity is zero

         F = 0 - p₀ / t

the speed is directed downwards which is why it is negative, therefore the result is positive

         F = m v₀ / t

         F = 63.5 7.89 / 3.99 10⁻³

         F = 1.26 10⁵ N

b) in this case flex the knees giving a time of t = 0.205 s

          F = 63.5 7.89 / 0.205

          F = 2.44 10³ N

c) The net force is

         F_net = Sum F

         F_net = F - W

         F_net = F - mg

let's calculate

         F_net = 2.44 10³ - 63.5 9.8

         F_net = 1.82 10³ N

since it is positive it is directed vertically upwards

50 POINTS ANSWER CORRECTLY 4. Identify what elements are made in a Super Red Giant as it starts to die?

Answers

The super red giant star is the aging star and it is a dying star in the final stage of stellar evolution. From the burst of the super red giant star, magnesium is formed from the core of the red giant star.

The super red giant star has a larger mass and produces greater gravitational pressure. The giant red star is in the final stage of dying and the core of the red star has heavier elements like nitrogen, carbon, etc.

In the core of stars, nuclear fusion takes place. Nuclear fusion is the process of two lighter nuclei fusing or joining together to form a heavier nucleus.

The hydrogen fuses to form helium and helium fuses together to form carbon atoms. Carbon atoms fuse together to form oxygen atoms and it forms heavier elements like magnesium and iron.

Hence, from the burst of a super red giant star, heavier elements like magnesium, iron, carbon, and helium ions are formed.

To learn more about the super red giant star:

https://brainly.com/question/31592739

#SPJ1

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