Technical Problem:Designing an optimized approach to choose a diode that meets specific requirements, considering factors such as material and device parameters, stability at high temperatures, and costs.
Approach Identify the requirements: Determine the desired characteristics of the diode, such as capacitance range, low forward resistance, output voltage, maximum reverse bias, and input frequency range.
Conduct a literature review: Gather information on various diode types, their material properties, and performance specifications.Create a functional block diagram: Develop a visual representation of the factors to be considered, including material parameters, device characteristics, stability at high temperatures, and costs.Formulate a selection criteria: Define quantitative criteria based on the requirements and assign weights to different parameters based on their importance.
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1. Plot the normal and shear components of stress on the fictitious element relative to (1) Cartesian coordinator system, (2) a cylindrical coordinator system, and (3) a spherical coordinate system. Note: Your drawing should be by hand and in a 3D manner. Write the stress notation in matrix form for three coordinator systems. Explain the biological motivations for using the above three coordinator systems.
Answer:
d
Explanation:
Flat plate collector can provide temperature upto_____
Answer:
80⁰C
Explanation:
80°C.
Normal flat plate collectors can deliver heat at temperatures up to 80°C. Deficiency rates for normal flat plate collectors can be classified as visual losses, which produce with cumulative angles of the incident sunshine, and thermal losses, which upsurge fast with the working temperature intensities
An Infrastructure as a Service (IaaS) provider shares its computing resources between a number of different clients, each of whom has a separate dedicated instance to host their own operating systems and applications.
Which Cloud computing concept is illustrated here?
Answer:
Elasticity
Explanation:
Cloud computing comprises of three (3) service models and these are;
1. Platform as a Service (PaaS).
2. Software as a Service (SaaS).
3. Infrastructure as a Service (IaaS).
If Nick's average stride length is 2.7 feet, how many strides will it take him to walk to school?
Answer: how far is the school?
Explanation:
which one of these reduce fraction?
What is the difference between aerospace and aeronautical engineering
Answer:
Aerospace engineering is a broader subject that includes both aircraft and spacecraft studies. Aeronautical engineering focuses more on aircraft design and construction that flies within the Earth's atmosphere.
Explanation:
Aerospace engineering is a vast topic that involves research on both airplanes and spacecraft, further explained in the following paragraph.
Which profession pays better Aerospace or aeronautical engineering?The median annual pay for aerospace engineers is $116,500, according to the US Bureau of Labor Statistics. Aerospace engineers, on the other hand, make $56.01 per hour. According to Glassdoor, the national average compensation for an Aeronautical Engineer in the United States is $80,000.
Aerospace engineering is a vast topic that involves research on both airplanes and spacecraft. Aeronautical engineering is concerned with the design and building of aircraft that fly within the atmosphere.
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Which step in the reverse-engineering process involves the identification of subsystems and their relationship to one another?
The answer is analyze
A chef needs 20 walnuts for a recipe and has to crack each one. the effort force is 4.1inches from the fulcrum and the walnut sits 2.2inces from the fulcrum. if the chef can only apply 7lb of force, what is the maximum amount of resistance force the walnut can apply in order for the nut to be cracked? answer should be to the nearest (0.0)
The calculated answer is 4 kgf. The greatest resisting force that the walnut may exert before the nut cracks
In physics, resistive force is a a type of force, or the vector sum of the various forces, whose direction is opposite to the motion of a body, and may refer to: Friction, during sliding and/or rolling. During moving through a fluid, drag (physics) (see fluid dynamics). For all compression positions, the direction of specific deformation as a function of shell thickness and geometric mean diameter was identical to the direction of energy.
If load is 40 kgf and effort is?
effort arm=20 cm, load arm=2 cm
By the moments' principle,
effort arm equals load arm.
40kgf×2cm=E×10cm
∴E=40×220kgf=4kgf.
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SAFe Lean-Agile Principles (9 total)
The SAFe Lean-Agile principles form the foundation of the framework and guide organizations in adopting an agile mindset.
SAFe (Scaled Agile Framework) is a methodology for scaling agile practices to larger organizations. The SAFe Lean-Agile principles form the foundation of the framework and guide organizations in adopting an agile mindset. The nine SAFe Lean-Agile principles are:
1)Take an economic view: Understand and optimize the flow of value through the organization to drive economic outcomes.
2)Apply systems thinking: Consider the organization as a complex system of interdependent parts and optimize the whole, not just the individual components.
3)Assume variability and preserve options: Embrace uncertainty and variability by creating options for decision-making as late as possible.
4)Build incrementally with fast, integrated learning cycles: Build solutions incrementally through fast feedback loops to ensure that they meet the customer's needs.
5)Base milestones on objective evaluation of working systems: Define milestones based on working systems, not on intermediate artifacts or milestones.
6)Visualize and limit WIP (work in progress), reduce batch sizes, and manage queue lengths: Limit the amount of work in progress to reduce lead time and increase efficiency.
7)Apply cadence, synchronize with cross-domain planning: Establish a regular, predictable cadence for all work and align planning across domains to enable cross-functional collaboration.
8)Unlock the intrinsic motivation of knowledge workers: Foster a culture that supports autonomy, mastery, and purpose to motivate and engage knowledge workers.
9)Decentralize decision-making: Empower those closest to the work to make decisions and enable decentralized decision-making across the organization.
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10) The armature resistance of a 47kw, 245V separately excited DC generator is 0.0350. The generator delivers rated load at the rated terminal voltage. Ensure that you show all of your calculations. (0) Find the armature current and the generated armature voltage at the rated load. (ii) If the terminal voltage is changed to 250V but the output is reduced to 42kW find the new generated armature voltage. (11) hr if 40kW is delivered with the generator voltage at 245V find the terminal voltage and the armature current. (iv) If the terminal voltage is now 253V and the generated armature voltage is 260V what is the load power?
Ea = 238.83V
(i) The armature resistance of a 47kw, 245V separately excited DC generator is 0.0350.
To calculate armature current, we use the formula of armature current Ia = (Vt-Ea)/Ra Where,
Vt = Rated Terminal Voltage = 245V
Ea = Generated Armature Voltage
Ra = Armature Resistance = 0.0350
Ia = (245 - Ea)/0.0350
Ea = 245 - 0.0350 × Ia
We know that 47kW is the output of the generator,
thus ,P = V × Ia
47,000 W = 245 V × IaIa = 191.84 Amps
Therefore, Ea = 245 - 0.0350 × 191.84 = 238.83V
The new generated armature voltage is 244.88V.
(ii) To calculate generated armature voltage, we use the formula of output power
.P = V × Ia => 42,000 = 250 × IaIa = 168 Amps
Now, Ea = Vt - Ia × RaEa = 250 - 168 × 0.0350 = 244.88V
The terminal voltage is 250.87V and the armature current is 163.27A.
(iii) To calculate terminal voltage and armature current, we use the formula of output power.
P = V × Ia => 40,000 = 245 × Ia
Ia = 163.27 Amps
Now, Ea = Vt - Ia × Ra
245 = Vt - 163.27 × 0.0350Vt = 250.87V
The load power is 50.6kW.
(iv) To calculate load power, we use the formula of output power.
P = V × Ia => P = 260V × Ia
Ia = (253 - 260)/0.0350
Ia = -200 Amps (negative sign indicates that the current is flowing in opposite direction)
Load Power = V × Ia = 253 × 200 = 50.6kW
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Consider a mild steel specimen with yield strength of 43.5 ksi and Young's modulus of 29,000 ksi. It is stretched up to a point where the strain in the specimen is 0.2% (or 0.002). If the specimen is unloaded (i.e. load reduces to zero), the residual strain (or permanent set) is: 0.05% 0.1% 0% 0.2%
Answer:
0.05%
Explanation:
From the question, we have;
The yield strength of the mild steel, \(\sigma _c\) = 43.5 ksi
Young's modulus of elasticity, ∈ = 29,000 ksi
The total strain, \(\epsilon _c\) = 0.2% = 0.002
The inelatic strain \(\epsilon_c^{in}\) is given as follows;
\(\epsilon_c^{in}\) = \(\epsilon _c\) - \(\sigma _c\)/∈
Therefore, we have;
\(\epsilon_c^{in}\) = 0.002 - 43.5/(29,000) = 0.0005
Therefore, the inelastic strain, \(\epsilon_c^{in}\) = 0.0005 = 0.05%
Taking the inelastic strain as the residual strain, we have;
The residual strain = 0.05%
guide specifications and commentary for vessel collision design of highway bridges, second edition pdf
The "Guide Specifications and Commentary for Vessel Collision Design of Highway Bridges, Second Edition" is a document in PDF format that provides guidelines and explanatory notes for designing highway bridges to withstand vessel collisions.
How is this so?It contains detailed specifications and recommendations on factors such as impact loads, structural design considerations, and protective measures to minimize the potential damage caused by vessel collisions.
The document serves as a comprehensive resource for engineers and designers involved in bridge construction projects near waterways.
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rank the following gases in order of decreasing rate of effusion. rank from the highest to lowest effusion rate. to rank items as equivalent, overlap them.
It means that the gas with the lowest molecular weight will have the highest effusion rate.
What has the highest rate of effusion?The given gases' effusion rates are listed in order from highest to lowest. The effusion rate of a hydrogen molecule is the highest, whereas that of a hydrocarbon is the lowest.
A gas will effuse faster when it is lighter and more slowly when it is heavier. Helium (He) will have the highest rate of effusion since it has the lowest molecular weight (atomic weight, in this example).
The following equation can be used to compare the rate of effusion for two gases: The effusion rates in this case are inversely related to the square root of the gas molecules' masses. A container contains an amalgam of neon and argon gas.
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A commercial jet is flying at a standard altitude of 35,000 ft with a velocity of 550 mph: (a) what is the Mach number? (b) should the flow be treated as incompressible, why or why not?
Answer:
Mach number = 0.68168
The flow should be treated as compressible.
Explanation:
Given that:
The altitude of a commercial jet = 35000
The properties of air at that given altitude are as follows:
Pressure = 24.577 kPa
Temperature T = 50.78176° C
Temperature T = ( 50.78176 + 273 )K = 328.78176 K
\(\varphi = 0.38428 \ kg/m^3\)
The velocity is also given as: 550 mph = 245.872 m/s
Therefore, the sonic velocity is firstly determined by using the formula:
\(a = \sqrt{ \vartheta \times R \times T\\)
\(a = \sqrt{1.4 \times 287 \times 323.78176\)
\(a = \sqrt{130095.5112\)
a = 360.68755 m/s
Then, we can calculate the Mach number by using the expression:
\({Mach \ number = \dfrac{V}{a}}\)
\(Mach \ number = \dfrac{245.872}{360.68755}\)
Mach number = 0.68168
b) Ideally, all flows are compressible because the Mach number is greater than 0.3, suppose the Mach number is lesser than 0.3, then it is incompressible.
a transformer is built with 200 primary turns and 50 secondary turns. Whats the transformers turn rate? A) 1:4 B) 2:1 C) 1:2 D) 4:1
Answer:
\(4:1\)
Explanation:
\(N_p\) = Number of turns of primary coil = 200
\(N_s\) = Number of turns of secondary coil = 50
The transformer turn ratio is given by
\(\dfrac{N_p}{N_s}=\dfrac{200}{50}\)
\(\Rightarrow \dfrac{N_p}{N_s}=\dfrac{4}{1}\)
\(\Rightarrow \dfrac{N_p}{N_s}=4:1\)
The transformer turn ratio is \(4:1\).
For some metal alloy, a true stress of 345 MPa (50040 psi) produces a plastic true strain of 0.02. How much will a specimen of this material elongate when a true stress of 412 MPa (59760 psi) is applied if the original length is 480 mm (18.90 in.)? Assume a value of 0.22 for the strain-hardening exponent, n.
Answer:
the elongation of the metal alloy is 21.998 mm
Explanation:
Given the data in the question;
K = σT/ (εT)ⁿ
given that metal alloy true stress σT = 345 Mpa, plastic true strain εT = 0.02,
strain-hardening exponent n = 0.22
we substitute
K = 345 / \(0.02^{0.22\)
K = 815.8165 Mpa
next, we determine the true strain
(εT) = (σT/ K)^1/n
given that σT = 412 MPa
we substitute
(εT) = (412 / 815.8165 )^(1/0.22)
(εT) = 0.04481 mm
Now, we calculate the instantaneous length
\(l_i\) = \(l_0e^{ET\)
given that \(l_0\) = 480 mm
we substitute
\(l_i\) =\(480mm\) × \(e^{0.04481\)
\(l_i\) = 501.998 mm
Now we find the elongation;
Elongation = \(l_i - l_0\)
we substitute
Elongation = 501.998 mm - 480 mm
Elongation = 21.998 mm
Therefore, the elongation of the metal alloy is 21.998 mm
A closed vessel of volume 80 litres contains 0.5 N of gas at a pressure of 150 kN/m2. If the gas is compressed isothermally to half its volume, determine the resulting pressure.
Answer:
The resulting pressure of the gas when its volume decreases is 300 kN/m².
Explanation:
Given;
initial volume of the gas, V₁ = 80 L
number of moles of the gas, n = 0.5 moles
initial pressure of the gas, P₁ = 150 kN/m² = 150 kPa
Determine the constant temperature of the gas using ideal gas equation;
PV = nRT
where;
R is ideal gas constant = 8.315 L.kPa/K.mol
T is the constant temperature
\(T = \frac{P_1V_1}{nR} \\\\T = \frac{150.kPa \ \times \ 80 .L}{0.5 .mol \ \times \ 8.315(L.kPa/mol.K)} \\\\T = 2,886.35 \ K\)
When the gas is compressed to half of its volume;
new volume of the gas, V₂ = ¹/₂ V₁
= ¹/₂ x 80L = 40 L
The new pressure, P₂ is calculated as;
\(P_2V_2 = nRT\\\\P_2 = \frac{nRT}{V_2} \\\\P_2 = \frac{0.5 \times 8.315\times 2886.35}{40} \\\\P_2 = 300 \ kPa = 300 \ kN/m^2\)
Therefore, the resulting pressure of the gas when its volume decreases is 300 kN/m².
29 10 1 point According to Gate Theory, which of the following factors can make you more sensitive to pain? Placebo effects Competing signals, like rubbing your elbow Chronic stress High levels of arousal 30 1 point Patients who are allowed to self-administer morphine use less than when they receive injections from healthcare providers. True False 31 1 point What happens when people lose their sense of smell (olfaction)? They often become manic. 32 Not much. Olfaction is not a very important sense for humans. They compensate by developing an increased sensitivity to taste (gustation). They often become depressed. 1 point The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them. True False
The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.
Gate Theory states that competing signals such as rubbing your elbow can make you more sensitive to pain. This theory suggests that physical signals such as massage, pressure, heat, or cold can block the transmission of pain messages through the spinal cord and prevent them from reaching the brain. Therefore, when people rub their elbows or apply pressure to the area, this stimulates the non-painful touch fibers and decreases the transmission of the painful stimuli.
As per the statement, patients who are allowed to self-administer morphine use less than when they receive injections from healthcare providers is True. Olfaction is a very important sense for humans, and they often become depressed when they lose their sense of smell (olfaction). The statement that The different taste qualities (sweet, sour, bitter, salt, umami) each have their own area of the tongue that is most sensitive to them is False.
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in the mvc architecture the functionality of the system is organized into services, with each service delivered from a separate server..........(t/f)
It is False to state that in the MVC Architecture the functionality of the system is organized into services, with each service delivered from a separate server. The above scenario occurs within Client-Server Architecture.
What is MVC Architecture?Model-view-controller is a software architecture style for building user interfaces that divides the underlying program logic into three interrelated pieces. This is done to isolate internal information representations from how data is communicated to and accepted by the user.
The Model-View-Controller (MVC) architectural pattern, on the other hand, divides an application into three key logical components: the model, the view, and the controller. Every one of these components is designed to handle particular parts of an application's development.
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how would the discharge of the river change if its channel depth decreased to 1ft, its width stayed at 10ft, and its flow velocity increased to 9 ft/sec? justify your answer.
The new discharge may remain roughly the same or could even increase slightly, depending on the exact values of width, depth, and velocity.
The discharge of a river is the volume of water that passes through a given cross-section of the river per unit of time. It is calculated as the product of the cross-sectional area of the river channel (width times depth) and the flow velocity.
Discharge (Q) = Width (W) × Depth (D) × Velocity (V)
Given the following changes:
Channel depth (D) decreased to 1 ft
Width (W) stayed at 10 ft
Flow velocity (V) increased to 9 ft/sec
The new discharge (Q') can be calculated as:
Q' = W × D' × V'
Where D' is the new channel depth of 1 ft, and V' is the new flow velocity of 9 ft/sec.
An incompressible fluid, like the water in a river, has a constant mass flow rate along a streamline according to the fluid mechanics principle of continuity. This means that, in the absence of external forces, the product of the cross-sectional area and the flow velocity is constant. Here, we make the assumption that the river is in a stable state and that no outside factors are changing its flow.
When the channel depth (D) decreases to 1 ft, but the width (W) stays the same at 10 ft, the cross-sectional area (W × D') of the river decreases. However, the flow velocity (V') increases to 9 ft/sec.
As a result, if the continuity principle is valid, the decline in channel depth is balanced by the rise in flow velocity. This indicates that depending on the precise values of breadth, depth, and velocity, the new discharge (Q') may either stay nearly the same or perhaps significantly rise.
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The most common type of pressure gauge is the 1. Piston 2. Linkage 3. Bourdon Tube 4. 5. Temperature
Answer:
Bourdon Tube gauge
Explanation:
The most popular type of pressure gauge in several countries is the Bourdon pressure tube gauge, that is used to determine medium and high loads. Bourdon tube will measure pressures ranging between 600 mbar - 4,000 bar. While the inner pressure is greater than the exterior pressure, the tube pushes forward, and vise versa.
Matlab Assignment BME496
Consider the filtration of a fluid flowing within a Hollow Fiber Module which consist of 1000 fibers. Assume that the length of the hollow fiber is 20 cm and that the radius of the hollow fiber is 0.005 cm. if the filtration flux is 0.5 cm/s and the feed to the Module is 500 cm3/s. Use MATLAB to do the following:
Plot the Flow rate in each fiber as a function of Z (i.e F(z))
If the concentration of a solute in the feed is 6 g/L. Knowing that the sieving coefficient (So) is 0.4. Plot the concentration of the solute in the fiber (in g/L) as a function of z (i.e Cb(z))
If the concentration of a solute in the feed is 6 g/L. Knowing that the sieving coefficient (So) is 0.4. Plot the concentration of the solute in the fiber (in g/L) as a function of z (i.e Cb(z)) if length of the hollow fiber is 10 cm
If the concentration of a solute in the feed is 6 g/L. Knowing that the sieving coefficient (So) is 0.4. Plot the concentration of the solute in the fiber (in g/L) as a function of z (i.e Cb(z)) if the radius of the hollow fiber is 0.01 cm
The submitted file must be in a pdf format and must include:
Cover page: Student(s) names and Student(s) numbers.
Matlab Code
Matlab plots: the plots must have all details such as: axes names, unit, legends….ext.
Discussion of the obtained results in your own words
Given information: Length of the hollow fiber, \(L = 20\)cm Radius of the hollow fiber,\(r = 0.005\) cm Filtration flux,\(J = 0.5\) cm/s Feed to the module, \(Q = 500 cm3/s\) Concentration of a solute in the feed, \(C = 6\)g/L Sieving coefficient, So = 0.4
Therefore, the concentration of the solute in the fiber can be found using the formula, \(C b(z) = C*(1-So)*exp(-z^2/(4*L*J))*exp(r^2/R^2-z^2/(4*L*J))C b(z) = C*(1-So)*exp(-z^2/(4*L*J))*exp(1^2/0.01^2-z^2/(4*L*J))Plot of C b(z) for r = 0.01\)cm will be, The MATLAB code for the above can be written as: c lc; clear all; close all;%Given Data\(L = 20; %cm r = 0.005; %cm J = 0.5; %cm/s Q = 500; %cm^3/s C = 6; %g/L So = 0.4;%Flow Rate F = (Q./(pi*r^2)).*exp(-(z.^2)./(4.*L.*J))\)
figure(1)plot(z,F,'LineWidth',2);x label('z (cm)')y label('Flow Rate (cm^3/s)')title('Flow Rate in each fiber')grid on% Concentration of the solute in the fiber (in g/L) as a function of z C b = C.*(1-S_o).*exp(-(z.^2)./(4.*L.*J));figure(2)plot(z,Cb,'LineWidth',2);x label('z (cm)')y label('C b (g/L)')title('Concentration of the solute in the fiber')grid on% C b(z)
For Discussion From the obtained plots, it can be observed that the flow rate in each fiber is maximum at the inlet of the module and it decreases gradually as the fluid passes through the fibers.
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A driver is traveling at 90 km/h down a 3% grade on good, wet pavement. An accident
investigation team noted that braking skid marks started 75m before a parked car was
hit at an estimated 45 km/h. Ignoring air resistance, calculate the theoretical friction
coefficient.
Answer:
0.35
Explanation:
We resolve the component of the weight of the car along and perpendicular to the grade. We have mgsinФ and mgcosФ where Ф = angle of grade.
Now, the frictional force f = μN = μmgcosФ where μ = coefficient of friction
So, the net force along the grade is F = mgsinФ - μmgcosФ.
The work done by this force moving a distance, d along the grade is
W = (mgsinФ - μmgcosФ)d
This work equals the change in kinetic energy of the car. So ΔK = 1/2m(v₂² - v₁²) = W = (mgsinФ - μmgcosФ)d
1/2m(v₂² - v₁²) = (mgsinФ - μmgcosФ)d
1/2(v₂² - v₁²) = (gsinФ - μgcosФ)d
(v₂² - v₁²)/2d = (gsinФ - μgcosФ)
dividing through by gcosФ, we have
(v₂² - v₁²)/2dgcosФ = (gsinФ/gcosФ) - μgcosФ/gcosФ
(v₂² - v₁²)/2dgcosФ = tanФ - μ
μ = tanФ - (v₂² - v₁²)/2dgcosФ
given that tanФ = 3% = 3/100 and 1 + tan²Ф = 1/cos²Ф, cosФ = 1/(√1 + tan²Ф) = 1/(√1 + (3/100)²) = 1/(√1 + (9/10000)) = 1/(√10000 + 9/10000) = 1/√(10009/10000) = 100/√10009 = 100/100.05 = 0.9995.
Also, given that v₁ = 90 km/h = 90 × 1000/3600 m/s = 25 m/s and v₂ = 45 km/h = 45 × 1000/3600 m/s = 12.5 m/s, d = 75 m and g = 9.8 m/s².
So, substituting the values of the variables into the equation, we have
μ = tanФ - (v₂² - v₁²)/2dgcosФ
μ = 3/100 - ((12.5 m/s)² - (25 m/s)²)/(2 × 75 m × 9.8 m/s² × 0.9995)
μ = 3/100 - ((156.25 m/s)² - (625 m/s)²)/1,469.265 m²/s²
μ = 3/100 - (-468.75 m²/s²)/1,469.265 m²/s²
μ = 3/100 + 468.75 m²/s²/1,469.265 m²/s²
μ = 0.03 + 0.32
μ = 0.35
So, theoretical friction coefficient is 0.35
what is the difference between zinc and galvanized zinc
Answer:
Both zinc plating and galvanizing is an application of zinc plating. The big difference is thickness: zinc plating is normally 0.2 mils thick. Hot dip galvanizing might be 1.0 mil thick – you get over 5 times the protection with galvanizing. ... After 20 years outdoors a galvanized product will not show signs of rust.
Explanation:
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Which term is defined as an interrelated and harmonized collection of components and methods that transform inputs into outputs?
A. Value chain
B. Critical path
C. Inventory control
D. Supply chain
E. System
Answer: D. Supply chain
Explanation:
A combination of physical fitness, skills, habits, attitude, emotional fitness, knowledge, and mental fitness make up the
a)
The Arch of Driver Safety
b)
The Arch of New Drivers
c)
The Arch of Safe Drivers
The combination of physical fitness, skills, habits, attitude, emotional fitness, knowledge, and mental fitness make up the Arch of Safe Drivers.
Correct answer is c) The Arch of Safe Drivers.
Safe driving requires more than just being physically able to operate a vehicle. It involves having a variety of skills, such as being able to navigate traffic, obey traffic laws, and react to unexpected situations. Good driving habits, such as avoiding distractions and not driving under the influence, are also important for staying safe on the road. Attitude plays a big role in safe driving as well, as drivers with a positive attitude are more likely to stay calm and focused behind the wheel. Emotional fitness is also important, as being able to manage stress and other emotions while driving can help prevent accidents. Knowledge of traffic laws and safe driving techniques is also crucial for safe driving.
This concept highlights the importance of these factors in ensuring that drivers are well-equipped to maintain safety on the roads. Finally, mental fitness, such as being able to concentrate and make quick decisions, is also important for safe driving. All of these factors combined make up the Arch of Safe Drivers.
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An adiabatic pump is to be used to compress saturated liquid water at 10 kPa to a pressure of 15 MPa in a reversible manner. 15 MPa P Pump Determine the work input using entropy data from the compressed liquid table. Use steam tables. (You must provide an answer before moving on to the next part.) The work input is kJ/kg. Determine the work input using inlet specific volume and pressure values. (You must provide an answer before moving on to the next part.) The work input is kJ/kg Determine the work input using average specific volume and pressure values. answer before moving on to the next part.) The work input is kJ/kg. Calculate the errors involved in parts b and c. The error involved in part b is 1% The error involved in part cis 1%.
To determine the work input using entropy data from the compressed liquid table, we need to find the specific entropy of water at 10 kPa and 15 MPa, then calculate the change in entropy during the compression process.
From the compressed liquid table, we can find that the specific entropy of saturated liquid water at 10 kPa is 0.2888 kJ/kg-K. At 15 MPa, the specific entropy of saturated liquid water is 1.2960 kJ/kg-K.
The change in entropy during the compression process is ΔS = S2 - S1 = 1.2960 - 0.2888 = 1.0072 kJ/kg-K.
Using the definition of adiabatic work as dW = -TdS, where T is the temperature and dS is the change in entropy, we can calculate the work input per unit mass as:
dW = -TΔS
To find the temperature at each state, we can use the saturated liquid table again. At 10 kPa, the saturation temperature is 10.01°C, and at 15 MPa, the saturation temperature is 198.4°C.
Using these temperatures and the change in entropy calculated above, we get:
dW = - (198.4 + 273.15) * 1.0072 = -478.5 kJ/kg
Therefore, the work input using entropy data from the compressed liquid table is -478.5 kJ/kg.
To determine the work input using inlet specific volume and pressure values, we can use the equation for reversible adiabatic work:
dW = v(P2 - P1)
where v is the specific volume and P1 and P2 are the initial and final pressures, respectively.
Using the saturated liquid table, we find the specific volume of saturated liquid water at 10 kPa is 0.001043 m³/kg. At 15 MPa, we can use the compressed liquid table to find that the specific volume of saturated liquid water is approximately 0.001066 m³/kg.
Using these values in the equation above, we get:
dW = 0.001043 * (15 - 0.01) * 10⁶ = 154.7 kJ/kg
Therefore, the work input using inlet specific volume and pressure values is 154.7 kJ/kg.
To determine the work input using average specific volume and pressure values, we can use the average pressure and specific volume during the compression process:
Pavg = (P1 + P2) / 2 = (0.01 + 15) / 2 = 7.505 MPa
vavg = (v1 + v2) / 2 = (0.001043 + 0.001066) / 2 = 0.001055 m³/kg
Using these values, we can calculate the work input as:
dW = vavg * (P2 - P1)
dW = 0.001055 * (15 - 0.01) * 10⁶ = 155.7 kJ/kg
Therefore, the work input using average specific volume and pressure values is 155.7 kJ/kg.
To calculate the errors involved in parts b and c, we can use the formula:
error = |(actual value - approximate value) / actual value| * 100%
For part b, the actual value is -478.5 kJ/kg and the approximate value is 154.7 kJ/kg. Plugging in these values, we get:
error = |(-478.5 - 154.7) / -478.5| * 100% = 132.6%
Therefore, the error involved in part b is 132.6%.
For part c, the actual value is -478.5 kJ/kg and the approximate value is 155.7 kJ/kg. Plugging in these values, we get:
error = |(-478.5 - 155.7) / -478.5| * 100% = 132.5%
Therefore, the error involved in part c is 132.5%.
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Using a roof calculator or rafter length guidebook, calculate the theoretical length of the common rafters for a gable roof on a building which is 12’ wide by 36’ long, with a slope of 5/12.
Answer:
35 feet
Explanation:
Write a program to play the Card Guessing Game. Your program must give the user the following choices: - Guess only the face value of the card. - Guess only the suit of the card. - Guess both the face value and the suit of the card. Before the start of the game, create a deck of cards. Before each guess, use the function random_shuffle to randomly shuffle the deck.
how am I going to do this, I have a friend that might be able to help I will check
a load of 12tonnes is put along a horizontal plane by a force at 30°to and above the flat. if the coefficient of sliding friction is 0.2 find the frictional force
Answer:
20368.917N
Explanation:
Frictional force (F) is the product of the Coefficient of friction and the normal reaction.
F = μN
Coefficient of friction, μ = 0.2
Normal reaction = MgCosθ
Mass, m = 12 tonnes = 12 * 1000 = 12000 kg
N = 12000 * 9.8 * cos30
N = 101844.58
F = 0.2 * 101844.58
F = 20368.917N