if i measure the speed of a shaft to be 1000 rpm /- 100 rpm, what is the shaft's speed and uncertainty in speed measured in radians/sec?\

Answer:

It is when the focus of the ellipse that is closer to the point where Mars is moving the fastest.

Explanation:

I hope it helps! Have a great day!

Anygays-

Answer:

the answer is UV Radiation

The jovian planets in our solar system include Jupiter, Saturn, Uranus, and Neptune. These gas giants are distinct from the terrestrial planets like Mercury, Venus, Earth, and Mars.

Jovian planets, namely Jupiter, Saturn, Uranus, and Neptune, are characterized by their composition and physical properties. They are primarily composed of gases and lack a solid surface. Jovian planets are much larger in size compared to the terrestrial planets.

They possess thick atmospheres with swirling cloud formations and dynamic weather systems. These gas giants also have a significant number of moons and are accompanied by planetary rings made up of dust and ice particles.

Jovian planets are located farther away from the Sun and have lower densities compared to the terrestrial planets. Their unique characteristics distinguish them from the rocky, inner planets like Mercury, Venus, Earth, and Mars.

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Answer:

Line dividing each court half into two sides; the center line separates the left and right service zones.

Answer:

I believe the answer is 2.0

Explanation:

The net force that would be required is 2 N

From the question,

We have that

A net force of 10 N accelerates an object at 5.0 m/s².

To determine the net force that would be required to accelerate the same object at 1.0 m/s²,

First, we will determine the mass of the object

From the Newton's second law of motion, we have that

F = ma

Where F is the force

m is mass

and a is acceleration

From the given information

F = 10N

a = 5.0 m/s²

Putting the above parameters into the formula, we get'

10 = m × 5.0

∴ m = 10 ÷ 5.0

m = 2 kg

∴ The mass of the object is 2kg

Now,

For the net force that would be required to accelerate the same object at 1.0 m/s²,

Using the same formula

F= ma

Here,

a = 1.0 m/s²

and m = 2 kg

∴ F = 2 × 1

F = 2 N

Hence, the net force that would be required is 2 N

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Answer:

for students to do nothing

Explanation:

because doing nothing is not a course goal

Answer:

Q = k M T    where k is the absorption constant, Q the heat absorbed, M the mass involved and T the temperature change (for change in temperature)

Q1 = 4.18 kJ/kg * 1 kg * 273 deg K     heat contained

Q2 = 4.18 kJ/kg * .5 kg * 373 deg K     heat contained

Q1 = 1141 kJ deg K

Q2 = 780 kJ deg K

Q = Q1 + Q2 = 1921 kJ deg K

T = 1921 / (4.18 * 1.5) deg K = 306 deg K = (306 - 273) = 33 deg Celsius

(The total mass  is now 1.5 kg)

mass=30 force=50

(a) 50÷30

The correct order of the Sun's layers from the center outward is e. core, radiative zone, convective zone, photosphere, chromosphere, corona.                                                                                                                                                                          

The chromosphere is the layer above the photosphere and below the corona. It is characterized by a reddish glow that is visible during a total solar eclipse.
The core is where nuclear fusion occurs, generating the Sun's energy. The radiative and convective zones transport this energy outward. The photosphere is the visible surface of the Sun, while the chromosphere is a layer above it, giving rise to solar phenomena. Finally, the corona is the Sun's outermost layer, characterized by its high temperature and plasma emissions.

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Explanation:

list in order with the smallest molecules at the top and largest molecules at the bottom:

1.Oxygen

2.Water

3.Carbon dioxide

4.amino acid

5.Glucose

6. Starch

7. Protein

The molecules can be arranged as follows with the smallest at the top is oxygen, water, carbon dioxide, amino acid, glucose, starch, protein.

The given molecules;

starch, water, glucose, carbon dioxide, protein, amino acid, oxygen

The molecular weight of the given compounds is listed as follows;

water -------- 18 g/mol

glucose -------  180.2 g/mol

starch (2 or more glucose) ------ 360 g/mol

carbon dioxide ------ 44 g/mol

protein -------- 20,000 g/mol

amino acid (glycine) ----- 75 g/mol

oxygen -------- 16 g/mol

Thus, the molecules can be arranged as follows with the smallest at the top;

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If you pull yourself to the center of the merry-go-round,  the rotation of the merry go round will decrease.

This is the radial acceleration experienced by a person moving in a circular path as the merry-go-round rotates about its mean position.

a = v²/r

where;

From the formula given above, as the radius of the merry go round increases, the centripetal acceleration of the merry go round decreases.

v = ωr

where;

Thus, when the radius of the circular path decreases, the speed of the merry go round will decrease as well.

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When loading a trailer, more than half the weight should be placed in the back half of the trailer. The given statement is false.

When loading a trailer, more than half of the weight should actually be placed in the front half of the trailer, not the back half. This helps to maintain stability and control while towing the trailer.

Ideally, 60% of the weight should be placed towards the front half, with the remaining 40% distributed towards the back half.
In order to ensure proper weight distribution and trailer stability, it is essential to place more than half of the load weight in the front half of the trailer, rather than the back half.

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Answer:

10m/s

Explanation:

Data

mass=55kg, Maximum height (h1) =10m

Height reached when going down (h2)= 5m

final velocity (v)=?

At Maximum height the velocity is zero

hence intial velocity is 0m/s

The change in Potential energy = change in kinetic energy

mgh1-mgh2=1/2mv²-1/2mu²

But (u)= 0m/s

mgh2-mgh1=1/2mv²

mg(h1-h2)=1/2mv²

2g(h1-h2)=v²

v²=2(10m/s²)(10m-5m)

v²=100m²/s³

v=10m/s

The value that represents the mass of block C that would keep crate D in equilibrium is 196.2 kg (Option D).

To determine of value that represents the mass of block C that would keep crate D in equilibrium, ee can begin by determining the tension in the ropes. Since the crate is held in a certain location by two blocks, the tension in the ropes should be equal. We can use this fact to calculate the tension in the ropes by assuming that they have the same magnitude.

In this case, let T be the tension in each rope segment. The forces acting on the system can be represented in the following free-body diagram:

For the x-direction: T sin 30° = T sin 60° + µg = 0

where µ is the coefficient of friction and g is the acceleration due to gravity. Since the pulleys are frictionless, µ = 0. Therefore, we can simplify the equation as follows:

T sin 30° = T sin 60°

Dividing both sides by T:

sin 30° = sin 60°/2

This gives us: T = (2/√3) mg where m is the total mass of the system and g is the acceleration due to gravity.

Substituting the given values, we obtain:

T = (2/√3) × 150 × 9.81 ≈ 1962 N

Next, we can use the law of the lever to calculate the mass of block C required to keep the crate in equilibrium. According to this law, the sum of the moments acting on the system must be zero. We can choose the point where the ring is attached to the rope as the pivot. This gives us the following equation:

(135 kg)(9.81 m/s²)(3 m) + (mC)(9.81 m/s²)(6 m) - (150 kg)(9.81 m/s²)(4.5 m) - (1962 N)(3 m) = 0

Simplifying: (135)(3) + (6mC) - (150)(4.5) - (1962)(3) = 0

Rearranging: 6mC = 150(4.5) + 1962 - 135(3)

6mC = 2127

mC ≈ 196.2 kg

Therefore, the value that represents the mass of block C required to keep crate D in equilibrium is approximately 196.2 kg. Thus, the correct option is D.

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Answer:

2 Mg + O2 = 2MgO

Type: Synthesis

Answer: A rotating body or system can be in equilibrium if its rate of rotation is constant and remains unchanged by the forces acting on it.

hope this helped

It's worth noting that the negative signs in the lens equation and magnification formula indicate that the image formed by a diverging lens is always virtual and upright. This means that the light rays from the object are diverging when they reach the lens, and the lens bends the light rays so that they appear to be coming from a virtual image point on the opposite side of the lens.

In terms of the magnification, a magnification of 0.40 means that the image is 40% the size of the object, but it is also inverted. So, if the object is an upright arrow, the image will be a smaller, inverted arrow. It's also worth noting that a diverging lens always has a negative focal length, which means that it always forms virtual images that are smaller than the object. Diverging lenses are used in eyeglasses to correct nearsightedness, and in certain optical instruments to spread out light or reduce its intensity.

The magnification formula for a diverging lens is:

m = -di/do

where m is the magnification, di is the image distance, and do is the object distance.

The focal length (f) of the lens is related to the image and object distances by the lens equation:

1/f = 1/di + 1/do

Substituting the given value of focal length (f = -10 cm) into the lens equation, we get:

1/-10 cm = 1/di + 1/do

Simplifying this equation, we can rearrange it to solve for di:

di = -do / (m - 1)

Substituting the given magnification (m = 0.40) into this equation, we get:

di = -do / (0.40 - 1)

di = -do / (-0.60)

di = 1.67 do

Therefore, the image distance is 1.67 times the object distance. To find the object distance that gives a magnification of 0.40, we can set di = -0.40 do (since m = -di/do) and solve for do:

-0.40 do = 1.67 do

Simplifying this equation, we get:

do = di / (-0.40)

do = -1.67 di

Therefore, the object distance that gives a magnification of 0.40 is 1.67 times the image distance. If we assume that the image is formed at the lens' focal length (di = -10 cm), then the object distance is:

do = -1.67 di

do = -1.67 (-10 cm)

do = 16.7 cm

Therefore, the object distance at which the magnification is 0.40 is 16.7 cm.

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The distance and velocity of one of the galaxies, the universe "started its trip about 17.23 billion years.

A galaxy redshift = 0.228

velocity = redshift × speed of light

= 0.228 × 3 × 10⁸m/s

velocity = 6.84 × 10⁷ m/s

Distance = 1050 × 3.2 × 10⁶ light years

= 1050 × 3.2 × 10⁶× 9.46 × 10¹⁵ m

= 3.17856 × 10²⁵ m

So,

Age = D/v

= 5.436 × 10¹⁷ sec

1 sec = 3.17 × 10¹⁷ sec

Age = 5.436 × 10¹⁷ × 3.17 × 10¹⁷ sec

= 17.23 billion years

Thus, according to the relationship between distance and velocity, the universe started its trip about 17.23 billion years.

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When an object is placed on the left of a converging lens, the following statements are true and false as follows:

The image is always to the right of the lens - True

The image can be upright or inverted - True

The image is always smaller or the same size as the object - False

Converging lens is also known as convex lens, which produces a real or virtual image based on the position of the object in relation to the lens. The image formed by the converging lens can either be inverted or upright, depending on the distance of the object from the lens, whether it is closer or further.

1. The image is always to the right of the lens - True

When an object is placed to the left of a converging lens, the image formed by the lens is always located on the opposite side of the lens. That is, the image is located on the right side of the lens. This statement is, therefore, true.

2. The image can be upright or inverted - True

The image formed by the converging lens can be upright or inverted depending on the position of the object in relation to the lens. When the object is placed closer to the lens than the focal length, the image is always virtual, upright and magnified. On the other hand, if the object is placed beyond the focal length, the image is inverted and real. This statement is, therefore, true.

3. The image is always smaller or the same size as the object - False

The size of the image formed by a converging lens is determined by the distance of the object from the lens and the focal length of the lens. When the object is placed closer to the lens than the focal length, the image formed is always virtual, upright, and magnified. However, when the object is placed beyond the focal length, the image formed is inverted, real and diminished. This statement is, therefore, false.

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Explanation:

the answer is 2.46 × 10^12

Explanation:

hope this helps you

.....,.......

Answer:

I thick it's ccc not for sure

Answer:

The speed of water is 32.2 m/s .

Explanation:

Mass of squid, M = 1.5 kg

mass of water, m = 0.12 kg

velocity of squid, V = - 2.8 m/s

Let the speed of water is v.

Use the conservation of momentum,

Momentum before expelling the water  momentum after expelling water

M x 0 = (M - m) x V + m x v

0 = - (1.5 - 0.12) x 2.8 + 0.12 v

3.864 = 0.12 v

v = 32.2 m/s

Answer:

I = 5[amp]

Explanation:

Electrical power is defined as the product of voltage by current.

\(P=V*I\)

where:

P = power = 1150 [W]

V = voltage = 230 [V]

I = current [amp]

Now replacing:

\(1150=230*I\\I=1150/230\\I=5[amp]\)

A 15 [amp] fuse must be used. Always the fuse must be larger than the operating current, to protect the equipment from very high currents. above 15 [amp]

The apparent weight of the astronaut is 58.5 N.

The acceleration due to gravity pulling on the astronaut at the given position is calculated by applying Newton's law of universal gravitation.

\(g = \frac{GM_{moon} }{R^2} \\\\g = \frac{6.67 \times 10^{-11} \times 7.35\times 10^{22}}{(2.5 \times 10^6)^2 } \\\\g = 0.78 \ m/s^2\)

The apparent weight of the astronaut is calculated as follows;

\(W = mg\\\\W = 75 \times 0.78\\\\W = 58.5 \ N\)

Thus, the apparent weight of the astronaut is 58.5 N.

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Answer:

Asking a question

Research existing sources

Define an hypothesis

Design and conduct a study

Draw conclusion

Report result.

Explanation:

Scientific study simply means establishing the existence or proving the veracity of an hypothesis, hence making it a fact. A scientific study follows an orders set of procedure;

Asking a question is the first step as this is what prompts the research, question usually stems after making an observation.

The a observation made and question asked will lead to making research on the observed phenomenon, this is to check if such question has been asked in the past and maybe any scientific study as been carried out in the past.

To make research further, an hypothesis is defined in a bid to find more evidence to support one's observation through experiment.

Study design and implementation is next as the type of study to be embarked upon will determine which type of design preparation and study pattern to deploy.

Conclusion a d report of observations made are the last part of a scientific study which is key as all outcomes of the study should be adequately detailed in an understandable format while also ensuring reproducibility.

Answer:

   Gravitational potential energy.

   Chemical energy.

   Nuclear energy.

   Elastic potential energy

   Electrical potential energy

    Hope this helps :)

Answer: