if 84.9 grams of solid iron reacts with oxygen gas, how many molecules of oxygen will react

Answer:

Within smokestacks and tailpipes

Explanation:

this is where manmade ozone is usually produced

The final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

To determine the final concentration of I ions in the resulting solution, we need to consider the stoichiometry and volumes of the solutions being mixed.Given:

Volume of NH4l solution = 129.13 mL

Concentration of NH4l solution = 112.9 mM = 0.1129 M (converting from millimolar to molar)

Volume of Mgl2 solution = 105.31 mL

Concentration of Mgl2 solution = 0.87 M

First, we need to determine the moles of NH4l and Mgl2 in their respective solutions:

Moles of NH4l = Volume of NH4l solution * Concentration of NH4l solution

Moles of NH4l = 0.12913 L * 0.1129 M = 0.01459 moles NH4l

Moles of Mgl2 = Volume of Mgl2 solution * Concentration of Mgl2 solution

Moles of Mgl2 = 0.10531 L * 0.87 M = 0.09157 moles Mgl2

Next, we determine the limiting reagent, which is the reactant that is completely consumed and determines the maximum amount of product formed. In this case, the limiting reagent is NH4l because it has fewer moles than Mgl2.

The balanced chemical equation for the reaction between NH4l and Mgl2 is:

2 NH4l + Mgl2 → 2 NH4+ + MgI2

From the balanced equation, we can see that for every 2 moles of NH4l, we get 1 mole of MgI2.

Since the moles of NH4l is the limiting reagent, it will be completely consumed, and the moles of MgI2 formed will be half of the moles of NH4l.

Moles of MgI2 = 0.01459 moles NH4l * (1 mole MgI2 / 2 moles NH4l) = 0.007295 moles MgI2

Finally, we calculate the final concentration of I ions in the resulting solution:

Volume of resulting solution = Volume of NH4l solution + Volume of Mgl2 solution

Volume of resulting solution = 0.12913 L + 0.10531 L = 0.23444 L

Final concentration of I ions = Moles of MgI2 / Volume of resulting solution

Final concentration of I ions = 0.007295 moles / 0.23444 L = 0.0311 M

Therefore, the final concentration of I ions in the resulting solution is approximately 0.0311 M, expressed with three significant figures.

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Following the quantic theory, the energy of a photon equals the radiation frequency multiplied by the universal constant. ν = 2.923x10¹⁵ Hz. E = 3.09x10¹⁵Hz.

It is the branch of physics that studies objects and forces at a very low scale, at atoms, subatoms, and particles levels.

Quantum mechanics states that the elemental particles that constitute matter -electrons, neutrons, protons- have the properties of a wave and a particle.

It emerges from the quantic theory exposed by Max Planck (1922), in which he affirmed that light propagates in energy packages or photons.

He discovered the Universal Planck constant, h, used to calculate the energy of a photon.

He stated that the energy of a photon (E) equals the radiation frequency (ν) multiplied by the universal constant (h).

E = νh

In the exposed example, we need to calculate the energy required to change from the 3rd shell to the first shell.

To do it, we should know that the energy in a level (Eₙ) equals the energy associated to an electron in the most inferior energy level (E₁) divided by the square of the shell number (n²).

Eₙ = E₁ / n²

E₁ is a constant. We can express it in Joules or electroVolts

So, let us calculate the energy at level 1 and 3

Eₙ = E₁ / n²

        E₁ =  -13.6 eV / 1² =  -13.6 eV

        E₃ =  -13.6 eV / 3² =  -13.6 eV / 9 = - 1.51 eV

The change of energy can be calculated in two ways,

Option 1

ΔE = E₁ - E₃ = 2.18x10⁻¹⁸ - 2.42x10⁻¹⁹ = 1.93x10⁻¹⁸J

ΔE = E₁ - E₃ = 13.6 - 1.51 = 12.09 eV

Option 2

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE =-13.6 eV (1/nf² - 1/ni²)

Where nf is the final level and ni is the initial level. When the electron passes from its initial level to its final level it is called electronic transition.

ΔE = -2.18x10⁻¹⁸ J (1/nf² - 1/ni²)

ΔE = -2.18x10⁻¹⁸ J (1/1² - 1/3²)

ΔE = -2.18x10⁻¹⁸ J (1 - 0.111)

ΔE = -2.18x10⁻¹⁸ J (0.888)

ΔE = - 1.937x10⁻¹⁸ J

or

ΔE = -13.6 eV  (1/nf² - 1/ni²)

ΔE = -13.6 eV  (1/1² - 1/3²)

ΔE = -13.6 eV  (1 - 0.111)

ΔE = -13.6 eV  (0.888)

ΔE = -12.08 eV

This is the energy required for the electron to go from n= 3 to n = 1. The negative sign (-) means energy (as light or photons) released or emitted.

If we want to express the result in Hz, we just need to make a conversion.

1Hz ⇔ 6.626x10⁻³⁴J ⇔ 4.136x10¹⁵ eV.

The energy required for the electron to go from n= 3 to n = 1 is 3.09x10¹⁵ Hz.

Now, we need to calculate the frequency, ν. This is, how many times the wave oscillates back and foward per second.

To do it, we will use the universal Planck constant, h, and the absolute value of the energy, E.

ν = E/h = 1.937x10⁻¹⁸ J / 6.626x10⁻³⁴ Js = 2.923x10¹⁵ 1/s =  2.923x10¹⁵ Hz.

Answer:

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Answer:

compound

Explanation:

Answer:

The answer is compound

Explanation:

0.361 moles of N₂ were required to produce 12.3 g of NH₃, using the balanced chemical equation N₂ + 3H₂ → 2NH₃.

The balanced chemical equation for the reaction is N₂ + 3H₂ → 2NH₃. We can use the balanced equation and the molar mass of NH₃ to calculate the number of moles of N₂ required to produce 12.3 g of NH₃,

1 mol NH₃ = 2 mol N₂ (from the balanced equation)

molar mass of NH₃ = 17.03 g/mol

moles of NH₃ = 12.3 g / 17.03 g/mol

moles of NH₃ = 0.722 mol

moles of N₂ = (0.722 mol NH₃) / 2

moles of N₂ = 0.361 mol

Therefore, 0.361 moles of N₂ were needed to produce 12.3 grams of NH₃.

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Complete question - For the reaction, N₂ + 3H₂ → 2NH₃. Given 12.3 grams of NH3, how many moles of N₂ were needed?​

a. The Mass of water driven off = 0.15 g

b. Moles of anhydrate = 0.00257 moles

c. Moles of water driven off is 0.00833 moles

d. There are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. The molecular formula of the hydrated salt will be X.3H₂O

a. The mass of water driven off from the hydrated salt is:

Mass of water driven off = 0.5 g - 0.35 g

Mass of water driven off = 0.15 g

b. Molecular mass of salt = 136 g/mol

moles of anhydrate = 0.35/136

Moles of anhydrate = 0.00257 moles

c. Moles of water driven off = mass/molar mass

molar mass of water = 18 g/mol

Moles of water driven off = 0.15/18

Moles of water driven off = 0.00833 moles

d. Moles of water within the crystalline structure of one molecule of the hydrated salt is determined by converting to whole number mole ratio by dividing with the smallest ratio,

Salt to water ratio = 0.00257 /0.00257  :  0.00833/0.00257

Salt to water ratio = 1 : 3

Therefore, there are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. Assuming the anhydrous salt is X, the molecular formula of the hydrated salt will be X.3H₂O

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0.1621 mol FeCl₃

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Compounds

Atomic Structure

Step 1: Define

26.29 g FeCl₃ (iron (III) chloride)

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of FeCl₃ - 55.85 + 3(35.45) = 162.2 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

0.162084 mol FeCl₃ ≈ 0.1621 mol FeCl₃

Answer:

The object at the bottom of the yellow layer: 6 g/mL

The object at the bottom of the blue layer: 1.5 g/mL

The nut in the red layer: 3 g/mL

The object at the top of the yellow layer: 0.5 g/mL

Answer: D. Intensity

Explanation: Intensity is correct, because if you originally were working on a treadmill with a speed of 8, that is how much intensity your putting your body on. And if you put the speed for a treadmill at 11 to increase your exercise, you are increasing the speed you have to run, making it more intense. The more intense you make your workout or training, the more stressful exercise you are doing.

Hope this helps,

:)

Answer:

179g

Explanation:

Molar ratio for Copper : Lithium is

1:2

If there are 89.5g of copper

Grams for Lithium= 89.5 × 2 = 179g of Lithium

The amount of lithium are formed from the reaction if you begin with 89.5 grams of copper is 19.6 grams.

Mass can be converted into moles by using the below equation as:

n = W/M, where

W = given mass

M = molar mass

Moles of 89.5g of copper = 89.5g / 63.5g/mol = 1.4 mol

Given chemical reaction is:

Cu + Li₂S → 2Li + CuS

From the stoichiometry of the reaction, it is clear that

1.4 mole of Cu = produces 1.4 mole of CuS

1.4 mole of CuS = produced by 1.4 mole of Li₂S

1.4 mole of Li₂S = produces 2×1.4=2.8 moles of Li

Mass of 2.8 moles of Li = (2.8mol)(7g/mol) = 19.6g

Hence resultant mass of lithium is 19.6g.

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The volume of the acid that we are going to need in this case is 27000 mL.

We know that we have to know the reaction equation as this is the first step to solve the problem that we have here;

We know that;

CaCO3 + 2HCl → CaCl2 + H2O + CO2

Then we have that;

Molarity of the acid = Antilog (-1.55)

= 0.028 M

Number of moles of the base;

38 g/100 g/mol

= 0.38 moles

If 1 mole of the base reacts with 2 moles of the acid;

0.38 moles of the base reacts with 0.38 * 2/1

= 0.76 moles

Then;

Number of moles = Concentration * volume

Volume = Number of moles/Concentration

= 0.76/ 0.028

= 27 L or 27000 mL

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Answer:

1 - Gravitational.

2 - Normal

3 - Tension

4 - Frictional

5 - Centripetal

Explanation:

1. If you drop something, gravity pulls it down to the Earth, So falling towards the earth is gravity.

2. Pushing back on another object is normal, Newton's law: Every action has an equal and opposite reaction.

3. When two forces are pulled on opposite sides, the object must stretch which creates tension. Think of a rubber band. If it is pulled more than the object can stretch, it will tear. Tensile strength refers to how much pulling force an object can withstand before it tears.

4. When objects or molecules rub against other objects or molecules they create friction.

5. Last two options go together.

a. [C]: \(HCl\) or any other strong acid b. [S]: Lead acetate or any other heavy metal salt c. [I]: Lead nitrate or silver nitrate

a. To confirm the presence of \(CO_32\)-, a solution of dilute \(HCl\) (hydrochloric acid) is added. If \(CO_32\)- is present, it will react with the \(HCl\) to produce \(CO_2\) gas, which can be identified by bubbling it through limewater \((Ca(OH)_2)\).

b. To confirm the presence of \(S_2\)-, a solution of lead acetate \((Pb(CH_3COO)_2)\) is added. If \(S_2\)- is present, it will react with the lead acetate to produce a black precipitate of lead sulfide (\(PbS\)).

c. To confirm the presence of I-, a solution of chlorine water (\(Cl_2\) in water) is added. If I- is present, it will react with the chlorine to produce a brown color, which is due to the formation of iodine (I2).

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These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Option B)

A colloid is a type of mixture in which particles are dispersed throughout a medium, creating a homogeneous appearance. Unlike solutions, where the particles are completely dissolved, and suspensions, where the particles settle out, colloids have particles that are larger than those in solutions but smaller than those in suspensions. One characteristic of colloids is that they can scatter light due to the size of the particles. This scattering of light is known as the Tyndall effect. Examples of colloids include milk, fog, and aerosol sprays. These substances have dispersed particles that are large enough to scatter light, making the beam visible. Therefore, out of the options provided, a mixture that scatters light is an example of a colloid. Therefore option B) is correct

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Note Complete Question

which is an example of a colloid?

a mixture that settles out,

b mixture that scatters light,

c mixture that is separated by filtration,  

d salt and water mixture?

To calculate the moles of H+ and OH-, you need to know the concentration of the solution in terms of its pH or pOH value.

When you get the pH of the solution, you can use this formula to calculate the concentration of H+ ions: [H+] = 10^(-pH)

Also, if you know the pOH of the solution, you can use this formula to calculate the concentration of OH- ions: [OH-] = 10^(-pOH)

Having determined the concentration of H+ and OH- ions, the molarity formula can be used to calculate the number of moles of each ion as follows: moles = concentration (in mol/L) x volume (in L)

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Answer:

b

Explanation:

The conserved quantities obeys the conservation laws. Among the given options mechanical energy and mass are examples of conservable quantities. The correct option is C.

A conserved quantity is defined as something which remains constant in amount over time and it cannot be created nor destroyed. In an isolated system, energy is an example of a conserved quantity.

The conserved quantities can change form one state to another, for example from light to heat, but the total amount of energy in the system will not change. Some of the other examples of conserved quantities are electric charge, momentum and angular momentum.

The mass can neither be created nor be destroyed, so it is a conserved quantity. Similarly the mechanical energy which is the sum of potential and kinetic energy is also conserved.

Thus the correct option is C.

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Answer:

C. 6

Explanation:

The atomic number of a number is related to the number of protons in the nucleus.

Answer:

The correct answer is - option C. Law of superposition.

Explanation:

According to the law of superposition states that within a sequence of layers of natural sedimentary rock without any disturbance, the oldest layer is lies under the younger layers with ascending order in the sequence.

If a sedimentary rock has 4 layers as a, b, c and d where the younger layer d would be on top and the oldest layer a would be at the bottoms.

Thus, the correct answer is - option C.

Answer:

C.Law of superposition

Explanation:

C is the correct answer because it is the law of superposition

Answer:

OC. Fe³+

Explanation:

Greater reduction potential (bigger positive E value) means that things wants to get electrons. For this, you have to look at the chart that I have attached. Since, Fe3+ has highest E value out of other options, it will likely be reduced.

The species which is most likely to get reduced is Fe³⁺.

Reduction is the process of the addition of electrons and loss of oxygen atoms. It is part of redox reactions.

Redox reactions are the type of reactions in which oxidation and reduction simultaneously take place. Oxidation is the addition of oxygen atoms. Reduction is the removal of oxygen atoms.

Redox reaction can be represented as:

PbO (s) + H₂ (g) → Pb(s) + H₂O (l)

In the above reaction, PbO is getting reduced and H₂ is getting oxidized.

Fe³⁺ is most likely to get reduced because the more positive the value of reduction potential, the more will be its tendency to get reduced.

In the given four species, the value of the reduction potential of Fe³⁺ is the highest.

Values of the reduction potential of four species are:

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At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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Answer:

1) easy compressed

2) fills its container

3) far more space

Explanation:

The molecules in a copper penny is closely packed and and has no space to move apart thus the material will be denser than that in the molten state. That's why the penny sink in the molten copper.

Copper is a transition metal exhibiting all the metallic properties. The molten state of metals is the fluid state where the molecule are not strongly held by the metallic bonds.

Molten material is made by melting them and the liquid like state contains molecules with some space to move apart. Whereas, in solid state as in a copper penny, the molecules are closely packed and have no space to move apart.

An object will sink in a liquid if it is less dense than the liquid. Copper penny is denser than the molten copper because the molecules are densely packed and it will sink on to it.

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Answer:

that the poem needs to be finished heh pog

Explanation:

Answer:

Where is the poem?

Explanation:

Answer:

17.5 Km

Explanation:

T = 3.5 hours

v = 5 K/hr

S = VT

S = 5 × 3.5

S = 17.5 Km

Answer:

The entropy change in the environment is 3.62x10²⁶.

Explanation:

The entropy change can be calculated using the following equation:

\(\Delta S = \frac{Q}{k_{B}}(\frac{1}{T_{f}} - \frac{1}{T_{i}})\)

Where:

Q: is the energy transferred = 5.0 MJ

\(k_{B}\): is the Boltzmann constant = 1.38x10⁻²³ J/K  

\(T_{i}\): is the initial temperature = 1000 K

\(T_{f}\): is the final temperature = 500 K

Hence, the entropy change is:

\( \Delta S = \frac{5.0 \cdot 10^{6} J}{1.38 \cdot 10^{-23} J/K}(\frac{1}{500 K} - \frac{1}{1000 K}) = 3.62 \cdot 10^{26} \)                                    

Therefore, the entropy change in the environment is 3.62x10²⁶.

I hope it helps you!          

Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals. For example, the electron configuration of the neon atom is 1s² 2s² 2p⁶, using the notation explained below

Explanation: welcome

The empirical formula for each compound are as follow,

a)\(Ag_2 O\)

b)\(Co_3As_2O_8\)

c)\(SeBr_4\)

As per the data share in the above question are as follow,

The mass of their constituent elements are as follow,

a) Ag=1.651 g

   O=0.1224 g

b)Co =0.672 g

    As =0.569 g

    O=0.486 g

c) Se =1.443 g

    Br =5.841 g

We have to calculate the empirical formula for each compound.

a)Now Moles of (given mass upon Molar mass) \(Ag=\frac{1.651}{108} =0.015 \:moles\)

Moles of \(O=\frac{0.1224}{8\times 2} =0.0077 \:moles\)

Smallest mole value \(0.0077 \:moles\)

Divide all component by smallest mass.

Therefore \(Ag \Rightarrow\frac{0.015}{0.0077} \rightarrow2\\\\O \Rightarrow\frac{0.0077}{0.0077} \rightarrow1\)

Combine to get empirical formula,

\(Ag_2 O\)

b)Now Moles of (given mass upon Molar mass) \(Co=\frac{0672}{59} =0.011 \:moles\)

Moles of \(As=\frac{0.569}{75} =0.0076\: moles\)

Moles of \(O=\frac{0.486}{16} =0.0304 \:moles\)

Smallest mole value \(0.0076 \:moles\)

Divide all component by smallest mass.

Therefore

\(Co \Rightarrow\frac{0.011}{0.0076} \rightarrow1.5\rightarrow1.5 \times 2\rightarrow3\\\\As \Rightarrow\frac{0.0076}{0.0076} \rightarrow1\rightarrow1 \times 2\rightarrow2\\\\O \Rightarrow\frac{0.0304}{0.0076} \rightarrow4\rightarrow4 \times 2\rightarrow8\)

Combine to get empirical formula,

\(Co_3As_2O_8\)

c)Now Moles of (given mass upon Molar mass) \(Se=\frac{1.443}{79} =0.018 \:moles\)

Moles of \(Br=\frac{5.841}{80} =0.073 \:moles\)

Smallest mole value \(0.018 \:moles\)

Divide all component by smallest mass.

Therefore

\(Se \Rightarrow\frac{0.018}{0.018} \rightarrow1\\\\Br \Rightarrow\frac{0.073}{0.018} \rightarrow4\)

Combine to get empirical formula,

\(SeBr_4\)

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