Identify the compound with the lowest wavelength in an UV spectrum a) 1-decene b) 1,3-decadiene c) 1,3,5-decatriene d) 1,4-decadiene e) 1,3,5,7-decatetraene

The slope of the given line in the fig. is more than -1 , as clearly visible in the fig.

Making Use of the Slope Equation

Determine the coordinates of two points on the line.

Calculate the difference in y-coordinates between these two places (rise).

Determine the x-coordinate difference between these two places (run).

Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).

The slope formula is used to compute the inclination or steepness of a line. The slope of the lines is calculated using the x and y coordinates of the lines. It is the ratio of the y-axis change to the x-axis change.

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In what order does the light from a microscope pass through the lenses necessary to create a magnified, real image of a specimen is as follow:

The light from a microscope passes through the lenses in the following order to create a magnified, real image of a specimen.

1. Illuminator: The light source or the illuminator is the first lens through which light passes, to illuminate the object being observed.

2. Condenser lens: After passing through the illuminator, the light passes through the condenser lens which helps to focus the light onto the object.

3. Objective lens: The objective lens is the primary lens of a microscope, which is positioned near the specimen, and through which light passes and helps to magnify the image of the specimen.

4. Eyepiece lens: The eyepiece lens is the second lens in the system, through which light passes after leaving the objective lens. It further magnifies the image formed by the objective lens and helps to make the image visible to the viewer.

Therefore, the order of lenses through which light passes to create a magnified, real image of a specimen in a microscope is Illuminator, Condenser lens, Objective lens, and Eyepiece lens.

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The ratio of the tension Tt in the string when the ball is at the top of its path to Tb when the ball is at the bottom of its path is given by the expression TbTt = 1 - v²/gL. Therefore, the correct option is D.

When a ball of mass m is swung in a vertical circle with uniform speed, it follows a circular path with radius R, which is equal to the length of the string L. The gravitational force provides the centripetal force required to keep the ball moving in a circle.The tension T in the string can be calculated at the top and bottom of the circular path by resolving the forces acting on the ball. At the top, the weight of the ball acts downwards, and the tension acts upwards.

Hence, the net force is the centripetal force, which is given by

mv²/R - mg = mv²/L

The tension Tt can be calculated by resolving the forces vertically, which givesTt - mg = mv²/LTt = mv²/L + mg ------------ (1)

At the bottom of the path, the weight of the ball acts downwards, and the tension acts upwards. Hence, the net force is the centripetal force, which is given bymv²/R + mg = mv²/LThe tension Tb can be calculated by resolving the forces vertically, which gives

Tb + mg = mv²/LTb = mv²/L - mg ------------- (2)

Taking the ratio of equations (1) and (2), we get

TbTt = (mv²/L - mg)/(mv²/L + mg)

TbTt = (v²/gL - 1)/(v²/gL + 1) TbTt = 1 - v²/gL

The expression TbTt = 1 - v²/gL gives the ratio of the tension Tt in the string when the ball is at the top of its path to Tb when the ball is at the bottom of its path. Hence, the correct option is D.

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Answer:

A liquid is a nearly incompressible fluid that conforms to the shape of its container but retains a (nearly) constant volume independent of pressure. A liquid is made up of tiny vibrating particles of matter, such as atoms, held together by intermolecular bonds.

Here, a denotes acceleration, t denotes time, and u and v denote beginning and ultimate velocities, respectively. u = v + at.

       0 m/s = 45 m/s + 7 m/s t t = 6.42 s.

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Answer:

The ability of gases to be forced or squeezed into smaller volumes is called compressibility

Answer:

The solar wind is created by the outward expansion of plasma (a collection of charged particles) from the Sun's corona (outermost atmosphere). This plasma is continually heated to the point that the Sun's gravity can't hold it down. It then travels along the Sun's magnetic field lines that extend radially outward.

Answer:

B. oxygen

Explanation:

Answer:

it's oxygen lolllllllllllll they kinda need it

Explanation:

Answer:

A satellite rotates around the earth by using earth's gravitational force as centripetal force. Also as there is no air in space, it does not have to work against air resistance. Hence it doesn't lose any energy while rotating. So it does not require fuel to rotate around the earth.

A rock with a mass of 550 g in air has an apparent mass of 346 g when submerged in water. To find the mass of water displaced, calculate the difference between the rock's mass in air and its apparent mass in water.

Explanation:
The apparent mass of an object submerged in a fluid is less than its mass in air due to buoyancy. The buoyant force exerted by the water opposes the weight of the object. By Archimedes' principle, the buoyant force is equal to the weight of the water displaced by the object.

The mass of water displaced can be calculated by finding the difference between the rock's mass in air and its apparent mass in water:
Mass of water displaced = Mass of rock in air - Apparent mass of rock in water
= 550 g - 346 g
= 204 g

Therefore, 204 g of water is displaced by the rock when submerged in water.

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A color television tube also generates some x rays when its electron beam strikes the screen.he shortest wavelength of the X-rays produced by the color television tube, when a 30.0-kV potential is used to accelerate the electrons, is approximately 2.26 angstroms (Å).

The shortest wavelength of X-rays produced by a color television tube can be determined using the formula for calculating the wavelength of X-rays generated by an accelerating voltage. The formula is given by:

Λ = (12.4 Å)/(√V)

Where:

Λ is the wavelength of the X-rays in angstroms (Å)

V is the accelerating voltage in kilovolts (kV)

Given that the accelerating voltage is 30.0 kV, we can substitute this value into the formula:

Λ = (12.4 Å)/(√30.0 kV)

Calculating the square root of 30.0 kV:

√30.0 kV ≈ 5.48 kV

Substituting this value into the formula:

Λ ≈ (12.4 Å)/(5.48 kV)

Calculating the wavelength:

Λ ≈ 2.26 Å

Therefore, the shortest wavelength of the X-rays produced by the color television tube, when a 30.0-kV potential is used to accelerate the electrons, is approximately 2.26 angstroms (Å).

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The volume of water fell on the town is 1382 acre foot.

To find the volume of water, the given values are:

Area of the town = 28 km² (square kilometer)

Time = 30 minutes

Height = 2.4 inch

   The volume of water during a severe thunderstorm can be calculated as,

At first inch should be converted to meter,

1m = 39.37 inch

So, 2.4 inch = 2.4 / 39.37

                    = 0.0609 m

Then, we have to calculate the volume,

Formula of volume,

Volume V = Height H × Area A

                = 0.0609 × 28 × 1000²

                = 1705200 m³

Here, the volume should be in acre feet,

The value of, 1 m³ = 0.000810714 acre foot

so, 1705200 m³ = 1382.43 acre foot

Hence, the volume of water during a severe thunderstorm, fell on the town was 1382 acre foot.

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This question involves the concepts of tension force, centripetal force, and time period.

The tension force in the string is "0.88 N".

We will find the angular speed of the ball:

\(\omega = \frac{2\pi}{T}\)

where,

ω = angualar speed = ?

T = time period = 0.9 s

\(\omega = \frac{2\pi}{0.9\ s}\)

ω = 6.98 rad/s

We will find the linear speed of the ball:

v = rω

whre,

v = linear speed = ?

r = radius of circular path = length of string = 0.3 m

Therefore,

v = (0.3 m)(6.98 rad/s)

v = 2.09 m/s

We will find the tension force in the string:

In order for the ball to stay on the circular path the tension force in the string must be equal to the centripetal force:

\(Tension = Centripetal\ Force\\\\ T = \frac{mv^2}{r}=\frac{(0.06\ kg)(2.09\ m/s)^2}{0.3\ m}\)

T = 0.88 N

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1. The vector for velocity is represented by the blue arrow, and the vector for acceleration is represented by the green arrow in the simulation.

2. a. For the object to speed up, the orientation of the vectors should be in the same direction.

b. For the object to slow down, the orientation of the vectors should be in opposite directions.

3. In the Simple Harmonic motion, the object moves back and forth in a linear path.

4. In the Circular motion, the orientation of the vectors (relative to each other) determines the turning of the object: The blue (velocity) vector should be tangent to the circular path, indicating the direction of the object's motion.

5. When attempting to move the object like a planet in orbit (an ellipse), the object must follow an elliptical path.

1. The vector for velocity is represented by the blue arrow, and the vector for acceleration is represented by the green arrow in the simulation.

2. When observing the Linear Acc 1 motion, we can determine the orientation of the vectors for the object to speed up or slow down:

a. For the object to speed up, the orientation of the vectors should be in the same direction. This means that the blue (velocity) and green (acceleration) vectors should be pointing in the same direction.

b. For the object to slow down, the orientation of the vectors should be in opposite directions. This means that the blue (velocity) and green (acceleration) vectors should be pointing in opposite directions.

3. In the Simple Harmonic motion, the object moves back and forth in a linear path. The orientation of the vectors does not play a significant role in this motion.

4. In the Circular motion, the orientation of the vectors (relative to each other) determines the turning of the object:

The blue (velocity) vector should be tangent to the circular path, indicating the direction of the object's motion. The green (acceleration) vector should be pointing towards the center of the circle, providing the centripetal acceleration necessary to maintain circular motion.

5. When attempting to move the object like a planet in orbit (an ellipse), the object must follow an elliptical path. This requires the object to continuously change its velocity vector and direction. The object must constantly accelerate towards the center of the ellipse to maintain the curved path.

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In order for the equations for uniformly accelerated motion to be applied, a constant net force acts on the body (option B)

The net force represents the resultant vector obtained by combining all the forces exerted on an object. It quantifies the collective magnitude and orientation of these forces acting upon the object. The net force can assume three possibilities: zero, positive, or negative.

When the net force equals zero, the object remains stationary or maintains a uniform velocity.

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Answer:

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

Explanation:

From Physics we get that expansion of the rod portion is found by this formula:

\(\Delta l = \alpha\cdot l_{o}\cdot (T_{f}-T_{o})\) (Eq. 1)

Where:

\(\Delta l\) - Expansion of the rod portion, measured in meters.

\(\alpha\) - Linear coefficient of expansion for titanium, measured in \(\frac{1}{^{\circ}C}\).

\(l_{o}\) - Initial length of the rod portion, measured in meters.

\(T_{o}\) - Initial temperature of the rod portion, measured in Celsius.

\(T_{f}\) - Final temperature of the rod portion, measured in Celsius.

If we know that \(\alpha = 5\times 10^{-6}\,\frac{1}{^{\circ}C}\), \(l_{o} = 10\,m\), \(T_{o} = 0\,^{\circ}C\) and \(T_{f} = 400\,^{\circ}C\), the expansion experimented by the rod portion is:

\(\Delta l = \left(5\times 10^{-6}\,\frac{1}{^{\circ}C} \right)\cdot (10\,m)\cdot (400\,^{\circ}C-0\,^{\circ}C)\)

\(\Delta l = 0.02\,m\)

The 10-meter long rod of an SR-71 airplane expands 0.02 meters (2 centimeters) when plane flies at 3 times the speed of sound.

The overall efficiency of the steam power plant is 33.3%.

Power output of a steam power plant = 150 MW, Coal consumption rate = 60 tons/h, Heating value of coal = 30,000 kJ/kg, We can calculate the overall efficiency of the plant using the formula,

Efficiency = (Power output / Heat rate) * 100

where, Heat rate = Energy input / Fuel power input.

Heat rate can be calculated using the formula,

Heat rate = (Fuel consumption rate * Heating value of fuel) / Power output

Putting the given values in the above formula,

Heat rate = (60 tons/h * 30,000 kJ/kg * 1000 kg/ton) / (150 MW * 10⁶ W/MW)

Heat rate = 8.0 MJ/kWh

Now, using the calculated heat rate and given power output, we can calculate the energy input to the plant,

Energy input = Power output / Efficiency

where,Efficiency = (Power output / Heat rate) * 100

Now, substituting the values,

150 MW = Energy input / Efficiency

Efficiency = (150 MW) / (Energy input)

From the above equations,

Efficiency = (150 MW) / ((150 MW * 10⁶ W/MW) / (8.0 MJ/kWh))

Efficiency = 33.3%

Therefore, the overall efficiency of the steam power plant is 33.3%.

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Answer:

SUP DAD i love cookies

Explanation:

yuh

Answer: 0.85 N

Explanation: We can solve this problem using the principles of buoyancy and Newton's laws.

First, we need to find the buoyant force acting on the metallic alloy block. The buoyant force is equal to the weight of the water displaced by the block, which can be calculated using the block's volume and the density of water:

V = m_block / ρ_block = 3.4 kg / 3700 kg/m³ = 0.0009189 m³

F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0009189 m³ = 8.96 N

So the buoyant force acting on the metallic alloy block is 8.96 N.

Next, we can calculate the tension force in the spring scale attached to the block. Since the block is in static equilibrium, the tension force must be equal in magnitude and opposite in direction to the weight of the block plus the buoyant force:

Tension force = weight of block + buoyant force

Tension force = m_block x g + F_buoyant

Tension force = 3.4 kg x 9.8 m/s² + 8.96 N = 42.04 N

So the hanging scale reads 42.04 N.

Finally, we can find the reading of the lower scale. The lower scale measures the weight of the beaker and the water in it, minus the buoyant force acting on the beaker. The weight of the beaker and the water is:

weight of beaker + weight of water = m_beaker x g + m_water x g

weight of beaker + weight of water = 1.3 kg x 9.8 m/s² + 2.5 kg x 9.8 m/s² = 35.35 N

The buoyant force acting on the beaker can be calculated using the volume of water displaced by the beaker:

V = m_water / ρ_water = 2.5 kg / 1000 kg/m³ = 0.0025 m³

F_buoyant = ρ_water x g x V = 1000 kg/m³ x 9.8 m/s² x 0.0025 m³ = 24.5 N

So the reading of the lower scale is:

Reading of lower scale = weight of beaker + weight of water - buoyant force

Reading of lower scale = 35.35 N - 24.5 N = 10.85 N

Therefore, the lower scale reads 10.85 N.

To calculate the height of the cliff and the time it takes for the rock to reach the ground when thrown straight down, we can use the equations of motion.

(a) Height of the cliff:

When the rock is thrown straight up, it reaches its highest point before falling back down. The time it takes for the rock to reach its highest point is equal to the time it takes for the rock to fall back down to the ground.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff),

u is the initial velocity (8.19 m/s),

t is the time (2.32 s),

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Rearranging the equation:

s = ut + (1/2)at^2

s = (8.19)(2.32) + (1/2)(-9.8)(2.32)^2

s = 19.004 - 25.798

s = -6.794 m

Since the height of a cliff cannot be negative, we take the absolute value of the result:

Height of the cliff = |s| = 6.794 m

So, the height of the cliff is approximately 6.794 meters.

(b) Time to reach the ground when thrown straight down:

When the rock is thrown straight down with the same speed, the initial velocity (u) is still 8.19 m/s, but the acceleration due to gravity (a) remains -9.8 m/s^2.

Using the equation:

s = ut + (1/2)at^2

Where:

s is the distance traveled (height of the cliff, which is now negative),

u is the initial velocity (8.19 m/s),

t is the time we want to find,

a is the acceleration due to gravity (-9.8 m/s^2, taking downward direction as negative).

Substituting the known values:

-6.794 = (8.19)t + (1/2)(-9.8)t^2

Rearranging the equation:

-6.794 = 8.19t - 4.9t^2

Rearranging further:

4.9t^2 - 8.19t - 6.794 = 0

Solving this quadratic equation, we find two possible values for t: 0.828 seconds and 1.303 seconds. Since we are considering the time it takes to reach the ground, the valid solution is t = 0.828 seconds.

Therefore, when the rock is thrown straight down, it takes approximately 0.828 seconds to reach the ground.

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Answer:

heymelissa its amanda i hate ms spearman

Explanation:

yuh

Answer:

New technology is developed that provides more information about the theory. (New technologies can lead to new results).

New experimental methods are designed to test a theory.

New information is discovered that does not support the theory.

Explanation:

A theory is an explanation of an aspect of the natural based on careful examination of facts. A theory by its definition can be repeatedly tested. A theory can be changed or replaced because of the following reasons:

The current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

When three resistors are connected in series with a six resistor and a 12-volt battery, the total resistance of the series circuit is R = R1 + R2 + R3 + ...

The current flowing through the circuit is the same at every point. So, if we want to know the current flowing through each resistor, we need to use Ohm's law, I = V/R, where V is the voltage of the battery and R is the resistance of each resistor.

I1 = V/R1 = 12/3 = 4 AI2 = V/R2 = 12/6 = 2 AI3 = V/R3 = 12/3 = 4 A. The voltage drop across each resistor can be calculated using Ohm's law, V = IR.

V1 = I1R1 = 4 x 3 = 12 VV2 = I2R2 = 2 x 6 = 12 VV3 = I3R3 = 4 x 3 = 12 V.

Therefore, the current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

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Answer:

Here's a rough diagram for this question!

The scale I used is 1cm = 5000N.

So, 20000N = 4 cm & 30000N = 6cm.

To find the magnitude of the resultant force, draw a straight line from one corner of the parallelogram to the other end and measure the line. From the diagram, mine would be around 10cm. So, based on the scale I used, 10cm would be 50000N. Therefore, the resultant force is 50000N!

For the angle between the resultant force, I got around 13°-14°!

I hope this helps!

EDIT: My bad, I just noticed I wrote 2000N on my pic loll, thats supposed to be 20000N.

In order to test for the temperature and consistency of heated wax, it is true that a small drop should be applied to the wrist.

To test the temperature and consistency of heated wax, apply a small drop on your wrist. This helps ensure the wax is at a comfortable temperature and has the right consistency before applying it to larger areas.

It is recommended to test the wax on a small area of your skin that is not sensitive, such as the inside of your wrist or elbow, and wait a few seconds to ensure that the temperature is comfortable before using it for hair removal. It is also important to follow the instructions and safety precautions provided by the wax manufacturer.

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A) The modulation index is undefined. B) The lower-side band (LSB) frequency is 99,500Hz. C) Percentage modulation = 20%

a) The modulation index (m) may be calculated through the usage of the formulation:

m = (Vmax - Vmin) / (Vmax + Vmin)

where Vmax and Vmin are the most and minimum amplitudes of the modulating signal, respectively.

In this case, the modulating sign is vi(t) = 90cos(2π500t) V. The most amplitude (Vmax) is 90 V, and the minimum amplitude (Vmin) is -90 V (for the reason that the cosine feature varies between -1 and 1).

Therefore, the modulation index is:

m = (Vmax - Vmin) / (Vmax + Vmin) = (90 - (-90)) / (90 + (-90)) = 180 / 0 = undefined

b) The carrier frequency is fc =100,000 Hz.

The higher-aspect band (USB) frequency is given via:

fUSB = fc + fm =100,000 Hz + 500 Hz = 100,500 Hz

The decrease-aspect band (LSB) frequency is given by way of:

fLSB = fc - fm = 100,000 Hz - 500 Hz = 99,500 Hz

c) If vi(t) = 120cos(2π500t) V, we will calculate the share modulation using the components:

Percentage modulation = (Vm - Vc) / Vc * 100%

in which Vm is the peak amplitude of the modulating sign and Vc is the peak amplitude of the service signal.

In this situation, Vm = 120 V and Vc = 100 V.

Percentage modulation = (Vm - Vc) / Vc * 100% = (120 - 100 ) / 100  * 100% = 20%

Increasing the modulation amplitude increases the percentage modulation. This outcome is in a larger version within the amplitude of the AM signal, which could result in extended sidebands and a more said modulation impact. The audio content of the modulating signal turns more distinguished, ensuing in a more potent modulation effect inside the AM signal.

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Answer:

B

Explanation:

Speed is distance divided by time.

Answer:

revolution of the planets around the Sun.

Explanation:

The revolution of the planets around the Sun is a result of the gravitational force exerted by the Sun. The Sun's gravitational pull attracts the planets, causing them to move in an elliptical orbit around it. This motion is known as the revolution of the planets around the Sun. The other options listed (rotation of the planets on their axes, rotation of the Moon on its axis, and revolution of the Moon around Earth) are also related to motion and gravity, but they are different phenomena.

the answer is C difference in density because hot air is less dense than cold air so hot air will rise and cold air will fall.

Answer:

a difference in density

Explanation:

Density measures the amount of mass (the number of particles) in a specific volume.

Since the molecules in warm air are spread farther apart than the molecules in cold air, there are fewer air particles per unit volume in warm air than in cold air. This means that warm air is less dense than cold air, and it will rise.

So, warm air rises and cold air sinks because of a difference in density.