Identical forces act for the same length of time on two different object. The change in momentum of the smaller object is
A) smaller than the change in momentum of the larger mass, but not zero.
B) zero.
C) equal to the change in momentum of the larger mass.
D) larger than the change in momentum of the larger mass.

The mass of H₂O in the oceans is much larger than the mass of H₂O originally contained in the mantle by a factor of approximately 3860

The mass of H2O in the oceans can be calculated using the following formula:mass of H2O in the oceans = volume of seawater × density of seawater × percentage of H2O in seawater where the volume of seawater is the total volume of the oceans on Earth, which is approximately 1.332 billion km³.

The density of seawater is 1.025 gm/cm³, and seawater is 96.5 percent H₂O. Therefore, the mass of H2O in the oceans is:m = 1.332 × 10⁹ km³ × (1.025 gm/cm³) × (0.965)= 1.307 × 10²¹ gmTo compare the mass of H₂O in the oceans to the mass of H₂O originally contained in the mantle, we need to first find the mass of H₂O originally contained in the mantle. The total mass of the mantle is approximately 4.5 × 10²⁴ gm, and it is estimated that the mantle contains between 50 and 100 ppm of H₂O.

Taking an average value of 75 ppm and using the mass of the mantle, we can calculate the mass of H₂O originally contained in the mantle as follows: mass of H₂O in mantle = (75 ppm) × (4.5 × 10²⁴ gm)= 3.38 × 10¹⁹ gm Therefore, the mass of H₂O in the oceans is much larger than the mass of H₂O originally contained in the mantle by a factor of approximately 3860. It is unlikely that the H₂O of the oceans came from the outgassing of the mantle alone, as the amount of H₂O in the oceans is much greater than the amount of H₂O originally contained in the mantle. Other sources of water, such as comets and asteroids, are thought to have contributed to the water content of the oceans.

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If the zero is located in the RHP and the poles are located in the LHP, it is possible that the process will exhibit an inverse response based on the transfer function G(s) = K(Tzs + 1) / ((115 + 1)(T25 + 1)).

To determine when the process will possess an inverse response based on the given transfer function G(s) = K(Tzs + 1) / ((115 + 1)(T25 + 1)), we need to analyze the characteristics of the transfer function.

In a transfer function, an inverse response occurs when the sign of the phase angle changes by 180 degrees or π radians as the frequency increases. Mathematically, this corresponds to a pole and a zero that are located in the right-half plane (RHP) of the complex plane.

From the given transfer function G(s) = K(Tzs + 1) / ((115 + 1)(T25 + 1)), we can observe the following:

The numerator of the transfer function has a single zero, which is given by (Tzs + 1).

The denominator of the transfer function has two poles, which are given by ((115 + 1)(T25 + 1)).

To determine the location of the poles and zeros, we need specific values for T, z, and K. Without those values, we cannot determine the exact location of the poles and zeros or whether they lie in the RHP.

However, in general, if the zero (Tzs + 1) is located in the RHP and the poles ((115 + 1)(T25 + 1)) are located in the left-half plane (LHP), the transfer function may possess an inverse response. The presence of a pole in the RHP and a zero in the LHP can lead to an inverse response behavior.

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The missing word is "oxygen". Elements are the simplest form of matter that cannot be broken down into simpler substances by chemical means.

In order to speed up a fire to create an explosion, you need to provide more oxygen to the combustion process. The reaction between fuel and oxygen produces heat and gases, which cause the fire to grow and spread. By regulating the amount of oxygen available and how closely it's packed together with other elements, you can control the rate of the reaction and the intensity of the fire. If the oxygen supply is suddenly increased or the fuel is densely packed, the fire can quickly become an explosion due to the sudden release of energy.

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Taking into account the scientific notation, the result of the sum is 6.6365×10⁵.

First, remember that scientific notation is a quick way to represent a number using powers of base ten.

The numbers are written as a product:

a×10ⁿ

where:

You want to add two numbers in scientific notation. It should be noted that when the numbers to be added do not have the same base 10 exponent, the base 10 power with the highest exponent must be found.

In this case, the highest exponent is 5.

Then all the values ​​are expressed as a function of the base 10 exponent with the highest exponent. In this case: 8.6500×10³= 0.086500×10⁵

Taking the quantities to the same exponent, all you have to do is add what was previously called the number "a". In this case:

0.086500×10⁵ + 6.5500×10⁵= (0.086500+ 6.5500)×10⁵=  6.6365×10⁵

Finally, the result of the sum is 6.6365×10⁵.

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Surely, when there is a decrease in temperature accompanying a chemical reaction, this indicates that: energy was absorbed.

The correct answer choice is option d.

In happens that in a chemical reaction which leads to the absorption of energy due to decrease in temperature, this results as a result of the fact that bonds in the reactants of the reaction are broken than it is released

So therefore, we can now deduce and confirm from the explanation given above that it is an endothermic reaction when energy is absorbed by the system.

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The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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The fruit basket recipe will the specialty store need to fulfill all 725 orders is 120 strawberries.

Fruit basket is defined as a gift basket filled with a variety of fruits.

A fruit basket can be called as a punnet is a compact box or square basket used for gathering, transporting, and selling fruits and vegetables, typically for small berries.

As one basket has 6 strawberries.

So, for completing 725 order we need

= 725 / 6

= 120.8 = 120 strawberries

Thus, the  fruit basket recipe will the specialty store need to fulfill all 725 orders is 120 strawberries.

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The average atomic mass of silver is approximately 108.3324. The mass of an atom is defined as its atomic mass.

The two isotopes of silver are Ag-107 (60 neutrons) and Ag-109 (62 neutrons).

To calculate the average atomic mass of silver, we need to multiply the mass of each isotope by its natural abundance, then add these values together.

Ag-107 has a mass of 107

Natural abundance of 51.83%,

so its contribution to the average atomic mass of silver is 107 * 0.5183 = 55.8391

Ag-109 has a mass of 109 and a natural abundance of 48.17%,

so its contribution to the average atomic mass of silver is 109 * 0.4817 = 52.4933

The average atomic mass of silver is the sum of these two values,

which is 55.8391 + 52.4933 = 108.3324.

So, the average atomic mass of silver is approximately 108.3324.

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Total moles of gas in the reactants: 4

Total moles of gas in the products: 2

Answer:

Regional metamorphism occurs at convergent plate boundaries, due to intense pressure. As two plates collide, the Earth's crust folds and faults. The intense pressure changes large areas of the Earth's crust into metamorphic rock. Mountain ranges are typically metamorphic rock, due to plate tectonic processes.

Explanation:

Hope this helps :D

Tectonic plate movement is responsible for forming regional metamorphic rock.

The tectonic plate movement involves the subsurface movement of formation caused by natural force of earth.  These movement can be uplifting, faulting or folding.

There are three main types of tectonic plate movement.

There are mainly three types of rock.

Thus, tectonic plate movement is responsible for forming regional metamorphic rock.

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Your question is incomplete but most probably your full question was

Tectonic plate movement is responsible for forming which type of rock? Choose all that apply

A. Igneous rock

B. Metamorphic rock

C. Sedimentary rock

D. None of the above

The idea of this excerpt is that John Burns' outdated clothing did not prevent him from being a strong supporter of the Union Army. Despite his unconventional appearance, his dedication to the cause was evident to his fellow soldiers.

This explanation emphasizes that John Burns' clothing did not define his ability to support the Union Army. The best retelling of the central idea of this excerpt is: John Burns wore old-fashioned clothing, but his fellow soldiers learned that he was still strongly devoted to the Union.

This option conveys the central idea that despite his old-fashioned appearance, John Burns was committed to the Union cause. It highlights that his fellow soldiers eventually recognized his devotion. The other options do not accurately retell the central idea ,The commanders not understanding his outfit is not the central idea, as it doesn't focus on his devotion to the Union. John Burns being silly looking and therefore unable to help the Union army at Gettysburg is not relevant to the central idea of his devotion. The jealousy of other soldiers about his attire is not the central focus of the excerpt.

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The compounds ranked based on their relative Bronsted acidities from strongest to weakest are as follows:

1. H-I (Hydrogen iodide)

2. H-CH3 (Methyl radical)

3. H-OH (Hydroxide ion)

4. H-NH2 (Ammonia)

5. H-F (Hydrogen fluoride)

Bronsted acidities can be determined by analyzing the stability of the corresponding conjugate bases. A stronger acid will have a more stable conjugate base. Here is the explanation for the ranking:

1. H-I: Hydrogen iodide (HI) is a strong acid because iodide ion (I-) is a stable conjugate base. Iodide ion is large and can effectively disperse negative charge, leading to stability.

2. H-CH3: Methyl radical (CH3) is weaker than HI but stronger than the remaining compounds. It is a stable radical and has resonance structures that stabilize its conjugate base.

3. H-OH: Hydroxide ion (OH-) is less acidic than HI and CH3. It forms a stable conjugate base, but it is not as stable as iodide ion or the methyl radical.

4. H-NH2: Ammonia (NH3) is weaker than the previous compounds. The lone pair on the nitrogen atom can be donated to accept a proton, making NH2- a relatively unstable conjugate base.

5. H-F: Hydrogen fluoride (HF) is the weakest acid among the given compounds. The fluoride ion (F-) is a relatively strong base, and its conjugate acid, HF, is a weaker acid compared to the others.

The ranking of the given compounds based on their relative Bronsted acidities, from strongest to weakest, is H-I, H-CH3, H-OH, H-NH2, and H-F. This ranking is determined by analyzing the stability of their respective conjugate bases, with stronger acids having more stable conjugate bases.

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Answer:

B)

Explanation:

it has 5

Answer:Aluminum metal in silver nitrate ….

You might be expecting silver metal, Ag, and aluminum nitrate, Al(NO3)3, as products. But instead all you will end up with is wet aluminum. The passivating layer of Al2O3 will prevent aluminum from reducing silver ions.

Explanation: Al(s) + AgNO3(aq) → No reaction

The two things we might do to the mixture to disrupt the Al2O3 surface will cause the Ag+ ions to react. Often a source of chloride ion is used because AlCl4^- will form, exposing the aluminum surface. But that will cause AgCl(s) to precipitate. You can also make the solution basic with NaOH and form Al(OH)4^-, but that will cause Ag2O(s) to form. (You will get Ag2O instead of AgOH.)

Concentrated acids will oxidize any aluminum metal that might be exposed if you were to add concentrated HNO3. That would simply enhance the

11.2L is the total volume of O\(_2\) produced when 1 mole of PbO decomposes at STP for reaction 2 PbO(s) → 2 Pb(s) + O\(_2\)(g).

Lead(II) oxide, often known as lead monoxide, is an inorganic chemical having the formula PbO. PbO exists in two polymorphs: litharge, which has a tetragonal crystalline structure, as well as massicot, which has an orthorhombic crystalline structure.

The majority of modern PbO uses are already in lead-based commercial glass as well as industrial ceramics, particularly computer components. It is a kind of amphoteric oxide.

2 PbO(s) → 2 Pb(s) + O\(_2\)(g)

mole of PbO =1 mole

the mole ratio between PbO  and oxygen is 2:1

mole of oxygen = 0.5mole

volume of oxygen = mole of oxygen ×22.4L

                              = 0.5×22.4L

                              = 11.2L

Therefore,  11.2L is the total volume of O\(_2\) produced when 1 mole of PbO decomposes at STP.

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Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl

To calculate the concentration of NaCl in the resulting solution in mg/L NaCl, we can use the formula; Concentration (mg/L) = (Mass of solute ÷ Volume of solution in L) × 1000 g / 1 mg NaCl is present in the stock solution of 25 mL. So, the mass of NaCl in the solution would be;0.0842 g ÷ 25 mL = 0.00337 g/mL. Now, in the resulting solution, a 1.00 mL aliquot of the stock solution is transferred to a 50.00 mL volumetric flask and diluted to volume. Therefore, the volume of the resulting solution is 50.00 mL. We will substitute these values in the formula, Concentration (mg/L) = (0.00337 g/mL ÷ 50 mL) × 1000 g / 1 mg concentration (mg/L) = 67.4 mg/L. Therefore, the concentration of NaCl in the resulting solution in mg/L NaCl is 67.4 mg/L.7.  Concentration = 67.4 mg/LTolerance = 4.28 mg/LTotal concentration = 67.4 + 4.28 mg/L = 71.68 mg/LWe round off this value to one decimal place; Total concentration = 71.7 mg/LTherefore, the concentration of NaCl in the resulting solution using propagation of error through the calculation is 67.4+0.4 mg/L.8. Two possible sources of random (indeterminate) error in the experiment are; Errors in temperature measurement. Errors in measurement of water volume. Two possible sources of systematic (determinate) error in the experiment are; Incorrect calibration of volumetric glasswareIncorrect mass of NaCl.

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The half-life for the reaction is 0.693/k. It will take approximately 1.386/k seconds for the concentration of A to decrease to 25% of its initial concentration. It will take approximately 2.218/k seconds for the concentration of A to decrease to 0.78 M. If the initial concentration of A is 0.150 M, the concentration of A after 5 half-lives is 0.00938 M, and after 10 half-lives it is 0.00059 M.

The decomposition of A is a first-order reaction with a rate constant of k at a certain temperature. The rate law for this reaction is given by:

Rate = k[A]

The half-life for a first-order reaction is given by the equation:

t1/2 = 0.693/k

Substituting the given rate constant into this equation gives the half-life for the reaction.

To calculate how long it will take for the concentration of A to decrease to 25% of its initial concentration, we can use the equation:

\(ln\frac{A_{t} }{A_{0}} = -k_{t}\)

Substituting 0.25[A]0 for [A]t and the given rate constant into this equation, we can solve for t.

Similarly, to calculate how long it will take for the concentration of A to decrease to 0.78 M, we can use the same equation and substitute 0.78 M for [A]t and the given rate constant into the equation.

To determine the concentration of A after a certain amount of time has passed, we can use the equation: [A]t = [A]₀ \(e^{-kt}\)

Substituting the given rate constant and the time elapsed into this equation will give us the concentration of A at that time.

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The slope of the graph mass versus volume for the data is the density of the material.

The slope of a line in mathematics is given as;

m = y2 - y1/x2 - x1.

In this case we have a graph in which the y axis is the mass of the substance and the x axis is the volume of the substance. We know that ratio of the mass to the volume of the substance is the density and that this value is a constant.

As such, the slope of the graph mass versus volume for the data is the density of the material.

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One mole of each element contains Avogadro's number of atoms, which is 6.022 x 10^23 atoms. Therefore, all three substances have the same number of atoms, which is 6.022 x 10^23 atoms.

Answer:

A

Explanation:

A compound machine is a combination of two or more simple machines.

2-Methyl-2-butanol is a type of alcohol that is also known as tert-butyl alcohol or 2-methylpropyl alcohol.

what are the properties of 2-Methyl-2-butanol ?

It is a clear, colorless liquid that has a characteristic sweet and fruity odor. This alcohol is used in a variety of applications, including as a solvent, as a fuel additive, and as an intermediate in the synthesis of other chemicals. It is also used in the production of various fragrances and flavors, as well as in the formulation of certain pharmaceuticals and personal care products.

2-Methyl-2-butanol (tert-butyl alcohol) is a branched-chain alcohol that is characterized by its four carbon atoms and its secondary alcohol functional group. It is a clear, colorless, and relatively low-volatility liquid that has a low water solubility and a relatively low boiling point compared to other alcohols of similar molecular weight.

In terms of its properties and uses, 2-methyl-2-butanol is an effective solvent for a variety of organic compounds, including resins, fats, and oils, and it is also used as a starting material for the production of other chemicals. As a fuel additive, it can help to increase the octane rating of gasoline, and it can also help to reduce engine knock and improve fuel efficiency.

2-Methyl-2-butanol is a type of alcohol that is also known as tert-butyl alcohol or 2-methylpropyl alcohol.

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A compound with a soapy feel suggests that it is likely a basic substance. Basic substances have pH values above 7 on the pH scale, which ranges from 0 to 14.

The pH scale is logarithmic, meaning each unit represents a tenfold difference in hydrogen ion concentration. Given that the soapy feel is a characteristic of basic compounds, you would expect the mystery compound to exist in a pH range that is greater than 7.

This range typically falls between pH 8 and pH 14, with higher pH values indicating stronger alkaline properties.

However, without further information, it is challenging to determine the exact pH range of the mystery compound.

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Answer:

I don't know about the rest but A is heptane

Explanation:

I honestly believe the answer is greater

If the energy required to break the lattice is less than the energy released as the ions go into solution, then the dissolution of solute is endothermic.

An endothermic reaction is one in which energy is absorbed. This implies that the energy change of the reaction is positive.

Now, if the energy required to break the lattice is less than the energy released as the ions go into solution, then the process is endothermic and energy is absorbed.

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Answer: A3B2

Explanations:- It is given that the charge for A is +2 and the charge for B is -3. The over all compound is neutral means the over all charge is zero. For making the over all charge zero, we need 3 positive ions and 2 negative ions. This makes a +6 charge for A and -6 charge for B and the over all charge is zero.

Also, if we think about the criss cross then charge of A becomes the subscript of B and the charge of B becomes the subscript of A.

So, the formula of the ionic compound is . In this compound the ratio of A to B is 3:2.

The balanced equation could be shown as:

A3B2

Answer: Cr2(SO4)3 its this

Explanation:

Answer:

Displacement reactions occur when a more reactive metal reacts to displace a less reactive metal in a compound.

Explanation:

All of the following are qualitative tests that are often used to identify unknown ionic compounds except titration.

Qualitative tests are conducted to determine the presence or absence of certain ions or compounds in a sample based on their characteristic reactions. Common qualitative tests include flame tests, precipitation reactions, color changes, and gas evolution tests.

Titration, on the other hand, is a quantitative technique used to determine the concentration of a specific substance in a solution by reacting it with a standardized solution of another substance. It is not typically used as a qualitative test for identifying unknown ionic compounds.

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The percentage of chloride in the unknown sample is approximately 15.93%.

To calculate the percentage of chloride in the unknown sample, you can use the mass of silver chloride obtained to determine the number of moles of chloride in the original sample, and then convert that to a percentage.

First, calculate the number of moles of silver chloride by dividing the mass by its molar mass:

0.7332 g / 143.32 g/mol = 0.00513 mol AgCl

Next, calculate the number of moles of chloride in the original sample by assuming a 1:1 ratio of chloride ions to silver ions in the reaction:

0.00513 mol AgCl * 1 Cl- / 1 Ag+ = 0.00513 mol Cl-

Finally, divide the number of moles of chloride by the mass of the original sample and multiply by 100 to convert to a percentage:

(0.00513 mol Cl- / 0.3221 g) * 100 = 15.93%

So, the percentage of chloride in the unknown sample is approximately 15.93%.

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