identify the following electrical components by specifying whether they are input field devices (a) or output field devices (b). group of answer choices push button a solenoid b pilot lamp b selector switch

Answer:

the rate of flow of heat through the roof is 45616.858 BTU/hr

Explanation:

Given the data in the question;

pin thickness \(t_p\) = 2 in

fiber glass thickness \(t_f\) = 4 in

Asphalt shingles thickness \(t_a\) = 0.1 in

R/inch for pine = 1.28

R/inch for fiberglass = 3.0

R/inch for Shingles = 4.0

Temperature inside the house \(T_{inside\) = 700 F

Temperature outside the house \(T_{outside\) = 300 F

area of the roof A = 500 ft²

we calculate the total Resistance;

R = ( 2 × 1.28 ) + ( 4 × 3.0 ) + ( 0.1 × 4.0 )

R = 2.56 + 12 + 0.4

R = 14.96

Now, we determine the rate of heat flow;

dQ/dt = ΔT(A) / R

⇒ ( \(T_{inside\) - \(T_{outside\) )A / R

we substitute

⇒ (( 700 - 300 ) × 500 ) / 14.96

⇒ ( 400 × 500 ) / 14.96

⇒ 200000 / 14.96

⇒ 13368.98 watt

we know that 1 watt = 3.412142 BTU/hr

⇒ ( 13368.98 × 3.412142 ) BTU/hr

⇒ 45616.858 BTU/hr

Therefore, the rate of flow of heat through the roof is 45616.858 BTU/hr

Answer:

  a) 2.40 V

  b) 120

  c) 150

  d) 8 kΩ in parallel with the amplifier input

Explanation:

The voltage divider between the source resistance and the amplifier input resistance makes the amplifier input voltage be ...

  vi = (10 mV)(ri/(rs+ri)) = (10 mV)(40/(10+40)) = 8 mV

(a) The gain of 300 makes the open-circuit amplifier output voltage be ...

  Vo = 300(8 mV) = 2400 mV = 2.40 V . . . . open-circuit output voltage

__

(b) The load voltage is the result of voltage-divider action between the output resistance and the load resistance.

  Vl = Vo(rl)/(ro +rl) = 2.40 V(100)/(100 +100) = 1.20 V

So, the overall voltage gain from the source is ...

  vl/vs = (1.20 V)/(0.010 V) = 120 . . . . voltage gain from source

__

(c) The voltage gain to the load from the amplifier input is ...

  vl/vi = 1.200 V/0.008 V = 150 . . . . voltage gain from input to load

__

(d) To reduce the input of the amplifier without breaking the circuit, we could add a resistor in parallel with the amplifier input. It would need to reduce the gain of that voltage divider from 0.8 to 0.4 to cut the output voltage in half. That is, for some parallel resistor R (in kOhms), we want ...

  R(Ri)/(R·(Ri +Rs) +Ri·Rs)) = 0.40

  40R/(50R + 400) = 2/5

  200R = 100R +800 . . . . cross multiply

  100R = 800 . . . . . . . . . . . subtract 100R

  R = 8 . . . . kOhms

Putting 8 kOhms in parallel with the amplifier input will reduce the overall gain by the required amount.

The mercury manometer that attached to the bottom will reading 2.7 cm.

\(p_1\) = ethanol density = 789 kg/m^3

\(p_2\) = oil density = 918 kg/m^3

\(p_3\) = water density = 1000 kg/m^3

\(p_4\) = mercury density = 13600 kg/m^3

Since the ethanol is exposed to air and the manometer also exposed to air, we can determine the height of mercury is equal by extra pressure by liquid. So,

\(p_4\)*g*h = \(p_1\)*g*0.1+\(p_2\)*g*0.1+\(p_3\)*g*0.2

we can eliminate the g or gravity.

13600h = 789*0.1+918*0.1+1000*0.2

13600h = 78.9+91.8+200

13600h = 370.7

h = 0.027 m

h = 2.7 cm

Thus, the mercury manometer reading will be 2.7 cm.

You question is incomplete, but most probably your full question was

A tank is constructed of a series of cylinders having diameters of 0.30, 0.25, and 0.15 m as shown in the figure. The tank contains ethanol, oil and water. Ethanol is exposed to air. A mercury manometer is attached to the bottom. Determine the manometer reading, h

(image attached)

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Answer:

OBJECTLINE

HIDDEN LINE

SECTION LINE

CENTER LINE

Explanation:

Answer:

Not seeing any other information, the best answer I can give is 2m.

Explanation:

M = magnitude

You see, if they have an equal charge, and you add them, it'd be 2 * m, or 2m.

The system's response to the initial excitation, with a displacement of 10m and a velocity of 20m/s at time t = 0s, depends on the characteristics of the system.

The response of a system is influenced by factors such as the system's natural frequency, damping ratio, and external forces. These factors determine whether the system response will oscillate, decay, or exhibit other behavior.

The system's response is determined by its natural frequency, which is a measure of how quickly the system oscillates when undisturbed. If the excitation frequency matches the natural frequency, resonance can occur, leading to large oscillations.

The damping ratio characterizes the amount of damping in the system. A higher damping ratio results in quicker decay of the oscillations. Conversely, a lower damping ratio can lead to sustained or even growing oscillations.

External forces, such as applied loads or disturbances, can also affect the system's response. These forces may alter the equilibrium position, introduce additional energy, or change the system's behavior in other ways.

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All of the following statements with respect to manual transmission are true EXCEPT releasing the clutch pedal closes the contacts of the clutch safety switch.

Manual automobiles are useful due to the fact they normally value much less and are extra fuel-efficient. You can also see decreased upkeep prices and coverage prices. They additionally provide you higher management of the car for the reason that driver, now no longer the car, is in fee of converting gears.

With the pedal totally released, there's complete touch between the engine and the driveshaft, through the take hold of the plate, because of this the engine can observe energy immediately to the driveshaft. However, it's miles feasible to have the take hold of plate partly engaged, permitting the take hold of to slip.

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An eyewash station should be located within a maximum distance of 25 feet from every location where a person may come into contact with substances that can cause damage to their eyes.

Explanation:

I can't see the whole question... How can I solve it?

Answer: the engineers are performing a tensile test

Explanation:

i took the test and got it right

Main Answer:

On most days he could only ride the elevator to the fifteenth story, and he would have to walk the rest of the way

sub heading:

explain elevator?

Explanation:

1.elevator, also called lift, car that moves in a vertical shaft to carry passengers or freight between the levels of a multistory building.

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Consider the four sub-cases for each of those three cases two positives, two negatives, one of each . Show that some of those sub-cases are not possible in each case. Then examine each sub-case to see if it indicates overflow.

Two's complement is a mathematical operation that converts a positive binary number with equivalent value reversibly into a negative binary number with equivalent value.

it occurs using the binary digit with the greatest place value to indicate whether the binary number is positive or negative.

Consider each of those three cases' four sub-cases. There are two positives and two negatives, with one of each.

Demonstrate that some of the sub-cases are not feasible in each case. Then, for each sub-case, determine whether it indicates overflow.

Thus, by this it can be proved that in a 2’s complement number system addition overflows if and only if the carry from the sign position does not equal the carry into the sign position.

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Without additional information on the raceway distance, ambient temperature, and voltage drop, it is impossible to determine the size of the copper service conductors required.

To determine the size of copper service conductors required for a multifamily building with a total demand load of 260 kW for a 120/208V wye, three-phase system, additional information is needed, such as the raceway distance, ambient temperature, and voltage drop. Without this information, it is impossible to accurately calculate the conductor size.

In general, conductor sizing is determined by the National Electrical Code (NEC), which provides guidelines based on various factors, including the load, the type of conductor, the length of the run, and the ambient temperature. To determine the conductor size for this particular situation, a licensed electrician or engineer would need to perform a detailed load calculation and take into account the specific installation requirements and local code regulations.

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The minimum clock period for this CPU should be at least 345 ps.

To determine the latencies and clock period requirements for different instructions in the given exercise, we will consider the provided values for the logic block latencies.

4.7.1:

The latency of an R-type instruction refers to the time required for the instruction to complete its execution. In this case, the R-type instruction consists of register read, ALU operation, and register write. From the given values, we can determine the total latency by summing the latencies of the logic blocks involved:

Latency = Register Read + ALU Adder + Register Write

Latency = 150 ps + 25 ps + 150 ps

Latency = 325 ps

Therefore, the clock period should be at least 325 ps to ensure the correct execution of an R-type instruction.

4.7.2:

The latency of ld (load) instruction represents the time required to complete the load operation, which involves register read, sign extension, ALU operation, and register write. Adding up the latencies of the involved logic blocks:

Latency = Register Read + Sign Extend + ALU Adder + Register Write

Latency = 150 ps + 20 ps + 25 ps + 150 ps

Latency = 345 ps

Thus, the clock period should be at least 345 ps for the correct execution of the ld instruction.

4.7.3:

Similar to the ld instruction, the sd (store) instruction involves register read, sign extension, ALU operation, and register write. Adding up the latencies:

Latency = Register Read + Sign Extend + ALU Adder + Register Write

Latency = 150 ps + 20 ps + 25 ps + 150 ps

Latency = 345 ps

The clock period should be at least 345 ps for the correct execution of the sd instruction.

4.7.4:

The latency of beq (branch equal) instruction involves register read, ALU operation, and control logic. Summing up the latencies:

Latency = Register Read + ALU Adder + Control

Latency = 150 ps + 25 ps + 50 ps

Latency = 225 ps

A clock period of at least 225 ps is required for the correct execution of the beq instruction.

4.7.5:

The I-type instruction refers to the load and store instructions (ld and sd). Since we have already determined their latencies in previous questions:

I-type Instruction Latency = Latency of ld or sd = 345 ps

4.7.6:

The minimum clock period for this CPU would be equal to the highest latency among all the instructions. From the previous calculations, the highest latency is 345 ps.

Therefore, the minimum clock period for this CPU should be at least 345 ps.

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Based on the descriptions, the correct answer is (a) Thermal transfer printer, as it is the only option that utilizes a ribbon containing wax-based ink.

To identify the type of printer that uses a ribbon with wax-based ink, we need to analyze each option provided.

a. Thermal transfer - This type of printer uses a thermal printhead and a wax-based ink ribbon to transfer the ink onto the paper.
b. Laser - A laser printer uses a laser beam and toner to create an image on a drum, which then transfers the image onto the paper.
c. Dye-sublimation - This printer uses heat to transfer dye onto materials, but it does not involve a wax-based ink ribbon.
d. Inkjet - An inkjet printer sprays ink droplets onto the paper, and it also does not use a wax-based ink ribbon.

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Answer:

A rectangular shaped tool that functions as a pulley.

Explanation:

i beleive

The correct answer is diameter of clarifier = 66.261 feet Image transcriptions Water Flow rate Hydraulic residence.

Hydraulic residence time. The HRT indicates the duration in hours that the feed solution remains in the MBR before it is processed as permeate by the membrane. The formula for HRT is. (5.1) From Eqn (5.1), it is evident that HRT depends on the hydraulic volume of the reactor and the permeate flow.So, for accurate HRT calculation, use the hydraulic retention time formula “HRT = V/Q.” Here, you are dividing the volume of the aeration tank, which is a value of meters cubed, by the influent flow rate.

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The work done on the gas during this process if the final pressure is 456 kPa is; -82.8 kJ

We are given;

The initial pressure; P₁ = 96 kPa

Final Pressure; P₂ = 456 kPa

The gas is compressed according to;

p = aV + b

where;

a = -1200 kPa/m³

b = 600 kPa

Thus, at initial pressure P₁ = 96 kPa;

96 = -1200V₁ + 600

1200V₁ = 600 - 95

1200V₁ = 505

V₁ = 505/1200

V₁ = 0.42 m³

At Final Pressure P₂ = 456 kPa;

456 = -1200V₂ + 600

1200V₂ = 600 - 456

1200V₂ = 144

V₂ = 144/1200

V₂ = 0.12 m³

Formula for the workdone during the process is;

W_out = ¹/₂(P₁ + P₂)(V₂ - V₁)

W_out = ¹/₂(96 + 456)(0.12 - 0.42)

W_out = -82.8 kJ

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Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Explanation:

Given that;

Weight of soil r = 118 lb/ft³

stress parameter C = 250 lb/ft²

φ total = 29°

depth Z = 12 ft

The shear strength on a horizontal plane at a depth of 12ft

ζ = C + δtanφ

where δ = normal stress

normal stress δ = r × z = 118 × 12 = 1416

so

ζ = C + δtanφ

ζ = 250 + 1416(tan29°)

ζ = 250 + 1416(tan29°)

ζ = 250 + 784.9016

ζ = 1034.9015 lb/ft²

Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²

Answer:

1.) dV/dt = -187200πSin(120πt)

2.) No

3.) -187200

Explanation:

The voltage, V, in volts, in an electrical outlet is given as a function of time, t, in seconds, by the function V=156cos(120πt)

dV/dt = -187200πSin(120πt)

Since the rate of change above is negative, that is, its maximum is negative. definitely, it will never be equal to zero.

The maximum value of the rate of change will be its amplitude, which is

-187200

Answer:

you can't eat your school computer or a pencil.

Answer:

local. It is a very popular

Pearson Math Lab is an online platform developed by Pearson Education, a leading educational publisher. The platform is designed to help students learn and practice math concepts at their own pace and in a personalized way.

It offers interactive learning tools, assessments, and homework resources for K-12 students, as well as college and university students.

Pearson Math Lab provides access to a range of digital resources, including eTextbooks, video lectures, animations, and online platform. These resources are designed to help students build foundational knowledge and practice problem-solving skills in math. The platform also provides immediate feedback and personalized recommendations based on students' performance, helping them to identify areas where they need more practice and support.

In addition to providing resources for students, Pearson Math Lab also includes features for instructors and educators. These features allow instructors to track student progress, monitor their performance, and customize learning paths to meet the needs of individual students. The platform also integrates with learning management systems (LMS) commonly used in educational institutions, making it easy for instructors to integrate Pearson Math Lab into their teaching and assessment practices.

Overall, Pearson Math Lab is a comprehensive platform that provides students with the tools and resources they need to learn and practice math in a flexible and personalized way.

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To display the pet id, name and type for all pets that have a 5-letter name starting with a C, the following SQL statement can be used:

```sql
SELECT pet_id, name, type
FROM pets
WHERE LENGTH(name) = 5 AND name LIKE 'C%';
```

Step-by-step procedure to write the statement to display the pet details:

1. `SELECT pet_id, name, type` specifies the columns you want to display in the result.
2. `FROM pets` specifies the table where the data is coming from.
3. `WHERE LENGTH(name) = 5` filters the rows to only include pets with a 5-letter name.
4. `AND name LIKE 'C%'` further filters the rows to include only pets whose names start with the letter 'C'.

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To display the pet id, name and type for all pets that have a 5-letter name starting with a C, the following SQL statement can be used:

```sql
SELECT pet_id, name, type
FROM pets
WHERE LENGTH(name) = 5 AND name LIKE 'C%';
```

Step-by-step procedure to write the statement to display the pet details:

1. `SELECT pet_id, name, type` specifies the columns you want to display in the result.
2. `FROM pets` specifies the table where the data is coming from.
3. `WHERE LENGTH(name) = 5` filters the rows to only include pets with a 5-letter name.
4. `AND name LIKE 'C%'` further filters the rows to include only pets whose names start with the letter 'C'.

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Answer:

a.) 4.46 m/s

b.) 0.41 m/s

Explanation:

a) Given that the mass M of the bullet = 30g = 30/1000 = 0.03 kg

Velocity V = 450 m/s

From conservative of linear momentum,

Sum of momentum before impact = Sum of momentum after impact

0.03 × 450 = (0.03 + 3 ) × v₂

v₂ = 13.5/3.03 = 4.4554 m/s

Therefore the velocity of the bullet and B after the first impact = 4.46 m/s approximately

(b) To calculate the velocity of the carrier, you will consider the conservation of linear momentum again.

(m₁ + m₂)×v₂  = (m₁ + m₂ + m₃)×v₃

Where:

Mass of the carrier m₃ = 30 kg

Substitute all the parameters into the formula

3.03×4.4554 = (3.03 +30) × v₃

v₃ = 13.5 / 33.03 = 0.40872 m/s

Therefore the velocity of the carrier is 0.41 m/s approximately.

Answer:

The answer is 920 kJ

Explanation:

Solution

Given that:

Mass = 5kg

Pressure = 600 kPa

Temperature = 80° C

Liquid vapor mixture state (quality) = 0.3

Now we find out the amount of heat extracted in the process

Thus

Properties of  RI34a at:

P₁ = 600 kPa

T₁ = 80° C

h₁ = 320 kJ/kg

So,

P₁ = P₂ = 600 kPa

X₂ =0.3

h₂ = 136 kJ/kg

Now

The heat removed Q = m(h₁ -h₂)

Q = 5 (320 - 136)

Q= 5 (184)

Q = 920 kJ

Therefore the amount of heat extracted in the process is 920 kJ