If I pull a spring back slightly more than last time, what happens to its potential energy?A. Stays the sameB. IncreasesC. Not enough infoD. Decreases

Answers

Answer 1

ANSWER:

B. Increases

STEP-BY-STEP EXPLANATION:

We have that when a spring is stretched or compressed, it works against the restoring force of the spring. This work is stored as elastic potential energy in the spring. The more you stretch or compress the spring, the more work you do and the more energy you store.

The elastic potential energy therefore will depend directly on the length of elongation, the greater the length, the greater the potential energy.

With the above, we can conclude that the correct answer is B. Increases


Related Questions

Modern psychology traces its roots back

Answers

Answer:

Psychology traces its roots back through recorded history to India, China, the Middle East, and Europe. Buddha and Confucius focused on the powers and origin of ideas. ... The ideas of Bacon and Locke contributed to the development of modern empiricism.

Explanation:

This is my first question don’t really know how to use this app yet lol but somebody answer it for me pls!! Seded the corredare
in which sitter is the maximum possible work done
Oh when the age between the face and displacements
OB, when the age beween the face and displacement is 180°
when the age between the force and displacement is 45
OD, when the angle between the force and displacement is 90°
Reset
Bert

Answers

3x6



(This just for extras )

The magnitudes of the current density and the diameters for wires 1 and 2 are given in the table. The current directions are indicated by the arrows.
Find the current I3 in wire 3.
Express your answer in amperes to two significant figures. Call current out of the junction positive and current into the junction negative.
The magnitudes of the current density and the diam
Wire Current density
(A/mm2) Diameter
(mm)
1 2.1 1.7
2 3.9 2.4

Answers

To solve for the current I3 in wire 3, we can apply the principle of conservation of charge, which states that the total current flowing into a junction must equal the total current flowing out of the junction. This can be expressed mathematically as:

I1 + I2 = I3

where I1 and I2 are the currents in wires 1 and 2, respectively, and I3 is the current in wire 3.

To find I1 and I2, we can use the formulas for current (I = J x A), where J is the current density and A is the cross-sectional area of the wire. The cross-sectional area can be calculated from the diameter using the formula A = π/4 x d^2, where d is the diameter.

For wire 1:

I1 = J1 x A1 = 2.1 A/mm^2 x π/4 x (1.7 mm)^2 = 4.52 A

For wire 2:

I2 = J2 x A2 = 3.9 A/mm^2 x π/4 x (2.4 mm)^2 = 13.21 A

Substituting these values into the conservation of charge equation, we get:

4.52 A + 13.21 A = I3

Simplifying, we get:

I3 = 17.73 A

Therefore, the current I3 in wire 3 is approximately 17.73 amperes (or amps) to two significant figures.

What is a current ?

Current can be thought of as the rate at which electric charges flow through a circuit. It is caused by the movement of electrons, which are negatively charged particles, in response to an electric field. In a metallic conductor, such as a wire, electrons can move freely through the material, which allows current to flow easily.

Current can be either direct current (DC) or alternating current (AC). DC flows in one direction, whereas AC changes direction periodically. DC is commonly used in batteries and electronic devices, while AC is used for power transmission over long distances.

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Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval listed below.

HELP PLEASE!!!

Analyze the data on the plot below. Determine the speed of the hawksbill sea turtle during each interval

Answers

Answer:

Day 0 to day 2: 5km/day

Day 2 to day 3: 2km/day

Explanation:

Day 0 to day 2: 10/2 = 5

Day 2 to day 3: 12 - 10 = 2

To Calculate:

The x-axis, or the days from 0 to 6, line up with the y-axis, or the distance from 0 to 24.  The point in the graph means that on that day, the turtle traveled that much distance.  For example, on the third point (2, 10), the day is 2 and the distance is 10.  To find the distance over multiple days, catalog the days in your mind and look for the points.  Then, find the difference.  For example, from day 2 (2, 10) to day 5 (5, 18), this would look like: 5 - 2 = 3, and 18 - 10 = 8, so this means that over 3 days, the turtle traveled 8 km.

What is the displacement illustrated?
What is the distance illustrated?
start/finish
2m
4m
4m
2m

Answers

(a) The displacement of the person as illustrated is 0 m.

(b) The distance travelled by the person is determined as 12 m.

What is the displacement of the person?

The displacement of the person as illustrated is the change in the position of the person.

Mathematically, the formula for displacement of an person is given as;

Δx = xf - xi

where;

xf is the final position of the personxi is the initial position of the person

Δx = (2 m + 4m ) - ( 4m  + 2m ) = 0

The total distance travelled by the person is calculated as;

d = 2 m + 4 m + 4 m + 2 m

d = 12 m

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What is the displacement illustrated?What is the distance illustrated?start/finish2m4m4m2m

Which observation is evidence that electromagnetic radiation (EMR) has particle-like
properties? (1 point)
O EMR refracts as it moves into a different medium.
O
A diffraction pattern is observed when EMR passes through a narrow slit.
O Some EMR is blocked when it passes through a polarized lens.
O EMR with energy above a certain value can eject electrons out of a metal.

Answers

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

Electromagnetic radiations as particles

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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Do you think the rider in the above figure is really in danger? What If people below were removed?

Answers

The rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium.

A system subjected to different forces is said to be in equilibrium when all the forces applied to the system are equal.

For a system subject to two opposite forces, the following exists;

If the upward force and the downward forces are equal, the system will remain in equilibrium positionIf the upward or downward force is greater than the other, the system will move in the direction of the greater force.

Thus, we can conclude that the rider will be in danger when the people below  are removed, because they initially helped to maintain equilibrium. Once these people are removed, the rider tends to move at a greater speed and possibly fall from the initial position.

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what kind of substance has particles that are close together, but can change shape depending on its container

Answers

Answer:

the liquid state

Explanation:

because the particles can move about freely, a liquid has no definite shape and takes a shape dictated by its container.

Two plates labeled A and B are separated and initially neutral. Through some mechanism, 7 μC (microcoulombs) of positive Charge are move from plate A to plate B. Answer below questions about the final electrostatic state of each plate after the transfer. 1) After the transfer is complete, indicate how many excess protons (or singly positive ions) are on Plate B ? 2) After the transfer is complete, what is the sign and number of the uncanceled elemental charges on Plate A. Note: positive values require no sign.

Answers

Answer:

1)  Approximately  \(4\,\,\,10^{13}\)  excess protons

2)  negative \(4\,\,\,10^{13}\)     (\(-4\,\,\,10^{13}\))

Explanation:

1)

Recall that the charge of an electron or proton is approximately: \(1.6\,\,\,10^{-19} \,C\)

Therefore, to find the number of protons transferred in 7 micro-Coulombs of charge, we do:

\(\frac{7\,\,10^{-6}\,}{1.6\,\,10^{-19}} \approx 4\,\,10^{13}\)

Approximately  \(4\,\,\,10^{13}\)  excess protons

2)

The sign and number of uncanceled elemental charges on plate A is therefore negative \(4\,\,\,10^{13}\)  , because the same number of positive charges were removed from it, changing its neutrality

I put Frank at a position directly between the Earth and the Moon such that he is stuck there at rest…equally pulled in two wdirections. I then make the moon disappear. How fast is Frank moving when he hits the Earth? You may assume there is no air friction when he re-enters the atmosphere

Answers

Frank would be moving at approximately 86,784 meters per second (m/s) when he hits the Earth.

In the scenario you described, Frank is initially placed at rest in a position directly between the Earth and the Moon, being equally pulled by their gravitational forces. When the Moon disappears, the only gravitational force acting on Frank is the Earth's gravitational pull.

As there is no air friction in this scenario, Frank would fall freely toward the Earth, accelerating under the influence of the Earth's gravity. The acceleration due to gravity near the surface of the Earth is approximately 9.8 meters per second squared (m/s²).

To determine the speed at which Frank hits the Earth, we need to know the distance between Frank and the Earth. If we assume Frank is initially positioned at the Earth-Moon distance (approximately 384,400 kilometers), we can calculate his speed when he reaches the Earth's surface using the laws of motion.

Using the kinematic equation:

v² = u² + 2as

where:

v = final velocity (speed when Frank hits the Earth)

u = initial velocity (zero in this case, as Frank is initially at rest)

a = acceleration due to gravity (9.8 m/s²)

s = distance fallen (Earth-Moon distance)

Converting the Earth-Moon distance to meters:

s = 384,400,000 meters

Plugging the values into the equation:

v² = 0 + 2 * 9.8 m/s²* 384,400,000 m

v²= 7,528,480,000 m²/s²

Taking the square root of both sides:

v ≈ 86,784 m/s

Therefore, When Frank collides with the Earth, he will be traveling at a speed of approximately 86,784 meters per second (m/s).

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a car traveling in a highway brakes to a stop without skidding. what happens to its kinetic energy? can that energy be recovered and reused?

Answers

Answer:

A car traveling on a highway takes to stop without skidding. What happens to its kinetic energy? ... The energy goes to parts of the brakes. No, the energy can only be reused if there is a heat pump present

A 2800-lbm car climbs a 1160 ft. long uphill road which is inclined at 15o (to the horizontal) and covers the distance in 12 sec. Determine the power required if the car covers the distance (a) at constant velocity, (b) from an initial velocity, at the bottom of the hill, of 10 mph to a final velocity of 50 mph at the top of the hill and (c) from an initial velocity of 45 mph to a final velocity of 15 mph. Neglect the effects of friction and wind resistance.

Answers

Answer:

a) P = 70054.3 W,  b)  P = 18820 W,  c)   P = 14116.7 W

Explanation:

Power is defined as work per unit of time

         P = W / t = F x / t

         P = F v

a) in this case the velocity is constant, let's use the equilibrium relation to find the force.

Let's set a reference system with the x axis parallel to the plane

           

        F - Wₓ = 0

         F = Wₓ

with trigonometry let's decompose the weight

        sin θ = Wₓ / W

        Wₓ = W sin θ

         

          F = W sin 15

          F = 2800 sin 15

          F = 724.7 lb

we look for the speed, as it rises with constant speed we can use the relations of uniform motion

          v = x / t

          v = 1160/12

          v = 96.67 ft / s

we calculate the power

          P = 724.7 96.67

          P = 70054.3 W

b) In this case, the speed of the vehicle changes during the ascent, so we use the relationship between work and the change in kinetic energy

           W = ΔK

           W = ½ m v_f² - ½ m v₀²

   let's reduce to the SI system

           v₀ = 10 mph (5280 ft / 1 mile) (1h / 3600 s = 14.67 ft / s

           v_f = 50 mph (5280 ft / 1 mile) (1 h / 3600s) = 73.33 ft.s

           

 mass :         m = w / g

           W = ½ 2800/32 (73.33² - 14.67²)

           W = 225841 J

we calculate the average power

           P = W / t

           P = 225841/12

           P = 18820 W

c) we repeat the previous procedure

          v₀ = 45 mph = 66 ft / s

          v_f = 15 mph = 22 ft / s

          W = ½ 2800/32 (22² - 66²)

          W = -169400 J

         

          P = W / t

          P = 169400/12

          P = 14116.7 W

A man pushes a 35.2-kilogram box across a frictionless floor with a force of 128 Newtons. What is the acceleration of the box?

Answers

ANSWER:

3.636 m/s^2

STEP-BY-STEP EXPLANATION:

We have the following formula, which is the force formula:

\(\begin{gathered} F=m\cdot a \\ m=\text{ mass = 35.2 kg} \\ F=\text{ force = 128 N} \\ a=\text{ acceleration} \end{gathered}\)

Replacing and solving for a (acceleration):

\(\begin{gathered} 128=35.2\cdot a \\ a=\frac{128}{35.2} \\ a=3.636m/s^2 \end{gathered}\)

Therefore, the acceleration is equal to 3.636 m/s^2

please help me out with this​

please help me out with this

Answers

The current flowing through the 1Ω resistor in the circuit is 0.66 A.

The emf of the cells, V = 1.1 V

Internal resistance of the cells, r = Ω

Resistance across the circuit, R = 1 Ω

According to Kirchhoff's current law, the total current flowing into and out of a junction in an electrical circuit is equal.

According to Kirchoff's current law,

(1.1 - V'/2) + (1.1 - V'/2) + (1.1 - V'/2) = V'/1

3/2(1.1 - V') = V'

3.3 - 3V' = 2V'

5V' = 3.3

Therefore, the terminal velocity of the battery is,

V' = 3.3/5

V' = 0.66 V

Therefore, according to Ohm's law, the current flowing through the 1Ω resistor is given by,

I = V'/R

I = 0.66/1

I = 0.66 A

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DESCRIBE THE FORMATION OF THE SOLAR SYSTEM ACCORDING TO THE NEBULAR THEORY

Answers

When a cloud of gas and dust in space was disturbed, maybe by the explosion of a nearby star.This explosion made waves in space which squeezed the cloud of gas & dust.

A 3.5 kilogram cannon is loaded with a 0.52-kilogram ball. The cannon and ball are initially rolling forward with a speed of 1.27 m/s. The cannon is fired and launches the ball forward with a total speed of 75 m/s. Determine the post-explosion velocity of the cannon.

Answers

The cannon's forward post-explosion velocity is 6.18 m/s.

What are the fundamentals of momentum?

Momentum is the force necessary to bring an item to a complete halt in a unit of time and is determined by multiplying an object's mass by its velocity. The overall momentum is equal to the sum of the individual momenta for any array of multiple objects.

Total momentum before = Total momentum after

(3.5 kg + 0.52 kg) × 1.27 m/s = 3.5 kg × v_cannon + 0.52 kg × 75 m/s

where v_cannon is the velocity of the cannon after the explosion.

Simplifying and solving for v_cannon, we get:

v_cannon = (0.52 kg × 75 m/s - (3.5 kg + 0.52 kg) × 1.27 m/s) / 3.5 kg

v_cannon = 6.18 m/s.

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pls help need it last question on my test

pls help need it last question on my test

Answers

The force that results in the decrease in speed from the midpoint to the end of the track is friction. The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

The force that would cause the Hot Wheels car to slow down from the midpoint of the track to the end of the track is friction between the car's wheels and the track.

Friction is a force that opposes motion between two surfaces in contact.

In this case, the wheels of the car and the surface of the track are in contact, and the friction force acts in the opposite direction of the car's motion, which slows it down.

As the Hot Wheels car travels down Track #2 during the Speed Lab activity, its initial velocity decreases due to friction.

Friction is a resistance force that opposes motion.

It is caused by the interaction between the surfaces in contact. In this case, the surface of the track and the wheels of the car are in contact.

When the car is moving, there is friction between the two surfaces.

The direction of the friction force is opposite to the direction of motion of the car.

This means that the friction force slows the car down.

In conclusion, the force that results in the decrease in speed from the midpoint to the end of the track is friction.

The friction force slows down the vehicle because it acts in the opposite direction of the car's motion.

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A 2.0 g metal cube and a 4.0 g metal cube are 6.0 cm apart, measured between their centers, on a horizontal surface. For both, the coefficient of static friction is 0.65. Both cubes, initially neutral, are charged at a rate of 7.0 nC/s .
(a) Which cube moves first?
(b) How long after charging begins does one cube begin to slide away?
Draw a Sketch of the Problem and Create a "Parameter Panel" for the Problem.

Answers

Cube moves first, that the cube which is neutral in nature. Hence, the cube which is neutral will move.  

To solve this problem, we need to calculate the electrostatic force between the two charged cubes and compare it with the force of static friction between the cubes and the surface. The cube with the smaller force of friction will begin to move first. The parameter panel and sketch of the problem are shown below:

Parameter Panel:

Mass of cube 1 (m1) = 2.0 g = 0.002 kg

Mass of cube 2 (m2) = 4.0 g = 0.004 kg

Distance between the centers of the cubes (d) = 6.0 cm = 0.06 m

Charge rate of each cube (q) = 7.0 nC/s

Coefficient of static friction (μ) = 0.65

Sketch:

     |-----------|        |-----------|

     |     2     |        |     1     |

     |-----------|        |-----------|

           |                 |

          d=6.0 cm          d=6.0 cm

           |                 |

           |-----------------|

(a) To determine which cube moves first, we need to calculate the electrostatic force between the charged cubes and compare it with the force of static friction between the cubes and the surface. The electrostatic force between two charged objects is given by Coulomb's law:

F = (k * q1 * q2) / d^2

where k is the Coulomb constant (9.0 x 10^9 N m^2/C^2), q1 and q2 are the charges on the cubes, and d is the distance between them. For each cube, the charge is increasing at a rate of 7.0 nC/s, so the charge at any time t is given by:

q = 7.0 x 10^-9 C/s * t

At t = 0, the cubes are neutral and have no charge. At some later time t, the charges on the cubes are:

q1 = 7.0 x 10^-9 C/s * t

q2 = 7.0 x 10^-9 C/s * t

The electrostatic force between the cubes is then:

F = (9.0 x 10^9 N m^2/C^2) * (q1 * q2) / d^2

= (9.0 x 10^9 N m^2/C^2) * [(7.0 x 10^-9 C/s * t)^2 / (0.06 m)^2]

The force of static friction between each cube and the surface is:

Ff = μ * N

= μ * m * g

where N is the normal force, m is the mass of the cube, μ is the coefficient of static friction, and g is the acceleration due to gravity (9.81 m/s^2).

The normal force N is the force exerted by the surface on the cube, and is equal in magnitude to the weight of the cube:

N = m * g

Plugging in the values for each cube, we get:

Ff1 = μ * m1 * g

= 0.65 * 0.002 kg * 9.81 m/s^2

= 0.0127 N

Ff2 = μ * m2 * g

= 0.65 * 0.004 kg * 9.81 m/s^2

= 0.0254 N

Comparing the electrostatic force between the cubes and the force of static friction, we find:

F - Ff1 = (9.0 x 10^9 N)

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How do meteorites differ from meteors and meteoroids?

Answers

Answer:

When meteoroids enter Earth's atmosphere (or that of another planet, like Mars) at high speed and burn up, the fireballs or “shooting stars” are called meteors. When a meteoroid survives a trip through the atmosphere and hits the ground, it's called a meteorite.

Explanation:

Answer: Meteoroid: Small particle from a comet or asteroid orbiting the Sun. Meteor: The light phenomena which results from a meteoroid entering the Earth's atmosphere and vaporizing; this is basically a shooting star. Meteorite: A meteoroid that survives through the Earth's atmosphere and lands on the Earth's surface.

why fur coats would keep their owners warmer if they were worn inside out?​

Answers

Answer:

The reason why this is, is because:

Explanation:

According to Jones, fur serves as an insulator for the body during cold weather and regulates the process of heat absorption during warm weather. It acts as a thermal regulator, preventing the body from taking on excessive heat. Dogs and cats shed their fur in hot weather to make their coats more appropriate for heat protection rather than warmth.

Answer:

Insulation

Explanation:

The reason for this is insulation, which describes the process of an object absorbing heat and harboring heat. It works as such: Fur protects you from the cold by forming what’s called a “boundary layer.” This happens as cold air hits the surface of your coat and the molecules cause friction.

While the block hovers in place, is the density of the block (top left) or the density of the liquid (bottom center) greater?

Answers

Answer:

for the body to float, the density of the body must be less than or equal to the density of the liquid.

Explanation:

For a block to float in a liquid, the thrust of the liquid must be greater than or equal to the weight of the block.

Weight is

        W = mg

let's use the concept of density

        ρ_body = m / V

        m = ρ_body V

        W = ρ_body V g

The thrust of the body is given by Archimedes' law

        B = ρ_liquid g V_liquid

 

as the body floats the submerged volume of the liquid is less than or equal to the volume of the block

       ρ_body V g = ρ_liquid g V_liquid

     

       ρ_body = ρ liquid Vliquido / V_body

As we can see, for the body to float, the density of the body must be less than or equal to the density of the liquid.

If the Sun, Earth, and Moon are lined up as shown above, then the Earth would have...



Neap tide, in which there are almost no tides


Spring tides, in which there is almost no tides


Spring Tides, in which the high tides are extremely high and the low tides are extremely low


Neap tides, in which there are very high and very low tides

Answers

This is 6th grade earth science right?

Answer: Left cheek from the sun

Explanation:

ball a 0.604 kg moving right at 11.6 m/s makes a head-on collision with ball B at rest. after, ball A moves right at 2.09 m/s, and ball B moves right at 5.03 m/s. what is the mass of ball B? unite=kg

Answers

Answer:

1.142

Explanation:

A motorcycle skids for a distance of 2.0 m with the icy road pushing on its tires with force of 120 N as its
brakes are applied
What is the change in kinetic energy for the motorcycle?
Round the answer to two significant digits.​

Answers

Answer:

-240

Explanation:

A motorcycle skids for a distance of 2.0 m on an icy road, then the change in kinetic energy for the motorcycle will be equal to -240 J.

What is kinetic energy?

The force which a moving object has is referred to as kinetic energy in physics. It is defined as the number of effort required to propel a person of a specific mass from still to a specific velocity.

Aside from slight fluctuations in speed, your body holds onto the kinetic energy it obtains during acceleration.

When the body slows down from its present level to a condition of rest, the same quantity of energy is used.

Formally, kinetic energy is any quantity that has a gradient concerning time in the Lagrangian of a system.

As per the given information in the question,

Distance, d = 2.0 m

Friction, f = 120 N

The angle between displacement and friction force, θ = 180°

Now, the change in kinetic energy for the motorcycle = Work done by the friction.

K.E = f × d(cos θ)

= 120 (2.0 m)(cos 180°)

Δ K.E = -240 J

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For an electron, magnitude of force on it
is
Select one
• Bev
bev
Be
BIL

Answers

Answer:

F = Bev

Explanation:

B is magnetic field density

e is the electron charge

v is the electron velocity

A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J

Answers

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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A catapult launches a rock with an initial speed of 35 m/s at an initial angle of 22o above the ground from a height of 0.0 m. After the rock has traveled 10 m horizontally along the ground from its starting point, what is its height above the ground

Answers

Answer:

h = 3.6 m

Explanation:

This is the case of a projectile motion. We assume the air resistance to be negligible. So the speed of the rock remains constant in x-direction. Therefore,

s = V₀ₓ t

where,

V₀ₓ = x - component of launching velocity = V Cos θ = (35 m/s)(Cos 22°)    V₀ₓ = 32.45 m/s

s = distance traveled horizontally by the rock = 10 m

t = time taken to cover the distance = ?

Therefore,

10 m = (32.45 m/s)(t)

t = (10 m)/(32.45 m/s)

t = 0.31 s

Now, we consider the vertical motion. The vertical motion is taking place under the action of gravity. So it is uniformly accelerated motion. Applying 2nd equation of motion to the vertical motion:

h = (Vi₀)(t) + (0.5)gt²

where,

h = height of rock = ?

Vi₀ = Vertical Component of Launching Velocity = V₀Sinθ = (35 m/s)(Sin 22°)

Vi₀ = 13.11 m/s

g = - 9.8 m/s² (negative for upward motion)

Therefore,

h = (13.11 m/s)(0.31 s) + (0.5)(-9.8 m/s²)(0.31 s)²

h = 4.06 m - 0.47 m

h = 3.6 m

How did earth change about 2.5 billion years ago when many organisms began using photosynthesis to make food

A. The amount of oxygen in the atmosphere increased

B. Mass extinctions occurred

C. The oceans became larger

D. Rainfall increased

Answers

The amount of oxygen in the air was increased

Find the equivalent resistance between points A and B
shown in Figure 31.

Find the equivalent resistance between points A and Bshown in Figure 31.

Answers

The equivalent resistance between points A and B is 0.837Ω.

Resistors in series are connected end-to-end so that the current flows through them in sequence. The equivalent resistance of resistors in series is the sum of their individual resistances.

The formula for equivalent resistance of resistors in series: R_eq = R_1 + R_2 + ... + R_n

Resistors in parallel are connected across each other so that the voltage is the same across each resistor. The equivalent resistance of resistors in parallel is the reciprocal of the sum of the reciprocals of their individual resistances.

The formula for equivalent resistance of resistors in parallel: 1/R_eq = 1/R_1 + 1/R_2 + ... + 1/R_n

Here in the Fig.

we can simplify the second set of resistors in parallel (4.8 Ω, 3.3 Ω, and 8.1 Ω) using the same formula:

1/Req1 = 1/4.8 + 1/3.3 + 1/8.1

Req1=1.575Ω

This Req1 connected series with 6.3Ω, then Req of this two resistance given by:

Req2= 1.575Ω+ 6.3Ω

Req2=7.875Ω

Once again this req2 makes the parallel with the other two resistance i. e 1.5Ω and 2.5Ω

Their equivalent resistance  is given by,

1/Req3=1/1.5 + 1/2.5 + 1/7.875

Req3=0.837Ω

Hence, The equivalent resistance between points A and B is 0.837Ω

To learn more about Ohm's Law click:

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what is magnetic flux thru a closed surface

Answers

Answer: Zero

Explanation:

Gauss's law states that the total magnetic flux through a closed surface is equal to zero. Because the magnetic field lines are in continuous loops, so all closed surfaces have magnetic field lines coming out, hence the net magnetic flux is zero.

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