Identify, critically analyse and communicate the potential technical problems in the industrial communication system to the stake holders.

Answer:

control loop unit

Explanation:

Edmentum/Plato

oooExplanation:

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Since the Richter scale is a base-10 logarithmic scale, each order of magnitude is 10 times more intense than the one before it. If disasters are compared on an order of magnitude scale, a catastrophe of magnitude 7 is larger than a catastrophe of magnitude 4.

The American tragedy of September 11, 2001, the earthquake and tsunami in Banda Aceh, the recent dreadful earthquakes in Haiti and Chile, and the immense, devastation-causing flooding in Pakistan and other parts of the world are just a few examples of recent catastrophic tragedies. 46 words that sound like catastrophic are listed on this page, including calamitous, cataclysmic, disastrous, fatal, destructive, and tragic. The potential for abrupt change and catastrophe exists in both natural and man-made events. The Earth uses a variety of calamities to keep things in balance as it changes. Something cataclysmic is a component of or the result of an unexpectedly horrific occurrence. The earthquake caused a tidal wave that hit the coast and caused extensive damage.

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Answer:

Explanation:

The process that Piaget called "adding another example to an existing scheme" is called assimilation. Assimilation refers to the cognitive process of incorporating new information or experiences into existing mental schemas or frameworks. In this case, Tammy assimilates the new example of a golf ball into her existing "ball" scheme, expanding her understanding of what falls under the category of a ball.

Both Tech A and Tech B are partially correct, as both the thickness of the head gasket and the valve timing can impact the effective compression ratio, but in different ways.

Tech A is correct in stating that using a thicker head gasket would lower the compression ratio. The head gasket sits between the engine block and cylinder head, and its thickness affects the volume of the combustion chamber when the piston is at top dead center. A thicker head gasket increases the volume of the combustion chamber, reducing the compression ratio.

Tech B is also correct in stating that the effective compression ratio is affected by valve timing. The opening and closing of the intake and exhaust valves can influence the effective compression ratio. For example, if the intake valve closes earlier, it reduces the amount of air-fuel mixture entering the combustion chamber, effectively reducing the compression ratio.

In summary, both Tech A and Tech B have identified factors that can impact the effective compression ratio, but they are independent of each other.

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Answer:

i would say C

Explanation:

Answer:

c

Explanation:

ye

Answer:

If the vehicle is accelerating from 20 mph using 100 kW of power, then:

- The motor is providing 60 kW of power to the vehicle.

- The generator is providing 30 kW of power to the vehicle.

- The engine is providing 10 kW of power to the generator, so the total power output of the engine is 70 kW, but only 30 kW of that is going directly to the vehicle.

During acceleration from 20 mph using 100 kW of power, the power output of the motor is 60 kW, the power output of the generator is 30 kW, and the power output of the engine is 70 kW.

The total power output during acceleration is given as 100 kW.

The power output of the motor is 60 kW, which means that the motor is providing 60% of the total power.

The power output of the generator is 30 kW, which means that the generator is providing 30% of the total power.

The power output of the engine is 70 kW, which means that the engine is providing 70% of the total power.

Therefore, the sum of the power outputs of the motor, generator, and engine is 60 kW + 30 kW + 70 kW = 160 kW, which is 60 kW more than the total power input of 100 kW.

This extra power output is due to the energy stored in the vehicle's kinetic energy during acceleration.

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The goal of Boeing, Inc is to determine whether an existing machine can mill an engine part that has a design specification of 5.0mm +- 0.10 mm. The process has a standard deviation of σ = 0.02 mm.

Given that the standard deviation of the process is σ = 0.02 mm. Now, we need to determine if the existing machine can produce a part that meets the design specification using the given standard deviation (σ).The tolerance limit (T.L) can be calculated as;

T.L = (Upper Limit – Lower Limit) / 2 where;

Upper Limit = 5.0 + 0.10 = 5.10 mm

Lower Limit = 5.0 – 0.10 = 4.90 mm

T.L = (5.10 – 4.90) / 2 = 0.10 / 2 = 0.05 mm

The value of T.L = 0.05 mm

The process standard deviation (σ) = 0.02 mm

Using the formula;

P = 0.6827, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10)

With a process standard deviation of σ = 0.02 mm and a tolerance limit of 0.05 mm, approximately 68.27% of the parts produced by the existing machine fall within the tolerance limit (5.0 ± 0.10). It can, therefore, be concluded that the existing machine can produce parts that meet the design specification.

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Here is the answer to your question. The enthalpy change(ΔH) for converting 10.0 g of ice at 0°C to water at 0°C is calculated as follows:

1) The enthalpy of fusion(ΔHf) of ice is known to be 6.01 kJ/mol at 0°C.

2) The molar mass(MM) of water is 18.015 g/mol.

3) The heat required(Q) to convert 1 mol of ice to water at 0°C is equal to the enthalpy of fusion multiplied by the molar mass of water, as well as the number of moles of ice that is present in 10.0 g of ice. Therefore: Q = ΔHf × n × MM , where Q = heat needed, ΔHf = enthalpy of fusion, n = number of moles of ice, and MM = molar mass of water.

4) The number of moles(n) of ice that is present in 10.0 g of ice can be calculated as follows: n = m / M , where n = number of moles of ice, m = mass of ice, and M = molar mass of water.

5) After calculating the value of n, the heat required to convert 10.0 g of ice to water at 0°C can be calculated using the equation: Q = ΔHf × n × MM , where Q = heat needed, ΔHf = enthalpy of fusion, n = number of moles of ice, and MM = molar mass of water.

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Answer:

Isn't the answer written upside down in the sentence?

Explanation:

The reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor

Usually at no load, the Cosine of the phase angle between the stator current(I1) and the stator applied voltage(V1) is the power factor of an induction motor.

In conclusion, the reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor

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Answer Digital measuring instruments are self-contained devices that automatically present the value of the measured quantity on a digital display. And Decimal Scaled Instruments: Record all digits that you can certainly determine from the scale markings and estimate one more digit. I hope this Helped I´m new to this.

Explanation:

Answer:a

Ieieksdjd snsnsnsnsksks

Answer:

my friend here justin

Explanation:

hes already taken

75743366

Explanation:

To change the timbre of a square wave produced by a voltage-controlled oscillator in a subtractive, modular synthesizer, there are several techniques you can use.

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Part 1: The types of metallic crystal structures are as follows: FCC (Face-centered cubic) structure.

BCC (Body-centered cubic) structure

SC (Simple cubic) structure

HCP (Hexagonal close-packed) structure

APF (Atomic Packing Factor) is the fraction of space occupied by the atoms in a unit cell. APF can be calculated by: APF = (Volume of atoms in the unit cell) / (Volume of the unit cell)

The higher the APF, the more closely packed the atoms are. The APF values for the above crystal structures are: FCC = 0.74BCC = 0.68SC = 0.52HCP = 0.74, 0.68

Part 2: Here's the pure elemental metal with each of the crystal structures listed in Part 1: FCC structure: Aluminum (Al)BCC structure: Tungsten (W)SC structure: Polonium (Po)HCP structure: Magnesium (Mg)The metallic elements have different crystal structures despite having more efficient packing for several reasons. Metallic elements exhibit different crystal structures because of their distinct atomic radius, which affects how closely the atoms can pack together. When atoms in the crystal lattice can be packed closely together, the crystal will have a more efficient packing. However, if the atom is too large or small, it can't pack as tightly as in a smaller or larger atom. This is why some metallic elements exhibit more efficient packing than others even though they have distinct crystal structures.

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A gravitational force of 4.93 10-12 N in the positive x-direction is applied by the copper sphere to the steel sphere.

Along the line connecting the centres of the two objects, the force is applied. Coulomb's law has an undesirable effect if the two charges have opposing signs. This indicates that there is an attractive force acting on the particles.

\(F = G * m1 * m2 / r^2\)

\(m = rho * (4/3) * pi * r^3\)

r = 65 mm = 0.065 m

a = 3.7r = 0.241 m

b = 2.1r = 0.137 m

c = 0.6r = 0.039 m

m_copper = rho_copper \(* (4/3) * pi * r^3\)

\(= 8,960 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0138 kg

m_steel = rho_steel \(* (4/3) * pi * r^3\)

= \(7,860 kg/m^3 * (4/3) * pi * (0.065 m)^3\)

= 0.0119 kg

F = G  m_copper  m_steel / \(r^2\)

= \(6.674 × 10^-11 N·(m/kg)^2 * 0.0138 kg * 0.0119 kg / (0.065 m)^2\)

\(= 4.74 × 10^-11 N\)

u = (0.241 - 0.137)i + 0j + 0k

= 0.104i + 0j + 0k

So the gravitational force F can be expressed as:

\(= 4.74 × 10^-11 N\)

\(= 4.74 × 10^-11 N\)

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Answer:

The National Electrical Code (NEC) primarily protects building occupants and the electrical system installation.

Answer: B the first person to propose the heliocentric model of the solar system was Nicolaus Copernicus

Explanation:

Answer:

1.933 KN-M

Explanation:

Determine the largest permissible bending moment when the composite bar is bent  horizontally

Given data :

modulus of elasticity of steel = 200 GPa

modulus of elasticity of aluminum = 75 GPa

Allowable stress for steel = 220 MPa

Allowable stress for Aluminum = 100 MPa

a = 10 mm

First step

determine moment of resistance when steel reaches its max permissible stress

next : determine moment of resistance when Aluminum reaches its max permissible stress

Finally Largest permissible bending moment of the composite Bar = 1.933 KN-M

attached below is a detailed solution

The amount by which the counter variable is incremented in a for loop is known as the incremental value. Option A is the correct answer.

In programming, a for loop is a control flow statement that allows a certain block of code to be repeated a specific number of times. One of the key components of a for loop is the incremental value, which determines how much the counter variable will be incremented with each iteration of the loop. This value is typically specified as part of the loop's initialization statement and can be a positive or negative integer or a floating-point value. The incremental value can also be used to skip over certain values or to reverse the direction of the loop.

Option A is the correct answer.

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The correct option for the variation of shear stress in a circular shaft subjected to a torque is option B, i.e., it varies linearly along the radius.
When a circular shaft is subjected to a torque, shear stress is developed due to the twisting action. The shear stress varies along the radial direction from the center to the outermost radius. The variation of shear stress can be determined by using the formula τ = T*r/J, where τ is the shear stress, T is the torque applied, r is the radial distance from the center, and J is the polar moment of inertia of the shaft.
From the formula, it is evident that shear stress is directly proportional to the radial distance from the center. Hence, the shear stress varies linearly along the radius. This means that the shear stress at any point on the cross-section of the shaft is proportional to its distance from the center and is maximum at the outermost radius.
Option A is incorrect as the shear stress varies along the radial direction. Option C is also incorrect as the shear stress is not zero at the center but is maximum at the center. Option D is also incorrect as the shear stress is maximum at the outermost radius and not at the center.
To sum up, the shear stress developed in a circular shaft subjected to a torque varies linearly along the radius. This means that the shear stress at any point on the cross-section of the shaft is proportional to its distance from the center and is maximum at the outermost radius.

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Answer:

Used to recall the direction a standard screw

Answer:

a) the tubular resistance of the blood vessel is 6.88 Gpa.s/m³.

b) the flow rate is 5.8 ml/min

Explanation:

Given the data in the question;

Length of blood vessel L = 1 m

radius r = 1 mm = 0.001 m

blood viscosity μ = 2.7 × 10⁻³ pa.s = 2.7 × 10⁻³ × 10⁻⁹ Gpa.s = 2.7 × 10⁻¹² Gpa.s

Now, we know that Resistance = 8μL / πr⁴

so we substitute

Resistance = [8 × (2.7 × 10⁻¹²) × 1] / [π(0.001)⁴]

Resistance = [2.16 × 10⁻¹¹] / [3.14159 × 10⁻¹²]

Resistance = 6.8755 ≈ 6.88 Gpa.s/m³

Therefore, the tubular resistance of the blood vessel is 6.88 Gpa.s/m³.

b)

blood pressure at the inlet of the vessel = 43 mm Hg

blood pressure at the outlet of the vessel = 38 mm Hg

flow rate = ?

we know that;

flow rate Q = ΔP / R

where ΔP is change in pressure and R is resistance.

ΔP = Inlet pressure - Outlet pressure = 43 - 38 = 5 mm Hg =  665 pa

R = 6.8755 Gpa.s/m³ = { 6.8755 × 10⁹ / 60 × 10⁶ } = 114.5916 pa.min.ml⁻¹

so we substitute

Q =  665 pa / 114.5916 pa.m.ml⁻¹

Q = 5.8 ml/min

Therefore, the flow rate is 5.8 ml/min

Answer:

b

Explanation:

Answer:

Explanation:

myth