(i) when vs 10 v with the switch on, what is the total charge q transported through rl in 2.5 seconds? (ii) when vs 15 v with the switch on, what is the energy w required to transport 0.5 (c) of charge through rl?
Answers
(i) when vs 10 v with the switch on, what is the total charge q transported through rl in 2.5 seconds?
(ii) when vs 15 v with the switch on, what is the energy w required to transport 0.5
The is 7.5 Joule.
The unit of energy in line with the metric device of devices (SI) is said to be the joule (J).
similarly, power is expressed non a extensive style of other SI-incompatible units. energy, ergs, kilowatt-hours, kilocalories, and British Thermal gadgets are some of these gadgets.
(i) v_s = 10 v when switch ON
q_0=0 [when switch off]
q=q_0+∫0-t i(t)dt
q=∫0-t=2.5sec i(t)dt
q= ∫0-t=sec 1mAdt
q=1×10^-3[t]0 - 2.5 sec
q=1×10^-3[2.5]
q=2.5×10^-3
q=2.5mC
(ii)
i=15/10=1.5mA
w=vit
q=0.5 column
q=q_0-0+∫0-t i(t)dt
q=∫ 0-t 1.5mAdt
q= 1.5×10^-3t
0.5= 1.5×10^-3t
t=0.5/ 1.5×10^-3t=(0.5/1.5)×10^3t
t=0.3333×10^3=333.3 second
w=vit
=15×1.5×10^3×0.3333×10^3
w=15×1.5×0.3333
w=7.49925
w=7.5 Joule
To learn more about energy refer the link:
https://brainly.com/question/14310506
#SPJ9
Related Questions
Identify the smallest measurement.
a) attometer
b) nanometer
c) centimeter
d) megameter
e) petameter
Answers
Answer:
Attometer
Explanation:
an attometer is the smallest unit of measurement.
Hope it helped!
Figure I shows the position of the moon at local time 10:00 P. M with respect to point A on earth’s surface. Figure II shows the position of the moon 24 hours later with respect to the same place. Which phenomenon will a person at point A observe?
Answers
Answer:
A
Explanation:
i just did this on usatestprep the answer A
Which on the following subatomic particles can modify on an object
A: electrons
B: neutrons
C: protons
Answers
Answer:
electrons i think
Explanation:
If you are driving an oscillatory system at a certain frequency, but the amplitude is much smaller than it could be, you can be certain that If you are driving an oscillatory system at a certain frequency, but the amplitude is much smaller than it could be, you can be certain that The driving frequency is too low. The driving frequency is too high. The driving frequency is not matched to the natural frequency of the oscillatory system.
Answers
If you are driving an oscillatory system at a certain frequency, but the amplitude is much smaller than it could be, you can be certain that the driving frequency is not matched to the natural frequency of the oscillatory system.
When an oscillatory system is driven at its natural frequency, it undergoes resonance, resulting in maximum amplitude. However, if the driving frequency is not matched to the natural frequency, the system will not respond with a large amplitude. Instead, the amplitude will be smaller.
In such a case, the oscillatory system is not efficiently absorbing energy from the driving force, and the motion becomes less pronounced. This indicates that the driving frequency does not coincide with the natural frequency of the system, leading to a suboptimal response and a smaller amplitude.
To know more about oscillatory system, click here https://brainly.com/question/28256327
#SPJ11
A regulation basketball has a 15 cm diameter and may be appropriated as a thin spherical shell.
How long will it take a basketball starting from rest to roll without slipping 2.9 m down an incline that makes an angle of 29.7 with the horizontal? The acceleration of gravity is 9.81 m/s^2 .
Answer in units of s.
Answers
Solution :
From the given data,
For the spherical shell is \($\frac{k^2}{R^2}= \frac{2}{3}$\)
where x is the radius of gyration and the acceleration of a rolling body on an inclined plane = a
Therefore,
\($a =\frac{g \sin \theta}{1+ \frac{k^2}{R^2}} $\)
\($= \frac{g \sin \theta}{1 +\frac{2}{3}}$\)
\($= \frac{3}{5} g \sin \theta$\)
= 0.6 x 9.81 x sin ( 29.7)
\($= 2.913 \ m/s^2$\)
\($h = \frac{1}{2} a(\Delta t)^2$\)
\($\Delta t = \sqrt{\frac{2h}{a}}$\)
\($\Delta t = \sqrt{\frac{2 \times 2.9}{2.913}}$\)
Δt = 1.411 s
Write a paragraph about getting to Mars using the dot points
Answers
Complete the statements using data from Table A of your Student Guide. The speed of the cart after 8 seconds of Low fan speed is cm/s. The speed of the cart after 3 seconds of Medium fan speed is cm/s. The speed of the cart after 6 seconds of High fan speed is cm/s.
Answers
Answer:
8 seconds = 72cm
3 seconds = 36cm
6 seconds = 96cm
Explanation:
lab assignment i just took.
Speed is the rate of distance over time. The speed of the cart is as follows:
\(72cms^{-1}\) at 8 seconds.\(36cms^{-1}\) at 3 seconds.\(96cms^{-1}\) at 6 seconds.Let:
\(s \to\) speed
\(d \to\) distance
\(t \to\) time
After 8 seconds
For low fan speed; the distance (d) at 8 seconds is:
\(d =576cm\)
Speed (s) is calculated using:
\(s = \frac dt\)
\(s = \frac{576cm}{8s}\)
\(s = 72cms^{-1}\)
Hence, the speed after 8 seconds is \(72cms^{-1}\)
After 3 seconds
For medium fan speed; the distance (d) at 3 seconds is:
\(d = 108cm\)
The speed (s) is :
\(s = \frac dt\)
\(s = \frac{108cm}{3s}\)
\(s = 36cms^{-1}\)
Hence, the speed after 3 seconds is \(36cms^{-1}\)
After 6 seconds
For high fan speed; the distance (d) at 6 seconds is:
\(d = 108cm\)
The speed (s) is :
\(s = \frac dt\)
\(s = \frac{576cm}{6s}\)
\(s = 96cms^{-1}\)
Hence, the speed at 6 seconds is \(96cms^{-1}\)
Read more about speed at:
https://brainly.com/question/7359669
if the car ha a mass of 1000 kilograms, what is its momentum (v=35m/s)
Answers
Answer:
The momentum of the car is 35,000 kg.m/s
Explanation:
Momentum
Momentum is often defined as mass in motion.
Since all objects have mass, if it's moving, then it has momentum. It can be calculated as the product of the mass by the velocity of the object:
\(\vec p = m\vec v\)
If only magnitudes are considered:
p = mv
The car has a mass of m=1,000 kg and travels at v=35 m/s. Calculating its momentum:
p = 1,000 kg * 35 m/s
p = 35,000 kg.m/s
The momentum of the car is 35,000 kg.m/s
The momentum of the car is 35000 kgm/s.
MomentumLinear momentum, translational momentum, or simply momentum is the product of the mass and velocity of an object. It is a vector quantity, possessing a magnitude and a direction.
If m is the mass and v is the velocity of an object, then the object's momentum p is given below.
\(p = mv\)
Given that the mass of the car is m=1,000 kg and travels at v=35 m/s. The momentum is given below.
\(p = 1000 \times 35\)
\(p = 35000 \;\rm kg m/s\)
Hence we can conclude that the momentum of the car is 35000 kgm/s.
To know more about the momentum, follow the link given below.
https://brainly.com/question/4956182.
How should the amount of elastic potential energy when the spring is fully stretched compare to the amount of kinetic energy when the spring is relaxed?
Answers
If there are no dissipative forces acting on the string, than the principle of conservation of energy holds.
When the string is relaxed, it has zero elastic potential energy
If we were strech the she spring, we would increase it's potential energy. After releasing the spring, when it's relaxed again, all potential energy will have been converted into kinetic energy.
Therefore, the elastic potential energy of the stretched spring should be equal to the amount of kinetic energy when it's relaxed
A car with a mass of 1180 kilograms is being driven at 18.2 meters per second when it runs into a tree. What is the change in kinetic energy of the car? Include units in your answer. Answer my be in 3 significant digits.
Answers
The change in kinetic energy of the car can be given as,
\(\Delta K=\frac{1}{2}m(v^2-u^2)\)After running to tree the car will stop therefore, the final speed of car is 0 m/s.
Substitute the knwon values,
\(\begin{gathered} \Delta K=\frac{1}{2}(1180kg)((0m/s)^2-(18.2m/s)^2) \\ =(590\text{ kg)(-}331.24m^2s^{-2})(\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ =-195431.6\text{ J} \\ \approx-195000\text{ J} \end{gathered}\)Thus, the magnitude of change in the kinetic energy of car is 195000 J.
Directions: Complete the thinking map below as you learn about characteristics of chemical reactions.
Answers
The evolution of a gas, precipitate formation, color change, temperature change, and state change are significant aspects of chemical reaction.
What are chemical reactions and what do they look like?A chemical reaction occurs when one or more substances completely transform into another one or more substances. It can exhibit one or more characteristics, such as a state change, color change, gas evolution, temperature change, precipitate development, etc. The majority of our energy is produced by chemical reactions. Many different types of materials are tested, identified, and studied using chemical reactions.
What do the seven various categories of chemical reactions mean?Combustion reaction, decomposition reaction, neutralization reaction, redox reaction, precipitation or double-displacement reaction, and synthesis reaction are some of the numerous types of reactions.
To learn more about chemical reactions visit:
brainly.com/question/29039149
#SPJ9
What are the characteristics of chemical reactions?
Which part of a plant works as its "nostrils"?
A. Stoma
B. Guard cells
C. Chloroplasts
D. All of the above
Answers
Answer:
I think it might be A but I'm not sure
2. An airboat with mass 3.50 x 102 kg, including the passenger, has an engine that produces a net horizontal force of 7.70 x 102 N, after accounting for forces resistance. a. Find the acceleration of the airboat b. Starting from rest, how long does it take the airboat to reach a speed of 12.0 m/s
Answers
The acceleration of the airboat is 2.2m/s^2 and starting from rest, it take the airboat to reach a speed of 12.0 m/s is 5.45s
Given mass of airboat (m) = 3.50 x 10^2kg
horizontal force of engine (F) = 7.70 x 10^2N
We know that from newtons laws of motion Force = mass x acceleration such that F = ma
(a) Now a = F/m = 7.70 x 10^2 / 3.50 x 10^2 = 2.2m/s^2
(b) Initial speed of airboat (u) = 0m/s
final speed (v) = 12m/s
We have acceleration a = 2.2m/s
Then we have another newtons law as: v = u+ at where t is the time taken
So t = v/a = 12/2.2 = 5.45s
Hence it takes to reach 5.45s a speed of 12m/s
To learn more about acceleration click here https://brainly.com/question/12550364
#SPJ4
What is the minimum length of time water must remain motionless in service lines prior to first-draw residential lead sampling?
a) 2 hours
b) 4 hours
c) 6 hours
d) 8 hours
Answers
The recommended minimum length of time that water should remain motionless in service lines prior to first-draw residential lead sampling is 6 hours.
Lead can leach into drinking water from the service lines and plumbing fixtures, particularly in older homes that may have lead pipes or lead-based solder. When water sits stagnant in these pipes for a period of time, such as overnight or during the day when no one is home, the lead particles that have accumulated in the plumbing system can dissolve into the water. This is why it's important to collect first-draw samples after a period of stagnation.
The EPA recommends a 6-hour stagnation period for collecting first-draw samples from residential plumbing systems because this is typically the longest period of time that water remains stagnant in home plumbing systems. This means that the water has been sitting in the pipes long enough to allow any lead particles to leach into the water, but not so long that the water quality may be affected by other factors, such as microbial growth or chemical reactions.
It's important to note that first-draw samples are used to identify the presence of lead in the plumbing system, but they may not be representative of the actual exposure to lead that a person may experience. This is because the lead concentration in the water can vary depending on factors such as the age and condition of the plumbing system, the water chemistry, and the length of time that water has been sitting in the pipes.
Visit to know more about Lead :-
brainly.com/question/14512284
#SPJ11
Which statement about electric charges is correct?
(A) An object with a positive charge and an object with a negative charge will repel each other.
(B) An object with a negative charge and an object with a positive charge will attract each other.
(C) Two objects with negative charges will attract each other.
(D) Two objects with positive charges will attract each other.
Answers
True or False. Retracting the caliper piston on an integrated parking brake system is different than on a standard caliper.
Answers
The given statement "Retracting the caliper piston on an integrated parking brake system is different than on a standard caliper" is True because Integrated parking brake systems are becoming more common in newer vehicles.
These systems integrate the parking brake function into the rear calipers, rather than using a separate parking brake assembly. This means that retracting the caliper piston on an integrated parking brake system requires additional steps.
On a standard caliper, retracting the piston is typically done by compressing it with a piston compression tool. However, on an integrated parking brake system, the piston must be rotated while being compressed. This is because the parking brake mechanism is engaged by turning the piston, rather than by pulling a separate parking brake lever.
Overall, retracting the caliper piston on an integrated parking brake system requires extra care and attention to ensure proper functioning of the brake system. It is important to consult the vehicle manufacturer's instructions or a qualified mechanic for guidance on this process.
Know more about Caliper piston here :
brainly.com/question/5438877
#SPJ11
A local electricity company charges $1. 00 per kWh for the first 2000 kWh and $3. 50 for every kWh afterwards. A fuel adjustment charge of
$0. 50 per kWh is added to all electricity bills. If Mrs. Browns previous
monthly meter reading was 17 800 kWh and the current monthly meter
reading is 20 300 kWh, calculate the electricity bill for Mrs Brown for
the current month
Answers
According to the given statement Mrs. Brown's electricity bill for the current month is $5000.00.
To calculate Mrs. Brown's electricity bill for the current month, we need to determine the total number of kilowatt-hours (kWh) she has consumed and apply the corresponding rates.
1. Calculate the electricity usage:
Current meter reading - Previous meter reading
20,300 kWh - 17,800 kWh = 2,500 kWh
2. Determine the cost for the first 2000 kWh:
$1.00/kWh * 2000 kWh = $2000.00
3. Determine the cost for the remaining kWh:
500 kWh * $3.50/kWh = $1750.00
4. Add the fuel adjustment charge:
$0.50/kWh * 2500 kWh = $1250.00
5. Calculate the total bill:
$2000.00 + $1750.00 + $1250.00 = $5000.00
To calculate the electricity bill, we first find the difference between the current and previous meter readings.
In this case, Mrs. Brown used 2,500 kWh.
For the first 2000 kWh, the cost is $1.00 per kWh, resulting in a charge of $2000.00.
For the remaining 500 kWh, the cost is $3.50 per kWh, totaling $1750.00.
Additionally, a fuel adjustment charge of $0.50 per kWh is added to the bill. This amounts to $1250.00.
Finally, we add up all the charges to get the total bill, which is $5000.00.
To know more about electricity visit;
https://brainly.com/question/12791045
#SPJ11
The universe now contains a large variety of different elements. Describe how this happened
Answers
Answer: Because Allah made it
Explanation:
Because Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made itBecause Allah made it
the vast size of our solar system makes it impossible for a large, civilization-threatening asteroid or comet to collide with earth.
Answers
Statistically speaking, an asteroid or comet large enough to do serious damage to the human race will eventually collide with Earth.
What is solar system?The Solar System is made up of the Sun, eight planets, and a variety of other celestial bodies. These celestial bodies and planets are drawn to the Sun and circle around it. The Sun, an ordinary star, the planets Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune make up our solar system.The risk of collision presented by astronomical tiny things whose orbits around the Sun bring them close to Earth is known as the "Earth Impact Hazard." These include comet nuclei, asteroids, and their bigger components, all of which are composed of rock.The asteroid's magnitude, likely, contributed to the climatic changes it brought about, including a quick increase in atmospheric temperature, widespread forest fires, and acidified ocean waters.To learn more about solar system refer to:
https://brainly.com/question/1286910
#SPJ4
Elmo finds himself at a Coke machine on a hot and dusty Sunday. The Coke machine requires exact change—two quarters and a dime. No other combination of coins will make anything come out of the machine. No stores are open; no one is in sight. Elmo is so thirsty that the only thing he cares about is how many soft drinks he will be able to buy with the change in his pocket; the more he can buy, the better. While Elmo searches his pockets, your task is to draw some indifference curves that describe Elmo’s preferences about what he finds.
(a) If Elmo has 2 quarters and a dime in his pockets, he can buy 1 soft drink. How many soft drinks can he buy if he has 4 quarters and 2 dimes? 1
(b) Does Elmo have convex preferences between dimes and quarters?
(c) Does Elmo always prefer more of both kinds of money to less?
(d) Does Elmo have a bliss point?
(e) If Elmo had arrived at the Coke machine on a Saturday, the drugstore across the street would have been open. This drugstore has a soda fountain that will sell you as much Coke as you want at a price of 4 cents an ounce. The salesperson will take any combination of dimes and quarters in payment. Suppose that Elmo plans to spend all of the money in his pocket on Coke at the drugstore on Saturday. Draw one or two of Elmo’s indifference curves between quarters and dimes in his pocket. Describe these new indifference curves in words.
Answers
The answers are- (a) 2 soft drinks. (b) Uncertain. (c) Not necessarily.
(d) No bliss point. and, (e) Steeper indifference curves.
(a) If Elmo has 4 quarters and 2 dimes in his pockets, he can buy 2 soft drinks. Since each soft drink requires two quarters and a dime, having double the amount of each coin allows him to make two purchases.
(b) Elmo's preferences between dimes and quarters may or may not be convex. Convex preferences imply that as Elmo increases the quantity of one type of money (quarters or dimes), the marginal utility he derives from each additional unit of that money diminishes. If Elmo's preference for soft drinks is based solely on the ability to purchase them and not on any diminishing marginal utility of the coins themselves, then his preferences may not exhibit convexity.
(c) Elmo does not necessarily always prefer more of both kinds of money to less. Given the specific context of the Coke machine, Elmo's only concern is to have the exact change required to obtain a soft drink. As long as he has the necessary combination of two quarters and a dime, having additional coins does not increase his utility further.
(d) Elmo does not have a bliss point in this scenario. A bliss point refers to the combination of goods or factors that maximizes an individual's utility or satisfaction. Since Elmo's sole objective is to purchase soft drinks from the Coke machine, his utility is maximized when he has the exact change required (two quarters and a dime). Having more coins does not enhance his utility beyond being able to buy a single soft drink.
(e) If Elmo had arrived at the Coke machine on a Saturday, with the drugstore across the street open, his preferences would change. Instead of being limited to the specific combination of two quarters and a dime, he could now use any combination of quarters and dimes to purchase as much Coke as he wants at a price of 4 cents per ounce.
In this case, Elmo's indifference curves between quarters and dimes would exhibit a downward slope, indicating that he is willing to trade off some quantity of one coin for a corresponding increase in the other, while still maintaining the same level of utility. The indifference curves would be steeper than the ones in the previous scenario, as Elmo can now acquire more soft drinks by having a larger combination of quarters and dimes.
These new indifference curves reflect Elmo's preference for more quarters and dimes, as they enable him to buy more Coke at the drugstore. The curves demonstrate that Elmo is willing to sacrifice some quantity of quarters to obtain additional dimes or vice versa, as long as the overall combination allows him to maximize the quantity of Coke he can purchase.
To know more about bliss point,
https://brainly.com/question/33565766
#SPJ4
A car runs 4200m on a straight path in 40 minute. find its velocity?
Answers
Answer:
velocity = displacement/time
= 4200m/ 2400s
= 1.75 m/s
Explanation:
40 minutes × 60 = 2400 seconds
Using the free-body diagram, calculate the net force acting on the sled. Is the sled in a state of dynamic equilibrium?
Answers
The net force acting on the sled is zero. The sled is in a state of dynamic equilibrium.
Explanation:
The two vertical forces, Fg and Fn, cancel each other out, but I choose to "ignore" them in my explenation, although they remain present at all times.
Since the net force acting on the sled is zero, the sled is in some state of equilibrium...
Whether the sled or a stationary equilibrium or in a dynamic equilibrium, depends on the the motion of the object. If the object is moving then it is a dynamic equilibrium and if the object is not moving, then there is a stationary equilibrium.
Look closely at the picture of the sled and the dogs, and try to find out if the sled is standing still or if the sled is moving with a constant speed.
From the movement of snow around the dogs, you can tell, the sled is moving. It clearly is not stationary or left standing still.
So in this case it must be a dynamic equilibrium. The combined pull of all dogs is shown by Ft = 225 N.
Apparently, the friction is displayed as an opposite force shown as Ff = - 225 N. These two horizontal forces cancel each other out.
Strangely enough, this can be compared with a situation like a "tug of war", in which both sides pull with equal force. Although there can be an enormous tension in the cord, nothing moves.... The same is true here although the sled is moving with a constant speed...
EXTRA
Given is that the sled is moving with a constant speed.
No imagine two situations and try to predict what will happen.... Here we go...
Situation 1 The friction force remains Ff = - 225 N but the dogs suddenly start to pull harder, say with a force of 275 N.
Now the net Force will be greater then zero. In that case it will be 275 - 225 = 50 N in favour of the dogs, which would result in an exeleration of the sled, and thus an increase of the speed...
Situation 2 The friction force becomes greater Ff = - 300 N, but the dogs pull with the same force of 225 N.
Now the net Force will be less then zero. In that case it will be 225 - 300 = -75 N in favour of the friction Force, which would result in slowing down the sled. Perhaps the sled operator applied the brake on the sled, which caused a deceleration of the sled, and thus the speed decreases.
Answer:
yes
Explanation:
edg 2020
What do we call the potential mechanical energy stored in an object when work is performed to change its shape?
A.) elastic energy
B.) sound energy
C.) kinetic energy
Answers
A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
Answers
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
For more such questions on time, click on:
https://brainly.com/question/26046491
#SPJ8
You throw a can of cranberry sauce straight up in the air with an initial velocity of 12 m/s. What is the maximum height the baseball reaches above your head.
Answers
Answer:
Δx=7.35m
Explanation:
This is a free fall problem (g= -9.8 m/s²).
Displacement: ? <--- what you're trying to find (max height)
Initial Velocity: 12 m/s
Final Velocity: 0 m/s <-- since the can will land back in your hands
Time: Missing <-- not needed to solve
Acceleration: -9.8 m/s²
The equation that you will use is vf²=vi²+2aΔx
Now plug the information into the equation!
(0m/s)²=(12m/s)²+2(-9.8m/s²)Δx
Multiply the 2 with the acceleration (-9.8m/s²)
(0m/s)²=(12m/s)²-19.6m/s²Δx
Now you need to square the final and initial velocity
0m/s=144m/s-19.6m/s²Δx
Move 144 to the other side of the equal sign
-144m/s=-19.6m/s²Δx
Divide both sides by -19.6m/s²
7.346m=Δx
You can round it to the tenth or hundreth place, up to you!
For this example, I'll round to the hundredth...
Δx=7.35m
I would double check this answer or review it yourself to see if it's correct.
Good luck with your studies!
consider a pipe 45.0 cm long if the pipe is open at both ends. use v=344m/s.
Answers
Consider a pipe 45.0 cm long that is open at both ends, and use v=344 m/s for the speed of sound.
1. First, convert the length of the pipe from centimeters to meters: 45.0 cm = 0.45 m.
2. The fundamental frequency for an open pipe can be found using the formula: f1 = v / (2 * L), where f1 is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.
3. Plug the values into the formula: f1 = 344 m/s / (2 * 0.45 m).
4. Calculate the fundamental frequency: f1 = 344 m/s / 0.9 m = 382.22 Hz.
So, for a 45.0 cm long pipe open at both ends with a speed of sound at 344 m/s, the fundamental frequency is 382.22 Hz.
Learn more about speed of sound at
https://brainly.com/question/15137350
#SPJ11
You place a basketball in the back of a pickup truck and then accelerate the pickup quickly.
Describe the motion of the ball relative to:
(a) the ground and
(b) the pickup.
Answers
a)When the pickup truck accelerates forward then the ball will shift to the back of the of the truck because of inertia relative to ground.
b)You place a basketball in the back of a pickup truck and then accelerate the pickup quickly then ball would be traveling at the same speed with respect to the truck.
What do you mean by relative motion?Relative Motion refers to the motion of any object with respect to a particular point.
For example, a ball thrown upward in a moving object such as bus, would be traveling in the same speed with respect to the bus and would fall in relation to that speed.
To know more about relative motion, refer
https://brainly.com/question/867069
#SPJ13
Books in a library were counted one by one. There were a total of 57000 books in the library. How many significant digits are there in the result? Will the result change if the books are measured in the paacket of 10?
Answers
The total number of significant digits in the given number is five. If the books are measured in packets of 10, the number of significant digits reduces to two.
The given data is: Total number of books in the library = 57,000. We are to determine how many significant digits are there in the result? For this, let us define what are significant digits: Digits that are used to communicate meaning or accuracy of measurements are known as significant digits. In other words, the digits that carry meaning contributing to its measurement uncertainty are called significant digits. It is used to determine the accuracy of the results. In this question, the total number of books in the library is given as 57,000. As there are five non-zero digits in the given number, there are five significant digits in the result. Will the result change if the books are measured in the packet of 10? If the number of books is measured in the packet of 10, then there will be a change in the number of significant digits. When we express 57,000 in the packet of 10, we get: 57,000 = 5.7 × 10^4. Now, there are only two significant digits in the result (5 and 7), and hence the result changes.
Learn more about significant digits here :-
https://brainly.com/question/28993414
#SPJ11
A Ford Shleby GT 500 has a horsepower of 760 hp. What is that is Watts? DO NOT include units - just the numeric answer. I QUESTION 15 An object of mass 100 kg is moved with an acceleration of 10 m/2, and goes fron an initial position of 10 m to a final position of 30 m. What work was done on the object? DO NOT include units - just the numeric answer.
Answers
the work done on the object is 20000 J.
The conversion factor from horsepower to watts is 1 hp = 746 watts.
Therefore, the Ford Shelby GT 500's horsepower of 760 hp can be converted to watts as follows:
760 hp × 746 watts/hp = 567760 watts
To convert horsepower to watts, you simply need to multiply the number of horsepower by the conversion factor of 746 watts/hp.So, the numeric answer for 760 hp in watts is 567760.
According to the work-energy principle, the work done on an object is equal to the change in kinetic energy. Mathematically, the work-energy principle can be represented as follows:
W = ΔKHere, W represents the work done on the object, and ΔK represents the change in kinetic energy of the object.
The change in kinetic energy can be calculated using the following formula:
ΔK = (1/2)mvf² - (1/2)mvi²
Here, m represents the mass of the object, vi represents the initial velocity of the object, and vf represents the final velocity of the object. In this case, the object is initially at rest (vi = 0), so the formula can be simplified to
:ΔK = (1/2)mvf²
Now, we can use the following kinematic equation to calculate the final velocity of the object:
vf² = vi² + 2ax
Here, a represents the acceleration of the object, x represents the displacement of the object, and vi represents the initial velocity of the object. Plugging in the given values, we get:
vf² = 0 + 2(10 m/s²)(30 m - 10 m)vf² = 400 m²/s²vf = 20 m/s
Now, we can plug in the values of m and vf to calculate the change in kinetic energy:
ΔK = (1/2)(100 kg)(20 m/s)²ΔK = 20000 JSo, the numeric answer for the work done on the object is 20000 J.
learn more about work done here
https://brainly.com/question/25573309
#SPJ11
When ammonium chloride is dissolved in water the solution becomes colder.
a) Is the dissolution of ammonium chloride endothermic or exothermic?
b) What can you say about the relative magnitudes of the lattice energy of ammonium
chloride and its heat of hydration?
c) Sketch a qualitative energy diagram
d) Why does a solution form? What drives the process?
Answers
a) Ammonium chloride dissolves in water in an exothermic process.
b) Ammonium chloride's hydration heat is less intense than its lattice energy.
b) A qualitative energy diagram for the dissolving of solid ammonium chloride in water would demonstrate that the starting state has more energy than the final state (ammonium chloride ions in solution). A downward slope would be visible in the diagram, signifying the release of energy (exothermic process).
d) Intermolecular forces draw the molecules of the solute and solvent together, resulting in the formation of a solution. Entropy (disorder) increases as solvent molecules surround solute molecules, making the solution more disordered than the solid, which drives the process. This tendency to more entropy
Learn more about ammonium chloride here:
https://brainly.com/question/23387600
#SPJ4