If a metal rod is moved through magnetic field, the charged particles will feel a force, and if there is a complete circuit, a current will flow. We talk about the induced emf of the rod. The rod essentially acts like a battery, and the induced emf is the voltage of the battery. A magnetic field with a strength of 0.732 T is pointing into the page and a metal rod L=0.362 m in length is moved to the right at a speed v of 15.1m/s.

Required:
a. What is the induced emf in the rod?
b. Suppose the rod is sliding on conducting rails, and a complete circuit is formed. If the load resistance is 5.74Ω , what is the magnitude and direction (clockwise or counterclockwise) of the current flowing in the circuit?

Two mirrors are inclined at an angle of 30 degrees a ray of light obliquely at 180.

A mirror is said to be inclined when it is positioned perpendicular to a surface or if a flat mirror is positioned at an angle from the base (other than 90 degrees).

We first need to comprehend light in order to comprehend mirrors. According to the rule of reflection, a light beam that strikes a surface will bounce back like a tennis ball bounced against a wall.

Always equal to the angle leaving the surface, or the angle of reflection, is the entering angle, also known as the angle of incidence.

Therefore, Two mirrors are inclined at an angle of 30 degrees a ray of light obliquely at 180.

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The velocity of the combined lump after the collision is 39.5 cm/s, which is the average velocity of the two lumps before the collision.

To solve this problem, we can use the principle of conservation of momentum, which states that the total momentum of a system before a collision is equal to the total momentum of the system after the collision, provided there are no external horizontal forces acting on the system.

The momentum of an object is equal to its mass multiplied by its velocity. Therefore, we can calculate the total momentum of the system before the collision as:

Total momentum before collision = (0.50 g) × (-20.0 cm/s) + (70.0 g) × 40.0 cm/s

= -10.0 g·cm/s + 2800.0 g·cm/s

= 2790.0 g·cm/s

Since the two lumps stick together after the collision, their masses combine to form a single lump. Let's call the velocity of the combined lump after the collision "v". We can then calculate the total momentum of the system after the collision as:

Total momentum after collision = (0.50 g + 70.0 g) × v

= 70.50 g × v

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we can equate these two expressions and solve for "v":

Total momentum before collision = Total momentum after collision

2790.0 g·cm/s = 70.50 g × v

v = 2790.0 g·cm/s ÷ 70.50 g

v = 39.5 cm/s

This result can be explained by the fact that, in the absence of external horizontal forces, the momentum of the system is conserved, and the total mass of the system remains constant.

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The efficiency of motor is 90.58%.To determine the efficiency of the motor, we need to calculate the input power and the output power, and then divide the output power by the input power

The input power can be calculated using the formula:

Input Power = Voltage × Current

Given that the voltage is 230 V and the current is 24 A, we have:

Input Power = 230 V × 24 A

Input Power = 5520 W (or 5.52 kW)

The output power of the motor is given as 5 kW (since it is a 5 kW motor).

Now, we can calculate the efficiency:

Efficiency = (Output Power / Input Power) × 100%

Efficiency = (5 kW / 5.52 kW) × 100%

Efficiency ≈ 90.58%

Therefore, the efficiency of this motor is approximately 90.58%.

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Answer:

» Image distance :

\({ \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\ \)

\({ \tt{ \frac{1}{v} + \frac{1}{10} = \frac{1}{5} }} \\ \\ { \tt{ \frac{1}{v} = \frac{1}{10} }} \\ \\ { \tt{v = 10}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: image \: distance \: is \: 10 \: cm \: \: }}}}}\)

» Magnification :

• Let's derive this formula from the lens formula:

\( { \tt{ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} }} \\ \)

» Multiply throughout by fv

\({ \tt{fv( \frac{1}{v} + \frac{1}{u} ) = fv( \frac{1}{f} )}} \\ \\ { \tt{ \frac{fv}{v} + \frac{fv}{u} = \frac{fv}{f} }} \\ \\ { \tt{f + f( \frac{v}{u} ) = v}}\)

• But we know that, v/u is M

\({ \tt{f + fM = v}} \\ { \tt{f(1 +M) = v }} \\ { \tt{1 +M = \frac{v}{f} }} \\ \\ { \boxed{ \mathfrak{formular : } \: { \tt{ M = \frac{v}{f} - 1 }}}}\)

\({ \tt{M = \frac{10}{5} - 1 }} \\ \\ { \tt{M = 5 - 1}} \\ \\ { \underline{ \underline{ \pmb{ \red{ \: magnification \: is \: 4}}}}}\)

» Nature of Image :

Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

The Earth's surface is a living union of its solid crust, atmosphere, hydrosphere, and biosphere, all of which have worked together to create a continually regenerating and dynamic symphony of form. From the Solar System Encyclopedia.

It has a substantial and dynamic surface with mountains, valleys, canyons, plains, and a variety of other features. Earth is unique in that it is an ocean world. 70% of the Earth's surface is covered by water. The Earth's atmosphere is mainly nitrogen, with enough of oxygen for humans to breathe.

a) The mass of an object is an intrinsic attribute, which means that it is determined only by the qualities of the thing and is not affected by its position. As a result, Gary's mass at 300 kilometers above the Earth's surface equals his mass at the Earth's surface.

b) The weight of an object is given by, W = mg

where

m is the mass and g = GM /r²

It is the gravitational acceleration at the location of the object, with G being the gravitational constant, M the mass of the planet and r the distance of the object from the center of the planet.

At the Earth's surface, g = 9.81 m/sec²

so Gary's weight is W = mg

W = 9.81 m  ...........(1)

where m is Gary's mass.

Then, we must calculate the value of g at 300 km above Earth's surface. the Earth's radius is, R = 6370 Km.

So the distance of Gary from the Earth's center is:

r = R + h

r = (6370 +300) Km

r = 6670 km

r = 6.67 × 10⁶ m

The Earth's mass is M = 5.97 × 10²⁴ Kg , so the gravitational acceleration is, g₁ = GM /r²

g₁ = [(6.67 10⁻¹¹ m³ kg⁻¹ s⁻²) × (5.97 × 10²⁴ Kg)] ÷ (6.67 × 10⁶ m)²

g₁ = 8.95 m/sec²

Therefore, Gary's weight at 300 km above Earth's surface is:

W₁ = mg₁

W₁ = 8.95 m  ............(2)

If we compare (1) and (2), we find that Gary's weight has changed by

W₁/W = 8.95 m/ 9.81 m

W₁/W = 0.91

So, Gary's weight at 300 km above Earth's surface is 91% of his weight at the surface.

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(a) The x and y component of 6 N are 4.8 N and 3.6 N respectively.

(b) The magnitude of the resultant of the three forces is 1 N.

The direction of the forces is calculated as follows;

θ = arc tan ( Vy / Vx )

θ = arc tan ( 3 / 4 )

θ = 36.87 ⁰

The x and y component of 6 N is calculated as follows;

Fx = 6 cos (36.87 ) = 4.8 N

Fy = 6 x sin ( 36.87 ) = 3.6 N

The sum of all the x component of the three forces = -4 N + 4.8 N = 0.8 N

The sum of all the y component of the three forces = -3 N + 3.6 N = 0.6 N

The resultant force is calculated as follows;

F = √ ( 0.6² + 0.8² )

F = 1 N

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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a) The capacitance of the ceramic capacitor is approximately 354.16 pF.

b) The potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

To calculate the capacitance of the ceramic capacitor, we can use the formula:

C = (ε₀ * εᵣ * A) / d

where:

C is the capacitance,

ε₀ is the vacuum permittivity (approximately 8.854 x 10^(-12) F/m),

εᵣ is the relative permittivity of the ceramic (given as 100),

A is the effective plate area (given as 4 cm², which is equal to 4 x 10^(-4) m²),

d is the separation between the plates (given as 0.1 mm, which is equal to 0.1 x 10^(-3) m).

Let's calculate the capacitance in picofarads (pF):

a) Calculation of capacitance (C):

C = (ε₀ * εᵣ * A) / d

= (8.854 x 10^(-12) F/m * 100 * 4 x 10^(-4) m²) / (0.1 x 10^(-3) m)

= (8.854 x 100 x 4) / 0.1

= 354.16 pF

Therefore, the capacitance of the ceramic capacitor is approximately 354.16 pF.

b) To find the potential difference (PD) between the plates when the capacitor is given a charge of 1.2 μC (microcoulombs), we can use the formula:

PD = Q / C

where:

PD is the potential difference,

Q is the charge (given as 1.2 μC, which is equal to 1.2 x 10^(-6) C),

C is the capacitance (calculated in part a) as 354.16 pF, which is equal to 354.16 x 10^(-12) F).

Let's calculate the potential difference (PD):

b) Calculation of potential difference (PD):

PD = Q / C

= (1.2 x 10^(-6) C) / (354.16 x 10^(-12) F)

= 3.39 x 10^6 V

Therefore, the potential difference between the plates of the capacitor will be approximately 3.39 x 10^6 volts.

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The potential energy is at the maximum when you reach the top of your jump on a trampoline. The correct answer is option B.

Potential Energy is the type of energy an object possesses by virtue of its position relative to others, stresses within itself, electric charge, and other factors. Potential energy exists in various forms, including gravitational potential energy, elastic potential energy, chemical potential energy, and electrical potential energy.

This type of energy can be converted into another type of energies. Examples, a charged battery has potential energy and it can be used as electrical potential energy. Petrol, diesel and and gas have chemical potential energy and be used as kinetic energy.

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The elongation of the rod beyond its original length would be 2.5 mm.

To elongation of the rod can be deduced using the formula:

ΔL = FL / AE

where:

The cross-sectional area of the steel rod is given by:

The force applied to the rod:

Thus:

ΔL = (98.1 x 2) / ((7.85 x \(10^{-7\)) x (200 x \(10^9\) ))

ΔL = 0.0025 m = 2.5 mm

In other words, the elongation of the steel rod beyond its original length is 2.5 mm.

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Given:

The weight of the proton is: W = 1.6 × 10^(-26) N.

The charge on a proton is: q = 1.60 × 10^(-19) C

To find:

The magnitude and the direction of the electric field.

Explanation:

The weight of the proton is the force that the proton experiences due to its mass and acceleration. The electric force balances the weight of the proton. Thus we have,

F = W

Here, F is the electric force a proton experiences when it is placed in an electric field and W is the weight of the proton,

The force experienced by a photon when it is placed in an electric field is given as,

Here, E is the electric field.

Rearranging the above equation and substituting the values, we get:

Thus, the magnitude of the electric field is 1.025 × 10^(-7) N/C.

The charge on the proton is positive and when it is placed in the electric field, the electric force on the proton is balanced by the weight of the proton. Thus, The direction of the electric force is opposite to the direction of the weight of the proton which is radially outward.

Final answer:

The magnitude of the electric field is 1.025 × 10^(-7) N/C and it has a radially outward direction that is opposite to the wight of the proton.

Answer:

o my god how big is the question

Answer:

C.

Explanation:

There is such thing a wave energy, but that doesn't quite fit for this question. B. I have not heard of that, so it has to be incorrect. C.  Yes, energy can cause motion in a lot of ways. D. Energy can change forms so that is incorrect.

Answer:

\(\boxed {\boxed {\sf 3.5 \ Newtons}}\)

Explanation:

Force is the product of mass (in kilograms) and acceleration (in meters per square second).

\(F=ma\)

The mass of the ball is 140 grams and the acceleration is 25 m/s². Convert grams to kilograms.

Substitute the values into the formula.

\(F= 0.14 \ kg * 25 \ m/s^2\)

Multiply.

\(F= 3.5 \ kg*m/s^2\)

\(F= 3.5 \ N\)

3.5 Newtons of force are required.

Answer:

 t = 1.62 h

Explanation:

A flat mirror fulfills the law of reflection where the incident angle is equal to the reflected angle.

          θ_i = θ_r

If we use trigonometry to find the angles, the mirror is at a height of L = 1.87 m,   and the reflected rays reach a distance x1 = 3.56 m

         tan θ₁ = x₁ / L

         tan θ₁ = \(\frac{3.56}{1.87}\)

         θ₁ = tan⁻¹  1.90

         θ₁ = 62.29º

for the second case x₂ = 1.46 m

        tan θ₂ = x₂ / L

        θ₂ = tan⁻¹  \(\frac{1.46}{1.87}\)

        θ₂ = 37.98º

the difference in degree traveled is

         Δθ = θ₁- θ₂

          Δθ = 62.29 - 37.98

          Δθ = 24.31º

as in the exercise they indicate that every 15º there is an hour

         t = 24.31º (1h / 15º)

         t = 1.62 h

The presence of ice on the road reduces the frictional force between the tires and the road, thus if you drive at a greater speed the car will slip off the road.

This is the angle at which the vehicle is inclined with respect to the horizontal is curved road.

A banked road or curve has maximum speed or speed limit in which a vehicle must ply safely to avoid slipping or fall off from the curved road.

The presence of ice on the road reduces the frictional force between the tires and the road, thus if you drive at a greater speed the car will slip off the road.

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During a 10-second period, a car travels 80 meters. This car typically travels at a speed of 8 m/s.

For instance, if it takes a person 40 minutes to travel 20 miles north, 20 miles south, and finally 20 miles in between, their average speed is 40 miles divided by 40 minutes, or 1 mile per minute. Instead of distance, average velocity takes into account total displacement.

The total displacement must be divided by the total time elapsed in order to determine the average velocity.

average velocity= total displacement/ total time

avg velocity=80/10=8m/s

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The distance between the similar charges is 0.753 m. The electric force is the inverse of the square of the distance.

Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.

The given data in the problem is;

q₁,q₂ are the charges = 1.6 ×10⁻¹⁹ C

R is the distance

F is the electric force=2.0×10²⁴ N

The electric force is found as;

\(\rm F = \frac{Kq_1q_2}{R^2} \\\\ \rm 2.0 \times 10^{28}= \frac{9\times 10^9 \times 1.6 \times 10^{-19}1.6\times 10^{-19} }{R^2} \\\\ R =0.753 \ m\)

Hence, the distance between the similar charges is 0.753 m.

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Answer:

D

Explanation:

transparent_objects that allows light to pass through and can you see through them

Answer:

A)   θ = 13.1º  , B)  E

Explanation:

A) For this exercise, let's use Newton's second law, let's set a reference frame where the axis ax is in the radial direction and is horizontal, the axis y is vertical.

In this reference system the only force that we must decompose is the Normal one, let's use trigonometry

        sin θ = Nₓ / N

        cos θ = \(N_{y}\) / N

        Nₓ = N sin θ

       Ny = N cos θ

x-axis (radial)

        Nₓ = m a

where the acceleration is centripetal

         a = v² / R

we substitute

        -N sin θ = -m v² / R                   (1)

the negative sign indicates that the force and acceleration towards the center of the circle

y-axis (Vertical)

          Ny - W = 0

           N cos θ = mg

           N = mg / cos θ

we substitute in 1

          mg / cos θ  sin θ = m v² / R

          g tan θ = v² / R

          θ = tan⁻¹ (v² / gR)

we calculate

        θ = tan⁻¹ (25² / 9.8 274)

        θ = 13.1º

B) when comparing the equations the correct one is E

Using the formula F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them, we can calculate the gravitational force between Jupiter and the sun.

Plugging in the values, we get:

F = (6.674 x 10^-11 N * (m^2 / kg^2)) * ((1.9 x 10^27 kg) * (2 x 10^30 kg)) / (78 x 10^6 m)^2

Simplifying this, we get:

F = 1.98 x 10^27 N

Therefore, the gravitational force between Jupiter and the sun is approximately 1.98 x 10^27 Newtons.

The gravitational force between Jupiter and the sun, calculated using Newton's law of gravitation with their masses and distance, is \(1.95 * 10^{22} N.\)

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A miniature quadcopter is located at xi = −1.75 m and yi = 2.70 m at t = 0, so the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

The equation that is used here is the kinematic equations to find the position of the quadcopter at time t,

x = xi + vav, x × t

y = yi + vav, y × t

Substituting the given values, one can get:

x = -1.75 m + 1.70 m/s × 2.10 s = -0.185 m

y = 2.70 m - 2.50 m/s × 2.10 s = -3.175 m

Hence, the x-coordinate of the quadcopter's position at t = 2.10 s is -0.185 m, and the y-coordinate is -3.175 m.

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Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.

Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.

When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.

This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.

Answer:

"The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. ... The only way to use energy is to transform energy from one form to another."

Explanation:

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Supersonic flights are moving with speed greater than that of sound. This speed through air will combine the pressure waves and creates shock waves. Continuation of shock waves leads to sonic boom in air.

Sonic booms are sound created on the ground by overpressure in the air generated by fastly moving objects. Similar to someone dumping goods from a moving car, an aircraft travelling at supersonic speeds continuously produces shock waves that cause sonic booms to travel throughout its flight path.

The boom seems to be swept rearward as it moves away from the aeroplane from its point of view. The boom will strike the ground in front of the aircraft if the aircraft makes a rapid turn or pulls up.

The abrupt start and release of pressure following the building by the shock wave or "peak overpressure" is what is heard as a "sonic boom" on the ground. Only a few pounds per square foot change in pressure results from a sonic boom, which is about equivalent to the pressure shift we experience in an elevator.

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Answer:

The change in the car's momentum is equal to -8910 kgm/s.

Explanation:

Given that,

The mass of a car, m = 990 kg

Initial speed, u = 22 m/s

Final momentum, v = 13 m/s

We need to find the change in the car's momentum. The change in momentum of the car is given by :

\(\Delt p=m(v-u)\\\\=990\times (13-22)\\\\=-8910\ kg-m/s\)

So, the required change in the car's momentum is equal to -8910 kgm/s.

Answer:

Electromagnetic waves carry energy.

Explanation:

The waves consist of transverse vibrations in electrical and magnetic fields, not vibrating particles.

Answer:

the acceleration of gravity.

Answer:

g stand for the acceleration of gravity .

Explanation:

The density of water is approximately 1 g/cm^3. Therefore, the volume of 2800 g of water would be 2800 cm^3 because density is mass/volume, and so volume is mass/density.

Since this volume is inside a cubic box, the length of each side of the cube (a, for instance) could be found by taking the cubic root of the volume. This is because the volume of a cube is calculated by a^3 (length of one side cubed). Hence, a = cube root of 2800 cm^3 ≈ 14.1 cm.

Converting centimeters to meters (as 1 meter is equal to 100 centimeters), we get approximately 0.141 meters.

So the filled cubic box has a side length of approximately 0.141 m.