if it takes 16 yards of material to make costumes, how much material will be needed to make costumes of that same size?
A.
60.8 yards
B.
50.7 yards
C.
40 yards
D.
34 yards

Answer:

3

Step-by-step explanation:

Easy pythagorean theorum question.

The law states that "A squared plus B squared, equals C squared."

A and B are the two sides that border the 90 degree mark.

C is the hypotenuse or the longest side/diagonal.

Since we know C and A (I chose to use A because why not) we can fill in the equation with what we know

2^2 + ?^2 = \(\sqrt{13^{2} }\)

So

4 + ?^2 = \(\sqrt{13^{2} }\)

Since the 13 is already squared in side of a root, it stays as 13

4 + x^2 = 13

4 - 4 + x^2 = 13 - 4

x^2 = 9

x^2 root = root of 9

x = 3

The missing side is 3.

Or you could use an online calculator xD

Therefore, the solution to the system of equations is: x = 13/12, y = -3/4 that is option C.

In mathematics, an equation is a statement that asserts the equality of two expressions, separated by an equals sign (=). The expressions on either side of the equals sign are referred to as the left-hand side (LHS) and the right-hand side (RHS) of the equation. Equations are used to describe relationships between variables and to solve problems.

Here,

To solve the system of equations:

4y + 12x = 10 ...(1)

2y - 6x = -8 ...(2)

We can use the method of elimination or substitution.

Method of elimination:

We can eliminate x by multiplying equation (2) by 2 and adding it to equation (1) to obtain:

4y + 12x = 10

(4y - 12x = -16)

8y = -6

Dividing both sides by 8, we get:

y = -6/8

y = -3/4

Substituting this value of y in equation (1), we get:

4(-3/4) + 12x = 10

Simplifying and solving for x, we get:

-3 + 12x = 10

12x = 13

x = 13/12

So the answer is C. x = 13/12, y = -3/4.

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Answer:

the product of the given radical is \(\sqrt[5]{12}\)

Step-by-step explanation:

The computation of the product of the given radicals is as follows

According to the question, the following radical is

\(\sqrt{50} \ and \sqrt[5]{6}\)

Now simplify it

\(\sqrt{25 \times 2} and \sqrt[5]{6}\\\\\sqrt{25} \sqrt{2} and \sqrt[5]{6}\\\\\sqrt[5]{2} and \sqrt[5]{6}\\\\\sqrt[5]{12}\)

Hence, the product of the given radical is \(\sqrt[5]{12}\)

This is the answer but the same is not given in the options

The formula to calculate the gradient of a line is given as, gradient `= (y2 − y1) / (x2 − x1)`where (x1, y1) and (x2, y2) are the coordinates of two distinct points on the line AB.

The above problem is based on finding out the value of d when we know the gradient of line AB. We know that line AB passes through two points, A (5, 9) and B (d, 15) and the gradient of line AB is given as 3. The formula to calculate the gradient of a line is given as,

gradient = (y2 − y1) / (x2 − x1)

where (x1, y1) and (x2, y2) are the coordinates of two distinct points on the line AB. We can use the above formula to find out the equation of line AB using point A. We know that the coordinates of point A are (5, 9) and we can assume that the coordinates of point B are (d, 15). Substituting these values in the above formula, we get:

gradient = (y2 − y1) / (x2 − x1)

3 = (15 − 9) / (d − 5)

Multiplying both sides by (d − 5), we get:

3(d − 5) = 15 − 9

Expanding the brackets, we get:

3d − 15 = 6

Simplifying the above equation, we get:

3d = 21

d = 7

Therefore, the value of d is 7.

Thus, we can conclude that the value of d is 7 when A is the point with coordinates (5,9), B is the point with coordinates (d,15), and the gradient of the line AB is 3.

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For a two-tailed test, the p-value is the probability of obtaining a value for the test statistic are as follows:

p-value = 0.09 is the probability of obtaining a value for the test statistic.

We are going step by step

Step 1) the p-value is the probability of obtaining a value for the test statistic at least as extreme as that provided by the sample

Step 2) Here the Confidence level is equal to 0.95

So the level of significance is equal to 0.05

p-value = 0.09

Since the p-value is higher than the level of significance that we do not reject the null hypothesis.

Hence the answer, the p-value = 0.09 is the probability of obtaining a value for the test statistic.

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The necessary probability is 0.8186.

Take into account the details offered.

The daily revenue is $7200 on average, with a $1200 standard deviation.

u=7200 and s=1200

The following 30 days' worth

sx= s/sqrt(n) = 1200/sqrt(30) =219.089

As we know

z= x-u/sx

x=7000

u=7200

sx=219.089

Substitute in above formula.

z=7000-7200/219.089

z= -200/219.089

z= -0.912

According to the standard normal table, P(Z > -0.912) = 0.8186

Consequently, 0.8186 is the required probability.

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It will take 12 seconds until Hudson and Knox have run the same number of feet.

Let's denote the time it takes until Hudson and Knox have run the same number of feet as "t" (in seconds).

The distance Hudson runs can be calculated by multiplying his speed (8.8 feet/second) by the time "t". Thus, the distance Hudson covers is 8.8t feet.

Knox, on the other hand, had a head start of 30 feet. So the distance Knox covers can be calculated by multiplying his speed (6.3 feet/second) by the time "t" and adding the head start of 30 feet. Thus, the distance Knox covers is 6.3t + 30 feet.

To find the time when both runners have covered the same distance, we set their distances equal to each other:

8.8t = 6.3t + 30

Simplifying the equation:

2.5t = 30

Dividing both sides by 2.5:

t = 30 / 2.5

t = 12

Therefore, it will take 12 seconds until Hudson and Knox have run the same number of feet.

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Answer: use the algebric condistional process

Step-by-step explanation: this is sample only

There are 27720 strings.

Strings of 12 ternary digits, 3 possibilities for each digit in the string, gives a total of 3^12 = 531,441 ternary strings of length 12.

There are

C(12,3) = 12! / (9! 3!) = 12 * 11 * 10/ 3 * 2 = 220 possible combinations of positions for the three 0s.

Of the 9 remaining positions, there are

C(9,4) = 9! / (5! 4!)

= 9 * 8 * 7 * 6/ (4 * 3 * 2 * 1)

= 126 possible combinations of positions for the four 2s.

The remaining 5 places are, of course, occupied by the five 1s.

So there that contain exactly three 0s, five 1s, and 4 2s are 220 * 126= 27720 such strings.

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Answer:

  (a)  $810.45

Step-by-step explanation:

You want the value of an investment of $300 earning 5% interest compounded quarterly for 20 years.

The compound interest formula tells you the value is ...

  A = P(1 +r/n)^(nt)

where P = 300, r = 0.05, n = 4, t = 20.

Using the given parameters in the given equation, you find the account value to be ...

  A = $300(1 +0.05/4)^(4·20) ≈ $810.45

__

Additional comment

The "rule of 72" tells you the account value will approximately double in a number of years equal to 72 divided by the interest rate percentage: 72/5 = 14.4 years. After 20 years, it will be worth more than that doubled amount, $600. This only leaves one reasonable answer choice.

<95141404393>

Based on the graph the easy score of a shoe size of 14 cannot be determined from the graph since it is not represented

Option D

The area of this house in square meters is 152.24.

To convert square feet to square meters, you can use the conversion factor of 1 square foot = 0.092903 square meters.

A house is advertised as having 1640 square feet under the roof.

So, the area of the house in square meters is:

1640 square feet * 0.092903 square meters/square foot = 152.24 square meters.

Unit Conversion: It is defined as the changing from one quantity unit to another quantity unit followed by the method of division, and multiplication by a conversion factor.

Thus, the area of this house in square meters is 152.24 if the house is advertised as having 1640 square feet under the roof.

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To assign the sum of extra credit received to the total extra credit, you need to follow these steps:

1. Make a list of all the test grades, and mark the ones that have extra credit with a "+" sign. For example, if the test scores are: 95, 110+, 80, 120+, 100, you would mark the 110+ and the 120+.

2. Add up all the extra credit marks. In this example, that would be 110 + 120 = 230.

3. Count the number of extra credit marks. In this example, there are two.

4. Multiply the number of extra credit marks by the maximum extra credit value. If full credit is 100, then the maximum extra credit value is the amount that a student can exceed the maximum score by. In this case, that would be 20 (since 120 - 100 = 20). So, 2 x 20 = 40.

5. Add the extra credit value to the total score. In this example, the total score is 505 (95 + 110 + 80 + 120 + 100). So, you would add 40 to that to get 545.

Therefore, the answer is: To assign sum extra with the total extra credit received given list test grades, you need to add the extra credit value to the total score by multiplying the number of extra credit marks by the maximum extra credit value, and then adding that value to the total score.

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\(x = 2 \frac{4}{5} x =2.8\)

Have a good day

The ratio of all the corresponding sides and corresponding angles is one. Then the quadrilateral is congruent with each other.

The quadrilateral has four sides and four angles. The sum of internal angles is 360 degrees.

The quadrilaterals are LMNP and LKJQ shown.

In quadrilaterals LMNP and LKJQ,

LK = LM = LQ = LP         (Given)

JK = JQ = NM = NP        (Given)

∠KJQ = ∠MNP          (Given)

∠KLQ = ∠MLP           (Given)

∠JKL = ∠NML            (Given)

∠JQL = ∠NPL            (Given)

The ratio of all the corresponding sides and corresponding angles is one. Then the quadrilateral is congruent with each other.

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Answer:

B. Radius

The line from the center of a circle to the edge is called a radius. The radius can be used in pi and a lot of other things

Answer:

30mm squared

Step-by-step explanation:

The area of a triangle is b x h /2

Therefore, 5x12/2=30

Answer:

30mm squared

Step-by-step explanation:

The area of a triangle is b x h /2

There for 5x12/2=30

you also can add 5+12+13=30

The first four terms are f( x) = 1-1/2(x-1)+1/4(x-1) ²/ 2! - 1/8(x-1) ³/ 3!. The general term of the Taylor series for f( x) about x = 1 is

(- 1) ⁿ\((x-1)^{n}\)/( 2ⁿn).

The Taylor series for f( x) about x = 1 can be written as

f( x) = ∑( n = 0 to ∞) fⁿ( 1)/\(n!^{n}\)

where fⁿ( 1) denotes the utmost derivative of f at x = 1.

Using the given information, we can write the first four nonzero terms of the Taylor series for function f( x) about x = 1 as

f( 1) +f'( 1)(x-1) +f''( 1)(x-1) ²/ 2!+ f'''( 1)(x-1) ³/ 3!............

Substituting f( 1) = 1, f'( 1) = -1/ 2, f''( 1) = 1/4, and f'''( 1) = -1/ 8 in the below equation, we get

f( x) = 1-1/2(x-1)+1/4(x-1) ²/ 2! - 1/8(x-1) ³/ 3!............

The general term of the Taylor series can be attained by substituting the utmost outgrowth of f at x = 1 in the below equation

fⁿ( 1)/\(n!^{n}\)= (- 1) ⁿ( n- 1)!/ 2ⁿn!\((x-1)^{n}\) = (- 1) ⁿ\((x-1)^{n}\)/( 2ⁿn)

thus, the general term of the Taylor series for f( x) about x = 1 is

(- 1) ⁿ\((x-1)^{n}\)/( 2ⁿn)

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Answer:You can choose 6 different sets of 5 books to read.

Step-by-step explanation:All you need to do is do 30 divided by 5 and you get 6

Im pretty sure its permutation

Answer:

8 x 0.16 = 1.28

Step-by-step explanation:

It is important to note that the chi-squared test of independence is applicable for categorical variables, and the assumptions of the test should be met for valid results.

The null hypothesis is a type of hypothesis that explains the population parameter and is used to examine if the provided experimental data are reliable.

To determine if the distribution of a given categorical variable is consistent with a null hypothesis, you can use a statistical test called the chi-squared test of independence.

The chi-squared test of independence is used to assess whether there is a significant association between two categorical variables. It compares the observed frequencies (counts) of each category in the given variable with the expected frequencies that would be observed if the null hypothesis were true. The null hypothesis typically assumes that there is no association or relationship between the variables, and any deviations from expected frequencies are due to random chance.

Here are the steps involved in conducting a chi-squared test of independence:

1. Formulate the null and alternative hypotheses: The null hypothesis assumes no association between the variables, while the alternative hypothesis suggests that there is an association.

2. Create a contingency table: Construct a contingency table that shows the observed frequencies of the categories for each variable.

3. Calculate the expected frequencies: Based on the null hypothesis, calculate the expected frequencies for each category. This is typically done assuming independence between the variables.

4. Calculate the test statistic: Using the observed and expected frequencies, calculate the chi-squared test statistic. This measures the overall discrepancy between the observed and expected frequencies.

5. Determine the p-value: The chi-squared test statistic follows a chi-squared distribution. Calculate the p-value associated with the test statistic, which represents the probability of obtaining results as extreme as the observed data under the null hypothesis.

6. Make a decision: Compare the p-value to a predetermined significance level (e.g., 0.05). If the p-value is smaller than the significance level, you reject the null hypothesis and conclude that there is evidence of an association between the variables. Otherwise, if the p-value is larger than the significance level, you fail to reject the null hypothesis and conclude that there is no evidence of an association.

It is important to note that the chi-squared test of independence is applicable for categorical variables, and the assumptions of the test should be met for valid results. These assumptions include having independent observations and sufficient expected frequencies in each cell of the contingency table.

It is also worth mentioning that there are other statistical tests available for specific scenarios or different types of categorical data analysis, such as Fisher's exact test or McNemar's test. The choice of the appropriate test depends on the research question, study design, and the specific characteristics of the data.

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Answer:

B)

Explanation:

The slope-intercept form of the equation of a line is generally given as;

where m = slope of the line

b = y-intercept of the line

So given a slope(m) of 2/3 and a y-intercept(b) of -2, we can go ahead and write the equation of the line as;

The reason it is equilateral is because: Triangle BDC is equilateral because arcs BD and BE are two arcs with the same radius and center O.

We have that she drew two arcs that are centered at B. The point of intersection is at DE. This tells us that the chords that connects BD and DE are equal.

DC = EC = BC

This is because the center of the circle is at C

BDE are also points on the circle with length equal to radius

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Answer:

m-5=15!

Step-by-step explanation:

The probabilities are given as follows:

Fewer than 4 siblings: P(X < 4) = 0.737.

At least 5 siblings: P(X >= 5) = 0.111.

Not an only child: P(X > 1) = 0.734.

The probabilities are called identifying the desired outcomes from the distribution of the number of children per parent.

Hence the probability of fewer than 4 siblings is of

P(X < 4) = P(X = 1) + P(X = 2) + P(X = 3) = 0.266 + 0.322 + 0.149 = 0.737.

The probability of at least 5 siblings is of

P(X >= 5) = P(X = 5) + P(X = 6) + P(X > 6) = 0.059 + 0.032 + 0.02 = 0.111.

The probability that the student is not an only child is given as follows:

P(X > 1) = 1 - P(X = 1) = 1 - 0.266 = 0.734.

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Full Question:

The distribution is given as follows:

P(X = 1) = 0.266.

P(X = 2) = 0.322.

P(X = 3) = 0.149.

P(X = 4) = 0.152.

P(X = 5) = 0.059.

P(X = 6) = 0.032.

P(X > 6) = 0.02.

Use the probability distribution and histogram found here to select the correct probability for each statement.

The probability that a randomly selected student has fewer than 4 siblings is P(X < ) = .

The probability that a randomly selected student has at least 5 siblings is P(X ≥ ) = .

The probability that a randomly selected student is not an only child is P(X ≠ 0) =

Answer:

7542 by the end of the sec week