If he same pair of shoes weighs 0.3 newtons on Pluto what does the pair of shoes weigh on earth?

Answer:

Explanation:

A converging lens id also known as a convex lens. A convex lens has a positive focal length.

Using the lens formula to determine the image distance from the lens for each object distance.

1/f = 1/u + 1/v

f = focal length

u = object distance

v = image distance

For an object placed at distance of 18.0cm with focal length 14.0cm,

1/v = 1/f-1/u

1/v = 1/14 - 1/18

1/v = 9-7/126

1/v = 2/126

v = 126/2

v = 63cm

Since the image distance is positive for an object 18cm from the lens, the image formed by the object at this distance is a real and inverted image.

The magnification = v/u = 63/18 = 3.5

Similarly for an object placed at distance of 7.0cm with focal length 14.0cm,

v = uf/u-f

v = 7(14)/7-14

v= -14.0 cm

Since the image distance is negative for an object placed 7.0 cm from the lens, the image formed by the object at this distance is a virtual and upright image.

The magnification = v/u = 14/7 = 2

Note that the negative value is not taken into account when calculating magnification. The negative value only tells us the nature of the image formed.

The length of the pendulum is measured from the lower part of the wooden clamp, because the center of gravity is at the center of the bob.

The simple pendulum's length, l is determined by measuring it from the point of suspension to the center of gravity (center of the bob), which is the place where all of this sphere's mass is concentrated.

The center of the mass will exactly reside in the center of the bob when we take the bob's dimensions into account.

As a result, the total length is now equal to the length of the string plus the bob's radius. The length is thus measured from the lower part of the wooden clamp.

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For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.

Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,

R = 55*30/(55+30)

R = 19.4 Ω

Power given to the circuit is,

P = V²/R = 4.2/19.4 = 0.9 W

Receiving power taken from 55Ω resistor

P = V²/R = 4.2/55 = 0.07 W

Receiving power taken from 30Ω resistor

P = V²/R = 4.2/30 = 0.14 W

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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Lifting an air parcel vertically causes it to cool at the moist adiabatic lapse rate up to the dew point, then temperature cools at the wet lapse rate at a rate of 5 degrees Celsius every 1000 metres.

Adiabatic dry lapse rate When the air parcel has either no moisture at all or very little moisture, the temperature varies with height. Air in unsaturated atmosphere cools by 3 degrees Celsius for every 1,000 feet of elevation. It condenses when it cools. Clouds will eventually develop. The concept of temperature is used to convey quantitatively how hot and cold something is. Using a thermometer, one can gauge temperature. Thermometers are calibrated according to a variety of temperature scales that traditionally drew on a variety of reference locations.

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Answer: NO, there are many examples of non-conservative forces.

Explanation: Conservatives forces are special forces whose work is zero in a closed path.

Answer:

250 m/s

Explanation:

Velocity (v) = Frequency (f) × Wavelength (λ)

Velocity (v) = 25 Hz × 10 m

Calculating the multiplication:

Velocity (v) = 250 m/s

The magnitude of the Coulomb force between the spheres, when 1.90 x \(10^{12\) electrons are transferred, is 2.34 x \(10^{-4\) Newtons.

To determine the magnitude of the Coulomb force between two uncharged spheres.

Given that 1.90 x \(10^{12\) electrons are removed from one sphere and placed on the other, we need to calculate the charge on each sphere. The charge on a single electron is -1.6 x \(10^{-19\) coulombs, so the charge transferred from one sphere to the other is:

Q = (1.90 x \(10^{12\)) × (-1.6 x \(10^{-19\)) = -3.04 x \(10^{-7\) coulombs

Since one sphere loses electrons and becomes positively charged, while the other gains electrons and becomes negatively charged, the magnitude of the charge on each sphere is:

|Q| = 3.04 x \(10^{-7\)  coulombs

Now, we can calculate the magnitude of the Coulomb force using Coulomb's law:

F = k * (|Q1| * |Q2|) / \(r^2\)

where k is the electrostatic constant (k = 8.99 x \(10^{9}\) N \(m^{2}\)/\(C^{2}\)) and r is the distance between the centers of the spheres (r = 2.60 m).

Plugging in the values, we get:

F = (8.99 x \(10^{9}\) N \(m^{2}\)/\(C^{2}\)) * (3.04 x \(10^{-7\)C)² / \((2.60 m)^2\)

Simplifying this expression, we find:

F ≈ 2.34 x \(10^{-4\) N

Therefore, the magnitude of the Coulomb force between the spheres, when 1.90 x \(10^{12\) electrons are transferred, is approximately 2.34 x \(10^{-4\) Newtons.

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Answer:

C. Muddy Water

The moment of inertia of the flat square is MA²/6

The moment of inertia of a body is a property of the body which shows its ability to ritate about an axis.

To find the moment of inertia of the flat square through its center of mass, we know that the moment of  inertia of  a rectangular slab is given by

I = M(a² + b²)/12 where

Now, for a flat square a = b. so,its moment of inertia is I = M(a² + b²)/12

I = M(a² + a²)/12

= 2Ma²/12

= Ma²/6

Now for the given flat square, we have that

So, substituting these into the equation of moment of inertia for the flat square, we have that

The moment of inertia of the flat square is given by

I = Ma²/6

I = MA²/6

So, moment of inertia is MA²/6

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The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path

From the formula in the question;

B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.

The accelerating voltage used to move the ions is called Vaccelm.

The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.

The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.

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The speed of the ball just after striking the floor a second time, is 30.0 m/s.

Initial height (h) = 45 m

Acceleration due to gravity (g) = 10 m/s²

Energy loss per collision (k) = 19% = 0.19

At each collision with the floor, the ball loses 19% of its kinetic energy, which means the remaining kinetic energy is 81% (100% - 19%).

When the ball reaches the floor for the first time, it has converted all its potential energy into kinetic energy. So, the initial kinetic energy (K₁) is equal to the potential energy (PE) at the initial height:

K₁ = PE = mgh

Now, let's consider the ball's motion from the initial height to the first collision point. The ball undergoes free fall, so we can use the equations of motion:

h = (1/2)gt²

t = sqrt(2h/g)

Using this time, we can calculate the initial kinetic energy (K₁):

K₁ = mgh = m * 10 m/s² * 45 m

Since the ball loses 19% of its kinetic energy at each collision, the remaining kinetic energy is 81%:

K₂ = K₁ * 0.81

The ball then rebounds elastically from the floor, conserving both kinetic energy and speed. Therefore, the speed just after striking the floor for the second time (v₂) is equal to the speed just before the first collision (v₁):

v₂ = v₁

To find the speed just before the first collision (v₁), we can use the equation of motion:

v = gt

Substituting the time (t) we found earlier, we have:

v₁ = g * sqrt(2h/g)

Now, we can substitute the known values and calculate the speed just after striking the floor for the second time:

v₁ = 10 m/s² * sqrt(2 * 45 m / 10 m/s²)

v₂ = v₁

By evaluating the expression, we find:

v₁ ≈ 30.0 m/s

v₂ ≈ 30.0 m/s

Therefore, the speed of the ball just after striking the floor for the second time is 30.0 m/s.

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Answer:

where u put it last time or retrace ur steps to where u last put it

Answer:

Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.

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Answer: In contrast to the 21st century, which is a period of enormous technological advancement and globalization, ancient civilizations were agrarian communities with a high degree of social stratification.

Explanation: the differences between ancient civilizations and the 21st century, in two paragraphs of five lines each:

A)

Ancient civilizations:

Paragraph 1: Ancient societies were agrarian, focusing on commerce and agriculture, with a small elite ruling a large population of farmers, artisans, and laborers.

Paragraph 2:Ancient civilizations advanced art, architecture, mathematics, science, and social systems, creating religious beliefs and intricate social systems like Egyptian, Greek, Roman, and Chinese.

21st century:

Paragraph 1: Globalization and technological advancements in the 21st century have made us connected to the world, enabling us to stay connected through information and communication tools.

Paragraph 2: The 21st century faces challenges like economic inequality, political instability, and climate change, yet it also represents a hopeful generation dedicated to improving the world and overcoming these challenges.

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In ancient civilizations, major developments in human history took place, such as the invention of writing systems and the rise of empires. In the 21st century, advancements in technology and globalization have transformed the world. Ancient civilizations have exerted a lasting influence on our modern world, from written communication to political systems and architectural wonders.

In ancient civilizations, major developments in human history took place, such as the invention of writing systems, the rise of empires, and the development of complex societies. For example, in ancient Egypt, pharaohs ruled over a hierarchical society and constructed impressive monuments like the pyramids. In the 21st century, advancements in technology and globalization have transformed the world. This period is characterized by rapid communication, scientific and technological breakthroughs, and interconnectedness through the internet and social media.

Locating ancient civilizations in our own context, we can observe their influence in our modern world. The writing systems developed by ancient civilizations laid the foundation for written communication, which is still vital today. The concept of empires and nation-states, which began in ancient times, is significant in understanding modern political systems. Additionally, the architectural wonders of ancient civilizations, like the Great Wall of China and the Colosseum, continue to be celebrated and preserved as cultural heritage.

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The momentum of the blobs after the collision of a 1 kg blob of putty moving at 10 m/s with another 1 kg stationary blob will be 5 m/s.

The term "completely inelastic collision" is used to describe every time two masses cling together after colliding. Any inelastic collision will result in the internal energy of the objects being transformed into kinetic energy. Because of this, even though the system's energy is conserved (no outside forces are at action), its internal energy is changing in an unknowable and unpredictable fashion. This implies that the concept of energy conservation in inelastic collisions is absolutely meaningless to us. However, the conserved quantity that we can monitor is momentum.

Initial momentum is expressed as p = m1v1 + m2v2,

where, I denotes vector quantities.

v2 = 0  (because the second blob is at rest).

As a result, p=m1v1, |p|=m1|v1|=1*10= 10 kg*m/s,

The total amount of momentum is conserved in a closed system. The end momentum is 10 kg*m/s and is therefore also directed in the same direction as the beginning momentum.

The combined mass is now M=m1+m2= 1+1 = 2 kg due to the fact that two blobs are now clumped together. As a result, p = mv= 10 =2v; from this, v= 10/2 = 5 m/s, headed in the same direction as the first blob's starting velocity.

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Biomolecules are fundamental for life. They required both energy supply and building structures.

Biomolecules are organic molecules that fundamental for life and must be ingested from the regular diet.

Biomolecules include proteins (e.g., meal proteins), lipids (fats) and also carbohydrates (e.g., glucose).

Biomolecules required both energy supply (e.g., glucose) and building structures (e.g., amino acids in proteins).

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Objective observations do not include bias or opinions.

Observations can capture a child's strengths and weaknesses

This refers to the types of observation that is done through the senses through what we see, touch, feel, hear, smell, and taste.

Hence, we can see that objective observation is important because they provide insight into the strengths and needs of a child.

One of the ways you can capture your observations is through note-taking.

The federal law which ensures that all children and family education information is confidential is called The Family Educational Rights and Privacy Act (FERPA)

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Answer:

3

Explanation:

3

There are many similarities between the earth and the home we live in.

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

Have a building, as well as the tools and components that were utilized to create this house and the soil.

Both home and earth have an environment of their own.

We also reside on both the earth as well as in our homes.

These are the items we have, such as food, drink, and raw materials.

Home and earth are similar because, as we know that the earth is our primary supply of materials for building homes.

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When the rest of a half-filled container containing a steel ball floating on the surface of the mercury is filled with water, the ball remains partially submerged in mercury but not as deeply as before.

Whether a substance will float or sink in a liquid is determined by its density relative to the density of the liquid.

If the density of the substance is less than the density of the liquid, it will float because it is less dense than the liquid and will experience a buoyant force that is greater than its own weight. If the density of the substance is greater than the density of the liquid, it will sink because it is denser than the liquid and will experience a buoyant force that is less than its own weight.

For example, water will float on mercury since it is less dense than mercury.

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Complete question:

Consider a steel ball floating on the surface of the mercury in a half-filled container.

What happens when the rest of the container is filled with water? Mercury is denser than steel, and both are denser than water. Mercury and water do not mix.

1. The ball remains partially submerged in mercury to exactly the same depth as before.

2. The ball Boats to the surface of the water.

3. Mercury floats on top of the water, and the ball floats on the mercury's surface

4. The ball remains partially submerged in mercury but not as deeply as before.

5. The ball sinks to the bottom of the container

6. The ball remains partially submerged in mercury to a greater depth than before.

Answer: So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power). When the distance between the 2 objects is halved, the gravitational force between the 2 objects is doubled. when the distance between the 2 objects is doubled then the gravitational force doubles

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Please find attached photograph for your answer.

Answer:

the intercept is the orgin (0,0)

The potential energy of a magnet would increase if you removed it from a refrigerator door and put it on a table.

Potential energy of magnet would increase if you removed it from refrigerator door and put it on table.

This is because when the magnet is on refrigerator door, it is in a position where it is attracted to metal surface of the door, and this attraction creates  certain amount of potential energy. When the magnet is removed from door and placed on table, it is no longer in that attractive position, so potential energy that was associated with magnet's attraction to the door is no longer present. Instead, magnet now has gravitational potential energy, which depends on its height above the ground and acceleration due to gravity.

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Speed = distance / time

Speed = (33 cm) / (2min 20sec)

Speed = (0.33 m) / (140 sec)

Speed = 0.0024 m/s

Speed = (0.0024 m/s) x (3600 sec / 1 hr) x (1 km / 1000 m)

Speed = (0.0024 x 3600 / 1000) (m-sec-km / sec-hr-m)

Speed = 0.0085 km/hr

For the time of 2 min and 20 seconds, Archie's speed in m/s will be 0.0024 m/s and Archie's speed in km/hr will be 0.0085 km/hr.

The "speed at which an object is traveling," or speed, is a scalar quantity. The speed of an object is the rate at which it moves through space. A fast-moving object covers a considerable distance in a short amount of time while traveling at a high speed. An object moving slowly, on the other hand, moves a comparatively modest distance in the same amount of time. An object with zero speed is one that is not moving at all.

According to the question, the given values are :

Distance, d = 33 inches or,

d = 33 cm

Time, t = 2 minutes 20 seconds, or,

t = 140 seconds.

Speed is the ratio of distance to time.

s = 33/140

s = 0.0024 m/s

Now the distance in km/hr will be :

s = 0.0024 m/s × 3600 sec / 1hr × 1 km/ 1000 m

s= 0.0085 km/hr

Hence, the speed in km/hr is 0.0085 km/hr and in m/s speed is 0.0024 m/s.

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The value of  the missing resistance, R₃ = 10.35 ohms.

The value of the missing voltages, V₁ = 6 V, V ₃ = 24 V.

The value of the missing currents, I₁ = 3 A, I₃ = 2.32 A.

The values of the missing component of the circuit is calculated by applying the following formula.

The total resistance of the circuit;

For R₂, R₃, 1/R = 1/R₂ + 1/R₃

1/R = 1/12 +  1/R₃

1/R = (R₃ + 1)/(12R₃)

R = 12R₃ / (R₃ + 1)

For, R₁, R₂ and R₃, total resistance;

R = 12R₃ / (R₃ + 1) + R₁

R = [12R₃ / (R₃ + 1)] + 2

R = (12R₃ + 2(R₃ + 1) ) / (R₃ + 1)

R = (12R₃ + 2R₃ + 2 ) / (R₃ + 1)

R = (14R₃ + 2 ) / (R₃ + 1)

The total current in circuit is calculated as;

I = V/R

I = 30 / R

I = ( 30 ) / (14R₃ + 2 ) / (R₃ + 1)

I = (30R₃ + 30) / (14R₃ + 2) ------- (1)

The voltage in parallel circuit is the same

V₂ = V₃ = 24 V

V₃ = IR₃

24 = IR₃

I = 24/R₃  --------- (2)

Solve (1) and (2) together as follows;

24/R₃ = (30R₃ + 30) / (14R₃ + 2)

30R₃² - 306R - 48 = 0

Solve the quadratic equation, using formula method.

R₃ = 10.35 ohms

I₃ = V₃/R₃

I₃ = 24 V / 10.35

I₃ = 2.32 A

If the voltage drop at R₂ and R₃ = 24 V, the voltage drop at R₁ = 30V - 24 V = 6 V

The current in R₁ = V₁/R₁ = 6 V / 2 V = 3 A

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The formula that can be used to show that the speed of the stone when it hits the ground is 32 m/s is v = u + at

According to equations of motion,

v = u + at

v = Final velocity

u = Initial velocity

t = Time

a = Acceleration due to gravity

t = 3.2 s

a = 10 m / s²

v = 0 + ( 10 * 3.2 )

v = 32 m /s

Equations of motion are used to describe the position of a moving object in a constantly accelerated manner. The position can be described using acceleration, velocity, displacement and time.

Therefore, the formula that can be used to show that the speed of the stone when it hits the ground is 32 m/s is v = u + at

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