If a hydrogen emission line appears at 656. 2 nm in the laboratory, what can we say about a cloud of hydrogen gas with this same emission line at 680. 2 nm?.

The magnitude of attractive forces between particles that compose matter determine the state of matter. Hence, if all particles of matter on earth have equal attractive forces, only a single state of matter (solid, liquid or gas) will exist on earth.

Matter exists in three states;

In solids, there exists the greatest magnitude of attractive forces between particles.

There are weaker inter-molecular attractive forces between liquid particles. However, inter molecular attractive  forces are almost non-existent in gases.

The reason for the existence of different states of matter on earth is difference in magnitude of inter molecular attractive forces in each state of matter.

If all particles of matter possess equal attractive forces, only one state of matter will be found on earth; either solid, liquid or gas.

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For a tetrahedral complex with four different monodentate ligands, there are two possible geometrical isomers: the cis isomer, where the identical ligands are adjacent to each other (i.e., either WX-ZY or WY-XZ), and the trans isomer, where the identical ligands are opposite to each other (i.e., either WX-YZ or WY-XZ).

Therefore, the number of geometric isomers for the [ZnWXYZ]2+ ion is two. It's worth noting that if any of the ligands were bidentate or polydentate, the number of isomers would be higher due to the possibility of different chelating modes.
In a tetrahedral [ZnWXYZ]2+ complex, there are no geometric isomers present. This is because a tetrahedral complex has a single symmetrical arrangement of the four monodentate ligands W, X, Y, and Z around the central metal ion Zn2+. Geometric isomerism arises when there are multiple possible arrangements of ligands around the metal ion, leading to distinct structures. However, in a tetrahedral complex, there is only one possible arrangement, and hence no geometric isomers can be formed.

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Answer: 243K

Explanation:

The pressure changes from 1.00 atm to approximately 1.033 atm when the gas is heated from 30.0 °C to 40.0 °C at a constant volume.

To determine the pressure change when a constant volume of gas is heated, we can use the Ideal gas law:

PV = nRT

Where:

P = Pressure

V = Volume (constant in this case)

n = Number of moles of gas (constant in this case)

R = Ideal gas constant (0.0821 L·atm/(mol·K))

T = Temperature in Kelvin

We need to convert the temperatures from Celsius to Kelvin:

T1 = 30.0 °C + 273.15 = 303.15 K

T2 = 40.0 °C + 273.15 = 313.15 K

Since the volume and number of moles of gas are constant, we can rewrite the ideal gas law equation as:

P1/T1 = P2/T2

Now we can plug in the given values and solve for P2, which represents the pressure at the new temperature:

P1 = 1.00 atm

T1 = 303.15 K

T2 = 313.15 K

(1.00 atm) / (303.15 K) = P2 / (313.15 K)

Cross-multiplying and solving for P2:

P2 = (1.00 atm) × (313.15 K) / (303.15 K)

P2 ≈ 1.033 atm

Therefore, the pressure changes from 1.00 atm to approximately 1.033 atm when the gas is heated from 30.0 °C to 40.0 °C at a constant volume.

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Answer:

1) Anaerobic respiration

2) Lactic acid

3) Stop the work out

Explanation:

1) Anaerobic respiration

Muscular anaerobic respiration to produce energy during exercises or workout, takes place when the level of oxygen available for the amount of energy being generated is not sufficient, and the balance generated energy is produced along with lactic acid by anaerobic respiration

2) Lactic acid

The produced lactic acid from the anaerobic respiration at the muscle sites results in a burning sensation being felt during strenuous muscular activity in the presence of low oxygen supply

3) Stop the work out

In order to stop the burning, the muscular activity is to be stopped, to allow the resumption of the aerobic process of energy production, and to allow the produced lactic acid to be cleared

Answer:

Unicellular organisms consist of only one cell and multicellular organisms consist of many cell.

Explanation:

Living things made up of a cell are called unicellular beings. They are very small and simple. In other words, unicellular organisms are those that are formed only by a single cell in which all the vital functions necessary for life are produced. For this reason, they are mostly microscopic organisms. Examples of unicellular organisms are viruses or bacteria.

Multicellular organisms are made up of a large number of cells. They present, therefore, a greater complexity than unicellular organisms in terms of the functions they develop. All current multicellular organisms come from a single cell, that is, they begin their life being unicellular. That is, they are formed from a zygote. Some examples of multicellular organisms are mammals, fungi, and mosses.

So, unicellular organisms consist of only one cell and multicellular organisms consist of many cell.

Approximately 9,220 years have passed since the 14C level in the sample of organic matter has been reduced to 0.200% of its original value.

Radioactive decay of carbon-14 follows first-order kinetics, which means the decay rate is proportional to the amount of remaining radioactive material.

The half-life of carbon-14 is 5730 years, which is the time it takes for half of the radioactive carbon-14 atoms in a sample to decay.

To determine the time elapsed, we can use the formula for the decay of a first-order reaction:

t = (ln(N₀/N)) / k,

where t is the time elapsed, N₀ is the initial amount, N is the final amount (0.200% of the original value), and k is the decay constant. The decay constant (k) can be calculated as ln(2) divided by the half-life (5730 years).

Substituting the values into the equation, we can solve for t. The result is approximately 9,220 years.

Therefore, approximately 9,220 years have passed since the 14C level in the sample of organic matter has been reduced to 0.200% of its original value.

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Answer: Water (H2O)  And Hydrogen peroxide (H2O2)

Explanation:

Answer:

6.022x10 with an exponent of 2 and then you write three after

Explanation:

Answer:

Explanation: 6.022 x 10 raised to 23

Answer:

B

Explanation:

AlCl3 + NaOH → Al(OH)3 + NaCl

a) 3, 1, 3, 1

b)1, 3, 1, 3

c) 1, 1, 1, 3

d) 1, 3, 3, 1

cause there are 3Cl= AlCl3; NaCl must be 3 as well

So answers (a) and (d) are wrong

Then cause it is 3NaCl and there are (OH)3 so it must be 3NaOH.

Answer:

It will shift toward the reactant side as there is lower pressure on the reactant side.

Explanation:

There are more moles of gaseous reactants (4) than moles of gaseous products (2). Thus, any change in pressure will affect the reactants side more than the products side. Decreasing pressure decreases the pressure of the reactant side more than that of the product side. Thus, the reaction will shift to the reactants side to reestablish a pressure equilibrium.

Answer:

0.00757 grams

Explanation:

Find the molar mass of the compound: which is 60.05.

The molar mass is basically just the sum of all the atomic masses of each of the elements.

Then multiply the molar mass by the number of moles in the compound, which is 1.26 x 10^-4 moles.

Your answer should be 0.00757 grams.

Answer

b. It produces carbon dioxide when burned in pure oxygen.

Explanation

The reaction between diamond and oxygen, producing carbon dioxide is not a physical property of diamond, it is a chemical property because breaking and synthesis of chemical bonds occur.

a) Subscript (s) means solid or precipitate.

b) CdSO₄ (aq) → Cd²⁺ (aq) + SO₄²⁻(aq) and K₂S(aq) → 2K⁺ (aq) + S²⁻ (aq). There are 4 types of ions present in the solution Cd²⁺, SO₄²⁻, 2K⁺ and S²⁻.

c) Yellow to orange color precipitate will be seen after this reaction.

d) The reaction is known as double displacement or a precipitation reaction.

e) 2K⁺ and SO₄²⁻ are the ions still present in the solution.

The detailed answer to the questions related to the given equation are as follows:

Given equation: CdSO₄ (aq) + K₂S (aq) → CdS (s) + K₂SO₄ (aq)

a) The subscript (s) means "solid." In this reaction, CdS is a solid product formed by the reaction of aqueous CdSO₄ and K₂S.

b) When cadmium sulfate (CdSO₄) dissolves in water, it dissociates into ions:

CdSO₄ (aq) → Cd²⁺ (aq) + SO₄²⁻ (aq)

Similarly, when potassium sulfide (K₂S) dissolves in water, it dissociates into ions:

K₂S (aq) → 2K⁺ (aq) + S²⁻ (aq)

In this solution, there are four types of ions are present: Cd²⁺, SO₄²⁻, 2K⁺, and S²⁻.

c) Cadmium sulfide (CdS) has a yellow to orange color and is insoluble in water. When you mix cadmium sulfate (CdSO₄) and potassium sulfide (K₂S), you would expect to see a yellow to orange precipitate forming, which is cadmium sulfide (CdS).

d) The name for this type of reaction is a double displacement reaction or a precipitation reaction.

e) After the reaction, the soluble product potassium sulfate (K₂SO₄) is formed, which dissociates into ions in the solution. The ions still present in the solution after the reaction are: 2K⁺ (aq) + SO₄²⁻ (aq).

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Answer:

true.................

Answer:

the answer is true hope it helps

the element is in group 2

Answer:

Potential gravitational energy, potential elastic energy, and kinetic energy

Answer:

the first one is the answer

Answer:

Phrases that describe the oceans are

cover more than 70 percent of Earth

constantly in motion

interact with other Earth systems

Explanation:

What are the two most important properties of ocean water?

Two of the most important characteristics of ocean water are its temperature and salinity.

Based on the assumption that the reaction involves N and O to produce NO, if 25.0 g of NO are produced, the amount of N gas used would be 11.66 grams

From the equation of the reaction:

       N + O ---------> NO

Mole ratio of N to NO is 1:1

Mole of 25.0 g of NO = 25/30.01 = 0.833 moles

Equivalent mole of N = 0.833 moles

Mass of 0.833 moles N = 0.833 x 14 = 11.66 grams

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Answer:

about 42m 3

copied from google

hope that helps

approximately 42m 3 was Able Hill

When antacid reacts with HCl to produce H2CO3 it produce fizzy gas react due to a double displacement reaction.

Table salt and carbonic acid are produced in a two fold displacement process when hydrochloric acid and antacid are combined. Additionally, due to the instability of carbonic acid, it will decompose into water and carbon dioxide, emitting a "fizzy" gas.

Strong acid hydrochloric acid is denoted by the chemical formula HCl. The primary ingredient in antacids is sodium bicarbonate, sometimes known as baking soda and has the chemical formula NaHCO3.

Antacid undergoes a chemical reaction when it reacts as a carbonate with powerful acids like hydrochloric acid to create compounds with a different chemical makeup from the beginning components. Similar reactions will be produced by other carbonates, such as calcium carbonate, which makes up the majority of Tums.

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Cation A, with a +3 charge and smaller size, is more likely to occupy negatively charged sites on a clay mineral given equal concentrations in solution.

This is because the higher positive charge allows for stronger electrostatic attraction to the negatively charged sites, overcoming the size difference between the two cations.

Cation A is more likely to occupy negatively charged sites on a clay mineral given equal concentrations in solution. This is because its higher charge makes it more attracted to the negatively charged sites on the mineral, and its smaller size allows it to fit more easily into the interlayer spaces of the mineral.

Cation B, on the other hand, may be too large to fit into these spaces, and its lower charge may make it less attracted to the negatively charged sites.

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Given equal concentrations in solution, cation A with a +3 charge and smaller size is more likely to occupy negatively charged sites on a clay mineral compared to cation B with a +1 charge and larger size, which makes it less likely to occupy those sites due to weaker attraction and less compatibility with the available spaces on the clay mineral.

Cation A is more likely to occupy negatively charged sites on a clay mineral given equal concentrations in solution. This is because cations with higher charges have stronger electrostatic attraction to negatively charged sites on the clay mineral. Additionally, the smaller size of cation A allows for a tighter fit into the negatively charged sites, increasing the likelihood of occupation.

However, other factors such as competition with other cations in solution and the specific characteristics of the clay mineral may also play a role in determining which cation occupies the negatively charged sites.

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Answer:

A) Scandium

B)

C) Gallium

D

Based on its caffeine concentration, the number of soda cans that would be lethal for the person drinking the soda is 131 cans of soda.

Caffeine toxicity produces symptoms such as:

Headache, dizziness, anxiety, agitation, trembling, tingling in the perioral region and in the extremities, disorientation, psychosis, and seizures are all symptoms of the central nervous system (CNS).

The mass of caffeine in a drinking can of soda is 3.91 mg/oz * 12 = 46.92

The number of cans of soda that will contain 10.0 g of caffeine is calculated as follows:

10.0 g of caffeine = 10 * 1000 mg

10.0 g of caffeine = 10000 mg

The number of cans that will be lethal = 10000 / 46.92

The number of cans that will be lethal = 213 cans of soda

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The concentration of gypsum in solution increased while that of sulfates decreased. The rate of gypsum precipitation decreased with time.

The experimental results revealed that the concentration of gypsum in solution increased with time, while that of sulfates decreased. This trend can be explained by the reaction between calcium and sulfate ions in the solution, which led to the precipitation of gypsum. The concentration of sulfate ions in solution decreased with time due to their consumption in the reaction.

As a result, the rate of gypsum precipitation decreased over time. The findings suggest that the reaction was not complete, and that a fraction of sulfate ions remained in solution. To investigate this further, one could perform additional experiments to measure the concentration of sulfate ions at various time points during the reaction.

In addition, one could study the effect of temperature, pH, and other parameters on the reaction rate and the properties of the gypsum crystals formed. Finally, one could compare the experimental results with theoretical models to gain a deeper understanding of the reaction kinetics and mechanisms.

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Among the given options, the tests that are left-tailed are H0:μ≥18, Ha:μ<18, H0:μ≥11.3, Ha:μ<11.3, and H0:μ≥3.7, Ha:μ<3.7.

In these tests, the null hypothesis (H0) states that the population mean (μ) is greater than or equal to a specific value, while the alternative hypothesis (Ha) suggests that the population mean is less than that value.

A left-tailed test is used when the alternative hypothesis suggests that the population parameter is less than a certain value.

This indicates a left-tailed test, where the critical region is in the left tail of the distribution. These tests focus on detecting a significant decrease or difference in the population mean.

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Complete question :

Which of the hypothesis tests listed below is a left-tailed test? Select all correct answers.

Select all that apply: H0:μ≥18, Ha:μ<18 H0:μ≤19.3, Ha:μ>19.3 H0:μ=8, Ha:μ≠8 H0:μ≥11.3, Ha:μ<11.3 H0:μ≥3.7, Ha:μ<3.7

Answer:

\(\boxed {\boxed {\sf 9.6 \ mol \ KCl}}\)

Explanation:

We must use stoichiometry to solve this, which is the calculation of reactants and products in a reaction using ratios.

Let's analyze the reaction given.

\(MgCl_2 _{(aq)} + K_2SO_4 _{(aq)} \rightarrow 2KCl _{(aq)} + MgSO_4 _{(s)}\)

Now, look at the coefficients, or numbers in front of the molecule formulas. If there isn't a coefficient, then a 1 is implied.

We want to find how many moles of potassium chloride (KCl) are produced from 4.8 moles of magnesium chloride (MgCl₂). Check the coefficients for these molecules.

The coefficient represents the number of moles. Therefore, 1 mole of magnesium chloride produces 2 moles of potassium chloride. We can set up a ratio using this information.

\(\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}\)

Multiply by the given number of moles of magnesium chloride: 4.8

\(4.8 \ mol \ MgCl_2 *\frac { 1 \ mol \ MgCl_2} {2 \ mol \ KCl}\)

Flip the ratio so the moles of magnesium chloride cancel out.

\(4.8 \ mol \ MgCl_2 *\frac {2 \ mol \ KCl} { 1 \ mol \ MgCl_2}\)

\(4.8 *\frac {2 \ mol \ KCl} { 1 \ } }\)

\(4.8 * {2 \ mol \ KCl}\)

\(9.6 \ mol \ KCl\)

9.6 moles of potassium chloride are produced from 4.8 moles of magnesium chloride.

In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals