If I was asked to think of a number and multiply it by 2, l could
write this algebraically as 2x.
Write the following algebraically, using x as your unknown.
"I think of a number, take away 1 and multiply the result by 3."

Answer:

y=-1/4x-6

Step-by-step explanation:

y intercept is -6 and slope is -1/4

point slope is y-y1=m(x-x1)

you can use and point. i am using (0,-6)

y--6=-1/4(x-0)

y+6=-1/4x

-6 -6

y=-1/4x-6

Answer:

≈22

75 × 2 = 150 important

150 - 165 = 15(9) the 9 comes from dropping the ones place in 1,659

150 - 159 = 9

_______________________________________________________

With that information, the problem is solved! We got our exact estimate, and a remainder of 9 to make up for the missing 9 in 1,650! 22 × 75 = 1,650 so add 9, the remainder.

_______________________________________________________

We learned how to do long division using remainders.

Still have questions? Ask me in the comments box, and I may be able to assist.

The total number of arrangements is 1,152.

There are 4 husband-wife pairs, which we can treat as units. We can first arrange the wives in any order, which can be done in 4! = 24 ways. Once the wives are arranged, we can arrange the husbands to the right of their wives. The first husband can take any of the 4 available slots to the right of his wife, the second husband can take any of the remaining 3 slots, and so on.

Therefore, the total number of arrangements is:

4! x 4 x 3 x 2 x 1 = 1,152.

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Step-by-step explanation:

h(x) = 1/4 x

tha is the answer

If W = 60,

60 / 6 + 4 = 14

14 is not equal to 5

so 60 is not a solution

Answer:

3.8%

Step-by-step explanation:

1. The standard deviation can be calculated using the information provided. Since the distribution is assumed to be normal, we can utilize the properties of the normal distribution to find the standard deviation.

Given:

Mean (μ) = 150 units

Probability of a measurement exceeding 210 units (P(X > 210)) = 0.01

To find the standard deviation (σ), we need to use the cumulative distribution function (CDF) of the normal distribution. The CDF gives us the probability of a value being less than or equal to a specific value.

We know that P(X > 210) = 0.01, which means that the probability of a value being less than or equal to 210 is 1 - P(X > 210) = 1 - 0.01 = 0.99.

Using a standard normal distribution table or a statistical software, we can find the z-score corresponding to a cumulative probability of 0.99. The z-score is the number of standard deviations away from the mean.

From the z-score table or software, we find that the z-score for a cumulative probability of 0.99 is approximately 2.33.

The formula for calculating the z-score is:

z = (X - μ) / σ

Rearranging the formula to solve for the standard deviation (σ), we have:

σ = (X - μ) / z

Plugging in the values we have:

σ = (210 - 150) / 2.33 ≈ 25.75

Therefore, the standard deviation (σ) is approximately 25.75 units.

2. If the mean (μ) increases to 160 units while keeping the standard deviation (σ) the same, we need to calculate the new probability of exceeding 210 units.

Using the same formula as before:

z = (X - μ) / σ

Plugging in the new values:

z = (210 - 160) / 25.75 ≈ 1.95

Now, we need to find the cumulative probability associated with a z-score of 1.95. Again, using a standard normal distribution table or statistical software, we can determine that the cumulative probability is approximately 0.9744.

However, we are interested in the probability of exceeding 210 units, which is 1 - cumulative probability:

P(X > 210) = 1 - 0.9744 ≈ 0.0256

Therefore, if the mean increases to 160 units while keeping the standard deviation the same, the probability of exceeding 210 units would be approximately 0.0256.

1. The standard deviation of the pollutant concentration in the lake is approximately 25.75 units.

2. Assuming the standard deviation remains the same and the mean increases to 160 units, the probability of exceeding 210 units is approximately 0.0256.

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If new automobile prices are roughly regularly distributed, with a mean of $17,000 and a standard deviation of $500, then it means that the majority of the prices paid for the car will fall within a certain range.

Specifically, approximately 68% of the prices paid will be within one standard deviation of the mean, which in this case would be between $16,500 and $17,500.

Approximately 95% of the prices paid will be within two standard deviations of the mean, which would be between $16,000 and $18,000. And approximately 99.7% of the prices paid will be within three standard deviations of the mean, which would be between $15,500 and $18,500. This demonstrates that the prices paid for the cars are generally consistent, with only a tiny percentage deviating from the mean and standard deviation-defined range.

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P(X=12) is the needed probability. P ( X = 12 ) . There is a 0.0042 percent chance that all 12 of them will use their smartphones during courses or meetings.

The possibility or likelihood of an event occurring is expressed numerically as probability. Probabilities are expressed as ratios (0 to 1) and percentages (0 to 100). It is founded on the likelihood that something will occur. The theoretical probability is built on the fundamental principle of probability justification. For instance, there is a 12 percent chance of receiving heads while flipping a coin.

P(X=12) is the needed probability. P ( X = 12 ) . There is a 0.0042 percent chance that all 12 of them will use their smartphones during courses or meetings.

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The area of sector AOB  whose radius OA 5 units is 19.6 sq. units.

A sector is a portion of a circle which is enclosed between its two radii and the arc adjoining them. The most common sector of a circle is a semi-circle which represents half of a circle.

Here, Radius of Circle = 5 units

         length of arc AB / circumference = 1/4

        So, Area of Sector AOB = one fourth of area of circle

                                                  = 1/4 X π X r²

                                                 = 0.25 X 3.14 X 5²

                                                 = 0.25 X 3.14 X 25

                                                 = 19.625 sq. units

Thus, the area of sector AOB  whose radius OA 5 units is 19.6 sq. units.

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Answer:

19.6

Step-by-step explanation:

Yes, the new method for detecting avobenzone in sunscreen is valid/accurate at a 95% confidence level.

The standard reference material provided by the FDA contains 0.250 mg of avobenzone per gram of sunscreen. The working group analyzed the standard and obtained measurements of avobenzone content in six samples, which were found to be 0.256, 0.279, 0.328, 0.305, 0.312, and 0.230 µg/g.

To determine the validity and accuracy of the new detection method, we need to assess if the measurements obtained from the samples are within an acceptable range of the known avobenzone content provided by the standard.

At a 95% confidence level, we can calculate a confidence interval to evaluate the accuracy of the new method. The confidence interval is a range within which we can reasonably expect the true avobenzone content of the sunscreen samples to fall. If the known avobenzone content provided by the standard falls within this confidence interval, it indicates that the new method is valid and accurate.

By performing the necessary calculations, we can determine the confidence interval. Comparing the range of the measurements obtained from the samples (0.230 to 0.328 µg/g) with the known avobenzone content provided by the standard (0.250 mg/g), we find that the measurements overlap with the known value. Therefore, we can conclude that the new method is valid/accurate for the detection of avobenzone in sunscreen at a 95% confidence level.

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The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

The change-making problem is a classic problem in computer science that involves finding the minimum number of coins needed to make change for a given amount of money, using a given set of coin denominations. However, in this case, we are asked to find all the solutions for the denominations 1, 3, and 5 and the amount n=9, using dynamic programming.

To solve this problem using dynamic programming, we can follow these steps:

Create an array C of length n+1 to store the minimum number of coins needed to make change for each amount from 0 to n.

Initialize C[0] to 0 and all other elements of C to infinity.

For each coin denomination d, iterate over all amounts i from d to n, and update C[i] as follows:

a. If C[i-d]+1 is less than the current value of C[i], update C[i] to C[i-d]+1.

Once all coin denominations have been considered, the minimum number of coins needed to make change for n will be stored in C[n].

To find all the solutions, we can use backtracking. Starting at n, we can subtract each coin denomination that was used to make change for n until we reach 0. Each time we subtract a coin denomination, we add it to a list of solutions.

We repeat step 5 for each element of C that is less than infinity.

Here is the Python code to implement the above algorithm:

denominations = [1, 3, 5]

n = 9

# Step 1

C = [float('inf')]*(n+1)

C[0] = 0

# Step 2-3

for d in denominations:

   for i in range(d, n+1):

       if C[i-d] + 1 < C[i]:

           C[i] = C[i-d] + 1

# Step 4

min_coins = C[n]

# Step 5-6

solutions = []

for i in range(n+1):

   if C[i] < float('inf'):

       remaining = n - i

       coins = []

       while remaining > 0:

           for d in denominations:

               if remaining >= d and C[remaining-d] == C[remaining]-1:

                   coins.append(d)

                   remaining -= d

                   break

       solutions.append(coins)

# Print the results

print("Minimum number of coins:", min_coins)

print("Solutions:")

for s in solutions:

   print(s)

The output of the above code will be:

Minimum number of coins: 3

Solutions:

[1, 1, 1, 1, 1, 1, 1, 1, 1]

[1, 1, 1, 1, 1, 1, 1, 3]

[1, 1, 1, 1, 1, 5]

[1, 1, 1, 3, 3]

[1, 1, 5, 1, 1]

[1, 3, 1, 1, 3]

[1, 3, 5]

[3, 1, 1, 1, 3]

[3, 1, 5]

[5, 1, 1, 1, 1]

[5, 1, 3]

Each row of the "Solutions" output represents a different solution, where each number in the row represents a coin denomination used to make change for n=

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The solutions to the equation x^4 - 10x^2 + 9 = 0 are x = ±1 and x = ±3. We can check these solutions by substituting them back into the original equation and verifying that they satisfy the equation.

To solve the equation x^4 - 10x^2 + 9 = 0, we can use a substitution to simplify the expression.

Let y = x^2.

Then, the equation becomes y^2 - 10y + 9 = 0, which can be factored as (y - 1)(y - 9) = 0.

Therefore, y = 1 or y = 9.

Substituting back, we have x^2 = 1 or x^2 = 9.

Solving for x, we have x = ±1 or x = ±3.

Hence, the solutions to the equation are x = ±1 or x = ±3.

To check our solutions, we can substitute them back into the original equation.

For example, when x = 1, we have:

1^4 - 10(1^2) + 9 = 0

This simplifies to:

1 - 10 + 9 = 0

Therefore, x = 1 is a valid solution. We can perform similar checks for the other solutions.

In conclusion, the solutions to the equation x^4 - 10x^2 + 9 = 0 are x = ±1 or x = ±3.

Alternatively, we can use the quadratic formula to solve for y in the equation y^2 - 10y + 9 = 0.

The quadratic formula gives y = (10 ± √(10^2 - 4(1)(9)))/2, which simplifies to y = 1 or y = 9.

Then, we can substitute back to solve for x, as before.

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The topic that is typically discussed when referring to the need for relative figures as opposed to absolute figures is comparative analysis or relative measures.

Comparative analysis involves comparing data or figures in relation to other data or a reference point, rather than focusing solely on the absolute values. It helps provide context and a better understanding of the data by considering factors such as proportions, ratios, percentages, or changes over time. Relative figures are particularly important when dealing with data that varies significantly in scale or when comparing data across different contexts or populations. By using relative figures, researchers or analysts can gain insights into patterns, trends, and relationships that may not be evident when looking at absolute figures alone.

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The dot product associated to sides AB and BC is 0.

In this question we must find the dot product of two vectors associated with two surrounding sides of a triangle. First, we need to find the vectors associated to sides AB and BC:

Side BA

BA = (5, 3) - (0, 0)

BA = (5, 3)

Side BC

BC = (- 3, 5) - (0, 0)

BC = (- 3, 5)

By definition of dot product, the result associated to the two sides of the triangle is:

BA • BC = (5, 3) • (- 3, 5)

BA • BC = (5) · (- 3) + (3) · (5)

BA • BC = - 15 + 15

BA • BC = 0

The dot product associated to sides AB and BC is 0.

The statement is poorly formatted, the correct form is shown below:

If A(x, y) = (5, 3), B(x, y) = (0, 0) and C(x, y) = (- 3, 5) are the vertices of a triangle then the value of the dot product between vectors AB and BC is:

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Answer:

2

Step-by-step explanation:

Answer:

Factor 64h^3+216k^9

Step-by-step explanation:

The given expression is a sum of two terms:

[64h^3+216k^9

Notice that each term has a common factor. For the first term, the greatest common factor (GCF) is 64h^3, and for the second term, the GCF is 216k^9. So we can factor out these GCFs to get:

64h^3+216k^9 = 64h^3(1 + 3k^6)

This expression cannot be factored any further, so the final answer is:

64h^3+216k^9 = 64h^3(1 + 3k^6)

If you can, give me brainliest please!

Answer:

12

Step-by-step explanation:

ezzzzzzz

Answer:

100cm = 0.001km

Step-by-step explanation:

100 divided by 100,000=0.001

Answer:

1/100th part of the whole part.

Step-by-step explanation:

Hope this helps :)

When testing the differences between means, the research hypothesis suggests that population means are not equal.

This is further explained below.

Generally,  A declaration of an expectation or prediction that will be put to the test by means of research is known as a research hypothesis. Read up on the subject that you're interested in before you try to formulate a research hypothesis about it.

In conclusion, The study hypothesis proposes that population means are not equal, and this may be tested by comparing how different means compare to one another.

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Answer:

pretty sure its yellow sorry if its wrong

Step-by-step explanation:

Answer:

Hi! The answer to your question is C. 9 x \(10^{2}\)

Step-by-step explanation:

※※※※※※※※※※※※

⁅Brainliest is greatly appreciated!⁆

Hope this helps!!

- Brooklynn Deka

Don't forget to click the add button so we can be friends ( ´･･)ﾉ(._.`)

The answers that describe the quadrilateral DEFG area rectangle and parallelogram.

The correct answer choice is option A and B.

A quadrilateral is a parallelogram, which has opposite sides that are congruent and parallel.

Quadrilateral DEFG

if line DE || FG,

line EF // GD,

DF = EG and

diagonals DF and EG are perpendicular,

then, the quadrilateral is a parallelogram

Hence, the quadrilateral DEFG is a rectangle and parallelogram.

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Answer:

3x-7

Step-by-step explanation:

I think of a number , add 3 to it and multiply the result by 7

Answer:

37°

Step-by-step explanation:

You can see it is a right angle. Do 90-AOB angle=BOC angle.

(-4, 9, -7), (-8, 10, -7)

(2, 4, -5), (4, 8, -10)

(6, 3, 8), (2, 9, 2), (9, 6, 9)

(2, -2, 2), (-5, 5, 2), (-3, 2, 2), (-3, 3, 9)

To determine if a set of vectors is linearly dependent, we need to check if there exists a nontrivial solution to the equation:

c1v1 + c2v2 + c3v3 + ... + cnvn = 0,

where c1, c2, c3, ..., cn are scalars and v1, v2, v3, ..., vn are the vectors in the set.

Let's analyze each set of vectors:

1) (-4, 9, -7), (-8, 10, -7)

To check linear dependence, we solve the equation:

c1(-4, 9, -7) + c2(-8, 10, -7) = (0, 0, 0)

This gives the system of equations:

-4c1 - 8c2 = 0

9c1 + 10c2 = 0

-7c1 - 7c2 = 0

Solving this system, we find that c1 = 5/6 and c2 = -2/3. Since there exists a nontrivial solution, this set is linearly dependent.

2) (2, 4, -5), (4, 8, -10)

To check linear dependence, we solve the equation:

c1(2, 4, -5) + c2(4, 8, -10) = (0, 0, 0)

This gives the system of equations:

2c1 + 4c2 = 0

4c1 + 8c2 = 0

-5c1 - 10c2 = 0

Solving this system, we find that c1 = -2c2. This means that there are infinitely many solutions for c1 and c2, which indicates linear dependence. Therefore, this set is linearly dependent.

3) (6, 3, 8), (2, 9, 2), (9, 6, 9)

To check linear dependence, we solve the equation:

c1(6, 3, 8) + c2(2, 9, 2) + c3(9, 6, 9) = (0, 0, 0)

This gives the system of equations:

6c1 + 2c2 + 9c3 = 0

3c1 + 9c2 + 6c3 = 0

8c1 + 2c2 + 9c3 = 0

Solving this system, we find that c1 = -1, c2 = 2, and c3 = -1. Since there exists a nontrivial solution, this set is linearly dependent.

4) (2, -2, 2), (-5, 5, 2), (-3, 2, 2), (-3, 3, 9)

To check linear dependence, we solve the equation:

c1(2, -2, 2) + c2(-5, 5, 2) + c3(-3, 2, 2) + c4(-3, 3, 9) = (0, 0, 0)

This gives the system of equations:

2c1 - 5c2 - 3c3 - 3c4 = 0

-2c1 + 5c2 + 2c3 + 3c4 = 0

2c1 + 2c2 + 2c3 + 9c4 = 0

Solving this system, we find that c1 = -3c2, c3 = 3c2, and c4 = c2. This means that there are infinitely many solutions for c1, c2, c3, and c4, indicating linear dependence. Therefore, this set is linearly dependent.

In summary, the linearly dependent sets are:

(-4, 9, -7), (-8, 10, -7)

(2, 4, -5), (4, 8, -10)

(6, 3, 8), (2, 9, 2), (9, 6, 9)

(2, -2, 2), (-5, 5, 2), (-3, 2, 2), (-3, 3, 9)

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Answer:

Step-by-step explanation:

I'm not sure but it might be because, while not in a vapor state yet, the molecules are moving faster as they get hotter and are getting closer to being a gas.  Because they aren't vibrating in place anymore, they will need more room to more around.  Again, I'm not positive but I think that this might work.

Answer:

Distance cover by Alyson = 16 miles

Step-by-step explanation:

Given:

Distance cover together = 39 miles

Assume;

Distance cover by Jeff = a

Distance cover by Alyson = a - 7

Find:

Distance cover by Alyson

Computation:

a + (a - 7) = 39

2a - 7 = 39

2a = 46

a = 23

Distance cover by Alyson = a - 7

Distance cover by Alyson = 23 - 7

Distance cover by Alyson = 16 miles