identify is this is percent increase or percent decrease, then calculate percentage


Last year the Chess club had 30 members. This year the club has 24 members.


Please help asap

Answer:

\(x-8y=-24\)

Step-by-step explanation:

Standard form of a linear equation:  \(Ax+By=C\)

(where A, B and C are integers, and A shouldn't be negative)

Given equation:

\(y=\dfrac{1}{8}x+3\)

Multiply both sides by 8:

\(\implies 8 \cdot y=8 \cdot \dfrac{1}{8}x+8 \cdot 3\)

\(\implies 8y=x+24\)

Subtract 8y from both sides:

\(\implies 8y-8y=x+24-8y\)

\(\implies 0=x+24-8y\)

Subtract 24 from both sides:

\(\implies 0-24=x+24-8y-24\)

\(\implies -24=x-8y\)

In standard form:

\(\implies x-8y=-24\)

25/100

Step-by-step explanation:

if he has a fraction of a bar graph it is 25% if that grah so in other words 25% as a fraction is 25/100

Answer:

AC

Step-by-step explanation:

The total cost function considers the costs of labor and capital, the supply function determines the quantity supplied based on the production function, the profit function calculates the difference between revenue and cost, and the demand function for capital reflects the equilibrium between the marginal product of capital and the rental rate.

a. The total cost function (C) for this firm can be calculated by multiplying the cost of labor (w) with the number of hours of labor (L) and adding it to the cost of capital (r) multiplied by the quantity of capital (K).

So, C = wL + rK.

b. The supply function (MC) for assembled calculators [q(P,v)] can be found by taking the derivative of the production function with respect to q. In this case, MC = ∂q/∂k * ∂k/∂P.

To find q, you will need to substitute the given value of P and v into the production function.

c. The profit function (π) for this firm, stated as a function of the parameters "P" and "v", can be calculated by subtracting the total cost (C) from the revenue (P*q).

So, π = P*q - C.

d. The demand function for capital (k) can be obtained by equating the marginal product of capital (∂q/∂k) to the rental rate (v).

Solve for k to find the demand function for k.

e. The above functions (C, MC, π, k) have the form they do because they are derived from economic principles such as cost minimization, profit maximization, and the marginal productivity of inputs.

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Answer:

i think its X=108

Step-by-step explanation:

Answer:

x=118°

Step-by-step explanation:

a straight line is 180°

therefore 180-62=x

The theoretical probability is given by 1 over the number of hobbies.

If there is a total of 8 hobbies, the probability of a student having a specific hobby is:

The experimental probability is given by the number of students with that hobby over the total number of students. If 3 students have the hobby roller skating among the 24 students surveyed, the probability is:

The coefficient a of the term in the expansion of the binomial is 4455.

                         \((a+b)^n= \sum_{r=0} ^n ^nC_r a^{n-r}b^r\), where n is a positive integer, a, b, and 0,  r < n are all real integers.

(3x - y)¹¹

here

n = 11

r = 8

a = 3x

b = -y

coefficient  of the term \(x^3y^8\).

\(\implies\) \(^nC_r a^{n-r}b^r\)

\(\implies\) \(^{11}C_8\ (3x)^{3}(-y)^8\)

\(_{11} C_8=\frac{11!}{8 ! (3) !}\) = 165

\(\implies\) \(165\times 27(x)^{3}(y)^8\)

\(\implies 4455 \ x^3\ y^8\)

the coefficient a of the term in the expansion of the binomial is 4455.

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The approximate value of the fifteenth term is 244.141 or it can also be written as 244 1/8.

The seventh term of a geometric sequence is 5 and the tenth term is 16.875. The given information shows that a=5 and a10=16.875.

We have to find a15. Since the sequence is geometric, therefore the common ratio (r) can be determined from this information as below; a10 = ar9 16.875 = 5r9 r = (16.875)/5r9 r = 1.25On substituting the values of a, r and n in the nth term formula of a geometric sequence,

we can determine the value of a15 as below; an = arn-1 a15 = 5 × (1.25)14 a15 = 244.140625So, the fifteenth term of the sequence is 244.140625 (approximately).

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Answer:

(3) An amusement park allows 50 people to enter every 30 minutes.

Step-by-step explanation:

I hope it helped because it helped me so much.

The formula for the area of ​​a triangle is (1/4)√(105a?)

By applying the triangle inequality theorem, we can verify that the given formula represents the length of the sides of a triangle. This theorem states that the sum of his two sides of a triangle must be greater than his third side.

Given the expressions 2a?, 6a + 5, and 10a?, applicable

2a? + 6a + 5 > 10a? (sum of first two pages greater than third)

2a?+10a?> 6a+5 (1st and his 3rd sides sum greater than 2nd)

6a + 5 + 10a? >2a? (sum of last 2 pages greater than first page)

Therefore, the given formula can express the length of the sides of a triangle.

According to Heron's formula, the area of ​​a triangle with side lengths a, b, and c is

Area = √(s(s-a)(s-b)(s-c))

where s is the semicircle of the triangle and is defined as

s = (a + b + c) / 2

Replacing the given formula with a, b, c, we get:

s = (2a? + 6a + 5 + 10a?) / 2

= 6a? + 3a + 5/2

Find the value of s to calculate the area of ​​the triangle.

Area = √((6a? + 3a + 5/2)((6a? + 3a + 5/2)-(2a? + 6a + 5))((6a? + 3a + 5/2)-(10a?)))

= √((6a? + 3a + 5/2)(2a? - 3a + 5/2)(-4a? + 3a + 5/2))

= √((15/4)(a?)(-5/4)(-a?)(-7/4)(a?))

= √(105a?/16)

= (1/4)√(105a?)

So the formula for the area of ​​a triangle is (1/4)√(105a?). 

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Answer:

Tn = 3n + 1

Step-by-step explanation:

The given sequence 2,5,8,11,14 is an arithmetic sequence

The nth term of an arithmetic sequence is expressed as;

Tn = a + (n-1)d

a is the first term

d is the common difference

n is the number of terms

Given

a = 2

d = 5-2 = 8-5 = 3

Substitute into the formula

Tn = 2 + (n-1) * 3

Tn = 2 + 3n - 3

Tn = 3n + 1

This gives the term rule for the sequence  

The range of time values describes the entire interval over which Georgiana would be interpolating is 0 to 30 minutes.

What is the domain and range of a function?

The domain of a function is the set of x values for which it is defined, whereas the range is the set of y values for which it is defined.

As in the table, the minimum time for which the distance is defined is 0 minutes while the maximum time is 30 minutes. Therefore, the range of time values describes the entire interval over which Georgiana would be interpolating is 0 to 30 minutes.

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Answer:

C

Step-by-step explanation:

To eliminate the roots in 1.1 and 1.2, we can use trigonometric substitution. In 1.1, we can substitute x = 4 sin(theta) to eliminate the root of 4. In 1.2, we can substitute z = 7 sin(theta) to eliminate the root of 7.

1.1. V64+2 + 1 We can substitute x = 4 sin(theta) to eliminate the root of 4. This gives us:

V64+2 + 1 = V(16 sin^2(theta) + 2 + 1) = V16 sin^2(theta) + V3 = 4 sin(theta) V3 1.2. V4z2 – 49

We can substitute z = 7 sin(theta) to eliminate the root of 7. This gives us:

V4z2 – 49 = V4(7 sin^2(theta)) – 49 = V28 sin^2(theta) – 49 = 7 sin(theta) V4 – 7 = 7 sin(theta) (2 – 1) = 7 sin(theta)

Here is a more detailed explanation of the substitution:

In 1.1, we know that the root of 4 is 2. We can substitute x = 4 sin(theta) to eliminate this root. This is because sin(theta) can take on any value between -1 and 1, including 2.

When we substitute x = 4 sin(theta), the expression becomes V64+2 + 1 = V(16 sin^2(theta) + 2 + 1) = V16 sin^2(theta) + V3 = 4 sin(theta) V3

In 1.2, we know that the root of 7 is 7/4. We can substitute z = 7 sin(theta) to eliminate this root. This is because sin(theta) can take on any value between -1 and 1, including 7/4.

When we substitute z = 7 sin(theta), the expression becomes: V4z2 – 49 = V4(7 sin^2(theta)) – 49 = V28 sin^2(theta) – 49 = 7 sin(theta) V4 – 7 = 7 sin(theta)

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These solutions are not in the interval [0, 2π), so the only solutions are: θ = 0.7227, 5.5599

We can use the addition formula for cosine and sine:

cos(θ) cos(2θ) + sin(θ) sin(2θ)

= cos(θ)(cos²θ - sin²θ) + sin(θ)(2sinθ cosθ)

= cos³θ + cosθ sin²θ + 2sin²θ cosθ

Using the identity cos²θ + sin²θ = 1, we can substitute sin²θ = 1 - cos²θ:

cos³θ + cosθ(1 - cos²θ) + 2(1 - cos²θ) cosθ  = 3cosθ - 4cos³θ

So the equation simplifies to:
3cosθ - 4cos³θ = 3/2

We can then rearrange and factor:

4cos³θ - 3cosθ + 3/2 = 0
(4cosθ - 3)(2cos²θ + 2cosθ - 1) = 0

The first factor gives us the solution:
cosθ = 3/4

Using the inverse cosine function, we get:
θ = ±0.7227, 2π - 0.7227

To check the second factor for solutions, we can use the quadratic formula:
cosθ = (-1 ± √3)/2

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The Taylor polynomial of degree 4 for g(x) = x^2 ln x about the center a = 1 is (x - 1) + (3/2)(x - 1)^2 + (1/3)(x - 1)^3 - (1/6)(x - 1)^4.

To find the Taylor polynomial of degree 4 for the function g(x) = x^2 ln x about the center a = 1, we first need to find the first four derivatives of g(x):

g(x) = x^2 ln x

g'(x) = 2x ln x + x

g''(x) = 2ln x + 3

g'''(x) = 2/x

g''''(x) = -4/x^3

Next, we evaluate these derivatives at x = 1 to find the coefficients of the Taylor polynomial:

g(1) = 1^2 ln 1 = 0

g'(1) = 2(1) ln 1 + 1 = 1

g''(1) = 2ln 1 + 3 = 3

g'''(1) = 2/1 = 2

g''''(1) = -4/1^3 = -4

Using these coefficients, we can write the Taylor polynomial of degree 4 for g(x) about a = 1:

P4(x) = g(1) + g'(1)(x - 1) + (g''(1)/2!)(x - 1)^2 + (g'''(1)/3!)(x - 1)^3 + (g''''(1)/4!)(x - 1)^4

P4(x) = 0 + 1(x - 1) + (3/2)(x - 1)^2 + (2/6)(x - 1)^3 - (4/24)(x - 1)^4

Simplifying and combining like terms, we get:

P4(x) = (x - 1) + (3/2)(x - 1)^2 + (1/3)(x - 1)^3 - (1/6)(x - 1)^4

Therefore, the Taylor polynomial of degree 4 for g(x) = x^2 ln x about the center a = 1 is (x - 1) + (3/2)(x - 1)^2 + (1/3)(x - 1)^3 - (1/6)(x - 1)^4.

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Answer: the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

Step-by-step explanation:

Let's assume the price of one senior citizen ticket is 's' dollars and the price of one student ticket is 't' dollars.

According to the given information, on the first day, the school sold 7 senior citizen tickets and 11 student tickets, totaling $125. This can be expressed as the equation:

7s + 11t = 125 ---(1)

On the second day, the school sold 14 senior citizen tickets and 8 student tickets, totaling $180. This can be expressed as the equation:

14s + 8t = 180 ---(2)

We now have a system of two equations with two variables. We can solve this system to find the values of 's' and 't'.

Multiplying equation (1) by 8 and equation (2) by 11, we get:

56s + 88t = 1000 ---(3)

154s + 88t = 1980 ---(4)

Subtracting equation (3) from equation (4) eliminates 't':

(154s + 88t) - (56s + 88t) = 1980 - 1000

98s = 980

s = 980 / 98

s = 10

Substituting the value of 's' back into equation (1), we can solve for 't':

7s + 11t = 125

7(10) + 11t = 125

70 + 11t = 125

11t = 125 - 70

11t = 55

t = 55 / 11

t = 5

Therefore, the price of one senior citizen ticket is $10, and the price of one student ticket is $5.

Answer: 8.1

Step-by-step explanation:

The upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

To determine the upper and lower control limits for the sample means, we can use the formula:

Upper Control Limit (UCL) = Mean + (Z * Standard Deviation / sqrt(n))

Lower Control Limit (LCL) = Mean - (Z * Standard Deviation / sqrt(n))

In this case, we want to include roughly 95.5 percent of the sample means, which corresponds to a two-sided confidence level of 0.955. To find the appropriate Z-value for this confidence level, we can refer to the standard normal distribution table or use a calculator.

For a two-sided confidence level of 0.955, the Z-value is approximately 1.96.

Given:

Mean = 2.0 litres

Standard Deviation = 0.01 litres

Sample size (n) = 5

Using the formula, we can calculate the upper and lower control limits:

UCL = 2.0 + (1.96 * 0.01 / sqrt(5))

LCL = 2.0 - (1.96 * 0.01 / sqrt(5))

Calculating the values:

UCL ≈ 2.0018 litres

LCL ≈ 1.9982 litres

Therefore, the upper control limit (UCL) is approximately 2.0018 litres, and the lower control limit (LCL) is approximately 1.9982 litres, which would include roughly 95.5 percent of the sample means.

Now let's check if the process is in control using the given sample means:

Mean of the sample means = (2.005 + 2.001 + 1.998 + 2.002 + 1.995 + 1.999) / 6 ≈ 1.9997

Since the mean of the sample means falls within the control limits (between UCL and LCL), we can conclude that the process is in control.

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1) The rule of transformation is described as; A: A rotation 90° clockwise about the origin

2) The value of x is; 2

3) The value of x is 10

4) The slope of the line is; 2

1) The rule of transformation for When the point M (h, k) is rotated through 90° clockwise about the origin, the point M (h, k) takes the image M' (k, -h). Thus, that is the rule here.

2) From the given image, we can tell that the angles 50° and 26x - 2 are corresponding angles. Thus, they are congruent and we have;

26x - 2 = 50

26x = 52

x = 2

3) From the given image, we can see that the given angles are supplementary and as such they add up to 180 degrees. Thus;

9x + 15 + 6x + 15 = 180

15x + 30 = 180

15x = 150

x = 10

4) Slope is;

m = (y2 - y1)/(x2 - x1)

m = (1 - (-3))/(1 - (-1))

m = 4/2

m = 2

5) Same question as the first one.

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Answer:

the answer is table d 12 =12+34=4

Step-by-step explanation:

Answerh

Step-by-step explanation:

huh

The time practiced in the 12 days is an illustration of proportions

The given parameters are:

Days = 12

Proportion = 3/4

So, the number of hours is:

Hours = Days * Proportion

This gives

Hours = 12 *3/4

Hours = 9

Hence, she practices a total of 9 hours in the 12 days

There are 60 minutes in an hour.

So, we have:

Minutes = 9 * 60

Minutes = 540

Hence, she practices a total of 540 minutes in the 12 days

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Answer:

(-1, 5), (2, -1), (0, 3)

The width of the new interval is about three times the width of the original interval. As the sample size decreases, the standard error of the estimate increases, resulting in a wider confidence interval. In fact, the width of a confidence interval is inversely proportional to the square root of the sample size.

The width of a confidence interval is affected by three factors: the sample size, the level of confidence, and the variability of the data. In this case, the sample size has decreased from 225 to 25, while the level of confidence and the variability of the data have remained constant.

As the sample size decreases, the standard error of the estimate increases, resulting in a wider confidence interval. In fact, the width of a confidence interval is inversely proportional to the square root of the sample size.

To be more specific, the formula for the width of a confidence interval for a population proportion is:

Width = 2 × zα/2 × SE

where zα/2 is the critical value of the standard normal distribution corresponding to the desired level of confidence, SE is the standard error of the estimate, and the factor of 2 is used to account for the two-sided nature of the interval.

Assuming a 95% level of confidence and a sample proportion of 0.5, the standard error of the estimate for the original sample size of 225 is:

SE = sqrt[(0.5 × 0.5) / 225] = 0.033

The critical value of zα/2 for a 95% level of confidence is approximately 1.96. Therefore, the width of the original confidence interval is:

Width = 2 × 1.96 × 0.033 = 0.13

For a new sample size of 25, the standard error of the estimate becomes:

SE = sqrt[(0.5 × 0.5) / 25] = 0.1

Using the same critical value of zα/2, the width of the new confidence interval is:

Width = 2 × 1.96 × 0.1 = 0.39

Therefore, the width of the new interval is about three times the width of the original interval.

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Answer:yes 3x2=6

Step-by-step explanation:

Answer:

No thus statement is not right...

Step-by-step explanation:

3×3=9

but multiples of 6 doesnt have a 9

hope this helped you

please mark as the brainliest (ㆁωㆁ)

Using Uniform distribution,

a) the mean of distribution is 75.25 and variance is 13.02.

b) the cdf of depth is (x - 7.5)/12.5 , 7.5<x<19 or 1 if X>19

A random variable X is said to have a continuous rectangular distribution over an interval (a, b), i.e.

(−∞<a<b<∞)

if its probability density function is given by,

F(x) = 1/(b-a) , a<x<b

Let the random variable X represents the depth of the bioturbation layer in sediment in a certain region. From the given information the random variable X is uniformly distributed on the interval [7.5, 19].

mean of the uniform distribution is,

μ=E(X)=(b+a)/2

Let the random variable X follows uniform distribution with parameters (a, b), then the variance of the uniform distribution is,

σ²=V(X)=(b−a)²/12

we have, a = 7.5 , b = 19

a) mean of the uniform distribution( μ) = 19 +(7.5)²

= 75.25

variance of the uniform distribution = (19-7.5)²/12

= (12.5)²/12 = 13.02

b) The cumulative distribution function of the random variable X is,

Fₓ(x) = P(X<x)

=> Fₓ(x) = ₇.₅∫ˣ f(x) dx

=> Fₓ(x) = ₇.₅∫ˣ(1/12.5)dx

=> Fₓ(x) = 1/12.5 ₇.₅[x]ˣ = 1/12.5(x - 7.5)

=>Fₓ(x) = (x - 7.5)/12.5

Therefore, the cumulative distribution function of the depth is,

Fₓ(x) = (x - 7.5)/12.5 , 7.5<x<19 or 1 if X>19 or zero if X<7.5

Hence, we get the mean of distribution is 75.5 and variance is 13.02.

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Answer:

|x − 10| = 0.15; x = 9.85 ounces

Step-by-step explanation:

its common math skills but yea.

Answer:|x − 10| = 0.15; x = 9.85 ounces

Step-by-step explanation:

Answer:

Nancy had 7 correct answers.

Step-by-step explanation:

To solve this problem, we can set up a system of equations.  Let's assign the variable c to represent the number of correct answers Nancy had and the variable i represent the number of incorrect answers she had.

We know that the total number of answers is 10 because it is given that she answered all 10 problems.  This lets us set up the first equation as follows:

c + i = 10

Then, we can set up a second equation using the number of points (29 total).  We know that +5 points were added for each correct response (c) and -2 points were added for each incorrect response (i).  Our next equation will look like this:

5c - 2i = 29

There are many different strategies one can use to solve systems of equations.  In this case, I am going to use combination.  This means I am going to add the two equations together.  However, first I should multiply our first equation by 2 so that the "I" variable terms cancel out.  This is modeled below:

2c + 2i = 20

Now we can add the two equations:

5c + 2c +2i - 2i = 20 +29

Now we can simplify the equation by combining the like terms to get:

7c = 49

Finally, we should divide both sides of the equation by 7 in order to get the variable c by itself on the left side of the equation.

c = 7

Therefore, the correct number of responses Nancy gave was 7.

Hope this helps!