Identify the following substances:
(1) An acidic gas which gives dense white fumes with NH3
(11 An alkane which can also be called a green house gas.
(iii) A solid which when kept in the open, forms a solution after som
(iv) An alloy used in electrical fittings.
(v) A metal which gives hydrogen gas on reacting with both dilute a
Write equations for the following reactions:
Aluminium oxide and Sodium hydroxide.
(ii) Zine and dilute sulphuric acid.
(
11​

Answers

Answer 1

Answer:

1) HCl (Hydrochloric acid reacts with NH3 and forms dense fumes)

2) Methane (It is from the group of alkanes and is a green house gas)

3) Deliquescent substance (It is a solid which when kept in open forms a solution after sometime)

4) Brass (It is a solid-in-solid solution used to make electrical fittings)

5) Aluminium

Question 2:

1)    Al₂O₃ + 2NaOH    ⇒   2NaAlO₂  (Sodium Aluminate) + H₂O

2)   Zn +  H₂SO₄   (dilute)  =>  ZnSO₄  (Zinc Sulphate) + H₂

Answer 2

Answer:

HCl is the gasmethanedeliquescent substances (they absorbs water out of the air until they dissolve themselves into liquid solutions. )brass

equations

Aluminium oxide and Sodium hydroxide react to form water and sodium aluminate

Al2O3 + 2NaOH → 2NaAlO2 + H2O

Zinc reacts with dilute sulphuric acid to form zinc sulphate and hydrogen gas

Zn + H2SO4 → ZnSO4 +H2


Related Questions

Consider the following reaction: 2N2O5(g) → 4NO2(g) + O2(g) Calculate the volume N2O5 that must decompose completely to produce 9.64 L nitrogen dioxide.​

Answers

The volume of \(N_2O_5\) needed to produce 9.64 L of \(NO_2\) is 4.97 L, calculated using stoichiometry and the ideal gas equation.

The given chemical equation is \(2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g)\) .The volume of \(N_2O_5\) that decomposes completely to form 9.64 L of \(NO_2\) is to be calculated. For this, we can use the concept of stoichiometry. Stoichiometry is a branch of chemistry that deals with the quantitative relationships between reactants and products in a balanced chemical equation.To calculate the volume of \(N_2O_5\) that is needed to produce 9.64 L of \(NO_2\), we will first determine the number of moles of NO2 produced in the reaction. For this, we can use the ideal gas equation, PV = nRT. Here, we have the volume of NO2 and we can assume the pressure and temperature to be constant. Thus, we have PV = nRT, where P = pressure, V = volume, n = number of moles, R = ideal gas constant, and T = temperature. Substituting the given values in the ideal gas equation, we get,n = PV/RT = (1 atm × 9.64 L)/(0.0821 L atm K-1 mol-1 × 300 K) = 0.404 molFrom the chemical equation, we see that 2 moles of \(N_2O_5\) give 4 moles of \(NO_2\). Thus, 0.404 mol of \(NO_2\) must have been produced from (0.404/2) = 0.202 mol of \(N_2O_5\). Using the ideal gas equation, we can also find the volume of 0.202 mol of \(N_2O_5\) at the given conditions. Thus, V = nRT/P = (0.202 mol × 0.0821 L atm K-1 mol-1 × 300 K)/1 atm = 4.97 L. Thus, the volume of \(N_2O_5\) that must decompose completely to produce 9.64 L nitrogen dioxide is 4.97 L.

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how many atoms of hydrogen are present in a molecule of methane, CH 4​

Answers

Answer: One methane molecule, CH4, contains one carbon atom and four hydrogen atoms.

Explanation:

Please someone help me!
I need this done ASAP *URGENT*
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PLEASE HURRY AND ANSWER ALL QUESTIONS CORRECTLY
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What’s the difference worksheet
Atoms,molecules,elements and compounds
PLEASE PLEASE PLEASE PLEASE PLEASEEEEEEE ANSWER THIS I only have TWO days of school left! And I need this done quickly

Please someone help me! I need this done ASAP *URGENT* I Need this done before Thursday or Friday because

Answers

sorry needed the points

3. Suppose you had titrated your vinegar sample with barium hydroxide instead of sodium hydroxide:

Ba(OH)2(aq)+2CH3COOH(aq)⟶Ba(CH3COO)2(aq)+2H2O(l)

Consider a 0.586 M aqueous solution of barium hydroxide,

What volume (in mL) of 0.586 M Ba(OH)2 solution are required to neutralize 10 ml of vinegar containing 2.78 g of acetic acid?

Answers

Answer:

39.6 mL

Explanation:

Step 1: Write the balanced neutralization reaction

Ba(OH)₂(aq) + 2 CH₃COOH(aq) ⟶ Ba(CH₃COO)₂(aq) + 2 H₂O(l)

Step 2: Calculate the moles corresponding to 2.78 g of CH₃COOH

The molar mass of CH₃COOH is 60.05 g/mol.

2.78 g × 1 mol/60.05 g = 0.0463 mol

Step 3: Calculate the moles of Ba(OH)₂ needed to react with 0.0463 moles of CH₃COOH

The molar ratio of Ba(OH)₂ to CH₃COOH is 1:2. The moles of Ba(OH)₂ needed are 1/2 × 0.0463 mol = 0.0232 mol.

Step 4: Calculate the volume of 0.586 M solution that contains 0.0232 moles of Ba(OH)₂

0.0232 mol × 1 L/0.586 mol = 0.0396 L = 39.6 mL

The density of Na2Co3 solution at 20Celsius is 1.019g/mL. The mass fraction w(Na2CO3) is 0.02 (2%). What's the concentration of the solution?

Answers

1. we are given :

• that the mass fraction of Na2CO3 = 2%

meaning 2 grams of Na2Co3 was dissolved in 98g of water .

∴ total mass of solution = 100g

• Density = 1.019g/mL.

,

• Molar mass Na2CO3=105,9888 g/mol

2. Calculate volume

Density = mass /volume

∴Volume = mass/density = 100g /1.019g/mL.

= 90.66mL.

3.Calculate moles of the solution

n = mass Na2CO3/MolMass Na2Co3

= 2 g /105.9888g/mol

∴moles of Na2CO3 =0.019moles Na2CO3

4. Calculate the Molarity (concentration)of the solution

Molarity =( n/v) * 1000

= (0.019mol/(90.66/1000) L

= (0.019/90.66)*1000 ( multiply by 1000: 90.66/1000=0.09066)

=0.21M

This means that the concentration of the solution is 0.21M

12. In rocket fuel (as in many of the balloons we blow up in class), hydrogen gas (H2) reacts with oxygen gas (O2) to form water vapor. a) Write a balanced reaction for the process. b) Suppose you have a mini rocket and access to 2.50 L of oxygen gas and 4.00 L of hydrogen gas. If you use up all of the gas possible blasting off your rocket, how many liters of water vapor did you produce (at the same temperature as the original mixture)

Answers

Answer:  a) \(2H_2(g)+O_2(g)\rightarrow 2H_2O(g)\)

b) 4.00 L of \(H_2O\) will be produced

Explanation:

a) The balanced chemical reaction is:

\(2H_2(g)+O_2(g)\rightarrow 2H_2O(g)\)

b) According to avogadros law, equal moles of gases occupy equal volumes at same temperature and presure conditions.

According to stoichiometry :

2 L of \(H_2\) require  = 1 L of \(O_2\)

Thus 4.00 L of \(H_2\) will require=\(\frac{1}{2}\times 4.00=2.00L\)  of \(O_2\)

Thus \(H_2\) is the limiting reagent as it limits the formation of product and \(O_2\) is the excess reagent.

As 2 L of \(H_2\) give = 2 L of \(H_2O\)

Thus 4.00 L of \(H_2\) give =\(\frac{2}{2}\times 4.00=4.00L\)  of \(H_2O\)

Thus 4.00 L of \(H_2O\) will be produced

a. The balanced reaction for the process should be 2h_2(g) + O_2(g) ⇒2H_2O(g)

b. The number of liters of water vapor should be 4.00 liters of H_2O.

Avogadro's law:

a. The balanced reaction for the process should be 2h_2(g) + O_2(g) ⇒2H_2O(g)

b. As per the law, the equal moles of gases occupied equal volumes at the similar temperature

So, the number of liters should be

= 2/2*4.00

= 4.00 of H_2O

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"drivers license"

I got my driver's license last week
Just like we always talked about
'Cause you were so excited for me
To finally drive up to your house
But today I drove through the suburbs
Crying 'cause you weren't around

And you're probably with that blonde girl
Who always made me doubt
She's so much older than me
She's everything I'm insecure about
Yeah, today I drove through the suburbs
'Cause how could I ever love someone else?

And I know we weren't perfect but I've never felt this way for no one
And I just can't imagine how you could be so okay now that I'm gone
Guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street

And all my friends are tired
Of hearing how much I miss you but
I kinda feel sorry for them
'Cause they'll never know you the way that I do
Yeah, today I drove through the suburbs
And pictured I was driving home to you

And I know we weren't perfect but I've never felt this way for no one
Oh, and I just can't imagine how you could be so okay now that I'm gone
I guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street

Red lights
Stop signs
I still see your face
In the white cars
Front yards
Can't drive past the places
We used to
Go to
'Cause you know I still love you, babe

Sidewalks
We crossed
I still hear your voice
In the traffic
We're laughing
Over all the noise
God, I'm so blue
Know we're through
But you know I still love you, babe

I know we weren't perfect but I've never felt this way for no one
And I just can't imagine how you could be so okay now that I'm gone
Guess you didn't mean what you wrote in that song about me
'Cause you said forever now I drive alone past your street
Yeah, you said forever now I drive alone past your street

Answers

Answer:

omg that song l0wkey but high.key slaps

can you not please? this is an education website

For a certain ideal gas, the temperature is increased from 200 K to 376 K allowing pressure, which is initially 1 atm, to vary while
the volume and number of moles of gas are held constant. What is the new pressure? Answer in units of atm.

Answers

So, the new pressure of the gas is approximately 0.759 atm.

What is the pressure of the gas?

To find the new pressure of the gas when the temperature is increased from 200 K to 376 K, we can use the ideal gas law:

P/T = nR/V

Now, we can plug in the initial pressure and temperature, and the new temperature, to find the new pressure:

P1/T1 = nR/V (initial conditions)

P2/T2 = nR/V (new conditions)

Where P1 = 1 atm, T1 = 200 K, and T2 = 376 K. Solving for P2, we get:

P2 = (P1 * T2) / T1

P2 = (1 atm * 376 K) / 200 K

Using the value of the universal gas constant, R = 8.31 J/mol*K, we can convert the units of pressure from atmospheres to pascals:

P2 = (1 atm * 101,325 Pa/atm * 376 K) / 200 K

P2 = (101,325 * 376) / 200

P2 = 75937.5 Pa

So, the new pressure of the gas is approximately 75,937.5 Pa or approximately 0.759 atm.

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The new pressure of the ideal gas would be 1.88 atm

Pressure law

According to Pressure law, the pressure of a gas is directly proportional to the temperature of the gas, provided that the volume of the gas is constant.

Mathematically: p1/t1 = p2/t2

In this case, p1 = 1 atm, t1 = 200 K, and t2 = 376 K

P2 = p1 x t2/t1 = 1x376/200

                       = 1.88 atm

In other words, the new pressure of the ideal gas would increase to 1.88 atm from 1 atm.

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What did the Copernicus revolution demonstrate?

Answers

The Ptolemaic model of the heavens, which put the Earth in a fixed position at the center of the cosmos, was replaced by the heliocentric model, which placed the Sun at the center of the Solar System, during the Copernican Revolution.

Help with chemistry??

Help with chemistry??

Answers

Answer:

The first image = double replacement

Second = single replacement

Third = Decomposition

Fourth = Combination

Explanation:

1. a color from each pair is being swapped and replacing each other so there is a double replacement

2. only the blue and the red are changing places so it is single replacement

3. the pair is being separated (decomposed)

4. the red and green are coming together (combined)

Please help me do this

Please help me do this

Answers

The total mass of the balloon and its content is 1521.17 g, the number of moles of CO₂ in the balloon is 34.15 mol, and the number of CO₂ molecules in the balloon is 2.06 x 10²⁵ molecules.

a) The molar mass of CO₂ is 44.01 g/mol. To find the total mass of the balloon and its content, we need to add the mass of the balloon (20g) to the mass of the CO₂ inside the balloon.

Mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

Since the balloon is at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to find the number of moles of CO₂ in the balloon:

Volume of CO₂ = Volume of balloon = 765 L (at STP)

Number of moles of CO₂ = volume of CO₂ / molar volume of a gas at STP

                                          = 765 L / 22.4 L/mol

                                          = 34.15 mol

Mass of CO₂ = 34.15 mol x 44.01 g/mol

                       = 1501.17 g

Total mass of balloon and its content = 20 g + 1501.17 g

                                                               = 1521.17 g

b) Number of moles of CO₂ in the balloon is 34.15 mol

c) To find the number of CO₂ molecules in the balloon, we need to use Avogadro's number (6.02 x 10²³ molecules/mol).

Number of CO₂ molecules = number of moles of CO₂ x Avogadro's number

                                           = 34.15 mol x 6.02 x 10²³ molecules/mol

                                           = 2.06 x 10²⁵ molecules

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I need help with Discussion of chemical reaction of experiment Asp please!!

Answers

Answer:

may I help?............

pls someone help me when i get this done i am done with my work i will give brainlist to

Heat is often a by-product of an energy transfer, even when it is not intentional. Name one example where heat is an intentional product and one example where heat is not an intentional product of an energy transfer. Use details to support your answer.

Answers

Answer:

well i think coffe is an example cause it goes from hot to cold

Most modern catalytic converters in automobiles have a surface with a platinum-rhodium catalyst. For which of the following reactions is this catalyst used?

a. the conversion of nitric oxide into elemental nitrogen and oxygen gas
b. the conversion of carbon dioxide into bicarbonate
c. the conversion of carbon monoxide into carbon dioxide
d. the conversion of octane into carbon dioxide and water vapor

Answers

Answer:

a. the conversion of nitric oxide into elemental nitrogen and oxygen gas.

Explanation:

Hello,

In this case, combustion at the automobiles' motors is not complete since gasoline usually has a considerable nitrogen oxides content (NOx) which is highly toxic when giving off from the cars. For that reason, recent advancements have shown platinum-rhodium-based catalytic converters have the capacity to catalyze the conversion of nitrogen oxides to elemental nitrogen and oxygen which are nontoxic. For that reason, answer is a. the conversion of nitric oxide into elemental nitrogen and oxygen gas.

Regards.

What is true about dominant alleles? a They almost never appear as the trait. b They appear as the trait only when there are two of them c They appear as the trait over a recessive allele d They appear as the trait if there is not recessive allele

Answers

They appear as the trait over a recessive allele. Statement C) is true about the dominant alleles.

Dominant alleles are genetic variants that, when present in an individual's genotype, are expressed phenotypically, meaning they determine the visible or observable traits. Dominant alleles are represented by capital letters, while recessive alleles are represented by lowercase letters in genetics.

In terms of inheritance, if an individual has at least one copy of the dominant allele, it will be expressed in the phenotype, regardless of the presence of a recessive allele. This is because dominant alleles exert their influence over recessive alleles, thus "dominating" their expression.

To illustrate this, let's consider a specific example using a trait controlled by a single gene with two possible alleles: dominant (A) and recessive (a). If an individual is homozygous dominant (AA), meaning they possess two copies of the dominant allele, the dominant trait will be expressed.

However, if an individual is homozygous recessive (aa), with two copies of the recessive allele, the recessive trait will be expressed since there are no dominant alleles to override it.

Therefore, dominant alleles appear as the trait over recessive alleles, regardless of the presence or absence of a recessive allele. The presence of even a single copy of the dominant allele is sufficient for its expression in the phenotype. Option C

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How many atoms of hydrogen in the product side of the balanced equation?
Fe + H2O ---> FeO + H2
A) 2
B) 3
C)6

Answers

Answer:

i think the answer should be a

How many atoms are in 12 g of Carbon-12 (12C)?

Answers

There are approximately 6.022 × 10^23 atoms in 12 grams of Carbon-12 (12C).

The number of atoms in a given amount of a substance can be calculated using Avogadro's number, which represents the number of atoms or molecules in one mole of a substance. Avogadro's number is approximately 6.022 × 10^23.

Carbon-12 is a specific isotope of carbon, with an atomic mass of 12 atomic mass units (amu). One mole of Carbon-12 has a mass of 12 grams. Since one mole of any substance contains Avogadro's number of particles, in the case of Carbon-12, it contains 6.022 × 10^23 atoms.

Therefore, if we have 12 grams of Carbon-12, which is equal to one mole, we can conclude that there are approximately 6.022 × 10^23 atoms in this amount of Carbon-12.

In summary, 12 grams of Carbon-12 contains approximately 6.022 × 10^23 atoms. Avogadro's number allows us to relate the mass of a substance to the number of atoms or molecules it contains, providing a fundamental concept in chemistry and enabling us to quantify and understand the microscopic world of atoms and molecules.

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An atom of an element has neutral change because the.......... ​

Answers

Answer:

They contain equal quantities of positively charged protons and negatively charged electrons

Explanation:

Atoms are electrically neutral because they contain equal quantities of positively charged protons and negatively charged electrons. Electrons and protons have equal but opposite charges, so the result is no net charge.

6. Balance the reaction
PCIS + H₂O → H3PO4 + HCI

Answers

The balanced chemical equation for the reaction is:

PCl5 + H2O → H3PO4 + HCl

To balance this equation, we need to make sure that the number of atoms of each element is equal on both sides of the equation.

To do this, we can start by balancing the phosphorus (P) and chlorine (Cl) atoms. There is one P atom and five Cl atoms on the left side of the equation, and one P atom and one Cl atom on the right side of the equation. We can balance these by adding a coefficient of 5 in front of HCl:

PCl5 + H2O → H3PO4 + 5HCl

Now we have five Cl atoms on both sides of the equation. Next, we can balance the hydrogen (H) atoms. There are two H atoms on the left side of the equation and five H atoms on the right side of the equation. We can balance these by adding a coefficient of 2 in front of H2O:

PCl5 + 2H2O → H3PO4 + 5HCl

Now we have two H atoms on both sides of the equation. Finally, we can balance the oxygen (O) atoms. There are two O atoms on the left side of the equation and four O atoms on the right side of the equation. We can balance these by adding a coefficient of 2 in front of H3PO4:

PCl5 + 2H2O → 2H3PO4 + 5HCl

Therefore, to balance this reaction, we need to use this balanced chemical equation:

PCl5 + 2H2O → 2H3PO4 + 5HCl

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describe what xeriscaping is and what is involved in a successful xeriscaping project

Answers

Xeriscaping is a landscaping approach that focuses on conserving water by using drought-tolerant plants and efficient irrigation techniques. The goal is to create a visually appealing and sustainable garden while minimizing water usage.

Successful xeriscaping projects involve several key elements. Firstly, careful plant selection is crucial, opting for species that can thrive in arid conditions without excessive watering. Mulching is used to reduce evaporation and retain soil moisture.

Proper soil preparation, such as improving drainage and adding organic matter, promotes healthier plant growth. Efficient irrigation systems, like drip irrigation or soaker hoses, deliver water directly to plant roots, minimizing wastage.

Additionally, controlling erosion through the use of retaining walls or terracing is important. Lastly, regular maintenance, including appropriate pruning and weed control, ensures the longevity and vitality of the xeriscape garden. Overall, a successful xeriscaping project harmonizes sustainable practices with a beautiful outdoor environment.

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Calculate the pH at the equivalence point when 22.0 mL of 0.200 M hydroxylamine, HONH2, is titrated with 0.15 M HCl. (Kb for HONH2

Answers

Answer:

pH = 3.513

Explanation:

Hello there!

In this case, since this titration is carried out via the following neutralization reaction:

\(HONH_2+HCl\rightarrow HONH_3^+Cl^-\)

We can see the 1:1 mole ratio of the acid to the base and also to the resulting acidic salt as it comes from the strong HCl and the weak hydroxylamine. Thus, we first compute the required volume of HCl as shown below:

\(V_{HCl}=\frac{22.0mL*0.200M}{0.15M}=29.3mL\)

Now, we can see that the moles of acid, base and acidic salt are all:

\(0.0220L*0.200mol/L=0.0044mol\)

And therefore the concentration of the salt at the equivalence point is:

\([HONH_3^+Cl^-]=\frac{0.0044mol}{0.022L+0.0293L} =0.0858M\)

Next, for the calculation of the pH, we need to write the ionization of the weak part of the salt as it is able to form some hydroxylamine as it is the weak base:

\(HONH_3^++H_2O\rightleftharpoons H_3O^++HONH_2\)

Whereas the equilibrium expression is:

\(Ka=\frac{[H_3O^+][HONH_2]}{[HONH_3^+]}\)

Whereas Ka is computed by considering Kw and Kb of hydroxylamine:

\(Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{9.10x10^{-9}} \\\\Ka=1.10x10^{-6}\)

So we can write:

\(1.10x10^{-6}=\frac{x^2}{0.0858-x}\)

And neglect the x on bottom to obtain:

\(1.10x10^{-6}=\frac{x^2}{0.0858}\\\\x=\sqrt{1.10x10^{-6}*0.0858}=3.07x10^{-4}M\)

And since x=[H3O+] we obtain the following pH:

\(pH=-log(3.07x10^{-4})\\\\pH=3.513\)

Regards!

an element with the valence electron configuration 3s2 3p6 belongs to period

an element with the valence electron configuration 3s2 3p6 belongs to period

Answers

Answer:

The answer is D

Explanation:

The element is in the 3rd period because n = 3.

if there are more products than reactants, does that mean there is an increase in the forward or backward reaction? And if there are more reactants that products, is there an increase in the forward or backward reaction?

Answers

Answer:

If there are more products than reactants, that means the reaction has shifted towards the left, which is the backward direction. If there are more reactants than products, that means the reaction has shifted towards the right, which is the forward direction.

The chemical on this list which is not a humectant is: O sorbitol O glycerol O lanolin O methyl O alcohol

Answers

Option (e) is correct. Alcohol is not a humectant because it binds to water and dehydrates the body.

Humectant is a substance which is used to keep things moist. A humectant attracts and retains the moisture in the air nearby via absorption. Sorbitol is a naturally occurring polyol. It is widely used in the food industry as a humectant. Sorbitol is a good humectants. Glycerol is a humectant which is most often derived naturally from vegetable oils. Humectants work to preserve other skincare ingredients and retain moisture by drawing water from the surface of your skin down into the deeper skin layers. Lanolin oil softens the skin and is a good humectant making it ideal for use in you skin care products. Methyl is an extremely effective humectant for both rinse off and leave on products. It is recommended for use in skin care products including lotions and creams.

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PLEASE HELP. !!
A 15kg student climbs 3m to get to the top of the stairs. What is the potential energy of the student ?

Answers

Answer:

Potential energy = 441 N

Explanation:

Given:

Mass M = 15 kg

Height = 3 m

Find:

Potential energy

Computation:

Potential energy = mgh

Potential energy = (15)(9.8)(3)

Potential energy = 441 N

Which of these substances would be an alkali?
A substance which turns universal indicator orangeA substance with a pH of 1A substance which turns universal indicator blueA substance with a pH of 7

Answers

A substance which turns universal indicator blue. It’s not pH 1 cause it’s acidic. And pH 7 is neutral not alkali.
Hope u understood.
Pls give me the brainliest

The water vapor that condenses low to the ground and becomes visible is known as ___________.

Answers

Water droplets I think
I’m sorry if I’m wrong but I’m pretty sure that’s the answer:)

A type of emergency apparatus that can be used where oxygen may be limited or where the air might be poisoned is based on the following reaction in which CO2 produced by your own respiration reacts and O2 gas is produced. Calculate the mass of KO2 needed to produce 25 g of oxygen gas.

4 KO2(s) + 2 CO2(g)  2 K2CO3(s) + 3 O2 (g)

Answers

Answer:

so I don't know how to answer that

Strontium hydroxide reacts with hydrobromic acid to produce Strontium bromide and
water.
Write and balance the chemical reaction above, use it for problems 1-4 below:
1. If 5.50 moles of strontium hydroxide were consumed, how much moles of water are
produced?
2. Find the mass of hydrobromic acid used to produce 7.50 moles water.
3. If 10.8 g of strontium hydroxide were used, how much moles of strontium bromide are
produced?
4. If 13.3 g of hydrobromic acid were consumed, find the mass of the water produced.

Answers

The chemical reaction for the reaction of strontium hydroxide with hydrobromic acid is:

Sr(OH)2 + 2 HCl --> SrCl2 + 2 H2O

To find the moles of water produced when 5.50 moles of strontium hydroxide are consumed, we need to apply the law of conservation of mass. The mass of water produced is equal to the mass of strontium hydroxide consumed. Since strontium hydroxide has a molar mass of 142 g/mol and water has a molar mass of 18 g/mol, 1 mol of strontium hydroxide can produce 9 mol of water. Therefore, 5.50 moles of strontium hydroxide can produce 49.5 mol of water.

Similarly, 7.50 moles of water can be produced by reacting 18 moles of hydrobromic acid with strontium hydroxide. Hydrobromic acid has a molar mass of 79.9 g/mol, so 18 moles of hydrobromic acid would have a mass of 79.9 * 18 = 1435.2 g.

To find the moles of strontium bromide produced when 10.8 g of strontium hydroxide is used, we need to apply the law of conservation of mass again. The mass of the strontium bromide produced is equal to the mass of strontium hydroxide consumed. Since strontium bromide has a molar mass of 410 g/mol and strontium hydroxide has a molar mass of 142 g/mol, 1 mol of strontium bromide can consume 3.23 moles of strontium hydroxide. Therefore, 10.8 g of strontium hydroxide can produce 10.8 / 3.23 = 3.34 moles of strontium bromide.

Finally, to find the mass of water produced when 13.3 g of hydrobromic acid is consumed, we need to apply the law of conservation of mass yet again. The mass of the water produced is equal to the mass of hydrobromic acid consumed. Since hydrobromic acid has a molar mass of 79.9 g/mol, 13.3 g of hydrobromic acid would produce 13.3 / 79.9 = 0.166 moles of water.

According to the octet rule, an atom is usually stable when it has _____ valence electrons.
A. 4
B. 8
C. 6
D. 10

Answers

Answer:

B. 8

Explanation:

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