If a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s, the average acceleration is 1.62m/s².
How to calculate acceleration?The acceleration of a moving body can be calculated by dividing the change in velocity (∆V) by the time taken. That is;
a = v - u/t
Where;
a = accelerationv = final velocityu = initial velocityt = timeAccording to this question, a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s. The average acceleration is as follows:
acceleration = 21 - 0/13
acceleration = 1.62m/s²
Therefore, if a car decreases in speed to a stop from an initial speed of 21 m/s in a period of 13 s, the average acceleration is 1.62m/s².
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Jorge wants to know if yearly income and amount of tax returns are related in any way. In looking for an association between
these two variables, Jorge should utilize the method of research.
a. Correlational
b. Ethnographer
c. Naturalistic observation
d. Case study
We have that In looking for an association between these two variables, Jorge should utilize the
Correlational Research
This a research method that focuses on two variant variable and uses statistics to analyse the to achieve desired result
From The options we have that
a Correlational Research
This a research method that focuses on two variant variable and uses statistics to analyse the to achieve desired result
b. Ethnographer Research
This is simply the a Research method that focuses on variable mostly people in the Natural habitat and studies them or conversations with them for best results
c. Naturalistic observation Research
This method of research focuses on people in the Natural environment to determine their mental State .It is use mostly by Psychologists
d. Case study Research
This is is the use of real life testimonies to develop results to a particular Research it entails the study of Past events.
In conclusion the different variables
Having understood the different methods
In looking for an association between these two variables, Jorge should utilize the
Correlational Research
This a research method that focuses on two variant variable and uses statistics to analyse the to achieve desired result
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A force of 16N acts on a body of mass 90 kg for 2 min, if the body is initially at rest, the final velocity isA. 20.36 ms^- 1 B. 21.36 ms^- 1C. 22.36 ms^- 1D. 23.36 ms^- 1
Answer:
21.33 m s^-1
Explanation:
To find the final velocity, we will use the equation for impulse, so
\(I=Ft=mv_f-mv_i\)Where F is the force, t is the time, m is the mass, vf is the final velocity and vi is the initial velocity. We know that
F = 16 N
t = 2 min = 120 s
m = 90 kg
vi = 0 m/s
vf = ?
Solving for vf, we get:
\(\begin{gathered} Ft+mv_i=mv_f \\ \\ v_f=\frac{Ft-mv_i}{m} \end{gathered}\)Then, we can replace the values to get
\(\begin{gathered} v_f=\frac{(16\text{ N\rparen\lparen120 s\rparen- \lparen90 kg\rparen\lparen0 m/s\rparen}}{90\text{ kg}} \\ \\ v_f=\frac{1920\text{ kg m/s}}{90\text{ kg}} \\ \\ v_f=21.33\text{ m/s} \end{gathered}\)Therefore, the answer is
21.33 m s^-1
2. For electric circuit shown in Figure find currents in each resistor.
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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According to the FITT Principle you should exercise how many days ?
During a car collision, the knee, thighbone, and hip can sustain a force no greater than 4000 N. Forces that exceed this amount could cause dislocations or fractures. Assume that in a collision a knee stops when it hits the car's dashboard. Also assume that the mass of the body parts stopped by the knee is about 20% of the total body mass. The person with a mass of 50 kg is initially traveling at 11 m/s (25 mi/h). What minimum stopping time interval (in seconds) is needed to avoid injury to the knee
What type of atomic radiation will most deeply penetrate matter?
Multiple Choice
Beta radiation
Gamma radiation
Alpha radiation
Define measurement.
Answer:
Measurement is the comparison of any physical quantity of an object to a standard unit which is pre-determined. The standard units such as length, time, mass etc are known as the Fundamental units of Measurement.
Explanation:
Any object that can be measured is known as a physical quantity. So, to measure the physical quantity, we require some standard units. A measurement consists of two parts - the numerical measurement and the standard unit which is pre-determined. For example, the length of a given table is 10cm, which implies that 10 is the numerical value and the standard unit of measurement is centimeter (cm).
Measurements can be both Fundamental and Derived. Examples of Fundamental quantities are Length, Time etc, while example of Derived quantity is speed which is derived from Length and Time.
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A train car, which has a mass of 2000 kg, is rolling along with a velocity of 20 m/s East. It
strikes a stationary car, which also has a mass of 2000 kg, and they stick together after the
collision. What is their final velocity? (include appropriate units in your answer) * 15
10m/s East
Explanation:
p=mv
m1v1 = m2v
p = m1v1
2000kg*(20m/s) = 40000kg*m/s
Add the two masses together for m2
p = m2v2
40000kg*m/s = 4000kg * v2
v2 = 10m/s
Help me with this thanks!
Answer:
a. slope = 1
b. 70
c. y = 1.058x - 3.29 (it says under the graph)
d. about -3.29 or -3.3
hope this helps:)
Question 17 of 25
You place a book on top of a spring and push down, compressing the spring
by 10 cm. When you let go of the book, it is pushed up by the spring. Which
statement describes what happens to the energy of the spring-book system?
A. The kinetic energy of the system decreases.
B. The elastic potential energy of the system increases.
C. The gravitational potential energy of the system decreases.
D. The total energy of the system remains constant.
5. A ball is hit at 10.0 m/s at 30° above the horizontal. What is the net speed of the ball at the highest point of its motion?
The net speed of the ball at the highest point of the ball's motion which is hit at 10 m / s at 30° above the horizontal is 8.7 m / s
Net speed at the highest point of a projectile motion = Horizontal velocity component + Vertical velocity component
The direction of velocity of the ball is resolved into its horizontal and vertical components. It forms an right angled triangle.
cos θ = Adjacent side / Hypotenuse
cos θ = Horizontal component / Velocity
cos 30° = Horizontal component / 10
Horizontal component = 10 * 0.87
Horizontal component = 8.7 m / s
The vertical component of velocity at the highest point of a projectile motion is zero. Because as the ball moves higher the velocity decreases and finally reaches zero.
Net speed = 8.7 + 0
Net speed = 8.7 m / s
Therefore, the net speed of the ball at the highest point of the ball's motion is 8.7 m / s
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What forms when two air masses meet and create weather?
you are using a wrench to rotate a bolt around its center. consider all the forces in (figure 1), indicated by the arrows, to have the same magnitude. which of the following scenarios apply zero torque?
The following situations use no torque. C=D, A,B,E,C,D.
Describe a magnitude example.Size is referred to as magnitude. A automobile is traveling more quickly than a bike, for instance, when it comes to speed. In this case, the car is moving faster than the bike by a larger margin. It reveals the direction or size, whether absolute or relative, in which an object moves.
How big is a vector supposed to be?The vector's length determines its magnitude. The symbol for the vector's magnitude is a. To learn more about a vector's magnitude, see to its introduction. Vector magnitude formulas for two dimensions.
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Does the mass change how a bouncy ball bounces
Answer:
hiii what's up. and good morning hyd
Marco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?
The wave has traveled 32.4 cm in 3 seconds.
The wave has traveled 32.4 cm in 9 seconds.
The wave has traveled 97.2 cm in 3 seconds.
The wave has traveled 97.2 cm in 1 secondMarco is conducting an experiment. He knows the wave that he is working with has a wavelength of 32.4 cm. If he measures the frequency as 3 hertz, which statement about the wave is accurate?
The wave has traveled 32.4 cm in 3 seconds.
The wave has traveled 32.4 cm in 9 seconds.
The wave has traveled 97.2 cm in 3 seconds.
The wave has traveled 97.2 cm in 1 second
Taking into account the definition of wavelength, frecuency and propagation speed, the wave has traveled 97.2 cm in 1 second.
Wavelength, frecuency and propagation speedFirst of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length.
On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.
The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:
v = f×λ
Therefore, the previous expression establishes an inversely proportional relationship between the frequency and the wavelength: The higher the frequency, the lower the wavelength and when the frequency is lower, the greater the wavelength.
This caseIn this case, you know:
v=?f= 3 Hzλ= 32.4 cmReplacing in the definition of propagation speed:
v= 3 Hz× 32.4 cm
Solving:
v= 97.2 cm/s
In summary, the propagation speed is 97.2 cm/s. This indicates that the wave has traveled 97.2 cm in 1 second.
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Answer:
The wave has traveled 97.2 cm in 1 second.
Explanation:
took the test :)
explain why something falling reaches a top speed, draw free diagrams
PLEASE HELP URGETNT
When we look up into the night sky, we see
A) all the stars in the galaxy.
B) all the stars in the Milky Way.
C) only the stars surrounding Earth.
D) a few of the billions of stars in the galaxy.
Answer:
I think (d) is right answer
. The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth
A. The weight of the mass on the earth is 117.6 N
A. The weight of the mass on the moon is 19.56 N
How do i determine the weight of the mass?Weight is defined as follow:
Weight (W) = mass (m) × Acceleration due to gravity (g)
W = mg
Now we shall determine the weight. Details below:
A. Weight on earth
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Weight on earth (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 9.8
Weight on earth = 117.6 N
B. Weight on moon
Mass (m) = 12 KgAcceleration due to gravity on earth (g) = 9.8 m/s² Acceleration due to gravity on moon (g) = (1/6) × 9.8 = 1.63 m/s² Weight on moon (W) =?Weight (W) = mass (m) × Acceleration due to gravity (g)
Weight (W) = 12 × 1.63
Weight on moon = 19.56 N
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Complete question:
The force of gravity on the Moon is said to be one-sixth of that on the Earth. What would a mass of 12 kg weigh; (a) on the Earth (b) on the moon
URGENT!!! 50 POINTS NO CHATGPT!
A fisherman notices that his boat is moving up and down periodically without any horizontal motion, owing to waves on the surface of the water It takes a time of 3.00 s for the boat to travel from its highest point to its lowest, a total distance of 0.650 m
mThe fisherman sees that the wave crests are spaced a horizontal distance of 5.90 m apart
Part A
How fast are the waves traveling?
Express the speed v in meters per second using three significant figures.
What is the amplitude A of each wave?
Express your answer in meters using three significant figures.
Answer:
Part A: \(1.97ms^{-1}\) (2 s.f.)
Part B: 0.33m (2 s.f.)
Explanation:
Part A:
Frequency = \(\frac{1}{period} = \frac{1}{3}\) Hz
Wavespeed = frequency x wavelength
Wavelength = distance between two crests = 5.90
Freq = 1/3 Hz
Therefore: Wavespeed = 1/3 x 5.90
Wavespeed = 1.967 ms^-1
Part B:
Amplitude = \(\frac{peak-to-peak- amplitude }{2}\)
Peak to peak amplitude = 0.65m
Amplitude = 0.65/2 = 0.325m = 0.33m 2sf
Use the image below to answer the following question (ruler not to scale).
If magnet B is moved closer to magnet A, how will magnetic potential energy be affected?
O. It will become zero.
O. It willincrease.
O. It will decrease.
O. It will stay the same.
Please help
Answer:
it depends on wether the + and - are facing eachother
or away from eachother
Explanation:
Answer:
Yes, they are correct, you need to include all parts of the question, don't just copy and paste the words. But in the diagram that was supposed to be there, the magnets' north poles are facing each other. Therefore they would push away from each other if they were to get any closer. So, the magnetic potential energy would decrease due to their movement away from each other. So your answer is (C. It will decrease.
Explanation:
X= -5, 1, 7,10,22 f(x)= 7,2,0,1,18 what is the domain of the range is 1
Answer:
Well if X= -5, 1, 7, 10, 22 and if f(x)= 7, 2, 0, 1, 18 than there is your answer.
Explanation:
[X= 1]
34. [8 Marks] A spring is compressed with a 5.0 kg mass by 20.0 cm from its equilibrium position. When the spring is released, the 5.0 kg mass travels along a smooth horizontal surface and then up a frictionless plane at 30° to the horizontal. Calculate the distance it would travel up the inclined plane before coming back down again.
Answer and Explaination:
To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.
1. Gravitational force:
The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.
2. Force exerted by the spring:
The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.
Given:
Mass (m) = 5.0 kg
Compression of the spring (x) = 20.0 cm = 0.20 m
Angle of the inclined plane (θ) = 30°
First, let's find the force exerted by the spring (F_spring):
F_spring = -kx
To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.
Next, let's calculate the gravitational force components:
Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ
Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ
Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.
At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).
Therefore, we have:
F_perpendicular = F_spring
mg * cosθ = -kx
Now, let's substitute the known values and solve for k:
(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m
49.0 N * 0.866 = -k * 0.20 m
42.426 N = -0.20 k
k = -42.426 N / (-0.20 m)
k = 212.13 N/m
Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:
PE_spring = (1/2) * k * x^2
PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2
PE_spring = 4.243 J
The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.
KE_max = PE_spring = 4.243 J
Next, we can calculate the height (h) the mass reaches on the inclined plane:
KE_max = m * g * h
4.243 J = 5.0 kg * 9.8 m/s^2 * h
h = 4.243 J / (5.0 kg * 9.8 m/s^2)
h = 0.086 m
The height the mass reaches on the inclined plane is 0.086 m.
Now, we can calculate the distance traveled.
A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.
Given data: Mass of the object, m = 5.0 kg, Displacement of the spring, x = 20.0 cm = 0.20 mAngle of the inclined plane, θ = 30°Calculating the spring constant, k. Using Hooke’s Law; F = -kx Where F is the restoring force required to bring the spring back to its equilibrium position.From the equation, F = ma For the object attached to the spring,m * a = -kx. On integrating,∫ma dt = -∫kx dt .On integrating the left side with limits from 0 to t and right side with limits from 0 to x, where the limits on the left are for acceleration and the right are for the displacement of the spring; mv - mu = -½ kx²At maximum compression, the velocity of the mass is zero, i.e., v = 0 and the initial velocity is also zero. Therefore, mv - mu = -½ kx²0 - 0 = -½ k (0.20)²∴ k = 25 N/mWork done on the spring in compressing it, W = ½ kx² = 0.5 * 25 * (0.20)² = 0.5 JSince the inclined plane is frictionless, the only force acting on the object will be the component of its weight acting along the plane. Hence, it will move up the incline with an acceleration of, a = g sin θ = 9.8 * sin 30° = 4.9 m/s²When the object has reached its maximum height, its velocity will be zero. Using the equation of motion; v² - u² = 2as0 - u² = 2as∴ s = u² / 2a. Now, the initial velocity of the object up the incline is,u = √(2gH)Where H is the height to which it climbs, and is given by, H = W / m g Where W is the work done on the object in lifting it to height H, and m is the mass of the object. W = 0.5 J, m = 5 kg. So, H = 0.5 / (5 * 9.8) = 0.0102 m∴ u = √(2gH) = √(2 * 9.8 * 0.0102) = 0.4525 m/sNow, the distance traveled by the object up the incline is,s = u² / 2a = (0.4525)² / (2 * 4.9) = 0.0214 m. When the object comes back down, it will travel the same distance down the incline, before coming to rest. Therefore, the total distance travelled up and down the incline is,2s = 2 * 0.0214 = 0.0428 m.For more questions on the spring constant
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A capacitor is connected to a 9 V battery and acquires a charge Q. What is the charge on the capacitor if it is connected instead to an 18 V battery
An athlete can exercise by making mechanical waves in ropes. What is the
medium of these waves?
A. Energy
B. The rope
C. The athlete
D. Air
Answer:
It would be B. The Rope
Explanation:
I say this because the rope is transferring energy from one location to another. Now, I could be totally wrong on this but I think this is right lol.
Answer:
The answer is B the rope.
Hope this helps <3 ;)
person a and b traveling away from each other. It takes person a 2 hours to travel a full circle, and person b 5 hours to travel a full circle. how much time will it take for a and b to meet?
Let the circumference of the circle be 10L.
A moves at 10L/2 = 5L per hour
B moves at 10L/5 = 2L per hour
Therefore it takes 10L/(5L+2L) = 10/7 hours
101. A propeller is accelerated from rest to an angular velocity of 1000 rev/min over a period of 6.0 seconds by a constant torque of 2.0×103N⋅m . (a) What is the moment of inertia of the propeller? (b) What power is being provided to the propeller 3.0 s after it starts rotating?
The power being provided to the propeller 3.0 seconds after it starts rotating is approximately 21.8 MW and the moment of inertia of the propeller is approximately 0.55 kg⋅m².
What kind of forces do hydraulic systems produce?In hydraulic systems, forces are transferred from one area to another inside an incompressible fluid, such as water or oil. Most aircraft's landing gear and braking systems are hydraulic. In order to function, pneumatic systems need a compressible fluid like air.
I = (τt²) / (2πΔθ)
Substituting the given values, we get:
I = (2.0×10³ N⋅m × (6.0 s)²) / (2π × (1000 rev/min) × (1 min/60 s) × 2π)
I ≈ 0.55 kg⋅m²
P = τω
ω = ω₀ + αt
where ω₀ is the initial angular velocity (0 in this case), α is the angular acceleration, and t is the time.
ω = 0 + (τ/I)t
ω = (2.0×10³ N⋅m) / (0.55 kg⋅m²) × (3.0 s)
ω ≈ 10,909 rad/s
P = (2.0×10³ N⋅m) × (10,909 rad/s)
P ≈ 2.18×10⁷ W
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select and explain three features of the solar panel that maximises the final temperature of the water
Answer:
Irradiance (sunlight intensity or power), in Watts per square meter falling on a flat surface. ... Air Mass refers to “thickness” and clarity of the air through which the sunlight passes to reach the modules (sun angle affects this value). ... Cell temperature , which will differ from ambient air temperature
- A certain mass is suspended at one end of a spring of spring-constant of 32,000gm/s2. The
time taken to execute 10 oscillations is 15 second.
(a) What is the time period?
(b) What is the value of mass suspended at the end of the spring.
Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.
Explanation:
in a typical cop movie we see the hero pulling a gun firing that gun straight up into the air and shouting
It is not recommended to fire a gun straight up into the air.
When a bullet is fired into the air, it will eventually come down and can pose a danger to people and property below. The bullet can still be lethal when it reaches the ground, especially if it lands on a hard surface or hits someone directly.
Additionally, firing a gun in a residential area can be illegal and can result in legal consequences. In general, guns should only be fired in designated shooting ranges or in self-defense situations where there is an immediate threat to life. It is important to handle firearms responsibly and follow all safety guidelines to prevent accidents and injuries.
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A diver jumps from a 3.0 m board with an initial upward velocity of 5.5 m/s. What is the time the diver was in the air?
The answer is that the time the diver was in the air is 1.13 seconds.
To determine the time the diver was in the air, we can use the kinematic equation:
Δy = viΔt + 1/2at²,
where Δy is the displacement, vi is the initial velocity, a is the acceleration due to gravity (g), and t is the time.The initial velocity, vi, is given as 5.5 m/s, and since the diver jumps upwards, the displacement, Δy, is equal to the height of the board, which is 3.0 m. The acceleration due to gravity, a, is -9.8 m/s² (negative because it acts downwards).Substituting the known values into the equation:3.0
m = (5.5 m/s)t + 1/2(-9.8 m/s²)t²
Simplifying, we get:
4.9t² + 5.5t - 3.0 = 0
We can solve for t using the quadratic formula:
t = (-5.5 ± √(5.5² - 4(4.9)(-3.0))) / (2(4.9))= (-5.5 ± 1.59) / 9.8= -0.47 s or 1.13 s
Since time cannot be negative, the time the diver was in the air is 1.13 seconds.
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