If a galaxy has an apparent velocity of 2300 km/s, what is its distance if the Hubble constant is assumed to be 70 km/s/Mpc

Answer:

What is the frequency of ocean waves that have a speed of 18 m/s and wavelength of 50 m/s?

0.36hz

The frequency of the wave is 0.36 Hz.

Frequency of a wave is defined as the number of oscillations completed by the wave in one second.

Here,

Speed of the wave, v = 18 m/s

Wavelength of the wave, λ = 50 m

We know that, the equation for the speed of a wave is given as,

v = fλ

where f is the frequency of the wave.

Therefore, frequency,

f = v/λ

f = 18/50

f = 0.36 Hz

Hence,

The frequency of the wave is 0.36 Hz.

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Answer:

water vapor is a type of gas

Explanation:

all gas are in air state of form

hope this helps

Answer:

chemical potential energy

Explanation:

When the sun's radiant energy falls on Earth's oceans, it causes water to change state by evaporating. The form of energy water vapor have is chemical potential energy. when heat energy of sun falls on water surface, its state change from liquid to gas. This gas rises above in the form of water vapor. Its a chemical change. If this vapor get condense/ cool, it will turn into liquid again. We can say that vapor has potential to transform into water again. Thus, the energy stored in water vapor is called chemical potential energy.

(1) The moment of 20N about the wheel is 30 Nm. (2) The distance of the wheel to the center of mass of the wheelbarrow is 1.2m.

1. The moment of 20N about the wheel can be calculated using the formula:

Moment = Force x Distance

Moment = 20N x 1.5m

Moment = 30 Nm

2. To find the distance of the wheel to the center of mass of the wheelbarrow, we can use the principle of moments, which states that the sum of the clockwise moments about a point is equal to the sum of the anticlockwise moments about the same point. Let the distance from the wheel to the center of mass be x.

Clockwise moment = Weight x Distance

Clockwise moment = 80N x (1.5m - x)

Anticlockwise moment = Upforce x Distance

Anticlockwise moment = 20N x x

Using the principle of moments:

80N x (1.5m - x) = 20N x x

Simplifying and solving for x:

120m = 100x

x = 1.2m

Therefore, the distance of the wheel to the center of mass of the wheelbarrow is 1.2m.

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At the temperature -40°C (-40°F), can you throw water in the air and it freezes.

This is known as the "flash freezing" point. It is the temperature at which water droplets instantly freeze when they come into contact with cold air.

This will occur in some actual temperature also. That will depend on various factors such as the size of the water droplets, the humidity of the air, and the speed of the wind.

The air around the freezing water droplets does not necessarily have to be in the temperature -40°C. For water to freeze in the air, the air temperature must be below this given temperature in at least some of the places. In many places the this is true also.

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Answer:

Hello friend where is the figure of the question

The motion or path of the tennis ball is the path of a projectile, which has

both vertical and horizontal motion.

The total horizontal distance traveled by the tennis ball during the entire

time it is in the air ≈ 16.514 meters.

Reasons:

The given parameters are;

The direction in which the ball is launched = 45°

The initial vertical velocity of the ball, \(v_y\) = 9.0 m/s

The initial horizontal velocity of the ball, vₓ = 9.0 m/s

The time it takes the ball to reach the maximum height, t = 0.92 seconds after its launch

The total horizontal distance traveled, by the tennis ball is given by the formula;

\(\Delta d_x = \dfrac{v_1^2 \cdot \left( 2 \cdot cos(\theta) \sin(\theta)}{y} = \dfrac{2 \times v_x \times v_y}{g}\)

Which gives;

\(\mathrm{The \ total \ distance \ travelled, \ \Delta} d_x = \dfrac{2 \times 9.0\times 9.0}{9.81} \approx 16.514\)

The total horizontal distance traveled by the tennis ≈ 16.514 meters

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This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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The angular momentum of the stick after collision will be 150 kg -m²-s. Option A is the correct.

Torque is the force's twisting action about the axis of rotation. Torque is the term used to describe the instant of force. It is the rotational equivalent of force.

The amount of torque is equal to force multiplied by the perpendicular distance between the point of application of force and the axis of rotation.

Total torque operating on the stick (in relation to the pivot at right) when all four forces are acting on it is found as;

\(\rm T_{total} = F_1 r_1 + F_2 r2 - F_3r_3 - F_4 r_4 \\\\\ T_{total} = F = (200 \times 0.5 ) + ( 100 \times 1.0 ) - ( 50 \times 1.5) - (25 \times 2.0) \\\\\ T_{total} = 75 N.m\)

The initial angular momentum(Li) is given zero. The final angular momentum is found as the sum of the initial angular momentum and the product of total torque and the time period.

The final angular momentum is found as;

\(\rm L_f = L_i + T_{total}\times t\\\\ L_f = ( 0 + 75.0 \times 2.0)\\\\ L_f = 150 kg.m^2.s\)

Hence, the angular momentum of the stick after collision will be 150 kg -m²-s.

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Answer:

Hi there!

There are many possible answers!

My best guesses are:

1) Knowing how they work will prevent injury! For example, knowing that the gears twist will stop you from putting your finger in it!

2) Allowing you to use it! Knowing how to line up the edge of the can with the tool will let you use it properly!

Hope this helps

The freezing point of the solution is - 3.53°C, when the concentration of the solute is 8.1 gm and water is 100gm.

The temperature at which a liquid turns into a solid under normal atmospheric pressure is known as the freezing point. A melting point, on the other hand, is the temperature at which a solid turns into a liquid at ordinary atmospheric pressure. The temperature at which solid and liquid phases coexist in equilibrium is a more precise definition of the freezing point. The temperature at which a substance melts (or freezes) at one atmosphere of pressure is known as the normal freezing point.

The amount of solute contained in a specific amount of solution is the substance's concentration. The number of moles of solute in 1 L of solution, or molarity, is used to express concentrations.

The concentration of Solute = 8.1gm and water = 100 gms, α = 0.9

We know that,

ΔTf = i(Kf)m

      = 1 + (n-1)α × 1.86 × 8.1/80 × 100/100

ΔTf = 1.91.861 = 3.53°C.

now, the freezing point of the solution = 0 - 3.53 = -3.53°C.

Hence, the freezing point of the solution is - 3.53°C, when the concentration of the solute is 8.1 gm and water is 100gm.

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Answer:

The efficiency of the Bluetooth speaker is 62.13 %.

Explanation:

Given;

input electrical energy of the Bluetooth speaker, = 573 J

output sound energy of the Bluetooth speaker, = 356 J

The efficiency of the Bluetooth speaker in transforming electrical energy into sound energy is given by;

\(Efficiency = \frac{0utput\ Energy}{1nput \ Energy} *100\% \\\\Efficiency = \frac{356}{573}*100 \% \\\\Efficiency = 62.13 \ \%\)

Therefore, the efficiency of the Bluetooth speaker is 62.13 %.

Answer:

.. answer explamkn

Explanation:

Answer:

The drawdown in a confined aquifer under transient conditions can be estimated using the Theis solution for the non-equilibrium radial flow of water. This solution is given by:

s = Q / (4πT) * W(u),

where s is the drawdown, Q is the pumping rate, T is the transmissivity, and W(u) is the well function (also called the Theis function) which depends on the variable u, where:

u = r²S / (4Tt),

where r is the distance from the pumping well and t is the time since pumping began.

Given T = 2500 m²/day, S = 1.0 x 10-3, and Q = 500 m³/day, we can calculate the drawdown at 10 m (r1 = 10 m) and 50 m (r2 = 50 m) for t = 150 days.

For (i) r1 = 10 m:

u1 = r1²S / (4Tt) = (10 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.000667

s1 = Q / (4πT) * W(u1) = 500 m³/day / (4π * 2500 m²/day) * W(0.000667).

For (ii) r2 = 50 m:

u2 = r2²S / (4Tt) = (50 m)² * 1.0 x 10-3 / (4 * 2500 m²/day * 150 days) = 0.01667

s2 = Q / (4πT) * W(u2) = 500 m³/day / (4π * 2500 m²/day) * W(0.01667).

Explanation:

Unfortunately, the well function W(u) cannot be evaluated directly without more specialized knowledge or tools. The well function is related to the exponential integral function, which requires numerical computation. You would typically use a table of values, a calculator with this function, or a computer program to evaluate it. After obtaining W(u), multiply it by the remaining fraction to find the drawdowns.

(a) For a(t) = t + 4 and v(0) = 5, the velocity at time t can be found by integrating the acceleration function, and then substituting t = 0 with the given initial velocity.

(b) The distance traveled during the time interval can be obtained by integrating the velocity function over the given range, from t = 0 to t = 10.

Scenario 1:

Given:

a(t) = t + 4

v(0) = 5

(a) Finding the velocity at time t:

Integrate the acceleration function a(t):

∫(t + 4) dt = (1/2)t² + 4t + C

Substitute t = 0 and v(0) = 5:

(1/2)(0)² + 4(0) + C = 5

C = 5

Therefore, the velocity at time t is:

v(t) = (1/2)t² + 4t + 5

(b) Finding the distance traveled during the time interval 0 ≤ t ≤ 10:

Integrate the velocity function v(t):

∫[(1/2)t² + 4t + 5] dt = (1/6)t³ + 2t² + 5t + D

Evaluate the integral at the upper and lower limits:

Distance = [(1/6)(10)³ + 2(10)² + 5(10)] - [(1/6)(0)³ + 2(0)² + 5(0)] = 383.33 units (approximately)

Scenario 2:

Given:

a(t) = 2t + 3

v(0) = -4

(a) Finding the velocity at time t:

Integrate the acceleration function a(t):

∫(2t + 3) dt = t² + 3t + C

Substitute t = 0 and v(0) = -4:

(0)^2 + 3(0) + C = -4

C = -4

Therefore, the velocity at time t is:

v(t) = t² + 3t - 4

(b) Finding the distance traveled during the time interval 0 ≤ t ≤ 3:

Integrate the velocity function v(t):

∫[(t^2 + 3t - 4)] dt = (1/3)t^3 + (3/2)t^2 - 4t + D

Evaluate the integral at the upper and lower limits:

Distance = [(1/3)(3)³ + (3/2)(3)² - 4(3)] - [(1/3)(0)³ + (3/2)(0)² - 4(0)] = 17.5 units

So, the distance traveled during the time interval 0 ≤ t ≤ 3 is 17.5 units.

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The complete question is:

The acceleration function (in m/s 2) and the initial velocity are given for a particle moving along a line. Find (a) the velocity at time t and (b) the distance traveled during the given time interval.

1. a(t)=t+4,v(0)=5,0⩽t⩽10 72. a(t)=2t+3,v(0)=−4,0⩽t⩽3

The energy gained by the cold water stream can be calculated using the equation: Q_cold = m_cold * C_cold * (T_mixture - T_cold)

Q_hot = m_hot * C_hot * (T_hot - T_mixture)

Q_hot is the energy lost by the hot water stream

m_hot is the mass flow rate of the hot water stream (given as 0.5 kg/s)

C_hot is the specific heat capacity of water (approximately 4,186 J/kg°C)

T_hot is the initial temperature of the hot water stream (80°C)

Since the energy gained by the cold water stream must be equal to the energy lost by the hot water stream, we can set up the following equation:

m_cold * C_cold * (T_mixture - T_cold) = m_hot * C_hot * (T_hot - T_mixture)

Now we can solve for m_cold:

m_cold = (0.5 * 4,186 * (80 - 42)) / (4,186 * (42 - 20))

m_cold ≈ 0.25 kg/s

Therefore, the mass flow rate of the cold water stream should be approximately 0.25 kg/s to achieve the desired mixture temperature of 42°C.

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Answer: KE = 34.425 kJ

Explanation:

KE = (1/2) mv^2

KE = (0.5)*(34kg)(45m/s)^2

KE = (0.5)*(34kg)(2025m^2/s^2)

KE = 34425 kg*m^2/s^2

1 Joule = 1 kg*m^2/s^2

KE = 34.425 kJ

To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

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Explanation:

Assume that the rock has a constant density,

then the density = volume/mass = 0.25g/cm^3.

Answer:

4 g/cm^3

Explanation:

Density can be found by dividing the mass by the volume.

d=m/v

We know that the mass of the rock is 24 gram. We also know the volume of the rock is 6 cubic centimeters.

m=24 g

v= 6 cm^3

Substitute the values into the formula and divide.

d= 24 g / 6 cm^3

d= 4 g/cm^3

The density of the rock is 4 grams per cubic centimeter.

The time required for the change in magnetic flux is 0.5 seconds.

The induced emf in a single loop of wire is given by the equation ΔΦ/Δt, where ΔΦ represents the change in magnetic flux and Δt represents the change in time. In this case, the change in magnetic flux is given as 0.850 - 0.110 = 0.740 Wb. The magnitude of the induced emf is given as 1.48 V.

To find the time required for this change in flux, we can rearrange the equation to solve for Δt:
Δt = ΔΦ / (induced emf)

Plugging in the given values:
Δt = 0.740 Wb / 1.48 V

Calculating this gives us:
Δt = 0.5 seconds

Therefore, the time required for the change in magnetic flux is 0.5 seconds.

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Thermodynamics can be said to be a branch of Physics which involves the transfer of heat and other energy forms.

Thermal energy is the energy possesed by a system due to its temperature.

In thermodynamics, during the transfer of thermal energy, energy is wasted due to entryopy. And entropy is the measure of disorder of a system.

Therefore, in amy thermodynamic system that deals with the transfer of thermal energy, the most ideal state for that system is Entropy

ANSWER:

A. Entropy

True. Neutron stars are some of the densest objects that we can directly observe in the universe. These stars are formed when a massive star undergoes a supernova explosion, and the core of the star collapses under its own gravity, creating a super-dense object that is composed almost entirely of neutrons.

The Neutron stars have a mass similar to that of the sun but are only about 10 miles in diameter, making them incredibly compact. Because of their extreme density, neutron stars have very strong gravitational fields and can cause the space around them to warp and bend. They also emit intense radiation, including X-rays and gamma rays, which can be detected by telescopes. Studying neutron stars can provide insights into the fundamental properties of matter, as well as the processes that occur in the most extreme environments in the universe.

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Answer:

Electric potential energy

Explanation:

The Electric potential energy of a system is less than that carried out by electrostatic forces during the development of the system (as long as charges are initially cut infinitely).

The change in potential energy between an initial and final configuration  is equal to minus the work done by the electrostatic forces.

Given

mj = 65 kg

mc = 78 kg

voj = 5.75 m/s

after collision

vfj = vfc = 0 m/s

Procedure

The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

The velocity before the collision would be 4.8m/s

Newton's law of cooling relates the temperature of an object with the time. This law is the following:

Where:

Since we are asked to determien time we need to solve for "t". To do that we will subtract the temperature of the surrounding from both sides:

Now, we divide by the factor multiplying "e":

Now, we use natural logarithm on both sides:

Now, we use the following property of logarithms on the right side:

This means that we can lower the exponent, like this:

Now, we divide both sides by "-r":

Now, we substitute the values:

Solving the operations:

Therefore, the time to wait is 20.15 minutes.

The given statement is true

Inertia is the tendency of an object to stay at rest or in motion

The work done by the tension force on Magnus can be calculated by multiplying the force exerted by the tension (1833 N) by the distance that Magnus pulls the bus (0.711 m). This is equal to 1303.48 Joules.

Since the rope is perfectly horizontal, the tension force is the only force acting on Magnus, and the work done is equal to the force multiplied by the distance. The force of 1833 N represents the maximum amount of work that can be done on Magnus, and the distance of 0.711 m represents the amount of work that was actually done on Magnus.

As a result, the work done on Magnus by the tension force is 1303.48 Joules.

1833×0.711=1303.48J

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Answer:

The best sources of essential amino acids are animal proteins like meat, eggs and poultry. When you eat protein, it's broken down into amino acids, which are then used to help your body with various processes such as building muscle and regulating immune function ( 2 ).

Explanation:

The total absolute pressure at the depth where the research submarine is located is approximately 2.4 x 10⁵ pascals or 2.4 atmospheres.

The total absolute pressure at a given depth in a fluid is given by the hydrostatic pressure formula: P = P₀ + ρgh, where P is the total pressure, P₀ is the atmospheric pressure (assumed to be 1 atmosphere or 1.01325 x 10⁵ pascals), ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth.

To calculate the total pressure at the given depth, we need to consider the pressure exerted by the fluid column above the depth as well as the atmospheric pressure. The density of seawater is approximately 1030 kilograms per cubic meter.

The thickness of the window is 8.0 cm (or 0.08 meters), the depth can be calculated as h = 0.5 × thickness = 0.5 × 0.08 = 0.04 meters.

Substituting the values into the formula, we get P = 1.01325 x 10⁵ + (1030 kg/m³) × (9.8 m/s²) × (0.04 m) ≈ 2.4 x 10⁵ pascals.

Converting to atmospheres, 2.4 x 10⁵ pascals is approximately 2.4 atmospheres (since 1 atmosphere is equal to 1.01325 x 10⁵ pascals).

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